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    Transmission Lines and E. M. Waves

    Prof. R. K. Shevgaonkar

    Department of Electrical Engineering

    Indian Institute of Technology, Bombay

    Lecture 45Radiation for the Hertz Dipole

    In the last lecture we derived the magnetic vector potential for the hertz dipole. We saw

    hertz dipole is the basic unit on which we can develop and we can find out the fields for

    more complex current distribution. So the analysis of hertz dipole is very important

    because once we understand the fields developed by the hertz dipole we can always find

    the electric and magnetic fields generated by any other current distribution.

    So we had got this hertz dipole which is nothing but a small current element and from

    there we got the magnetic vector potential. we considered a coordinate system where the

    hertz dipole is oriented in the z direction and from there we found that the magnetic

    vector potential at any point in the space will be oriented in the same direction as the

    current element that everywhere in the space we will have the magnetic vector potential

    which will be oriented in z direction.

    (Refer Slide Time: 2:50)

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    So the magnetic vector potential at a distance r from the origin essentially is given by this

    which we wrote explicitly as the z component which was essentially given by that.

    (Refer Slide Time: 3:06)

    Now, since we are talking about the spherical coordinate system (Refer Slide Time: 3:14)

    and we are going to investigate now the fields in the spherical coordinate system,

    essentially we have to convert this A z component in the appropriate spherical

    components that is the r component and the theta component. So note here this is the

    radius vector, this is the direction which is theta direction; the radially outward direction

    this direction is the r direction (Refer Slide Time: 3:42) and phi direction is perpendicular

    to the plane of the paper which is going this way. So this vector potential does not have

    any component in this direction perpendicular to the plane of the paper that is 90 degrees

    with respect to this so the vector potential in the spherical coordinate system would have

    two components: the r component and the theta component. So since this angle is theta

    this angle is also theta so this component will be A z cos of theta, this component will be

    negative of A z sine of theta so you will have theta component which is minus A z sine

    theta and r component which is A z cos theta. So from here we get now the component

    from the spherical coordinate system.

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    So I have from here A r is equal to A z cos of theta; A theta which will be minus A z sine

    of theta and A phi in this case is equal to 0 where A z is essentially this quantity; so if

    you put the whole thing together that is this quantity A z.

    (Refer Slide Time: 5:13)

    Now, once we have the knowledge of the vector potential then we can go now to the

    definition of the vector potential and from there we can find out the magnetic field. We

    can use mu times h which is b is equal to del cross of A or the magnetic field h is 1 upon

    mu del cross A.

    So once I know these components of the vector potential A r A theta A phi then I can

    substitute into this and I can get the magnetic field.

    Write in this curl explicitly. This is equal to 1 upon mu and I can write the curl in the

    spherical coordinate system which is 1 upon r square sine theta determinant r r theta r

    sine theta unit vector phi d by dr d by d theta d by d phi A r r A theta r sine theta A phi.

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    (Refer Slide Time: 7:06)

    Now, since the current element which we have got here (Refer Slide Time: 7:12) is

    symmetric in the phi direction because it appears same no matter from which direction

    we see; only when we see in different direction in theta the element will appear

    differently. See if i see from this direction in theta it will look like a line, then I see from

    the top it will look like a point and so on. So we have a theta dependence for these

    currents but there is no phi dependence because it appears symmetric from all directions.

    As a result this quantity d by d phi is identically equal to 0 in this case and we also have

    seen that the phi component of the magnetic field vector potential is also 0.

    So substituting now into this we get the magnetic field h that is equal to 1 upon mu r

    square sine theta determinant r r theta r sine theta phi d by dr d by d theta d by d phi is 0

    then the r component A r which is A z cos theta so this is A z cos theta, the theta

    component is minus A z sine theta so this is minus A z sine theta and the phi component

    is 0 you get this is 0.

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    (Refer Slide Time: 9:08)

    So the vector magnetic field essentially is given by the determinant which is this. Now it

    is immediately clear that since these two elements are 0 here the r component and the

    theta component are identically 0. The only component which you will get will be

    corresponding to the phi component which will be d by dr of this quantity minus d by d

    theta of this quantity (Refer Slide Time: 9:33).

