Date post: | 15-Jul-2015 |
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PARABOLA (horizontal)
Center C(h,k)
Vertices V(h±a,k)
Foci F(h±c,k)
Endpoints of the minor axis B(h,k±b)
Directrices x = h±a/e
( ) ( )1
b
ky
a
hx2
2
2
2=−+−
1
Center C(h,k)
Vertices V(h,k±a)
Foci F(h,k±c)
Endpoints of the minor axis B(h±b,k)
Directrices y = k±a/e
( ) ( )1
b
hx
a
ky2
2
2
2=−+−
2
PARABOLA (vertical)
directrix
focus
P1
P2
F
Q1
Q2
Given the eccentricity e of a conic section, the conic is
parabola if e = 1;
ellipse if 0 < e < 1;
hyperbola if e > 1.
PQ
principal axis
vertex
Non-degenerate Conic
Objectives: At the end of this section students should be able to:
• give the standard equation of a hyperbola;
• identify parts of a hyperbola;
• sketch the graph of a hyperbola.
Hyperbola
1b
y
a
x2
2
2
2=−Standard Equation
( )0,a( )0,a−
( )b,0
( )b,0 −
centervertex
auxiliary rectangle
The line segment joining the vertices is called the transverse axis.
The line segment joining the points (0,b) and (0,-b) is called the conjugate axis.
vertex
focus( )0,c( )0,c−
focus
y=(b/a)xy=(-b/a)x
eccentricity: e = c/a
directrices:c
a
e
ax
2±=±=
222 bac +=
1b
x
a
y2
2
2
2=−Standard Equation
( )0,b( )0,b−
( )a,0
( )a,0 −
y=(a/b)xy=(-a/b)x
eccentricity: e = c/a
c
a
e
ay
2±=±=directrices:
Example 1. Given the hyperbola
14
y
9
x 22=−
Determine the (a) center, (b) principal axis, (c) vertices, (d) endpoints of the conjugate axis, (e) foci, (f) eccentricity, and (g) equations of the directrices. Sketch also the graph.
SOLUTION
center:
principal axis: x -axis
vertices:
(3,0) and (-3,0).
endpoints of conjugate axis: (0,2) and (0,-2)
3a =
2 2
19 4
x y− =
2 2 13c a b= + =2b =
(0,0)
SOLUTION
foci:
eccentricity:
equation of the directrices:
( )13 0,±
13
2
2ax
c= ±
9
13x = ±
3a = 2b =2 2 13c a b= + =
2 2
19 4
x y− =
Example 2. Given the hyperbola
19
x
16
y 22
=−
Determine the (a) center, (b) principal axis, (c) vertices, (d) endpoints of the conjugate axis, (e) foci, (f) eccentricity, and (g) equations of the directrices. Sketch also the graph.Tr
y Thiz
z on
your
own!!!
If the center of the hyperbola is at (h,k) and the line y = k as principal axis then the standard equation is given by
( ) ( ).1
b
ky
a
hx2
2
2
2=−−−
Hyperbola with center (h,k)
If the center of the hyperbola is at (h,k) and the line x = h as principal axis then the standard equation is given by
( ) ( ).1
b
hx
a
ky2
2
2
2=−−−
Hyperbola with center (h,k)
Example 3. Given the hyperbola
( ) ( )1
16
2x
4
1y 22=+−−
determine the (a) center, (b) principal axis, (c) vertices, (d) endpoints of the conjugate axis, (e) foci, (f) eccentricity, and (g) equations of the directrices. Sketch also the graph.
SOLUTION
center: (-2,1)
principal axis: x = -2
vertices:
(-2,-1) and (-2,3).
endpoints of conjugate axis: (2,1) and (-6,1)
2a =
( ) ( )1
16
2x
4
1y 22=+−−
52bac 22 =+=4b =
( )1,2( )1,6−
( )3,2−
( )1,2 −−
(-2,1)
SOLUTION
2a =
( ) ( )1
16
2x
4
1y 22=+−−
52bac 22 =+=4b =
foci:
eccentricity:
equation of the directrices:
( )521,2 ±−
5
c
a1y
2±=
52
41y ±=
(-2,1) ( )1,2( )1,6−
( )3,2−
( )1,2 −−
Example 4. Given the hyperbola
determine the (a) center, (b) principal axis, (c) vertices, (d) endpoints of the conjugate axis, (e) foci, (f) eccentricity, and (g) equations of the directrices. Sketch also the graph.
( ) ( )1
4
1
4
2 22
=+
−− yx
Try T
hizz o
n
your
own!!!
Example 5. Determine the standard equation of the hyperbola with center at ( 1,1), principal axis is vertical, length of the transverse axis and conjugate axis are 4 and 8, respectively.
SOLUTION:
center: (1, 1)
vertical principal axis
h = 1 and k = 1.
( ) ( )2 2
2 2
y k x h1
a b
− −− =
Example 5. Determine the standard equation of the hyperbola with center at ( 1,1), principal axis is vertical, length of the transverse axis and conjugate axis are 4 and 8, respectively.
SOLUTION:
length of the transverse axis: 4
b = 4
a = 2
length of the conjugate axis: 8
Example 5. Determine the standard equation of the hyperbola with center at ( 1,1), principal axis is vertical, length of the transverse axis and conjugate axis are 4 and 8, respectively.
SOLUTION:
( ) ( )2 2y 1 x 1
14 16
− −− =
standard equation
Example 6. Determine the standard equation of the hyperbola with a vertex at ( 2,0), center at the origin and its eccentricity is 3/2.
Try T
hizz o
n
your
own!!!
CENTER C(h,k)
VERTICES V(h±a,k)
FOCI F(h±c,k)
ENDPTS OF CONJUGATE AXIS B(h,k±b)
DIRECTRICES x=h±a/e
( ) ( )1
b
ky
a
hx2
2
2
2
=−−−
HYPERBOLA (horizontal)