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Oxidation-Reduction Reactions
Oxidation and ReductionOxidation-reduction reactions always occur
simultaneoulsy.Redox Reactions
OxidationLoss of electrons Gain oxygen
2Fe2O3 + 3C2 4Fe + 3CO2
Reduced Oxizided
ReductionGain ElectronsLoss of Oxygen
Redox Reactions that Form IonsBetween metal and nonmetals, electrons are
transferred from the metal to the nonmetal.Increases stabilityMg + S Mg2+ + S2-
Oxidation: Mg Mg2+ + 2e- (loss of electrons)Reduction: S + 2e- S2- (gain of electrons)
Oxidizing and Reducing AgentsReducing Agent: substance that loses
electrons.Oxidizing Agent: substance that accepts the
electrons is the oxidizing agent.Mg + S Mg2+ + S2-
Mg: reducing agent, oxidizedS: oxidizing agent, reduced
LEO the lion goes GERLEO: Losing Electrons is OxidationGER: Gaining Electrons is Reduction
Redox with Covalent CompoundsIn covalent compounds, polar molecules
involve unequal sharing of electronsThe shift in electrons is redox for it is the
partial gain and loss of electronsH2OOxygen: electrons shift toward
Reduced, oxidizing agentHydrogen: electrons shift away
Oxidized, reducing agent
Processes Leading to RedoxOxidation
Complete loss of electrons (ionic reactions)
Shift of electrons away from an atom in covalent bond
Gain of OxygenLoss of Hydrogen by a
covalent compoundIncrease in oxidation
number
ReductionComplete gain of
electrons (ionic reactions)
Shift of electrons toward from an atom in covalent bond
Loss of OxygenGain of Hydrogen by a
covalent compoundDecrease in oxidation
number
CorrosionIron, corrodes by being oxidized to ions of
iorn by oxgyen2Fe +O2 + H2O 2Fe(OH)2
To protect iron, a piece of magnesium is placed in electrical contact.
When oxygen or water attack the iron object, iron lose electrons.
Because Mg is more easily oxidized, the Mg immediately transfers electrons to the iron, preventing their oxidation to iron ions.
Oxidation Numbers
Oxidation NumbersA positive or negative number assigned to an
atom to indicate its degree of oxidation or reduction.
Rule of Thumb: when bonded, the oxidation number is the same as its ionic charge.
In a chemical reaction:Increase in oxidation number oxidationDecrease in oxidation number reduction
Rules for Assigning Oxidation NumbersMonatomic ions equal ionic charge; Br1-: -1H: compounds is +1; metal hydrides is -1
H2O: +1, NaH: -1
O: compounds is -2; peroxides is -1, or in compounds with F it’s +H2O: -2, H2O2: -1
Atoms in elemental form or diatomic is 0.S: 0, H2: 0
For compound, the sum of oxidation numbers must equal 0.H2O H(+1), O(-2) 2(+1) + 1(-2) =0
For a polyatomic ion, the sum of the oxidation numbers must equal the ionic charge of the ion.NO3
2- : N(4), O(-2) 1(+4) + 3(-2) = 2-
Oxidation Number PracticeNaCl
(+1,-1)H2O
(+1,-2)SO2
(+4, -2)CO3
2-
(+4,-2)Na2SO4
(+1,+6,-2)
Oxidation-Number Changes in Chemical Reactions +1 +5 -2 0 +2 +5 -2 02AgNO3 +Cu Cu(NO3)2 + 2Ag
Ag: reducedCu: oxidized
Let’s Try These:Cl2 + 2HBr 2HCl +Br
2H2 + O2 2H2O
2KNO3 2KNO2 + O2
AnswersLet’s Try These:0 +1 -1 +1 -1 0 Cl2 + 2HBr 2HCl +Br
0 0 +1 -22H2 + O2 2H2O
+1 +5 -2 +1 +3 -2 02KNO3 2KNO2 + O2
Balancing Redox Reactions
How to tell if it’s a redox rxnIf the oxidation number of an element in a
reacting species changes 0 0 +2 -2N2 + O2 2NO
Balancing by Oxidation No.1) Assign oxidation numbers to all the atoms
+3 -2 +2 -2 0 +4 -2
Fe2O3 + CO Fe + CO2
2) Identify which atoms are oxidized and reduced.
3) Use brackets to connect that atoms undergoing oxidation, and other set for those reduced.
+2 Oxidation +3 -2 +2 -2 0 +4 -2
Fe2O3 + CO Fe + CO2
-3 reduction
Balancing by Oxidation No.Make the total increase in oxidation number
equal the total decrease using coefficients (+2)x3=6
+3 -2 +2 -2 0 +4 -2
Fe2O3 + 3CO 2Fe + 3CO2
(-3)x2=6
Make sure the equation is balanced for both atoms and charge
Let’s PracticeKClO3 KCl + O2
HNO2 + HI NO + I2 + H2O
Bi2S3 + HNO3 Bi(NO3) 3 + NO + S + H2O
SbCl5 + KI SbCl3 +KCl + I2
Balancing Half-ReactionsRedox Reactions
Half-ReactionsEquation showing just the oxidation or
reduction portion of the redox reaction.S + HNO3 SO2 + NO +H2O 0 +4 -2
Oxidation Half: S SO2
+5 -2 +2 -2
Reduction Half: NO3- NO
Balancing Half-ReactionsTo balance:
Write the unbalanced ionic equationWrite separate half reactions for oxidation &
reductionBalance atoms in each half-reactionAdd enough electrons to one side of each half-
reaction to balance the chargesMultiply each half-reaction by an appropriate
number to make the numbers of electrons equal
Add the half reaction to show the overall equation
Add the spectator ions and balance the equation
Half-ReactionsS + HNO3 SO2 + NO +H2O
Ionic Form: S + H+ + NO3- SO2 + NO +H2O
0 +4 -2
Oxidation Half: S SO2
+5 -2 +2 -2
Reduction Half: NO3- NO
Balancing Atoms in Half –Reactions2H2O + S SO2 + 4H+ 4H+ + NO3
- NO + 2H2O
Half-ReactionsAdd e- to each side of half reactions to
balance chargesOxidation: 2H2O + S SO2 + 4H+ + 4e-
Reduction: 4H+ + NO3- + 3e- NO + 2H2O
Multiply each half reaction by an appropriate number to make the numbers of electrons equalOxidation: 6H2O + 3S 3SO2 + 12H+ + 12e-
Reduction: 16H+ + 4NO3- + 12e- 4NO +
8H2O
Subtract the terms that appear on both sides and add in the spectator ions6H2O + 3S + 16H+ + 4NO3
- + 12e- 3SO2 + 12H+ + 12e-+ 4NO + 8H2O
3S + 4HNO3 3SO2 + 4NO + 2H2O
Half-ReactionsLet’s Practice:KMnO4 + HCl MnCl2 + Cl2 + H2O + KCl