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Mathcad - D1

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  • 8/3/2019 Mathcad - D1

    1/15

    Client - EPSTEINProject - Alpina Foods LLCJob No - 11128Calc No - Detail-1

    Date - 11.17.2011Calc By - PSChk By - SN

    BRACE CONNECTION DETAIL-1 (Connection along Grid B and @ Grid 2.5 at Enlarged roof framing level)

    LOADS:- Vertical Shear Force Axial Force (Ten / Comp)

    Beam W18x55 V1 15kip:= (Factored) Fa1 70kip:= (Factored)Brace 2L 7x4x3/8

    (LLBB)Fb1 135kip:= (Factored)

    3"

    3"

    3"

    3"

    212"

    3"

    3"

    3"

    3"11 2

    "

    11 2

    "

    1'-9" (MIN)

    3"

    3"3"3"3"

    3"

    13

    4"

    2" 3" 2"

    1'-6

    "

    12"

    1" DIA A490 SC-TYPE (CLASS-A) BOLTS

    BOLTS IN STD HOLES

    2L7x4

    x3/8

    LLB

    B

    W

    12x65

    W18x55

    1/2" THK GUSSET PLATE

    12"

    (3/4"x3/4" CLIP CORNER)

    5/8" THK SHEAR TAB

    5/16

    5/16

    2L 7x4x3/8 LLBB

    135ki

    p

    55

    110.

    58k

    ip

    77.43 kip

    DETAIL-1

    SECTION B-B

    5/8" THK STIFFENER PLATE

    (3/4"x3/4" CLIP CORNER)

    (3/4"x3/4" CLIP CORNER)

    5/8" THK STIFFENER PLATE

    (3/4"x3/4" CLIP CORNER)

    3/4" THK STIFFENER PLATE

    1/4

    1/4

    1/2

    1/2(FLG)

    (3/8)

    3/8

    1/4

    (1/4)

    (FLG)3/8

    3/8

    1/4

    1/4

    (CJP)

    W18x55

    1/2" THK GUSSET PLATEGUSSET C/L IN LINE WITH THE BEAM C/L

    SECTION A-A

    B

    3"

    3"

    3"

    3"

    3"

    1

    5

    8"

    B

    12"

    12"

    A

    A

    SHEAR TAB TO BE SLOTTED TO

    SUIT STIFFENER

    CUT FLUSH N/S AND F/S BEAM FLANGES

    (MAX)

    CUT FLUSH N/S AND F/S BEAM FLANGES

    (SLOPED)

    1"

    JOIST THIS SIDE

    3"

    13

    4"

    3/4" A325 SC-TYPE (CLASS-A) BOLTS

    BOLTS IN STD HOLES

    5/165/16 (3 SIDES)

    (3 SIDES)5/16

    5/16

    1"

    Notes :-

    1. Connection Design confirming to AISC 13th Edition LRFD

    2. All Main steel W-Section are Grade A992 Fy50

    3. All Connection material are Grade A36 Fy36

    4. All welds are electrode class E70xx

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    Client - EPSTEINProject - Alpina Foods LLCJob No - 11128Calc No - Detail-1

    Date - 11.17.2011Calc By - PSChk By - SN

    BRACE CONNECTION DETAIL-1 (Connection along Grid B and @ Grid 2.5 at Enlarged roof framing level)

    LOADS:- Vertical Shear Force Axial Force (Ten / Comp)

    Beam W18x55 V1 15kip:= (Factored) Fa1 70kip:= (Factored)Brace 2L 7x4x3/8

    (LLBB)Fb1 135kip:= (Factored)

    SECTION PROPERTIES:-

    Beam W18x55

    db1 18.1in:= bfb1 7.53in:= tfb1 0.630in:= twb1 0.390in:= kb1 1.3125in:= k1b1 0.8125in:= Zxx1 112in3

    :=

    Column W12x65

    dc1 12.1in:= bfc1 12in:= tfc1 0.605in:= twc1 0.390in:= kc1 1.5in:= k1c1 1in:= Zxx2 96.8in3

    :=

    Brace 2L 7x4x3/8 (LLBB)

    dbr 7in:= bbr 4in:= tbr 0.375in:= Abr 7.96in2

    :=MATERIAL PROPERTIES:-

    Yield strength of ASTM Grade A992

    materialfy50 50ksi:= Shear strength of ASTM Grade

    A325 boltfnv 48ksi:=

    Ultimate strength of ASTM Grade A992

    materialfu50 65ksi:= Tensile strength of ASTM Grade

    A325 boltfnt 90ksi:=

    Yield strength of ASTM Grade A36

    materialfy36 36ksi:= Minimum bolt pre-tension for

    3/4" A325 boltTub1 28kip:=

    Ultimate strength of ASTM Grade A36

    materialfu36 58ksi:= Minimum bolt pre-tension for 1"

    A490 boltTub2 64kip:=

    Strength of weld for E70xx electrode fw 70ksi:=

    DESIGN CALCULATION

    Check for slip critical capacity of bolts in brace :-

    Bolt diameter d1 0.75in:=

    Bolt Grade ASTM Grade = A325

    Bolted Connection type Connection = Slip Critical Type (Class-A)

    Hole type in brace leg and gusset plate Type = STD Holes

    Dia. of bolt hole (in brace) dh1 0.8125in:=

    Dia of bolt hole (In gusset plate) dh2 0.8125in:=

    End distance end1 1.5in:=

    Bolt gage on the leg g1 2.5in:=

    Bolt gage on the leg g2 3in:=

    Edge distance edg1 7in g1 g2+( ):= edg1 1.50 in=Bolt spacing Sbg 3in:=

    Mean slip co-effecient for Class-A surfaces 0.35:=

    Ratio of mean installed bolt pretension

    to the specified minimum bolt pretension

    Du 1.13:=

    Hole factor (For STD Holes) hsc 1:=

    Number of slip planes Nsb 2:=

    Slip resistance offered by one

    3/4" A325 SC Type - (Class A) boltRslip1

    Du hsc Nsb Tub1

    1.0:= Rslip1 22.15 kip=

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    Client - EPSTEINProject - Alpina Foods LLCJob No - 11128Calc No - Detail-1

