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EENGIINFE 420 Digital Signal Processing PI 1 25 P2 1 25 F3 1 25 P4 1 25 P5 1 25 Total 1 100 FALL 2016-2017 MIDTERM EXAM Name(fuU): __________ St. Number: _________ Lecture r: Prof. Dr. Erhan A. ince Date: 22 /1112016 Duration: 90 min Read the following instructions carefully: 1) Please put your name on both the question paper and the answer booklet. 2) Use / ront and back of each page on the anwers booklet to answer questions. 3) Please answer Any FOllR questions you like. Problem 1 For two discrete-time systems that are characterized by the input-output relationships depicted below, determine if the systems are (a) linear, (b) time-invariant and (c) causal. (i) y[n] = x[n] . cos (3n) (ii) y[n] = x[n-2] + x[2-n] Problem 2 For each of the linear time-invariant systems described by the input-output relationships shown below detennine the corresponding impulse response h[n], (i) y[n] = x[n] + 2x[n - 1] + x[n - 2] (ii) Y [n] - - 1] + - 2] = - 1] 6 6 3
Transcript

EENGIINFE 420

Digital Signal Processing

PI 125

P2 125

F3 125

P4 125

P5 125

Total 1100

FALL 2016-2017

MIDTERM EXAM

Name(fuU) __________

St Number _________

Lecturer Prof Dr Erhan A ince

Date 221112016

Duration 90 min

Read the following instructions carefully

1) Please put your name on both the question paper and the answer booklet

2) Use ront and back of each page on the anwers booklet to answer questions

3) Please answer Any FOllR questions you like

Problem 1

For two discrete-time systems that are characterized by the input-output relationships depicted below determine if the systems are (a) linear (b) time-invariant and (c) causal

(i) y[n] = x[n] cos (3n) (ii) y[n] = x[n-2] + x[2-n]

Problem 2

For each of the linear time-invariant systems described by the input-output relationships

shown below detennine the corresponding impulse response h[n]

(i) y[n] = x[n] + 2x[n - 1] + x[n - 2]

(ii) Y [n] - ~y[n - 1] + ~y[n - 2] = ~x[n - 1]6 6 3

Problem 3

Given a discrete time sequence x[n] = 2O111011

(i) Compute the fast Fourier Transform values showing all computations

(ii) Also draw and label the butterfly structures required

Problem 4

A sound wave has the form

x(t) = 2A cos(10nt) + 2Bcos(30nt) + 2C cos(50nt) + 2D cos(60nt) + 2E cos(90nt) + 2F cos(1257tl)

where t is in milliseconds This signal is pre-filtered by an analog pre-filter H(f) Then the outputy(t) of the pre-filter is sampled at a rate of 40 kHz and immediately reconstructed by an ideal analog reconstruction filter resulting in the final analog output Ya(t) as shown below

)x(t) prefilter yet)

40 kHz y(n1)

analog yaltt

alog an H(j)

analog sampler

digital reconstructor

anal0 g

Determine the output signals yet) and Ya(t) in the following cases

(a) When there is no pre-filter thatis H(f)= 1 for all f

(b) When H(f) is the ideal pre-filter with cutoffs2 = 20 kHz

Problem 5

Let x(t) be the sum of sinusoidal signals

x(t)= 4 + 3 cos(nt)+ 2 cos(2nt) + cos(3nt) where t is in milliseconds

(a) Determine the minimum sampling rate that will not cause any aliasing effects that is

the Nyquist rate

(b) To observe such aliasing effects suppose this signal is sampled at half its Nyquist rate

and determine the signal Xa(t) that would be aliased with x(t)

lt

B-o o k (yen) - I

)~ Q X I (Ij -gt JI L1 J Clx [1 J Cos lt3VL

bXZ Co)) 7 ~ 1- J= b ~L l f) (cgtS 3 rL

Lj [P1 0 ~ l () J+ b Xl l 1 7 ~ ((1J 0-x l3 -t ~l(l LY [053 VLshy

ct X LI1J (Or~ct11 + bXL lnj (~3r-L1

~ I lll ) + ~~ ltU

l Ltlj ~ X1LJ CO 3 ft

~ CA) C9-lbj -gt ch lflJ ~ x (l-noJ ioS3rlshy

- ~ In-roJ ~[n()1gtJ Co5 J(f-n)

