+ All Categories
Home > Documents > Martha Casquetemarthacasqueteutpa.weebly.com/uploads/2/0/9/9/20997728/...A cheetah is crouched in...

Martha Casquetemarthacasqueteutpa.weebly.com/uploads/2/0/9/9/20997728/...A cheetah is crouched in...

Date post: 17-Nov-2020
Category:
Upload: others
View: 0 times
Download: 0 times
Share this document with a friend
25
Martha Casquete
Transcript
Page 1: Martha Casquetemarthacasqueteutpa.weebly.com/uploads/2/0/9/9/20997728/...A cheetah is crouched in ambush 20 m to the east of an observer’s blind. At time t= 0 the cheetah charges

Martha Casquete

Page 2: Martha Casquetemarthacasqueteutpa.weebly.com/uploads/2/0/9/9/20997728/...A cheetah is crouched in ambush 20 m to the east of an observer’s blind. At time t= 0 the cheetah charges

Would you risk your live driving drunk?

Intro

Page 3: Martha Casquetemarthacasqueteutpa.weebly.com/uploads/2/0/9/9/20997728/...A cheetah is crouched in ambush 20 m to the east of an observer’s blind. At time t= 0 the cheetah charges

Acceleration

Constant acceleration: A special case

Free fall acceleration

Page 4: Martha Casquetemarthacasqueteutpa.weebly.com/uploads/2/0/9/9/20997728/...A cheetah is crouched in ambush 20 m to the east of an observer’s blind. At time t= 0 the cheetah charges

Motion

Position and displacement

Average velocity and average speed

Instantaneous velocity and speed

Page 5: Martha Casquetemarthacasqueteutpa.weebly.com/uploads/2/0/9/9/20997728/...A cheetah is crouched in ambush 20 m to the east of an observer’s blind. At time t= 0 the cheetah charges

Assignments: For next class: Read Chapter 3 (Vectors)

HW3 Set due next Tuesday, 9/10 Pg. 48 – 52: 5, 11, 18, 40, 49 (8th edition)

Question/Observation Thursdays Research Q/O Tuesdays with HW (due date

Tuesdays)

Page 6: Martha Casquetemarthacasqueteutpa.weebly.com/uploads/2/0/9/9/20997728/...A cheetah is crouched in ambush 20 m to the east of an observer’s blind. At time t= 0 the cheetah charges

A cheetah is crouched in ambush 20 m to the east of an observer’s blind. At time t= 0 the cheetah charges an antelope in a clearing 50 m east of the observer. The cheetah runs along a straight line. Later analysis of a videotape shows that during the first 2.0 s of the attack, the cheetah’s coordinator x varies with time according to the equation x = 20m + (5.0m/s2 )t2 a) Find the displacement of the cheetah during the interval between t1 = 1.0 s and t2 = 2.0 s

b) Find the average velocity during the same time interval. c) Find the average velocity at time t1 = 1.0 s by taking ∆t = 0.1 s. d) Derive a general expression for the instantaneous velocity as a function of time, and from it find v at t = 1.0 s and = 2.0 s.

Page 7: Martha Casquetemarthacasqueteutpa.weebly.com/uploads/2/0/9/9/20997728/...A cheetah is crouched in ambush 20 m to the east of an observer’s blind. At time t= 0 the cheetah charges

Uniform velocity is constant velocity

The instantaneous velocities are always the same, all the instantaneous velocities will also equal the average velocity

Begin with then

t

xx

t

xv

if

x

tvxx xif

x

x(t)

t 0

xi

xf

v

v(t)

t 0 tf

vx

ti

Page 8: Martha Casquetemarthacasqueteutpa.weebly.com/uploads/2/0/9/9/20997728/...A cheetah is crouched in ambush 20 m to the east of an observer’s blind. At time t= 0 the cheetah charges

Changing velocity (non-uniform) means an acceleration is present.

Acceleration is the rate of change of velocity.

Acceleration is a vector quantity.

Acceleration has both magnitude and direction.

Acceleration has a unit of [length/time2]: m/s2.

