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Latihan Matematik Tingkatan 4 Exercise Mathemtics Form 4 · PDF filechapter 03 – sets...

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https://tutormansor.wordpress.com/ ANSWER / JAWAPAN CHAPTER 03 – SETS (MATHEMATICS FORM 4) BAB 03 – SETS (MATEMATIK TINGKATAN 4) Β© HAK CIPTA TERPELIHARA MAY 2013 https://tutormansor.wordpress.com/ 1 Latihan Matematik Tingkatan 4 Exercise Mathemtics Form 4 Bab 03 – SETS Chapter 03 – SETS JAWAPAN / ANSWER Question: http://goo.gl/Ny39Z EXERCISE 2 1. {4} 2. ( βˆͺ ) ∩ 3. = {1, 2, 3, 4, 6, 12} = {4, 8, 12} βˆͺ = {1, 2, 3, 4, 6, 8, 12} 4. = {14, 16, 18, 20, 22, 24, 26} = {16, 25} βˆͺ = {14, 16, 18, 20, 22, 24, 25, 26} ( βˆͺ ) β€² = {15, 17, 19, 21, 23, 27}
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ANSWER / JAWAPAN

CHAPTER 03 – SETS (MATHEMATICS FORM 4)

BAB 03 – SETS (MATEMATIK TINGKATAN 4)

Β© HAK CIPTA TERPELIHARA MAY 2013

https://tutormansor.wordpress.com/

1

Latihan Matematik Tingkatan 4

Exercise Mathemtics Form 4

Bab 03 – SETS

Chapter 03 – SETS

JAWAPAN / ANSWER

Question: http://goo.gl/Ny39Z

EXERCISE 2

1. {4}

2. (𝐴 βˆͺ 𝐡) ∩ 𝐢

3. 𝐴 = {1, 2, 3, 4, 6, 12}

𝐡 = {4, 8, 12}

𝐴 βˆͺ 𝐡 = {1, 2, 3, 4, 6, 8, 12}

4. 𝐴 = {14, 16, 18, 20, 22, 24, 26}

𝐡 = {16, 25}

𝐴 βˆͺ 𝐡 = {14, 16, 18, 20, 22, 24, 25, 26} (𝐴 βˆͺ 𝐡)β€² = {15, 17, 19, 21, 23, 27}

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ANSWER / JAWAPAN

CHAPTER 03 – SETS (MATHEMATICS FORM 4)

BAB 03 – SETS (MATEMATIK TINGKATAN 4)

Β© HAK CIPTA TERPELIHARA MAY 2013

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2

5. (𝐴 βˆͺ 𝐡 βˆͺ 𝐢)

6. 𝑃 = {6, 12}

𝑄 = {5, 7, 9, 11, 13}

𝑃 βˆͺ 𝑅 = {4, 6, 8, 10, 12, 14} 𝑃 βŠ‚ 𝑅

π‘ π‘œ, 𝑅 = {4, 6, 8, 10, 12, 14}

𝑃′ ∩ 𝑅 = {4, 8, 10, 14}

7. 𝐹 = {4, 10}

𝐺 = {2, 5, 7}

𝐹 βˆͺ 𝐺 = {2, 4, 5, 7, 10} (𝐹 βˆͺ 𝐺)β€² = {3, 6, 8, 9}

8. 𝐴′ ∩ (𝐡 βˆͺ 𝐢)

9. 𝑃 = {6, 8, 10, 12, 14}

𝑄 = {5, 7, 11, 13} 𝑃 βˆͺ 𝑄 = {5, 6, 7, 8, 10, 11, 12, 13, 14}

10. 𝐴′ ∩ 𝐡

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ANSWER / JAWAPAN

CHAPTER 03 – SETS (MATHEMATICS FORM 4)

BAB 03 – SETS (MATEMATIK TINGKATAN 4)

Β© HAK CIPTA TERPELIHARA MAY 2013

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3

DIAGNOSTIC TEST

1. πœ‰ = {1 , 2, 2, 3, 4, 5, 6, 7}

𝑃 = {1, 2, 2, 4, 6}

𝑄 = {2, 3, 5, 6, 7}

𝑅 = {5, 7}

𝑃′ βˆͺ 𝑅′ ∩ 𝑄 = {2, 3, 6, 7}𝑫

2. π‘ͺ

3. A/D

4. 𝐿 = {1, 3, 5, 9}

𝑀 = {1, 4, 9}

𝑁 = {3, 6, 9}

𝐿 βˆͺ 𝑀 ∩ 𝑁′ = {1, 4, 5} π‘ͺ = πŸ‘ π’Šπ’•π’†π’Žπ’”

