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Oct. 29, 2012
AGENDA:1 – Bell Ringer2 – Kinematics
Equations3 – Exit Ticket
Today’s Goal:Students will be able to identify which kinematic equation to apply in each situationHomework
1. Pages 4-5
CHAMPS for Bell Ringer
C – Conversation – No Talking H – Help – RAISE HAND for questionsA – Activity – Solve Bell Ringer on
binder paper. Homework out on desk
M – Materials and Movement – Pen/Pencil, Notebook or Paper
P – Participation – Be in assigned seats, work silently
S – Success – Get a stamp! I will collect!
October 29th (p. 13)
Objective: Students will be able to identify which kinematic equation to apply in each situation
Bell Ringer:Let’s say two people are
racing:The first person has a large
initialvelocity (20 m/s) but a slowacceleration (1 m/s2).
The other has a small initialvelocity (0 m/s) but a largeAcceleration (5 m/s2).Who will win the race and
why?
4 MINUTES REMAINING…
October 29th (p. 13)
Objective: Students will be able to identify which kinematic equation to apply in each situation
Bell Ringer:Let’s say two people are
racing:The first person has a large
initialvelocity (20 m/s) but a slowacceleration (1 m/s2).
The other has a small initialvelocity (0 m/s) but a largeAcceleration (5 m/s2).Who will win the race and
why?
3 MINUTES REMAINING…
October 29th (p. 13)
Objective: Students will be able to identify which kinematic equation to apply in each situation
Bell Ringer:Let’s say two people are
racing:The first person has a large
initialvelocity (20 m/s) but a slowacceleration (1 m/s2).
The other has a small initialvelocity (0 m/s) but a largeAcceleration (5 m/s2).Who will win the race and
why?
2 MINUTES REMAINING…
October 29th (p. 13)
Objective: Students will be able to identify which kinematic equation to apply in each situation
Bell Ringer:Let’s say two people are
racing:The first person has a large
initialvelocity (20 m/s) but a slowacceleration (1 m/s2).
The other has a small initialvelocity (0 m/s) but a largeAcceleration (5 m/s2).Who will win the race and
why?
1minute Remaining…
October 29th (p. 13)
Objective: Students will be able to identify which kinematic equation to apply in each situation
Bell Ringer:Let’s say two people are
racing:The first person has a large
initialvelocity (20 m/s) but a slowacceleration (1 m/s2).
The other has a small initialvelocity (0 m/s) but a largeAcceleration (5 m/s2).Who will win the race and
why?
30 Seconds Remaining…
October 29th (p. 13)
Objective: Students will be able to identify which kinematic equation to apply in each situation
Bell Ringer:Let’s say two people are
racing:The first person has a large
initialvelocity (20 m/s) but a slowacceleration (1 m/s2).
The other has a small initialvelocity (0 m/s) but a largeAcceleration (5 m/s2).Who will win the race and
why?
BELL-RINGER TIME IS
UP!
October 29th (p. 13)
Objective: Students will be able to identify which kinematic equation to apply in each situation
Bell Ringer:Let’s say two people are
racing:The first person has a large
initialvelocity (20 m/s) but a slowacceleration (1 m/s2).
The other has a small initialvelocity (0 m/s) but a largeAcceleration (5 m/s2).Who will win the race and
why?
Shout Outs
Period 5 –Period 7 –
Oct. 29, 2012
AGENDA:1 – Bell Ringer2 – Kinematics
Equations3 – Exit Ticket
Today’s Goal:Students will be able to identify which kinematic equation to apply in each situationHomework
1. Pages 4-5
Week 8
Weekly AgendaMonday – Kinematic Equations ITuesday – Kinematic Equations IIWednesday – Kinematic Equations
IIIThursday – ReviewFriday – Review
Unit Test in 2 weeks!
CHAMPS for Problems p. 4-6
C – Conversation – No Talking unless directed to work in groups
H – Help – RAISE HAND for questionsA – Activity – Solve Problems on Page
4-6M – Materials and Movement –
Pen/Pencil, Packet Pages 4-6P – Participation – Complete Page 4-6S – Success – Understand all
Problems
Notes: Kinematic Equations
The Four Kinematic Equations:vf = vi + aΔt
Δx = viΔt + aΔt2
2vf
2 = vi2 + 2aΔx
Δx = (vf + vi)Δt 2
Solving Kinematics Problems
Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.
