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ANSWER / JAWAPAN
CHAPTER 03 β SETS (MATHEMATICS FORM 4)
BAB 03 β SETS (MATEMATIK TINGKATAN 4)
Β© HAK CIPTA TERPELIHARA MAY 2013
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Latihan Matematik Tingkatan 4
Exercise Mathemtics Form 4
Bab 03 β SETS
Chapter 03 β SETS
JAWAPAN / ANSWER
Question: http://goo.gl/Ny39Z
EXERCISE 2
1. {4}
2. (π΄ βͺ π΅) β© πΆ
3. π΄ = {1, 2, 3, 4, 6, 12}
π΅ = {4, 8, 12}
π΄ βͺ π΅ = {1, 2, 3, 4, 6, 8, 12}
4. π΄ = {14, 16, 18, 20, 22, 24, 26}
π΅ = {16, 25}
π΄ βͺ π΅ = {14, 16, 18, 20, 22, 24, 25, 26} (π΄ βͺ π΅)β² = {15, 17, 19, 21, 23, 27}
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ANSWER / JAWAPAN
CHAPTER 03 β SETS (MATHEMATICS FORM 4)
BAB 03 β SETS (MATEMATIK TINGKATAN 4)
Β© HAK CIPTA TERPELIHARA MAY 2013
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5. (π΄ βͺ π΅ βͺ πΆ)
6. π = {6, 12}
π = {5, 7, 9, 11, 13}
π βͺ π = {4, 6, 8, 10, 12, 14} π β π
π π, π = {4, 6, 8, 10, 12, 14}
πβ² β© π = {4, 8, 10, 14}
7. πΉ = {4, 10}
πΊ = {2, 5, 7}
πΉ βͺ πΊ = {2, 4, 5, 7, 10} (πΉ βͺ πΊ)β² = {3, 6, 8, 9}
8. π΄β² β© (π΅ βͺ πΆ)
9. π = {6, 8, 10, 12, 14}
π = {5, 7, 11, 13} π βͺ π = {5, 6, 7, 8, 10, 11, 12, 13, 14}
10. π΄β² β© π΅
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ANSWER / JAWAPAN
CHAPTER 03 β SETS (MATHEMATICS FORM 4)
BAB 03 β SETS (MATEMATIK TINGKATAN 4)
Β© HAK CIPTA TERPELIHARA MAY 2013
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3
DIAGNOSTIC TEST
1. π = {1 , 2, 2, 3, 4, 5, 6, 7}
π = {1, 2, 2, 4, 6}
π = {2, 3, 5, 6, 7}
π = {5, 7}
πβ² βͺ π β² β© π = {2, 3, 6, 7}π«
2. πͺ
3. A/D
4. πΏ = {1, 3, 5, 9}
π = {1, 4, 9}
π = {3, 6, 9}
πΏ βͺ π β© πβ² = {1, 4, 5} πͺ = π πππππ
5. π β© π = {πΌπ}
π = {πΌ, πΌπΌ}
π βͺ (π β© π) = {πΌ, πΌπΌ, πΌπ} π©
6. [Cancel Question]
7. C
8. πΈ = {1, 4, 9, 16}
πΉ = {4, 8, 12, 16}
πΈ β© πΉβ² = {1, 9}π©
9. π΄ = 30 + 50 + 20 + 40 = 140
π΅ = π΄ + 40
= 140 + 40
= 180
180 = 50 + 20 + 30 + π
= 100 + π
π = 180 β 100
= 80
30 + 50 + 20 + 40 + 30 + π + π = 300
170 + 80 + π = 300
π = 50 πͺ
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ANSWER / JAWAPAN
CHAPTER 03 β SETS (MATHEMATICS FORM 4)
BAB 03 β SETS (MATEMATIK TINGKATAN 4)
Β© HAK CIPTA TERPELIHARA MAY 2013
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4
10. 4 + π₯ + 5 + 1 + 2π₯ + 3 + 6 = 40
19 + 3π₯ = 40
3π₯ = 21
π₯ = 7 π«
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ANSWER / JAWAPAN
CHAPTER 03 β SETS (MATHEMATICS FORM 4)
BAB 03 β SETS (MATEMATIK TINGKATAN 4)
Β© HAK CIPTA TERPELIHARA MAY 2013
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5
EXERCISE 1 (Paper 2)
1. setΞΎ = Aβͺ B βͺC
(a) π΄ βͺ π΅
(b) π΅β² β© πΆ
2. π = π βͺ π βͺ π
(a) π β© π βͺ π β²
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ANSWER / JAWAPAN
CHAPTER 03 β SETS (MATHEMATICS FORM 4)
BAB 03 β SETS (MATEMATIK TINGKATAN 4)
Β© HAK CIPTA TERPELIHARA MAY 2013
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(b) π βͺ π β© π β²
3. ΞΎ = E βͺ F βͺG
(a) πΉβ² β© πΊ
(b) (πΉ βͺ πΊ)β² β© πΈ
(c) πΉ βͺ (πΈ β© πΊβ²)
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ANSWER / JAWAPAN
CHAPTER 03 β SETS (MATHEMATICS FORM 4)
