Laser Physics EAL 501
Lecture 6 Power & Frequency
• We said that there are two types of cavities• 1- Ring cavities
• Standing wave cavities• 1- Longitudenal modes due to standing waves
Do ring lasers have longitudenal modes?
nLc2
2-Transversal modes [Gaussian beams]The electric field distribution in the x-y plane
Satisfy the wave eq.The Fresnel-Kirchoff’s theory states that“if we know the field distribution at a plan 1 (x1,y1,z1) then the
distribution at any plane (x,y,z) is given by
We can write
Where The solution is
Higher order modes are given by
Gaussian BeamsThe solution of wave equation can be plane waves
But it is not real
q(z) is the complex beam parameter of the beam
Amplitude factor Transverse phase factor Longitudenal phase factorRayleigh range
Beam waist
Radius of curvature
Gain Saturation
We drive the rate equations
))(()( 12
12 NggNg
)1(21..
)1(21)1ln(
21
1
21
2121
221
rrL
lossescavity
rrLrrL
g
err
t
Lgt
• The steady state solution of the rate equation in the case I=0 gives us the threshold condition
• The steady state solution of the rate equation in the case after the threshold can be shown to be
Steady state under threshold solution is
In case of 3 level laser In case of 4 level laser
Solution above threshold in the case of two levels without pumping
Solution above threshold in the case of 3levels with pumping
Since g(ν)=σ(v)(N2-N1) then we can write
)()(1
)()(
sat
o
II
gg
)(2)(
)()(
21
21
21
PhI
NPPg
sat
To
Problem : find small signal gain and saturation intensity for 4 level laser
Hole burning1. Spatial hole burning2. Spectral hole burning
1- Spatial hole burning in the case of standing wave cavity there are points of zero intensity and points of max. intensity which depletes the gain much more rapidly2- Spectral hole burning in the case of inhomogeneous broadening the atoms that feed the laser modes will be depleted much more rapidly
Output power
Usually only one mirror produces output and if the mirror reflection is high
Where s is the scattering losses
The condition of steady state lasing
tgrrl
g )1(21)( 21
tsat
o gII
gg
/1)()(
It2
It is easy to find the value of transmission t to get the maximum output
So the optimum output intensity is