OCE421 Marine Structure Designs
Lecture #19 (Wave Forces on Vertical Cylinder)
Definition Sketch
d z
z
x
f = f i +fd
1
=cm½¼D2
4dudt
+cd2
½D ujuj
2
f i dz
1
fddz
2
d
z = 0
z = -d
Morison Equation
f i =
fd =
½=
D =
u =dudt =
cm; cd =
1
f = f i +fd
1
=cm½¼D2
4dudt
+cd2
½D ujuj
2
inertia force per unit length of pile
drag force per unit length of pile
density of fluid (1025 kg/m3 for sea water)
diameter of pile
horizontal water particle velocity at the axis of the pile
horizontal water particle acceleration at the axis of the pile
inertia (mass) and drag coefficient, respectively
horizontal force per unit length of a vertical cylindrical pile
Usage of Morison Equation
Morison's equation is valid for all ratios of pile diameter to wave length:
Given d, H andT, which wave theory should be used?
For a particular wave condition, what are appropriate values of cd and cm?
Two problems:
DL
<120
1
Drag and Inertia Coefficients
• Drag coefficients to be used in Morison's equation can only be obtained experimentally.
• In theory, the value of the inertia coefficient can be calculated (2.0 for a smooth cylinder in an ideal fluid). However, measured values are used in practice, particularly when drag is the dominant force.
• One problem facing the user of Morison's equation is the larger scatter in values of the inertia and drag coefficients.
• There is a useful degree of correlation between the coefficients and two flow parameters: Keulegan-Carpenter number and Reynolds number.
K-C & Reynolds Number
K =UmTD
1
velocity amplitude of the flow
period of the flow
diameter of pile
Re=UmD
º
1
Um =
T =
D =
º =
2
kinematic viscosity (approximately 10-5 ft2/sec for sea water).
Reynolds numberKeulegan-Carpenter number
Inertia & Drag Coefficients (API,1980)
• Engineering practice is simply to assume them constant, with the values of the drag coefficient chosen within the range 0.6 to 1.0 and the values of the inertia coefficient within the range 1.5 to 2.0 (API,1980)
Linear Wave Theory
wave elevation
´ =H2
cos(kx ¡ ¾t)
@2Á@t2
+g@Á@z
=0 at z =0
¾2=gktanhkd
7
u=@Á@x
=¼HT
coshk(d+z)sinhkd
cos(kx ¡ ¾t)
1
horizontal water particle velocity
Horizontal Acceleration
ax =@u@x
dxdt
+@u@z
dzdt| {z }
+@u@t|{z}
3
convective acceleration
local acceleration
ax =u@u@x
+w@u@z
+@u@t
4
u(x;z;t)
2
Note:ax =dudt
1
for small wave steepness
ax ¼@u@t
=2¼2HT2
coshk(d+z)sinhkd
sin(kx¡ ¾t)
1
Horizontal Force & Moment
F =Z ´
¡ df i dz+
Z ´
¡ dfddz
1
=Fi +Fd
2
horizontal force (F)
moment about the mud line (M)
M =Z ´
¡ d(z+d)f i dz+
Z ´
¡ d(z+d)fddz
3
=M i +Md
4
Fi =³ ¼cm
4½gD2H
´K i
1
Fd =³ cd
2½gDH2
´K d
2
M i =(Fi d) Si
Md =(Fd d) Sd
3
M i =(Fi d) Si
Md =(Fd d) Sd
3
dimensionless
Horizontal Force & Moment (contd.)
If the upper limit of integration is zero instead of andlinear wave theory is used, analytical expression ofKi , Kd , Si , Sd can be obtained (SPM Eq. 7-33 ~ 7-36)
F =Z ´
¡ df i dz+
Z ´
¡ dfddz
1
M =Z ´
¡ d(z+d)f i dz+
Z ´
¡ d(z+d)fddz
3
0 (still water level)
Maximum Forces & Moments
Fi;max =³ ¼cm
4½gD2H
´K i;max
1
Fd;max =³ cd
2½gDH2
´K d;max
2
M i;max =¡Fi;max d
¢Si;max
Md;max =¡Fd;max d
¢Sd;max
3
Using Dean's stream-function theory, graphs [SPM: Fig. (7-71) through Fig. (7-74)] have been prepared and may be used to obtain
K i;max, K d;max, M i;max andMd;max
1
maximum inertia force
maximum drag force
SPM: Fig. (7-71)K i;max vs. d=gT2, for H=Hb=0, 1/4, 1/2, 3/4and1.
1
Maximum Total Forces/Moments
maximum total force
maximum total moment
Fmax =Ám
³½gcdH
2D´
1
Mmax =®m
³½gcdH
2Dd´
2
Ám and®m arefunctionsofd
gT2
HgT2
¯ =cmcd
DH
3
Ám and®m arefunctionsofd
gT2
HgT2
¯ =cmcd
DH
3
Ám and®m arefunctionsofd
gT2
HgT2
¯ =cmcd
DH
3
Ám and®m arefunctionsofd
gT2
HgT2
¯ =cmcd
DH
3
relative depth
wave steepness
inertia-drag ratio index
SPM: Fig. (7-76)
Isolinesof Ám vs. H=gT2andd=gT2, for ¯ =0:05.
1
Figs. (7-77) through (7-79) arefor ¯ =0.1, 0.5and1.
1
SPM: Fig. (7-80)Isolinesof ®m vs. H=gT2andd=gT2, for ¯ =0:05.
1
Figs. (7-81) through (7-84) arefor ¯ =0.1, 0.5and1.
2
Example Problem: SPM, p. 7-127
• A design wave with height H=3 m and period T=10 s acts on a vertical circular pile with a parameter D=0.3 m in depth d=4.5 m. Assume that cm=2, cd= 0.7, and the density of seawater =1025.2 kg/m3.
Find: The maximum total horizontal force and the maximum total moment around the mud line of the pile.
Transverse Forces (Lift Forces)
• Transverse forces result from vortex or eddy shedding on the downstream side of a pile.
• Transverse forces were found to depend on the dynamic response of the structure.
• For rigid structures, transverse forces equal to the drag force is a reasonable upper limit.
• Eddies are shed at a frequency that is twice the wave frequency
Design Estimates of Lift Force
SPM’s recommendation for design lift force:
FL =FL;maxcos(2µ)
1
=³ cL
2½gDH2
´K d;maxcos(2µ)
2
cL =
3
empirical lift coefficient (analogous to the drag coefficient)
K =umaxT
D
4
maximum horizontal velocity (velocity amplitude) averaged over the depth
umax =12
£(umax)bottom+(umax)swl
¤
5
Example Problem: SPM, p. 7-133
• A design wave with height H=3 m and period T=10 s acts on a vertical circular pile with a parameter D=0.3 m in depth d=4.5 m. Assume that cm=2, cd= 0.7, and the density of seawater =1025.2 kg/m3.
Find: The maximum transverse (lift) force acting on the pile and the approximate time variation of the transverse force assuming that Airy theory adequately predicts the velocity field. Also estimate the maximum total force.