    Date - 11.17.2011Calc By - PSChk By - SN

    No. of 3/4" A325 SC Type - (Class A) bolts

    requiredNb

    Fb1

    Rslip1

    := Nb 6.10=

    Provide 4 rows x 2 columns (Total of 8 Nos.) of 3/4" A325 SC Type - (Class A) Bolts @ 3" Spacing

    Check for tension capacity of brace member :-

    No. of bolt rows in brace member leg Nr 4:=

    Length of the connection Lc Nr 1( ) Sbg:= Lc 9.00 in=

    Distance of C.G of the brace angle

    to the bolt connection C.Gx1 g1 g2+( ) 2.35in:= x1 3.15 in=

    Shear lag factor U 1x1

    Lc

    := U 0.65=

    Gross tension capacity of the brace Ftgb 0.9 Abr fy36:= Ftgb 257.90 kip=

    Net tension capacity of the brace Ftnb U Abr 4 dh11

    16in+

    tbr

    0.75 fu36:= Ftnb 187.96 kip=

    Minimum capacity of brace member

    in tensionFtb min Ftgb Ftnb,( ):= Ftb 187.96 kip=

    F.tb (187.97 kip) > F.b1 (135.01 kip): Therefore O.K.

    Check for block shear capacity of brace member :-

    No. of bolt columns in brace member leg Nc 2:=

    Gross shear area Agv1 Nr 1( ) Sbg end1+ tbr:= Agv1 3.94 in2

    =

    Net shear area Anv1 Nr 1( ) Sbg end1+ Nr 0.5( ) dh1 116 in+

    tbr:= Anv1 2.79 in2=

    Net tension area Ant1 g2 edg1+ Nc 0.5( ) dh11

    16in+

    tbr:= Ant1 1.20 in2

    =

    Ubs 0.5:= (Tension stress concentration is Non-Uniform, Refer J.4.3 AISC 13th Ed)

    Block shear capacity Fblock1 2 min 0.45 Agv1 fy36( ) 0.45 Anv1 fu36( ), 0.75 Ubs Ant1 fu36+:=

    F.block1 (179.58 kip) > F.b1 (135.01 kip): Therefore O.K.Fblock1 179.57 kip=

    Check for block shear capacity of gusset plate :-

    Thickness of the gusset plate tg 0.5in:=

    Gross shear area Agv2 2 Nr 1( ) Sbg end1+ tg:= Agv2 10.50 in2

    =

    Net shear area Anv2 2 Nr 1( ) Sbg end1+ Nr 0.5( ) dh21

    16in+

    tg:= Anv2 7.44 in2

    =

    Net tension area Ant2 g2 dh21

    16in+

    tg:= Ant2 1.06 in2

    =

    Ubs 1:= (Tension stress concentration is Uniform, Refer J.4.3 AISC 13th Ed)

    Block shear capacity Fblock2 min 0.45 Agv2 fy36( ) 0.45 Anv2 fu36( ), 0.75 Ubs Ant2 fu36+:=F

    block2216.32 kip=

    F.block2 (216.33 kip) > F.b1 (135.01 kip): Therefore O.K.

    Check for compression capacity of gusset plate :-

    Max effective length for out of plane buckling Leff 18in:=

    Effective length factor k1 0.75:=

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    Client - EPSTEINProject - Alpina Foods LLCJob No - 11128Calc No - Detail-1

    Date - 11.17.2011Calc By - PSChk By - SN

    Minimum radius of gyration rtg

    2

    12:= r 0.14 in=

    Slenderness ratio k1

    Leff

    r:= 93.53=

    Modulus of elasticity E 29000ksi:=

    Elastic critical buckling stress fe

    2E

    2

    := fe 32.72 ksi=

    Compressive strength Fcs 0.658

    fy36

    fe

    fy36 fe 0.44 fy36if

    0.877 fe( ) fe 0.44 fy36if

    := Fcs 22.71 ksi=

    Max available dispersion length Wd tan 30deg( ) Nr 1( ) Sbg 2 g2+:= Wd 13.39 in=Compression capacity of gusset plate Fcg 0.9 Wd tg Fcs:= Fcg 136.89 kip=

    Fcg (136.89 kip) > F.b1 (135.01 kip): Therefore O.K.

    Check for tension capacity gusset plate :-

    Effective width of gusset plate Wd tan 30deg( ) Nr 1( ) Sbg 2 g2+:= Wd 13.39 in=Gross area of the gusset plate in tension Ag2 Wd tg:= Ag2 6.70 in

    2=

    Net area of the gusset plate in tension An2 tg Wd 2 dh2 116in+

    := An2 5.82 in2=

    Tension capacity of gusset plate Ftg min 0.9 Ag2 fy36 0.75 An2 fu36,( ):= Ftg 216.96 kip=

    F.tg (216.97 kip) > F.b1 (135.01 kip): Therefore O.K.

