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Matter and Measurements

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Matter and Measurements. Matter and Energy - Vocabulary. Chemistry Matter Energy Natural Law-(scientific law) Observation, Hypothesis, Theory, Law. States of Matter. Solids. States of Matter. Solids Liquids. States of Matter. Solids Liquids Gases. States of Matter. Change States - PowerPoint PPT Presentation
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Matter and Measurements
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Page 1: Matter and Measurements

1

Matter and Measurements

Page 2: Matter and Measurements

2

Matter and Energy - Vocabulary

• Chemistry• Matter• Energy• Natural Law-(scientific law)

– Observation, Hypothesis, Theory, Law

Page 3: Matter and Measurements

3

States of Matter

• Solids

Page 4: Matter and Measurements

4

States of Matter

• Solids• Liquids

Page 5: Matter and Measurements

5

States of Matter

• Solids• Liquids• Gases

Page 6: Matter and Measurements

6

States of Matter

• Change States– heating– cooling

Page 7: Matter and Measurements

7

States of Matter• Illustration of changes in state

– requires energy

Page 8: Matter and Measurements

8

Substances, Compounds, Elements and Mixtures

• Substance– matter that all samples have identical composition

and properties• Elements

– Pure substances that cannot be decomposed into simpler substances via chemical reactions

– Special elemental forms of atoms (diatomic)Elemental symbols

– found on periodic chart

Page 9: Matter and Measurements

9

Substances, Compounds, Elements and Mixtures

Page 10: Matter and Measurements

10

Substances, Compounds, Elements and Mixtures

• Compounds– Pure substances composed of two or more

elements in a definite ratio by mass– can be decomposed into the constituent elements

REVIEW– Element cannot be broken down– Compound can be broken down into its elements!

Page 11: Matter and Measurements

11

Substances, Compounds, Elements and Mixtures

• Mixtures– composed of two or more substances– homogeneous mixtures

• Uniform throughout• Example: solutions

– heterogeneous mixtures• Not uniform • Example: rocks

Page 12: Matter and Measurements

12

Classify the following substances as an element, compound or a mixture

(homogeneous or heterogeneous). Which are pure substances?

• Lightly scrambled egg• Water• Lava lamp• Seawater• Chicken noodle soup• Root beer• Sucrose (C12H22O11)

Page 13: Matter and Measurements

13

Separating Mixtures• Distillation

Page 14: Matter and Measurements

14

Separating Mixtures• Chromatography

paper

Page 15: Matter and Measurements

15

Chemical and Physical Properties• Extensive Properties - depend on quantity

of material Ex. mass

• Intensive Properties - do not depend on quantity of material

Ex. boiling point

Page 16: Matter and Measurements

16

Chemical and Physical Properties• Chemical Properties - chemical changes

– Observed during change of material to new material• Iron rusting

• Physical Properties - physical changes– No change to the identity of the substance

• changes of state• density • color • solubility

Page 17: Matter and Measurements

17

Physical Properties• Density

– mass / volume intensive property– Mass and volume extensive

properties• Solubility

– Amount of substance dissolved in the solvent at a given temperature• Saturated solution• Unsaturated solution• Supersaturated solution

Page 18: Matter and Measurements

18

Identify the following as either a chemical or physical change.

• Combination of sodium and chlorine to give sodium chloride.

• Liquefaction of gaseous nitrogen.• Separation of carbon monoxide into

carbon and oxygen.• Freezing of water.

Page 19: Matter and Measurements

19

Measurements in Chemistry

• length meter m• volume liter l• mass gram g• time second s• current ampere A• temperature Kelvin K• amt. substance mole mol

Page 20: Matter and Measurements

20

Measurements in Chemistry• mega M 106

• kilo k 103

• deka da 10• deci d 10-1

• centi c 10-2

• milli m 10-3

• micro m 10-6

• nano n 10-9

• pico p 10-12

• femto f 10-15

Page 21: Matter and Measurements

21

Units of Measurement• Mass

– measure of the quantity of matter in a body• Weight

– measure of the gravitational attraction for a body

• Length 1 m = 39.37 inches2.54 cm = 1 inch

• Volume1 liter = 1.06 qt 1 qt = 0.946 liter

Page 22: Matter and Measurements

22

The Use of Numbers

• Exact numbers 1 dozen = 12 things• Accuracy

– how closely measured values agree with the correct value

• Precision– how closely individual measurements

agree with each other

Page 23: Matter and Measurements

23

The Use of Numbers

Page 24: Matter and Measurements

24

The Use of Numbers

• Exact numbers 1 dozen = 12 things– Counted numbers ex. 3 beakers

• Significant figures– digits believed to be correct by the person

making the measurement• Scientific notation

– Way of signifying the significant digits in a number

Page 25: Matter and Measurements

25

Significant Figures - rules

• leading zeroes - never significant0.000357 has three sig fig

• trailing zeroes - may be significantmust specify (after decimal – significant

before decimal - ambiguous)

1300 nails - counted or weighed?

