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Paper2 North B Electrical

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Question Booklet Series :ç'u iqfLrdk J`a[kyk %& A Question Booklet No. :ç'u iqfLrdk la[;k %& 520566 Time Allowed: 90 Minutes Total No. of Questions : 120 vuqer le; % 90 feuV PAPER – II ç”uksa dh dqy la[;k % 120 Roll No. : (Paper–II) OMR Answer Sheet No. : vuqØekad % -------------------------------------------- ¼isij&II½ vks-,e-vkj- mÙkj if=dk la[;k : --------------------------- Name of the Candidate (in capital letters) : vH;FkÊ dk uke % ---------------------------------------------------------------------------------------------- Candidate's Signature Invigilator's Signature vH;FkÊ ds gLrk{kj % ------------------------------- d{k fujh{kd ds gLrk{kj % --------------------------------- POST CODE NAME OF THE POST SUBJECT B J.E. (ELECTRICAL Engineering) ELECTRICAL IMPORTANT:– Read the following instructions carefully. Do not mark answers on the question booklet, otherwise you may be debarred from the selection process. 1. Before commencing to answer, check that the Question Booklet has 120 questions. Each Question Booklet will be in different series (combination of question booklet number and series). You must write correct Question Booklet Number and Question Booklet Series on your OMR Answer Sheet. Further check that there is no misprinting, overprinting and/or any other shortcoming in it. If there is any shortcoming in the question booklet, intimate the same to your room invigilator and take a fresh question booklet and a fresh OMR sheet. No complaint in this regard shall be entertained at any later stage. IMPORTANT NOTE: The OMR Answer Sheet will be evaluated with a combination of question booklet series and question booklet number hence you must write correct question booklet series and question booklet number. Any mistake in filling any of them will lead to invalidation of your OMR Answer Sheet. Also in case of non filling of question booklet series and question booklet number the OMR Answer Sheet will not be evaluated and its sole responsibility lies on the candidate. 2. Question paper is bilingual (Hindi/English). In case of any variation in Hindi version, English version will be taken as final for evaluation purposes. 3. Ensure that your admit card and OMR sheet is signed by you and the invigilator. If the same is not signed, your candidature is liable to be rejected. 4. All Multiple Choice Questions carry 1 mark. No Mark will be awarded or deducted for not attempting a question. Darken ONLY ONE OVAL for each answer. If you darken more than one oval or any stray mark is found on more than one oval, no mark will be awarded for that oval. 5. This is an objective type test in which each objective question is followed by four responses serialled (1) to (4). Your task is to choose the correct/best response and mark your response in the OMR Answer Sheet only as per the instructions given and NOT in the Question Booklet. 6. Use Blue/Black Ball Point Pen for all your work on the OMR Answer Sheet. The ovals on the OMR Answer Sheet are to be completely filled by Blue/Black Ball Point Pen only. ANSWERS ONCE GIVEN CAN NOT BE CHANGED. Cutting/overwriting the answers are not allowed. 7. Use of Calculators, Slide rules, Mobiles, calculator watches or any such devices and any other study/reference material is NOT allowed inside the examination hall and prohibited If found carrying, it shall be punishable offence. 8. Rough Work is to be done in the blank space provided in the Question Booklet, not on the OMR Answer Sheet. No other paper will be allowed/provided for rough work. 9. Handover OMR Answer Sheet to the invigilator on completion of the test. Do not take OMR Answer Sheet outside the examination room. Doing so is a punishable offence. The candidate can retain question paper after exam is over. fgUnh esa vuqns”k vfUre i`’B ¼Back cover½ ij fn;k x;k gSA
Transcript

Question Booklet Series :– ç'u iqfLrdk J`a[kyk %& A Question Booklet No. :–

ç'u iqfLrdk la[;k %& 520566

Time Allowed : 90 Minutes Total No. of Questions : 120vuqer le; % 90 feuV PAPER – II ç”uksa dh dqy la[;k % 120

Roll No. : (Paper–II) OMR Answer Sheet No. : vuqØekad % -------------------------------------------- ¼isij&II½ vks-,e-vkj- mÙkj if=dk la[;k : ---------------------------

Name of the Candidate (in capital letters) : vH;FkÊ dk uke % ----------------------------------------------------------------------------------------------

Candidate's Signature Invigilator's Signature vH;FkÊ ds gLrkkj % ------------------------------- dk fujhkd ds gLrkkj % ---------------------------------

POST CODE NAME OF THE POST SUBJECT

B J.E. (ELECTRICAL Engineering) ELECTRICAL

IMPORTANT:– Read the following instructions carefully. Do not mark answers on the question booklet, otherwise you may be debarred from the selection process. 1. Before commencing to answer, check that the Question Booklet has 120 questions. Each Question Booklet will be in

different series (combination of question booklet number and series). You must write correct Question Booklet Number and Question Booklet Series on your OMR Answer Sheet. Further check that there is no misprinting, overprinting and/or any other shortcoming in it. If there is any shortcoming in the question booklet, intimate the same to your room invigilator and take a fresh question booklet and a fresh OMR sheet. No complaint in this regard shall be entertained at any later stage. IMPORTANT NOTE: The OMR Answer Sheet will be evaluated with a combination of question booklet series and question booklet number hence you must write correct question booklet series and question booklet number. Any mistake in filling any of them will lead to invalidation of your OMR Answer Sheet. Also in case of non filling of question booklet series and question booklet number the OMR Answer Sheet will not be evaluated and its sole responsibility lies on the candidate.