    Check for bearing / tearing capacity of brace member and gusset plate :-

    Bearing capacity at the brace member Fbear1 0.75 2.4 d1 2 tbr Nr Nc fu36:= Fbear1 469.80 kip=

    Bearing capacity at gusset plate Fbear2 0.75 2.4 d1 tg Nr Nc fu36:= Fbear2 313.20 kip=

    Tear out due to extreme bolt at

    gusset plateF

    tear12 0.75 1.2 e

    nd1

    dh2

    2

    t

    g f

    u36:= F

    tear157.09 kip=

    Tear out due to intermediate bolts at

    gusset plateFtear2 2 0.75 1.2 Sbg dh2( ) Nr 1( ) tg fu36:= Ftear2 342.56 kip=

    Tear out due to extreme bolt at

    brace memberFtear4 2 0.75 1.2 end1

    dh1

    2

    2 tbr fu36:= Ftear4 85.64 kip=

    Tear out due to intermediate bolts at

    brace memberFtear3 2 0.75 1.2 Sbg dh1( ) Nr 1( ) 2 tbr fu36:= Ftear3 513.84 kip=

    Bearing Capacity of the

    connectionFbc1 min min Ftear1 Ftear2+( ) Ftear3 Ftear4+( ), min Fbear1 Fbear2,( ),:=

    F.bc1 (313.22 kip) > F.b1 (135.01 kip): Therefore O.K.Fbc1 313.20 kip=

    To determine beam to gusset and column to gusset interface forces due to brace axial force(Uniform Force Distribution Method) :-

    Angle of inclination of the brace

    with respect to horizontal1 55deg:=

    Length of weld B/W gusset and beam flange Lw1 21in:=

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    Client - EPSTEINProject - Alpina Foods LLCJob No - 11128Calc No - Detail-1

    Date - 11.17.2011Calc By - PSChk By - SN

    12in:=

    eb

    db1

    2

    := eb 9.05 in=

    ec 0in:= ec 0.00 in=

    eb tan 90deg 1( ) ec tan 90deg 1( )+:= 14.74 in=

    r ec+( )2

    eb+( )2

    +:= r 25.70 in=

    Vertical shear acting on the gusset and

    column interfaceVc

    rFb1:= Vc 63.04 kip=

    Axial force acting on the gusset and

    column interfaceHc

    ec

    rFb1:= Hc 0.00 kip=

    Vertical shear acting on the gusset andbeam interface Vb

    eb

    r Fb1:= Vb 47.54 kip=

    Axial force acting on the gusset and

    beam interfaceHb

    rFb1:= Hb 77.43 kip=

    To check the weld B/W the gusset plate and the beam flange :-

    Distance of the weld C.G from dd Lw1

    2 1in

    bfc1 twc1

    2+

    := dd 2.6 in=

    Moment on the weld (Since the Vb was

    transfered to the gusset to column interface)Me1 Vb := Me1 700.8 kip in=

    Shear force per mm on the fillet weld fsw1

    Hb

    2 Lw1:= fsw1 1.8 kipin

    =

    Tensile force per mm on the fillet weld

    due to Vbftw1

    Vb

    2 Lw1:= ftw1 1.1

    kip

    in=

    Tensile force per mm on the fillet weld

    due to Moment Me1ftmw1

    6Me1

    2 Lw12

    := ftmw1 4.8kip

    in=

    Peak stress per mm on weld fpeak ftw1 ftmw1+( )2

    fsw12

    +:= fpeak 6.18kip

    in=

    Average stress per mm on weld favgftw1 ftmw1+( )

    2fsw1

    2

    + ftw1 ftmw1( )2

    fsw12

    ++

    2:=

    favg 5.13kip

    in=

    2 atanftw1 ftmw1+( )

    fsw1

    := 2 72.64 deg=

    Resultant shear per mm on weld Rw max fpeak favg 1.25,( ):= Rw 6.41kip

    in=

    Size of fillet weld required Sw1

    Rw

    0.45 0.707 fw 1 0.5 sin 2( )1.5

    +

    := Sw1 0.20 in=

    Provide a minimum fillet weld of 1/4" B/W the gusset plate and the beam flange

    Check for bolts B/W beam web and the shear tab :-

    Bolt diameter d2 1in:=

    Bolt type (SC-Type / N-Type) Type = SC

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    Client - EPSTEINProject - Alpina Foods LLCJob No - 11128Calc No - Detail-1

    Date - 11.17.2011Calc By - PSChk By - SN

    Bolt Grade ASTM Grade = A490

    Hole type in member web Type = STD Holes

    Hole type in shear tab Type = STD Holes

    End distance end 1.625in:= (minimum)

    Edge distance edg 2in:=

    Bolt spacing Sbg 3in:=

    Dia. of bolt hole (In member web) dh1 1.0625in:=

    Dia. of bolt hole (In shear tab) dh2 1.0625in:=

    Shear tab thickness tsp 0.625in:=

    No. of bolt rows Nr2 6:=

    No. of bolt columns Nc2 2:=

    End clearance ec 1in:=

    Bolt gage on the shear tab gc 3in:=

    Mean slip co-effecient for Class-A surfaces 0.35:=

    Ratio of mean installed bolt pretension

    to the specified minimum bolt pretensionDu 1.13:=

    Hole factor (For STD Holes) hsc 1:=

    Number of slip planes Nsb 1:=

    Slip resistance offered by one

    1" A490 SC Type - (Class A) bolt

    Rslip2

    Du hsc Nsb Tub2

    1.0:= Rslip2 25.31 kip=

    Eccentricity of the bolt group C.G

    measured from the column webecc1

    bfc1 tfc1

    2ec+ edg+

    gc

    2+:= ecc1 10.20 in=

    Polar bolt group modulus /

    unit area of the boltIbg 342in

    2:=

    Vertical distance of the outermost bolt

    from the bolt group C.Gymax 7.5in:=

    Horizontal distance of the outermost bolt

    from the bolt group C.Gxmax 1.5in:=

    Moment on the bolt group due to beam

    shear force and eccentricity ecc1

    Mbg V1 ecc1:= Mbg 152.96 kip in=

    Vertical Shear force per bolt due to

    shear force, V1fsv

    V1

    Nr2 Nc2:= fsv 1.25 kip=

    Horizontal Shear force per bolt due to

    beam axial force, Fa1fsh

    Fa1

    Nr2 Nc2:= fsh 5.83 kip=

    Vertical Shear force per bolt due to

    moment, Mbg

    fsvm

    Mbg xmax

    Ibg

    := fsvm 0.67 kip=

    Horizontal Shear force per bolt due to

    moment, Mbg

    fshm

    Mbg ymax

    Ibg

    := fshm 3.35 kip=

    Resultant shear force / bolt Rb fsv fsvm+( )2 fsh fshm+( )2+:= Rb 9.39 kip=

    R.slip2 (25.31 kip) > R.b (9.39 kip): Therefore O.K.