~ ~ [I)J 4- ~ pound11-(1 J

01) ~ vJ X- (P - Z J +( ll-ilj c-~(~J gt ~ LA) ~~ [n-zJ +CCpound [2-J ~~ pound~J 01- CJ b -2 [11- 2j -t b~LlmiddotflJ

-x ll tA-LU j 4- b~ enJ gt ~lfJ cvc[r- 2] +bx~(-Y Q4t-n]-+bXz(z-j

=G- x-frt -~ -t Gt ~ [2- fly +- ( blC-z [II--aJ + ~ll -iI)

-- ~ I [ j -r ~1-tj - l ifllAr

s~s~ IS

-gtc(0 ~ ~I [II1=- ~ ll-~ x G-rJ ~1 t~JXI c1~ Jl(u - [0-110 - D-r [1- (n()Q)J

= X Ln no tJ e l~- fL -+ 0 ~ [1-10J= gteLII- 110 bull 11 -10 x f2 - ( () il)l i2[k1(~ ~~~t

~ ~Il ~Iu~ II olAes h ence

No ~ CQ fIIJ() L

U) ~ LA - J ~ (-j + t j l-~ -f )(~ - J

~ LI1 j - f d (1 -J + t j lr1-2 J = 0

l-f) +7=0

pIe rUOise Call be ~er-t~d rofY) A Iyen~~(gtu $olrd-lol2 b(J determll1ll ~ c~mc-ttrIpound 4 ~L l3 to si-1S~J ~ 2uQ ()tfl d (D1 eli-Ii ~

~r ()= 0 ~ loJ -~ 4 ~lt] = 3- x(-J

~(fJ ~ 3- b[-tJ ~ 0

ho+ (oJ=- Gf+ B(5Y~ A+B ~ f I

d Llj - ~ ~lcJ +~ = ~ x[~ v) Lj - +[oJ -= f s(oJ =3

t x [6] cr---~~T~+-~--+-A~~~~L

omiddot x [1] ~~-~==t~r---------t=~~~~~U

x[3] ~-~~l~t---7~+~~L4-~~

I 1-0 -t~O---------+---------+-~ X [7]

W~

5

r41

X(-l) 21 ~s (It7It-l) -f 25 COS(301Tt) +2C eagt(so7rlj

-t- 2-1) caS(60 -rt) ~ 2 E s (7 17 ~ -+ 2F (tgtS ( 2S 71t)

v M l ~uoll~

40 k1h

H(f) =I

~ Lt)~ x(t)

tA ~ 5 ct-c- ~ IS kH7

0( J t- Cd -t 0- ifL Q LA lib~

oUFL -t 17JL S ~ ~ 0 ltAi 0 bfw ( i k ~ olcL 20 k U-t

X ( +) = 2 1+ (OS CJ01T-t) -t 2 B (OS (30lt-0 It XC-f)

f

In ~ ( ) iih r1ltgt p~-tH~

a(-t) xCt)

Od

da ft) ZftCo5 ( I 07f-i)+ z]5 cogt(~OTt+) + 2C cos(- 27f(IS)-t)

-t 2 0 CoS ( -211 lot) j- 2E cltgtS(zrrstj +lF COS-17T (ItS) J

i( CA-Samp lt b)

~ (t)= X (t)= 1- At 0$ (11)1i-t) + 28 ( bull 1 (30 11~

Vro blefY1 5

(~) 3 I-n-~) + 2- o~ 1211-l + (0) (371-t)xct) = 4 t (~ -IIL ~ gt l )

~ centL -2 c~ 1 -k ~vj

tV-4Lh c-At t- (ot f ~ Xf)M V~ cd ~d( be QL)c~

w i ~ (3 = fol olQ 0 I J (t s) - I C -0 skIIt

f4~ +4 Mo(-C =o 5 M oL I S == 0 ltH

c (i)- 4- (OS ( 21r-r-I) f- 3 cos (2ir ftAi) T 2~QS (r)1-G J)(Of -h~~r r ~~

4 + 3 Cc6 (1f) + 2 Cos (- 7r~ -+ agts (0)