BAB 03 β SETS (MATEMATIK TINGKATAN 4)
Β© HAK CIPTA TERPELIHARA MAY 2013
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7
4. _
a. π = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
π΄ = {1, 2, 4, 8, 9}
π΅ = {1, 2, 3, 4, 5}
πΆ = {4, 5,6, 7, 8}
i) π΄ βͺ π΅ = {1, 2, 3, 4, 5, 8, 9}
(π΄ βͺ π΅)β² = {6, 7, 10}
π((π΄ βͺ π΅)β²) = 3
ii) πΆβ² = {1, 2, 3, 9, 10}
π΄ β© π΅ β© πΆβ² = {1, 2}
π(π΄ β© π΅ β© πΆβ²) = 2
b. π = {π, π, π, π, π, π, π, β, π}
π΄ = {π, π, π, π, π}
π΅ = {π, π, π, π} πΆ = {π}
i) π΄ β© πΆ βͺ π΅ = {π, π, π, π, π}
π(π΄ β© πΆ βͺ π΅) = 5
ii) π΄β² βͺ π΅ = {π, π, π, π, β, π}
π(π΄β² βͺ π΅) = 6
5. π(π) = 6 + 3 + 2 + 1 + 5 + 7 = ππ
π(π) = 6 + 3 + 2 + 1 = ππ
π(π) = 3 + 2 = π
π(π) = 1 + 2 + 5 = π
a. π(π βͺ π) = 3 + 2 + 1 + 5 = ππ
b. π(π β© π) = 1 + 2 = π
c. π(π βͺ π)β² = π(π) β π(π βͺ π) = 24 β 11 = ππ
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ANSWER / JAWAPAN
CHAPTER 03 β SETS (MATHEMATICS FORM 4)
BAB 03 β SETS (MATEMATIK TINGKATAN 4)
Β© HAK CIPTA TERPELIHARA MAY 2013
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EXERCISE 2
1. π = {π₯: 20 β€ π₯ β€ 35, π₯ πππ πππ‘πππππ }
π΄ = {20, 25, 30, 35}
π΅ = {20, 30}
πΆ = {23, 24, 25, 26, 27, 28, 29, 34, 35}
(a) π΅ = {20, 30}
πΆ = {23, 24, 25, 26, 27, 28, 29, 34, 35}
(b) π΄ βͺ π΅ = {20, 25, 30, 35}
π(π΄ βͺ π΅) = 4
(c) π΄ β© πΆ = {25, 35}
π(π΄ β© πΆ) = 2
2. ΞΎ = π βͺ π βͺ π
π = {2, 4}
π = {1, 2, 3, 4, 5, 6} π = {0, 2, 3, 4, 5, 6, 7, 8, 12}
a. _
b. π β© π = {2, 3, 4, 5, 6}
c. π β² β© π = {0, 3, 5, 6, 7, 8, 12}
π(π β² β© π) = 7
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ANSWER / JAWAPAN
CHAPTER 03 β SETS (MATHEMATICS FORM 4)
BAB 03 β SETS (MATEMATIK TINGKATAN 4)
Β© HAK CIPTA TERPELIHARA MAY 2013
https://tutormansor.wordpress.com/
9
3. _
(a) π β© π
(b) πβ² β© π β© π
4. π = {π₯: 20 β€ π₯ β€ 32}
π = {21, 24, 27, 30}
π = {20, 25}
π = {23, 32}
(a) Set π = {21, 24, 27, 30}
(b) Set π = {20, 25}
(c) π(π β© π β²) = π(20, 25} = 2
5. _
(a) πβ² β© π β© π β²
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ANSWER / JAWAPAN
CHAPTER 03 β SETS (MATHEMATICS FORM 4)
BAB 03 β SETS (MATEMATIK TINGKATAN 4)
Β© HAK CIPTA TERPELIHARA MAY 2013
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10
(b) π βͺ πβ² βͺ π
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ANSWER / JAWAPAN
CHAPTER 03 β SETS (MATHEMATICS FORM 4)
BAB 03 β SETS (MATEMATIK TINGKATAN 4)
Β© HAK CIPTA TERPELIHARA MAY 2013
https://tutormansor.wordpress.com/
11
Diagnostic Test
1. _
(a) π β© πβ²
(b) (π β© πβ²) βͺ π
2. _
(a) (π½ βͺ πΎ) β© πΏ
(b) π½ β© (πΎβ² β© πΏ)
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ANSWER / JAWAPAN
CHAPTER 03 β SETS (MATHEMATICS FORM 4)
BAB 03 β SETS (MATEMATIK TINGKATAN 4)
Β© HAK CIPTA TERPELIHARA MAY 2013
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12
3. _
(a) π β© πβ²
(b) (π β© π )β² β© π
4. _
(a) π΄ βͺ π΅
(b) πΆ β© π΅β²
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ANSWER / JAWAPAN
CHAPTER 03 β SETS (MATHEMATICS FORM 4)
BAB 03 β SETS (MATEMATIK TINGKATAN 4)
Β© HAK CIPTA TERPELIHARA MAY 2013
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(c) (π΅ βͺ πΆ)β² β© π΄
5. .