    Therefore the bolts B/W the beam web and shear tab are adequate

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    Client - EPSTEINProject - Alpina Foods LLCJob No - 11128Calc No - Detail-1

    Date - 11.17.2011Calc By - PSChk By - SN

    Check for shear capacity of shear tab @ beam web :-

    Gross shear area Agv Nr2 1( ) Sbg 2 end+ tsp:= Agv 11.41 in2

    =

    Net shear area Anv Nr2 1( ) Sbg 2 end+ Nr2 dh21

    16in+

    tsp:= Anv 7.19 in2=

    Shear capacity Fshe min 0.6 Agv fy36 0.45 Anv fu36,( ):= Fshe 187.59 kip=

    Fshe (187.6 kip) > V1 (15 kip): Therefore O.K.

    Check for axial capacity of the shear tab @ beam web in tension :-

    Gross tension area Atg Nr2 1( ) Sbg 2 end+ tsp:= Atg 11.41 in2

    =

    Net tension area Atn Nr2 1( ) Sbg 2 end+ Nr2 dh21

    16in+

    tsp:= Atn 7.19 in2

    =

    Tension capacity Fax min 0.9 Atg fy36 0.75 Atn fu36,( ):= Fax 312.66 kip=F.ax (312.67 kip) > F.a1 (70 kip): Therefore O.K.

    Check for flexural capacity of the shear tab :-

    Eccentricity from the column web face

    to the first line of shear tab boltsecc2

    bfc1 tfc1

    2ec+ edg+:= ecc2 8.70 in=

    Moment due to the eccentricity Mp V1 ecc2:= Mp 10.87 kip ft=

    Length of the shear tab considered Lst Nr2 1( ) Sbg 2 end+:= Lst 18.25 in=

    Critical flexural stress in presence of shear Fcr 0.9 fy36( )2 3V

    1tsp Lst

    2

    := Fcr 32.32 ksi=

    Moment capacity of the shear tab

    based on flexural yieldingMsy Fcr

    tsp Lst2

    4:= Msy 140.16 kip ft=

    Net section modulus of the shear tab section Znet

    tsp

    4Lst

    2Sbg

    2Nr2 Nr2

    21 dh2 0.0625in+( )

    Lst

    :=

    Znet 33.84 in3

    =

    Moment capacity of the shear tab

    based on flexural rupture

    Msr 0.75fu36 Znet:= Msr 122.66 kip ft=

    Minimum capacity of the shear tab

    in flexureMm min Msy Msr,( ):= Mm 122.66 kip ft=

    M.m (122.66 kip ft) > M.p (10.87 kip ft): Therefore O.K.

    To check the tension and flexural interaction of the shear tab @ beam web :-

    Interaction Ratio RatioFa1

    Fax

    8

    9

    Mp

    Mm

    +

    Fa1

    Fax

    0.2if

    Fa1

    2Fax

    Mp

    Mm

    +

    otherwise

    := Ratio 0.30=

    Since the Interaction Ratio is less than '1', the shear tab is safe in tension and flexure interaction

    Check for block shear capacity of shear tab @ beam web for vertical shear (V1) :-

    Gross shear area Agv3 Nr2 1( ) Sbg end+ tsp:= Agv3 10.39 in2

    =

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    Client - EPSTEINProject - Alpina Foods LLCJob No - 11128Calc No - Detail-1

    Date - 11.17.2011Calc By - PSChk By - SN

    Net shear area Anv3 Nr2 1( ) Sbg end+ Nr2 0.5( ) dh21

    16in+

    tsp:= Anv3 6.52 in2

    =

    Net tension area Ant3 edg gc+( ) Nc2 0.5( ) dh2 116 in+ tsp:= Ant3 2.07 in2=

    Ubs 0.5:= (Tension stress concentration is Non-Uniform, Refer J.4.3 AISC 13th Ed)

    Block shear capacity Fblock3 min 0.45 Agv3 fy36( ) 0.45 Anv3 fu36( ), 0.75 Ubs Ant3 fu36+:=Fblock3 213.36 kip=

    F.block3 (213.37 kip) > V1 (15 kip): Therefore O.K.

    Check for block shear capacity of shear tab @ beam web for axial force :-

    Gross shear area Agv4 edg gc+( ) tsp:= Agv4 3.13 in2

    =

    Net shear area Anv4 edg gc+( ) Nc2 0.5( ) dh21

    16 in+

    tsp:= Anv4 2.07 in

    2

    =

    Net tension area Ant4 Nr2 1( ) Sbg end+ Nr2 0.5( ) dh21

    16in+

    tsp:= Ant4 6.52 in2

    =

    Ubs 0.5:= (Tension stress concentration is Non-Uniform, Refer J.4.3 AISC 13th Ed)

    Block shear capacity Fblock4 min 0.45 Agv4 fy36( ) 0.45 Anv4 fu36( ), 0.75 Ubs Ant4 fu36+:=

    F.block4 (192.52 kip) > F.a1 (70 kip): Therefore O.K.Fblock4 192.51 kip=

    Shear and tension interaction for Block shear of shear tab at beam web :-

    Interaction ratio for block shear Ratio Fa1Fblock4

    2

    V1Fblock3

    2

    +:= Ratio 0.37=

    Since the Interaction Ratio is less than '1', the shear tab is safe in tension and shear

    interaction for block shear

    Check for shear capacity of beam web :-

    Gross shear area Agv2 Nr2 1( ) Sbg 2 end+ twb1:= Agv2 7.12 in2

    =

    Net shear area Anv2 Nr2 1( ) Sbg 2 end+ Nr2 dh21

    16in+

    twb1:= Anv2 4.48 in2

    =

    Shear capacity Fshe2 min 0.6 Agv2 fy50 0.45 Anv2 fu50,( ):= Fshe2 131.19 kip=Fshe2 (131.19 kip) > V1 (15 kip): Therefore O.K.

