Date post: | 06-Apr-2018 |
Category: |
Documents |
Upload: | sivanantham-ramachandiran |
View: | 292 times |
Download: | 9 times |
of 15
8/3/2019 Mathcad - D1
1/15
Client - EPSTEINProject - Alpina Foods LLCJob No - 11128Calc No - Detail-1
Date - 11.17.2011Calc By - PSChk By - SN
BRACE CONNECTION DETAIL-1 (Connection along Grid B and @ Grid 2.5 at Enlarged roof framing level)
LOADS:- Vertical Shear Force Axial Force (Ten / Comp)
Beam W18x55 V1 15kip:= (Factored) Fa1 70kip:= (Factored)Brace 2L 7x4x3/8
(LLBB)Fb1 135kip:= (Factored)
3"
3"
3"
3"
212"
3"
3"
3"
3"11 2
"
11 2
"
1'-9" (MIN)
3"
3"3"3"3"
3"
13
4"
2" 3" 2"
1'-6
"
12"
1" DIA A490 SC-TYPE (CLASS-A) BOLTS
BOLTS IN STD HOLES
2L7x4
x3/8
LLB
B
W
12x65
W18x55
1/2" THK GUSSET PLATE
12"
(3/4"x3/4" CLIP CORNER)
5/8" THK SHEAR TAB
5/16
5/16
2L 7x4x3/8 LLBB
135ki
p
55
110.
58k
ip
77.43 kip
DETAIL-1
SECTION B-B
5/8" THK STIFFENER PLATE
(3/4"x3/4" CLIP CORNER)
(3/4"x3/4" CLIP CORNER)
5/8" THK STIFFENER PLATE
(3/4"x3/4" CLIP CORNER)
3/4" THK STIFFENER PLATE
1/4
1/4
1/2
1/2(FLG)
(3/8)
3/8
1/4
(1/4)
(FLG)3/8
3/8
1/4
1/4
(CJP)
W18x55
1/2" THK GUSSET PLATEGUSSET C/L IN LINE WITH THE BEAM C/L
SECTION A-A
B
3"
3"
3"
3"
3"
1
5
8"
B
12"
12"
A
A
SHEAR TAB TO BE SLOTTED TO
SUIT STIFFENER
CUT FLUSH N/S AND F/S BEAM FLANGES
(MAX)
CUT FLUSH N/S AND F/S BEAM FLANGES
(SLOPED)
1"
JOIST THIS SIDE
3"
13
4"
3/4" A325 SC-TYPE (CLASS-A) BOLTS
BOLTS IN STD HOLES
5/165/16 (3 SIDES)
(3 SIDES)5/16
5/16
1"
Notes :-
1. Connection Design confirming to AISC 13th Edition LRFD
2. All Main steel W-Section are Grade A992 Fy50
3. All Connection material are Grade A36 Fy36
4. All welds are electrode class E70xx
8/3/2019 Mathcad - D1
2/15
Client - EPSTEINProject - Alpina Foods LLCJob No - 11128Calc No - Detail-1
Date - 11.17.2011Calc By - PSChk By - SN
BRACE CONNECTION DETAIL-1 (Connection along Grid B and @ Grid 2.5 at Enlarged roof framing level)
LOADS:- Vertical Shear Force Axial Force (Ten / Comp)
Beam W18x55 V1 15kip:= (Factored) Fa1 70kip:= (Factored)Brace 2L 7x4x3/8
(LLBB)Fb1 135kip:= (Factored)
SECTION PROPERTIES:-
Beam W18x55
db1 18.1in:= bfb1 7.53in:= tfb1 0.630in:= twb1 0.390in:= kb1 1.3125in:= k1b1 0.8125in:= Zxx1 112in3
:=
Column W12x65
dc1 12.1in:= bfc1 12in:= tfc1 0.605in:= twc1 0.390in:= kc1 1.5in:= k1c1 1in:= Zxx2 96.8in3
:=
Brace 2L 7x4x3/8 (LLBB)
dbr 7in:= bbr 4in:= tbr 0.375in:= Abr 7.96in2
:=MATERIAL PROPERTIES:-
Yield strength of ASTM Grade A992
materialfy50 50ksi:= Shear strength of ASTM Grade
A325 boltfnv 48ksi:=
Ultimate strength of ASTM Grade A992
materialfu50 65ksi:= Tensile strength of ASTM Grade
A325 boltfnt 90ksi:=
Yield strength of ASTM Grade A36
materialfy36 36ksi:= Minimum bolt pre-tension for
3/4" A325 boltTub1 28kip:=
Ultimate strength of ASTM Grade A36
materialfu36 58ksi:= Minimum bolt pre-tension for 1"
A490 boltTub2 64kip:=
Strength of weld for E70xx electrode fw 70ksi:=
DESIGN CALCULATION
Check for slip critical capacity of bolts in brace :-
Bolt diameter d1 0.75in:=
Bolt Grade ASTM Grade = A325
Bolted Connection type Connection = Slip Critical Type (Class-A)
Hole type in brace leg and gusset plate Type = STD Holes
Dia. of bolt hole (in brace) dh1 0.8125in:=
Dia of bolt hole (In gusset plate) dh2 0.8125in:=
End distance end1 1.5in:=
Bolt gage on the leg g1 2.5in:=
Bolt gage on the leg g2 3in:=
Edge distance edg1 7in g1 g2+( ):= edg1 1.50 in=Bolt spacing Sbg 3in:=
Mean slip co-effecient for Class-A surfaces 0.35:=
Ratio of mean installed bolt pretension
to the specified minimum bolt pretension
Du 1.13:=
Hole factor (For STD Holes) hsc 1:=
Number of slip planes Nsb 2:=
Slip resistance offered by one
3/4" A325 SC Type - (Class A) boltRslip1
Du hsc Nsb Tub1
1.0:= Rslip1 22.15 kip=
8/3/2019 Mathcad - D1
3/15
Client - EPSTEINProject - Alpina Foods LLCJob No - 11128Calc No - Detail-1
Date - 11.17.2011Calc By - PSChk By - SN
No. of 3/4" A325 SC Type - (Class A) bolts
requiredNb
Fb1
Rslip1
:= Nb 6.10=
Provide 4 rows x 2 columns (Total of 8 Nos.) of 3/4" A325 SC Type - (Class A) Bolts @ 3" Spacing
Check for tension capacity of brace member :-
No. of bolt rows in brace member leg Nr 4:=
Length of the connection Lc Nr 1( ) Sbg:= Lc 9.00 in=
Distance of C.G of the brace angle
to the bolt connection C.Gx1 g1 g2+( ) 2.35in:= x1 3.15 in=
Shear lag factor U 1x1
Lc
:= U 0.65=
Gross tension capacity of the brace Ftgb 0.9 Abr fy36:= Ftgb 257.90 kip=
Net tension capacity of the brace Ftnb U Abr 4 dh11
16in+
tbr
0.75 fu36:= Ftnb 187.96 kip=
Minimum capacity of brace member
in tensionFtb min Ftgb Ftnb,( ):= Ftb 187.96 kip=
F.tb (187.97 kip) > F.b1 (135.01 kip): Therefore O.K.
