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Lesson 10-1: The Pythagorean Theorem

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Lesson 10-1: The Pythagorean Theorem. Simplifying Radicals . Lesson 10-2. Essential Understanding . A radical is any number with a square root. You can simplify a radical expressions using multiplication and division. MULIPLICATION PROPERTY OF SQUARE ROOTS: √32 = √16 ∙ √2 = 4√2. - PowerPoint PPT Presentation
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LESSON 10-1: THE PYTHAGOREAN THEOREM
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Page 1: Lesson 10-1: The Pythagorean Theorem

LESSON 10-1: THE PYTHAGOREAN THEOREM

Page 2: Lesson 10-1: The Pythagorean Theorem

SIMPLIFYING RADICALS LESSON 10-2

Page 3: Lesson 10-1: The Pythagorean Theorem

ESSENTIAL UNDERSTANDING A radical is any number with a square root. You can simplify a radical expressions using multiplication and division.

MULIPLICATION PROPERTY OF SQUARE ROOTS: √32 = √16 ∙ √2 = 4√2

Page 4: Lesson 10-1: The Pythagorean Theorem

PROBLEM 1What is the simplified form of √160?Ask “what perfect square goes into 160?”

160 = 2 ∙ 80 No perfect square160 = 4 ∙ 40 Yes perfect square160 = 16 ∙ 10 Yes perfect square

√160 = √16 ∙ √10 = 4√10

Page 5: Lesson 10-1: The Pythagorean Theorem

GOT IT? 1Simplify: √72

6 √2

Page 6: Lesson 10-1: The Pythagorean Theorem

PROBLEM 2 Simplify: √54n7

√9 ∙ 6 ∙ n ∙ n ∙ n ∙ n ∙ n ∙ n ∙ n√9 ∙ √6 ∙ √n2 ∙ √n2 ∙ √n2 ∙ √n

3 ∙ √6 ∙ n ∙ n ∙ n ∙ √n3n3 ∙ √6n3n3√6n

Page 7: Lesson 10-1: The Pythagorean Theorem

GOT IT? 2Simplify: -m √80m9

Page 8: Lesson 10-1: The Pythagorean Theorem

PROBLEM 3Simplify: 2√7t ∙ 3√14t2

2 ∙ 3 ∙ √ 7t ∙ 14t2

6 ∙ √98t3

6 ∙ √49t2 ∙ 2t6 ∙ 7t ∙ √2t

42t√2t

Page 9: Lesson 10-1: The Pythagorean Theorem

DIVISION PROPERTY OF SQUARE ROOT

√3649 √ 144

36

Page 10: Lesson 10-1: The Pythagorean Theorem

PROBLEM 5

√8x3

50x8x3 = √4 2 x2 x50x = √25 2 x

2 x

5

2x 5

Page 11: Lesson 10-1: The Pythagorean Theorem

RATIONALIZING THE DENOMINATOR

It’s okay to have a square root in the numerator, but not the denominator. It’s not simplified enough if you keep a square root in the denominator.

√3√7

√3√7

√7√7

√21√49

√21 7

Really equals 1

Page 12: Lesson 10-1: The Pythagorean Theorem

OPERATIONS WITH RADICAL EXPRESSIONSLESSON 10-3

Page 13: Lesson 10-1: The Pythagorean Theorem

COMBINING “LIKE” RADICALS

3√5 and 7√5 have the same radicand.

Radicand = number under the square root.

-2√9 and 4√3 do not have the same radicand.

If two or more numbers have the same radicand, then we can combine them together.

Page 14: Lesson 10-1: The Pythagorean Theorem

PROBLEM 1What is the simplified form of 2√11 + 5√11?

2√11 + 5√11We could break it down even more…

(√11 + √11) + (√11 + √11 + √11 + √11 + √11)How many √11’s do we have altogether?

7 √11

2√11 + 5√11 = 7 √11

Page 15: Lesson 10-1: The Pythagorean Theorem

WHAT IS THE SIMPLIFIED FORM OF √3 - 5√3?

√3 - 5√31√3 - 5√3(1 – 5)√3

-4√3Got it?

1. 7√2 - 8√2 2. 5√5 + 6√5

Page 16: Lesson 10-1: The Pythagorean Theorem

PROBLEM 2: WHAT IF THEY DON’T “LOOK LIKE THEY CAN BE SIMPLIFIED?

5√3 - √12Simplify √12 to see if there is a perfect

square.√12 = √4 ∙ 3 = 2√3

So we have 5√3 - 2√3.

5√3 - 2√3 = 3√3

Page 17: Lesson 10-1: The Pythagorean Theorem

GOT IT? 2

1. 4 √7 + 2 √28

2. 5 √32 - 4 √18

Page 18: Lesson 10-1: The Pythagorean Theorem

PROBLEM 3: USING THE DISTRIBUTIVE PROPERTY

10(6 + 3) = 10(6) + 10(3) = 60 + 30 = 90

In the same way…√10(√6 + 3)

Use the Distributive Property(√10 ∙ √6) + (√10 ∙ 3)

√60 + 3√10Break down 60 to find a perfect square.

