NAME: 4U$wc.e ~y

PERIOD:

HOMEWORK 4.1

a. Read pp. 324 - 331b. Review your notes.c. Answer the following:

1. Determine the frequency of an X ray having a wavelength of 1.15 x 10.10 m.

c~;t--v3.007<-/0 8 ~-------=~-

/,/S-,...'O IY/

2. The laser in a compact disc (CD) player uses light with a frequency of3.85 x 1014S·I+.

wavelength in cm.

L-V

Determine the

10 ".3. OO~IO ~.s

3. Determine the speed of an electromagnetic wave that has a frequency of7.80 x 106S'I.

ALL TnA"£L AT n-IE .sP€l:;~ of LlGI4T.

g- M3.00 X to s

4. Determine the energy of an electromagnetic wave that has a frequency of 6.32 x 1020S·I.

E::hv-3'4 ~o )

z: (10.(.,3'1.10 J,s)(fo.3CJ.'tIO s-'

, "UOI. ~ 10-'~ J' = I 'i.19-;~~-::~~r5. Determine the energy of a photon of red light having a frequency of 4.48 x 1014

S·I.

E:: hV:; ((q.~3 '1--10- 3tf ::T. s)( "I, '-If X 10 It{ s .,)

=_ iL()

&q. 10:.pl 'f. 10

z: ~O.:~7J

NAME: AN.sw 8Z K~ Y

PERIOD:

HOMEWORK 4.2

a. Read pp. 330 - 333b. Review your notes.c. Answer the following:

1. List the three characteristic properties that all waves possess.

ArY\ PL.\ T\J~~

FR.E Q lJE N C "(

WI·W~LEtJGn,,",

2. Electromagnetic waves travel at S PeE~ OF' LIGHT in a vacuum.

3. The particle nature of light treats light as being comprised of PHOTO 1'1..5

4. Defme a quantum of energy.

Tl-\E M/tJlW\'\VM AnlOUJ\Jf Ot= Ll6l-1T TH~-r C4N 1.3(5l..O~T Oft. ~Al NeD &""( AAI I:)TOf'f(.

5. Describe the cause of atomic emission spectrum of an element.

f-jN EL£C.TJ2.0Al Tl-lAT I-/I-iS I3£EAJ EXCITED AIJ./:) NOt.) I<..tESt1.)€;-.sAT A HIGI-\G.I<. cNE.RG'f l0/El. R8.f::~ScS TJe/47 l::"'I::.-rl...G.., AJ IT RI::/IJ/CtJ.,J

Tb n40 Gttov,vc ~r~TE:. THIS 'ReSv\.TS .IN ,q,J ATtJW\/C b""t~sro,J $PEc:rx.un..,1=\} t<- 11-+(; I:l-t: ~ OJ. T •

6. State the Heisenberg Uncertainty Principle.

I.T IS I=Ut..lbt\/~EtJY1~1.l.'1 IMPOS~II3LE. ,0 ~f.JOW AeECt~€L""f 10011-1

TI-I€. "!Sl.OC""'I Ao.l~ PoSITIOAJ OF A PRl27ICL£ flT 7J.(G Sil/11G TlI'"1£.

7. Define atomic orbital.

A nta.EE. bll'1~tJSIOtJi~L.. t<tGIOIJ AeOVtJb n-tE NUCLEW

ntAT ~S~I dES n;E U£cr120N l..s R2084t3L£ LOCA7101l1.

~~-.-.'-----""----"'--

NAME: I!AlSwa Kt Y ,

PERIOD:

HOMEWORK 4.3

a. Read pp.331 - 347b. Review your notes.c. Answer the following questions.

I. Write the letter symbol and definition of each of the following quantum numbers:

principal quantum number - (f)') Of..S~\ ~~~ -fl4€. £NE.,I2G. "i LIE" G. L

azimuthalquantumnumber- (~) ~6sc.R.113£.S. -rHE SHAP/E ·OF'TriG oe..el7tiL

magneticquantumnumber- (rY\..t) l::IE-SCR.18ES THE sp,cniAL oe./EN"TAnOA) O~

n-lE Ol<elTAL

spin quantum number- (rYls) DfSCR,t8f,S "T11E,.f)1~CTiOl\,) of SPIN OF iJ,/£ €l£C7110N

2. State each of the following:

Pauli Exclusion Principle - A mA'lC I fllUIl'1 OF TWO €LEc..:,llcJA1S tl14"'1

A1D," I C. C:U~eI'TY'\\..) BoT ONe! :rF nle;O(.lpa!lITt' s(.luJ S •

OCcupy A StAJGlE'

CI..Ecre.ONS f..ft'lvE

Aufbau Principle - £Atll E'LEl..i"20iV oCc.Ufll ES nt€. LoWE:.ST I=1J1::126'f 0Il13. rm«.AVAILA ell:

Hund's Rule - SINGLE ELE.Creo~S f.Vl1"H THE- ~AMf::; SPI;.J. MUST oc.e.UPY

EACH E.qU/~L EAIEJ26'1 ~~nl-\L. i3EF02.E. A.Db ITWI'JA L

ELECr~o/JS wnt·\ OPPOSITe SPoJS mAY OCCupy /He.SAl'\'le OR~ITAt..S.