2. Question paper is bilingual (Hindi/English). In case of any variation in Hindi version, English version will be taken as final for evaluation purposes.

3. Ensure that your admit card and OMR sheet is signed by you and the invigilator. If the same is not signed, your candidature is liable to be rejected.

4. All Multiple Choice Questions carry 1 mark. No Mark will be awarded or deducted for not attempting a question. Darken ONLY ONE OVAL for each answer. If you darken more than one oval or any stray mark is found on more than one oval, no mark will be awarded for that oval.

5. This is an objective type test in which each objective question is followed by four responses serialled (1) to (4). Your task is to choose the correct/best response and mark your response in the OMR Answer Sheet only as per the instructions given and NOT in the Question Booklet.

6. Use Blue/Black Ball Point Pen for all your work on the OMR Answer Sheet. The ovals on the OMR Answer Sheet are to be completely filled by Blue/Black Ball Point Pen only. ANSWERS ONCE GIVEN CAN NOT BE CHANGED. Cutting/overwriting the answers are not allowed.

7. Use of Calculators, Slide rules, Mobiles, calculator watches or any such devices and any other study/reference material is NOT allowed inside the examination hall and prohibited If found carrying, it shall be punishable offence.

8. Rough Work is to be done in the blank space provided in the Question Booklet, not on the OMR Answer Sheet. No other paper will be allowed/provided for rough work.

9. Handover OMR Answer Sheet to the invigilator on completion of the test. Do not take OMR Answer Sheet outside the examination room. Doing so is a punishable offence. The candidate can retain question paper after exam is over.

fgUnh esa vuqns”k vfUre i`’B ¼Back cover½ ij fn;k x;k gSA

1. The per unit impedance of a circuit element is 0.15. If the base kV and base MVA are halved, then the new value of the per-unit impedance of the circuit element will be: (1) 0.075 (2) 0.15 (3) 0.30 (4) None of these

1. ,d ifjiFk&vo;o dh izfr ;wfuV izfrck/kk 0.15 gSA ;fn vk/kkj kV rFkk vk/kkj MVA vk/ks dj fn, tk,a rks ifjiFk&vo;o dh izfr

;wfuV izfrck/kk dk u;k eku D;k gksxk\

(1) 0.075 (2) 0.15 (3) 0.30 (4) buesa ls dksbZ ugha

2. A mho relay is used for protection of: (1) Protection of a transformer against external faults. (2) Long Transmission lines (3) Protection of a transformer against all the internal

faults and external faults. (4) Medium length lines

2. mho fjys dk iz;ksx fuEu dh jkk ds fy, fd;k tkrk gS% (1) ckg~; fodkjksa ls VªkalQkeZj dh lqjkk

(2) yach lapj.k ykbusa

(3) lHkh vkarfjd vkSj ckg~; =qfV;ksa ls VªkalQkeZj dh jkk

(4) e>ksyh nwjh dh ykbusa

3. In coal-fired thermal power stations, what are the electrostatic precipitators used for? (1) To remove dust particles settling on the bus bar

conductors in the station yard. (2) To condense steam by electrostatic means. (3) To keep the air heaters clean. (4) To collect the dust particles from the flue gases.

3. dks;yk&izTofyr Å’eh; fo|qr “kfDr dsUnz esa] fLFkj fo|qr voksfi=ksa

dk iz;ksx fdlfy, fd;k tkrk gS\

(1) LVs”ku ;kMZ esa cl ckj pkydksa ij tek gksus okys /kwy ds d.kksa

dks gVkuk

(2) fLFkj fo|qr lk/kuksa kjk Hkki dks nzfor djuk

(3) ok;q ghVjksa dks lkQ j[kuk

(4) ¶yw xSlksa ls /kwy ds d.k bdV~Bs djuk

4. Equivalent π model is quite suitable for analyzing the performance of transmission line of: (1) 50 km length. (2) 150 km length. (3) 250 km length. (4) All of these.

4. fuEu dh lapj.k ykbu ds fu’iknu dk fo”ys’k.k djus ds fy,

lerqY; π ekMy loZFkk mi;qDr gS%

(1) 50 km yackbZ (2) 150 km yackbZ (3) 250 km yackbZ (4) ;s lHkh

5. For reducing tower footing resistance, it is better to employ: (1) Chemical and counterpoise (2) Ground Rods and counterpoise (3) Chemical and ground rods (4) Chemical, Ground Rods and counterpoise

5. Vkoj ikn izfrjks/k ?kVkus ds fy, fuEu dk iz;ksx djuk csgrj gS%

(1) jlk;u vkSj izfrrksy

(2) Hkw&NM+ vkSj izfrrksy

(3) jlk;u vkSj Hkw&NM+

(4) jlk;ui] Hkw&NM+ vkSj izfrrksy

6. The non-uniform distribution of voltage across the units in a string of suspension insulators is due to: (1) Unequal self capacitance of the units (2) The existence of stray capacitance between the

metallic junctions of the units and the tower body. (3) Non uniform distance of separation of the units from

the tower body. (4) Non uniform distance of between the cross-arm and

the units.