Check for block shear capacity of brace member :-
No. of bolt columns in brace member leg Nc 2:=
Gross shear area Agv1 Nr 1( ) Sbg end1+ tbr:= Agv1 3.94 in2
=
Net shear area Anv1 Nr 1( ) Sbg end1+ Nr 0.5( ) dh1 116 in+
tbr:= Anv1 2.79 in2=
Net tension area Ant1 g2 edg1+ Nc 0.5( ) dh11
16in+
tbr:= Ant1 1.20 in2
=
Ubs 0.5:= (Tension stress concentration is Non-Uniform, Refer J.4.3 AISC 13th Ed)
Block shear capacity Fblock1 2 min 0.45 Agv1 fy36( ) 0.45 Anv1 fu36( ), 0.75 Ubs Ant1 fu36+:=
F.block1 (179.58 kip) > F.b1 (135.01 kip): Therefore O.K.Fblock1 179.57 kip=
Check for block shear capacity of gusset plate :-
Thickness of the gusset plate tg 0.5in:=
Gross shear area Agv2 2 Nr 1( ) Sbg end1+ tg:= Agv2 10.50 in2
=
Net shear area Anv2 2 Nr 1( ) Sbg end1+ Nr 0.5( ) dh21
16in+
tg:= Anv2 7.44 in2
=
Net tension area Ant2 g2 dh21
16in+
tg:= Ant2 1.06 in2
=
Ubs 1:= (Tension stress concentration is Uniform, Refer J.4.3 AISC 13th Ed)
Block shear capacity Fblock2 min 0.45 Agv2 fy36( ) 0.45 Anv2 fu36( ), 0.75 Ubs Ant2 fu36+:=F
block2216.32 kip=
F.block2 (216.33 kip) > F.b1 (135.01 kip): Therefore O.K.
Check for compression capacity of gusset plate :-
Max effective length for out of plane buckling Leff 18in:=
Effective length factor k1 0.75:=
8/3/2019 Mathcad - D1
4/15
Client - EPSTEINProject - Alpina Foods LLCJob No - 11128Calc No - Detail-1
Date - 11.17.2011Calc By - PSChk By - SN
Minimum radius of gyration rtg
2
12:= r 0.14 in=
Slenderness ratio k1
Leff
r:= 93.53=
Modulus of elasticity E 29000ksi:=
Elastic critical buckling stress fe
2E
2
:= fe 32.72 ksi=
Compressive strength Fcs 0.658
fy36
fe
fy36 fe 0.44 fy36if
0.877 fe( ) fe 0.44 fy36if
:= Fcs 22.71 ksi=
Max available dispersion length Wd tan 30deg( ) Nr 1( ) Sbg 2 g2+:= Wd 13.39 in=Compression capacity of gusset plate Fcg 0.9 Wd tg Fcs:= Fcg 136.89 kip=
Fcg (136.89 kip) > F.b1 (135.01 kip): Therefore O.K.
Check for tension capacity gusset plate :-
Effective width of gusset plate Wd tan 30deg( ) Nr 1( ) Sbg 2 g2+:= Wd 13.39 in=Gross area of the gusset plate in tension Ag2 Wd tg:= Ag2 6.70 in
2=
Net area of the gusset plate in tension An2 tg Wd 2 dh2 116in+
:= An2 5.82 in2=
Tension capacity of gusset plate Ftg min 0.9 Ag2 fy36 0.75 An2 fu36,( ):= Ftg 216.96 kip=
F.tg (216.97 kip) > F.b1 (135.01 kip): Therefore O.K.
