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IPR with SKIN or Flow
Efficiency
Muhammad Taufiq Fathaddin
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IPR with FE11. Standing Method
Where:
Rearrangement Eq. 1a, results in
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Example 1
Diketahui:Pr = 2000 psi = pb
FE = 0.5
Q = 1000 bpd @ pwfa= 500 psi1. Tentuka q max pada FE = 1
2. Tentukan q max pada FE = 0.5
3. Tentukan q pada pwf = 1000 dan FE = 0.5
4. Tentukan q pada pwf = 1000 dan FE = 1
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Solution
1. Determine qmax@FE=1=
Pwf = Pr(PrPwfa) FE = 2000(2000-500)0.5
= 1250 psi
Qmax,FE=1 = 1000/(1-0.2(1250/2000)-0.8(1250/2000)^2) = 1777.78 bpd
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IPR=1
pwf q
0 1777.78
200 1728.002
400 1649.78600 1543.113
800 1408.002
1000 1244.446
1200 1052.446
1400 832.001
1600 583.1118
1800 305.7782
2000 0
0
500
1000
1500
2000
2500
0 500 1000 1500
pwf,
psi
q, b/d
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Solution
2. Determine qmax@FE=0.5=
Pr = 2000 psi Pwf a= 0
Pwf = Pr(PrPwfa) FE = 2000(2000-0)0.5
= 1000 psi
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IPR FE=0.5
pwf q
0 1244.45
200 1209.605
400 1154.85
600 1080.183
800 985.6044
1000 871.115
1200 736.7144
1400 582.40261600 408.1796
1800 214.0454
2000 0
0
500
1000
1500
2000
2500
0 500 1000 1500
pwf,psi
q, b/d
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Solution
3. Find q for Pwf = 1000 psi and FE = 0.5
q=871.1 b/d
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Solution
3. Find q for Pwf = 1000 psi and FE = 1
q=1244.5 b/d
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IPR with FE12. Harrison Method
Where:
Rearrangement Eq. 1a, results in
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Example 1
Diketahui:
Pr = 2000 psi = pb
FE = 0.5, S = 2
Q = 1000 bpd @ pwfa = 500 psi1. Tentuka q max pada FE = 1
2. Tentukan q max pada FE = 0.5
3. Tentukan q pada pwf = 1000 dan FE = 0.5
4. Tentukan q pada pwf = 1000 dan FE = 1
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Solution
1. Determine qmax@FE=1=
Pwf = Pr
(Pr
Pwfa) FE = 2000
(2000-500)0.5= 1250 psi
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Solution
2. Determine qmax@FE=0.5=
Pr = 2000 psi Pwfa = 0
Pwf = Pr(PrPwfa) FE = 2000(2000-0)0.5
= 1000 psi
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Solution
3. Find q for Pwf = 1000 psi and FE = 0.5
Pr = 2000 psi Pwf = 0
Pwf = Pr(PrPwfa) FE
= 2000(20001000)0.5 = 1500 psi
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Solution
3. Find q for Pwf = 1000 psi and FE = 1
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IPR with SKIN FACTOR3. Pudjo Sukarno Method
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Given data:Pr = 1345 psia (Pb = 3000 psia)
A test shows q = 321 bpd at a flowing pressure of 719
psia.
API > 40 and S = 0, -5, and 5
Calculate:
(1). qomaxat 1345 psia @S=0
(2). Construct PRESENT IPR Curve For Skin Factor = 0, 5,
-5
Example # 3
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(1). qomaxat 1345 psia
Solution of Example # 3
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Pwf q0 432.4
200 422.6
400 396.9
600 354.6800 294.1
1000 211.8
1200 102.2
1345 0
Solution of Example # 3b. IPR Curve for S = 0
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Solution of Example # 3b. IPR Curve for S = 5
Pwf (psi) q (bpd)
0 279.9
200 270.8
400 251.7
600 222.2
800 181.5
1000 128.4
1200 61.1
1345 0
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Perbandingan IPR dengan dan Tanpa Skin
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METODE IPR with SKIN FACTOR4. Klins Method
The standard Vogel's method was modified by Klins et
alto explicitly account for the effects of bubble point
pressure and skin, as follows:
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Example 1Diketahui:
Pr = 2000 psi = pb
S = 2
Q = 1000 bpd @ pwf = 500 psi
1. Tentukan q max pada S = 0
2. Tentukan q max pada S = 2
3. Buat IPR untuk S = 0
4. Buat Kurva IPR untuk S = 25.Tentukan q pada pwf = 1000 dan S = 2
6. Tentukan q pada pwf = 1000 dan S = 0
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Solution1. Determine qmax@S=0=
n = (0.28+0.72*2000/2000)(1.235+0.001*2000)
= 3.24
M = 6.835/(6.835+0) = 1
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Solution2. Determine qmax@S=2=
n = (0.28+0.72*2000/2000)(1.235+0.001*2000)
= 3.24
M = 6.835/(6.835+2) = 0.774
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Solution
3. IPR untuk Skin = 0
q Pwf
1088.9 0
1056.3 200
1020.5 400
977.0 600
921.0 800
847.0 1000
749.5 1200622.3 1400
459.4 1600
254.1 1800
0.0 2000
0
500
1000
1500
2000
2500
0.0 200.0 400.0 600.0 800.0 1000.0
Pwf,psi
q, bpd
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Solution
4. IPR untuk S = 2
0
500
1000
1500
2000
2500
0.0 200.0 400.0 600.0 800.0 1000.0
Pwf,psi
q, bpd
Pwf, psi q, STB/D
0 842.4
200 817.2
400 789.5600 755.8
800 712.5
1000 655.3
1200 579.8
1400 481.5
1600 355.4
1800 196.6
2000 0.0
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METODE IPR with SKIN FACTOR5. Gema-Taufiq Equation
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Example 1Diketahui:
Pr = 2000 psi = pb
S = 2
Q = 1000 bpd @ pwf = 500 psi
1. Tentukan q max pada S = 0
2. Tentukan q max pada S = 2
3. Buat IPR untuk S = 0
4. Buat Kurva IPR untuk S = 25.Tentukan q pada pwf = 1000 dan S = 2
6. Tentukan q pada pwf = 1000 dan S = 0
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Solution1. Determine qmax@S=0=
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Solution2. Determine qmax@S=2=
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Solution
3. IPR untuk S = 0
0
500
1000
1500
2000
2500
0.0 200.0 400.0 600.0 800.0 1000.0 1200.0
Pwf,
psi
q, bpd
Pwf, psi q, STB/D
0 1156.9
200 1104.7
400 1038.4
600 958.0
800 863.5
1000 754.9
1200 632.1
1400 495.31600 344.3
1800 179.2
2000 0
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Solution
4. IPR untuk Skin = 2
Pwf, psi q, STB/D
0 925.5
200 883.8
400 830.8600 766.4
800 690.8
1000 603.9
1200 505.7
1400 396.2
1600 275.4
1800 143.4
2000 0
0
200
400
600
800
1000
1200
1400
1600
1800
2000
0.0 200.0 400.0 600.0 800.0 1000.0 1200.0
Pwf,
psi
qo, STB/D
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Given data:Pr = 1345 psia (Pb = 3000 psia)
A test shows q = 321 bpd at a flowing pressure of 719
psia.
API > 40 and S =5
Calculate using Klins and G-T Methods
(1). qomaxat 1345 psia @S=0
(2). qomaxat 1345 psia @S= 5
(3). Construct PRESENT IPR Curve For Skin Factor = 0
and 5
Task