    Check for axial capacity of the beam web in tension :-

    Gross tension area Atg2 Nr2 1( ) Sbg 2 end+ twb1:= Atg2 7.12 in2

    =

    Net tension area Atn2 Nr2 1( ) Sbg 2 end+ Nr2 dh21

    16in+

    twb1:= Atn2 4.48 in2

    =

    Tension capacity Fax2 min 0.9 Atg2 fy50 0.75 Atn2 fu50,( ):= Fax2 218.64 kip=

    F.ax2 (218.65 kip) > F.a1 (70 kip): Therefore O.K.

    Check for flexural capacity of the beam with top & bottom flange flushed on both sides of the web :-

    Eccentricity from the column web face

    to the second line of shear tab boltsecc3

    bfc1 tfc1

    2ec+ edg+ gc+:= ecc3 11.70 in=

    Moment due to the eccentricity Mbw V1 ecc3:= Mbw 14.62 kip ft=

    Length of the beam web considered Lbw db1:= Lbw 18.10 in=

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    Client - EPSTEINProject - Alpina Foods LLCJob No - 11128Calc No - Detail-1

    Date - 11.17.2011Calc By - PSChk By - SN

    Critical flexural stress on beam web

    in presence of shearFcrb 0.9 fy50( )

    23

    V1

    twb1 Lbw

    2

    := Fcrb 44.85 ksi=

    Moment capacity of the beam web

    based on flexural yieldingMsyb Fcrb

    twb1 Lbw2

    4:= Msyb 119.38 kip ft=

    Net section modulus of the beam

    web sectionZnetb

    twb1

    4Lbw

    2Sbg

    2Nr2 Nr2

    21 dh2 0.0625in+( )

    Lbw

    :=

    Znetb 20.49 in3

    =

    Moment capacity of the beam web

    based on flexural ruptureMsrb 0.75fu50 Znetb:= Msrb 83.23 kip ft=

    Minimum capacity of the beam web

    in flexure Mmb min Msyb Msrb,

    ( ):=

    Mmb 83.23 kip ft=

    M.mb (83.24 kip ft) > M.bw (14.62 kip ft): Therefore O.K.

    To check the tension and flexural interaction of the beam web :-

    Interaction Ratio RatioFa1

    Fax2

    8

    9

    Mbw

    Mmb

    +

    Fa1

    Fax2

    0.2if

    Fa1

    2Fax2

    Mbw

    Mmb

    +

    otherwise

    := Ratio 0.48=

    Since the Interaction Ratio is less than '1', the beam web is safe in tension and flexure interactionCheck for block shear capacity of beam web for vertical shear (V1) :-

    Gross shear area Agv5 Nr2 1( ) Sbg end+ twb1:= Agv5 6.48 in2

    =

    Net shear area Anv5 Nr2 1( ) Sbg end+ Nr2 0.5( ) dh11

    16in+

    twb1:= Anv5 4.07 in2

    =

    Net tension area Ant5 edg gc+( ) Nc2 0.5( ) dh11

    16in+

    twb1:= Ant5 1.29 in2

    =

    Ubs 0.5:= (Tension stress concentration is Non-Uniform, Refer J.4.3 AISC 13th Ed)

    Block shear capacity Fblock5 min 0.45 Agv5 fy50( ) 0.45 Anv5 fu50( ), 0.75 Ubs Ant5 fu50+:=Fblock5 150.56 kip=

    F.block5 (150.56 kip) > V1 (15 kip): Therefore O.K.

    Check for block shear capacity of beam web for axial force (Fa1) :-

    Gross shear area Agv6 edg gc+( ) twb1:= Agv6 1.95 in2

    =

    Net shear area Anv6 edg gc+( ) Nc2 0.5( ) dh11

    16in+

    twb1:= Anv6 1.29 in2

    =

    Net tension area Ant6 Nr2 1( ) Sbg end+ Nr2 0.5( ) dh11

    16

    in+

    twb1:= Ant6 4.07 in2

    =

    Ubs 0.5:= (Tension stress concentration is Non-Uniform, Refer J.4.3 AISC 13th Ed)

    Block shear capacity Fblock6 min 0.45 Agv6 fy50( ) 0.45 Anv6 fu50( ), 0.75 Ubs Ant6 fu50+:=

    F.block6 (137.02 kip) > F.a1 (70 kip): Therefore O.K.Fblock6 137.01 kip=

  • 8/3/2019 Mathcad - D1

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    Client - EPSTEINProject - Alpina Foods LLCJob No - 11128Calc No - Detail-1

    Date - 11.17.2011Calc By - PSChk By - SN

    Shear and tension interaction for Block shear of beam web :-

    Interaction ratio for block shear Ratio

    Fa1

    Fblock6

    2V1

    Fblock5

    2

    +:= Ratio 0.52=

    Since the Interaction Ratio is less than '1', the beam web is safe in tension and shear

    interaction for block shear

    Check for bearing / tearing capacity of shear tab at beam web for shear force V1 :-

    Bearing capacity at the beam web Fbear1 0.75 2.4 d2 twb1 Nr2 Nc2 fu50:= Fbear1 547.56 kip=

    Bearing capacity at shear tab Fbear2 0.75 2.4 d2 tsp Nr2 Nc2 fu36:= Fbear2 783.00 kip=

    Tear out due to extreme bolt at

    shear tabFtear1 2 0.75 1.2 end

    dh2

    2

    tsp fu36:= Ftear1 71.37 kip=

    Tear out due to intermediate bolts atshear tab

    Ftear2 2 0.75 1.2 Sbg dh2( ) Nr2 1( ) tsp fu36:= Ftear2 632.11 kip=

    Tear out due to extreme bolt at

    beam webFtear4 2 0.75 1.2 end

    dh1

    2

    twb1 fu50:= Ftear4 49.91 kip=

    Tear out due to intermediate bolts at

    beam webFtear3 2 0.75 1.2 Sbg dh1( ) Nr2 1( ) twb1 fu50:= Ftear3 442.04 kip=

    Bearing Capacity of the

    connectionFbc2 min min Ftear1 Ftear2+( ) Ftear3 Ftear4+( ), min Fbear1 Fbear2,( ),:=