Check for bearing / tearing capacity of brace member and gusset plate :-
Bearing capacity at the brace member Fbear1 0.75 2.4 d1 2 tbr Nr Nc fu36:= Fbear1 469.80 kip=
Bearing capacity at gusset plate Fbear2 0.75 2.4 d1 tg Nr Nc fu36:= Fbear2 313.20 kip=
Tear out due to extreme bolt at
gusset plateF
tear12 0.75 1.2 e
nd1
dh2
2
t
g f
u36:= F
tear157.09 kip=
Tear out due to intermediate bolts at
gusset plateFtear2 2 0.75 1.2 Sbg dh2( ) Nr 1( ) tg fu36:= Ftear2 342.56 kip=
Tear out due to extreme bolt at
brace memberFtear4 2 0.75 1.2 end1
dh1
2
2 tbr fu36:= Ftear4 85.64 kip=
Tear out due to intermediate bolts at
brace memberFtear3 2 0.75 1.2 Sbg dh1( ) Nr 1( ) 2 tbr fu36:= Ftear3 513.84 kip=
Bearing Capacity of the
connectionFbc1 min min Ftear1 Ftear2+( ) Ftear3 Ftear4+( ), min Fbear1 Fbear2,( ),:=
F.bc1 (313.22 kip) > F.b1 (135.01 kip): Therefore O.K.Fbc1 313.20 kip=
To determine beam to gusset and column to gusset interface forces due to brace axial force(Uniform Force Distribution Method) :-
Angle of inclination of the brace
with respect to horizontal1 55deg:=
Length of weld B/W gusset and beam flange Lw1 21in:=
8/3/2019 Mathcad - D1
5/15
Client - EPSTEINProject - Alpina Foods LLCJob No - 11128Calc No - Detail-1
Date - 11.17.2011Calc By - PSChk By - SN
12in:=
eb
db1
2
:= eb 9.05 in=
ec 0in:= ec 0.00 in=
eb tan 90deg 1( ) ec tan 90deg 1( )+:= 14.74 in=
r ec+( )2
eb+( )2
+:= r 25.70 in=
Vertical shear acting on the gusset and
column interfaceVc
rFb1:= Vc 63.04 kip=
Axial force acting on the gusset and
column interfaceHc
ec
rFb1:= Hc 0.00 kip=
Vertical shear acting on the gusset andbeam interface Vb
eb
r Fb1:= Vb 47.54 kip=
Axial force acting on the gusset and
beam interfaceHb
rFb1:= Hb 77.43 kip=
To check the weld B/W the gusset plate and the beam flange :-
Distance of the weld C.G from dd Lw1
2 1in
bfc1 twc1
2+
:= dd 2.6 in=
Moment on the weld (Since the Vb was
transfered to the gusset to column interface)Me1 Vb := Me1 700.8 kip in=
Shear force per mm on the fillet weld fsw1
Hb
2 Lw1:= fsw1 1.8 kipin
=
Tensile force per mm on the fillet weld
due to Vbftw1
Vb
2 Lw1:= ftw1 1.1
kip
in=
Tensile force per mm on the fillet weld
due to Moment Me1ftmw1
6Me1
2 Lw12
:= ftmw1 4.8kip
in=
Peak stress per mm on weld fpeak ftw1 ftmw1+( )2
fsw12
+:= fpeak 6.18kip
in=
Average stress per mm on weld favgftw1 ftmw1+( )
2fsw1
2
+ ftw1 ftmw1( )2
fsw12
++
2:=
favg 5.13kip
in=
2 atanftw1 ftmw1+( )
fsw1
:= 2 72.64 deg=
Resultant shear per mm on weld Rw max fpeak favg 1.25,( ):= Rw 6.41kip
in=
Size of fillet weld required Sw1
Rw
0.45 0.707 fw 1 0.5 sin 2( )1.5
+
:= Sw1 0.20 in=
Provide a minimum fillet weld of 1/4" B/W the gusset plate and the beam flange
Check for bolts B/W beam web and the shear tab :-
Bolt diameter d2 1in:=
Bolt type (SC-Type / N-Type) Type = SC
8/3/2019 Mathcad - D1
6/15
Client - EPSTEINProject - Alpina Foods LLCJob No - 11128Calc No - Detail-1
Date - 11.17.2011Calc By - PSChk By - SN
Bolt Grade ASTM Grade = A490
Hole type in member web Type = STD Holes
Hole type in shear tab Type = STD Holes
End distance end 1.625in:= (minimum)
Edge distance edg 2in:=
Bolt spacing Sbg 3in:=
Dia. of bolt hole (In member web) dh1 1.0625in:=
Dia. of bolt hole (In shear tab) dh2 1.0625in:=
Shear tab thickness tsp 0.625in:=
No. of bolt rows Nr2 6:=
No. of bolt columns Nc2 2:=
End clearance ec 1in:=
Bolt gage on the shear tab gc 3in:=
Mean slip co-effecient for Class-A surfaces 0.35:=
Ratio of mean installed bolt pretension
to the specified minimum bolt pretensionDu 1.13:=
Hole factor (For STD Holes) hsc 1:=
Number of slip planes Nsb 1:=
Slip resistance offered by one
1" A490 SC Type - (Class A) bolt
Rslip2
Du hsc Nsb Tub2
1.0:= Rslip2 25.31 kip=
Eccentricity of the bolt group C.G
measured from the column webecc1
bfc1 tfc1
2ec+ edg+
gc
2+:= ecc1 10.20 in=
Polar bolt group modulus /
unit area of the boltIbg 342in
2:=
Vertical distance of the outermost bolt
from the bolt group C.Gymax 7.5in:=
Horizontal distance of the outermost bolt
from the bolt group C.Gxmax 1.5in:=
Moment on the bolt group due to beam
shear force and eccentricity ecc1
Mbg V1 ecc1:= Mbg 152.96 kip in=
Vertical Shear force per bolt due to
shear force, V1fsv
V1
Nr2 Nc2:= fsv 1.25 kip=
Horizontal Shear force per bolt due to
beam axial force, Fa1fsh
Fa1
Nr2 Nc2:= fsh 5.83 kip=
Vertical Shear force per bolt due to
moment, Mbg
fsvm
Mbg xmax
Ibg
:= fsvm 0.67 kip=
Horizontal Shear force per bolt due to
moment, Mbg
fshm
Mbg ymax
Ibg
:= fshm 3.35 kip=
Resultant shear force / bolt Rb fsv fsvm+( )2 fsh fshm+( )2+:= Rb 9.39 kip=
R.slip2 (25.31 kip) > R.b (9.39 kip): Therefore O.K.