    So essentially what we get from here we get H r is equal to 0 H theta is also equal to 0

    and H phi equal to 1 upon mu r d by dr of minus A z sine theta minus d by d theta of A z

    cos theta; from here (Refer Slide Time: 10:27) d by dr of minus A z sine theta minus d by

    d theta of A z cos theta; so this is the phi component of the magnetic field.

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    (Refer Slide Time: 12:18)

    Once we get the magnetic field then we can go to the Maxwell's equation and now we

    want to find out the electric field not at a location of the source but somewhere in the

    space where there are no charges or no sources so essentially we can substitute the

    magnetic field in the source free Maxwell's equation and then find out what is the electric

    field.

    So we can take this magnetic field now and substitute into a source free Maxwell's

    equation which is del cross H that is equal to j omega epsilon times e. And since I know h

    i can find out E so the electric field now at the observation point that will be equal to 1

    upon j omega epsilon del cross H.

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    (Refer Slide Time: 13:12)

    Again I can use the determinant in spherical coordinates. So this quantity will be 1 upon j

    omega epsilon, 1 upon r square sine theta r r theta r sine theta phi d by dr d by d theta d

    by d phi which is 0 because we have seen earlier that there is a symmetry in phi so this

    quantity will be 0 and now we do not have a component which is H r component for the

    magnetic field, there is no theta component for the magnetic field, the component which

    we have is only phi so H r is 0 H theta is 0 so I can substitute this quantity is 0 first (Refer

    Slide Time: 14:33) this is 0 this is 0 and this is phi.

    Now again simplifying and taking out the components so the r component essentially will

    be d by d theta of H phi and this quantity theta component will correspond to the

    derivative of this quantity d by dr of H phi. So now just taking this derivative and

    separate out you get the component E r that will be equal to I 0 d cos of theta e to the

    power j omega t minus j beta r upon 4pi omega epsilon beta upon r square minus j upon r

    cube; and theta component E theta will be equal to I 0 d sine theta e to the power j

    omega t minus j beta r upon 4pi epsilon j beta square upon omega r plus beta upon omega

    r square minus j upon omega r cube and the phi component of the electric field is

    identically zero in this case.

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    (Refer Slide Time: 17:14)

    So now note here (Refer Slide Time: 17:20) the magnetic field or the hertz dipole will be

    going around z axis which is like that but for the electric field we have two components:

    one is the r component which is like that and other one is the component which is in theta

    direction which is like this. So depending upon the location this electric field direction

    will be changing, the magnetic field direction will change only in this plane which is

    parallel to this xy plane because we have only the phi component.

    Now up till now the derivation is very straightforward. Essentially what we did we took

    the magnetic vector potential substituted into the Maxwell's equation, found the magnetic

    field, once we have a knowledge of the magnetic field we again substituted it into the

    Maxwell's equation and we got the electric field.

    Now we try to look at these terms which we have got various terms into the electric and

    magnetic fields.

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    (Refer Slide Time: 18:20)

    So if I look in general the field expression the H phi and these two components E r and E

    theta I noticed there are three types of field which are generated by the hertz dipole

    depending upon the variation of the field as a function of distance. One variation is 1 over

    r and the other variation is 1 over r square and the third variation is 1 over r cube; same is

    for magnetic field, we do not have 1 over r cube term but I have 1 over r square and I

    have a term which is 1 over r (Refer Slide Time: 20:04).

    We know that from the Amperes law that if I have a current then it produces the

    magnetic field and the magnetic field has a variation from from a current that varies as 1

    over r square. So I know this term which is varying at 1 over r square is same as what we

    used to get from the simple Amperes law. This phenomenon was the induction

    phenomena. So if we had a current it would produce a magnetic field surround it and that

    magnetic field had a variation which was 1 over r square so this term which varies as 1

    over r square we call as the induction current. So we have these fields, we denote them as

    induction term because it was the magnetic induction I had when the current was flowing

    in the wire (Refer Slide Time: 20:02).