6. fuyacu fo|qr jks/kdksa dh J`a[kyk esa ;wfuVksa ds chp oksYVrk dk

vleku foHkktu fuEu dkj.k ls jgrk gS%

(1) ;wfuVksa dh vleku Lo&/kkfjrk

(2) ;wfuVksa ds /kkfRod tksM+ksa vkSj Vkoj fudk; ds chp izdh.kZ /kkfjrk

dh ekStwnxh

(3) Vkoj fudk; ls ;wfuVksa ds ikFkZD; dh vleku nwjh

(4) dSaph Hkqtk vkSj ;wfuVksa ds chp vleku nwjh

7. Which one of the following statements correctly represents the post acceleration in cathode-ray tube? (1) It provides deflection of the beam. (2) It increases the brightness of the trace if the signal

frequency is higher than 10 MHz. (3) It accelerates the beam before deflection. (4) It increases the brightness of the trace of low

frequency signal.

7. fuEu esa ls dkSu&lk dFku dSFkksM&fdj.k V~;wc ds i”p Roj.k dks lgh

:i ls ifjyfkr djrk gS\

(1) ;g che dk foksi miyC/k djkrk gS

(2) ;fn ladsrd vko`fRr 10 MHz ls c<+dj gks rks ;g Vªsl dh ped c<+krk gS

(3) ;g foksi ls igys che dks Rofjr dj nsrk gS

(4) ;g U;wu vko`fRr ladsrd dh ped c<+k nsrk gS

8. A spring controlled moving iron voltmeter draws a current of 1mA for full scale value of 100 V. If it draws a current of 0.5 mA, the meter reading is: (1) 25 V (2) 50 V (3) 100 V (4) None of these

8. ,d fLizax fu;af=r py ykSg oksYVehVj 100 V ds laiw.kZ eku ds fy, 1mA /kkjk vkgfjr djrk gSA ;fn ;g 0.5 mA /kkjk dk vkgj.k

djrk gS rks ehVj iBu gksrk gS

(1) 25 V (2) 50 V (3) 100 V (4) buesa ls dksbZ ugha

PAPER – II_Electrical [ 5 2 0 5 6 6 ] NFCX5 [ A–1 ]

9. In Thevenin’s theorem, to find Z,: (1) All independent voltage sources are short circuited and

all independent current sources are open circuited. (2) All independent voltage sources are open circuited and

all independent current sources are short circuited. (3) All independent voltage sources are short circuited and

all independent current sources are short circuited. (4) All independent voltage sources are open circuited and

all independent current sources are open circuited.

9. Fksosfu;e izes; esa Z dk irk yxkus ds fy,% (1) lHkh Lora= oksYVrk lzksrksa dks y?kqifFkr dj fn;k tkrk gS rFkk

lHkh Lora= /kkjk lzksrksa dks foo`r ifFkr dj fn;k tkrk gS

(2) lHkh Lora= oksYVrk lzksrksa dks foo`rifFkr dj fn;k tkrk gS rFkk

lHkh Lora= /kkjk lzksrksa dks y?kqifFkr dj fn;k tkrk gS

(3) lHkh Lora= oksYVrk lzksrksa dks y?kqifFkr dj fn;k tkrk gS rFkk

lHkh Lora= /kkjk lzksrksa dks y?kqifFkr dj fn;k tkrk gS

(4) lHkh Lora= oksYVrk lzksrksa dks foo`rifFkr dj fn;k tkrk gS rFkk

lHkh Lora= /kkjk lzksrksa dks foo`rifFkr dj fn;k tkrk gS

10. In a single phase power factor meter, the controlling torque is: (1) Provided by the spring control. (2) Not required. (3) Provided by the gravity control. (4) Provided by the stiffness of suspension.

10. ,dy dyk “kfDr xq.kkad ehVj esa fu;a=d cy vk?kw.kZ%

(1) fLizax fu;a=.k kjk miyC/k djk;k tkrk gS

(2) dh t:jr ugha gksrh

(3) xq#Ro fu;a=.k kjk miyC/k djk;k tkrk gS

(4) fuyacu dh n`<+rk kjk miyC/k djk;k tkrk gS

11. A dc circuit can be represented by an internal voltage source of 50 V with an output resistance of 100 KΩ. In order to achieve accuracy better than 99% for voltage measurement across its terminals, the votage measuring device should have a resistance of at least: (1) 10 MΩ (2) 1 MΩ (3) 10 KΩ (4) None of these

11. ,d dc ifjiFk dks 100 KΩ ds fuxZe izfrjks/k lfgr 50 V ds vkarfjd oksYVrk lzksr kjk fu:fir fd;k tk ldrk gSA blds VfeZuyksa

ds chp oksYVrk ekiu ds fy, 99% ls csgrj “kq)rk izkIr djus ds

fy,] oksYVrkekih midj.k esa de ls de fuEu izfrjks/k gksuk pkfg,%

(1) 10 MΩ (2) 1 MΩ (3) 10 KΩ (4) buesa ls dksbZ ugha

12. Two meters X and Y require 40 mA and 50 mA, respectively, to give full-scale deflection, then: (1) Sensitivity can not be judged with given information. (2) X is more sensitive. (3) Both are equally sensitive. (4) Y is more sensitive.