√4 ∙ √15 + 3√102 √15 + 3 √10

Can we simplify even more?

Page 19: Lesson 10-1: The Pythagorean Theorem

PROBLEM 3: (√6 - 2 √3)(√6 + √3)

(√6 - 2 √3)(√6 + √3)Carefully FOIL

(√6)(√6) + (- 2 √3)(√6) + (√6)(√3) + (- 2 √3)(√3) First Inside Outside Last √36 + -2√3 ∙ 6 + √6 ∙ 3 + -2√3 ∙ 3 6 + -2√18 + √18 + -2 ∙ 3

6 – √18 – 6-√18 = -1 √9 ∙ 2

= -1 ∙ 3 √2 = -3√2

Page 20: Lesson 10-1: The Pythagorean Theorem

GOT IT? 31. √2(√6 + 5)

Page 21: Lesson 10-1: The Pythagorean Theorem

GOT IT? 32. (√11 – 2)2

Page 22: Lesson 10-1: The Pythagorean Theorem

GOT IT? 33. (√6 – 2 √3)(4 √3 + 3 √6)

Page 23: Lesson 10-1: The Pythagorean Theorem

PROBLEM 4: COJUGATESExamples:

+ and - + 8 and - 8

What do you notice?Cojugates: the sum and difference of the same

two terms. ( + )( - )7 – 3 = 4

Page 24: Lesson 10-1: The Pythagorean Theorem

PROBLEM 4: RATIONALIZING A DENOMINATOR

Multiply by the cojugates. =

= = 2 + 2

Page 25: Lesson 10-1: The Pythagorean Theorem

SOLVING RADICAL EQUATIONSLESSON 10-4

Page 26: Lesson 10-1: The Pythagorean Theorem

ESSENTIAL UNDERSTANDINGRadical equations = equations with a radicand (square root)

Some radical equations can be solved by squaring each side.

The expression under the radicand MUST be positive.

Page 27: Lesson 10-1: The Pythagorean Theorem

PROBLEM 1What is the solution of 7 + = 16?

7 + = 16Subtract 7 from both sides.

= 9Square both sides.

()2 = 92

x = 81

Page 28: Lesson 10-1: The Pythagorean Theorem

GOT IT? 1What is the solution of -5 + = -2?

Page 29: Lesson 10-1: The Pythagorean Theorem

PROBLEM 2In the expression, t = 2, what is m when t is 3?

3 = 21.5 =

1.52 = ()2

2.25 =

2.25 =

(2.25)(3.3) = (3.3)

7.425 = m

Page 30: Lesson 10-1: The Pythagorean Theorem

PROBLEM 3What is the solution of ?

()2 = ()2

5t – 11 = t + 54t – 11 = 5

4t = 16t = 4

Page 31: Lesson 10-1: The Pythagorean Theorem

GOT IT? 3

Page 32: Lesson 10-1: The Pythagorean Theorem

EXTRANEOUS SOLUTIONSTake the original equation x = 3.

Let’s square each side.

x2 = 9

The solutions would be 3 and -3….right?

However, -3 doesn’t fit in our original equation.

Sometimes when we square each sides, we create a false solution.

Page 33: Lesson 10-1: The Pythagorean Theorem

n2 = n + 12n2 - n – 12 = 0

(n – 4)(n + 3) = 0n = 4 and -3

Does both numbers work for n?

PROBLEM 4

Page 34: Lesson 10-1: The Pythagorean Theorem

(n – 4)(n + 3) = 0n = 4 and -3

PROBLEM 4

Page 35: Lesson 10-1: The Pythagorean Theorem

PROBLEM 5What is the solution √3y + 8 = 2?

√3y = -6Can you ever have a negative as a product of a square

root?(√3y)2 = -62

3y = 36y = 12

Check:

Page 36: Lesson 10-1: The Pythagorean Theorem

LESSON CHECK 1

Page 37: Lesson 10-1: The Pythagorean Theorem

LESSON CHECK 2

Page 38: Lesson 10-1: The Pythagorean Theorem

LESSON CHECK 3

Page 39: Lesson 10-1: The Pythagorean Theorem

LESSON CHECK 4

Page 40: Lesson 10-1: The Pythagorean Theorem

GRAPHING SQUARE ROOT FUNCTIONSLESSON 10-5

Page 41: Lesson 10-1: The Pythagorean Theorem

SQUARE ROOT FUNCTION IS…A function where the “x” or independent

variable is under the square root.

The parent square root function is y = .

Page 42: Lesson 10-1: The Pythagorean Theorem

WHAT IS THE DOMAIN AND RANGE?

Domain: What numbers can you put in for x?

All positive numbers

Range: What kind of numbers are the output of y?

All positive numbers

Page 43: Lesson 10-1: The Pythagorean Theorem

PROBLEM 1What is the domain and range of this function?

y = 2Domain: what numbers can you put in for x?

*the radicand can not be negative*

3x – 9 03x 9x 3

So, the domain of this function are all real numbers greater or equal to 3. Range: all positive numbers

Page 44: Lesson 10-1: The Pythagorean Theorem

GOT IT? 1What is the domain of y = ?

