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NUMBER SYSTEM UNITS DIGIT SYSTEM UNITS DIGIT 1. What is the last digit of the number 35^7^9+ 1? A. 1...

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1 NUMBER SYSTEM UNITS DIGIT 1. What is the last digit of the number 3 5^7^9 + 1? A. 1 B. 4 C. 7 D. 3 2. What is the unit’s digit of 6 15 - 7 4 - 9 3 ? A. 6 B. 9 C. 7 D. 5 3. Which of the following numbers will completely divide (4 61 + 4 62 + 4 63 + 4 64 ) ? A. 3 B. 10 C. 11 D. 13 4. Which of the following is a perfect square? (a) 12194061 (b) 12194064 (c) 12194051 (d) 12194046 LCM AND GCD 1. A and B runs around a circular race track. A takes 4 minutes to finish it and B takes 6 minutes to finish it. Now both of them start running from the same point at the same time in the same direction. They’ll continue running on this track forever. So after how many minutes will they meet for the first time on the starting point? 2. Two traffic lights blink at an interval of 40 and 60 seconds respectively. After how many minutes will they link together? 3. The LCM of two numbers is 4800 and their HCF is 160. If one number is 480, then the second number is A.1200 B.1500 C.1600 D.1800 4. In a meet, persons from five different places have assembled in Bangalore High School. From the five places the persons come to represent are 42, 60, 210, 90 and 84. What is the minimum number of rooms that would be required to accommodate so that each room has the same number of occupants and occupants are all from the same places? A.44 B.62 C.81 D.96 5. What is the minimum number of square marbles required to tile a floor of length 5 meter 78 centimeter and width 3 meter 74 centimeter, given that 1 meter length is same as 100 centimeter length? (A) 176 (B) 187 (C) 216 (D) 748 6. What is the greatest length that can be used to measure exactly the following lengths -20 ft, 13ft 9 inches, 17ft 6 inches and 21 ft 3 inches? (a) 1 ft (b) 3 inches (c) 1ft 3 inches (d) None of these 7. What is the greatest four digit number that when divided by any of the numbers 6, 9, 12, 17 leaves a remainder of 1?
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Page 1: NUMBER SYSTEM UNITS DIGIT SYSTEM UNITS DIGIT 1. What is the last digit of the number 35^7^9+ 1? A. 1 B. 4 C. 7 D. 3 2. ... 9.Mr. ‘X’ is worried about the balance of his monthly

NUMBER SYSTEM

UNITS DIGIT 1. What is the last digit of the number 35^7^9+ 1?A. 1 B. 4 C. 7 D. 3 2. What is the unit’s digit of 615 - 74 - 93?A. 6 B. 9 C. 7 D. 5 3. Which of the following numbers will completely divide (461 + 462 + 463 + 464) ?A. 3 B. 10 C. 11 D. 13 4. Which of the following is a perfect square?(a) 12194061 (b) 12194064 (c) 12194051 (d) 12194046

LCM AND GCD 1. A and B runs around a circular race track. A takes 4 minutes to finish it and B takes 6minutes to finish it. Now both of them start running from the same point at the same time in the same direction. They’ll continue running on this track forever. So after how many minutes will they meet for the first time on the starting point?

2. Two traffic lights blink at an interval of 40 and 60 seconds respectively. After how manyminutes will they link together?

3. The LCM of two numbers is 4800 and their HCF is 160. If one number is 480, then thesecond number is A.1200 B.1500 C.1600 D.1800

4. In a meet, persons from five different places have assembled in Bangalore High School.From the five places the persons come to represent are 42, 60, 210, 90 and 84. What is the minimum number of rooms that would be required to accommodate so that each room has the same number of occupants and occupants are all from the same places? A.44 B.62 C.81 D.96

5. What is the minimum number of square marbles required to tile a floor of length 5 meter 78centimeter and width 3 meter 74 centimeter, given that 1 meter length is same as 100 centimeter length? (A) 176 (B) 187 (C) 216 (D) 748

6. What is the greatest length that can be used to measure exactly the following lengths -20 ft,13ft 9 inches, 17ft 6 inches and 21 ft 3 inches? (a) 1 ft (b) 3 inches (c) 1ft 3 inches (d) None of these

7. What is the greatest four digit number that when divided by any of the numbers 6, 9, 12, 17leaves a remainder of 1?

Page 2: NUMBER SYSTEM UNITS DIGIT SYSTEM UNITS DIGIT 1. What is the last digit of the number 35^7^9+ 1? A. 1 B. 4 C. 7 D. 3 2. ... 9.Mr. ‘X’ is worried about the balance of his monthly

(a) 9997 (b) 9793 (c) 9895 (d) 9487

NUMBER OF DIVISORS 1. Find the number of factors of 362?2. How many odd positive divisors does 540 have?3. Find the sum of factors of 7200?4. N is the smallest number that has 5 factors. How many factors does (N - 1) have??A.2 B.3 C.4 D.5

REMAINDER THEOREM 1. What is the remainder of 1421 *1423 * 1425 is divided by 12?2. A number when divided by 296 leaves 75 as remainder. When the same number is dividedby 37, the remainder will be: A. 1 B. 2 C. 8 D. 11 3. Find the remainder when 1! +2! +3! +……+100! is divided by product of first 7 naturalnumbers 4 . What is the remainder when 64999 is divided by 7? 5 . What is the remainder when 444444^444 is divided by 7? 6 . What is the remainder when 725 is divided by 6? 7 . When a number X is divided by 13 the remainder obtained is 12. What is the remainder when X13 is divided by 13? 8. R [(2101+3101) / 5] =?9. R [(1523+2323) / 19] =?10. R [(1613+1713 +1813+1913) / 70] =?11. R [(5100-2100) /7] =?12. R [(10175-7675) /25] =?

MAXIMUM POWER 1. What is the maximum value of m such that 7m divides into 14! evenly?A.1 B.2 C.3 D.4 2. The highest power of 9 dividing 99! completely isA.12 B.14 C.22 D.24 3. What is the least number that should be multiplied to 100! to make it perfectly divisible by350? (a) 144 (b) 9 (c) 108 (d) 216 4. For what maximum value of n, will the expression 10200! / 504n be an integer?(a) 1698 (b) 2547 (c) 3397 (d) 547

NUMBER OF ZEROES 1. Find the no of zeros at the end of the product 24x32x17x23x19?2. Find the no of zeros at the end of the product 8x15x23x17x25x22?3. How many zeroes will be there in the expansion of the expression 11×22×33×44……..×100100?

Page 3: NUMBER SYSTEM UNITS DIGIT SYSTEM UNITS DIGIT 1. What is the last digit of the number 35^7^9+ 1? A. 1 B. 4 C. 7 D. 3 2. ... 9.Mr. ‘X’ is worried about the balance of his monthly

A.1200 B.1232 C.1300 D.1296 4. Find the no of zeros at the end of 250!?

MISC QUESTIONS 1. How many natural numbers are there between 23 and 100 which are exactly divisible by 6 ?A.8 B.11 C.12 D.13 2. A boy multiplied 987 by a certain number and obtained 559981 as his answer. If in theanswer both 9 are wrong and the other digits are correct, then the correct answer would be: A. 553681 B. 555181 C. 555681 D. 556581 3. If a and b are prime numbers such that a>b, which of the following cannot be even? (a) a + b (b) a - b (c) a × b (d) ab

4. If the 8 th term of an AP is 88 and the 88 th term is 8, then 100 th term is :(a) 1 (b) 2 (c) -4 (d) 8 5. If the ratio of the sum of the first 6 terms of a G.P. to the sum of the first 3 terms of the G.P.is 9, what is the common ratio of the G.P? (a) 3 (b) 2 (c) 1/3 (d) 9

Page 4: NUMBER SYSTEM UNITS DIGIT SYSTEM UNITS DIGIT 1. What is the last digit of the number 35^7^9+ 1? A. 1 B. 4 C. 7 D. 3 2. ... 9.Mr. ‘X’ is worried about the balance of his monthly

PERCENTAGES(Questions)

1. Whichofthefollowingisthelargestnumber.a)20%of200 b)7%of500 c)1300%of3 d) 600%of7 e)700%of9

2. Ifweexpress41(3/17)%asafractionthenitisequalto.a)17/7 b)7/17 c)12/17 d)3/17 e)27/17

3. ‘A’sellshisgoods25%cheaperthan‘B‘and25%dearerthan‘C’.HowmuchpercentageisC’sgoodscheaperB”sa)33.33% b) 50% c)66.66% d)40% e)none

4. Thelength,breadthandheightofaroomintheshapeofacuboidareincreasedby10%,20%and50%respectively.Findthepercentagechangeinthevolumeofthecuboid.a) 77% b) 75% c)88% d) 98% e)99%