12. nks ehVjksa X vkSj Y dks iw.kZ&Lrjh; foksi iznku djus ds fy, Øe”k% 40 mA vkSj 50 mA dh t:jr jgrh gS] rks% (1) nh xbZ tkudkjh ls laos|rk dk fu/kkZj.k ugha fd;k tk ldrk

(2) X vf/kd laosnh gS

(3) nksuksa leku :i ls laosnh gS

(4) Y vf/kd laosnh gS

13. The dielectric loss of a capacitor can be measured by: (1) Hay’s Bridge (2) Schering Bridge (3) Maxwell Bridge (4) Anderson Bridge

13. la/kkfj= dh ijkoS|qr gkfu dks fuEu kjk ekik tk ldrk gS%

(1) gs lssrq (2) “kSfjax lsrq (3) eSDlosy lsrq (4) ,sUMjlu lsrq

14. Sensitivity of LVDT is mainly due to: (1) Magnetic shielding of the core. (2) Permeability of the core. (3) Exact cancellation of secondary voltages. (4) Insulation used in the windings.

14. LVDT dh laos|rk eq[;r% fuEu ds dkj.k gksrh gS% (1) dksj dk pqacdh; ifjjk.k

(2) dksj dh ikjxE;rk

(3) frh;d oksYVrkvksa dk okLrfod fujlu

(4) yisVksa esa iz;qDr fo|qrjks/ku

15. The concept of transfer function applies to: (1) Linear time varying system. (2) Linear time invariant systems only. (3) Linear and non-linear systems only. (4) Only to MIMO systems.

15. varj.k Qyu dh vo/kkj.kk fuEu ij ykxw gksrh gS%

(1) jSf[kd le; ifjorhZ iz.kkyh

(2) dsoy jSf[kd dky vpj iz.kkfy;ka

(3) dsoy jSf[kd vkSj vjSf[kd iz.kkfy;ka

(4) dsoy MIMO iz.kkfy;ka

16. The stepper motor has six phase winding on its stator and has 12 teeth on rotor. The stepping angle is: (1) 5 degrees (2) 10 degrees (3) 2.5 degrees (4) 30 degrees

16. LVSij eksVj ds LVsVj ij ‘kV~dyk yisV vkSj jksVj ij 12 nkarsa gSaA LVSfiax dks.k gS%

(1) 5 fMxzh (2) 10 fMxzh (3) 2.5 fMxzh (4) 30 fMxzh

17. A d.c. series motor is accidently connected to single phase a.c. supply. The torque produced will be: (1) Of zero average value. (2) Oscillating (3) Steady and unidirectional (4) Pulsating and unidirectional

17. ,d d.c. J`a[kyk eksVj xyrh ls ,dy dyk a.c. iwfrZ ds lkFk tksM+ nh tkrh gSA mRiUu fd, tkus okyk cy&vk?kw.kZ gksxk%

(1) “kwU; vkSlr eku dk

(2) nksyk;eku

(3) fLFkjd vkSj vfn”kkRed

(4) Lianeku vkSj vfn”kkRed

PAPER – II_Electrical [ 5 2 0 5 6 6 ] NFCX5 [ A–2 ]

18. In an electromechanical energy conversion device, the developed torque depends upon: (1) Stator field strength and torque angle. (2) Stator field strength and rotor field strength. (3) Stator field and rotor field strengths and torque angle. (4) Stator field strength only.

18. ,d oS|qr ;kaf=d ÅtkZ ifjorZd midj.k esa mRiUu cy&vk?kw.kZ fuEu

ij fuHkZj djrk gS%

(1) LVSVj ks= lkeF;Z vkSj cy&vk?kw.kZ dks.k

(2) LVSVj ks= lkeF;Z vkSj jksVj ks= lkeF;Z

(3) LVSVj ks= vkSj jksVj ks= lkeF;Z rFkk cy&vk?kw.kZ dks.k

(4) dsoy LVSVj lkeF;Z

19. The starting current of a 3∅ induction motor is five times the rated current, while the rated slip is 4%. The ratio of starting torque to full load torque is: (1) 0.6 (2) 0.8 (3) 1.0 (4) None of these

19. ,d 3∅ izsj.k eksVj dh izorZu /kkjk fu/kkZfjr /kkjk dh ikap xq.kk gS tcfd fu/kkZfjr liZ.k 4% gSA iw.kZ Hkkj cy&vk?kw.kZ ds izfr izorZu

cy&vk?kw.kZ dk vuqikr gS%

(1) 0.6 (2) 0.8 (3) 1.0 (4) buesa ls dksbZ ugha

20. The full load copper loss and iron loss of transformer are 6400 W and 5000 W respectively. The copper loss and iron loss at half load will be, respectively: (1) 3200 W and 2500 W (2) 3200 W and 5500 W (3) 1600 W and 5000 W (4) None of these

20. VªkalQkeZj dh iw.kZ Hkkj rkack gkfu vkSj ykSg gkfu Øe”k% 6400 W rFkk 5000 W gSA v)Z Hkkj ij rkack gkfu vkSj ykSg gkfu gksxh

Øe”k%

(1) 3200 W rFkk 2500 W (2) 3200 W rFkk 5500 W (3) 1600 W rFkk 5000 W (4) buesa ls dksbZ ugha

