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7/26/2019 LPGHall Report
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CALCULATION REPORT
Filling Hall
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Bending Moment- M33
Bending Moment- M22
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Shear force-1stfloor
Axial Load
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Reaction
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Joint OutputCase CaseType F1 F2 F3 M1 M2 M3
Text Text Text Kgf Kgf Kgf Kgf-m Kgf-m Kgf-m
4 DL+LL+SDL Combination 93.07 818.78 9829.17 -208.61 8.96 21.86
13 DL+LL+SDL Combination 11.41 -815.07 9967.45 229.71 -4.31 -8.66
193 DL+LL+SDL Combination -51.04 640.21 9828.19 -126.29 -25.12 -26.78
196 DL+LL+SDL Combination 12.92 -636.27 9957.26 216.11 -4.06 7.71
230 DL+LL+SDL Combination -41.43 -238.88 10515.66 435.08 -27.35 2.55
233 DL+LL+SDL Combination -24.94 231.24 10780.86 -421.19 -15.36 -3.88
TABLE: Joint Reactions
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Purlin
DATA
Length ,L 8 m.
Spacing, @ 1.2 m.
Slope of Roof 5 degree
Load data
Live Load 30 kg/m.2
Dead Load
Roof Material 5 kg/m.2
Purlin 8 kg/m.2
Other 15 kg/m.3
Total Dead Load 28 kg/m.2
Wind Load 50 kg/m.2
Wind Load to perpendicular roof= (2Psin/1+sin^2) 8.65 kg/m.2
Load Case
Case 1 DL= Purlin spacing x DL= 33.6 kg/m.
Case 2 DL+LL = spacing x(DL+LL )= 69.6 kg/m.
Case 3 0.75(DL+LL+WL) x spacing = 59.98 kg/m.
Load to purlin W = 60 kg/m.
Wx = Wsinq = 5.23 kg/m.
Wy = Wcosq = 59.77 kg/m.
Member force from structural analysis program
Moment max. = 680.00 kg.m.
Section of modulus Sx= 47.22 cm.
Use C 200x 75x20x3.2 mm. @ 1.20 m.
Sx= 47.22 cm.
Ix = 716 cm.
Max. deflection 3.10 cm
Allowable deflection L/240 = 3.33 cm O.K.
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Rafter
DATA
Length ,L 2.04 m.
Distance between brace, Lb = 1.2 m.
Fy = 2400 kg/cm2
Moment = 220 kg.m
= .
Modulus of Section, Sx= 15.28 cm.
Use C 100 X50 X 20 x 3.2 mm.
Weight = 5.5 kg/m. Sx = 21.3 cm. Ix = 107 cm.
tw = 3.2 mm Iy =
24.5 cm.
tf = 3.2 mm bf= 50 mm
d= 100 mm
Compact or Noncompact Section
7.81 < 0.38(E/Fy)^0.5 = 10.97
h/tw= 27.25 < 3.76(E/Fy)^0.5 = 108.5
Compacted section
Lateral Support Checking
Compute Lc
= . cm = . cm
Lc = 64.91 cm.
Lb = 120.00 cm.
So Lb>Lc Not adequate bracing
Fb= 1440.00 kg/cm
Ma = Fb.Sx= 306.72 kg-m. > 220 kg-m OK
Shear Checkingh/tw= 29.25 < 3179/(Fy^0.5) = 64.89
Fv = 0.4Fy = 960 kg/cm
Va = Aw.Fv = 3,072.00 kg. > 460 kg. OK
ax. e ec on . cm.
Allowable deflection L/180 = 1.13 cm. OK
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BEAM
DATA
Length ,L 9 m.
Distance between brace, Lb = 9 m.
Fy = 2400 kg/cm2
Moment = 5,300 kg.m
= , .
Modulus of Section, Sx= 368.06 cm.
Use WF 250 X250 X 11x 11 mm.
Weight = 64.4 kg/m. Sx = 720 cm. Ix = 8790 cm.
tw = 11 mm Iy =
2940 cm.
tf = 11 mm bf= 250 mm
d= 250 mm
Compact or Noncompact Section
11.36 < 0.38(E/Fy)^0.5 = 10.97
h/tw= 18.73 < 3.76(E/Fy)^0.5 = 108.5
Compacted section
Lateral Support Checking
Compute Lc
= . cm = . cm
Lc = 324.56 cm.