    F.bc2 (491.97 kip) > V.1 (15 kip): Therefore O.K. Fbc2 491.95 kip=

    Check for bearing / tearing capacity of shear tab at beam web for axial force Fa1 :-

    Bearing capacity at the beam web Fbear1 0.75 2.4 d2 twb1 Nr2 Nc2 fu50:= Fbear1 547.56 kip=

    Bearing capacity at shear tab Fbear2 0.75 2.4 d2 tsp Nr2 Nc2 fu36:= Fbear2 783.00 kip=

    Tear out due to extreme bolt at

    shear tabFtear1 0.75 1.2 edg

    dh2

    2

    Nr2 tsp fu36:= Ftear1 287.51 kip=

    Tear out due to intermediate bolts at

    shear tabFtear2 0.75 1.2 gc dh2( ) Nr2 tsp fu36:= Ftear2 379.27 kip=

    Tear out due to extreme bolt at

    beam webFtear4 0.75 1.2 edg

    dh2

    2

    Nr2 twb1 fu50:= Ftear4 201.06 kip=

    Tear out due to intermediate bolts at

    beam webFtear3 0.75 1.2 gc dh2( ) Nr2 twb1 fu50( ):= Ftear3 265.22 kip=

    Bearing Capacity of the

    connectionFbc3 min min Ftear1 Ftear2+( ) Ftear3 Ftear4+( ), min Fbear1 Fbear2,( ),:=

    F.bc3 (466.3 kip) > F.a1 (70 kip): Therefore O.K.Fbc3 466.28 kip=

    Check for weld B/W the shear tab on the beam web side and the column web :-

    Length of weld available Lw2 15.5in:=

    Shear force per inch on the weld fsw1

    V1

    2 Lw2:= fsw1 0.48

    kip

    in=

    Size of fillet weld required sw1

    fsw1

    0.707 0.45 fw

    := sw1 0.02 in=

    Provide a fillet weld of 5/16" B/W the shear tab and the column web

    Check for weld B/W the shear tab on the beam web side and the top and bottom stiffeners :-

    Length of weld available Lw3

    bfc1 twc1

    20.75in:= Lw3 5.05 in=

  • 8/3/2019 Mathcad - D1

    11/15

    Client - EPSTEINProject - Alpina Foods LLCJob No - 11128Calc No - Detail-1

    Date - 11.17.2011Calc By - PSChk By - SN

    Shear force per inch on the weld fsw2

    Fa1

    4 Lw3

    Mbg

    Lw2( ) 2 Lw3+:= fsw2 4.44

    kip

    in=

    Size of fillet weld required sw2

    fsw2

    0.707 0.45 fw:= sw2 0.20 in=

    Provide a fillet weld of 5/16" B/W the shear tab on beam web side and the top and bottom stiffeners

    Size of fillet weld B/W the shear tab and

    the column web (for 16" of inch)Dw 5in:=

    Minimum shear tab thickness required

    for fillet weld size

    Minimum column web thickness required

    for fillet weld size

    tsm

    6.19 Dw

    58:= tsm 0.53 in= tcm

    3.09 Dw

    65:= tcm 0.24 in=

    Shear tab of 5/8" thk is safe for shear rupture strength of shear tab at weld

    Check for bolts B/W gusset plate and the shear tab :-

    Bolt diameter d2 1in:=

    Bolt type (SC-Type / N-Type) Type = SC

    Bolt Grade ASTM Grade = A490

    Hole type in gusset plate Type = STD Holes

    Hole type in shear tab Type = STD Holes

    End distance end 1.75in:=

    Edge distance edg 2in:=Bolt spacing Sbg 3in:=

    Dia. of bolt hole (In gusset plate) dh1 1.0625in:=

    Dia. of bolt hole (In shear tab) dh2 1.0625in:=

    No. of bolt rows Nr3 7:=

    No. of bolt columns Nc3 2:=

    End clearance ec 1in:=

    Bolt gage on the shear tab gc 3in:=

    Mean slip co-effecient for Class-A surfaces 0.35

    :=

    Ratio of mean installed bolt pretension

    to the specified minimum bolt pretensionDu 1.13:=

    Hole factor (For STD Holes) hsc 1:=

    Number of slip planes Nsb 1:=

    Slip resistance offered by one

    1" A490 SC Type - (Class A) boltRslip2

    Du hsc Nsb Tub2

    1.0:= Rslip2 25.31 kip=

    Eccentricity of the bolt group C.G

    measured from the column webecc1

    bfc1 tfc1

    2ec+ edg+

    gc

    2+:= ecc1 10.20 in=

    Polar bolt group modulus /unit area of the bolt

    Ibg 535.5in2:=

    Vertical distance of the outermost bolt

    from the bolt group C.Gymax 9in:=

    Horizontal distance of the outermost bolt

    from the bolt group C.Gxmax 1.5in:=

  • 8/3/2019 Mathcad - D1

    12/15

    Client - EPSTEINProject - Alpina Foods LLCJob No - 11128Calc No - Detail-1

    Date - 11.17.2011Calc By - PSChk By - SN

    Total shear force on gusset to

    column web interfaceVtot Vb Vc+:= Vtot 110.59 kip=

    Moment on the bolt group due to

    shear force Vtotand eccentricity ecc1

    M

    bg2

    V

    tot

    e

    cc1

    := Mbg2

    93.97 kip ft=

    Vertical Shear force per bolt due to

    shear force, Vtot

    fsv

    Vtot

    Nr3 Nc3:= fsv 7.90 kip=

    Horizontal Shear force per bolt due to

    brace horiz. componentfsh

    Hc

    Nr3 Nc3:= fsh 0.00 kip=

    Vertical Shear force per bolt due to

    moment, Mbg2

    fsvm

    Mbg2 xmax

    Ibg

    := fsvm 3.16 kip=

    Horizontal Shear force per bolt due to

    moment, M

    bg2

    fshm

    Mbg2 ymax

    Ibg

    := fshm 18.95 kip=

    Resultant shear force / bolt Rb2 fsv fsvm+( )2

    fsh fshm+( )2

    +:= Rb2 21.94 kip=

    R.slip2 (25.31 kip) > R.b2 (21.94 kip): Therefore O.K.