21. Which one of the following methods gives more accurate result for determination of voltage regulation of an alternator? (1) m.m.f. method (2) Synchronous impedance mrthod (3) American institution standard method (4) Potier triangle method

21. fuEu esa ls dkSu&lh fof/k ,d izR;kofrZ= ds oksYVrk fofu;eu ds

fu/kkZj.k dk vf/kd “kq) ifj.kke iznku djrh gS\

(1) m.m.f. fof/k (2) rqY;dkfyd izfrck/kk fof/k

(3) vejhdh laLFkku ekud fof/k

(4) iksfV;j f=dks.k fof/k

22. Kirchoff’s law is applicable to: (1) Passive networks only (2) A.c. netwoks only (3) d.c. netwoks only (4) Both a.c. and d.c. circuits

22. fØ[kkQ fu;e fuEu ij ykxw gksrk gS%

(1) dsoy fuf’Ø; usVodZ ij

(2) dsoy a.c. usVodZ ij (3) dsoy d.c. usVodZ ij (4) a.c. rFkk d.c. nksuksa ifjiFkksa ij

23. The circuit whose properties are same in either direction is known as: (1) Unilateral circuit. (2) Bilateral circuit. (3) Irreversible circuit. (4) Reversible circuit.

23. ,slk ifjiFk ftlds fdlh Hkh fn”kk esa xq.k&/keZ ,dleku gS] dgykrk

gS%

(1) ,d ik”ohZ; ifjiFk (2) f&ik”ohZ; ifjiFk (3) vizfrØE; ifjiFk (4) mRØE; ifjiFk

24. If two sinusoids of different amplitudes and phase angles are subtracted, the resultant is: (1) A sinusoid of double the frequency. (2) A sinusoid of half of the original frequency. (3) A sinusoid of same the frequency. (4) Not a sinusoid.

24. ;fn fofHkUu dks.kkadksa vkSj dyk dks.kksa ds nks T;koØksa dks ?kVk fn;k

tk, rks mldk ifj.kke gS%

(1) nqxquh vko`fRr dk ,d T;koØ

(2) ewy vko`fRr ls vk/kh vko`fRr dk ,d T;koØ

(3) mlh vko`fRr dk ,d T;koØ

(4) dksbZ T;koØ ugha

25. In a series resonant circuit the impedance of the circuit is: (1) Minimum (2) Maximum (3) Zero (4) None of these

25. Js.kh vuquknh ifjiFk esa] ifjiFk dh izfrck/kk gksrh gS%

(1) U;wure (2) vf/kdre

(3) “kwU; (4) buesa ls dksbZ ugha

26. In a circuit containing R, L and C power loss can take place in: (1) R only (2) L only (3) C only (4) All the above

26. R, L vkSj C ls ;qDr ifjiFk esa fo|qr gkfu dsoy fuEu esa gks ldrh gS%

(1) dsoy R (2) dsoy L (3) dsoy C (4) mi;qZDr lHkh

27. Which of the following is a piezoelectric material? (1) Quartz (2) Silica Sand (3) Copper (4) Polystyrene

27. fuEu esa ls dkSu ,d nkcfo|qr lkexzh gS\

(1) DokVZ~t (2) flfydk lSaM (3) rkack (4) ikfyLVhjhu

PAPER – II_Electrical [ 5 2 0 5 6 6 ] NFCX5 [ A–3 ]

28. The nominal ratio of a current transformer is: (1) Primary winding current / secondary winding current (2) Number of Primary winding turns / Number of

secondary winding turns (3) Rated Primary winding current / Rated secondary

winding current (4) Number of Secondary winding turns / Number of

Primary winding turns

28. ,d /kkjk VªkalQkeZj dk vfHkfgr vuqikr gksrk gS%

(1) izkFkfed yisVu /kkjk@frh;d yisVu /kkjk

(2) izkjafHkd yisVu Qsjksa dh la[;k@frh;d yisVu Qsjksa dh la[;k

(3) fu/kkZfjr izkFkfed yisVu /kkjk@fu/kkZfjr frh; yisVu /kkjk

(4) frh;d yisVu Qsjksa dh la[;k@izkFkfed yisVu Qsjksa dh la[;k

29. What is the value of total electric flux coming out of a closed surface? (1) Zero (2) Equal to the total charge enclosed by the surface. (3) Equal to the volume charge density. (4) Equal to the surface charge density.

29. ,d lao`r lrg ls ckgj vkus okys lexz oS|qr vfHkokg dk eku D;k

gS\

(1) “kwU;

(2) lrg kjk vko`Rr dqy vkos”k ds cjkcj

(3) vk;ru vkos”k ?kuRo ds cjkcj

(4) lrgh vkos”k ?kuRo ds cjkcj

30. Above the curie temperature, ferromagnetic materials behave like: (1) Paramagnetic (2) Diamagnetic (3) Anti-ferromagnetic (4) Ferrimagnetic

30. D;wjh rkieku ls Åij yksgpqaacdh; lkexzh fuEu tSlk O;ogkj djrh

gSa%

(1) ijkpqacdh; (2) izfrpqacdh; (3) yksgpqacdh;&jks/kh (4) yksgpqacdh;

31. Magnetostriction is a phenomenon of: (1) Generation of electricity in ferromagnetic materials (2) Generation of magnetism in ferromagnetic materials (3) Change in permeability of ferromagnetic materials

during magnetization (4) Change in physical dimension of ferromagnetic

materials during magnetization.