5. 50%ofa%ofbis75%ofb%ofc.Whichofthefollowingisca) 1.5a b) 0.667a c) 0.5a d) 1.25a e) 1.66a

6. ‘A’spend20%ofhismonthlyincomeonhishouseholdexpenditure,15%oftherestonbooks,30%oftherestonclothesandsavetherest.Oncounting,hecomestoknowthathehasfinallysaved9520RS.Findhismonthlyincomea) 10000 b) 15000 c) 20000 d) 12000 e) none

7. Anumberismistakenlydividedby5insteadofbeingmultipliedby5.Findthepercentagechangeintheresultduetohismistakea) 96% b) 95% c) 2400% d) 200% e) none

8. Inanelectionbetween2candidates,‘A’gets65%ofthetotalvalidvotes.Ifthetotalvoteswere6000,WhatisThenumberofvalidvotesthattheothercandidategetsif25%ofthetotalvotesweredeclaredinvalida) 1625 b) 1575 c) 1675 d) 1525 e) none

9. Mr.‘X’isworriedaboutthebalanceofhismonthlybudget.Thepriceofpetrolhasincreasedby40%.ByWhatpercentshouldhereducetheconsumptionofpetrolsothatheisabletobalancehisbudget.a) 33.33 b) 28.56 c) 25 d) 14.28 e) none

10. Afterreceivingtwosuccessiveraises,A’ssalarybecameequalto15/8timesofhisinitialsalary.ByhowmuchPercentwasthesalaryraisedthefirsttimeifthesecondraisewastwiceashigh(inpercent)asthefirst.a) 15% b) 20% c) 25% d) 30% e) 33.33%

11. Theminimumquantityofmilkinliters(inthewholenumber)thatshouldbemixedinamixtureof60litresinwhichtheinitialratioofmilktowateris1:4sothattheresultingmixturehas15%milkis.a) 3 b) 4 c) 5 d) 6 e)thisisnotpossible

12. Afractionissuchthatifdoubleofthenumeratorandtripleofthedenominatorischangedby+10%And‐30%respectivelythanweget11%of16/21.Findthefraction.a) 4/25 b) 2/25 c) 3/25 d) none

Page 5: NUMBER SYSTEM UNITS DIGIT SYSTEM UNITS DIGIT 1. What is the last digit of the number 35^7^9+ 1? A. 1 B. 4 C. 7 D. 3 2. ... 9.Mr. ‘X’ is worried about the balance of his monthly

13. Inatownthepopulationofmalesdecreasedby25%fromthe2001to2002.Thepopulationofthefemalesformed44(4/9)%ofthepopulationin2002,whatpercentageofthepopulationin2001weremales.a)50% b) 662/3% c) 80% d) 75%

14. Asalesmanisappointedonthebasicsalaryof1200permonthandtheconditionthatforeverysalesof10000above10000,hewillget50%ofbasicsalaryand10%ofsalesasareward.thisincentiveschemeDoesnotforfirst10000ofsales.Whatshouldbethevalueofsalesifhewantstoearn7600inaparticularMontha) 60,000 b) 50,000 c) 40,000 e) none

15. Duetoa25%hikeinthepriceofthericeperkgapersonisabletopurchase20kglessfor400Rs.Findtheincreasedpriceofriceperkg.a) 5 b) 6 c) 10 d) 4

16. OftheadultpopulationinHyderabad,45%ofmenand25%ofwomenaremarried.Whatpercentageofthetotalpopulationofadultismarried(assumethatnomenmarriedmorethanonewomanandviceversa).a) 33.33% b) 32.14% c) 31.1% d) none

17. Thepopulationofvillageis1,00,000.Increasedrateperannulis10%.FindthepopulationatthestartingofThefourthyear.a) 1,33,100 b) 1,21,000 c)1,333,00 d) none

18. Anorecontains25%ofanalloythathas90%iron.Otherthanthis,intheremaining75%oftheore,thereisnoIron.Howmanykilogramsoftheoreareneededtoobtain60kgofpureiron.a) 250kg b) 275kg c) 300kg d)266.66kg

19. Afterthreesuccessiveequalpercentageriseinthesalarythesumof100rupeesturnedinto140rupees49Paisa.FindthepercentRaiseinthesalary.a) 12% b) 22% c) 66% d) 82% e)77%

20. Thehourlywagesofalaborareincreasedby12.5%,whereastheweeklyworkinghoursarereducedby8%.Findthepercentagechangeinweeklywagesifshewasgetting1200Rsperweekfor50hourspreviously.a) 3.5% b) 4% c) 4.5% d)none

21. Aschoolhas2000students,outofwhich40%ofthestudentsareinhighersecondary.Outofthestudentsinhighersecondary,28%aregirlsand50%ofthempassed.Theoverallpasspercentageinthehighersecondaryis40%.Howmanyboyspassed?a) 208 b) 320 c) 200 d) 96

22. Inthetestquestionwereaskedinfivesection.Outofthetotalstudent,5%candidatesareclearedthecut‐offintheallsectionand5%clearednone.Oftherest,25%clearedonlyonesectionand20%clearedfoursectionsif24.5%oftheentirecandidatesclearedtwosectionand300candidatesclearedthreesections.Findhowmanycandidatesappearedatthetest.A) 1000 B) 1200 C)1500 D) 2000 E)1800

Page 6: NUMBER SYSTEM UNITS DIGIT SYSTEM UNITS DIGIT 1. What is the last digit of the number 35^7^9+ 1? A. 1 B. 4 C. 7 D. 3 2. ... 9.Mr. ‘X’ is worried about the balance of his monthly

23. Astudentsecured38%ofthetotalmarksinanexamandgets18marksmorethanthepassmarks.Asecondstudentsecured27%oftotalmarksinthesameexamandfailby37marks.Whatisthepassmarkasapercentageofthetotalmarks.A) 28% b) 32.2% c) 34.4% d) 35%

24. Anandcutarectangularpieceofpapertwice.Withthefirstcut,hedecreaseditsareaby40%.Withthesecondcuthedecreaseditsareaby50%.Itsfinalareawas30sqcmlessthanitsareaafterthefirstcut.FinditsoriginalareaA) 120 b) 100 c) 90 d)80

25. Anewcoachwasappointedinthemiddleofaseasonforfootballteam.Afterhetookover,theteamwon80%ofthe60matchesitplayed.Buttheoverallperformedoftheteamwasonly60%.Findtheminimumnumberofmatchestheteammusthaveplayedthatseasonbeforethenewcoachtookover.a) 10 b) 15 c) 20 d) 80

26. A student secured 38% of the total marks in an exam and gets 18 marks more than the pass marks. A second

student secured 27% of total marks in the same exam and fail by 37 marks. What is the pass mark as a 

percentage of the total marks?  

A) 28% b) 32.2%  (c)34.4%  d) 35%

27. A school has 2000 students, out of which 40% of the students are in higher secondary. Out of the students

in higher secondary, 28% are girls and 50% of them passed. The overall pass percentage in the higher secondary 

is 40%. How many boys passed?  

A)208                                           b)320  c) 200 d) 96

Page 7: NUMBER SYSTEM UNITS DIGIT SYSTEM UNITS DIGIT 1. What is the last digit of the number 35^7^9+ 1? A. 1 B. 4 C. 7 D. 3 2. ... 9.Mr. ‘X’ is worried about the balance of his monthly

PERCENTAGES(Solutions)

1. Which of the following is the largest number .a)20%of 200 b)7% of 500 c)1300% of 3 d) 600% of 7 e)700% of 9

2. If we express 41(3/17)% as a fraction then it is equal to.a)17/7 b)7/17 c)12/17 d)3/17 e)27/17

3. ‘A’ sells his goods 25% cheaper than ‘B ‘and 25% dearer than ‘C’. How much percentage is C’sgoods cheaper B”s a)33.33% b) 50% c)66.66% d)40% e)noneExp: A=75% of B, A= 125% of C, 75% of B= 125% of C

ofBCBBC %605

3

512

100

100

57

So, C is 40% less than B

4. The length, breadth and height of a room in the shape of a cuboid are increased by 10% ,20% and50% respectively. Find the percentage change in the volume of the cuboid. a) 77% b) 75% c)88% d) 98% e)99%Exp: Initial Volume of a cuboid = LBH New Volume = 1.1L *1.2B*1.5H = 1.98 LBH So 1.98 LBH - LBH= 0.98 LBH is increase.... So 98% increase

5. 50% of a% of b is 75% of b% of c .Which of the following is ca) 1.5a b) 0.667a c) 0.5a d) 1.25a e) 1.66aExp: Simplicity the equation by decimal... .5a/100b= .75b/100cC=.5/.75a= 0.667a