Express 26800 in scientific notation with4 sig figs 3 sig figs 2 sig figs

Page 26: Matter and Measurements

26

Significant Figures - rules• imbedded zeroes are always significant

3.0604 has five sig fig

How many significant figures are in the following numbers?

0.01240.1241.2401240

Page 27: Matter and Measurements

27

Significant Figures - rules

multiply & divide rule - easyproduct has the smallest number of sig. fig.

of multipliers

Page 28: Matter and Measurements

28

Significant Figures - rules

• multiply & divide rule - easyproduct has the smallest number of sig. fig.

of multipliers

310 x 5.22 tooff round

66.5217

31.2x 2424

Page 29: Matter and Measurements

29

Significant Figures - rules

• multiply & divide rule - easyproduct has the smallest number of sig. fig.

of multipliers

310 x 5.22 tooff round

66.5217

31.2x 2424

3.9 tooff round89648.3

41.x 2783.2

Page 30: Matter and Measurements

30

Practice

• 142 x 2 = • 4.180 x 2.0 = • 0.00482 / 0.080 = • 3.15x10-2 / 2.00x105 = • 24.8x106 / 6.200x10-2 =

Page 31: Matter and Measurements

31

Practice

• 142 x 2 = 300• 4.180 x 2.0 = • 0.00482 / 0.080 = • 3.15x10-2 / 2.00x105 = • 24.8x106 / 6.200x10-2 =

Page 32: Matter and Measurements

32

Practice

• 142 x 2 = 300• 4.180 x 2.0 = 8.4• 0.00482 / 0.080 = • 3.15x10-2 / 2.00x105 = • 24.8x106 / 6.200x10-2 =

Page 33: Matter and Measurements

33

Practice

• 142 x 2 = 300• 4.180 x 2.0 = 8.4• 0.00482 / 0.080 = 0.060• 3.15x10-2 / 2.00x105 = • 24.8x106 / 6.200x10-2 =

Page 34: Matter and Measurements

34

Practice

• 142 x 2 = 300• 4.180 x 2.0 = 8.4• 0.00482 / 0.080 = 0.060• 3.15x10-2 / 2.00x105 = 1.58x10-7

• 24.8x106 / 6.200x10-2 =

Page 35: Matter and Measurements

35

Practice

• 142 x 2 = 300• 4.180 x 2.0 = 8.4• 0.00482 / 0.080 = 0.060• 3.15x10-2 / 2.00x105 = 1.58x10-7

• 24.8x106 / 6.200x10-2 = 4.00x108

Page 36: Matter and Measurements

36

Significant Figures - rules

• add & subtract rule - subtleanswer contains smallest decimal place of

the addends

Page 37: Matter and Measurements

37

Significant Figures - rules

• add & subtract rule - subtleanswer contains smallest decimal place of

the addends

6.95 tooff round9463.6

20.2423.13692.3

Page 38: Matter and Measurements

38

Significant Figures - rules

• add & subtract rule - subtleanswer contains smallest decimal place of

the addends

6.95 tooff round9463.6

20.2423.13692.3

6.671 tooff round6707.6

312.27793.8

Page 39: Matter and Measurements

39

Practice

• 416.2 – 10.18 =• 16.78 + 10. = • 422.501 – 420.4 = • 25.5 + 21.1 + 3.201 = • 42.00x10-4 + 1.8x10-6 =

Page 40: Matter and Measurements

40

Practice

• 416.2 – 10.18 = 406.0• 16.78 + 10. = • 422.501 – 420.4 = • 25.5 + 21.1 + 3.201 = • 42.00x10-4 + 1.8x10-6 =

Page 41: Matter and Measurements

41

Practice

• 416.2 – 10.18 = 406.0• 16.78 + 10. = 27• 422.501 – 420.4 = • 25.5 + 21.1 + 3.201 = • 42.00x10-4 + 1.8x10-6 =

Page 42: Matter and Measurements

42

Practice

• 416.2 – 10.18 = 406.0• 16.78 + 10. = 27• 422.501 – 420.4 = 2.1• 25.5 + 21.1 + 3.201 = • 42.00x10-4 + 1.8x10-6 =

Page 43: Matter and Measurements

43

Practice

• 416.2 – 10.18 = 406.0• 16.78 + 10. = 27• 422.501 – 420.4 = 2.1• 25.5 + 21.1 + 3.201 = 49.8• 42.00x10-4 + 1.8x10-6 =