Therefore the bolts B/W the beam web and shear tab are adequate
8/3/2019 Mathcad - D1
7/15
Client - EPSTEINProject - Alpina Foods LLCJob No - 11128Calc No - Detail-1
Date - 11.17.2011Calc By - PSChk By - SN
Check for shear capacity of shear tab @ beam web :-
Gross shear area Agv Nr2 1( ) Sbg 2 end+ tsp:= Agv 11.41 in2
=
Net shear area Anv Nr2 1( ) Sbg 2 end+ Nr2 dh21
16in+
tsp:= Anv 7.19 in2=
Shear capacity Fshe min 0.6 Agv fy36 0.45 Anv fu36,( ):= Fshe 187.59 kip=
Fshe (187.6 kip) > V1 (15 kip): Therefore O.K.
Check for axial capacity of the shear tab @ beam web in tension :-
Gross tension area Atg Nr2 1( ) Sbg 2 end+ tsp:= Atg 11.41 in2
=
Net tension area Atn Nr2 1( ) Sbg 2 end+ Nr2 dh21
16in+
tsp:= Atn 7.19 in2
=
Tension capacity Fax min 0.9 Atg fy36 0.75 Atn fu36,( ):= Fax 312.66 kip=F.ax (312.67 kip) > F.a1 (70 kip): Therefore O.K.
Check for flexural capacity of the shear tab :-
Eccentricity from the column web face
to the first line of shear tab boltsecc2
bfc1 tfc1
2ec+ edg+:= ecc2 8.70 in=
Moment due to the eccentricity Mp V1 ecc2:= Mp 10.87 kip ft=
Length of the shear tab considered Lst Nr2 1( ) Sbg 2 end+:= Lst 18.25 in=
Critical flexural stress in presence of shear Fcr 0.9 fy36( )2 3V
1tsp Lst
2
:= Fcr 32.32 ksi=
Moment capacity of the shear tab
based on flexural yieldingMsy Fcr
tsp Lst2
4:= Msy 140.16 kip ft=
Net section modulus of the shear tab section Znet
tsp
4Lst
2Sbg
2Nr2 Nr2
21 dh2 0.0625in+( )
Lst
:=
Znet 33.84 in3
=
Moment capacity of the shear tab
based on flexural rupture
Msr 0.75fu36 Znet:= Msr 122.66 kip ft=
Minimum capacity of the shear tab
in flexureMm min Msy Msr,( ):= Mm 122.66 kip ft=
M.m (122.66 kip ft) > M.p (10.87 kip ft): Therefore O.K.
To check the tension and flexural interaction of the shear tab @ beam web :-
Interaction Ratio RatioFa1
Fax
8
9
Mp
Mm
+
Fa1
Fax
0.2if
Fa1
2Fax
Mp
Mm
+
otherwise
:= Ratio 0.30=
Since the Interaction Ratio is less than '1', the shear tab is safe in tension and flexure interaction
Check for block shear capacity of shear tab @ beam web for vertical shear (V1) :-
Gross shear area Agv3 Nr2 1( ) Sbg end+ tsp:= Agv3 10.39 in2
=
8/3/2019 Mathcad - D1
8/15
Client - EPSTEINProject - Alpina Foods LLCJob No - 11128Calc No - Detail-1
Date - 11.17.2011Calc By - PSChk By - SN
Net shear area Anv3 Nr2 1( ) Sbg end+ Nr2 0.5( ) dh21
16in+
tsp:= Anv3 6.52 in2
=
Net tension area Ant3 edg gc+( ) Nc2 0.5( ) dh2 116 in+ tsp:= Ant3 2.07 in2=
Ubs 0.5:= (Tension stress concentration is Non-Uniform, Refer J.4.3 AISC 13th Ed)
Block shear capacity Fblock3 min 0.45 Agv3 fy36( ) 0.45 Anv3 fu36( ), 0.75 Ubs Ant3 fu36+:=Fblock3 213.36 kip=
F.block3 (213.37 kip) > V1 (15 kip): Therefore O.K.
Check for block shear capacity of shear tab @ beam web for axial force :-
Gross shear area Agv4 edg gc+( ) tsp:= Agv4 3.13 in2
=
Net shear area Anv4 edg gc+( ) Nc2 0.5( ) dh21
16 in+
tsp:= Anv4 2.07 in
2
=
Net tension area Ant4 Nr2 1( ) Sbg end+ Nr2 0.5( ) dh21
16in+
tsp:= Ant4 6.52 in2
=
Ubs 0.5:= (Tension stress concentration is Non-Uniform, Refer J.4.3 AISC 13th Ed)
Block shear capacity Fblock4 min 0.45 Agv4 fy36( ) 0.45 Anv4 fu36( ), 0.75 Ubs Ant4 fu36+:=
F.block4 (192.52 kip) > F.a1 (70 kip): Therefore O.K.Fblock4 192.51 kip=
Shear and tension interaction for Block shear of shear tab at beam web :-
Interaction ratio for block shear Ratio Fa1Fblock4
2
V1Fblock3
2
+:= Ratio 0.37=
Since the Interaction Ratio is less than '1', the shear tab is safe in tension and shear
interaction for block shear
Check for shear capacity of beam web :-
Gross shear area Agv2 Nr2 1( ) Sbg 2 end+ twb1:= Agv2 7.12 in2
=
Net shear area Anv2 Nr2 1( ) Sbg 2 end+ Nr2 dh21
16in+
twb1:= Anv2 4.48 in2
=
Shear capacity Fshe2 min 0.6 Agv2 fy50 0.45 Anv2 fu50,( ):= Fshe2 131.19 kip=Fshe2 (131.19 kip) > V1 (15 kip): Therefore O.K.
