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MEME homework: probability of finding GAGTCA at a given position in the yeast genome, based on a background model of A = 0.3, T = 0.3, G = 0.2, C = 0.2 (0.2)(0.3)(0.2)(0.3)(0.2)(0.3) = 2.16 x 10 -4 is the probability that ANY 6 mer will be this sequence by ch many instances within 1,000 bp upstream of 6,000 ge mers per 1,000 bp: 1000 bp – 5 bp (account for 6mer start p 6000 genes * 995 = 5.97 x 10 6 possible 6mers total P that any one is your sequence: 2.16 x 10 -4 x 5.97 x 10 1290 sites = 995 6mers per gene upstream region BUT … can also have the reverse complement (i.e. site on other strand) = 2X possible sites (because of our bg model) = 1
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Page 1: MEME homework: probability of finding GAGTCA at a given position in the yeast genome, based on a background model of A = 0.3, T = 0.3, G = 0.2, C = 0.2.

MEME homework:

probability of finding GAGTCA at a given position in the yeast genome, based on a background model of A = 0.3, T = 0.3, G = 0.2, C = 0.2

(0.2)(0.3)(0.2)(0.3)(0.2)(0.3) = 2.16 x 10-4

This is the probability that ANY 6 mer will be this sequence by chance

How many instances within 1,000 bp upstream of 6,000 genes?Number of 6mers per 1,000 bp: 1000 bp – 5 bp (account for 6mer start position)

6000 genes * 995 = 5.97 x 106 possible 6mers totalP that any one is your sequence: 2.16 x 10-4 x 5.97 x 106 = 1290 sites

= 995 6mers per gene upstream region

BUT … can also have the reverse complement (i.e. site on other strand)= 2X possible sites (because of our bg model) = 2580 possible matches1

Page 2: MEME homework: probability of finding GAGTCA at a given position in the yeast genome, based on a background model of A = 0.3, T = 0.3, G = 0.2, C = 0.2.

An alternative approach: Phylogenetic footprinting

Rather than look at multiple, different regulatory regions from one species, look at one region but across multiple, orthologous regions from many species.

Hypothesis: functional regions of the genome will be conserved more than ‘nonfunctional’ regions, due to selection.

Therefore, simply look for regions of sequence that are conserved above background.

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Page 3: MEME homework: probability of finding GAGTCA at a given position in the yeast genome, based on a background model of A = 0.3, T = 0.3, G = 0.2, C = 0.2.

Simplest case: stretches of very highly conserved sequence

Kellis et al. 2003 “Sequencing and comparison of yeast species to identify genes and regulatory elements”Sequenced 4 closely related Saccharomyces genomes & identified conserved sequences in multiplealignments of orthologous sequences from the four species.

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Page 4: MEME homework: probability of finding GAGTCA at a given position in the yeast genome, based on a background model of A = 0.3, T = 0.3, G = 0.2, C = 0.2.

Position

bits

Information Profile:

Incorporating evolutionary models can improve motif finding

Remember that evolution acts on functionally important base pairs …

Also remember from our motif finding exercise that not all contiguous base pairsare equally important (information content).

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Page 5: MEME homework: probability of finding GAGTCA at a given position in the yeast genome, based on a background model of A = 0.3, T = 0.3, G = 0.2, C = 0.2.

Incorporating evolutionary models can improve motif finding

Remember that evolution acts on functionally important base pairs …

Also remember from our motif finding exercise that not all contiguous base pairsare equally important (information content).

Moses et al. 2003 “Position specific variation in the rate of evolution in transcription factor binding sites” Rate of evolution (ie. degree of conservation) within a motif is inversely proportional to the information content … important base pairs evolve slower 5

Page 6: MEME homework: probability of finding GAGTCA at a given position in the yeast genome, based on a background model of A = 0.3, T = 0.3, G = 0.2, C = 0.2.

Sinha et al. 2004 “PhyME: A probabalistic algorithm for finding motifs in sets of orthologous sequences”

Moses et al. 2004 “Monkey: identification of transcription factor binding sitesin multiple alignments using a binding site-specific evolutionary model

Siddharthan et al. 2005 “PhyloGibbs: A Gibbs sampling motif finder that incorporates phylogeny.”

Wang & Stormo. 2003 (PhyloCon) “Combining phylogenetic data with co-regulated genes to identify regulatory motifs”

Prakash et al. 2004. (OrthoMEME) “Motif discovery in heterogeneous sequence data

Multiple motif finding methods now work on multiple alignments of regulatory regions of coregulated genes.

Given: 1) group of regulatory regions of coregulated genes2) orthologs of each region, in the form of multiple alignments

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Page 7: MEME homework: probability of finding GAGTCA at a given position in the yeast genome, based on a background model of A = 0.3, T = 0.3, G = 0.2, C = 0.2.