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    beta square is nothing but omega square mu epsilon that is what we have seen earlier. So

    this quantity whatever we have that varies as omega square mu epsilon upon omega r so

    this field 1 over r that varies as omega mu epsilon upon r. That means this term which is

    varying as 1 over r it is proportional to frequency. So this quantity 1 over r term this is

    proportional to omega.

    (Refer Slide Time: 23:09)

    If I look at this term here which is beta upon omega r square, since beta is proportional to

    omega this term is independent of omega and this term is inversely proportional to

    omega. So this field induction field is independent of omega and this field electrostatic

    field whatever we are calling which is varying as 1 over r cube this is inversely

    proportional to omega 1 upon omega.

    So, as we go to the lower frequencies this is the term which is going to dominate. This

    term is independent of frequency so it is always present and this phenomena is essentially

    a higher frequency phenomena. So what that means is that this field whatever is the

    radiation field (Refer Slide Time: 24:12) is a higher frequency phenomena essentially and

    that is what is the radiation that when we go to the extremely low frequency there is no

    radiation but as I go to higher and higher frequency for the same current the I 0 into d

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    we will have now this term dominating more and more as the frequency increases that

    means for the same current amplitude if the frequency is increased the dominance of this

    field increases. So radiation becomes stronger and stronger for the same current as the

    frequency increases and that we understand from our basic arguments which we have put

    for the radiation that: as the frequency increases the rate of change of current increases

    that means the charges get accelerated decelerated in more way and because of that we

    have more radiation field so this relation that the radiation field is proportional to omega

    agrees with what basic understanding we had put forward for getting a radiation from the

    current. This variation also is okay because this is the field which is even generated by

    the dc current so its independency for omega is also understandable.

    (Refer Slide Time: 25:34)

    What is the origin of this field which is varying as 1 upon omega; that means this field is

    going to be more dominant as we go to the lower and lower frequency. As the term we

    are calling it here the electrostatic field that means this must be related to some kind of

    charges which are there. But we have not put any charges anywhere in our analysis, we

    simply assume there is a current I which is flowing into this current element and then we

    investigated the fields which are induced because of this small current element.

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    However, if you look at very carefully now one can ask a question this is my current so

    element, let me enlarge it little bit, current is flowing into this current element but where

    does the current go; the current flows into this so one half cycle the current will be

    flowing upwards, in the other half cycle the current will be flowing downwards and there

    is no closed path now for this because these things are closed by the fields. So essentially

    when the current is flowing in this direction (Refer Slide Time: 26:44) the electrons are

    moving downwards, positive charges effectively are going upwards. So when the current

    goes upwards there is accumulation of charge on these two points on the two ends of the

    current element. So when the current flows this way the positive charges are moving here

    and the negative charges will be moving in this direction. So in one half cycle the

    positive charges will get accumulated at this end and the negative charges will get

    accumulated in this end. In the next half cycle when the current reverses direction the

    negative charges will get accumulated here and the positive charge will get accumulated

    here (Refer Slide Time: 27:30).

    (Refer Slide Time: 27:33)

    So essentially this current flow which we are talking about which is time varying is

    equivalent to having time varying charges which are accumulated at the two ends of this

    this current element which is saying that I am having an electric dipole whose charges are

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    changing as a function of time and they essentially give you this current in this element

    so essentially you are having a dumbbell of charges equal and opposite charges which are

    located at the two ends of this current dipole. So as the current is oscillating positive and

    negative this dumbbell essentially is oscillating so it is positive, next half cycle will be

    negative and so on. So essentially we are having an oscillating dumbbell which is

    equivalent to the current flow which we have here.

    So though we did not say explicitly when we started with this current in this small current

    element that there are charges in this system, we simply started with a current flow in the

    small current element these charges will get accumulated at the ends of the hertz dipole

    and then they will produce their field which will be electrostatic field. So if I consider

    this electric dumbbell and now find out what is the the field produced because of these

    charges I can find out some observation point is very close so let us say I take some point

    here, some point here, I put some plus positive charge so I will get field which is like this

    the field will be like this, so resultant field will be always the vector some of these two

    fields which is produced because of these two charges.