Check for axial capacity of the beam web in tension :-
Gross tension area Atg2 Nr2 1( ) Sbg 2 end+ twb1:= Atg2 7.12 in2
=
Net tension area Atn2 Nr2 1( ) Sbg 2 end+ Nr2 dh21
16in+
twb1:= Atn2 4.48 in2
=
Tension capacity Fax2 min 0.9 Atg2 fy50 0.75 Atn2 fu50,( ):= Fax2 218.64 kip=
F.ax2 (218.65 kip) > F.a1 (70 kip): Therefore O.K.
Check for flexural capacity of the beam with top & bottom flange flushed on both sides of the web :-
Eccentricity from the column web face
to the second line of shear tab boltsecc3
bfc1 tfc1
2ec+ edg+ gc+:= ecc3 11.70 in=
Moment due to the eccentricity Mbw V1 ecc3:= Mbw 14.62 kip ft=
Length of the beam web considered Lbw db1:= Lbw 18.10 in=
8/3/2019 Mathcad - D1
9/15
Client - EPSTEINProject - Alpina Foods LLCJob No - 11128Calc No - Detail-1
Date - 11.17.2011Calc By - PSChk By - SN
Critical flexural stress on beam web
in presence of shearFcrb 0.9 fy50( )
23
V1
twb1 Lbw
2
:= Fcrb 44.85 ksi=
Moment capacity of the beam web
based on flexural yieldingMsyb Fcrb
twb1 Lbw2
4:= Msyb 119.38 kip ft=
Net section modulus of the beam
web sectionZnetb
twb1
4Lbw
2Sbg
2Nr2 Nr2
21 dh2 0.0625in+( )
Lbw
:=
Znetb 20.49 in3
=
Moment capacity of the beam web
based on flexural ruptureMsrb 0.75fu50 Znetb:= Msrb 83.23 kip ft=
Minimum capacity of the beam web
in flexure Mmb min Msyb Msrb,
( ):=
Mmb 83.23 kip ft=
M.mb (83.24 kip ft) > M.bw (14.62 kip ft): Therefore O.K.
To check the tension and flexural interaction of the beam web :-
Interaction Ratio RatioFa1
Fax2
8
9
Mbw
Mmb
+
Fa1
Fax2
0.2if
Fa1
2Fax2
Mbw
Mmb
+
otherwise
:= Ratio 0.48=
Since the Interaction Ratio is less than '1', the beam web is safe in tension and flexure interactionCheck for block shear capacity of beam web for vertical shear (V1) :-
Gross shear area Agv5 Nr2 1( ) Sbg end+ twb1:= Agv5 6.48 in2
=
Net shear area Anv5 Nr2 1( ) Sbg end+ Nr2 0.5( ) dh11
16in+
twb1:= Anv5 4.07 in2
=
Net tension area Ant5 edg gc+( ) Nc2 0.5( ) dh11
16in+
twb1:= Ant5 1.29 in2
=
Ubs 0.5:= (Tension stress concentration is Non-Uniform, Refer J.4.3 AISC 13th Ed)
Block shear capacity Fblock5 min 0.45 Agv5 fy50( ) 0.45 Anv5 fu50( ), 0.75 Ubs Ant5 fu50+:=Fblock5 150.56 kip=
F.block5 (150.56 kip) > V1 (15 kip): Therefore O.K.
Check for block shear capacity of beam web for axial force (Fa1) :-
Gross shear area Agv6 edg gc+( ) twb1:= Agv6 1.95 in2
=
Net shear area Anv6 edg gc+( ) Nc2 0.5( ) dh11
16in+
twb1:= Anv6 1.29 in2
=
Net tension area Ant6 Nr2 1( ) Sbg end+ Nr2 0.5( ) dh11
16
in+
twb1:= Ant6 4.07 in2
=
Ubs 0.5:= (Tension stress concentration is Non-Uniform, Refer J.4.3 AISC 13th Ed)
Block shear capacity Fblock6 min 0.45 Agv6 fy50( ) 0.45 Anv6 fu50( ), 0.75 Ubs Ant6 fu50+:=
F.block6 (137.02 kip) > F.a1 (70 kip): Therefore O.K.Fblock6 137.01 kip=
8/3/2019 Mathcad - D1
10/15
Client - EPSTEINProject - Alpina Foods LLCJob No - 11128Calc No - Detail-1
Date - 11.17.2011Calc By - PSChk By - SN
Shear and tension interaction for Block shear of beam web :-
Interaction ratio for block shear Ratio
Fa1
Fblock6
2V1
Fblock5
2
+:= Ratio 0.52=
Since the Interaction Ratio is less than '1', the beam web is safe in tension and shear
interaction for block shear
Check for bearing / tearing capacity of shear tab at beam web for shear force V1 :-
Bearing capacity at the beam web Fbear1 0.75 2.4 d2 twb1 Nr2 Nc2 fu50:= Fbear1 547.56 kip=
Bearing capacity at shear tab Fbear2 0.75 2.4 d2 tsp Nr2 Nc2 fu36:= Fbear2 783.00 kip=
Tear out due to extreme bolt at
shear tabFtear1 2 0.75 1.2 end
dh2
2
tsp fu36:= Ftear1 71.37 kip=
Tear out due to intermediate bolts atshear tab
Ftear2 2 0.75 1.2 Sbg dh2( ) Nr2 1( ) tsp fu36:= Ftear2 632.11 kip=
Tear out due to extreme bolt at
beam webFtear4 2 0.75 1.2 end
dh1
2
twb1 fu50:= Ftear4 49.91 kip=
Tear out due to intermediate bolts at
beam webFtear3 2 0.75 1.2 Sbg dh1( ) Nr2 1( ) twb1 fu50:= Ftear3 442.04 kip=
Bearing Capacity of the
connectionFbc2 min min Ftear1 Ftear2+( ) Ftear3 Ftear4+( ), min Fbear1 Fbear2,( ),:=
F.bc2 (491.97 kip) > V.1 (15 kip): Therefore O.K. Fbc2 491.95 kip=