OVER

3. How many orbital orientations are there in each ofthe following:-""'.

3p- .3

2s-

4p- 33d- 5

4f- 7

4. Write the symbol and name of the element that corresponds to each of the following electronconfigurations:

SILtCOiJ

PoTASStulV/

7/ mIJIU/YI

5. Write the complete electron configuration for:S

Manganese Is ~ ~ S~ ~f (, 3s:' 3f' ;.fs, 2. 3ti

--- - --' _._----------

NAME: AAlSwe:L Kef

PERlOO:

HOMEWORK 4.4

a. Read pp. 331 - 347.b. Review your notes.c. Answer the following:

1. Write the complete electronic configuration for each of the following elements:

Ca I :).;t J. s ;}.;). f c. 3.s d 3f (., I/s.;l

Is.J~.s~ ~f" 3:s0l '.3f~

~I ~3' 1'0'1 '1ISZ.~.s2 J-r" 3$.,) 3pf....,s 0(. I'

-Is (i ;:;$;) ;; f ~3s d Jf (. 1s #) 3d

Si

Se

Ti

2. Write the abbreviated electron configuration for each of the following elements:

Al [Ne] 3s1 'J ,";(1

::< ';~cJ.Ii) ll(),3

As f '\ "j l,!~ 0',-ht'j f

0 Dfe] J.S~Jf' «

Sr l~r'J 5s/.\

2. Construct an orbital diagram for each of the following elements:

S 11.- 1t. '!l1l 2." 1~ '!l: 11

y 7~ 1/; "I~ 1~ 1~ 1~ 1~ 1~ 1~ 1t- 1[, 11t 1lt 1{" 11; '1v 1~ 11t 1'"-- --- ---j)l.. Jsl. :Jf Ie ----- ---sv 3rb tjsz 3d 10 ~!fo 5s'---"

1~ 1t 1~". 1Co 11/ 1l- 1~ 1/; 11t 1~ \

1", 1~1t 1 \--------- 1 1 \ISL --- 1d Idsl J ~ 3s' 3f

fo --- -\f y~1- 3d? ",---CI 1/r 1lt 7{'- 1/r 1£, 7{'- 1/r 1~ 7--Is z. eJs a, dffe --- -3sl. 3 .sr

NAME: ~{ /C:ffPERIOD:

HOMEWORK 4.5Dimensional Analysis

a. Readpp.130-135b. Review your notesc. Answer the following:

KILO HECTO DECA BASE DECI CENTI MILLIUNIT

k h da gram (g) d c m1000 100 10 liter (L) .1 .01 .001103 102 101 meter (m) 10.1 10-2 10-3

Convert the following:

l. 35 mL = .3.5 dL 6. 4500 mg =;f •.s

01:>

2. 950 g = .rso kg 7.25cm= ;?SQ mm

3. 275 mm = d. 7• .5 em 8. 0.005 kg = oS dag

4. 1500 mL = I. S L 9. 0.015 g = /S mg

5.50mm= .0000 S km 10. 0.75 L = 7.50 mL

Using dimensional analysis, perform the following conversions:

I. If I year = 365 days and 1 month = 30 days, determine the number of seconds in 2.00 years.

:<,06 J r 3w sd. c). <f Ju- ~Oll-ll'l &O.sfA 3 07:1.000z:s .:

Ihr- Ime f)Ij , 10< --l.1 ,

~(~.31 ~X!OsfL

2. If 1 Ib = 453.59g, convert 185.0 Ibs to kilograms.

= 8'.3.CjltflS

:) g 3. qj--lj--l~:~-----.~

I LO

OVER

3. The distance from Exit 60 to the intersection ofI-66 and 1-81 is 60.0 mi. If 1 mi = 1.6093 krn; convertthis distance to km.

90,S:5~

z: 1 q~/~ ~~'--"" ---

4. When changing the oil on most cars, the mechanic will use 5.00 quarts of oil. Use the followingconversion factors to express this volume in liters.

1 gal = 4 quarts I L = .264 gal

S 'OO$r _ ...l-' J~~_+-I_L---:-~I L./b t . ;;t(. lrJoJ

- Jj, 7.3 Lf 8'tf i t(Rs

::t L{. 73 LJL .::

5. Determine the mass, in kilograms, of 5.50 bushels of potatoes.

- I

5.So (,I kg = 2.205 Ibs

tk-j

J I .:205 Lh/.50 XIO"'-B )

-----...

I bushel = 60 Ibs

I b

6. For a jet fighter to take off from the deck of an aircraft carrier, it must reach a speed of 62.0 m/s.Express this value in mi/hr.

1 mi = 1.6093 km Ikm = 1000m

s:Is 1000 ••.•

= 138-',t,93i'V;)'

z: ~J« ~ 17. The first measurement of sea depth was made in 1840 in the central South Atlantic, where a plummetwas lowered 2425 fathoms. What is this depth in meters?

1 fathom = 6 feet I foot = 12 inches I inch = 2.54 em 1m = 100 em

:J.«J.5 +J-~ ~t& Id,~ d. St(C'l1. IWJ - Ij~ 3L(.i((WI -:= 1ft 100 ernI I&-It I~

- l4Y'3S~ 1-'~ .

.. -_. _ ...•..__ . ... - ...._----_._-- --_ .._._---- -------_._--_.-.----_._ ... --- ._-------_ .._--_ .._--_ ..... _-