Overview (MA2730,2812,2815) lecture 20
Lecture slides for MA2730 Analysis I
Simon Shawpeople.brunel.ac.uk/~icsrsss
College of Engineering, Design and Physical Sciencesbicom & Materials and Manufacturing Research InstituteBrunel University
November 20, 2015
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MA2730, Analysis I, 2015-16
Overview (MA2730,2812,2815) lecture 20
Contents of the teaching and assessment blocks
MA2730: Analysis I
Analysis — taming infinity
Maclaurin and Taylor series.
Sequences.
Improper Integrals.
Series.
Convergence.
LATEX2ε assignment in December.
Question(s) in January class test.
Question(s) in end of year exam.
Web Page:http://people.brunel.ac.uk/~icsrsss/teaching/ma2730
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MA2730, Analysis I, 2015-16
Overview (MA2730,2812,2815) lecture 20
Lecture 20
MA2730: topics for Lecture 20
Lecture 20
Power series
Radius of Convergence
The natural domain of a power series function rule
Term-by-term differentiation of Taylor series
Examples and Exercises
Reference: The Handbook, Chapter 7, Section 7.2.Homework: Sheet 6a, Questions 1 and 3Seminar: Ad Hoc. Student driven
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MA2730, Analysis I, 2015-16
Overview (MA2730,2812,2815) lecture 20
Lecture 20
Clarity, Brevity and Accuracy
The Assignment — a comment on page limits
I didn’t have time to write a short letter, so I wrote a long oneinsteadMark Twain
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MA2730, Analysis I, 2015-16
Overview (MA2730,2812,2815) lecture 20
Lecture 20
Reference: Stewart, Chapter 12.
We’ve come a long way.
Improper integrals, Taylor and Maclaurin series. . . .
. . . sequences, series, convergence, limits.
We have seen that Maclaurin series of functions sometimeswork. . .
. . . and sometimes don’t
For example in the interval |x| < 1 we found that,
1
1− x= 1 + x+ x2 + x3 + x4 + · · · (if and only if −1 < x < 1).
Today we study this interval of convergence in more general terms:it is called radius of convergence.
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MA2730, Analysis I, 2015-16
Overview (MA2730,2812,2815) lecture 20
Lecture 20
This is the fundamental concept.
Power Series, Definition 7.6, the Handbook
A power series is a series of the form
∞∑
n=0
cn(x− a)n,
where {cn}∞n=0 is a sequence of real numbers.
The case a 6= 0 reminds us of Taylor series and the case a = 0, ofMaclaurin series.
For clarity, we will often focus mainly on the case a = 0.
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MA2730, Analysis I, 2015-16
Overview (MA2730,2812,2815) lecture 20
Lecture 20
Here it is again.
Power Series, Definition 7.6, the Handbook
A power series is a series of the form
∞∑
n=0
cn(x− a)n,
where {cn}∞n=0 is a sequence of real numbers.
In a power series x plays its usual role of an independent variable.So we can interpret a power series as a function rule.
f(x) =
∞∑
n=0
cn(x− a)n.
Then f : D → R where D is the natural domain for the function.
How could we define D?Shaw bicom, mathematics, CEDPS, IMM, CI, Brunel
MA2730, Analysis I, 2015-16
Overview (MA2730,2812,2815) lecture 20
Lecture 20
The main mathematical notions and tools are in The Handook:
Definition 7.8 — based on the ratio and root tests
Lemma 7.9 — the root and ratio tests are ‘equal’
Theorem 7.10 — the main result
Let’s review these.
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MA2730, Analysis I, 2015-16
Overview (MA2730,2812,2815) lecture 20
Lecture 20
Radius of Convergence. Definition 7.8
Let∞∑
n=0
cn(x− a)n be a power series and let
ρ1 = limn→∞
∣∣∣∣cn+1
cn
∣∣∣∣ and ρ2 = limn→∞
|cn|1/n.
The radius of convergence R of the series is equal to
1 R = 1/ρ2 when 0 < ρ2 < ∞,
2 R = 0 when ρ2 = ∞,
3 R = ∞ when ρ2 = 0.
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MA2730, Analysis I, 2015-16
Overview (MA2730,2812,2815) lecture 20
Lecture 20
Lemma 7.9
In Definition 7.8, when ρ1 and ρ2 exist, they are equal.More precisely: ρ2 = ρ1 whenever ρ1 exists.
Remark
The subtlety is that ρ2 might exist when ρ1 doesn’t.
Outline proof
For a positive sequence, the main observation is that ifan+1/an → L > 0 then, given ǫ > 0, there is an N ∈ N such thatfor n > m > N ,
∣∣∣∣lnan+1
an− lnL
∣∣∣∣ < ǫ =⇒ (n−m) lnL ≈n∑
k=m
lnak+1
ak.
The details are quite technical — PROOF IS NOT EXAMINABLE.
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MA2730, Analysis I, 2015-16
Overview (MA2730,2812,2815) lecture 20
Lecture 20
Pointwise convergence of a power series, Theorem 7.10
Given a power series∞∑
n=0
cn(x− a)n, either:
1 the series converges for all x when R = ∞;
2 the series converges just for x = a when R = 0;
3 the series converges for all x with |x− a| < R.
In the last case we need to check separately what happens at theboundary points where |x− a| = R. These are the points
x = a+R and x = a−R.
Proof
Boardwork (use the Cauchy root test).
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MA2730, Analysis I, 2015-16
Overview (MA2730,2812,2815) lecture 20
Lecture 20
Example 1
Determine the radius of convergence, R, for the power series
f(x) =
∞∑
n=1
(x− 1)n
n 2n
and investigate its behaviour at the boundary |x− a| = R.
