Letter of Transmittal BLACK & VEATCH Waste Science, Inc. 101 North Wacker Drive, Suite 1100, Chicago, Illinois, 60606, Phone (312) 346-3775, Fax (312) 346-4781 To: iJ.S. Ul. MSRM -^rtcia - t j) a/n/qr _ f f^ ^ . . Date: From: Project: Project No.: 1 \\ go / File: r.a We are sending you: Attached These items are transmitted: [l l| As requested [l l| For your approval Under separate cover via I I Preliminary Report I </ l| Other: ute.e.k\ For your information For review and comment Remarks: Copy To: Signed: s:\boiferpTvfomu\let-tran. wk4
Transcript
Letter of TransmittalBLACK & VEATCH Waste Science, Inc.101 North Wacker Drive, Suite 1100, Chicago, Illinois, 60606, Phone (312) 346-3775, Fax (312) 346-4781
To:iJ.S.
Ul. MSRM- rtcia- t j)
a/n/qr_ f f^ ^ . .Date:From:Project:Project No.: 1 \\ go /File: r.a
We are sending you: Attached
These items are transmitted:
[l l| As requested
[l l| For your approval
Under separate cover via
I I Preliminary Report
I </ l| Other: ute.e.k\
For your information
For review and comment
Remarks:
Copy To:
Signed:
s:\boiferpTvfomu\let-tran. wk4
USEPA/ARCS VBVWST WEEKLY OVERSIGHT SUMMARY
Reporting Period: Skpl \ a . L </ . i**tf Hours Worked:Site name/location; Fr.^Why urn BVWST Project No.:7u?o.&«»or 7/z«EPA Remedial Project Manager: Pit>l«> v»tUiA.--vProject Contractor: M,lc-<a.~ kr A -.c Cg^r.. « ««-) <T^r Jr ^p f fT.-^-
Personnel SummaryAffiliation No. of Personnel ResponsibilityBVW5 ______ "2- _____ Dot-'-
Met Worn P.'ro.'e _____ ________ E /la. f »>e g r __.
$ " 7 ______ C+r»\*<Ae.T-*r
- S
Summary of field activities: F.e^4- <?<><,. p \>V>J. _i..C ' V . r^et . ft
Hol Famil MemorialMedical CenterManllomc. Wlxonita
'ATIENT VISITO BE COMPLETED BY NURSE
r ' - ' T r T H J , pP] A>| 5 ; M
iJija tvLST FDLIOM 5 CC.ffiTC"03300042 IOG'05609/19/95 WHO JO/C4/CSS. D. m
)ATE TIME (PRESENT)
MPLOYER*
INITIAL VISIT RECHECK
,(
CURRENTJOB MRS/DAY
I hereby authorize the release of all medical information pertaining to this work related injury/illness to my employer, insurance company and anymedical provider involved in the diagnosis or treatment of this injury. In addition, authorization is hereby given to this treating facility to perform anyand aljjests or proceduresjelative to my Injuryftllness or physical examination as deemed necessary by the attending physician and/or employer.
, A-EMPLOYEE SIGflHTURE ]f TIMEOUT DATE SIGNED
JURY DATE / / x^"
?/f 7/9 ^WE OF INJURY ( '—~
IUG/ALCOHOL SCREEN] YES D NO
PATIENT DESCRIPTION OF INJURY [£J WORK-RELATED QJ NON WORK-RELATED
NC / * •'-'' J '' /
i BE COMPLETED BY PHYSICIANK3NOSIS,, , , • . PREVIOUS HX OF SIMILAR INJURY
1 SIGNS & SYMPTOMS CONSISTENT WITH WORK-RELATED INJURY X-RAY1 SIGNS & SYMPTOMS NOT CONSISTENT WITH WORK-RELATED INJURY 0 NORMAL (_J OTHER:DS PRESCRIBED — . / i > //
—————————————————————————— r —— —————————————————————————————;posmoN] PATIENT IS UNABLE TO WORK AT THIS TIME.
] PATIENT MAY RETURN TO WORK WITHOUT RESTRICTIONS: Q IMMEDIATELY Q ON ___
] PATIENT MAY RETURN TO WORK WITH THE FOLLOWING RESTRICTIONS/RECOMMENDATIONS: DATE:
SIGNATURE
LOW-UP SCHEDULED APPOINTMENTSC/PHYSICIAN
E COMPLETED BY WORK HEALTH OPTIONSTIME CALLED EMPLOYER
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.AIL
CURVE TABLESHOW TO USE CURVE TABLES
Table I. contains Tangents and Externals to a 1° curve. Tan. andExt. to any other radius may be found nearly enough, by dividing theTan. or Ext. opposite the given Central Angle by the given degree ofcurve.
To find Oeg. of Curve, having the Central Angle and Tangent:Divide Tan. opposite the given Central Angle by the given Tangent.
To find Deg. of Curve, having the Central Angle and External:>/ide Ext. opposite the given Central Angle by the given External.
To find Nat. Tan. and Nat. Ex. Sec. for any angle by Table I.: Tan.• Ext. of twice the given angle divided by the radius of a 1° curve will
the Nat. Tan. or Nat. Ex. Sec.EXAMPLE
Wanted a Curve with an Ext. of about 12 ft. Angle ofIntersection or I. P. = 23° 20' to the R. at Station 542+72.
Ext. in Tab. I opposite 23° 20' - 120.87120.87 + 12 - 10.07. Say a 10° Curve.
Tan. in Tab. I opp. 23° 20' = 1183.11183.1 + 10 - 118.31.
Correction for A. 23° 20' for a 10° Cur. = 0.16118.31+0.16 - 118.47 - corrected Tangent.(If corrected Ext. is required find In same way)
Ang. 23° 20' = 23.33° + 10 - 2.3333 - L C.
def. tor sta.
9° 49V4'11° 40'
sta.
sta.
Sta.
542+721 .18.47
541+53.532 .33.33
543 + 86.86100 - 53.53 - 46.47 x 3'(def. for 1 ft. of 10° Cur.) -139.41 ' =
2° 19V4' - def. for sta. 542.Def. for 50 ft. = 2° 30' for a 10° Curve.
Def. for 36.86 ft. = 1° SOW for a 10° Curve.
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