Solving Kinematics Problems
Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.
Solving Problems (p. 4)
1. Starting from rest, the Road Runner accelerates at 3 m/s2 for ten seconds. What is the final velocity of the Road Runner?
Solving Problems (p. 4)
1. Starting from rest, the Road Runner accelerates at 3 m/s2 for ten seconds. What is the final velocity of the Road Runner?
Solving Kinematics Problems
Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.
Solving Problems (p. 4)
1. Starting from rest, the Road Runner accelerates at 3 m/s2 for ten seconds. What is the final velocity of the Road Runner?
Solving Problems (p. 4)
1. Starting from rest, the Road Runner accelerates at 3 m/s2 for ten seconds. What is the final velocity of the Road Runner?
vi = 0 m/sa = 3 m/s2
Δt = 10 seconds
Solving Kinematics Problems
Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.
Solving Problems (p. 4)
1. Starting from rest, the Road Runner accelerates at 3 m/s2 for ten seconds. What is the final velocity of the Road Runner?
vi = 0 m/sa = 3 m/s2
Δt = 10 seconds
Solving Problems (p. 4)
1. Starting from rest, the Road Runner accelerates at 3 m/s2 for ten seconds. What is the final velocity of the Road Runner?
vi = 0 m/sa = 3 m/s2
Δt = 10 seconds
vf = ?
Solving Kinematics Problems
Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.
Notes: Kinematic Equations
The Four Kinematic Equations:vf = vi + aΔt
Δx = viΔt + aΔt2
2vf
2 = vi2 + 2aΔx
Δx = (vf + vi)Δt 2
Notes: Kinematic Equations
The Four Kinematic Equations:vf = vi + aΔt
Δx = viΔt + aΔt2
2vf
2 = vi2 + 2aΔx
Δx = (vf + vi)Δt 2
Solving Problems (p. 4)
2. Starting from rest, the Road Runner accelerates at 3 m/s2 for ten seconds. How far does the Road Runner travel during the ten second time interval?
Solving Kinematics Problems
Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.
Solving Problems (p. 4)
2. Starting from rest, the Road Runner accelerates at 3 m/s2 for ten seconds. How far does the Road Runner travel during the ten second time interval?
Solving Kinematics Problems
Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.
Solving Problems (p. 4)
2. Starting from rest, the Road Runner accelerates at 3 m/s2 for ten seconds. How far does the Road Runner travel during the ten second time interval?
Solving Problems (p. 4)
2. Starting from rest, the Road Runner accelerates at 3 m/s2 for ten seconds. How far does the Road Runner travel during the ten second time interval?
vi = 0 m/sa = 3 m/s2
Δt = 10 seconds
Solving Kinematics Problems
Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.
Solving Problems (p. 4)
2. Starting from rest, the Road Runner accelerates at 3 m/s2 for ten seconds. How far does the Road Runner travel during the ten second time interval?
vi = 0 m/sa = 3 m/s2
Δt = 10 seconds
Solving Problems (p. 4)
2. Starting from rest, the Road Runner accelerates at 3 m/s2 for ten seconds. How far does the Road Runner travel during the ten second time interval?
vi = 0 m/sa = 3 m/s2
Δt = 10 seconds
Δx = ?
Solving Kinematics Problems
Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.
Notes: Kinematic Equations
The Four Kinematic Equations:vf = vi + aΔt
Δx = viΔt + aΔt2
2vf
2 = vi2 + 2aΔx
Δx = (vf + vi)Δt 2
Notes: Kinematic Equations
The Four Kinematic Equations:vf = vi + aΔt
Δx = viΔt + aΔt2
2vf
2 = vi2 + 2aΔx
Δx = (vf + vi)Δt 2
Solving Problems (p. 4)
3. A bullet starting from rest accelerates at 40,000 m/s2 down a 0.5 m long barrel. What is the velocity of the bullet as it leaves the barrel of the gun?
Solving Kinematics Problems
Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.
Solving Problems (p. 4)
3. A bullet starting from rest accelerates at 40,000 m/s2 down a 0.5 m long barrel. What is the velocity of the bullet as it leaves the barrel of the gun?
Solving Kinematics Problems
Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.