6. ‘A’ spend 20% of his monthly income on his household expenditure, 15% of the rest on books ,30% of the rest on clothes and save the rest. On counting, he comes to know that he has finally saved 9520 RS . Find his monthly income a) 10000 b) 15000 c) 20000 d) 12000 e) noneExp: Initial value assume as 100% or X. (rest means suppose we spend 20% rem is only 80%, 15% of rest is 15% of 80% = 12% from over all) Final amount 9520= X*.8*.85*.7 => 47.6% of x= 9520

1006.47

9520X

X= 20000

7. A number is mistakenly divided by 5 instead of being multiplied by 5. Find the percentage changein the result due to his mistake a) 96% b) 95% c) 2400% d) 200% e) noneExp:

% change = 100TrueValue

Error

Page 8: NUMBER SYSTEM UNITS DIGIT SYSTEM UNITS DIGIT 1. What is the last digit of the number 35^7^9+ 1? A. 1 B. 4 C. 7 D. 3 2. ... 9.Mr. ‘X’ is worried about the balance of his monthly

=%96100

25

24

)5(5

25

55

5

x

x

x

xx

x

xx

8. In an election between 2 candidates, ‘A’ gets 65% of the total valid votes. If the total votes were 6000, What is The number of valid votes that the other candidate gets if 25% of the total votes were declared invalid a) 1625 b) 1575 c) 1675 d) 1525 e) none Exp: 1. 25% of the votes were invalid. Then, 75% of the votes are valid. 2. A got 65% of valid votes, then B got remaining 35% of valid votes Total votes for B = 75% of 35% of 6000 = 1575 9. Mr. ‘X’ is worried about the balance of his monthly budget. The price of petrol has increased by 40% . By What percent should he reduce the consumption of petrol so that he is able to balance his budget. a) 33.33 b) 28.56 c) 25 d) 14.28 e) none Exp: Expenditure = Quantity Price Assume Price=Rs.100, Exp=Rs.100, So Quantity=1 Now Price=Rs.140, Exp=Rs.100

SO reduce Quantity =%56.28100

140

40100

140

100140100

Pr

Pr

ice

Expice

10. After receiving two successive raises, A’s salary became equal to 15/8 times of his initial salary. By how much Percent was the salary raised the first time if the second raise was twice as high (in percent) as the first. a) 15% b) 20% c) 25% d) 30% e) 33.33% Exp: Let Initial salary was Rs. 100.After two rais it become 15/8 i.e. (15*100)/8 = Rs. 187.5 Raise = 187.5 -100 = 87.5 Using formula,[(first raise + 2nd rais) + (first raise *2nd raise)/100] = 87.5 X +2X + (2X^2)/100 = 87.5 300X + 2X^2 = 8750 X^2 + 150X = 4375 X^2 + 150X - 4375 = 0X^2 + 175 X - 25X - 4375 =0 X = -175, 25 (Negative value is not possible) So, X = 25% Second Raise was 2X = 2*25 = 50% 11. The minimum quantity of milk in liters (in the whole number ) that should be mixed in a mixture of 60 litres in which the initial ratio of milk to water is 1:4 so that the resulting mixture has 15% milk is . a) 3 b) 4 c) 5 d) 6 e ) this is not possible Exp: Already milk is 20% in 60 liters. After add 6 liter of milk it is increase in percentage. There is no possible of reduce to 15% 12. A fraction is such that if double of the numerator and triple of the denominator is changed by +10% And -30%respectively than we get 11% of 16/21. Find the fraction. a) 4/25 b) 2/25 c) 3/25 d) none Exp:

Page 9: NUMBER SYSTEM UNITS DIGIT SYSTEM UNITS DIGIT 1. What is the last digit of the number 35^7^9+ 1? A. 1 B. 4 C. 7 D. 3 2. ... 9.Mr. ‘X’ is worried about the balance of his monthly

Let the number is x/y

So, 21

16%11

%703

%1102

y

x

Solve x/y= 2/25

13. In a town the population of males decreased by 25% from the 2001 to 2002. The population of

the females formed 44(4/9)% of the population in 2002 , what percentage of the population in 2001

were males.

a)50% b) 66 2/3% c) 80% d) 75%

14. A salesman is appointed on the basic salary of 1200 per month and the condition that for every

sales of 10000 above 10000, he will get 50% of basic salary and 10% of sales as a reward . this

incentive scheme Does not for first 10000 of sales. What should be the value of sales if he wants to

earn 7600 in a particular Month

a) 60,000 b) 50,000 c) 40,000 e) none Exp: Earning = 7600 out of which 1200 is basic so he earns above basic = 7600-1200= 6400 for additional 10000 he earns extra = 600 + 1000= 1600 hence he sales extra = 10000*6400/1600=40,000 total sales = 40,000+10,000=50,000 15. Due to a 25% hike in the price of the rice per kg a person is able to purchase 20kg less for 400 Rs. Find the increased price of rice per kg. a) 5 b) 6 c) 10 d) 4 16. Of the adult population in Hyderabad, 45% of men and 25% of women are married. What percentage of the total population of adult is married (assume that no men married more than one woman and vice versa). a) 33.33% b) 32.14% c) 31.1% d) none Exp: Assume that 10men are married in the city means same no of women are married. So, 45% of men = 25% of women Men: Women= 25:45

% of adult married = %14.3210070

5.22

4525

)%(25)%(45

womenmen

17. The population of village is 1,00,000. Increased rate per annul is 10%. Find the population at the starting of The fourth year. a) 1,33,100 b) 1,21,000 c)1,333,00 d) none Exp: Every year 10% increase so end of each year 100%+10% =110% (1.1) of basic value So, 100000×1.1×1.1×1.1=133100 18. An ore contains 25% of an alloy that has 90% iron. Other than this ,in the remaining 75% of the ore ,there is no Iron. How many kilograms of the ore are needed to obtain 60 kg of pure iron. a) 250kg b) 275kg c) 300kg d)266.66 kg Exp: Let there is 100 kg of ore. 25% ore contains 90% off Iron that means 25 kg contains; 25*90/100 = 22.5 kg Iron.

Page 10: NUMBER SYSTEM UNITS DIGIT SYSTEM UNITS DIGIT 1. What is the last digit of the number 35^7^9+ 1? A. 1 B. 4 C. 7 D. 3 2. ... 9.Mr. ‘X’ is worried about the balance of his monthly

22.5 kg Iron contains 100 kg of ore. Then, 1 kg of iron contains = 25/100 kg ore; Hence, 60 kg iron contains = 100*60/22.5 = 266.66 kg ore. 19. After three successive equal percentage rise in the salary the sum of 100 rupees turned in to 140

rupees 49Paisa. Find the percent Raise in the salary.

a) 12% b) 22% c) 66% d) 82% e)77%

Exp:

We solve it through options. Choosing options for trial depends on mental thought.

100----12%↑--→112------12%↑----→125.44---12%↑--->140.49

So, answer is 12%.

20. The hourly wages of a labor are increased by 12.5% , where as the weekly working hours are

reduced by 8%.Find the percentage change in weekly wages if she was getting 1200 Rs per week for

50 hours previously .

a) 3.5% b) 4% c) 4.5% d)none

Exp:

Actual weekly wages Rs.1200 per week for 50 hours, so 1 hr wages is

Now, labor increase by 12.5% is 24+ 12.5% of 24= Rs.27

And hours reduce by 8% is 50- 8% of 50 = 46 hours.

So, total wages is 46*27=Rs.1242

Gain is Rs.42, gain % = %5.31001200

42

21. A’s monthly salary is A rupees. Of this ,he spends X rupees .The next month he has an increment

of C% in his salary and D% in his expenditure .The new amount saved is .

a) A(1+C/100)-X(1+D/100) b)(A/100)(C-(D)X(1+D/100)

C) X(C-(D)/100 d) X(C+D)-/100

22. A clock is set right at 12 noon on Monday . it loses 1.2% on the correct time in the first week but

gains ¼% on The true time during the second week . The time show on Monday after two weeks will

be .

a) 12:25:12 b) 11:34:48 c)12:50:24 d)12:24:16 e) none

23. In the test question were asked in five section .Out of the total student, 5% candidates are cleared

the cut-off in the all section and 5% cleared none. Of the rest, 25% cleared only one section and 20%

cleared four sections if 24.5% of the entire candidates cleared two section and 300candidates cleared

three sections .Find how many candidates appeared at the test.

A) 1000 B) 1200 C)1500 D) 2000 E)1800

Exp:

Total five sections,

1. 5% cleared all section

2. 5% not cleared any section

So 10%, then remaining 90%

3. 25% of remaining 90% cleared only one section is 22.5%

4. 20% of remaining 90% cleared four section is 18%

Page 11: NUMBER SYSTEM UNITS DIGIT SYSTEM UNITS DIGIT 1. What is the last digit of the number 35^7^9+ 1? A. 1 B. 4 C. 7 D. 3 2. ... 9.Mr. ‘X’ is worried about the balance of his monthly

5. 24.5% of total cleared two section.