5. π‘Œ ∩ 𝑍 = {𝐼𝑉}

𝑋 = {𝐼, 𝐼𝐼}

𝑋 βˆͺ (π‘Œ ∩ 𝑍) = {𝐼, 𝐼𝐼, 𝐼𝑉} 𝑩

6. [Cancel Question]

7. C

8. 𝐸 = {1, 4, 9, 16}

𝐹 = {4, 8, 12, 16}

𝐸 ∩ 𝐹′ = {1, 9}𝑩

9. 𝐴 = 30 + 50 + 20 + 40 = 140

𝐡 = 𝐴 + 40

= 140 + 40

= 180

180 = 50 + 20 + 30 + 𝑋

= 100 + 𝑋

𝑋 = 180 βˆ’ 100

= 80

30 + 50 + 20 + 40 + 30 + 𝑋 + π‘Œ = 300

170 + 80 + π‘Œ = 300

π‘Œ = 50 π‘ͺ

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ANSWER / JAWAPAN

CHAPTER 03 – SETS (MATHEMATICS FORM 4)

BAB 03 – SETS (MATEMATIK TINGKATAN 4)

Β© HAK CIPTA TERPELIHARA MAY 2013

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4

10. 4 + π‘₯ + 5 + 1 + 2π‘₯ + 3 + 6 = 40

19 + 3π‘₯ = 40

3π‘₯ = 21

π‘₯ = 7 𝑫

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ANSWER / JAWAPAN

CHAPTER 03 – SETS (MATHEMATICS FORM 4)

BAB 03 – SETS (MATEMATIK TINGKATAN 4)

Β© HAK CIPTA TERPELIHARA MAY 2013

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5

EXERCISE 1 (Paper 2)

1. setΞΎ = Aβˆͺ B βˆͺC

(a) 𝐴 βˆͺ 𝐡

(b) 𝐡′ ∩ 𝐢

2. πœ‰ = 𝑃 βˆͺ 𝑄 βˆͺ 𝑅

(a) 𝑃 ∩ 𝑄 βˆͺ 𝑅′

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ANSWER / JAWAPAN

CHAPTER 03 – SETS (MATHEMATICS FORM 4)

BAB 03 – SETS (MATEMATIK TINGKATAN 4)

Β© HAK CIPTA TERPELIHARA MAY 2013

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6

(b) 𝑃 βˆͺ 𝑄 ∩ 𝑅′

3. ΞΎ = E βˆͺ F βˆͺG

(a) 𝐹′ ∩ 𝐺

(b) (𝐹 βˆͺ 𝐺)β€² ∩ 𝐸

(c) 𝐹 βˆͺ (𝐸 ∩ 𝐺′)

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ANSWER / JAWAPAN

CHAPTER 03 – SETS (MATHEMATICS FORM 4)

BAB 03 – SETS (MATEMATIK TINGKATAN 4)

Β© HAK CIPTA TERPELIHARA MAY 2013

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7

4. _

a. πœ‰ = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

𝐴 = {1, 2, 4, 8, 9}

𝐡 = {1, 2, 3, 4, 5}

𝐢 = {4, 5,6, 7, 8}

i) 𝐴 βˆͺ 𝐡 = {1, 2, 3, 4, 5, 8, 9}

(𝐴 βˆͺ 𝐡)β€² = {6, 7, 10}

𝑛((𝐴 βˆͺ 𝐡)β€²) = 3

ii) 𝐢′ = {1, 2, 3, 9, 10}

𝐴 ∩ 𝐡 ∩ 𝐢′ = {1, 2}

𝑛(𝐴 ∩ 𝐡 ∩ 𝐢′) = 2

b. πœ‰ = {π‘Ž, 𝑏, 𝑐, 𝑑, 𝑒, 𝑓, 𝑔, β„Ž, 𝑖}

𝐴 = {π‘Ž, 𝑏, 𝑐, 𝑓, 𝑔}

𝐡 = {𝑑, 𝑒, 𝑓, 𝑔} 𝐢 = {π‘Ž}

i) 𝐴 ∩ 𝐢 βˆͺ 𝐡 = {π‘Ž, 𝑑, 𝑒, 𝑓, 𝑔}

𝑛(𝐴 ∩ 𝐢 βˆͺ 𝐡) = 5

ii) 𝐴′ βˆͺ 𝐡 = {𝑑, 𝑒, 𝑓, 𝑔, β„Ž, 𝑖}

𝑛(𝐴′ βˆͺ 𝐡) = 6

5. 𝑛(πœ‰) = 6 + 3 + 2 + 1 + 5 + 7 = πŸπŸ’

