Mole Concept and GMP Practice Problems.notebook October 13, 2019 Objectives 1. Define the concept of a mole using Avogadro’s number. 2. Calculate grams, moles, and number of particles of compounds given numerical data. • H.C.6A.4: Use mathematical and computational thinking to predict the amounts of reactants required and products produced in specific chemical reactions. • III.A.2.a. Explain the meaning of a mole and Avogadro’s number III.A.2.b. Interconvert between mass, moles, and number of particles What is a Mole? A mole is a counting number that is used to represent a large number of particles. Dozen Bushel Ream Pair 1 mole of any substance = 6.022 x 10 23 particles (atoms) 6.022 x 10 23 is called Avogadro's Number Example • How many donuts are in 1 mole of donuts? • How many feathers are in 1 mole of feathers? All of these terms mean a certain number. A mole means a certain number. Visualizing a Mole 1 mole of doughnuts 1 mole of pigs 6.022 x 10 23 doughnuts 6.022 x 10 23 pigs The mass of a mole of doughnuts does NOT equal the mass of a mole of pigs. How are a mole of carbon and gold the same? How are a mole of carbon and gold different? Get a pen!
Transcript
Mole Concept and GMP Practice Problems.notebook October 13, 2019
Objectives
1. Define the concept of a mole using Avogadro’s number.
2. Calculate grams, moles, and number of particles of compounds given numerical data.
• H.C.6A.4: Use mathematical and computational thinking to predict the amounts of reactants required and products produced in specific chemical reactions.• III.A.2.a. Explain the meaning of a mole and Avogadro’s numberIII.A.2.b. Interconvert between mass, moles, and number of particles
What is a Mole?
A mole is a counting number that is used to represent a large number of particles.
Dozen Bushel Ream Pair
1 mole of any substance = 6.022 x 1023 particles (atoms)
6.022 x 1023 is called Avogadro's Number
Example• How many donuts are in 1 mole of donuts?
• How many feathers are in 1 mole of feathers?
All of these terms mean a certain number.
A mole means a certain number.
Visualizing a Mole
1 mole of doughnuts 1 mole of pigs6.022 x 1023 doughnuts 6.022 x 1023 pigs
The mass of a mole of doughnuts does NOT equal the
mass of a mole of pigs.
How are a mole of carbon and gold the same?
How are a mole of carbon and gold different?
Get a pen!
Mole Concept and GMP Practice Problems.notebook October 13, 2019
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2018‐2019 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2018‐2019 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2018‐2019 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2018‐2019 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2018‐2019 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
Mole Concept and GMP Practice Problems.notebook October 13, 2019
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2018‐2019 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2018‐2019 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2018‐2019 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
Mole Concept and GMP Practice Problems.notebook October 13, 2019
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2018‐2019 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2018‐2019 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
Mole Concept and GMP Practice Problems.notebook October 13, 2019
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2018‐2019 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2018‐2019 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2018‐2019 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2018‐2019 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
Mole Concept and GMP Practice Problems.notebook October 13, 2019
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2018‐2019 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2018‐2019 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2018‐2019 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
Mole Concept and GMP Practice Problems.notebook October 13, 2019
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2018‐2019 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2018‐2019 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2018‐2019 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
1. A student uses a balance to mass out 111.2 g of calcium phosphate. How many moles is this?
g
g
mol=
111.2
Ca+2 PO43
Ca3(PO4)2
3 mol Ca x 40.08 g/mol = 120.2 g Ca
2 mol P x 30.97 g/mol = 61.94 g P
8 mol O x 16.00 g/mol =128.0 g O +
310.1 g/mol Ca3(PO4)2
Calcium phosphateGrams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2016‐2017 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
1. A student uses a balance to mass out 111.2 g of calcium phosphate. How many moles is this?
g
g
mol=
111.2
310.1
1
Mole Concept and GMP Practice Problems.notebook October 13, 2019
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2016‐2017 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
1. A student uses a balance to mass out 111.2 g of calcium phosphate. How many moles is this?
g
g
mol=
111.2
310.1
1 0.3586 mol
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2016‐2017 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
2. What is the mass of 1.12 x 1019 formula units of manganese(II) bromide?
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2016‐2017 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
2. What is the mass of 1.12 x 1019 formula units of manganese(II) bromide?
1. draw picket fence with units
2. place conversions in picket fence
formula
units
formula
units
mol
mol
g=
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2016‐2017 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
2. What is the mass of 1.12 x 1019 formula units of manganese(II) bromide?
1. draw picket fence with units
2. place conversions in picket fence
formula
units
formula
units
mol
mol
g=
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2016‐2017 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
2. What is the mass of 1.12 x 1019 formula units of manganese(II) bromide?
1. draw picket fence with units
2. place conversions in picket fence
formula
units
formula
units
mol
mol
g=
1.12 x 1019
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2016‐2017 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
2. What is the mass of 1.12 x 1019 formula units of manganese(II) bromide?
1. draw picket fence with units
2. place conversions in picket fence
formula
units
formula
units
mol
mol
g=
1.12 x 1019
6.022 x 1023
1
Mole Concept and GMP Practice Problems.notebook October 13, 2019
Manganese (II) bromide
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2016‐2017 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
2. What is the mass of 1.12 x 1019 formula units of manganese(II) bromide?
1. draw picket fence with units
2. place conversions in picket fence
formula
units
formula
units
mol
mol
g=
1.12 x 1019
6.022 x 1023
1 214.7
1
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2016‐2017 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
2. What is the mass of 1.12 x 1019 formula units of manganese(II) bromide?
1. draw picket fence with units
2. place conversions in picket fence
formula
units
formula
units
mol
mol
g=
1.12 x 1019
6.022 x 1023
1 214.7
1
0.00399 g
OR
3.99 x 103 g
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2016‐2017 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
3. A flask contains 1.27 x 1023 molecules of carbon tetrachloride. How many moles is this?
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2016‐2017 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
3. A flask contains 1.27 x 1023 molecules of carbon tetrachloride. How many moles is this?
=molecules
molecules
mol
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2016‐2017 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
4. In the separation of saltwater and sand experiment, you were able to recover 0.0234 mol of sodium chloride. You were supposed to recover 1.50 g of salt. Did you meet your goal?