Page 44: Matter and Measurements

44

Practice

• 416.2 – 10.18 = 406.0• 16.78 + 10. = 27• 422.501 – 420.4 = 2.1• 25.5 + 21.1 + 3.201 = 49.8• 42.00x10-4 + 1.8x10-6 = 4.2 x 10-3

Page 45: Matter and Measurements

45

More Practice

4.18 – 58.16 x (3.38 – 3.01) =

Page 46: Matter and Measurements

46

More Practice

4.18 – 58.16 x (3.38 – 3.01) = 4.18 – 58.16 x (0.37) =

Page 47: Matter and Measurements

47

More Practice

4.18 – 58.16 x (3.38 – 3.01) = 4.18 – 58.16 x (0.37) =4.18 – 21.5192 =

Page 48: Matter and Measurements

48

More Practice

4.18 – 58.16 x (3.38 – 3.01) = 4.18 – 58.16 x (0.37) =4.18 – 21.5192 = -17.3392Round off correctly

Page 49: Matter and Measurements

49

More Practice

4.18 – 58.16 x (3.38 – 3.01) = 4.18 – 58.16 x (0.37) =4.18 – 21.5192 = -17.3392Round off correctly to 2 sig. figs-17

Page 50: Matter and Measurements

50

Unit Factor MethodDimensional Analysis

• simple but important way to always get right answer

• way to change from one unit to another• make unit factors from statements

1 ft = 12 in becomes 1 ft/12 in or 12in/1 ft3 ft = 1 yd becomes 3ft/1yd or 1yd/3ft

Page 51: Matter and Measurements

51

Unit Factor MethodDimensional Analysis

• simple but important way to always get right answer

• way to change from one unit to another• make unit factors from statements

1 ft = 12 in becomes 1 ft/12 in or 12in/1 ft• Example: Express 12.32 yards in

millimeters.

Page 52: Matter and Measurements

52

Unit Factor Method

.).........yd1ft3( yd 12.32

mm ?yd 12.32

Page 53: Matter and Measurements

53

Unit Factor Method

mm 1011.27)cm1mm10( )

in1cm2.54( )

ft1in12( )

yd1ft3( yd 12.32

mm ?yd 12.32

3

Page 54: Matter and Measurements

54

Unit Factor Method• Example: Express 323. milliliters in

gallons

Page 55: Matter and Measurements

55

Unit Factor Method• Express 323. milliliters in gallons.

gal 0.0856gal 0.085595gal ?

)qt4

gal1( )L1

qt1.06( )mL1000

L1( mL 323gal ?

mL 323gal ?

Page 56: Matter and Measurements

56

Unit Factor Method• Example: Express 5.50 metric tons in

pounds. 1 metric ton = 1 Megagram

Page 57: Matter and Measurements

57

Unit Factor Method• Example: Express 5.50 metric tons in

pounds.

lbsxlbsglbgrams 4

6

1021.1537.121144541

tonmetric 11x10 tons5.50 lbs ?

tonsmetric 5.50 lbs ?

Page 58: Matter and Measurements

58

Unit Factor Method• area is two dimensional• Example: Express 4.21 x 106 square

centimeters in square feet

Page 59: Matter and Measurements

59

Unit Factor Method• area is two dimensional

express 4.21 x 106 square centimeters in square feet

2262 )cm 2.54

in 1(cm104.21ft ?

Page 60: Matter and Measurements

60

Unit Factor Method• area is two dimensional

express 4.21 x 106 square centimeters in square feet

22262 )in12ft 1()

cm2.54in 1(cm104.21ft ?

Page 61: Matter and Measurements

61

Unit Factor Method• area is two dimensional

express 4.21 x 106 square centimeters in square feet

232

22262

ft 4.53x10ft 4531.6063

)in12ft1()

cm2.54in1(cm104.21ft ?

Page 62: Matter and Measurements

62

Unit Factor Method• volume is three dimensional• Example: Express 3.61 cubic feet in

cubic centimeters.

Page 63: Matter and Measurements

63

Unit Factor Method• volume is three dimensional• Example: Express 3.61 cubic feet in

cubic centimeters.

353

3333

cm 101.02cm 102223.42

)in 1

cm 2.54()ft 1in 12(ft 3.61cm ?

Page 64: Matter and Measurements

64

Percentage

• Percentage is the parts per hundred of a sample.

• Example: A 500. g sample of ore yields 27.9 g of sulfur. What is the percent of sulfur in the ore?

Page 65: Matter and Measurements

65

Percentage• Percentage is the parts per hundred of

a sample.• Example: A 500. g sample of ore yields

27.9 g of sulfur. What is the percent of sulfur in the ore?

5.58%

100%x ore g 500S g 27.9

100% x ore of grams

sulfur of grams iron % ?

Page 66: Matter and Measurements

66

Derived Units - Density • density = mass/volume• What is density?• Example: Calculate the density of a

substance if 123. grams of it occupies 57.6 cubic centimeters.