Check for bearing / tearing capacity of shear tab at beam web for axial force Fa1 :-
Bearing capacity at the beam web Fbear1 0.75 2.4 d2 twb1 Nr2 Nc2 fu50:= Fbear1 547.56 kip=
Bearing capacity at shear tab Fbear2 0.75 2.4 d2 tsp Nr2 Nc2 fu36:= Fbear2 783.00 kip=
Tear out due to extreme bolt at
shear tabFtear1 0.75 1.2 edg
dh2
2
Nr2 tsp fu36:= Ftear1 287.51 kip=
Tear out due to intermediate bolts at
shear tabFtear2 0.75 1.2 gc dh2( ) Nr2 tsp fu36:= Ftear2 379.27 kip=
Tear out due to extreme bolt at
beam webFtear4 0.75 1.2 edg
dh2
2
Nr2 twb1 fu50:= Ftear4 201.06 kip=
Tear out due to intermediate bolts at
beam webFtear3 0.75 1.2 gc dh2( ) Nr2 twb1 fu50( ):= Ftear3 265.22 kip=
Bearing Capacity of the
connectionFbc3 min min Ftear1 Ftear2+( ) Ftear3 Ftear4+( ), min Fbear1 Fbear2,( ),:=
F.bc3 (466.3 kip) > F.a1 (70 kip): Therefore O.K.Fbc3 466.28 kip=
Check for weld B/W the shear tab on the beam web side and the column web :-
Length of weld available Lw2 15.5in:=
Shear force per inch on the weld fsw1
V1
2 Lw2:= fsw1 0.48
kip
in=
Size of fillet weld required sw1
fsw1
0.707 0.45 fw
:= sw1 0.02 in=
Provide a fillet weld of 5/16" B/W the shear tab and the column web
Check for weld B/W the shear tab on the beam web side and the top and bottom stiffeners :-
Length of weld available Lw3
bfc1 twc1
20.75in:= Lw3 5.05 in=
8/3/2019 Mathcad - D1
11/15
Client - EPSTEINProject - Alpina Foods LLCJob No - 11128Calc No - Detail-1
Date - 11.17.2011Calc By - PSChk By - SN
Shear force per inch on the weld fsw2
Fa1
4 Lw3
Mbg
Lw2( ) 2 Lw3+:= fsw2 4.44
kip
in=
Size of fillet weld required sw2
fsw2
0.707 0.45 fw:= sw2 0.20 in=
Provide a fillet weld of 5/16" B/W the shear tab on beam web side and the top and bottom stiffeners
Size of fillet weld B/W the shear tab and
the column web (for 16" of inch)Dw 5in:=
Minimum shear tab thickness required
for fillet weld size
Minimum column web thickness required
for fillet weld size
tsm
6.19 Dw
58:= tsm 0.53 in= tcm
3.09 Dw
65:= tcm 0.24 in=
Shear tab of 5/8" thk is safe for shear rupture strength of shear tab at weld
Check for bolts B/W gusset plate and the shear tab :-
Bolt diameter d2 1in:=
Bolt type (SC-Type / N-Type) Type = SC
Bolt Grade ASTM Grade = A490
Hole type in gusset plate Type = STD Holes
Hole type in shear tab Type = STD Holes
End distance end 1.75in:=
Edge distance edg 2in:=Bolt spacing Sbg 3in:=
Dia. of bolt hole (In gusset plate) dh1 1.0625in:=
Dia. of bolt hole (In shear tab) dh2 1.0625in:=
No. of bolt rows Nr3 7:=
No. of bolt columns Nc3 2:=
End clearance ec 1in:=
Bolt gage on the shear tab gc 3in:=
Mean slip co-effecient for Class-A surfaces 0.35
:=
Ratio of mean installed bolt pretension
to the specified minimum bolt pretensionDu 1.13:=
Hole factor (For STD Holes) hsc 1:=
Number of slip planes Nsb 1:=
Slip resistance offered by one
1" A490 SC Type - (Class A) boltRslip2
Du hsc Nsb Tub2
1.0:= Rslip2 25.31 kip=
Eccentricity of the bolt group C.G
measured from the column webecc1
bfc1 tfc1
2ec+ edg+
gc
2+:= ecc1 10.20 in=
Polar bolt group modulus /unit area of the bolt
Ibg 535.5in2:=
Vertical distance of the outermost bolt
from the bolt group C.Gymax 9in:=
Horizontal distance of the outermost bolt
from the bolt group C.Gxmax 1.5in:=
8/3/2019 Mathcad - D1
12/15
Client - EPSTEINProject - Alpina Foods LLCJob No - 11128Calc No - Detail-1
Date - 11.17.2011Calc By - PSChk By - SN
Total shear force on gusset to
column web interfaceVtot Vb Vc+:= Vtot 110.59 kip=
Moment on the bolt group due to
shear force Vtotand eccentricity ecc1
M
bg2
V
tot
e
cc1
:= Mbg2
93.97 kip ft=
Vertical Shear force per bolt due to
shear force, Vtot
fsv
Vtot
Nr3 Nc3:= fsv 7.90 kip=
Horizontal Shear force per bolt due to
brace horiz. componentfsh
Hc
Nr3 Nc3:= fsh 0.00 kip=
Vertical Shear force per bolt due to
moment, Mbg2
fsvm
Mbg2 xmax
Ibg
:= fsvm 3.16 kip=
Horizontal Shear force per bolt due to
moment, M
bg2
fshm
Mbg2 ymax
Ibg
:= fshm 18.95 kip=
Resultant shear force / bolt Rb2 fsv fsvm+( )2
fsh fshm+( )2
+:= Rb2 21.94 kip=
R.slip2 (25.31 kip) > R.b2 (21.94 kip): Therefore O.K.