Definition: ◦ Average acceleration

◦ Instantaneous acceleration if

if

avgtt

vv

t

va

2

2

0lim

dt

vd

dt

dx

dt

d

dt

dv

t

va

t

Page 9: Martha Casquetemarthacasqueteutpa.weebly.com/uploads/2/0/9/9/20997728/...A cheetah is crouched in ambush 20 m to the east of an observer’s blind. At time t= 0 the cheetah charges

Average acceleration

Velocity as a function of time

When the sign of the velocity and the acceleration are the same (either positive or negative), then the speed is increasing

When the sign of the velocity and the acceleration are in the opposite directions, the speed is decreasing

Average acceleration is the slope of the line connecting the initial and final velocities on a velocity-time graph

if

if

avgtt

vv

t

va

tavtv avgif )(

Page 10: Martha Casquetemarthacasqueteutpa.weebly.com/uploads/2/0/9/9/20997728/...A cheetah is crouched in ambush 20 m to the east of an observer’s blind. At time t= 0 the cheetah charges

2

2

0lim

dt

vd

dt

dx

dt

d

dt

dv

t

va

t

The limit of the average acceleration as the time interval goes to zero

When the instantaneous accelerations are always the same, the acceleration will be uniform. The instantaneous acceleration will be equal to the average acceleration

September 8, 2008

Page 11: Martha Casquetemarthacasqueteutpa.weebly.com/uploads/2/0/9/9/20997728/...A cheetah is crouched in ambush 20 m to the east of an observer’s blind. At time t= 0 the cheetah charges

Velocity and acceleration are in the same direction

Acceleration is uniform (blue arrows maintain the same length)

Velocity is increasing (red arrows are getting longer)

Positive velocity and positive acceleration

atvtv if )(

Page 12: Martha Casquetemarthacasqueteutpa.weebly.com/uploads/2/0/9/9/20997728/...A cheetah is crouched in ambush 20 m to the east of an observer’s blind. At time t= 0 the cheetah charges

Position is a function of time:

Velocity is the rate of change of position.

Acceleration is the rate of change of velocity.

Position Velocity Acceleration

Graphical relationship between x, v, and a

)(txx

dt

dv

t

va

t

lim

00lim

t

x dxv

t dt

dt

d

dt

d

Page 13: Martha Casquetemarthacasqueteutpa.weebly.com/uploads/2/0/9/9/20997728/...A cheetah is crouched in ambush 20 m to the east of an observer’s blind. At time t= 0 the cheetah charges

atvv 0

2

21

0 attvx

Uniform acceleration is constant

Kinematic Equations

xavv 22

0

2

tvvtvx )(2

10

Page 14: Martha Casquetemarthacasqueteutpa.weebly.com/uploads/2/0/9/9/20997728/...A cheetah is crouched in ambush 20 m to the east of an observer’s blind. At time t= 0 the cheetah charges

Given initial conditions: ◦ a(t) = constant = a, v(t=0) = v0, x(t=0) = x0

Start with

We have

Shows velocity as a function of acceleration and

time Use when you don’t know and aren’t asked to

find the displacement

atvv 0

at

vv

t

vv

tt

vv

t

vaavg

00

0

0

0

Page 15: Martha Casquetemarthacasqueteutpa.weebly.com/uploads/2/0/9/9/20997728/...A cheetah is crouched in ambush 20 m to the east of an observer’s blind. At time t= 0 the cheetah charges

Given initial conditions:

◦ a(t) = constant = a, v(t=0) = v0, x(t=0) = x0

Start with

Since velocity change at a constant rate, we have

Gives displacement as a function of velocity and time

Use when you don’t know and aren’t asked for the acceleration

t

x

t

xxvavg

0

tvvtvx avg )(2

10

Page 16: Martha Casquetemarthacasqueteutpa.weebly.com/uploads/2/0/9/9/20997728/...A cheetah is crouched in ambush 20 m to the east of an observer’s blind. At time t= 0 the cheetah charges

Given initial conditions: ◦ a(t) = constant = a, v(t=0) = v0, x(t=0) = x0

Start with

We have

Gives displacement as a function of time, initial velocity and acceleration

Use when you don’t know and aren’t asked to find the final velocity

2

002

1atvxxx

tatvvtvvx )(2

1)(

2

1000

atvv 0

tvvtvx avg )(2

10

Page 17: Martha Casquetemarthacasqueteutpa.weebly.com/uploads/2/0/9/9/20997728/...A cheetah is crouched in ambush 20 m to the east of an observer’s blind. At time t= 0 the cheetah charges

Given initial conditions: ◦ a(t) = constant = a, v(t=0) = v0, x(t=0) = x0

Start with

We have

Gives velocity as a function of acceleration and

displacement Use when you don’t know and aren’t asked for the

time

)(22 0

2

0

2

0

2 xxavxavv

a

vvt 0

at

vv

t

vaavg

0

a

vvvvvv

atvvx

2))((

2

1)(

2

12

0

2

000

Page 18: Martha Casquetemarthacasqueteutpa.weebly.com/uploads/2/0/9/9/20997728/...A cheetah is crouched in ambush 20 m to the east of an observer’s blind. At time t= 0 the cheetah charges

