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Operational Amplifier(Phe-10) (1)

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Differential Amplifiers
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Differential Amplifiers

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Two matched transistors form a

differential amplifier

input

 

0 V

-V EE +0.7 VConstantcurrent= I 1+I 2 

I 1  I 2 

V C 1=V CC -I 1R 2  V C 2=V CC -I 2R 4 

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Transisterized

Differential AmplifierDouble endedinput - double

ended outputdiff. amp:

v out =A (v 1-v 2)v 1  v 2 

v out 

- +

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● Single endedoutput

Non-inverting

input

Invertinginput

Single Ended Differential Amplifier (commonly used in op-amps)

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Op Amp stages with pin-outs of IC741

2

4

7

6

3

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Op amp Voltage Level Detector

V OUT  +

-V REF  

V IN  = +V SAT  for V IN >V REF 

= -V SAT  for V IN <V REF 

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Important features of Op Amp1. High open loop gain (ideally infinite)

which implies that even the smallest

difference between the two inputsresults into saturated output voltage

2. High input impedance (ideally infinite)

implies that there is no currentflowing into the input of an op amp

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Virtual GroundThese two conditions give rise to VIRTUALGROUND, where the voltages at both theinputs are maintained at exactly same level. 

To achieve this condition, a feedback circuitbetween the output and the inverting inputterminal of the op amp is necessary.

This results into many applications of op amp,which qualify it to be OPERATIONAL: adder, subtractor, multiplier, divider etc.

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Op amp Applications

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IntroductionThe operational amplifier or op-amp is acircuit of components integrated into one chip.

 A typical op-amp is powered by two dc voltages and has an inverting(-) and a non-inverting input (+) and an output.

 An op amp is an electronic device which provides a voltage output based on the voltageinput 

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Basic op-amp

Op-amp has two inputs that connect to two terminal and one output 

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Operational Amplifiers

• The output of the op amp is given by the following equation:

Vd = E1  – E2

and Vo = AVOL(Vd)

• AVOL is called the open-loop voltage gain because itis the gain of the op amp without any external feedback fromoutput to input

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What do they really look like?

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IC Circuit

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Operational Amplifiers

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Operational Amplifiers An ideal op-amp has infinite gain and 

bandwidth , we know this is impossible.

However, op-amps do have:

very high gain

very high input impedance(Z in = ∞) 

very low output impedance (Z out = 0)

wide bandwidth.

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Application in op-amp

• There are 2 types of application in op-amp

 – Linear application

 – Non-linear application

• Linear application is where the op-amp operate in linearregion:

 – Assumptions in linear application:

• Input current, Ii = 0

• Input voltage: V+=V-

• Feedback at the inverting input

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• Non-linear application is where the op-amp operate innon-linear region

• By comparing these two input voltages: positive inputvoltages, V+ and negative input voltage, V- where:

VO = VCC if V+ > V-

VO = -VEE if V+ < V- 

• Input current, Ii = 0

Application in op-amp

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Summary of op-amp behavior

V o = A(V + - V   )

V o /A = V + - V   

Let  A infinity 

then,

V +

- V   

0

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V + = V   

 I + = I  = 0

Seems strange, but the input terminals to anop-amp act as a short and open at the same time

Summary of op-ampbehavior

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To analyze an op-amp circuit for linearoperation

•Write node equations at + and - terminals

(I i =I + = I - = 0)

•Set V + = V -

Solve for V o

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Analysis of inverting amplifier

I 1

I f 

I i 

V  0 I i 0

 I 1

I  f  I i

V  s V 

 R1

V  V o

 R f 

V  V  0

V o

V  s

R f 

 R1

V o

R f 

 R1

V  s

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Application:Non-invertingamplifier

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Non-inverting configuration

 

 

 

 

1

2

21

21

21

1

0;

0:

;0

:

 R

 R

V V 

 R

V V 

 R

V V V insert 

 R

V V 

 R

V so

 I while I  I  I 

KCLuse

V V V 

io

oiii

o

i

i

i

Vi

 I 1

 I 2

 I i

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Summing Amplifier

V 1

V 2

V 3

 R1

 R2

 R3

 R f 

This circuit is call 

a weighted summe 

 