So, Total 5%+5%+22.5%+18%+24.5%= 75%

Remaining is 25% is 300. Then total =1200

25

100300

24. Anand cut a rectangular piece of paper twice. With the first cut , he decreased its area by

40%.With the second cut he decreased its area by 50%. Its final area was 30 sq cm less than its area

after the first cut. Find its original area

A) 120 b) 100 c) 90 d)80

Exp:

After 1st cut he decreased by 40%, so remaining is 60% area.

After 2nd cut decreased by 50%, so 60% of 50% =30% of total area.

Final area remaining is 30 sq.cm,

So, 30% of total area is 30 sq.cm

Then the original area iscmsq.100

30

10030

25. A new coach was appointed in the middle of a season for football team. After he took over, the

team won 80% of the 60 matches it played. But the overall performed of the team was only 60%. Find

the minimum number of matches the team must have played that season before the new coach took

over.

a) 10 b) 15 c) 20 d) 80

Exp:

Team won 80% of 60= 48 matches

So, let we take all the games they played in that season are loss.

The minimum no of matches loss and played x.

Overall perform only 60% won.

2060360

48

100

60

xx

x

26. A student secured 38% of the total marks in an exam and gets 18 marks more than the pass

marks. A second student secured 27% of total marks in the same exam and fail by 37 marks. What is

the pass mark as a percentage of the total marks?

A) 28% b) 32.2% c) 34.4% d) 35%

Exp:

Let, Total mark is T & Pass mark is P.

38% of Total Mark = P+18------1

27% of Total Mark = P-37------2

Solve 1 & 2, 11% of Total Mark = 55,

Total= 50010011

55

Pass Mark = 38% of Total – 18 = 1721819018)500100

38(

Pass %= %4.34100500

172

Page 12: NUMBER SYSTEM UNITS DIGIT SYSTEM UNITS DIGIT 1. What is the last digit of the number 35^7^9+ 1? A. 1 B. 4 C. 7 D. 3 2. ... 9.Mr. ‘X’ is worried about the balance of his monthly

27. A school has 2000 students, out of which 40% of the students are in higher secondary. Out of the

students in higher secondary, 28% are girls and 50% of them passed. The overall pass percentage in

the higher secondary is 40%. How many boys passed?

a) 208 b) 320 c) 200 d) 96

Exp:

Total students in higher secondary are 40% of 2000 is 800 students.

Among the 800 students 28% are girls, 28% of 800 = 224

Total no of girls pass 50% of 224 is 112.

But, overall pass only 40%, 40% of 800 is 320.

So, boys passed in the exam is Total Pass – No of girls pass = 320 – 112 = 208

Page 13: NUMBER SYSTEM UNITS DIGIT SYSTEM UNITS DIGIT 1. What is the last digit of the number 35^7^9+ 1? A. 1 B. 4 C. 7 D. 3 2. ... 9.Mr. ‘X’ is worried about the balance of his monthly

CDC DEPT    Profit, Loss & Discount_(Questions) SRM University

1. The cost price of 20 articles is the same as the selling price of x articles. If the profit is25%, find out the value of x. A. 15 B. 16 C. 18 D. 25 2. If selling price is doubled, the profit triples. What is the profit percent?A. 100 % B. 105 1/3 % C. 66 2/3 % D. 120 %

3. Some articles were bought at 6 articles for Rs. 5 and sold at 5 articles for Rs. 6. What isthe gain percentage? A. 44% B. 33.33% C. 30% D. 25% 4. On selling 17 balls at Rs. 720, there is a loss equal to the cost price of 5 balls. What is thecost price of a ball? A. Rs. 43 B. Rs. 60 C. Rs. 55 D. Rs. 34

5. A shopkeeper sells his goods at cost price but uses a weight of 800 gm instead of kilogramweight. What is his profit percentage? A. 18% B. 20% C. 25% D. 40% 6. A trader keeps the marked price of an item 35% above its cost price. The percentage ofdiscount allowed to gain 8% is A. 27% B. 17% C. 25% D. 20%

7. The total cost price of two items is 10200/- and their selling price are equal if one of thetwo items sold at a loss of 12% and another at a loss of 18% then the cost price of the item sold at a loss of 18% is? A. 5100 B. 5280 C. 4920 D. 4329.6

8. A machine is sold at a loss of 10%. Had it been sold at a profit of 15%, it would havefetched Rs. 50 more. The cost price of the machine is. A. Rs. 1000 B. Rs. 500 C. Rs.200 D. Rs.250

9. Goods are purchased for Rs. 450 and one-third is sold at a loss of 10%. At what profit percent should the remainder be sold so as to gain 20% on the whole transaction? A. 30% B. 35% C. 33.33 % D. 25%

10. A reduction of 10% in the price of sugar enables a man to buy 25 kg more for Rs. 225.What is the original price of sugar (per kilogram)? A. Rs.1 B. Rs. 1.5 C. Rs.0.9 D.Rs.2

11. If a merchant makes a profit of 20% after giving a 20% discount, what should be hismark-up? A. 20% B. 30% C. 40% D. 50%

12. An article is sold at certain price. By selling it at 2/3 of its price one losses 10%, find thegain at original price? A. 20% B. 33.33% C.35% D. 40%

13. A tradesman sold an article at a loss of 20%.if the selling price has been increased byRs100, there would have been a gain of 5%.what was the cost price of the article? A. 290 B. 350 C.400 D. None of these

Page 14: NUMBER SYSTEM UNITS DIGIT SYSTEM UNITS DIGIT 1. What is the last digit of the number 35^7^9+ 1? A. 1 B. 4 C. 7 D. 3 2. ... 9.Mr. ‘X’ is worried about the balance of his monthly

CDC DEPT           Profit, Loss & Discount_ Work Sheet SRM University  

 

14. A man sells an article at a profit of 25%if he had bought it 20% less and sold it for Rs 10.50 less, he would have gained 30%find the cost price of the article. A. 42 B. 57 C.50 D. None of these 15. A man 2 flats for Rs 675958 each on one he gains 16% while on the other he losses 16%. How much does he gain/loss in the whole transaction? A.2.56 % . B. 7.18% C.11.40% D. None of these 16. A man bought a horse and a car ridge for Rs 3000. He sold the horse at a gain of 20% and the carriage at a loss of 10%, thereby gaining 2% on the whole. Find the cost of the horse. A. 2000 B. 1500 C. 1300 D.1200 17. Find the single discount equivalent to a series discount of 20%, 10% and 5% A. 42.60 % B. 57.18% C.68.40% D. None of these 18. An uneducated retailer marks all its goods at 50% above the cost price and thinking that he will still make 25% profit, offers a discount of 25% on the market price. What is the actual profit on the sales? A.12.50 % B. 27.8% C.26.5% D. None of these 19. A retailer buys 40 pens at the market price of 36 pens from a wholesaler, if he sells these pens giving a discount of 1%, what is the profit %? A. 6 % B. 77.8% C.11% D. None of these 20. The profit earned after selling an article for Rs 625 is the same as the loss incurred after selling the article for Rs 435. What is the cost price of the article? A. 450 B. 480 C. 500 D. 530 21. By selling 5 articles for Rs.15, a man makes a profit of 20%. Find his gain or loss percentage if he sells 8 articles for Rs.18.4? A. 8% Loss B. 8.33% Loss C. 2.22% Loss D. 2.22% Profit 22. The Printed price of a calculator is Rs.180. A retailer pays Rs.137.7 for it by getting successive discounts of 10% and another rate which is illegible. What is the second discount rate? A. 12% B.15% C.12.5% D. 20% 23. The profit earned when an article is sold for Rs.800 is 20 times the loss incurred when it is sold for Rs.275. At what price should the article be sold if it is desired to make a profit of 25%. A. Rs.300 B. Rs.350 C. Rs.375 Rs.400 24. A sells to B goods at five-thirds the rate of profit at which B has decided to sell it to C. C, on other hand, sells it to D at one-third the rate of profit at which B sold it to C. If D gives Rs.2145 to C at 10% profit, how much did A buy it for?. A. Rs.1000 B. Rs.2000 C. Rs.1500 D. Rs.1800 25. A reduction of 20% in the price of sugar enables a house wife to purchase 6 kg more for Rs. 240 what is the original price per kg of sugar? A. 10 kg B. 15 kg C. 25 kg D.30 kg

Page 15: NUMBER SYSTEM UNITS DIGIT SYSTEM UNITS DIGIT 1. What is the last digit of the number 35^7^9+ 1? A. 1 B. 4 C. 7 D. 3 2. ... 9.Mr. ‘X’ is worried about the balance of his monthly

Profit, Loss & Discount (Solutions)Class Work: 1. The cost price of 20 articles is the same as the selling price of x articles. If the profit is

25%, find out the value of x.