- 5 -+ 3 ($ (Itt) -+ 2 Coo (-ITY

Problem 3

Given a discrete time sequence x[n] = 2O111011

(i) Compute the fast Fourier Transform values showing all computations

(ii) Also draw and label the butterfly structures required

Problem 4

A sound wave has the form

x(t) = 2A cos(10nt) + 2Bcos(30nt) + 2C cos(50nt) + 2D cos(60nt) + 2E cos(90nt) + 2F cos(1257tl)

where t is in milliseconds This signal is pre-filtered by an analog pre-filter H(f) Then the outputy(t) of the pre-filter is sampled at a rate of 40 kHz and immediately reconstructed by an ideal analog reconstruction filter resulting in the final analog output Ya(t) as shown below

)x(t) prefilter yet)

40 kHz y(n1)

analog yaltt

alog an H(j)

analog sampler

digital reconstructor

anal0 g

Determine the output signals yet) and Ya(t) in the following cases

(a) When there is no pre-filter thatis H(f)= 1 for all f

(b) When H(f) is the ideal pre-filter with cutoffs2 = 20 kHz

Problem 5

Let x(t) be the sum of sinusoidal signals

x(t)= 4 + 3 cos(nt)+ 2 cos(2nt) + cos(3nt) where t is in milliseconds

(a) Determine the minimum sampling rate that will not cause any aliasing effects that is

the Nyquist rate

(b) To observe such aliasing effects suppose this signal is sampled at half its Nyquist rate

and determine the signal Xa(t) that would be aliased with x(t)

lt

B-o o k (yen) - I

)~ Q X I (Ij -gt JI L1 J Clx [1 J Cos lt3VL

bXZ Co)) 7 ~ 1- J= b ~L l f) (cgtS 3 rL

Lj [P1 0 ~ l () J+ b Xl l 1 7 ~ ((1J 0-x l3 -t ~l(l LY [053 VLshy

ct X LI1J (Or~ct11 + bXL lnj (~3r-L1

~ I lll ) + ~~ ltU

l Ltlj ~ X1LJ CO 3 ft

~ CA) C9-lbj -gt ch lflJ ~ x (l-noJ ioS3rlshy

- ~ In-roJ ~[n()1gtJ Co5 J(f-n)

~ ~ [I)J 4- ~ pound11-(1 J

01) ~ vJ X- (P - Z J +( ll-ilj c-~(~J gt ~ LA) ~~ [n-zJ +CCpound [2-J ~~ pound~J 01- CJ b -2 [11- 2j -t b~LlmiddotflJ

-x ll tA-LU j 4- b~ enJ gt ~lfJ cvc[r- 2] +bx~(-Y Q4t-n]-+bXz(z-j

=G- x-frt -~ -t Gt ~ [2- fly +- ( blC-z [II--aJ + ~ll -iI)

-- ~ I [ j -r ~1-tj - l ifllAr

s~s~ IS

-gtc(0 ~ ~I [II1=- ~ ll-~ x G-rJ ~1 t~JXI c1~ Jl(u - [0-110 - D-r [1- (n()Q)J

= X Ln no tJ e l~- fL -+ 0 ~ [1-10J= gteLII- 110 bull 11 -10 x f2 - ( () il)l i2[k1(~ ~~~t

~ ~Il ~Iu~ II olAes h ence

No ~ CQ fIIJ() L

U) ~ LA - J ~ (-j + t j l-~ -f )(~ - J

~ LI1 j - f d (1 -J + t j lr1-2 J = 0

l-f) +7=0

pIe rUOise Call be ~er-t~d rofY) A Iyen~~(gtu $olrd-lol2 b(J determll1ll ~ c~mc-ttrIpound 4 ~L l3 to si-1S~J ~ 2uQ ()tfl d (D1 eli-Ii ~

~r ()= 0 ~ loJ -~ 4 ~lt] = 3- x(-J

~(fJ ~ 3- b[-tJ ~ 0

ho+ (oJ=- Gf+ B(5Y~ A+B ~ f I

d Llj - ~ ~lcJ +~ = ~ x[~ v) Lj - +[oJ -= f s(oJ =3

t x [6] cr---~~T~+-~--+-A~~~~L

omiddot x [1] ~~-~==t~r---------t=~~~~~U

x[3] ~-~~l~t---7~+~~L4-~~

I 1-0 -t~O---------+---------+-~ X [7]