Page 67: Matter and Measurements

67

Derived Units - Density • density = mass/volume• What is density?• Example: Calculate the density of a

substance if 123. grams of it occupies 57.6 cubic centimeters.

Vm D

mL 6.57cm 57.6 mL 1 cm 1 33

Page 68: Matter and Measurements

68

Derived Units - Density • density = mass/volume• What is density?• Example: Calculate the density of a

substance if 123. grams of it occupies 57.6 cubic centimeters.

g/mL 2.13 DmL 57.6

g 123. D

Vm D

mL 6.57cm 57.6 mL 1 cm 1 33

Page 69: Matter and Measurements

69

Derived Units - Density • Example: Suppose you need 175. g of a

corrosive liquid for a reaction. What volume do you need? – liquid’s density = 1.02 g/mL

Page 70: Matter and Measurements

70

Derived Units - Density • Example: Suppose you need 175. g of a

corrosive liquid for a reaction. What volume do you need? – liquid’s density = 1.02 g/mL

DmV

VmD

Page 71: Matter and Measurements

71

Derived Units - Density • Example: Suppose you need 175. g of a

corrosive liquid for a reaction. What volume do you need? – liquid’s density = 1.02 g/mL

mL 172mL 171.57 1.02g 175V

DmV

VmD

mLg

Page 72: Matter and Measurements

72

Heat & Temperature• heat and T are not the same thing

T is a measure of the intensity of heat in a body• 3 common T scales - all use water as a

reference

Page 73: Matter and Measurements

73

Heat & TemperatureMP BP

• Fahrenheit 32oF 212oF• Celsius 0oC 100cC• Kelvin 273 K 373 K

Page 74: Matter and Measurements

74

Relationships of the 3 T Scales

273KC

or 273 C K

o

o

Page 75: Matter and Measurements

75

Relationships of the 3 T Scales

1.859

1018

100180

273K C

or273 C K

o

o

Page 76: Matter and Measurements

76

Relationships of the 3 T Scales

1.832FC

or32C 1.8F

1.859

1018

100180

273KC

or273 C K

oo

oo

o

o

Page 77: Matter and Measurements

77

Heat and Temperature• Example: Convert 111.oF to degrees

Celsius.

1.832111C

1.832FC

o

oo

Page 78: Matter and Measurements

78

Heat and Temperature• Example: Convert 111.oF to degrees

Celsius.

9.438.1

791.8

32111C

1.832FC

o

oo

Page 79: Matter and Measurements

79

Heat and Temperature• Example: Express 757. K in Celsius

degrees.

Page 80: Matter and Measurements

80

Heat and Temperature• Example: Express 757. K in Celsius

degrees.

.484C

273..757C

273.KC

o

o

o

Page 81: Matter and Measurements

81

The Measurement of Heat

• SI unit J (Joule)• calorie

1 calorie = 4.184 J• English unit = BTU

Page 82: Matter and Measurements

82

Synthesis Question• It has been estimated that 1.0 g of

seawater contains 4.0 pg of Au. The total mass of seawater in the oceans is 1.6x1012 Tg, If all of the gold in the oceans were extracted and spread evenly across the state of Georgia, which has a land area of 58,910 mile2, how tall, in feet, would the pile of Au be?Density of Au is 19.3 g/cm3. 1.0 Tg = 1012g.

Page 83: Matter and Measurements

83

Au g106.4)OH of g

Au g104.0O)(H of g10(1.6

OH of g 101.6)Tg

g 10( Tg) 10(1.6

12

2

12

224

224

1212

Page 84: Matter and Measurements

84

331533

3113

12

12

2

12

224

224

1212

mile 1cm 104.16 mile 1cm 160,934

cm 160,934in 1

cm 2.54ft 1in 12

mile 1ft 5280mile 1

Aucm103.3Au g 19.3

1cmAu g106.4

Au g106.4)OH of g

Au g104.0O)(H of g10(1.6

OH of g 101.6)Tg

g 10( Tg) 10(1.6

Page 85: Matter and Measurements

85

ft 107.13mile 1

ft 5280mile)10(1.35mile 58,910

mile107.96

mile107.96cm104.16

mile 1Au) cm 10(3.3

692

35

35315

3311

Page 86: Matter and Measurements

86

Group Activity• On a typical day, a hurricane expends

the energy equivalent to the explosion of two thermonuclear weapons. A thermonuclear weapon has the explosive power of 1.0 Mton of nitroglycerin. Nitroglycerin generates 7.3 kJ of explosive power per gram of nitroglycerin. The hurricane’s energy comes from the evaporation of water that requires 2.3 kJ per gram of water evaporated. How many gallons of water does a hurricane evaporate per day?


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