A. 15 B. 16 C. 18 D. 25

Ans: Let the Cost Price (CP) of one article = 1

=> CP of x articles = x ------------------------------(Equation 1)

CP of 20 articles = 20

Given that cost price of 20 articles is the same as the selling price of x articles

=> Selling price (SP) of x articles = 20--------------(Equation 2)

Given that Profit = 25%

⇒(SP−CP/CP)=25/100=1/4------------( Equation 3)

Substituting equations 1 and 2 in equation 3,

⇒(20−x)/x=1/4⇒80−4x=x⇒5x=80⇒x=80/ 5=16

2. If selling price is doubled, the profit triples. What is the profit percent?

A. 100 % B. 105 1/3 % C. 66 2/3 % D. 120 %

ANS: Explanation :

Let the CP = x , SP = y, profit = SP –CP = y-x

If SP is doubled, SP = 2y , Now Profit = SP –CP = 2y - x

Given that If selling price is doubled, the profit triples

⇒2y–x=3(y−x) ⇒2y–x=3y−3x⇒y=2x ⇒Profit%=Profit/ CP×100 =y−x/ x×100=2x–x/ x×100=x/ x×100=100%

3. Some articles were bought at 6 articles for Rs. 5 and sold at 5 articles for Rs. 6. What is

the gain percentage?

A. 44% B. 33.33% C. 30% D. 25%

ANS: CP of 1 item=5/6SP of 1 item=6/5Gain%=SP−CP/CP×100=(6/5−5/6)/

5/6×100=(36/25−1)×100= 11/25×100=11×4=44

4. On selling 17 balls at Rs. 720, there is a loss equal to the cost price of 5 balls. What is the

cost price of a ball?

A. Rs. 43 B. Rs. 60 C. Rs. 55 D. Rs. 34

ANS: Loss = (CP of 17 balls) - (SP of 17 balls) = (CP of 17 balls) - 720

Given that Loss = (CP of 5 balls) => (CP of 17 balls) - 720 = (CP of 5 balls)

=> (CP of 17 balls) - (CP of 5 balls) = 720

=> CP of 12 balls = 720 => CP of 1 ball=720/12=60

Page 16: NUMBER SYSTEM UNITS DIGIT SYSTEM UNITS DIGIT 1. What is the last digit of the number 35^7^9+ 1? A. 1 B. 4 C. 7 D. 3 2. ... 9.Mr. ‘X’ is worried about the balance of his monthly

5. A shopkeeper sells his goods at cost price but uses a weight of 800 gm instead of kilogram

weight. What is his profit percentage?

A. 18% B. 20% C. 25% D. 40%

6. A trader keeps the marked price of an item 35% above its cost price. The percentage of

discount allowed to gain 8% is

A. 27% B. 17% C. 25% D. 20%

Let the Cost Price (CP) = 100, Then Market Price = 100×135/100=135

If he wants to gain 8%, SP = (100+Gain%)/100×CP=(100+8)/100×100=108

Discount %=(135−108)/135×100=2700/135=20

7. The total cost price of two items is 10200/- and their selling price are equal if one of the

two items sold at a loss of 12% and another at a loss of 18% then the cost price of the item

sold at a loss of 18% is?

A. 5100 B. 5280 C. 4920 D. 4329.6

ANS: Let cost prices be x and y

x+ y = 10200 ------------(1)

Selling price when the first item is sold at a loss of 12% = 88x/100

Selling price when the second item is sold at a loss of 18% = 82y/100

88x/100 = 82y/100 => 88x = 82y => x = 41y/44

from eq:(1), 41y/44 + y = 10200 => 41y + 44y = 10200 *44

85y = 10200 *44 => y = 10200 *44/85 = 5280

cost price of the item sold at a loss of 18% = Rs.5280

8. A machine is sold at a loss of 10%. Had it been sold at a profit of 15%, it would have

fetched Rs. 50 more. The cost price of the machine is.

A. Rs. 1000 B. Rs. 500 C. Rs.200 D. Rs.250

ANS: Let us assume cost price of the article is Rs.100x. then selling price = 90x. But if he

sold the product for Rs.50 more his profit is 15%. In this case his selling price is 115x. But

the difference in the selling prices were gives as Rs.50. So 115x - 90x = 50, therefore x =

2. Substituting in cost price, CP = Rs.200

Alternate method:

Difference in two selling prices = 10% - (-15%) = 10% + 15% = 25% of cost price

Actual difference in two selling price = Rs. 50 (i.e. 2 times of 25)

Therefore, Cost Price = 2 x Rs. 100 = Rs. 200

Page 17: NUMBER SYSTEM UNITS DIGIT SYSTEM UNITS DIGIT 1. What is the last digit of the number 35^7^9+ 1? A. 1 B. 4 C. 7 D. 3 2. ... 9.Mr. ‘X’ is worried about the balance of his monthly

9. Goods are purchased for Rs. 450 and one-third is sold at a loss of 10%. At what profit per

cent should the remainder be sold so as to gain 20% on the whole transaction?

A. 30% B. 35% C. 33.33 % D. 25%

ANS: Assume Total cost price of goods = Rs. 450

Our target SP of total goods = 120/100×450=Rs.540

One-third of the goods costs = 450/3 = Rs.150

SP of one-third goods = 90/100×150=Rs.135.

SP of the remaining goods = 540 – 135 = Rs. 405

CP of remaining (two-thirds) goods = Rs. 300

Hence, profit per cent = .105/300×100=35%

Alternate method

Applying weighted average, one-third of quantity there is a loss of 10% (or a profit of –10%)

and balance two-thirds gives a profit of x%.

Hence, overall profit is given by ,1/3(−10%)+2/3(x%)=20% thus x = 35%.

10. A reduction of 10% in the price of sugar enables a man to buy 25 kg more for Rs. 225.

What is the original price of sugar (per kilogram)?

A. Rs.1 B. Rs. 1.5 C. Rs.0.9 D. Rs.2

Let the original price be x. Then Original quantity = 225/x

New price = 90%(x) (if a number reduced by 10% it becomes 90% of the original number)

New quantity = 225/0.9x

Equating 225/0.9x−225/x=25 ⇒x=Rs.1

11. If a merchant makes a profit of 20% after giving a 20% discount, what should be his

mark-up?

A. 20% B. 30% C. 40% D. 50%

Explanatory Answer

Assume cost price = 100.

As profit % = 20%, the profit made after the discount = 20% of 100 = Rs.20

So, selling price = Rs.120.

The merchant makes this profit of 20% after a discount of 20%.

Therefore, he is selling at Marked price - 20% of marked price = 80% of marked price.

i.e., 80% of marked price = Rs.120

of marked price = 120, Or marked price = Or Markup = 50%

Page 18: NUMBER SYSTEM UNITS DIGIT SYSTEM UNITS DIGIT 1. What is the last digit of the number 35^7^9+ 1? A. 1 B. 4 C. 7 D. 3 2. ... 9.Mr. ‘X’ is worried about the balance of his monthly

12. An article is sold at certain price. By selling it at 2/3 of its price one losses 10%, find the

gain at original price?

A. 20% B. 33.33% C.35% D. 40%

Method 1:

Let CP = 100, Loss=10% so, SP=90 then SP * 2/3 = 90

So Actual SP = (90*2)/3 = 135… So 35% is Gain.

Method 2:

Let the original selling price be : x

And now the new selling price is : (2/3) of x = 2x/3 ,& Loss = 10%.

CP=100/90×2x/3 =20x/ 27

But actual it is gain, So Gain = SP-CP , Gain=x−20x/ 27= 7x/ 27

Now find the Gain Percentage: Gain% = 7 20

/ 10027 27

x x = 35%

13. A tradesman sold an article at a loss of 20%.if the selling price has been increased by

Rs100, there would have been a gain of 5%.what was the cost price of the article?

A. 290 B. 350 C.400 D. None of these

Let C.P be Rs x. then (105% of x)-(80 % of x) =100 or 25% of x=100

--->> x/4 = 100 or x=400---->> so, C.P = Rs 400

14. A man sells an article at a profit of 25%if he had bought it 20% less and sold it for Rs

10.50 less, he would have gained 30%find the cost price of the article.