W~

5

r41

X(-l) 21 ~s (It7It-l) -f 25 COS(301Tt) +2C eagt(so7rlj

-t- 2-1) caS(60 -rt) ~ 2 E s (7 17 ~ -+ 2F (tgtS ( 2S 71t)

v M l ~uoll~

40 k1h

H(f) =I

~ Lt)~ x(t)

tA ~ 5 ct-c- ~ IS kH7

0( J t- Cd -t 0- ifL Q LA lib~

oUFL -t 17JL S ~ ~ 0 ltAi 0 bfw ( i k ~ olcL 20 k U-t

X ( +) = 2 1+ (OS CJ01T-t) -t 2 B (OS (30lt-0 It XC-f)

f

In ~ ( ) iih r1ltgt p~-tH~

a(-t) xCt)

Od

da ft) ZftCo5 ( I 07f-i)+ z]5 cogt(~OTt+) + 2C cos(- 27f(IS)-t)

-t 2 0 CoS ( -211 lot) j- 2E cltgtS(zrrstj +lF COS-17T (ItS) J

i( CA-Samp lt b)

~ (t)= X (t)= 1- At 0$ (11)1i-t) + 28 ( bull 1 (30 11~

Vro blefY1 5

(~) 3 I-n-~) + 2- o~ 1211-l + (0) (371-t)xct) = 4 t (~ -IIL ~ gt l )

~ centL -2 c~ 1 -k ~vj

tV-4Lh c-At t- (ot f ~ Xf)M V~ cd ~d( be QL)c~

w i ~ (3 = fol olQ 0 I J (t s) - I C -0 skIIt

f4~ +4 Mo(-C =o 5 M oL I S == 0 ltH

c (i)- 4- (OS ( 21r-r-I) f- 3 cos (2ir ftAi) T 2~QS (r)1-G J)(Of -h~~r r ~~

4 + 3 Cc6 (1f) + 2 Cos (- 7r~ -+ agts (0)

- 5 -+ 3 ($ (Itt) -+ 2 Coo (-ITY

lt

B-o o k (yen) - I

)~ Q X I (Ij -gt JI L1 J Clx [1 J Cos lt3VL

bXZ Co)) 7 ~ 1- J= b ~L l f) (cgtS 3 rL

Lj [P1 0 ~ l () J+ b Xl l 1 7 ~ ((1J 0-x l3 -t ~l(l LY [053 VLshy

ct X LI1J (Or~ct11 + bXL lnj (~3r-L1

~ I lll ) + ~~ ltU

l Ltlj ~ X1LJ CO 3 ft

~ CA) C9-lbj -gt ch lflJ ~ x (l-noJ ioS3rlshy

- ~ In-roJ ~[n()1gtJ Co5 J(f-n)

~ ~ [I)J 4- ~ pound11-(1 J

01) ~ vJ X- (P - Z J +( ll-ilj c-~(~J gt ~ LA) ~~ [n-zJ +CCpound [2-J ~~ pound~J 01- CJ b -2 [11- 2j -t b~LlmiddotflJ

-x ll tA-LU j 4- b~ enJ gt ~lfJ cvc[r- 2] +bx~(-Y Q4t-n]-+bXz(z-j

=G- x-frt -~ -t Gt ~ [2- fly +- ( blC-z [II--aJ + ~ll -iI)

-- ~ I [ j -r ~1-tj - l ifllAr

s~s~ IS

-gtc(0 ~ ~I [II1=- ~ ll-~ x G-rJ ~1 t~JXI c1~ Jl(u - [0-110 - D-r [1- (n()Q)J

= X Ln no tJ e l~- fL -+ 0 ~ [1-10J= gteLII- 110 bull 11 -10 x f2 - ( () il)l i2[k1(~ ~~~t