Keep in mind that the relevant evolutionary models are specific for what one is looking for (TF binding sites, ncRNA, etc)

Moses et al. 2003 “Position specific variation in the rate of evolution in transcription factor binding sites” Rate of evolution (ie. degree of conservation) within a motif is inversely proportional to the information content … important base pairs evolve slower 7

Page 8: MEME homework: probability of finding GAGTCA at a given position in the yeast genome, based on a background model of A = 0.3, T = 0.3, G = 0.2, C = 0.2.

VISTA suite for visualizing conservation in global alignments

Pre-computed multiple global alignments of mammalian genomes, visualizedby conservation level.

-- Uses BLAT local alignment tool to find seeds of high sequence similarity,then these seeds are used for global single- or multiple-genome alignment

Frazer et al. 2004 “VISTA: computational tools for comparative genomics”8

Page 9: MEME homework: probability of finding GAGTCA at a given position in the yeast genome, based on a background model of A = 0.3, T = 0.3, G = 0.2, C = 0.2.

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Page 10: MEME homework: probability of finding GAGTCA at a given position in the yeast genome, based on a background model of A = 0.3, T = 0.3, G = 0.2, C = 0.2.

Which species to compare?

Balance between:-- species closely related enough that:

1) There’s enough similar sequence to get confident pairwise alignments

2) The sequences of interest and their corresponding functions have been conserved

-- species distantly enough related that:1) nonfunctional sequence has had time to diverge

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Page 11: MEME homework: probability of finding GAGTCA at a given position in the yeast genome, based on a background model of A = 0.3, T = 0.3, G = 0.2, C = 0.2.

The above approaches have focused on using similarity/conservationto identify important regions of the genome …

A large focus in genomics is understanding the differences in genome sequences and what accounts for the vast diversity in phenotypes

within a population.

Analysis of single nucleotide polymorphisms (SNP) within populations,Analysis of variations in gene expression within and between populations,Analysis of quantitative trait loci (QTLs) accounting for differences in gene expression.

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Page 12: MEME homework: probability of finding GAGTCA at a given position in the yeast genome, based on a background model of A = 0.3, T = 0.3, G = 0.2, C = 0.2.

Connecting phenotype to genotype

-- Large variations in size, shape, health, etc in human populations

-- Much of that variation has to do with disease susceptibility

-- A major goal of genetics (and now genomics) is understanding the consequencesof genetic variation.

A major force in genomics is to identify and annotate SNPs in human populations, and identify those related to disease

~2800 disease-associated genes known, mostly from positional cloning & mapping studies

Done by linkage analysis: pattern of marker inheritance in families with heritable diseases

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Page 13: MEME homework: probability of finding GAGTCA at a given position in the yeast genome, based on a background model of A = 0.3, T = 0.3, G = 0.2, C = 0.2.

2001

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Page 14: MEME homework: probability of finding GAGTCA at a given position in the yeast genome, based on a background model of A = 0.3, T = 0.3, G = 0.2, C = 0.2.

Each base-pair position on human chromosome 21 is interrogated 8 times(4 in forward & 4 in reverse orientations)

GGAGATGAGTTCGATTACTCTTAGG

GGAGATGAGTTCAATTACTCTTAGG

GGAGATGAGTTCTATTACTCTTAGG

GGAGATGAGTTCCATTACTCTTAGG

1.7 x 108 oligos total on eight Affy wafers were used to identify SNPs onhuman Chromosome 21 from 21 different individuals.

Array-based methods of SNP detection & Haplotype mapping

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Page 15: MEME homework: probability of finding GAGTCA at a given position in the yeast genome, based on a background model of A = 0.3, T = 0.3, G = 0.2, C = 0.2.

Each row = single SNPEach column = Ch 21

Blue = major alleleYellow = minor allele

Much of the chromosomalvariation is explained with

relatively limited haplotype diversity.

80% of haplotype structurecan be captured with only

10% of the SNPs in that block(need only 2SNPs to type)

Haplotype length can varyfrom a few kb to mega bases.

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Page 16: MEME homework: probability of finding GAGTCA at a given position in the yeast genome, based on a background model of A = 0.3, T = 0.3, G = 0.2, C = 0.2.

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Page 17: MEME homework: probability of finding GAGTCA at a given position in the yeast genome, based on a background model of A = 0.3, T = 0.3, G = 0.2, C = 0.2.

Phenotypic variation (including disease susceptibility) are often linked to copy # changes

This is especially true of numerous types of cancers, where local amplificationsand translocations increase the copy number of cell proliferation regulators, etc.

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Page 18: MEME homework: probability of finding GAGTCA at a given position in the yeast genome, based on a background model of A = 0.3, T = 0.3, G = 0.2, C = 0.2.

Amplifications in breastcancer lines increase the copy # of specific regulators ..

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Page 19: MEME homework: probability of finding GAGTCA at a given position in the yeast genome, based on a background model of A = 0.3, T = 0.3, G = 0.2, C = 0.2.

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