Read the problem Draw a diagram ◦ Choose a coordinate system, label initial and final

points, indicate a positive direction for velocities and accelerations

Label all quantities, be sure all the units are consistent ◦ Convert if necessary

Choose the appropriate kinematic equation Solve for the unknowns ◦ You may have to solve two equations for two

unknowns

Check your results ◦ Estimate and compare ◦ Check units

Page 19: Martha Casquetemarthacasqueteutpa.weebly.com/uploads/2/0/9/9/20997728/...A cheetah is crouched in ambush 20 m to the east of an observer’s blind. At time t= 0 the cheetah charges

An electron in a cathode-ray tube accelerates from a speed of 2.00 X 10 m/s over 1.50 cm. (a) in what time interval does the electron travel this 1.50 cm? (b) What is the acceleration

Page 20: Martha Casquetemarthacasqueteutpa.weebly.com/uploads/2/0/9/9/20997728/...A cheetah is crouched in ambush 20 m to the east of an observer’s blind. At time t= 0 the cheetah charges

Earth gravity provides a constant acceleration. Most important case of constant acceleration.

Free-fall acceleration is independent of mass.

Magnitude: |a| = g = 9.8 m/s2

Direction: always downward, so ag is negative if define “up” as positive,

a = -g = -9.8 m/s2

Try to pick origin so that xi = 0

y

Galileo Galilei (1564 - 1642

Page 21: Martha Casquetemarthacasqueteutpa.weebly.com/uploads/2/0/9/9/20997728/...A cheetah is crouched in ambush 20 m to the east of an observer’s blind. At time t= 0 the cheetah charges

gtvv 0

2

002

1gttvxx

Two important equation:

Begin with t0 = 0, v0 = 0, x0 = 0

So, t2 = 2|x|/g same for two balls!

Assuming the leaning tower of Pisa is 150 ft high, neglecting air resistance,

t = (21500.305/9.8)1/2 = 3.05 s

x

0

Page 22: Martha Casquetemarthacasqueteutpa.weebly.com/uploads/2/0/9/9/20997728/...A cheetah is crouched in ambush 20 m to the east of an observer’s blind. At time t= 0 the cheetah charges

A student throws a set of keys vertically upward to her sorority sister, who is in a window 4.00m above. The key are caught 1.50 s later by the sister’s outstretched hand. (a) With what initial velocity were the keys thrown? (b) What was the velocity of the keys just before they were caught?

Page 23: Martha Casquetemarthacasqueteutpa.weebly.com/uploads/2/0/9/9/20997728/...A cheetah is crouched in ambush 20 m to the east of an observer’s blind. At time t= 0 the cheetah charges

2-23

If frictional effects (air resistance) are neglected, every freely falling object on earth accelerates at the same rate, regardless of mass. Galileo is credited with this idea/experiment.

Astronaut David Scott demonstrated the principle on the moon, simultaneously dropping a feather and a hammer. Each fell at the same acceleration, due to no atmosphere & no air resistance.

Section 2.3 http://www.youtube.com/watch?v=KDp1tiUsZw8

Page 24: Martha Casquetemarthacasqueteutpa.weebly.com/uploads/2/0/9/9/20997728/...A cheetah is crouched in ambush 20 m to the east of an observer’s blind. At time t= 0 the cheetah charges

What do you need?

Ruler

Pencil

Paper

Brain

Volunteer with two fingers

Page 25: Martha Casquetemarthacasqueteutpa.weebly.com/uploads/2/0/9/9/20997728/...A cheetah is crouched in ambush 20 m to the east of an observer’s blind. At time t= 0 the cheetah charges

This is the simplest type of motion It lays the groundwork for more complex motion Kinematic variables in one dimension

◦ Position x(t) m L ◦ Velocity v(t) m/s L/T ◦ Acceleration a(t) m/s2 L/T2 ◦ All depend on time ◦ All are vectors: magnitude and direction vector:

Equations for motion with constant acceleration: missing quantities ◦ x – x0

◦ v

◦ t

◦ a ◦ v0

2

21

0 atvtxx

tvvxx )( 021

0

September 8, 2008

atvv 0

2

21

00 attvxx

)(2 0

2

0

2xxavv


Recommended