A. 42 B. 57 C.50 D. None of these

Explanation:

Let the C.P be Rs x

1st S.P=125% of x =125x/100=5x/4; 2nd C.P=80% of x=80x/100=4x/5

2nd S.P=130% of 4x/5= (130/100*4x/5) =26x/25

=> 5x/4-26x/25=10.50=> x= (10.50*100)/21=50 Hence C.P= Rs.50

15. A man 2 flats for Rs 675958 each on one he gains 16% while on the other he losses 16%.

How much does he gain/loss in the whole transaction?

A.2.56 % . B. 7.18% C.11.40% D. None of these

Explanation:

In this case there will be always loss. The selling price is immaterial

Hence, loss % = (common loss and gain %) 2 /10= (16/10) %=( 64/25) %=2.56%

16. A man bought a horse and a car ridge for Rs 3000. He sold the horse at a gain of 20%

and the carriage at a loss of 10%, thereby gaining 2% on the whole. Find the cost of the

horse.

Page 19: NUMBER SYSTEM UNITS DIGIT SYSTEM UNITS DIGIT 1. What is the last digit of the number 35^7^9+ 1? A. 1 B. 4 C. 7 D. 3 2. ... 9.Mr. ‘X’ is worried about the balance of his monthly

A. 2000 B. 1500 C. 1300 D.1200

Explanation:

Let the C.P of the horse be Rs. x, then C.P of the carriage =Rs (3000-x)

20% of x-10% of (3000-x) =2% of 3000

==> x/5-(3000-x)/10=60=.2x-3000+x=600=.3x+3600=>x=1200

==> hence, C.P of the horse =Rs 1200

17. Find the single discount equivalent to a series discount of 20%, 10% and 5%

A. 42.60 % B. 57.18% C.68.40% D. None of these

Explanation:

Let the marked price be Rs 100, Then, net S.P=95% of 90% of 80% of Rs 100

= Rs (95/100 * 90/100 * 80/100 *100)= Rs 68.40

18. An uneducated retailer marks all its goods at 50% above the cost price and thinking

that he will still make 25% profit, offers a discount of 25% on the market price. What is the

actual profit on the sales?

A.12.50 % B. 27.8% C.26.5% D. None of these

Explanation:

Let C.P =Rs 100.then, marked price =Rs100

S.P=75% of Rs 150= Rs 112.50

Hence, gain%=12.50%

19. A retailer buys 40 pens at the market price of 36 pens from a wholesaler, if he sells

these pens giving a discount of 1%, what is the profit %?

A. 6 % B. 77.8% C.11% D. None of these

Explanation:

Let the market price of each pen be Rs 1

Then, C.P of 40 pens = Rs 36 S.P of 40 pens =99% of Rs 40=Rs 39.60

profit %=(( 3.60*100)/36) %=10%

0B20. The profit earned after selling an article for Rs 625 is the same as the loss incurred

after selling the article for Rs 435. What is the cost price of the article?

A. 450 B. 480 C. 500 D. 530

ANS: If cost price is x, profit = 625-x, loss = x-435

since, profit = loss , so cost price (x) = Rs 530.

21. By selling 5 articles for Rs.15, a man makes a profit of 20%. Find his gain or loss

percentage if he sells 8 articles for Rs.18.4?

A. 8% Loss B. 8.33% Loss C. 2.22% Loss D. 2.22% Profit

Page 20: NUMBER SYSTEM UNITS DIGIT SYSTEM UNITS DIGIT 1. What is the last digit of the number 35^7^9+ 1? A. 1 B. 4 C. 7 D. 3 2. ... 9.Mr. ‘X’ is worried about the balance of his monthly

22. The Printed price of a calculator is Rs.180. A retailer pays Rs.137.7 for it by getting

successive discounts of 10% and another rate which is illegible. What is the second discount

rate?

A. 12% B.15% C.12.5% D. 20%

Ans: 180*0.9*x=137.7, Solve x=0.85, So 15% Discount…..

23. The profit earned when an article is sold for Rs.800 is 20 times the loss incurred when it

is sold for Rs.275. At what price should the article be sold if it is desired to make a profit of

25%.

A. Rs.300 B. Rs.350 C. Rs.375 Rs.400

24. A sells to B goods at five-thirds the rate of profit at which B has decided to sell it to C.

C, on other hand, sells it to D at one-third the rate of profit at which B sold it to C. If D

gives Rs.2145 to C at 10% profit, how much did A buy it for?.

A. Rs.1000 B. Rs.2000 C. Rs.1500 D. Rs.1800

Exp: (2145*100*100*100)/(110*130*150)= 1000

25. A reduction of 20% in the price of sugar enables a house wife to purchase 6 kg more for

Rs. 240 what is the original price per kg of sugar?

A. 10 kg B. 15 kg C. 25 kg D.30 kg

Explanation:

Let the price per kg of sugar be x

New price = 80x

= 4x

. 100 5

Total price of net sugar purchased = 240

amount of sugar could be purchased at x/kg = 240/x

Now due to reduction amount of sugar can be purchased = 240 × 5

4 x

Difference in both the amount is given i.e. 6 kg

So, 6 = 5 × 240

- 240

4 x x

6 = 240

× 1 .

x 4

x = 10

i.e. original price is Rs. 10/kg

Page 21: NUMBER SYSTEM UNITS DIGIT SYSTEM UNITS DIGIT 1. What is the last digit of the number 35^7^9+ 1? A. 1 B. 4 C. 7 D. 3 2. ... 9.Mr. ‘X’ is worried about the balance of his monthly

CDC Department       Simple Interest & Compound Interest (Questions) SRM University

1. Simple interest on an amount after 36 months at the rate of 3% per quarter is 720. Theamount is A. 4000 B. 2000 C. 6000 D. 4800

2. An amount becomes 8,800 in four years at 15% p.a. What is that amount?A. 5,500 B.7,500 C. 5,800 D. 6,400

3. Amir took a loan of 900 at the rate of 12% per year for 8 months. How much does he needto pay at the end of 8 months? A. 952 B. 852 C. 872 D. 972

4. The simple interest on a sum of money will be 900 after 3 years. In the next 3 years ifprincipal is doubled, then what will be the total interest at the end of the 6th year? A. 900 B. 1800 C. 2700 D. 3600

5. If A lends Rs. 3500 to B at 10% p.a. and B lends the same sum to C at 11.5% p.a., thenthe gain of B (in Rs.) in a period of 3 years is A. Rs. 154.50 B. Rs. 155.50 C. Rs. 156.50 D. Rs. 157.50

6. Ganesh borrowed some money at the rate of 5% p.a. for the first three years, 7% p.a. forthe next 5 years and 9% p.a. for the period beyond eight years. If the total interest paid by him at the end of 14 years is 6240, how much money did he borrow? A. 6300 B. 6180 C. 6200 D. 6000

7. A sum of money becomes 1120 in 4 years and 1360 in 7 years at SI. How much money isdeposited? A. 900 B. 700 C. 800 D. 1200

8. Arun borrows 1500 from two money lenders. He pays interest at the rate of 12% perannum for one loan and at the rate of 14% pa for the other. How much does he borrow at 12% pa if the total interest paid at the end of the year is 186? A. 1200 B. 1125 C. 1250 D. 1800

9. A sum amounts to 3 times itself at SI in 5 years. In what time will it become 5 timesitself? A. 5 years B. 15 years C. 10 years D. 7.5 years

10. What will be the compound interest on 15000 for 2 years at 12% per annum?A. 3604 B. 3816 C. 3836 D. 3800

Page 22: NUMBER SYSTEM UNITS DIGIT SYSTEM UNITS DIGIT 1. What is the last digit of the number 35^7^9+ 1? A. 1 B. 4 C. 7 D. 3 2. ... 9.Mr. ‘X’ is worried about the balance of his monthly

CDC Department       Simple Interest & Compound Interest SRM University

11. Compound interest on a certain amount for 2 years at the rate of 5% is 102.5. Find theamount. A. 500 B. 725 C. 850 D. 1000

12. An amount of 10000 is taken as loan by Ajmal at compound interest charging 8% p.a.for 1st year and 9% p.a. for the 2nd year. How much is the total to be paid by Ajmal after 2 years? A. 16000 B. 14772 C. 12000 D. 11772

13. A sum of 40000 is invested for 18 months at 20% p.a. on compound interest. If theinterest is compounded half yearly, what will be the interest to be paid? A. 13240 B. 13080 C. 13530 D. 13540

14. Rohit has given a loan to Sohit an amount of 20000 at an interest rate 8 % p.a. for aperiod of 30 months. If interest charged is at compound interest, how much does Sohit need to pay in the end? A. 23000 B. 24000.36 C. 24261.12 D. 25020.54

15. A sum of money invested at CI amounts to 800 in 3 years, 882 in 5 years. Find the rateof interest? A. 2.5% B. 5% C. 4% D. 6.66%