~ ~Il ~Iu~ II olAes h ence

No ~ CQ fIIJ() L

U) ~ LA - J ~ (-j + t j l-~ -f )(~ - J

~ LI1 j - f d (1 -J + t j lr1-2 J = 0

l-f) +7=0

pIe rUOise Call be ~er-t~d rofY) A Iyen~~(gtu $olrd-lol2 b(J determll1ll ~ c~mc-ttrIpound 4 ~L l3 to si-1S~J ~ 2uQ ()tfl d (D1 eli-Ii ~

~r ()= 0 ~ loJ -~ 4 ~lt] = 3- x(-J

~(fJ ~ 3- b[-tJ ~ 0

ho+ (oJ=- Gf+ B(5Y~ A+B ~ f I

d Llj - ~ ~lcJ +~ = ~ x[~ v) Lj - +[oJ -= f s(oJ =3

t x [6] cr---~~T~+-~--+-A~~~~L

omiddot x [1] ~~-~==t~r---------t=~~~~~U

x[3] ~-~~l~t---7~+~~L4-~~

I 1-0 -t~O---------+---------+-~ X [7]

W~

5

r41

X(-l) 21 ~s (It7It-l) -f 25 COS(301Tt) +2C eagt(so7rlj

-t- 2-1) caS(60 -rt) ~ 2 E s (7 17 ~ -+ 2F (tgtS ( 2S 71t)

v M l ~uoll~

40 k1h

H(f) =I

~ Lt)~ x(t)

tA ~ 5 ct-c- ~ IS kH7

0( J t- Cd -t 0- ifL Q LA lib~

oUFL -t 17JL S ~ ~ 0 ltAi 0 bfw ( i k ~ olcL 20 k U-t

X ( +) = 2 1+ (OS CJ01T-t) -t 2 B (OS (30lt-0 It XC-f)

f

In ~ ( ) iih r1ltgt p~-tH~

a(-t) xCt)

Od

da ft) ZftCo5 ( I 07f-i)+ z]5 cogt(~OTt+) + 2C cos(- 27f(IS)-t)

-t 2 0 CoS ( -211 lot) j- 2E cltgtS(zrrstj +lF COS-17T (ItS) J

i( CA-Samp lt b)

~ (t)= X (t)= 1- At 0$ (11)1i-t) + 28 ( bull 1 (30 11~

Vro blefY1 5

(~) 3 I-n-~) + 2- o~ 1211-l + (0) (371-t)xct) = 4 t (~ -IIL ~ gt l )

~ centL -2 c~ 1 -k ~vj

tV-4Lh c-At t- (ot f ~ Xf)M V~ cd ~d( be QL)c~

w i ~ (3 = fol olQ 0 I J (t s) - I C -0 skIIt

f4~ +4 Mo(-C =o 5 M oL I S == 0 ltH

c (i)- 4- (OS ( 21r-r-I) f- 3 cos (2ir ftAi) T 2~QS (r)1-G J)(Of -h~~r r ~~

4 + 3 Cc6 (1f) + 2 Cos (- 7r~ -+ agts (0)

- 5 -+ 3 ($ (Itt) -+ 2 Coo (-ITY

~ ~Il ~Iu~ II olAes h ence

No ~ CQ fIIJ() L

U) ~ LA - J ~ (-j + t j l-~ -f )(~ - J

~ LI1 j - f d (1 -J + t j lr1-2 J = 0

l-f) +7=0

pIe rUOise Call be ~er-t~d rofY) A Iyen~~(gtu $olrd-lol2 b(J determll1ll ~ c~mc-ttrIpound 4 ~L l3 to si-1S~J ~ 2uQ ()tfl d (D1 eli-Ii ~

~r ()= 0 ~ loJ -~ 4 ~lt] = 3- x(-J

~(fJ ~ 3- b[-tJ ~ 0

ho+ (oJ=- Gf+ B(5Y~ A+B ~ f I

d Llj - ~ ~lcJ +~ = ~ x[~ v) Lj - +[oJ -= f s(oJ =3

t x [6] cr---~~T~+-~--+-A~~~~L

omiddot x [1] ~~-~==t~r---------t=~~~~~U

x[3] ~-~~l~t---7~+~~L4-~~

I 1-0 -t~O---------+---------+-~ X [7]