    (Refer Slide Time: 29:27)

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    One can show that this field now varies as 1 over r cube where r is the distance from the

    center of this dipole. So this term which we are getting here 1 over r cube term is

    essentially electrostatic because this field is produced by the dumbbell of this electric

    charges which are separated by a distance d. So if I just without getting into the time

    varying thing if I consider two equal and opposite charges separated by distance dand

    find the field produced by these charges then I will get the resultant field which will vary

    as 1 over r cube and that is what is the field which we have got here.

    (Refer Slide Time: 30:26)

    Why this field (Refer Slide Time: 30:30) then varies as 1 over frequency because this

    frequency becomes smaller and smaller, for the same current more and more charges get

    accumulated here because the charge essentially is integral of the current over time. So if

    I have a time period which is very large for the same current amplitude I will be

    accumulating charges over the time period and as the time period increases I will get

    more accumulation of the charge. So, as the frequency becomes smaller and smaller the

    amplitude or the the amount of charge which will get accumulated on the ends of the

    hertz dipole will go on increasing and one can see that when if we go to frequency which

    is dc the current will be always flowing upwards and then if I take as a steady-state in

    finite time these charges will go to go to infinity.

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    So, as the frequency goes to zero this field essentially will go to infinity because in a

    steady-state it will be the infinite charges which will be resting on the two ends of this

    dipole. So this nature that the field which we have got here is because of a charge which

    is now the collection of the charges which are due to the current should vary inversely as

    a function of frequency because lower the frequency that means more accumulation of

    the charges and higher will be the field because of these electrostatic charges. So this

    field therefore then we call electrostatic field, (Refer Slide Time: 32:14) with this field

    we call the induction field and why there is no 1 over r cube variation for the induction

    field because there is no magnetic charge accumulation. So we get a variation which is 1

    over r square which is same as the induction field and we get a field which is 1 over r

    which is the one which is radiation which should contribute to the power flow; that we

    will see a little later.

    So this field (Refer Slide Time: 32:39) is the new field which the magnetic field has,

    there is no equivalent of 1 over r cube term here because there is no accumulation of the

    magnetic charges. For the electric field we have accumulation of electric charges and

    because of that we get a field which will be electrostatic field and that will vary as 1 over

    omega. So these there fields now: the radiation field, the induction field and the

    electrostatic field will be generated by the simple dipole hertz dipole. Our interest,

    however, is only in this field (Refer Slide Time: 33:17) because we are investigating now

    only the radiation field. So we will try to only take that component of that field which

    will be varying as a function of omega.

    So what we conclude from this analysis is that you take any time varying current the time

    varying current is going to generate three types of fields; one which will vary as 1 over r

    and this field will be linearly proportional to the frequency, the other field which will be

    varying as 1 over r square this field is independent of frequency and third one is the

    electrostatic field which will vary as 1 over r cube and this field will vary as inversely

    proportional to the frequency.

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    Interestingly one can see from the expression for these fields that all these three terms

    become equal so I can take the magnitude of this term and make it equal to this; for the

    same distance even this term will become equal to this so if I take a distance from the

    current element where these terms will become equal so I get a distance beta square upon

    omega r equal to beta upon omega r square one beta will cancel, omega will cancel, r will

    cancel so from here I get r is equal to 1 upon beta which is nothing but 1 upon 2pi upon

    lambda so this is lambda upon 2pi.

    (Refer Slide Time: 35:17)

    Taking approximately pi 3.14 so this I am taking approximately this quantity as 6 we say

    that approximately at r equal to lambda by 6 these three terms will become equal in

    magnitude wise. So we have... if I go from the hertz dipole a distance lambda by 6

    approximately then the radiation field, the induction field and the electrostatic field

    would be equal and as I go less than lambda by 6 this term will increase, this will

    increase further and as I go beyond lambda by 6 this term would have died down rapidly

    and the only term which will survive will be this term (Refer Slide Time: 36:06).

    So if I plot this now as a function of distance to different fields so this is e magnitude and

    plotting as a function of distance I will have three types of fields: one is the electrostatic

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    field which will be like this, so other will be the induction field will be like that and the

    third will be the radiation field which will be like this and this is the loop point which is

    lambda by 6 approximately or lambda by 2pi to be precise where these three fields are

    going to be equal so this is 1 over r, this is 1 over r square and this is 1 over r cube.