31. pqacdh; fo:i.k fuEu dk ?kVukØe gS%

(1) ykSgpqacdh; lkexzh esa fo|qr dh mRifRr

(2) ykSgpqacdh; lkexzh esa pqacdRo dh mRifRr

(3) pqacdu ds nkSjku ykSg&pqacdh; lkexzh dh ikjxE;rk esa ifjorZu

(4) pqacdu ds nkSjku ykSg&pqacdh; lkexzh ds HkkSfrd vk;ke esa

ifjorZu

32. The development of barrier potential in the depletion zone of a PN junction is consequent to: (1) Diffusion of majority carriers across the junction. (2) Drift of minority carriers across the junction. (3) Generation of minority carriers across the junction. (4) Initial flow of conduction current.

32. PN laf/k ds vok; ks= esa jksf/kdk foHko dh mRifRr fuEu dk

ifj.kke gS%

(1) laf/k ds vkjikj vf/kdka”k okgdksa dk folj.k

(2) laf/k ds vkjikj vYila[;d okgdksa dk fopyu

(3) laf/k ds vkjikj vYila[;d okgdksa dh mRifRr

(4) pkyu /kkjk dk izkjafHkd izokg

33. The armature of a d.c. machine is laminated: (1) to reduce the eddy current loss. (2) to reduce the hysteresis loss. (3) to reduce the inductance of the armature. (4) to reduce the mass of the armature.

33. d. c. e”khu dk vkesZpj iVfyr fd;k tkrk gS%

(1) Hkaoj /kkjk dh gkfu de djus ds fy,

(2) fgLVSjsfll gkfu de djus ds fy,

(3) vkesZpj dk izsj.k de djus ds fy,

(4) vkesZpj dk nzO;eku de djus ds fy,

34. An electric circuit with 10 branches and 7 nodes will have: (1) 4 loop equations (2) 7 loop equations (3) 10 loop equations (4) 5 loop equations

34. 10 “kk[kkvksa vkSj 7 uksMksa ls ;qDr oS|qr ifjiFk esa gksaxs% (1) 4 ywi lehdj.k (2) 7 ywi lehdj.k (3) 10 ywi lehdj.k (4) 5 ywi lehdj.k

35. Superposition theorem is not applicable for: (1) Voltage calculations (2) Bilateral elements (3) Power calculations (4) Passive elements

35. v/;kjksi.k izes; fuEu ds fy, ykxw ugha gksrk%

(1) oksYVrk x.ku (2) fikh; rRo (3) “kfDr x.ku (4) fuf’Ø; rRo

36. A standard resistor is made ‘bifilar’ type to eliminate: (1) Skin effect (2) Inductive effect (3) Temperature effect (4) Stray capacitance

36. ,d ekud izfrjks/kd dks fuEu ds mUewyu ds fy, ^f&lw=h*

¼ckbQk;yj½ dksfV dk cuk;k tkrk gS%

(1) Ropk izHkko (2) izsj.k izHkko (3) rkieku izHkko (4) izdh.kZ la/kkfjrk

37. Which bridge is used to determine frequency? (1) Wein Bridge (2) Anderson Bridge (3) Maxwell Bridge (4) Campbell Bridge

37. vko`fRr dk fu/kkZj.k djus ds fy, dkSu&ls lsrq dk iz;ksx fd;k tkrk gS\

(1) fou lsrq (2) ,sUMjlu lsrq (3) eSDlosy lsrq (4) dSEicsy lsrq

PAPER – II_Electrical [ 5 2 0 5 6 6 ] NFCX5 [ A–4 ]

38. The current and potential coils of a dynamometer type wattmeter were accidentally interchanged while connecting. After energizing the circuit, it was observed that the wattmeter did not show the reading. This could be due to: (1) Damage to potential coils (2) Damage to current coil (3) Damage to both current coil and pressure coil (4) Loose contacts

38. Mk;ueksehVj dksfV ds okVehVj dh /kkjk vkSj foHko dk;ysa la;ksftr

djrs le; xyrh ls ijLij cny xbZA ifjiFk dk ÅtkZ;u djrs

le; ;g ik;k x;k fd okVehVj esa dksbZ iBu izdV ugha gqvk] ftlds

ihNs fuEu dkj.k gks ldrk gS%

(1) foHko dk;yksa dh kfr

(2) /kkjk dk;y dh kfr

(3) /kkjk dk;y vkSj foHko dk;y & nksuksa dh kfr

(4) <hys la;kstu

39. A single–phase ac regulator is used to convert: (1) Fixed ac voltage to variable magnitude ac voltage of

same frequency (2) Fixed ac voltage to variable frequency ac voltage of

same magnitude (3) Fixed ac voltage to variable frequency ac voltage

through dc link (4) Fixed ac voltage to variable magnitude variable

frequency ac voltage

39. ,dy dyk ac jsxqysVj fdls ifjofrZr djus ds fy, ç;ksx fd;k tkrk gS\

(1) ,d gh vko`fÙk ds fLFkj ac oksYVrk dks ifjorÊ ifjek.k ac oksYVrk esa

(2) ,d gh ifjek.k ds fLFkj ac oksYVrk dks ifjorÊ vko`fÙk ac oksYVrk esa

(3) dc fyad ds ek/;e ls fLFkj ac oksYVrk dks ifjorÊ vko`fÙk esa

(4) fLFkj ac oksYVrk dks ifjorÊ ifjek.k ifjorÊ vko`fÙk ac esa

40. If a ramp input is applied to Type -2 system, the steady state error is: (1) Zero (2) Positive constant (3) Negative constant (4) Positive infinity