    Therefore 7 rows x 2 column of 1" dia A490 SC-type (Class-A) bolts @ 3" spacing and at 3" gage B/W the

    shear tab and gusset plate are adequate

    Check for shear capacity of shear tab at gusset and column interface :-

    Gross shear area Agv3 Nr3 1( ) Sbg 2 end+ tsp:= Agv3 13.44 in2

    =

    Net shear area Anv3 Nr3 1( ) Sbg 2 end+ Nr3 dh11

    16

    in+

    tsp:= Anv3 8.52 in2

    =

    Shear capacity Fshe3 min 0.6 Agv3 fy36 0.45 Anv3 fu36,( ):= Fshe3 222.26 kip=Fshe3 (222.27 kip) > V.tot (110.59 kip): Therefore O.K.

    Check for flexural capacity of the shear tab at gusset and column interface :-

    Eccentricity from the column web face

    to the first line of shear tab boltsecc2

    bfc1 tfc1

    2ec+ edg+:= ecc2 8.70 in=

    Moment due to the eccentricity Mp2 Vtot ecc2:= Mp2 80.15 kip ft=

    Total length of the shear tab Lst2 Nr3 1( ) Sbg 2 end+:= Lst2 21.50 in=

    Critical flexural stress in presence of shear Fcr2 0.9 fy36( )2

    3Vtot

    tsp Lst2

    2:= Fcr2 29.10 ksi=

    Moment capacity of the shear tab

    based on flexural yieldingMsy2 Fcr2

    tsp Lst22

    4:= Msy2 175.13 kip ft=

    Net section modulus of the shear tab section Znet2

    tsp

    4Lst2

    2Sbg

    2Nr3 Nr3

    21 dh2 0.0625in+( )

    Lst2

    :=

    Znet2 47.50 in3

    =

    Moment capacity of the shear tabbased on flexural rupture

    Msr2 0.75fu36 Znet2:= Msr2 172.20 kip ft=

    Minimum capacity of the shear tab

    in flexureMm2 min Msy2 Msr2,( ):= Mm2 172.20 kip ft=

    M.m2 (172.21 kip) > M.p2 (80.16 kip): Therefore O.K.

  • 8/3/2019 Mathcad - D1

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    Client - EPSTEINProject - Alpina Foods LLCJob No - 11128Calc No - Detail-1

    Date - 11.17.2011Calc By - PSChk By - SN

    Check for block shear capacity of shear tab for shear force Vtot :-

    Gross shear area Agv7 Nr3 1( ) Sbg end+ tsp:= Agv7 12.34 in2

    =

    Net shear area Anv7 Nr3 1( ) Sbg end+ Nr3 0.5( ) dh21

    16in+

    tsp:= Anv7 7.77 in2

    =

    Net tension area Ant7 edg gc+( ) Nc3 0.5( ) dh21

    16in+

    tsp:= Ant7 2.07 in2

    =

    Ubs 0.5:= (Tension stress concentration is Non-Uniform, Refer J.4.3 AISC 13th Ed)

    Block shear capacity Fblock7 min 0.45 Agv7 fy36( ) 0.45 Anv7 fu36( ), 0.75 Ubs Ant7 fu36+:=

    F.block7 (245.01 kip) > V.tot (110.59 kip): Therefore O.K.Fblock7 245.00 kip=

    Check for shear capacity of gusset plate :-

    Gross shear area Agv8 Nr3 1( ) Sbg 2 end+ tg:= Agv8 10.75 in2=

    Net shear area Anv8 Nr3 1( ) Sbg 2 end+ Nr3 dh11

    16in+

    tg:= Anv8 6.81 in2

    =

    Shear capacity Fshe4 min 0.6 Agv8 fy36 0.45 Anv8 fu36,( ):= Fshe4 177.81 kip=

    Fshe4 (177.82 kip) > V.tot (110.59 kip): Therefore O.K.

    Check for block shear capacity of gusset plate for shear force Vtot :-

    Gross shear area Agv9 Nr3 1( ) Sbg end+ tg:= Agv9 9.87 in2

    =

    Net shear area Anv9 Nr3 1( ) Sbg end+ Nr3 0.5( ) dh11

    16 in+

    tg:= Anv9 6.22 in2

    =

    Net tension area Ant9 edg gc+( ) Nc3 0.5( ) dh11

    16in+

    tg:= Ant9 1.66 in2

    =

    Ubs 0.5:= (Tension stress concentration is Non-Uniform, Refer J.4.3 AISC 13th Ed)

    Block shear capacity Fblock9 min 0.45 Agv9 fy36( ) 0.45 Anv9 fu36( ), 0.75 Ubs Ant9 fu36+:=

    F.block9 (196.01 kip) > V.tot (110.59 kip): Therefore O.K.Fblock9 196.00 kip=

    Check for bearing / tearing capacity of shear tab & gusset plate for shear force Vtot :-

    Bearing capacity at the gusset plate Fbear1 0.75 2.4 d2 tg Nr3 Nc3 fu36:= Fbear1 730.80 kip=

    Bearing capacity at shear tab Fbear2 0.75 2.4 d2 tsp Nr3 Nc3 fu36:= Fbear2 913.50 kip=