    (Refer Slide Time: 37:03)

    As we see as we go to lower and lower frequencies this is the term which will dominate.

    So if I go very close to the hertz dipole essentially the influence will be only the

    electrostatic field. If I am somewhere in between then I will get the induction field and if

    I go very far away from the dipole very far away means much much larger compared to

    lambda by 6 then practically the radiation fields will be present in the in the medium.

    So now this distance lambda by 6 is now the reference point and on the basis of this

    distance with respect to this I can now divide the field into two categories. So if I go to a

    zone which is very short compared to lambda by 6 I call those fields as the near fields and

    those fields will be essentially dominated by the induction and the electrostatic field

    whereas if I go to a distance which is much larger compared to lambda by 6 then the field

    which will be dominated will be only radiation field and I call that field as the far field.

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    So now depending upon the distance I now classify the fields. So we say near field, this

    for r much much less than lambda by 6 and then we have fields which are called the far

    fields which will correspond to r r much much greater than lambda by 6.

    Ideally if you want only 1 over r term which is the radiation field then we should go to a

    distance almost tending to infinity where 1 over r square and 1 over r cube field would

    have died down with a substantially low value and I will get a field which is only 1 over r

    which is the radiation field.

    (Refer Slide Time: 39:29)

    So basically we see now something interesting and that is if I go now very close towards

    to the hertz dipole we have a term which is 1 over r square and 1 over r cube so I will

    have a component which is this component e theta (Refer Slide Time: 39:51), I will have

    component which is E r because it has the r square 1 over r square and 1 over r cube, the

    magnetic field will have a term which is 1 over r square but if I go to the zone which is

    far field zone where r is much much greater than lambda by 6 then these fields are

    negligibly small so I will get only radiation field. There is no radiation field component

    corresponding to E r so this will be negligibly small so this will be taken as zero and we

    will have a theta component which will be given by that.

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    (Refer Slide Time: 40:28)

    So what we see in near field you will have a component E r, E theta and H phi all three

    components will be present whereas when I go for the far field the E r component is

    negligibly small and we will have only two components which is E theta and H phi. Since

    we are interested here only in the radiation field we can take appropriately only those

    terms which are having 1 over r variation. So I can take this quantity is zero now, this is

    the term (Refer Slide Time: 41:17) which gives me radiation field so I can write down

    only for far field that is what our interest is; we get the component E theta which is j I 0

    dbeta square sine theta e to the power j omega t minus j beta r upon 4pi omega epsilon r

    and we get H phi that will be equal to j I 0 dsine theta beta e to the power j omega t

    minus j beta r upon 4pi r.

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    (Refer Slide Time: 42:41)

    So, for the far field we have only these two components. Again few things can be noted

    here. Firstly, both the fields have a variation as a function of angle theta the sine theta.

    That means the fields are zero at theta equal to 0 and fields are maximum at theta equal to

    90 degrees. So that means both the fields are maximum in this direction when theta equal

    to 90 degrees and along the length of this hertz dipole that means along the axis of the

    dipole these two fields are identically zero; one of the ratio.

    That means the fields are not uniformly created in the space, they have a directional

    dependent. You have maximum field when we go perpendicular to the hertz dipole and

    along the hertz dipole the fields this far fields are identically zero. Second thing what we

    note from here is if I take a ratio of these two quantities or before that the electric and

    magnetic fields have this term j with respect to this current I 0 e to the power j omega t

    that means the field which are now generated what we call as the far field or radiation

    field they are 90 degrees out of phase with respect to the current; and what is the reason

    for that?

    The reason is simple that right from the beginning we said the radiation is a phenomena

    which is related to the rate of change of current. So if we are having a time varying

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    current which is e to the power j omega t the rate of change of current will be equivalent

    to multiplying the quantity by j omega so you have the fields which are 90 degrees out of

    face with respect to the current so this j which you get here in this field essentially

    supports our basic argument which we had for the radiation that if we accelerate the

    charges that means if we have a rate of change of current we will get the radiation field

    that is what we see from here.