 

 

 

3

3

2

2

1

1

3

3

2

2

1

1

3

3

2

2

1

1

321

;0

:

;0

:

0

 R

 R

 R

 RV 

 R

 R

 R

 R

V V insert 

 R

V V 

 R

V V 

 R

V V 

 R

V V so

 I while

 I  I  I  I  I 

KCLuse

V V 

 f o

 f 

o

 f 

o

i

 Rf i R R R

A li ti U it F ll (P ik t

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Application: Unity Follower(PengikutVoltan)

1V V 

O

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Exercise 1

Find V O ? 

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Exercise 2

Find V 2 and V 3 ? 

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Exercise 3

Find V O ? 

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Exercise 4

Find V O ? 

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Application:Difference amplifier

)(21

2

4V V 

 R

 RV O

43

21

 R R

 R R

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Application:Instrumentation Amplifier

2 R

Buffer (Penimbal)

2 R

1 R

1 R

 A R

 B R

 A R

Difference amplifier 

12

1

22

1 V V  R

 R

 R

 RV 

 B

 A

O

 

  

 

2 R

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Application:Integrator

 Feedback component = capacitor : Integrator

 I I C 

dt t v RC 

t v

dt 

t dvC 

 R

t v

 I  I  I 

io

i

C i

)(1

)(

)(0

)(0

sC

1

C j

1X

:impedancecetanCapaci

C

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Application:Differentiation

dt 

t dv RC t v

 Rt vV 

dt t dvC 

 I  I 

io

oi

 RC 

)()(

)()(

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• Non-linear application is where the op-amp operate innon-linear region

• By comparing these two input voltages: positive inputvoltages, V+ and negative input voltage, V- where:

VO = VCC if V+ > V-

VO = -VCC if V+ < V- 

• Input current, Ii = 0

Recall: Non-linear application in op-amp

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Non-linear application:Comparator

N li li ti

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Non-linear application:Comparator

V o (V)

10 

-5 

V S (V)

Compare V + and V -

V +=0

V -=V S 

When:V S >0,V +>V - so V o=10V V S <0,V +<V -  so V o=-5V  (b) Output Voltage of Comparator 

(a) Input Voltage of Comparator 

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Non-linear applicationSchmitt Trigger

O

 f 

V  R R

 RV 

1

1

Positive Feedback 

N li li ti

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V V 

V t V V and V V stateinitialwith

V V V and  R Rassume

V  R R

 RV 

S

o

 EE CC  f 

O

 f 

5.7)15(2

1

sin1015

151

1

1

 

Non-linear applicationSchmitt Trigger

V o (V)

15 

-15 

V S (V)

7.5 

-7.5 

V o (V)

V S (V)-7.5 7.5 -10 10 

15 

-15 

(a) Transfer Characteristic of Schmitt Trigger 

(c) Output Voltage of Schmitt Trigger 

(b) Input Voltage of Schmitt Trigger 

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Common Mode Rejection Ratio

(CMRR)• It is the ability of an op amp to reject the

signal which is present at its both inputssimultaneously i.e. the common modesignal

• CMRR = AOL / ACM , where ACM is commonmode voltage gain defined by V out  / V CM  

• Ideally CMRR is infinite• For IC 741 it is 90 dB

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Slew Rate

• Maximum rate of change of outputvoltage (when typically a step voltage isgiven at the input terminal)

StepInput

V out  

dV out  / dt 

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Slew Rate (cont…) 

• Slew rate is caused by the finite responsetime of the circuit elements of an op amp

• It limits the highest possible frequency ofoperation

V in  

V out 

ExpectedVoltage

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Input Offset Voltage 

• Small voltage needed to be appliedbetween INV and NI terminals to getzero output voltage

• Ideally it should be 0 V (CM operation)

Output Offset Voltage • Under common mode operation, output

voltage should be zero, but due to

mismatch is devices it is non-zero(Can be corrected by applying voltagebetween Pins 1 and 5 of IC 741)


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