    Tear out due to extreme bolt at

    shear tabFtear1 2 0.75 1.2 end

    dh2

    2

    tsp fu36:= Ftear1 79.52 kip=

    Tear out due to intermediate bolts at

    shear tabFtear2 2 0.75 1.2 Sbg dh2( ) Nr3 1( ) tsp fu36:= Ftear2 758.53 kip=

    Tear out due to extreme bolt at

    beam webFtear4 2 0.75 1.2 end

    dh1

    2

    tg fu36:= Ftear4 63.62 kip=

    Tear out due to intermediate bolts at

    beam webFtear3 2 0.75 1.2 Sbg dh1( ) Nr3 1( ) tg fu36:= Ftear3 606.82 kip=

    Bearing Capacity of the

    connectionF

    bc4min min F

    tear1F

    tear2+

    ( )F

    tear3F

    tear4+

    ( ), min F

    bear1F

    bear2,

    ( ),:=

    F.bc4 (670.48 kip) > V.tot (110.59 kip): Therefore O.K. Fbc4 670.44 kip=

    Check for weld B/W the shear tab on the gusset plate side and the column web :-

    Length of weld available Lw4 Lst2 2 0.75 in:= Lw4 20.00 in=

  • 8/3/2019 Mathcad - D1

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    Client - EPSTEINProject - Alpina Foods LLCJob No - 11128Calc No - Detail-1

    Date - 11.17.2011Calc By - PSChk By - SN

    Shear force per inch on the weld fsw3

    Vtot

    2 Lw4:= fsw3 2.76

    kip

    in=

    Size of fillet weld required sw3

    fsw3

    0.707 0.45 fw:= sw3 0.12 in=

    Provide a fillet weld of 5/16" B/W the shear tab and the column web

    Size of fillet weld B/W the shear tab and

    the column web (for 16" of inch)Dw 5in:=

    Minimum shear tab thickness

    required for fillet weld sizetsm

    6.19 Dw

    58:= tsm 0.53 in=

    Shear tab of 5/8" thk is safe for shear rupture strength of shear tab at weld

    Shear capacity of the gusset plate at the beam to gusset plate weld :-

    Length of weld B/W the gusset andthe beam flange

    Lg Lw1:= Lg 21.00 in=

    Gross shear capacity of the gusset plate Fsg 0.6 tg Lg fy36:= Fsg 226.80 kip=

    F.sg (226.81 kip) > H.b (77.44 kip): Therefore O.K.

    Moment capacity of the gusset plate at the beam to gusset weld :-

    Critical flexural stress in presence of shear Fcr3 0.9 fy36( )2

    3Hb

    tg Lg

    2

    := Fcr3 29.78 ksi=

    Moment capacity of the gusset platebased on flexural yielding

    Msy3 Fcr3

    tg Lg2

    4:= Msy3 136.78 kip ft=

    M.sy3 (136.79 kip) > M.e1 (58.4 kip): Therefore O.K.

    Check for weld B/W shear tab @ gusset side and middle / bottom most stiffener supporting the gusset :-

    Moment on the weld group Me2 Vtot ecc1:= Me2 93.97 kip ft=

    Length of weld available for shear tab

    weld to stiffenerLw5

    bfc1 twc1

    20.75in:= Lw5 5.05 in=

    Shear force per inch on the weld fsw4

    Me2

    Lw4( ) 2 Lw5:= fsw4 5.58

    kip

    in=

    Size of fillet weld required sw4

    fsw4

    0.707 0.45 fw:= sw4 0.25 in=

    Provide a fillet weld of 5/16" B/W the shear tab on gusset plate side and the top and bottom stiffeners

    Size of fillet weld B/W the shear tab and

    the stiffener plate (for 16" of inch)Dw 5in:=

    Minimum shear tab thickness

    required for fillet weld sizetsm

    6.19 Dw

    58:= tsm 0.53 in=

    Shear tab of 5/8" thk is safe for shear rupture strength of shear tab at weld

    Check for weld B/W the bottom most stiffener supporting the gusset plate with the column flange :-

    Length of weld available Lw6

    bfc1 twc1

    20.75in:= Lw6 5.05 in=

    Shear force per inch on the weld fsw5

    Me2

    Lw4( ) 4 Lw6:= fsw5 2.79

    kip

    in=

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    Client - EPSTEINProject - Alpina Foods LLCJob No - 11128Calc No - Detail-1

    Date - 11.17.2011Calc By - PSChk By - SN

    Size of fillet weld required sw5

    fsw5

    0.707 0.45 fw:= sw5 0.13 in=

    Thickness of bottom most stiffener tst1 0.625in:=Shear capacity of the stiffener Ftst1 0.6 Lw6 tst1 fy36:= Ftst1 68.24 kip=

    Shear force on the stiffener Fsf1

    Me2

    Lw4

    := Fsf1 56.38 kip=

    Ft.st1 (68.25 kip) > F.sf1 (56.39 kip): Therefore O.K.

    Provide a fillet weld of 5/16" B/W the stiffener and the column flange

    Check for weld B/W the top most stiffener supporting the shear tab on the beam web side

    with the column flange :-

    Length of weld available Lw7

    bfc1 twc1

    2 0.75in:= Lw7 5.05 in=

    Shear force per inch on the weld fsw6

    Mbg

    Lw2 4 Lw7:= fsw6 0.49

    kip

    in=

    Size of fillet weld required sw6

    fsw6

    0.707 0.45 fw:= sw6 0.02 in=

    Thickness of top most stiffener tst2 0.625in:=

    Shear capacity of the stiffener Ftst2 0.6 Lw7 tst2 fy36:= Ftst2 68.24 kip=

    Shear force on the stiffener Fsf2

    Mbg

    Lw2

    := Fsf2

    9.87 kip=

    Ft.st2 (68.25 kip) > F.sf2 (9.87 kip): Therefore O.K.

    Provide a fillet weld of 5/16" B/W the bottom side of the stiffener and the column flange and 5/16" PPW

    B/W the top of the stiffener and the column flange


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