Mole Concept and GMP Practice Problems.notebook October 13, 2019
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2016‐2017 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
4. In the separation of saltwater and sand experiment, you were able to recover 0.0234 mol of sodium chloride. You were supposed to recover 1.50 g of salt. Did you meet your goal?
mol
mol
g=
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2016‐2017 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
5. Pencil “lead” is really graphite, which is a form of carbon arranged in crystalline sheets that are easily sloughed off when you drag the pencil across your paper. The average unsharpened pencil contains 1.20 g of graphite. A student is able to determine that his pencil contains 5.09 x 1022 atoms of graphite. Is this an unsharpened pencil?
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2016‐2017 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
5. Pencil “lead” is really graphite, which is a form of carbon arranged in crystalline sheets that are easily sloughed off when you drag the pencil across your paper. The average unsharpened pencil contains 1.20 g of graphite. A student is able to determine that his pencil contains 5.09 x 1022 atoms of graphite. Is this an unsharpened pencil?
atoms
atoms
mol
mol
g=
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2016‐2017 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
6. During an experiment, a student needs to mass out 92.14 g of magnesium carbonate. How many formula units is this?
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2016‐2017 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
6. During an experiment, a student needs to mass out 92.14 g of magnesium carbonate. How many formula units is this?
g
g
mol
mol
formula
units=
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2016‐2017 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
1. A student uses a balance to mass out 111.2 g of calcium phosphate. How many moles is this?
Mole Concept and GMP Practice Problems.notebook October 13, 2019
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2016‐2017 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
1. A student uses a balance to mass out 111.2 g of calcium phosphate. How many moles is this?
g
g
mol=
1. draw picket fence with units
2. place conversions in picket fence
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2016‐2017 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
1. A student uses a balance to mass out 111.2 g of calcium phosphate. How many moles is this?
g
g
mol=
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2016‐2017 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
2. What is the mass of 1.12 x 1019 formula units of manganese(II) bromide?
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2016‐2017 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
2. What is the mass of 1.12 x 1019 formula units of manganese(II) bromide?
1. draw picket fence with units
2. place conversions in picket fence
formula
units
formula
units
mol
mol
g=
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2016‐2017 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
2. What is the mass of 1.12 x 1019 formula units of manganese(II) bromide?
1. draw picket fence with units
2. place conversions in picket fence
formula
units
formula
units
mol
mol
g=
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2016‐2017 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
3. A flask contains 1.27 x 1023 molecules of carbon tetrachloride. How many moles is this?
Mole Concept and GMP Practice Problems.notebook October 13, 2019
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2016‐2017 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
3. A flask contains 1.27 x 1023 molecules of carbon tetrachloride. How many moles is this?
=molecules
molecules
mol
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2016‐2017 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
4. In the separation of saltwater and sand experiment, you were able to recover 0.0234 mol of sodium chloride. You were supposed to recover 1.50 g of salt. Did you meet your goal?
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2016‐2017 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
4. In the separation of saltwater and sand experiment, you were able to recover 0.0234 mol of sodium chloride. You were supposed to recover 1.50 g of salt. Did you meet your goal?
mol
mol
g=
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2016‐2017 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
5. Pencil “lead” is really graphite, which is a form of carbon arranged in crystalline sheets that are easily sloughed off when you drag the pencil across your paper. The average unsharpened pencil contains 1.20 g of graphite. A student is able to determine that his pencil contains 5.09 x 1022 atoms of graphite. Is this an unsharpened pencil?
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2016‐2017 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
5. Pencil “lead” is really graphite, which is a form of carbon arranged in crystalline sheets that are easily sloughed off when you drag the pencil across your paper. The average unsharpened pencil contains 1.20 g of graphite. A student is able to determine that his pencil contains 5.09 x 1022 atoms of graphite. Is this an unsharpened pencil?
atoms
atoms
mol
mol
g=
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2016‐2017 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
6. During an experiment, a student needs to mass out 92.14 g of magnesium carbonate. How many formula units is this?
Mole Concept and GMP Practice Problems.notebook October 13, 2019
Grams—Moles—Particles Conversion Problems Name: _________________________ Unit 3: Language of Chemistry II CP Chemistry 2016‐2017 Guided Practice
1 mole = 6.022 x 10 23 particles (atoms, molecules, formula units, ions) 1 mole = molar mass of compound or element
6. During an experiment, a student needs to mass out 92.14 g of magnesium carbonate. How many formula units is this?
g
g
mol
mol
formula
units=
Homework:
Study for Naminq Quiz #5
Elements 130
All Polyatomic ions
Complete problems on yellow "extra practice worksheet" (Answers posted on class website
Homework:
Study for Naminq Quiz #5
Elements 130
All Polyatomic ions
Complete problems on yellow "extra practice worksheet" (Answers posted on class website
