Math 104 -‐ Yu
Math 104 – Calculus 10.2 Infinite Series
Math 104 -‐ Yu
Infinite series • Given a sequence we try to make sense of the infinite sum of its terms.
Nicolas Fraiman Math 104
Infinite series• Given a sequence we try to make sense of the infinite
sum of its terms.
• Example: an =1
2n
s1 = a1 =1
2
s2 = a1 + a2 =1
2+
1
4= 0.75
s3 = a1 + a2 + a3 =1
2+
1
4+
1
8= 0.875
s8 = a1 + · · ·+ a8 =1
2+ · · ·+ 1
256= 0.996
s20 = 0.99999905
Math 104 -‐ Yu
Infinite series
Nicolas Fraiman Math 104
Infinite series
Math 104 -‐ Yu
Geometric series
Nicolas Fraiman Math 104
Geometric series• A geometric series is one in which each term is obtained
from the preceding one by multiplying it by the common ratio r.
1X
k=1
arn�1 = a+ ar + ar2 + ar3 + · · ·
Nicolas Fraiman Math 104
Geometric series• A geometric series is one in which each term is obtained
from the preceding one by multiplying it by the common ratio r.
• Does not converge for some values of r
1X
k=1
arn�1 = a+ ar + ar2 + ar3 + · · ·
r = 1 then1X
k=1
arn�1 = a+ a+ a+ a+ · · · ! 1
r = �1 then1X
k=1
arn�1 = �a+ a� a+ a� a · · ·
Nicolas Fraiman Math 104
Geometric series• A geometric series is one in which each term is obtained
from the preceding one by multiplying it by the common ratio r.
• We have
1X
k=1
arn�1 = a+ ar + ar2 + ar3 + · · ·
sn = a+ ar + ar2 + · · ·+ arn�1
rsn = ar + ar2 + ar3 + · · ·+ arn
sn � rsn = a� arn
sn =a(1� rn)
1� r
Math 104 -‐ Yu
Geometric series
Nicolas Fraiman Math 104
Geometric series
Math 104 -‐ Yu
Geometric series
Nicolas Fraiman Math 104
Geometric series
1X
n=1
1
4n=
1
3
Math 104 -‐ Yu
RepeaEng decimals
Nicolas Fraiman Math 104
Repeating decimals• We can use geometric series to convert repeating
decimals to fractions.
• Example: 1.23 = 1.2323232323 . . .
1.23 = 1 +23
100+
23
10000+
23
1000000+ · · ·
1.23 = 1 +1X
n=1
23
100n= 1 +
23/100
1� 1/100
= 1 +23/100
99/100= 1 +
23
99=
122
99
Nicolas Fraiman Math 104
Repeating decimals• We can use geometric series to convert repeating
decimals to fractions.
• Example: 1.23 = 1.2323232323 . . .
1.23 = 1 +23
100+
23
10000+
23
1000000+ · · ·
1.23 = 1 +1X
n=1
23
100n= 1 +
23/100
1� 1/100
= 1 +23/100
99/100= 1 +
23
99=
122
99
Math 104 -‐ Yu
Telescoping series
Nicolas Fraiman Math 104
Telescoping series• A telescoping series is one in which the middle terms
cancel and the sum collapses into just a few terms.
• Find the sum of the following series: 1.2.3.
1X
n=1
✓3
n2� 3
(n+ 1)2
◆
1X
n=1
3
k(k + 3)
1X
n=1
✓1
ln(n+ 2)� 1
ln(n+ 1)
◆
Nicolas Fraiman Math 104
Telescoping series• A telescoping series is one in which the middle terms
cancel and the sum collapses into just a few terms.
• Find the sum of the following series: 1.2.3.
1X
n=1
✓3
n2� 3
(n+ 1)2
◆
1X
n=1
3
k(k + 3)
1X
n=1
✓1
ln(n+ 2)� 1
ln(n+ 1)
◆
Math 104 -‐ Yu
Divergence Test
Nicolas Fraiman Math 104
Divergence test
Nicolas Fraiman Math 104
Divergence test!
!
Proof: an =nX
k=1
ak �n�1X
k=1
ak = sn � sn�1 ! L� L = 0.
Nicolas Fraiman Math 104
Divergence test!
!
Proof: an =nX
k=1
ak �n�1X
k=1
ak = sn � sn�1 ! L� L = 0.
Math 104 -‐ Yu
Examples
Nicolas Fraiman Math 104
Examples1. Does converge?2. Does converge?
!
1X
n=1
3n2
n(n+ 1)
1X
n=1
sin(n)
Nicolas Fraiman Math 104
Examples1. Does converge?2. Does converge?
!
Remark:
The converse is not true but diverges!
1X
n=1
3n2
n(n+ 1)
1X
n=1
sin(n)
1X
n=1
1
n1
n! 0
Math 104 -‐ Yu
ProperEes of convergence
Nicolas Fraiman Math 104
Properties of convergent series
Nicolas Fraiman Math 104
Properties of convergent series!
!
!
!
!
Example:1X
n=1
3
2n= 3
1X
n=1
1
2n= 3 · 1 = 3.
Math 104 -‐ Yu
Reindexing series