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Module 6_Single Cash Flow Formulas

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    Interest Formulasfor Single Cash

    FlowsModule 6Chapter 3Contemporary Engineering EconomicsCopyright 2010

    Contemporary Engineering Economics, 5th edition, 2010

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    Types of CommonCash Flows inEngineering

    Economics

    Single cash ow

    Equal (uniform)payment series atregular intervals

    Linear gra ientseries

    !eometricgra ient series

    Irregular(ran om) paymentseries

    Contemporary Engineering Economics, 5th edition, 2010

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    Equivalence"elationship#etween P an

    FCompoun ing

    $rocess % Fin ing anequivalent futurevalue of current

    cash payment

    &iscounting$rocess % Fin ing anequivalent presentvalue of a futurecash payment

    Contemporary Engineering Economics, 5th edition, 2010

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    Single+mounts, FinF - !iven i - N -

    an P!iven , P .

    /0-111- i . 213- N . 4 years

    Fin , F

    E'cel Solution,

    Single Cash Flow Formula% Compoun +mountFactor

    Contemporary Engineering Economics, 5th edition, 2010

    P

    F

    N

    0

    (1 )( / , , )

    N

    F P iF P F P i N

    = +

    =

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    + TypicalCompounInterest Ta5le% say 203To 6n the compoun

    interest factor whenthe interest rate is203 an the num5erinterest perio s is 21-we coul evaluate thefollowing equationusing the interestta5le

    Contemporary Engineering Economics, 5th edition, 2010

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    Single+mounts, FinP - !iven i - N -

    an F!iven , F .

    /2-111- i . 203- N . 7 years

    Fin , P

    Excel Solution:

    Single Cash Flow Formula% $resent 8orth +mountFactor

    Contemporary Engineering Economics, 5th edition, 2010

    P

    F

    N

    0

    (1 )( / , , )

    N

    P F iP F P F i N

    = +

    =

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    Single+mounts, Fini - !iven P - F -

    an N

    !iven , F . /01- P ./21- N . 7 years

    Fin , i

    E'cel Solution,

    Solving for i

    Contemporary Engineering Economics, 5th edition, 2010

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    Single+mounts, FinN - !iven P - F -

    ani

    !iven , P . /:-111-F . /20-111- an i .013

    Fin , N

    E'cel Solution,

    Solving for N

    Contemporary Engineering Economics, 5th edition, 2010

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    "ule of

    *0

    +ppro'imating how long itwill ta;e for asum of moneyto ou5le

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    E'ample 22?neven$ayment

    Series

    @ow much oyou nee to

    eposit to ay ( P )to with raw/07-111 at n .2-/ -111 at n . 0-an /7-111 at n .A- if youraccount earns213 annualinterestB

    Contemporary Engineering Economics, 5th edition, 2010

    01 2 3 4

    $25,000

    $3,000 $5,000

    P

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    Chec; to see if /04-:00 isin ee su cient

    1 2 0 A#eginning#alance

    1 04-:00 :-A4A 01

    A-2 0 :0

    A-7A7 44

    InterestEarne(213)

    1 0-4:0 :A4 A0 A2 0: A7A 79

    $ayment

    D04-:00

    07-111 -111 1 7-111

    En ing#alance

    /04-:00 :-A4A 01

    A-2 0 :0

    A-7A7 44

    1 A*

    Contemporary Engineering Economics, 5th edition, 2010

    "oun ing errorIt shoul 5e 1 G

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    E'ample 20Future >alue of an?neven Serieswith >arying

    Interest "ates

    !iven , &eposit seriesas given over 7 years

    Fin , #alance at theen of year 7

    Contemporary Engineering Economics, 5th edition, 2010


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