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7/29/2019 Lecture_Chapter 12_part6_wmf.pdf
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Colligative Properties of Electrolytes
Since colligative properties depend on the number of
particles dissolved, solutions of electrolytes (which
dissociate in solution) should show greater changesthan those of nonelectrolytes.
7/29/2019 Lecture_Chapter 12_part6_wmf.pdf
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Colligative Properties of Electrolytes
However, a 1 M solution of NaCl does not showtwice the change in freezing point that a 1 Msolution of methanol does.
7/29/2019 Lecture_Chapter 12_part6_wmf.pdf
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Ion Pairing and the vant Hoff FactorOne mole of NaCl in water doesnot really give rise to two moles ofions.
Ion pairing and colligativeproperties. Ion pairing
becomes more prevalent as
the solution concentrationincreases
Some Na+
and Cl
reassociate
for a short time, so the true
concentration of particles is
somewhat less than two timesthe concentration of NaCl.
Reassociation is more likely at
higher concentration.
Therefore, the number of
particles present is
concentration dependent.
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The vant Hoff FactorWe modify theprevious equations by
multiplying by the
vant Hoff factor, i= lyte)nonelectroforcalculated(Tmeasured)(T ff
lyte)nonelectroforcalculated(T
measured)(T
f
f
=i
For an ideal solution: the vant Hoff factor equals the number of ionsper formula unit.For ideal solutions of NaCl
and K2
SO4 : i = 2 and i = 3, respectively
In absence of information about the value of i for a solution, usethe ideal value in calculations
7/29/2019 Lecture_Chapter 12_part6_wmf.pdf
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Osmosis
Some substances form semipermeable membranes (e.g
cellophane and many membranes in biological systems),allowing some smaller particles to pass through (e.g.
water molecules), but blocking other larger particles.
In biological systems, most semipermeable membranesallow water to pass through, but solutes are not free to do
so.
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Osmosis
In osmosis, there is net movement of solvent from the area ofhighersolvent concentration (lower solute concentration) to the are oflower solvent concentration (higher solute concentration). There isa net solvent movement through the semipermeable membrane, as ifthe solutions were driven to attain equal concentrations acrossthe membrane
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Osmotic PressureThe pressure required to stop osmosis, known as osmotic
pressure, , isnRTV =
If the osmotic pressure is the same on both sides of a membrane (i.e., the
concentrations are the same), the solutions are
isotonic. If one solution is
of lower osmotic pressure, it is hypotonic with respect to the more
concentrated solution. The more concentrated solution is hypertonic with
respect to the dilute solution.
V is the volume of the solution, n is the number of moles of
the solute, R is the gas constant, and T is the temperature in
Kelvin
MRTRTVn =
=Then
M is the molarity of the solution (mol/L)
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Osmosis in Blood Cells
If the solute concentration
outside the cell is hypertonicrelative to the intracellular
solution (the solution within
the cell)
Water will flow out of the
cell, this cause the cell toshrivel, a process called
crenation
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Osmosis in Cells
If the soluteconcentration outside thecell is hypotonic relativeto the intracellularsolution.
Water will flow into thecell. This causes the cellto rupture, a processcalled hemolysis.
The Intravenous (IV) solutions must be isotonic with
the intracellular fluids of the cell otherwise crenation
orhemolysis occur
7/29/2019 Lecture_Chapter 12_part6_wmf.pdf
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A solution of an unknown nonvolatile electrolyte was prepared by dissolving0.250 g of the substance in 40.0 g of CCl4. The boiling point of the resultantsolution was 0.357C higher than that of the pure solvent. Calculate the molarmass of the solute. For pure CCl4 kb
= 5.02 C/m
EXERCISE: Molar Mass from Freezing-Point Depression
m0711.0
C.m5.02
C375.0
k
T
kg1040.0
molnmolality
1-b
b3-
solute ==
=
=D
D
Answer:
soluteofmol102.84)(mol.kg0711.0kg1040.0n
m0711.0kg1040.0
n
3-1-3-solute
3-solute
==
=
1-3-
solute
3-solute
g.mol0.88mol102.84
g250.0(mol)n
(g)mMM
soluteofmol102.84MM
mn
=
==
==
7/29/2019 Lecture_Chapter 12_part6_wmf.pdf
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The osmotic pressure of an aqueous solution of a certain protein was measured
in order to determine the proteins molar mass. The solution contained 3.50 mgof protein dissolved in sufficient water to form 5.00 mL of solution. Theosmotic pressure of the solution at 25C was found to be 1.54 torr. Calculatethe molar mass of the protein.
EXERCISE: Molar Mass from Osmotic Pressure
nRTV =Answer
mol1014.4ml1000
L1ml5
mmHg760
atm1
K298.KL.atm.mol0.0821
mmHg54.1
RTVn
71-1-
=
=
=
1-37-
3
g.mol1045.8
mol104.14
g1050.3
n
mMM
MM
mn =
===
7/29/2019 Lecture_Chapter 12_part6_wmf.pdf
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ColloidsSuspensions or dispersions of particles larger than individual
ions or molecules, but too small to be settled out by gravity.
Colloids form the dividing line between solutions and
homogeneous mixtures
Size of colloid particles range from 5 to 1000 nm
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Tyndall Effect
Colloidal suspensions
can scatter rays of light. This phenomenon isknown as the Tyndall
effect.
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Colloids in Biological Systems
Some molecules havea polar, hydrophilic (water-loving) end anda nonpolar,hydrophobic (water-hating) end.