W~

5

r41

X(-l) 21 ~s (It7It-l) -f 25 COS(301Tt) +2C eagt(so7rlj

-t- 2-1) caS(60 -rt) ~ 2 E s (7 17 ~ -+ 2F (tgtS ( 2S 71t)

v M l ~uoll~

40 k1h

H(f) =I

~ Lt)~ x(t)

tA ~ 5 ct-c- ~ IS kH7

0( J t- Cd -t 0- ifL Q LA lib~

oUFL -t 17JL S ~ ~ 0 ltAi 0 bfw ( i k ~ olcL 20 k U-t

X ( +) = 2 1+ (OS CJ01T-t) -t 2 B (OS (30lt-0 It XC-f)

f

In ~ ( ) iih r1ltgt p~-tH~

a(-t) xCt)

Od

da ft) ZftCo5 ( I 07f-i)+ z]5 cogt(~OTt+) + 2C cos(- 27f(IS)-t)

-t 2 0 CoS ( -211 lot) j- 2E cltgtS(zrrstj +lF COS-17T (ItS) J

i( CA-Samp lt b)

~ (t)= X (t)= 1- At 0$ (11)1i-t) + 28 ( bull 1 (30 11~

Vro blefY1 5

(~) 3 I-n-~) + 2- o~ 1211-l + (0) (371-t)xct) = 4 t (~ -IIL ~ gt l )

~ centL -2 c~ 1 -k ~vj

tV-4Lh c-At t- (ot f ~ Xf)M V~ cd ~d( be QL)c~

w i ~ (3 = fol olQ 0 I J (t s) - I C -0 skIIt

f4~ +4 Mo(-C =o 5 M oL I S == 0 ltH

c (i)- 4- (OS ( 21r-r-I) f- 3 cos (2ir ftAi) T 2~QS (r)1-G J)(Of -h~~r r ~~

4 + 3 Cc6 (1f) + 2 Cos (- 7r~ -+ agts (0)

- 5 -+ 3 ($ (Itt) -+ 2 Coo (-ITY

t x [6] cr---~~T~+-~--+-A~~~~L

omiddot x [1] ~~-~==t~r---------t=~~~~~U

x[3] ~-~~l~t---7~+~~L4-~~

I 1-0 -t~O---------+---------+-~ X [7]

W~

5

r41

X(-l) 21 ~s (It7It-l) -f 25 COS(301Tt) +2C eagt(so7rlj

-t- 2-1) caS(60 -rt) ~ 2 E s (7 17 ~ -+ 2F (tgtS ( 2S 71t)

v M l ~uoll~

40 k1h

H(f) =I

~ Lt)~ x(t)

tA ~ 5 ct-c- ~ IS kH7

0( J t- Cd -t 0- ifL Q LA lib~

oUFL -t 17JL S ~ ~ 0 ltAi 0 bfw ( i k ~ olcL 20 k U-t

X ( +) = 2 1+ (OS CJ01T-t) -t 2 B (OS (30lt-0 It XC-f)

f

In ~ ( ) iih r1ltgt p~-tH~

a(-t) xCt)

Od

da ft) ZftCo5 ( I 07f-i)+ z]5 cogt(~OTt+) + 2C cos(- 27f(IS)-t)

-t 2 0 CoS ( -211 lot) j- 2E cltgtS(zrrstj +lF COS-17T (ItS) J

i( CA-Samp lt b)

~ (t)= X (t)= 1- At 0$ (11)1i-t) + 28 ( bull 1 (30 11~

Vro blefY1 5

(~) 3 I-n-~) + 2- o~ 1211-l + (0) (371-t)xct) = 4 t (~ -IIL ~ gt l )

~ centL -2 c~ 1 -k ~vj

tV-4Lh c-At t- (ot f ~ Xf)M V~ cd ~d( be QL)c~

w i ~ (3 = fol olQ 0 I J (t s) - I C -0 skIIt

f4~ +4 Mo(-C =o 5 M oL I S == 0 ltH

c (i)- 4- (OS ( 21r-r-I) f- 3 cos (2ir ftAi) T 2~QS (r)1-G J)(Of -h~~r r ~~

4 + 3 Cc6 (1f) + 2 Cos (- 7r~ -+ agts (0)