40. ;fn izo.k fuos”k ¼jSEi bUiqV½ dks dksfV&2 iz.kkyh ij ykxw fd;k tkrk gS rks LFkk;h n”kk =qfV gS%

(1) “kwU; (2) /kukRed fLFkjkad (3) _.kkRed fLFkjkad (4) /kukRed vuar

41. The effect of Tachometer feedback is to improve: (1) Steady state response (2) Transient response (3) Both steady state and transient response (4) Neither Steady state nor Transient response

41. VSdksehVj QhMcSd dk izHkko fuEu dks lq/kkjuk gS%

(1) fLFkj n”kk vuqfØ;k

(2) kf.kd vuqfØ;k

(3) fLFkj n”kk rFkk kf.kd vuqfØ;k & nksuksa

(4) u fLFkj n”kk u kf.kd vuqfØ;k

42. Standardization of potentiometers is done in order to make them: (1) Accurate and precise (2) Accurate (3) Accurate and direct reading (4) Precise.

42. foHkoekfi;ksa dk ekudhdj.k blfy, fd;k tkrk gS rkfd mUgsa cuk;k

tk lds%

(1) “kq) vkSj ifj”kq) (2) “kq)

(3) “kq) vkSj izR;k iBu (4) ifj”kq)

43. Sphere gaps are used for the measurement of: (1) Instantaneous values of voltage (2) Peak values of voltage (3) r.m.s. values of voltage (4) Average values of voltage

43. xksyd varjkyksa dk iz;ksx fuEu dks ekius ds fy, fd;k tkrk gS%

(1) oksYVrk dk rkRdkfyd eku

(2) oksYVrk dk f”k[kj eku

(3) oksYVrk dk r.m.s. eku (4) oksYVrk ds vkSlr eku

44. The main criterion for the design of distributor is: (1) The voltage drop (2) Corona loss (3) Temperature rise (4) Radio interference

44. forjd ds vfHkdYi ds fy, izeq[k ekunaM gS%

(1) oksYVrk ikr (2) dksjksuk gkfu (3) rkieku o`f) (4) jsfM;ks O;frØe

45. Shunt compensation in EHV is resorted to: (1) Improve the stability (2) Reduce the fault level (3) Improve the voltage profile (4) As a substitute for synchronous phase modifier.

45. EHV esa “kaV izfriwfrZ dk lgkjk fuEu iz;kstu ds fy, fy;k tkrk gS% (1) fLFkjrk esa lq/kkj ykuk

(2) =qfV Lrj dks ?kVkuk

(3) oksYVrk izksQkby esa lq/kkj ykuk

(4) ledkfyd dyk v”kksf/k= ds ,oth ds :i esa

46. The voltage of a particular bus can be controlled by controlling the: (1) Phase angle (2) Reactive power of the bus (3) Active power of the bus (4) Phase angle and reactive power of the bus

46. ,d fo”ks’k cl dh oksYVrk fuEu ds fu;a=.k kjk fu;af=r dh tk

ldrh gS%

(1) dyk dks.k

(2) cl dh izfr?kkrh “kfDr

(3) cl dh lfØ; “kfDr

(4) dyk dks.k vkSj cl dh izfr?kkrh “kfDr

PAPER – II_Electrical [ 5 2 0 5 6 6 ] NFCX5 [ A–5 ]

47. When two sinusoidal waves are 90° out of phase,: (1) One has its peak value when the other has zero value. (2) Each has its peak value at the same time (3) Each has its minimum value at the same time (4) None of these

47. tc nks T;koØh; rjaxs 90° dyk fHkUu gSa% (1) ,d dk pje eku gS tcfd nwljs dk eku “kwU; gS

(2) ,d gh le; esa izR;sd dk pje eku gS

(3) ,d gh le; esa izR;sd dk U;wure eku gS

(4) bueas ls dksbZ ugha

48. If a parallel resonant circuit is shunted by a resistance, then: (1) The circuit impedance is increased. (2) Q of the circuit is increased (3) The gain of the circuit is increased (4) The circuit impedance is decreased.

48. ;fn ,d lekukarj vuquknh ifjiFk dks izfrjks/kd kjk ik”oZ ifFkr

fd;k tkrk gS rks%

(1) ifjiFk izfrck/kk c<+ tkrh gS

(2) ifjiFk dk Q c<+ tkrk gS (3) ifjiFk dh yfC/k c<+ tkrh gS

(4) ifjiFk dh izfrck/kk ?kV tkrh gS

49. The purpose of having a commutator and brush arrangement in a dc motor is: (1) To produce a unidirectional torque (2) To produce a unidirectional current in the armature (3) To help in changing the direction of rotation of the

armature (4) To reduce eddy current loss in armature

49. dc eksVj esa ,d fnd~ifjorZd vkSj cz”k O;oLFkk j[kus dk iz;kstu

gksrk gS%

(1) vfn”kkRed cy vk?kw.kZ mRiUu djuk

(2) vkesZpj esa ,d vfn”kkRed /kkjk mRiUu djuk

(3) vkesZpj ds Qsjs dh fn”kk cnyus esa enn djuk

(4) vkesZpj esa Hkaoj /kkjk gkfu de djuk

50. Under full load running condition, the slip of a synchronous motor is: (1) About 0.01 (2) About 0.1 (3) Zero (4) Unity