    The third thing which we note from here is if I take a ratio of this quantity with theta and

    H phi this quantity will cancel, I 0 dwill cancel, sine theta will cancel, r will cancel, 4pi

    will cancel but what we will get we will get beta square here and here we will get beta so

    the ratio of these two quantities if I take E theta and H phi that will be equal to beta upon

    omega epsilon. And I know this beta is nothing but omega square root mu epsilon divided

    by omega epsilon. So this is equal to square root of mu upon epsilon which is nothing but

    the intrinsic impedance of the medium eta.

    (Refer Slide Time: 45:56)

    So note what we have got here. The wave which we have got now or the field which we

    have got is... this represents this spherical wave that means the wave is traveling in the r

    direction that is what we... right from the beginning we got from the solution.

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    We got a component E theta for the electric field and component H phi for the magnetic

    field which is perpendicular to the plane of the paper; and ratio of the electric and

    magnetic field is equal to the intrinsic impedance of the medium. That means these fields

    are having exactly identical properties as we used to have for uniform plane waves that

    the electric field, the magnetic field and the direction of the wave propagation are

    perpendicular to each other that is what we have here the wave propagates in all

    direction, the field is in theta direction electric field and the magnetic field is in phi

    direction so these three are perpendicular to each other and the ratio of the electric and

    magnetic field is equal to the intrinsic impedance of the medium (Refer Slide Time:

    47:03).

    So this wave is spherical wave and it has a transverse nature that the electric and

    magnetic field both are transverse to the direction of the wave propagation. So we have

    got here what is called a transverse spherical electromagnetic wave and it has properties

    all properties of transverse electromagnetic wave like the ratio of the electric and

    magnetic field should be decided by the medium properties which is the intrinsic

    impedance of the medium and the electric field, the magnetic field and the direction of

    the wave propagation should be perpendicular to each other.

    So, though the wave which is created by this is spherical, every point in space if you go

    around this hertz dipole you will see a transverse electromagnetic wave. Though the

    direction of the transverse electromagnetic wave will be varying at different points in

    space but any location if you ask what is that nature of the electromagnetic wave it is a

    transverse electromagnetic wave. So essentially if I take the observation point, draw a

    sphere passing through that point the radially outward direction direction gives me the

    direction of the wave propagation and the tangents which are drawn to the surface at that

    location perpendicular to each other they give you a direction of the electric and the

    magnetic fields.

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    (Refer Slide Time: 48:41)

    We can also see some interesting things from here and that is the electric and the

    transverse nature of the electromagnetic wave is there at every point in space and its

    direction will be changing when you go to different locations but at a given point how the

    electric field is varying as a function of time.

    Let us consider this point here the electric field is having a theta component which will be

    positive or negative. That means at this location the electric field is always oriented in

    this direction as a function of time. That means this wave is a linearly polarized wave.

    The direction of the electric field will change from location to location; here theta

    direction is this, if I go to a point here theta direction will be vertical, if I go here theta

    direction will be like that. So from one location to another location direction of the

    electric field will change but if I ask what is the polarization which is the direction of the

    electric field at a particular location that wave is linearly polarized.

    So now we have got very interesting conclusions and that is if we consider the small

    current element what is called the hertz dipole then it generates variety of fields, it

    generates induction field, it generates electrostatic field, it generates radiation field;

    however, if we take only the radiation fields then these radiation fields satisfy all the

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    properties which the transverse electromagnetic wave has. So it generates the spherical

    wave but the electric and magnetic fields are perpendicular to each other and they are

    also perpendicular to the direction of the wave propagation. Also, the ratio of the electric

    field and magnetic field is equal to the intrinsic impedance of the medium. And the

    polarization which the wave had at any point for the hertz dipole will be always linear

    polarization.

    So the hertz dipole essentially generates an electromagnetic wave which is spherical but

    it is linearly polarized. So on this concept then we will develop more and then we will try

    to investigate more practical antenna systems. We will see how much power is radiated

    by the current element and so on and so on.


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