16. On a given amount the compound interest at the end of first year was 81 and the secondyear was 88.29. How much money was invested? A. 900 B. 996 C. 880 D. Cannot be determined

17. A sum of 5000 is invested for 3 years at 5% p.a. on compound interest. Income Tax atthe rate of 20% on the interest earned was deducted at the end of each year. The amount at the end of 3rd year? A. 5624.32 B. 5630.50 C. 5620.54 D. 5608.30

18. A sum of money doubles itself at CI in 9 years. In how many years will it become 16times itself? A. 18 years B. 36 years C. 27 years D. 45 years

19. What is the difference between compound interest and simple interest for the sum of20000 over a 2 year period, if CI is calculated at 20% p.a. and SI is calculated at 23% p.a.? A. 200 B. 125 C. 250 D. 400

20. If the difference between the simple interest and compound interest on some amount at10% pa for 3 years is 372, then what must be the principal amount? A. 12400 B. 12000 C. 14800 D. 18000

Page 23: NUMBER SYSTEM UNITS DIGIT SYSTEM UNITS DIGIT 1. What is the last digit of the number 35^7^9+ 1? A. 1 B. 4 C. 7 D. 3 2. ... 9.Mr. ‘X’ is worried about the balance of his monthly

CDC Department              Simple Interest & Compound Interest SRM University   

 

21. The difference between the interests received from two different banks on Rs.500 for 2 years, is Rs.2.50.The difference between their rates is: A. 1% B. 0.5% C. 2.5% D. 0.25% 22. The rate of interest for a sum that becomes 216/125 times of itself in 3 years compounded annually. A. 10% B. 20% C. 15% D. 12% 23. A money lender finds that due to a fall in the rate of interest from 13% to 1212%, his yearly income diminishes by Rs.104. His capital is: A. Rs.21400 B. Rs.20800 C. Rs.22300 D. Rs.24000 24. Rs.2189 are divided into three parts such that their amounts after 1, 2 and 3 years respectively may be equal, the rate of simple interest being 4% p.a.in all cases. The smallest part is : A. Rs.702 B. Rs.597 C. Rs.756 D. Rs.1093 25. A bank offers 5% compound interest calculated on half-yearly basis. A customer deposits Rs. 1600 each on 1st January and 1st July of a year. At the end of the year, the amount he would have gained by way of interest is: A. Rs. 120 B. Rs. 121 C. Rs. 123 D. Rs. 122

Page 24: NUMBER SYSTEM UNITS DIGIT SYSTEM UNITS DIGIT 1. What is the last digit of the number 35^7^9+ 1? A. 1 B. 4 C. 7 D. 3 2. ... 9.Mr. ‘X’ is worried about the balance of his monthly

CDC Department Simple & Compound Interest(Solutions) SRM University

1. Simple interest on an amount after 36 months at the rate of 3% per quarter is 720. The

amount is

1) 4000 2) 2000 3) 6000 4) 4800

Exp:𝑆𝐼 =𝑃𝑅𝑇

100= 720 =

𝑃×3×36

4

100=> 𝑃 = 2000

Note: R is 3% per quarter, so 36 months is 36/4….

2. An amount becomes 8,800 in four years at 15% p.a. What is that amount?

1) 5,500 2)7,500 3) 5,800 4) 6,400

Exp: Amount becomes 8800, So Principal+ SI=8800,

P+SI= 𝑃 +𝑃𝑅𝑇

100= 𝑃 1 +

𝑅𝑇

100 = 𝑃 1 +

4×15

100 = 𝑃 1 +

3

5=

8

5𝑃 = 8800

P=8800×5

8=5500

3. Amir took a loan of 900 at the rate of 12% per year for 8 months. How much does he need

to pay at the end of 8 months?

1) 952 2) 852 3) 872 4) 972

Exp: SI=900×12×

8

12

100= 72 (Time usually calculate per year, so 8 months= 8/12)

Amount paid= Principal+ SI= 900+72=972

4. The simple interest on a sum of money will be 900 after 3 years. In the next 3 years if

principal is doubled, then what will be the total interest at the end of the 6th year?

1) 900 2) 1800 3) 2700 4) 3600

Exp: SI after 3 years 900. We know that SI always constant every year….

After 3rd year the principal is double. So, SI also doubles, then next 3 years 900*2=1800

Total after 6 years 900+1800=2700

5. If A lends Rs. 3500 to B at 10% p.a. and B lends the same sum to C at 11.5% p.a., then

the gain of B (in Rs.) in a period of 3 years is

A. Rs. 154.50 B. Rs. 155.50 C. Rs. 156.50 D. Rs. 157.50

Explanation: We need to calculate the profit of B.

It will be, SI on the rate B lends - SI on the rate B gets

Gain of B=157.50=3500×11.5×3/100−3500×10×3/100

6. Ganesh borrowed some money at the rate of 5% p.a. for the first three years, 7% p.a. for

the next 5 years and 9% p.a. for the period beyond eight years. If the total interest paid by

him at the end of 14 years is 6240, how much money did he borrow?

1) 6300 2) 6180 3) 6200 4) 6000

Exp: 𝑃×5×3

100+

𝑃×7×5

100+

𝑃×9×6

100 = 6240

𝑃15

100+

35

100+

54

100= 6240 => 𝑃 =

6240 × 100

104= 6000

Page 25: NUMBER SYSTEM UNITS DIGIT SYSTEM UNITS DIGIT 1. What is the last digit of the number 35^7^9+ 1? A. 1 B. 4 C. 7 D. 3 2. ... 9.Mr. ‘X’ is worried about the balance of his monthly

CDC Department Simple & Compound Interest SRM University

7. A sum of money becomes 1120 in 4 years and 1360 in 7 years at SI. How much money is

deposited?

1) 900 2) 700 3) 800 4) 1200

Exp: We know that SI always constant every year…

So, Difference 7year – 4 year is 3 year= 1360-1120= 240 is SI of money in 3 years

Then SI for 1 year is 240/3= 80, for 4 years 4*80= 320

A sum of money becomes 1120 in 4 years, Principal = Amount – SI= 1120-320=800

8. Arun borrows 1500 from two money lenders. He pays interest at the rate of 12% per

annum for one loan and at the rate of 14% pa for the other. How much does he borrow at

12% pa if the total interest paid at the end of the year is 186?

1) 1200 2) 1125 3) 1250 4) 1800

Exp: Let assume two amounts is X at 12% and 1500-X at 14%.

𝑆𝐼 =12𝑋

100 and 𝑆𝐼 =

1500−𝑋 14

100= 210 −

14𝑋

100

Total interest is 186= 12𝑋

100+ 210 −

14𝑋

100=

2𝑋

100= 24,𝑋 =

24×100

2= 1200

9. A sum amounts to 3 times itself at SI in 5 years. In what time will it become 5 times

itself?

1) 5 years 2) 15 years 3) 10 years 4) 7.5 years

Exp: Let Principal is P, then Amount =3P in 5 years. So, SI for 5 years is Amount-P= 3P-

P=2P

Then 2P=𝑃×𝑅×5

100, Rate of interest is 40% per year.

So, 5 times means Amount=5P, then SI=4P

Then, 4𝑃 =𝑃×40×𝑇

100, Time =10 years.

Short cut {based on SI only}: Let p=100, Amt=300 in 5 years so SI=200

100 SI=200, Amt=

300

SI= 400,

Amt=500

SI=600, Amt= 700 SI=800, Amt= 900

Principal 5 years 10 years 15 years 20 years

SI is constant value, so it doubles in 5 yr means, 4 times in next 5 yrs.

10. What will be the compound interest on 15000 for 2 years at 12% per annum?

1) 3604 2) 3816 3) 3836 4) 3800

Exp: 𝐶𝐼 = 𝑃(1 + 𝑅/100)𝑛 and CI=Principal + Interest

𝐶𝐼 = 15000(1 +12

100)2 = 15000 × (

112

100)2 = 18816

Then, Interest Amt = 18816-15000=3816

11. Compound interest on a certain amount for 2 years at the rate of 5% is 102.5. Find the

amount.

1) 500 2) 725 3) 850 4) 1000

Page 26: NUMBER SYSTEM UNITS DIGIT SYSTEM UNITS DIGIT 1. What is the last digit of the number 35^7^9+ 1? A. 1 B. 4 C. 7 D. 3 2. ... 9.Mr. ‘X’ is worried about the balance of his monthly

CDC Department Simple & Compound Interest SRM University

Exp: Interest= CI-P=> 𝑃{(1 +5

100)2 − 1} = 102.5

Simplify, P{(1.05×1.05)-1}=102.5 => P(1.1025-1)=102.5

P=102.5/ 0.1025= 1000

12. An amount of 10000 is taken as loan by Ajmal at compound interest charging 8% p.a.

for 1st year and 9% p.a. for the 2nd year. How much is the total to be paid by Ajmal after 2

years?