- 5 -+ 3 ($ (Itt) -+ 2 Coo (-ITY

r41

X(-l) 21 ~s (It7It-l) -f 25 COS(301Tt) +2C eagt(so7rlj

-t- 2-1) caS(60 -rt) ~ 2 E s (7 17 ~ -+ 2F (tgtS ( 2S 71t)

v M l ~uoll~

40 k1h

H(f) =I

~ Lt)~ x(t)

tA ~ 5 ct-c- ~ IS kH7

0( J t- Cd -t 0- ifL Q LA lib~

oUFL -t 17JL S ~ ~ 0 ltAi 0 bfw ( i k ~ olcL 20 k U-t

X ( +) = 2 1+ (OS CJ01T-t) -t 2 B (OS (30lt-0 It XC-f)

f

In ~ ( ) iih r1ltgt p~-tH~

a(-t) xCt)

Od

da ft) ZftCo5 ( I 07f-i)+ z]5 cogt(~OTt+) + 2C cos(- 27f(IS)-t)

-t 2 0 CoS ( -211 lot) j- 2E cltgtS(zrrstj +lF COS-17T (ItS) J

i( CA-Samp lt b)

~ (t)= X (t)= 1- At 0$ (11)1i-t) + 28 ( bull 1 (30 11~

Vro blefY1 5

(~) 3 I-n-~) + 2- o~ 1211-l + (0) (371-t)xct) = 4 t (~ -IIL ~ gt l )

~ centL -2 c~ 1 -k ~vj

tV-4Lh c-At t- (ot f ~ Xf)M V~ cd ~d( be QL)c~

w i ~ (3 = fol olQ 0 I J (t s) - I C -0 skIIt

f4~ +4 Mo(-C =o 5 M oL I S == 0 ltH

c (i)- 4- (OS ( 21r-r-I) f- 3 cos (2ir ftAi) T 2~QS (r)1-G J)(Of -h~~r r ~~

4 + 3 Cc6 (1f) + 2 Cos (- 7r~ -+ agts (0)

- 5 -+ 3 ($ (Itt) -+ 2 Coo (-ITY

In ~ ( ) iih r1ltgt p~-tH~

a(-t) xCt)

Od

da ft) ZftCo5 ( I 07f-i)+ z]5 cogt(~OTt+) + 2C cos(- 27f(IS)-t)

-t 2 0 CoS ( -211 lot) j- 2E cltgtS(zrrstj +lF COS-17T (ItS) J

i( CA-Samp lt b)

~ (t)= X (t)= 1- At 0$ (11)1i-t) + 28 ( bull 1 (30 11~

Vro blefY1 5

(~) 3 I-n-~) + 2- o~ 1211-l + (0) (371-t)xct) = 4 t (~ -IIL ~ gt l )

~ centL -2 c~ 1 -k ~vj

tV-4Lh c-At t- (ot f ~ Xf)M V~ cd ~d( be QL)c~

w i ~ (3 = fol olQ 0 I J (t s) - I C -0 skIIt

f4~ +4 Mo(-C =o 5 M oL I S == 0 ltH

c (i)- 4- (OS ( 21r-r-I) f- 3 cos (2ir ftAi) T 2~QS (r)1-G J)(Of -h~~r r ~~

4 + 3 Cc6 (1f) + 2 Cos (- 7r~ -+ agts (0)

- 5 -+ 3 ($ (Itt) -+ 2 Coo (-ITY

Vro blefY1 5

(~) 3 I-n-~) + 2- o~ 1211-l + (0) (371-t)xct) = 4 t (~ -IIL ~ gt l )

~ centL -2 c~ 1 -k ~vj

tV-4Lh c-At t- (ot f ~ Xf)M V~ cd ~d( be QL)c~

w i ~ (3 = fol olQ 0 I J (t s) - I C -0 skIIt

f4~ +4 Mo(-C =o 5 M oL I S == 0 ltH

c (i)- 4- (OS ( 21r-r-I) f- 3 cos (2ir ftAi) T 2~QS (r)1-G J)(Of -h~~r r ~~

4 + 3 Cc6 (1f) + 2 Cos (- 7r~ -+ agts (0)

- 5 -+ 3 ($ (Itt) -+ 2 Coo (-ITY


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