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Objective:Solving Quadratic Equations by Finding Square Roots
This lesson comes from chapter 9.1 from your
textbook, page 503
Quadratic Equations
Standard form: ax2 + bx + c = 0
Find the square root of numbersππ=ΒΏππβππ=ΒΏπ
ββππ=ΒΏ βπ
βπ=ΒΏπββπ=ΒΏπ πππ πππ ππππππ
Find the square root of numbers
βππβππ=ΒΏβππ=π
ββππ+π=ΒΏββπ=βπ
1.
2.
Find the square root of numbers
βπ (π )+ππ=ΒΏβππ=π
βπΒΏΒΏ
1.
2. βππ=π
Find the square root of numbersππ=π
π=Β±π
βππ=βπ
1.
Key ConceptsWhen x2 = d
If d > 0, then x2 = d has two solutions
example:
If d = 0, then x2 = d has one solution
example:
If d < 0, then x2 = d has no real solution
example:
ππ=πππ
ππ=βπ
ππ=π
Find the square root of numbers1. 2. ππ=ππ
π=Β±π
βππ=βππππ=π
π=π
βππ=βπ
Find the square root of numbers1. 2. ππ+π=ππ
π=Β±π
βππ=βππ
βπβπππ=ππ
ππβπ=ππ
π=Β±π
βππ=βππ
+π+πππ=ππ
Find the square root of numbers1. 2. πππ=ππ
π=Β±π
βππ=βππ
ππππ=ππ
πππβπ=ππ
βππ=βππ
ππππ=ππ
+π+ππππ=ππ
π=Β±π
Find the square root of numbers1. 2. πππ+π=ππ
π=Β±πβππ=βππ
ππππ=ππ
βπβππππ=ππ
π ππ+π=ππ
π=Β±π
βππ=βππ
ππππ=ππ
βπβππ ππ=ππ
Real Life: Equation of a falling object
When an object is dropped, the speed with which it falls continues to increase. Ignoring air resistance, its height h can be approximated by the falling object model.
sth 216h is the ending height in feet above the groundt is the number of seconds the object has been fallings is the starting height from which the object was dropped
Application
Sarah is going to drop a water balloon from a height of 144 feet. To the nearest tenth of a second, about how long will it take for the balloon to hit the ground? Assume there is no air resistance.
The question asks to find the time it takes for the container to hit the ground.
Initial height (s) = 144 feet
Height when its ground (h) = 0 feet
Time it takes to hit ground (t) = unknown
sth 216
Substitutesth 216
π=βππππ+πππ
3 sec.
βπ=βππ
βππβππ
βπππβπππβπππ=βππππ
π=ππ
Substitutesth 216
π=βππππ+πππ
4.24 sec.
βππ=βππ
βππβππ
βπππβπππβπππ=βππππ
ππ=ππ
Find the square root of numbers1. 2. πππβπ=π
π=Β±πβππ=βπ
ππππ=π
+π+ππππ=π
πππ+π=ππβπβππππ=ππππππ=πβππ=βπ
π=Β±π
Application
An engineering student is in an βegg dropping contest.β The goal is to create a container for an egg so it can be dropped from a height of 32 feet without breaking the egg. To the nearest tenth of a second, about how long will it take for the eggβs container to hit the ground? Assume there is no air resistance.
The question asks to find the time it takes for the container to hit the ground.
Initial height (s) = 32 feet
Height when its ground (h) = 0 feet
Time it takes to hit ground (t) = unknown
sth 216
Substitutesth 216
π=βππππ+ππ
Approximately 1.4 sec.
βπ=βππ
βππβππ
βππβππβππ=βππππ
π=ππ
Evaluate a Radical Expression
βππβπππ=β(βπ)πβπ(π)(βπ)=βπβπ(βπ)
βπ+ππ=βππ=π
Perfect Squares: Numbers whose square roots are integers or quotients of integers.
1316912144
1112110100
981864749
636525416
392411
What is a square root?
If a number square (b2) = another number (a), then b is the square root of a.
Example: If 32 = 9, then 3 is the square root of 9
Quadratic Equations
Standard form: ax2 + bx + c = 0a is the leading coefficient and cannot be equal to zero.If the value of b were equal to zero, the equation becomes ax2 + c = 0.We can solve equations is this form by taking the square root of both sides.
Some basicsβ¦
All positive numbers have two square rootsThe 1st is a positive square root, or principal square root.The 2nd is a negative square rootSquare roots are written with a radical symbol You can show both square roots by using the βplus-minusβ symbol Β±