Therefore 7 rows x 2 column of 1" dia A490 SC-type (Class-A) bolts @ 3" spacing and at 3" gage B/W the
shear tab and gusset plate are adequate
Check for shear capacity of shear tab at gusset and column interface :-
Gross shear area Agv3 Nr3 1( ) Sbg 2 end+ tsp:= Agv3 13.44 in2
=
Net shear area Anv3 Nr3 1( ) Sbg 2 end+ Nr3 dh11
16
in+
tsp:= Anv3 8.52 in2
=
Shear capacity Fshe3 min 0.6 Agv3 fy36 0.45 Anv3 fu36,( ):= Fshe3 222.26 kip=Fshe3 (222.27 kip) > V.tot (110.59 kip): Therefore O.K.
Check for flexural capacity of the shear tab at gusset and column interface :-
Eccentricity from the column web face
to the first line of shear tab boltsecc2
bfc1 tfc1
2ec+ edg+:= ecc2 8.70 in=
Moment due to the eccentricity Mp2 Vtot ecc2:= Mp2 80.15 kip ft=
Total length of the shear tab Lst2 Nr3 1( ) Sbg 2 end+:= Lst2 21.50 in=
Critical flexural stress in presence of shear Fcr2 0.9 fy36( )2
3Vtot
tsp Lst2
2:= Fcr2 29.10 ksi=
Moment capacity of the shear tab
based on flexural yieldingMsy2 Fcr2
tsp Lst22
4:= Msy2 175.13 kip ft=
Net section modulus of the shear tab section Znet2
tsp
4Lst2
2Sbg
2Nr3 Nr3
21 dh2 0.0625in+( )
Lst2
:=
Znet2 47.50 in3
=
Moment capacity of the shear tabbased on flexural rupture
Msr2 0.75fu36 Znet2:= Msr2 172.20 kip ft=
Minimum capacity of the shear tab
in flexureMm2 min Msy2 Msr2,( ):= Mm2 172.20 kip ft=
M.m2 (172.21 kip) > M.p2 (80.16 kip): Therefore O.K.
8/3/2019 Mathcad - D1
13/15
Client - EPSTEINProject - Alpina Foods LLCJob No - 11128Calc No - Detail-1
Date - 11.17.2011Calc By - PSChk By - SN
Check for block shear capacity of shear tab for shear force Vtot :-
Gross shear area Agv7 Nr3 1( ) Sbg end+ tsp:= Agv7 12.34 in2
=
Net shear area Anv7 Nr3 1( ) Sbg end+ Nr3 0.5( ) dh21
16in+
tsp:= Anv7 7.77 in2
=
Net tension area Ant7 edg gc+( ) Nc3 0.5( ) dh21
16in+
tsp:= Ant7 2.07 in2
=
Ubs 0.5:= (Tension stress concentration is Non-Uniform, Refer J.4.3 AISC 13th Ed)
Block shear capacity Fblock7 min 0.45 Agv7 fy36( ) 0.45 Anv7 fu36( ), 0.75 Ubs Ant7 fu36+:=
F.block7 (245.01 kip) > V.tot (110.59 kip): Therefore O.K.Fblock7 245.00 kip=
Check for shear capacity of gusset plate :-
Gross shear area Agv8 Nr3 1( ) Sbg 2 end+ tg:= Agv8 10.75 in2=
Net shear area Anv8 Nr3 1( ) Sbg 2 end+ Nr3 dh11
16in+
tg:= Anv8 6.81 in2
=
Shear capacity Fshe4 min 0.6 Agv8 fy36 0.45 Anv8 fu36,( ):= Fshe4 177.81 kip=
Fshe4 (177.82 kip) > V.tot (110.59 kip): Therefore O.K.