𝑛(𝑀) = 6 + 3 + 2 + 1 = 𝟏𝟐

𝑛(𝑁) = 3 + 2 = πŸ“

𝑛(𝑃) = 1 + 2 + 5 = πŸ–

a. 𝑛(𝑁 βˆͺ 𝑃) = 3 + 2 + 1 + 5 = 𝟏𝟏

b. 𝑛(𝑀 ∩ 𝑃) = 1 + 2 = πŸ‘

c. 𝑛(𝑁 βˆͺ 𝑃)β€² = 𝑛(πœ‰) βˆ’ 𝑛(𝑁 βˆͺ 𝑃) = 24 βˆ’ 11 = πŸπŸ‘

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ANSWER / JAWAPAN

CHAPTER 03 – SETS (MATHEMATICS FORM 4)

BAB 03 – SETS (MATEMATIK TINGKATAN 4)

Β© HAK CIPTA TERPELIHARA MAY 2013

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8

EXERCISE 2

1. πœ‰ = {π‘₯: 20 ≀ π‘₯ ≀ 35, π‘₯ π‘Žπ‘Ÿπ‘’ π‘–π‘›π‘‘π‘’π‘”π‘’π‘Ÿπ‘ }

𝐴 = {20, 25, 30, 35}

𝐡 = {20, 30}

𝐢 = {23, 24, 25, 26, 27, 28, 29, 34, 35}

(a) 𝐡 = {20, 30}

𝐢 = {23, 24, 25, 26, 27, 28, 29, 34, 35}

(b) 𝐴 βˆͺ 𝐡 = {20, 25, 30, 35}

𝑛(𝐴 βˆͺ 𝐡) = 4

(c) 𝐴 ∩ 𝐢 = {25, 35}

𝑛(𝐴 ∩ 𝐢) = 2

2. ΞΎ = 𝑅 βˆͺ 𝑆 βˆͺ 𝑇

𝑅 = {2, 4}

𝑆 = {1, 2, 3, 4, 5, 6} 𝑇 = {0, 2, 3, 4, 5, 6, 7, 8, 12}

a. _

b. 𝑆 ∩ 𝑇 = {2, 3, 4, 5, 6}

c. 𝑅′ ∩ 𝑇 = {0, 3, 5, 6, 7, 8, 12}

𝑛(𝑅′ ∩ 𝑇) = 7

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ANSWER / JAWAPAN

CHAPTER 03 – SETS (MATHEMATICS FORM 4)

BAB 03 – SETS (MATEMATIK TINGKATAN 4)

Β© HAK CIPTA TERPELIHARA MAY 2013

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9

3. _

(a) 𝑃 ∩ 𝑄

(b) 𝑃′ ∩ 𝑄 ∩ 𝑅

4. πœ‰ = {π‘₯: 20 ≀ π‘₯ ≀ 32}

𝑃 = {21, 24, 27, 30}

𝑄 = {20, 25}

𝑅 = {23, 32}

(a) Set 𝑃 = {21, 24, 27, 30}

(b) Set 𝑄 = {20, 25}

(c) 𝑛(𝑄 ∩ 𝑅′) = 𝑛(20, 25} = 2

5. _

(a) 𝑃′ ∩ 𝑄 ∩ 𝑅′

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ANSWER / JAWAPAN

CHAPTER 03 – SETS (MATHEMATICS FORM 4)

BAB 03 – SETS (MATEMATIK TINGKATAN 4)

Β© HAK CIPTA TERPELIHARA MAY 2013

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10

(b) 𝑃 βˆͺ 𝑄′ βˆͺ 𝑅

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ANSWER / JAWAPAN

CHAPTER 03 – SETS (MATHEMATICS FORM 4)

BAB 03 – SETS (MATEMATIK TINGKATAN 4)

Β© HAK CIPTA TERPELIHARA MAY 2013

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11

Diagnostic Test

1. _

(a) 𝑃 ∩ 𝑄′

(b) (𝑃 ∩ 𝑄′) βˆͺ 𝑅

2. _

(a) (𝐽 βˆͺ 𝐾) ∩ 𝐿

(b) 𝐽 ∩ (𝐾′ ∩ 𝐿)

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ANSWER / JAWAPAN

CHAPTER 03 – SETS (MATHEMATICS FORM 4)

BAB 03 – SETS (MATEMATIK TINGKATAN 4)

Β© HAK CIPTA TERPELIHARA MAY 2013

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12

3. _

(a) 𝑃 ∩ 𝑆′

(b) (𝑃 ∩ 𝑅)β€² ∩ 𝑆

4. _

(a) 𝐴 βˆͺ 𝐡

(b) 𝐢 ∩ 𝐡′

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ANSWER / JAWAPAN

CHAPTER 03 – SETS (MATHEMATICS FORM 4)

BAB 03 – SETS (MATEMATIK TINGKATAN 4)

Β© HAK CIPTA TERPELIHARA MAY 2013

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13

(c) (𝐡 βˆͺ 𝐢)β€² ∩ 𝐴

5. .


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