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More Applications of Linear Stress-Strain Relations (Credit for many illustrations is given to McGraw Hill publishers and an array of
internet search results)
Parallel Reading
• 3.4 Statically Determinate Structures
• 3.5 Statically Indeterminate Structures
• 2.13 Generalized Hooke’s Law
I Mentioned That Sometimes in Statics Problems we run out of
equations before we have answers
A
B
Looks like no brainer statics
0F z
300+600 = A + B
But we are out of equations toBreak-down how much force isAt A and how much is at B
This is one of those Statically IndeterminateThings.
Material Properties to the Rescue
Blow the bottom support out and let the loaded barJust hang there.
Calculate how much lengthening we will see.
Next Impose that the Ground Did not Disappear and will Push Up as
Necessary to Ensure 0 displacement
See how large the force B has to be toCancel the displacement
Now you have B
Now we can use our statics equation
600+300 = A + B
A General Comment On Solution Methods
• Look at the Problem• Look at What You Know• Look at What You Want to Know• Look for What Equations Apply• Plan your solution strategy before you start
number crunching
• Some people just start trying equations hoping that some miracle will suddenly pop out (it usually doesn’t)
Lets Do the Math
Chop our block into 4 pieces
What force is yanking on the bottom ofBlock 1
Well lets see – Nothing – so P1=0
What force is yanking on the bottom ofBlock 2
Looks like 600 KN so P2 = 600
What force is yanking on the bottom ofBlock 3
Well pretty clearly Block 2 is hanging onWorth about 600 KN so P3 = 600
Throw in Block P4 – has 600 KNFrom below plus 300 KN for aTotal of 900 KN
Estimate some Deformations
P2 0.15 M
A=400X10^-6 M
600KN
δ= 600*0.15/(400X10^-6 * E) = 225000/E
Add Up All the Deformations(P2, P3, and P4)
Now We Will Have the Reaction at the Base Reverse the Deformation
We Know the Supports Working Together Prevent Stretching Out
We Used Material Properties to Determine RB
Finish It Off With Statics
Statics Folks – Eat Your Heart Out
Assignment #5
• Problem 3.5-2
What Happens if I Try to Pull a Block Apart in 3 Directions at
Once?
Make it Easy to Solve
If the deformations are smallGeometry from one forceWon’t change anything for theNext force. We can justPut them over the top ofEach other.
Actually that’s what we didWhen we printed physicalCompression over thermalExpansion or solved theStatically indeterminate problem
Remember – Each Force Stretches in Its Direction and Thins things
down in the other directions
Force in X direction stretchedIn X direction, but the pullsIn Y and Z thinned it down
Principle of Superposition