Solution: Boardwork
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MA2730, Analysis I, 2015-16
Overview (MA2730,2812,2815) lecture 20
Lecture 20
It is important to check the boundary convergence behaviourseparately because anything can happen!From Subsection 7.2.1 of The Handbook we have the followinggeneral set up. Suppose that
f(x) =
∞∑
n=0
cn(x− a)n
has radius of convergence R < ∞. Then the series converges ifa−R < x < a+R and the boundary points x = a−R andx = a+R have to investigated separately.
xaa−R a+R
RR
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MA2730, Analysis I, 2015-16
Overview (MA2730,2812,2815) lecture 20
Lecture 20
We have the following general set up. The power series
f(x) =∞∑
n=0
cn(x− a)n
has radius of convergence R < ∞ and so converges in |x− a| < R.
At the left boundary point, x = a−R:
f(x) =
∞∑
n=1
cn(−R)n.
At the right boundary point, x = a+R:
f(x) =∞∑
n=1
cnRn.
We can expect the theory of alternating series to be important.Shaw bicom, mathematics, CEDPS, IMM, CI, Brunel
MA2730, Analysis I, 2015-16
Overview (MA2730,2812,2815) lecture 20
Lecture 20
Example 2
Find the natural domain of the function rule given by the powerseries
f(x) =∞∑
n=0
cn(x− a)n for cn =1
np2nand a = 1.
Boardwork
Determine R using the ratio test.
Put x = 1−R into the power series: is it convergent?
Put x = 1 +R into the power series: is it convergent?
Hence the natural domain is . . . ?
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MA2730, Analysis I, 2015-16
Overview (MA2730,2812,2815) lecture 20
Lecture 20
The main point
We have seen that provided we remain inside the radius ofconvergence and pay careful attention to the behaviour on theboundary, a power series defines a function, f : D → R.
Several questions naturally arise.
Can we add, subtract, multiply such power series?
If we differentiate the power series do we get f ′(x)?
Can we integrate the power series and get∫f(x) dx?
The answer is yes — if we remain inside the natural domain of f .
Addition, subtraction and multiplication work in the usual way. Wewill look at differentiation From Subsection 7.2.2 of TheHandbook.
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MA2730, Analysis I, 2015-16
Overview (MA2730,2812,2815) lecture 20
Lecture 20
Lemma 7.11, Subsection 7.2.2 in The Handbook
Let f, g : I → R be an infinitely differentiable functions with Taylor seriesT a∞f(x) =
∑∞n=0 cn(x− a)n about a ∈ I, and similarly for g.
1 The sum and product of the Taylor series of f and g about x = aare the Taylor series of the sum and product functions.
2 For k ∈ N, the Taylor series T a∞(x − a)kf(x) is given by
(x − a)kT a∞f(x) =
∞∑
n=0
cn(x− a)n+k.
3 Let b ∈ R, k ∈ N, the Maclaurin series for g(x) = f(bxk) is
T∞g(x) =
∞∑
n=0
(cnbn)xkn.
The most important part of this theorem is next. . .
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MA2730, Analysis I, 2015-16
Overview (MA2730,2812,2815) lecture 20
Lecture 20
Lemma 7.11, Subsection 7.2.2 in The Handbook
Let f : I → R be an infinitely differentiable function with Taylorseries T a
∞f(x) =∑∞
n=0 cn(x− a)n about a ∈ I.
1 The Taylor series of the derivative f ′ of f is given by theseries of term-by-term derivatives of the Taylor series of f andhas the same radius of convergence.
Outline Proof —- the main steps
First: T a∞f ′(x) =
∞∑
n=0
f (n+1)(a)
n!(x− a)n =
∞∑
n=1
f (n)(a)
(n− 1)!(x− a)n−1.
Second:d
dxT a∞f(x) =
d
dx
∞∑
n=0
f (n)(a)
n!(x− a)n =
∞∑
n=1
f (n)(a)
(n− 1)!(x− a)n−1.
They are the same so (T a∞f(x))′ = T a
∞f ′(x).
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Overview (MA2730,2812,2815) lecture 20
Lecture 20
For the second part of this outline proof we put
f(x) =∞∑
n=0
f (n)(a)
n!(x− a)n =
∞∑
n=0
cn(x− a)n,
f ′(x) =∞∑
n=1
f (n)(a)
(n− 1)!(x− a)n−1 =
∞∑
n=1
bn(x− a)n.
To use the root test we first note that,
bn =f (n)(a)
(n− 1)!= n
f (n)(a)
n!= ncn,
and so ρ2 = 1/R is the same for both power series because,
limn→∞
|bn|1/n = limn→∞
n1/n limn→∞
|cn|1/n = limn→∞
|cn|1/n
since n1/n → 1 (using Part 3 of Proposition 2.14, Lecture 10).
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MA2730, Analysis I, 2015-16
Overview (MA2730,2812,2815) lecture 20
Lecture 20
Summary
We will pick up on these observations in the next lecture.
For the moment we can:
Recognise a power series.
Interpret its natural domain in terms of R.
Use the root and ratio tests to determine R.
Investigate the convergence at the boundary |x− a| = R.
Find f ′(x) by term-by-term differentiation of f(x).
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MA2730, Analysis I, 2015-16
Overview (MA2730,2812,2815) lecture 20
End of Lecture
Computational andαpplie∂ Mathematics
The Assignment — a comment on page limits
I didn’t have time to write a short letter, so I wrote a long oneinsteadMark Twain
Reference: The Handbook, Chapter 7, Section 7.2.Homework: Sheet 6a, Questions 1 and 3Seminar: Ad Hoc. Student driven
Shaw bicom, mathematics, CEDPS, IMM, CI, Brunel
MA2730, Analysis I, 2015-16