Date post: | 14-Apr-2018 |
Category: |
Documents |
Upload: | joi-lynn-marie-jover |
View: | 215 times |
Download: | 0 times |
of 19
7/30/2019 L04_EfieldSuperposition_post.pdf
1/19
LECTURE 4 slide 1
Lecture 4
Vector Superposition
The Field of Standard ChargeDistributions
Sections: 2.4, 2.5
Homework: D2.2, D2.5, D2.6; 2.17, 2.18, 2.20, 2.25
7/30/2019 L04_EfieldSuperposition_post.pdf
2/19
LECTURE 4 slide 2
E-field of Multiple Sources
superposition holds in a linear medium
superposition means adding the individual contributions of sources
vector superposition implies adding/subtracting vectors
the E-field is a vector
The ESF of multiple charges at any point is a vectorial
sum of the fields created by each individual charge.
i
i
= E E
7/30/2019 L04_EfieldSuperposition_post.pdf
3/19
LECTURE 4 slide 3
E-field of a Point Charge Reminder
a point charge at the origin (spherical coordinates)
2
1
4r
Q
r=E a
a point charge at position r
2
1 ( )( )
4 | |R
Q
=
rE r a
r r or
3
( ) ( )( )
4 | |
Q
=
r r rE r
r r
7/30/2019 L04_EfieldSuperposition_post.pdf
4/19
LECTURE 4 slide 4
E-field of Multiple Point Charges 1
21
1 ( )( )
4 | |
Nn n
n
nn
Q
=
=
r
E r ar r
Examples with 2 charges:
1 2Q Q= 2Q Q= E
1r
2 1r r=
1E2E
E
2E
1E
7/30/2019 L04_EfieldSuperposition_post.pdf
5/19
LECTURE 4 slide 5
E-field of Multiple Point Charges 2
1 1 1 11 2 2 2 3/ 2
1 1 1
( ) ( ) ( )( , , )
4 | ( ) ( ) ( ) |
y zQ x x y y z z x y z
x x y y z z + + = + +
a a aE
2 2 2 2
2 2 2 2 3/ 22 2 2
( ) ( ) ( )
( , , ) 4 | ( ) ( ) ( ) |
x y zQ x x y y z z
x y z x x y y z z
+ +
= + +
a a a
E
1 2( , , ) ( , , ) ( , , )x y z x y z x y z= +E E E
7/30/2019 L04_EfieldSuperposition_post.pdf
6/19
LECTURE 4 slide 6
E-field of a Uniform Line Charge 1
The line charge is
represented by an
infinite number of
infinitesimal line
elements of charge
ldQ dz =
The field of the linecharge is a super-
position of the fields
created by each
linear charge
element dQ.
dz ldQ dz =
( , , 0 )
z
x y0
L
1R
2
1
2
7/30/2019 L04_EfieldSuperposition_post.pdf
7/19
LECTURE 4 slide 7
E-field of a Uniform Line Charge 2
The contribution of each line element is
3
( )
4 | |
ldzd
=
r rE
r r
, =0
, 0, 0 2
zz
z
=
= =