Check for block shear capacity of gusset plate for shear force Vtot :-
Gross shear area Agv9 Nr3 1( ) Sbg end+ tg:= Agv9 9.87 in2
=
Net shear area Anv9 Nr3 1( ) Sbg end+ Nr3 0.5( ) dh11
16 in+
tg:= Anv9 6.22 in2
=
Net tension area Ant9 edg gc+( ) Nc3 0.5( ) dh11
16in+
tg:= Ant9 1.66 in2
=
Ubs 0.5:= (Tension stress concentration is Non-Uniform, Refer J.4.3 AISC 13th Ed)
Block shear capacity Fblock9 min 0.45 Agv9 fy36( ) 0.45 Anv9 fu36( ), 0.75 Ubs Ant9 fu36+:=
F.block9 (196.01 kip) > V.tot (110.59 kip): Therefore O.K.Fblock9 196.00 kip=
Check for bearing / tearing capacity of shear tab & gusset plate for shear force Vtot :-
Bearing capacity at the gusset plate Fbear1 0.75 2.4 d2 tg Nr3 Nc3 fu36:= Fbear1 730.80 kip=
Bearing capacity at shear tab Fbear2 0.75 2.4 d2 tsp Nr3 Nc3 fu36:= Fbear2 913.50 kip=
Tear out due to extreme bolt at
shear tabFtear1 2 0.75 1.2 end
dh2
2
tsp fu36:= Ftear1 79.52 kip=
Tear out due to intermediate bolts at
shear tabFtear2 2 0.75 1.2 Sbg dh2( ) Nr3 1( ) tsp fu36:= Ftear2 758.53 kip=
Tear out due to extreme bolt at
beam webFtear4 2 0.75 1.2 end
dh1
2
tg fu36:= Ftear4 63.62 kip=
Tear out due to intermediate bolts at
beam webFtear3 2 0.75 1.2 Sbg dh1( ) Nr3 1( ) tg fu36:= Ftear3 606.82 kip=
Bearing Capacity of the
connectionF
bc4min min F
tear1F
tear2+
( )F
tear3F
tear4+
( ), min F
bear1F
bear2,
( ),:=
F.bc4 (670.48 kip) > V.tot (110.59 kip): Therefore O.K. Fbc4 670.44 kip=
Check for weld B/W the shear tab on the gusset plate side and the column web :-
Length of weld available Lw4 Lst2 2 0.75 in:= Lw4 20.00 in=
8/3/2019 Mathcad - D1
14/15
Client - EPSTEINProject - Alpina Foods LLCJob No - 11128Calc No - Detail-1
Date - 11.17.2011Calc By - PSChk By - SN
Shear force per inch on the weld fsw3
Vtot
2 Lw4:= fsw3 2.76
kip
in=
Size of fillet weld required sw3
fsw3
0.707 0.45 fw:= sw3 0.12 in=
Provide a fillet weld of 5/16" B/W the shear tab and the column web
Size of fillet weld B/W the shear tab and
the column web (for 16" of inch)Dw 5in:=
Minimum shear tab thickness
required for fillet weld sizetsm
6.19 Dw
58:= tsm 0.53 in=
Shear tab of 5/8" thk is safe for shear rupture strength of shear tab at weld
Shear capacity of the gusset plate at the beam to gusset plate weld :-
Length of weld B/W the gusset andthe beam flange
Lg Lw1:= Lg 21.00 in=
Gross shear capacity of the gusset plate Fsg 0.6 tg Lg fy36:= Fsg 226.80 kip=
F.sg (226.81 kip) > H.b (77.44 kip): Therefore O.K.
Moment capacity of the gusset plate at the beam to gusset weld :-
Critical flexural stress in presence of shear Fcr3 0.9 fy36( )2
3Hb
tg Lg
2
:= Fcr3 29.78 ksi=
Moment capacity of the gusset platebased on flexural yielding
Msy3 Fcr3
tg Lg2
4:= Msy3 136.78 kip ft=
M.sy3 (136.79 kip) > M.e1 (58.4 kip): Therefore O.K.
Check for weld B/W shear tab @ gusset side and middle / bottom most stiffener supporting the gusset :-
Moment on the weld group Me2 Vtot ecc1:= Me2 93.97 kip ft=
Length of weld available for shear tab
weld to stiffenerLw5
bfc1 twc1
20.75in:= Lw5 5.05 in=
Shear force per inch on the weld fsw4
Me2
Lw4( ) 2 Lw5:= fsw4 5.58
kip
in=
Size of fillet weld required sw4
fsw4
0.707 0.45 fw:= sw4 0.25 in=
Provide a fillet weld of 5/16" B/W the shear tab on gusset plate side and the top and bottom stiffeners
Size of fillet weld B/W the shear tab and
the stiffener plate (for 16" of inch)Dw 5in:=
Minimum shear tab thickness
required for fillet weld sizetsm
6.19 Dw
58:= tsm 0.53 in=
Shear tab of 5/8" thk is safe for shear rupture strength of shear tab at weld
Check for weld B/W the bottom most stiffener supporting the gusset plate with the column flange :-
Length of weld available Lw6
bfc1 twc1
20.75in:= Lw6 5.05 in=
Shear force per inch on the weld fsw5
Me2
Lw4( ) 4 Lw6:= fsw5 2.79
kip
in=
8/3/2019 Mathcad - D1
15/15
Client - EPSTEINProject - Alpina Foods LLCJob No - 11128Calc No - Detail-1
Date - 11.17.2011Calc By - PSChk By - SN
Size of fillet weld required sw5
fsw5
0.707 0.45 fw:= sw5 0.13 in=
Thickness of bottom most stiffener tst1 0.625in:=Shear capacity of the stiffener Ftst1 0.6 Lw6 tst1 fy36:= Ftst1 68.24 kip=
Shear force on the stiffener Fsf1
Me2
Lw4
:= Fsf1 56.38 kip=
Ft.st1 (68.25 kip) > F.sf1 (56.39 kip): Therefore O.K.
Provide a fillet weld of 5/16" B/W the stiffener and the column flange
Check for weld B/W the top most stiffener supporting the shear tab on the beam web side
with the column flange :-
Length of weld available Lw7
bfc1 twc1
2 0.75in:= Lw7 5.05 in=
Shear force per inch on the weld fsw6
Mbg
Lw2 4 Lw7:= fsw6 0.49
kip
in=
Size of fillet weld required sw6
fsw6
0.707 0.45 fw:= sw6 0.02 in=
Thickness of top most stiffener tst2 0.625in:=
Shear capacity of the stiffener Ftst2 0.6 Lw7 tst2 fy36:= Ftst2 68.24 kip=
Shear force on the stiffener Fsf2
Mbg
Lw2
:= Fsf2
9.87 kip=
Ft.st2 (68.25 kip) > F.sf2 (9.87 kip): Therefore O.K.
Provide a fillet weld of 5/16" B/W the bottom side of the stiffener and the column flange and 5/16" PPW
B/W the top of the stiffener and the column flange