1) 16000 2) 14772 3) 12000 4) 11772

Exp: CI Amount= 10000(108

100×

109

100) = 11772

13. A sum of 40000 is invested for 18 months at 20% p.a. on compound interest. If the

interest is compounded half yearly, what will be the interest to be paid?

1) 13240 2) 13080 3) 13530 4) 13540

Exp: CI Amt calculate half yearly = P(1 +𝑅/2

100)2𝑛 = 40000(1 +

20/2

100)2(

18

12)

Amount= 53240, interest= 53240-40000= 13240.

14. Rohit has given a loan to Sohit an amount of 20000 at an interest rate 8 % p.a. for a

period of 30 months. If interest charged is at compound interest, how much does Sohit need

to pay in the end?

1) 23000 2) 24000.36 3) 24261.12 4) 25020.54

Exp: 20000 ×108

100×

108

100×

104

100 = 24261.12

(Note: 1 +8

100 =

108

100

For 6 months R= 8/2=4%.... so 104/100

15. A sum of money invested at CI amounts to 800 in 3 years, 882 in 5 years. Find the rate

of interest?

1) 2.5% 2) 5% 3) 4% 4) 6.66%

Exp: 𝑃 1 +𝑅

100

3= 800 → 1. 𝑎𝑛𝑑 𝑃 1 +

𝑅

100

5= 882 → 2.

Solve 2 ÷ 1 => 1 +𝑅

100

2=

882

800=

441

400=

21

20

2 𝑆𝑜,𝐶𝑎𝑛𝑐𝑒𝑙 𝑡ℎ𝑒 𝑠𝑞𝑢𝑎𝑟𝑒 𝑖𝑛 𝑏𝑜𝑡ℎ 𝑠𝑖𝑑𝑒.

100 + 𝑅

100=

21

20 𝑠𝑜𝑙𝑣𝑒 𝑅 = 5%

16. On a given amount the compound interest at the end of first year was 81 and the second

year was 88.29. How much money was invested?

1) 900 2) 996 3) 880 4) Cannot be determined

Exp: 𝑃 1 +𝑅

100

1= 81 → 1. 𝑎𝑛𝑑 𝑃 1 +

𝑅

100

2= 88.29 → 2.

Solve 2÷ 1 => 1 +𝑅

100 =

88.79

81 𝑠𝑜𝑙𝑣𝑒 𝑅 = 9% 𝑝𝑒𝑟 𝑎𝑛𝑛𝑢𝑚.

Page 27: NUMBER SYSTEM UNITS DIGIT SYSTEM UNITS DIGIT 1. What is the last digit of the number 35^7^9+ 1? A. 1 B. 4 C. 7 D. 3 2. ... 9.Mr. ‘X’ is worried about the balance of his monthly

CDC Department Simple & Compound Interest SRM University

Interest on CI for 1 year = 𝑃{ 1 +9

100 − 1} = 81

Solve P=Rs. 900

Note: These kinds of problems go with options…

17. A sum of 5000 is invested for 3 years at 5% p.a. on compound interest. Income Tax at

the rate of 20% on the interest earned was deducted at the end of each year. The amount at

the end of 3rd year?

1) 5624.32 2) 5630.50 3) 5620.54 4) 5608.30

Exp:

Interest for 1 year Tax Amount

5% of 5000= 250 20% of 250=50 250-50=200

5% of 5200= 260 20% of 260=52 260-52=208

5% of 5208= 260.4 20% of 260.4=52.08 260.4-52.08= 208.32

Amount= 5000+ 200+ 208 + 208.32= 5616.32

18. A sum of money doubles itself at CI in 9 years. In how many years will it become 16

times itself?

1) 18 years 2) 36 years 3) 27 years 4) 45 years

Exp: 𝑃 1 +𝑅

100

9= 2𝑃 → 1, 𝑃 1 +

𝑅

100 𝑛

= 16𝑃 → 2

Solve 2÷1=> 1 +𝑅

100 𝑛

÷ 1 +𝑅

100

9=

16

2=

24

2

𝑛

9= 4.𝑆𝑜,𝑛 = 36 𝑦𝑒𝑎𝑟𝑠. {𝑃𝑜𝑤𝑒𝑟 𝑣𝑎𝑙𝑢𝑒𝑠 𝑎𝑟𝑒 𝑒𝑞𝑢𝑎𝑙}

Short cut {based on CI only}: Let P = 100, after 9 years 200. Final amount = 1600

100 200 400 800 1600

Basic 9 years 18 years 27 years 36 years

19. What is the difference between compound interest and simple interest for the sum of

20000 over a 2 year period, if CI is calculated at 20% p.a. and SI is calculated at 23% p.a.?

1) 200 2) 125 3) 250 4) 400

Exp: SI for 2 years, 20000 ×23

100× 2 = 9200

CI for 2 years, 20000 1 +20

100

2= 28800. 𝐼𝑛𝑡𝑒𝑟𝑒𝑠𝑡 𝑖𝑠 8800

Diff is 9200-8800=400

20. If the difference between the simple interest and compound interest on some amount at

10% pa for 3 years is 372, then what must be the principal amount?

1) 12400 2) 12000 3) 14800 4) 18000

Exp: Diff b/w CI & SI is PCI−PSI=P((1+R/100)^n −(1+nR/100))

P{(1 +10

100)3 − (1 +

3×10

100)}= 𝑃{(1.1)3 − 1.3} = 372 => 𝑃(1.331 − 1.3) = 0.031𝑃 = 372

P=372/0.031= 12000

Page 28: NUMBER SYSTEM UNITS DIGIT SYSTEM UNITS DIGIT 1. What is the last digit of the number 35^7^9+ 1? A. 1 B. 4 C. 7 D. 3 2. ... 9.Mr. ‘X’ is worried about the balance of his monthly

CDC Department Simple & Compound Interest SRM University

21. The difference between the interests received from two different banks on Rs.500 for 2

years, is Rs.2.50.The difference between their rates is:

A. 1% B. 0.5% C. 2.5% D. 0.25%

Explanation:

Let the rates be x% and y% . Then, 500×x×2/100 − 500×y×2/100=2.5

⇒10(x-y) =2.5 or x-y = 0.25

22. The rate of interest for a sum that becomes 216/125 times of itself in 3 years

compounded annually.

A. 10% B. 20% C. 15% D. 12%

23. A money lender finds that due to a fall in the rate of interest from 13% to 1212%, his

yearly income diminishes by Rs.104. His capital is:

A. Rs.21400 B. Rs.20800 C. Rs.22300 D. Rs.24000

Explanation: Let capital = Rs. P. Then,

, ,

24. Rs.2189 are divided into three parts such that their amounts after 1, 2 and 3 years

respectively may be equal, the rate of simple interest being 4% p.a.in all cases. The smallest

part is :

A. Rs.702 B. Rs.597 C. Rs.756 D. Rs.1093

Explanation:

Suppose these parts be p, q and [2189-(p+q)], Then,

, p/q = 2 or p = 2q

, q = [2189×12/ 44]=597

The smallest value is Rs.597/-

25. A bank offers 5% compound interest calculated on half-yearly basis. A customer deposits

Rs. 1600 each on 1st January and 1st July of a year. At the end of the year, the amount he

would have gained by way of interest is:

A. Rs. 120 B. Rs. 121 C. Rs. 123 D. Rs. 122

Explanation :

Amount after 1 year on Rs. 1600 (deposited on 1st Jan) at 5% when interest calculated half-

yearly

=P(1+(R/2)/100)2T =1600(1+(5/2)/100)2×1 =1600(1+1/40)2

25113 1 2 104

100 100

PP

13 8104,26 25 104 200

100 100

P PP P

20800P

2189 ( ) 3 41 4 2 4

100 100 100

p qp q

2189 3 3 42 1 444 1289 12

100 100

qqq

Page 29: NUMBER SYSTEM UNITS DIGIT SYSTEM UNITS DIGIT 1. What is the last digit of the number 35^7^9+ 1? A. 1 B. 4 C. 7 D. 3 2. ... 9.Mr. ‘X’ is worried about the balance of his monthly

CDC Department Simple & Compound Interest SRM University

Amount after 1/2 year on Rs. 1600 (deposited on 1st Jul) at 5% when interest calculated

half-yearly

=P(1+(R/2)/100)2T=1600(1+(5/2)/100)2×1/2=1600(1+1/40)

Total Amount after 1 year

=1600(1+1/40)2+1600(1+1/40)=1600(41/40)2+1600(41/40)=1600(41/40)[1+41/40]=1600(41/40)

(81/40)=41×81=Rs. 3321

Compound Interest = Rs.3321 - Rs.3200 = Rs.121


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