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Math Review Class Continuous Mass Flow

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    Math Review Night

    Continuous Mass Flow

    8.01

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    Category 1: Adding Rain

    There is a transfer of material into the object but no transfer ofmomentum in the direction of motion of the object. Consider for

    example rain falling vertically downward into a moving cart. A small

    amount of rain has no component of momentum in the direction of

    motion of the cart.

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    Category 2: Leaking Sand

    The material continually leaves the object but it does not transport

    any momentum away from the object in the direction of motion of the

    object. For example, consider an ice skater gliding on ice holding a

    bag of sand that is leaking straight down with respect to the moving

    skater.

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    Category 3: Impulse

    The material continually hits the object providing an impulseresulting in a transfer of momentum to the object in the direction of

    motion. For example, suppose a fire hose is used to put out a fire on

    a boat. The incoming water continually hits the boat impulsing it

    forward.

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    Category 4: Recoil

    The material continually is ejected from the object, resulting in arecoil of the object. For example when fuel is ejected from the back

    of a rocket, the rocket recoils forward.

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    Worked Example: Coal Car

    (constant force, varying speed)An empty coal car of mass m starts from rest under an

    applied force of magnitude F. At the same time coal

    begins to run into the car at a steady rate b from a coal

    hopper at rest along the track. Find the speed when amass mcof coal has been transferred.

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    Worked Example: Emptying a

    Freight CarAn freight car of mass mccontains a mass of sand ms. At t = 0 a

    constant horizontal force of magnitude F is applied in the direction of

    rolling and at the same time a port in the bottom is opened to let the

    sand flow out at the constant rate b = dms/dt. Find the speed of the

    freight car when all the sand is gone. Assume that the freight car is at

    rest at t = 0.

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    Table Problem: Filling a Cart

    Material is blown into cart A from cart B at a rate of b

    kilograms per second. The material leaves the chute

    vertically downward, so that it has the same horizontal

    velocity u, as cart B. At the moment of interest, cart hasmass mAand velocity v. Find an expression for the rate of

    change of velocity, the instantaneous acceleration, dv/dt.

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    Worked Example: Rocket

    A rocket at time t is moving with speed vr,0 in the positive x-direction inempty space. The rocket burns the fuel at a rate dmf,out /dt =b > 0. The fuel is

    ejected backward with speed u relative to the rocket.

    a) What is the relationship between the time rate of change of exhaust

    mass dmf /dt, and the time rate of change of rocket mass dmr /dt?

    b) Find an equation for the rate of change of the speed of the rocket interms mr (t) ,u, and dmr /dt and solve for v.

    c) Find the differential equation describing the motion of the rocket if it

    is in a constant gravitational field of magnitude g

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    Strategy : Rocket Problem

    Goal: Determine velocity of rocket as function of time asmass is continuously ejected at rate dmf /dt with speed urelative to rocket.

    System: consider all elements that undergo momentumchange: rocket and fuel

    Using Momentum flow diagram, apply

    to find differential equation that describes motion.

    total total

    ext0

    ( ) ( )lim

    t

    t t t

    t! "

    + ! #=

    !

    P PF

    ! !

    !

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    Rocket Problem:

    A rocket at time t = 0 is moving with speed vr,0in the positive x-

    direction in empty space. The rocket burns the fuel at a rate dm f /dt = b >0.

    The fuel is ejected backward with speed u relative to the rocket. The goal

    is to find an equation for the rate of change of the speed of the rocket in

    terms mr (t) ,u, and dmr /dt and solve for v.

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    State at time t

    1.

    Rocket with total mass mr(t) moves with speed vr(t) in positive x-direction according to observer

    2. Total mass consists of mass of rocket mr,0and fuel mf(t)

    3. Fuel element with mass !mf,moves with speed of rocket vr(t) attime t, is ejected during interval [t,t+!t]

    4. x-component of momentum at time t

    Px ,sys

    (t) = (mr(t) + !m

    f)v

    r(t)

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    State at t+ !t

    Rocket is propelled forward by ejected fuel with new rocket speed

    Fuel is ejected backward with speed u relative to rocket. Relative toobservers frame, ejected fuel element has speed

    x-component of systems momentum at time t+!t

    vr(t+ !t) = v

    r(t) + !v

    r

    vr

    + !vr" u

    P

    x ,sys(t+ !t) =m

    r(t)(v

    r + !v

    r) + !m

    f(v

    r + !v

    r" u)

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    Rocket EquationAre there any external forces at time t?

    Two cases:

    (1) Taking off (2) Negligible gravitational field

    Apply Momentum Principle:

    Conservation of mass: Rate of decrease of mass of rocket equals rate ofejection of mass

    ocket equation:

    !

    Fext

    (t) = mr(t)

    !

    g

    !

    Fext

    =

    !

    0

    total total

    ext0

    ( ) ( )limt

    t t t

    t! "

    + ! #

    =!

    P P

    F

    ! !

    !

    !

    Fext

    = lim!t"0

    mr(t)(

    !

    vr + !

    !

    vr) + !m

    f

    !

    u # mr(t)

    !

    vr

    !t= lim!t"0

    mr(t)!

    !

    vr + !m

    f

    !

    u

    !t

    mr(t)

    !

    g = mr(t)

    d!

    vr

    dt

    +

    dmf

    dt

    !

    u

    dmf

    dt=!

    dmr (t)

    dt

    !

    Fext

    = mr(t)

    d!

    vr

    dt

    !

    dmr

    dt

    !

    u

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    Rocket Equation in Gravitational

    Field Fuel ejection term can be interpreted as thrust force

    Relative fuel ejection velocity

    External force

    Rocket equation

    Integrate with respect to time

    Solution:

    !

    Fext+

    dmr

    dt

    !

    u = mr(t)

    d!

    vr

    dt

    !

    u =!u k

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    Rocket Equation in Gravitational

    Field Fuel ejection term can be interpreted as thrust force

    Solution: shorter the burn time, the greater the velocity

    !

    Fthrust

    =

    dmr

    dt

    !

    u

    !

    Fext +

    dmr

    dt

    !

    u = mr(t)

    d!

    vr

    dt

    vr,z (tf) =u lnmr (t =0)

    mr (tf)!gtf

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    Concept Question

    Suppose rain falls vertically into an open

    cart rolling along a straight horizontal track

    with negligible friction. As a result of theaccumulating water, the speed of the cart

    1.increases.

    2.does not change.

    3.decreases.

    4.not sure.

    5.not enough information is given to decide.

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    Concept Question

    If a rocket in gravity-free outer space has the

    same thrust at all times, is its acceleration

    1.

    constant?

    2.Increasing?

    3.

    decreasing?

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    Concept Question: Rocket

    Fuel Burn TimeWhen a rocket accelerates in a gravitational field, will it reacha greater final velocity if the fuel burn time is

    1. as fast as possible?

    3. as slow as possible?

    5. The final speed is independent of the fuel burn time?

    4. Im not sure.


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