Lb = 900.00 cm.
So Lb>Lc Not adequate bracing
Fb= 1031.07 kg/cm
Ma = Fb.Sx= 7,423.68 kg-m. > 5,300 kg-m OK
Shear Checkingh/tw= 20.73 < 3179/(Fy^0.5) = 64.89
Fv = 0.4Fy = 960 kg/cm
Va = Aw.Fv = 26,400.00 kg. > 3,200 kg. OK
ax. e ec on . cm.
Allowable deflection L/180 = 5.00 cm. OK
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Beam (attach between column head)
DATA
Length ,L 8 m.
Distance between brace, Lb = 8 m.
Fy = 2400 kg/cm2
Moment = 232 kg.m
= .
Modulus of Section, Sx= 16.11 cm.
Use 2 C 200 X75 X 20 x 3.2 mm.
Weight = 19.04 kg/m. Sx = 147.2 cm. Ix = 1472 cm.
tw = 3.2 mm Iy =
184.6 cm.
tf = 3.2 mm bf= 150 mm
d= 200 mm
Compact or Noncompact Section
23.44 > 0.38(E/Fy)^0.5 = 10.97
h/tw= 58.50 < 3.76(E/Fy)^0.5 = 108.5
Partial compact section
Lateral Support Checking
Compute Lc
= . cm = . cm
Lc = 140.00 cm.
Lb = 800.00 cm.
So Lb>Lc Not adequate bracing
Fb= 253.08 kg/cm
Ma = Fb.Sx= 372.53 kg-m. > 232 kg-m OK
Shear Checkingh/tw= 60.50 < 3179/(Fy^0.5) = 64.89
Fv = 0.4Fy = 960 kg/cm
Va = Aw.Fv = 6,144.00 kg. > 650 kg. OK
ax. e ec on . cm.
Allowable deflection L/180 = 4.44 cm. OK
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Beam B1 0.20x1.10
Section Width 0.20 m.
Depth 1.10 m.
Covering 0.03 m.
d = 1.054 m.
d' = 0.046 m.
Dead Load 0.20x1.10 528 kg/m.
M+
5,500 kg-m.
V 2,400 kg
Determine Flexural Reinforcement
Mc =Rbd2= 25,196.93 kg-m. > M
+Max.
As1= M+/fs.jd= 3.90 cm
Bottom Bars(Tension) 2 DB 20 mm As = 6.28 cm2
2 DB 20 mm As = 6.28 cm2
Total 12.56 cm
Top Bars(Compression) 2 DB 20 mm As = 6.28 cm2
Design of Shear Reinforcement
Shear, V 2400 kg
Shear Capacity Vc = 0.29fc'^0.5(b.d) = 8858.87 kg
V' = V -Vc= -6458.87 kg
Stirrup RB 6 mm. Av = 0.57 cm2
Spacing s = Av.fv.d/(V') = -11.07 cm.
spacing not exceed 0.20 m. OR 0.53 m.
Use Stirrup RB 6 mm @ 0.15 m.
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Beam B2 0.20 x 1.10
Section Width 0.20 m.
Depth 1.10 m.
Covering 0.03 m.
d = 1.056 m.
d' = 0.044 m.
Dead Load 0.20 x 1.10 528 kg/m.
M-max. 4200 kg-m.
M+max. 2400 kg-m.
Vmax. 2700 kg
Determine Flexural Reinforcement
At column
Mc =Rbd2= 25292.64 kg-m. > M
-max.
As = M-/fs.jd = 2.97 cm
2
Tension Bars(top) 2 DB 16 mm As = 4.02 cm2
2 DB 16 mm As = 4.02 cm2
total 8.04 cm2
At Middle span
M+max. 2400 kg-m.
Mc =Rbd2= 25292.64 kg-m. > M
+max.
As = M+/fs.jd = 1.70 cm
2
=2
.