Solving Problems (p. 4)
3. A bullet starting from rest accelerates at 40,000 m/s2 down a 0.5 m long barrel. What is the velocity of the bullet as it leaves the barrel of the gun?
Solving Problems (p. 4)
3. A bullet starting from rest accelerates at 40,000 m/s2 down a 0.5 m long barrel. What is the velocity of the bullet as it leaves the barrel of the gun?
vi = 0 m/sa = 40,000 m/s2
Δx = 0.5 m
Solving Kinematics Problems
Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.
Solving Problems (p. 4)
3. A bullet starting from rest accelerates at 40,000 m/s2 down a 0.5 m long barrel. What is the velocity of the bullet as it leaves the barrel of the gun?
vi = 0 m/sa = 40,000 m/s2
Δx = 0.5 m
Solving Problems (p. 4)
3. A bullet starting from rest accelerates at 40,000 m/s2 down a 0.5 m long barrel. What is the velocity of the bullet as it leaves the barrel of the gun?
vi = 0 m/sa = 40,000 m/s2
Δx = 0.5 m
vf = ?
Solving Kinematics Problems
Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.
Solving Problems (p. 4)
3. A bullet starting from rest accelerates at 40,000 m/s2 down a 0.5 m long barrel. What is the velocity of the bullet as it leaves the barrel of the gun?
vi = 0 m/sa = 40,000 m/s2
Δx = 0.5 m
vf = ?
Notes: Kinematic Equations
The Four Kinematic Equations:vf = vi + aΔt
Δx = viΔt + aΔt2
2vf
2 = vi2 + 2aΔx
Δx = (vf + vi)Δt 2
Notes: Kinematic Equations
The Four Kinematic Equations:vf = vi + aΔt
Δx = viΔt + aΔt2
2vf
2 = vi2 + 2aΔx
Δx = (vf + vi)Δt 2
Solving Problems (p. 4)
4. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. What is the acceleration of the car?
Solving Kinematics Problems
Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.
Solving Problems (p. 4)
4. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. What is the acceleration of the car?
Solving Kinematics Problems
Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.
Solving Problems (p. 4)
4. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. What is the acceleration of the car?
Solving Problems (p. 4)
4. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. What is the acceleration of the car?
vi = 20 m/svf = 0 m/sΔt = 4 seconds
Solving Kinematics Problems
Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.
Solving Problems (p. 4)
4. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. What is the acceleration of the car?
vi = 20 m/svf = 0 m/sΔt = 4 seconds
Solving Problems (p. 4)
4. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. What is the acceleration of the car?
vi = 20 m/svf = 0 m/sΔt = 4 seconds
a = ?
Solving Kinematics Problems
Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.
Solving Problems (p. 4)
4. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. What is the acceleration of the car?
vi = 20 m/svf = 0 m/sΔt = 4 seconds
a = ?
Notes: Kinematic Equations
The Four Kinematic Equations:vf = vi + aΔt
Δx = viΔt + aΔt2
2vf
2 = vi2 + 2aΔx
Δx = (vf + vi)Δt 2
Notes: Kinematic Equations
The Four Kinematic Equations:vf = vi + aΔt
Δx = viΔt + aΔt2
2vf
2 = vi2 + 2aΔx
Δx = (vf + vi)Δt 2
Solving Problems (p. 5)
5. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. How far does the car travel before coming to a stop?
Solving Kinematics Problems
Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.
Solving Problems (p. 5)
5. A car traveling at 20 m/s applies its brakes and comes to a stop in four seconds. How far does the car travel before coming to a stop?
Solving Kinematics Problems
Step 1: Read the Problem, underline key quantitiesStep 2: Assign key quantities a variableStep 3: Identify the missing variableStep 4: Choose the pertinent equation:Step 5: Solve for the missing variable.Step 6: Substitute and solve.
Solving Problems (p. 5)
6. The USS Enterprise accelerates from rest at 100,000 m/s2 for a time of four seconds. How far did the ship travel in that time?
Exit Ticket (p. 14)
12, Calvin tosses a water balloon to Hobbes. As Hobbes is about to catch it the balloon has a speed of 1 m/s. Hobbes catches the balloon, and the balloon experiences an acceleration of -0.5 m/s2 as it comes to rest. How far did Hobbes' hands move back while catching the balloon?
Write the given variables, the missing variable, and the equation you will use.