Page 45: Lesson 10-1: The Pythagorean Theorem

PROBLEM 2Graph the function I = , which gives the current I in ampere for a certain circuit with P watts of power. When will the current exceed 2 amperes?

Page 46: Lesson 10-1: The Pythagorean Theorem

GOT IT? 2When will the current exceed 1.5 amperes?

Page 47: Lesson 10-1: The Pythagorean Theorem

PROBLEM 3Take the parent square root function. y =

If you want to move it UP on the graph, you add OUTSIDE the square root.

If you want to move it DOWN on the graph, you subtract OUTSIDE the square root.

Page 48: Lesson 10-1: The Pythagorean Theorem

PROBLEM 4Take the parent square root function. y =

If you want to move it RIGHT on the graph, you SUBTRACT INSIDE the square root.

If you want to move it LEFT on the graph, you ADD INSIDE the square root.

Page 49: Lesson 10-1: The Pythagorean Theorem

GOT IT? 3 AND 4What coordinate does the graph of y = start on?

What coordinate does the graph of y = start on?

What coordinate does the graph of y = start on?

What coordinate does the graph of y = 4 start on?

Page 50: Lesson 10-1: The Pythagorean Theorem

LESSON QUIZ1. Is y = x a square root function? Why or why not?

2. Can a domain of a square root function include negative numbers? If it can, give an example. If it can not, explain.

Page 51: Lesson 10-1: The Pythagorean Theorem

HOME WORK#8 – 38 evens

On 16 – 24 just make a table.

On 30 – 38, tell me the coordinate that the graph will start. You don’t need to graph it.

Page 52: Lesson 10-1: The Pythagorean Theorem

TRIGONOMETRIC RATIOSLESSON 10-6

Page 53: Lesson 10-1: The Pythagorean Theorem

KEY CONCEPT: TRIG RATIOS

Page 54: Lesson 10-1: The Pythagorean Theorem

KEY CONCEPT: TRIG RATIOSOr…

Sine A =

Cosine A =

Tangent A =

Page 55: Lesson 10-1: The Pythagorean Theorem

EXAMPLEWhat are the sine of R?

Sine R =

Sine R =

Sine R =

9

12

15

R

Page 56: Lesson 10-1: The Pythagorean Theorem

EXAMPLEWhat are the cosine of R?

Cosine R =

Cosine R =

Cosine R =

9

12

15

R

Page 57: Lesson 10-1: The Pythagorean Theorem

EXAMPLEWhat are the tangent of R?

Tangent R =

Tangent R =

Tangent R =

9

12

15

R

Page 58: Lesson 10-1: The Pythagorean Theorem

GOT IT? 1What is the sine, cosine and tangent of E?

8

15

17

E

Page 59: Lesson 10-1: The Pythagorean Theorem

PROBLEM 2What is the cosine of 55 degrees?Step 1: Make sure your calculator is in Degree mode.

Step 2: Press “cos” and then 55 and then “enter”

Page 60: Lesson 10-1: The Pythagorean Theorem

GOT IT? 2Use a calculator to compute these trigonometric ratios.1. Sin 80

2. Tan 45

3. Cos 15

4. Sin 9

Page 61: Lesson 10-1: The Pythagorean Theorem

PROBLEM 3We can use sine, cosine or tangent to solve for x.

How does 14, 48 and x relate to each other?What ratio connects all three together?

Sine 48 =

Sin 48 =

Multiply each side by 14. 14 Sin 48 = x

x ≈ 10.4

Page 62: Lesson 10-1: The Pythagorean Theorem

GOT IT? 3To the nearest tenth, what is the value of x in the triangle?

Page 63: Lesson 10-1: The Pythagorean Theorem

FLIP CHART

Page 64: Lesson 10-1: The Pythagorean Theorem

INVERSE OF TRIG RATIOSSine(Sine-1) = 1 Cosine(Cosine-1) = 1

Tangent(Tangent-1) = 1

Sine and Sine-1 are inverses of each other.

Cos(Cos-1)(45) = 45

Page 65: Lesson 10-1: The Pythagorean Theorem

PROBLEM 4Find the angle of A in the triangle.

Page 66: Lesson 10-1: The Pythagorean Theorem

GOT IT? 4In a right triangle, the side opposite angle A is 8mm and the hypotenuse is 12 mm long. What is the angle of A?

Page 67: Lesson 10-1: The Pythagorean Theorem

OUTSIDE ANGLESAngle of Elevation: angle from the horizontal UP to the line of sight.

Angle of Depression: angle from the horizontal DOWN to the line of sight.

Page 68: Lesson 10-1: The Pythagorean Theorem

PROBLEM 5Suppose you are waiting in line for a ride. You see your friend at the top of the ride. How fare are you from the base of the ride?

Page 69: Lesson 10-1: The Pythagorean Theorem

PROBLEM 5

Tan 20 =

Tan 20 =

x tan 20 = 150

x tan 20 = 150

x =

x = 410

You are about 410 feet from the base of the ride.

Page 70: Lesson 10-1: The Pythagorean Theorem

HOME WORK#31 – 35, 39 – 42 all


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