0 DB 0 mm As = 0.00 cm3
Design of Shear Reinforcement
Shear, V 2,700 kg
Shear Capacity Vc = 0.29fc'^0.5(b.d) = 8,876 kg
V' = V -Vc= -6175.68 kg
Stirrup RB 6 mm. Av = 0.57 cm2
Spacing s = Av.fv.d/(V') = -11.60 cm
spacing not exceed 0.2 m.or 0.528 m
Use Stirrup RB 6 mm. @ 0.15 m.
V' = 4,775 kg. > -6175.68 kg.
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Column C-1
Axial load,P 12,000 kg.
Moment,M 1,650 kg.m
Dimension
b = 25 cm
h = 25 cm
Use rebar 8 DB 16 mm Ast = 16.08 cm2
Total area of steel 16.08 cm2
pg = 0.02572288 2.57 % OK
m=fy/(0.85f 'c) = 16.81 ksc
concrete covering 3 cm
Use Stirrup RB 6 mm
t = h = 25 cm
d' = 4.4 cm
eb= (0.67pgm+0.17)(t-d') = 9.47
e = M/P = 13.75 cm. Tension zone
I = bh3/12 + (2n-1)As(hl
2/4) 50483.6637 cm
Fa=0.34(1+p m)f'c= 102.27 ksc .
Fb=0.45f'c= 94.5
fb=MxCx/Ix = 40.9 ksc
fa=Pb/Ag = 0.0016 Pb
(fa/Fa) +(fb/Fb) =1
Pb= 36,284.11 kg
Mb= Pbx (eb/100 )= 3,435.69 kg.m
M = 1,650 kg.m
Mo=0.4Asfyjd = 887.22 kg.m As = 4.02 cm
to be check P
P= Pb(M-Mo)/(Mb-Mo)= 10,860.15 kg < 12,000 kg. OK
Use 8 DB 16 mm. rebar
RB 6 m. @ 0.20 m. Stirrup
25
25
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SPREAD FOOTING F-1
Axial load 12,000 kg.
Moment 450 kg-m
Below the ground 1.50 m.
Size of Column
a parallel Y-axis 0.25 m.
b parallel X-axis resist Moment 0.25 m.
Allowable Soil Pressure 8,000 kg./m2
Self Weigth of Footing 720 kg./m2
Soil above footing 2028 kg./m2
Required area 2.40 m2
use
Size of Footing
B parallel Y-axis 1.70 m.
L parallel X-axis 1.70 m. Area = 2.89 m2
Depth 0.3 m.
Covering 0.08 m.
d = 0.22 m.
Gross soil pressure = 7,449.81 < 8,000 kg./m2
OK
Net soil pressure ,qmax. = 4,701.81 kg./m2
Net soil pressure ,qmin. = 3,602.69 kg./m2
Net soil pressure at edge of column 4,233.07 kg./m2
q at d/2 from edge of column 4,303.22 kg./m2
q at d from edge of column 4,373.37 kg./m2
q at the middle of footing 4,152.25 kg./m2
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Bending Moment at the edge of column (about Y-axis ,My)
Distance from the edge of the column (X-direction) 0.725 m.
My = 2,030.87 kg.m.
Steel bars in X-direction
Ast= M+/fs.jd= 6.99 cm2
As,temp = 10.20 cm2 (0.002bh for SD30 )
12 DB 16 mm As = 24.12 cm2 @ 0.14 m.
Bending Moment at the edge of column (about X-axis ,Mx)
Distance from the edge of the column (y-direction) 0.725 m.
My = 1,855.15 kg.m.
Steel bars in Y-direction
Ast= M+/fs.jd= 6.38 cm2
As,temp = 10.20 cm2 (0.002bh for SD30 )
12 DB 16 mm As = 24.12 cm @ 0.14 m.
Shear Checking
1.One way shear
vp= 4.20 ksc
Distance from the edge of the column, d 0.51 m.
Shear force at critical section Vp = 3,918.66 kg.
Critical section area 3689 cm2
Vp = 1.06 ksc . < 4.20 ksc. OK
2.Punching shear
vc = 7.68 ksc
Shear force at critical section Vc = 5,936.05 kg.
Perimeter b0 93.40 cm
Puncing area 2026.78 cm2
Vc = 2.93 ksc . < 7.68 ksc. OK