50. iw.kZ yksM pkyw fLFkfr esa] rqY;dkfyd eksVj dk foliZ.k gS yxHkx%

(1) yxHkx 0.01 (2) yxHkx 0.1 (3) “kwU; (4) ;wfuVh

51. The direction of rotation of an ordinary shaded pole single phase induction motor: (1) Can be reversed by reversing the supply terminal

connections to the stator winding (2) Cannot be reversed (3) Can be reversed by open-circuiting the shading ring. (4) Can be reversed by short-circuiting the shading ring.

51. lkekU; Nkfnr /kzqo ,dy dyk izsj.k eksVj ds Qsjs dh fn”kk%

(1) vkiwfrZ VfeZuy la;kstuksa dks mRØfer djds mRØfer dh tk

ldrh gS

(2) mRØfer ugha dh tk ldrh

(3) Nknu foy; ds foo`r ifjiFku kjk mRØfer dh tk ldrh gS

(4) Nknu foy; ds y?kq&ifjiFku kjk mRØfer dh tk ldrh gS

52. A modern semiconductor device that combines the characteristics of BJT and MOSFET is: (1) IGBT (2) GTO (3) MCT (4) FCT

52. ,d vk/kqfud v)Zpkyd midj.k tks BJT vkSj MOSFET dh fo”ks’krkvksa dks tksM+rk gS] gS%

(1) IGBT (2) GTO (3) MCT (4) FCT

53. The snubber circuit is used in thyristor circuit for: (1) Triggering (2) dv/dt protection (3) di/dt protection (4) Phase shifting

53. FkkbZfjLVj ifjiFk esa iz.kkyh ÅtkZ vo”kks’kd ifjiFk dk iz;ksx fuEu ds

fy, fd;k tkrk gS%

(1) leizorZu (2) dv/dt lqjkk (3) di/dt lqjkk (4) dyk foLFkkiu

54. The total harmonic distortion (THD) of ac supply input current of rectifiers is maximum for: (1) Single-phase diode rectifier with dc inductive filter (2) 3-phase diode rectifier with dc inductive filter (3) 3-phase thyristor rectifier with inductive filter (4) Single-phase diode rectifier with capacitive filter

54. fn’Vdkfj;ksa dh a.c. vkiwfrZ fuos”k/kkjk dh lexz gkeksZuh fod`fr

¼THD½ fuEu ds fy, vf/kdre gksrh gS%

(1) d.c. izsjd fuL;and lfgr ,dy&dyk Mk;ksM fn’Vdkjh (2) d.c. izsjd fuL;and lfgr 3&dyk Mk;ksM fn’Vdkjh

(3) izsjd fuL;and lfgr 3-dyk FkkbZfjLVj fn’Vdkjh (4) /kkfjr fuL;and lfgr ,dy&dyk Mk;ksM fn’Vdkjh

55. Starting torque of a three-phase squirrel cage induction motor at rated voltage is: (1) 30% to 40% of the rated torque (2) The rated torque (3) 100% to 200% of the rated torque (4) 5 to 7 times of the rated torque

55. fu/kkZfjr oksYVrk ij ,d rhu Qst okyh fiatjh çsj.kh dk çkjfEHkd

cy vk?kw.kZ gS%

(1) fu/kkZfjr cy vk?kw.kZ dk 30% ls 40% rd

(2) fu/kkZfjr cy vk?kw.kZ

(3) fu/kkZfjr cy vk?kw.kZ dk 100% ls 200% rd

(4) fu/kkZfjr cy vk?kw.kZ dk 5 ls 7% xquk

PAPER – II_Electrical [ 5 2 0 5 6 6 ] NFCX5 [ A–6 ]

56. A four quadrant chopper can not be operated as: (1) One quadrant chopper (2) Inverter (3) Cycloconverter (4) Bi-directional rectifier

56. pkj DokMsaZV ladrÊ ¼pkSij½ dks fuEu :i esa izpkfyr ugha fd;k tk

ldrk%

(1) ,dy DokMZsaV ladrÊ (2) bUoVZj (3) lkbdyksduoVZj (4) Bi-fn”kkRed fn’Vdkjh

57. Which of the following is not the same as watt? (1) Joule / Sec. (2) (Ampere)2X ohm (3) (Volt)2 /ohm (4) Volt / Ampere

57. fuEufyf[kr esa ls dkSu&lk ,d okWV dh rjg ugha gS\

(1) Joule / Sec. (2) (Ampere)2X ohm (3) (Volt)2 /ohm (4) Volt / Ampere

58. Lap winding is most suitable for: (1) Low voltage, low current machine (2) High voltage, high current machine (3) Low voltage, high current machine (4) High voltage, low current machine

58. ySi okbZfUMax lcls T;knk mi;ksxh gksrk gS%

(1) fuEu oksYVrk] fuEu /kkjk e'khuksa gsrq

(2) mPp oksYVrk] mPp /kkjk e'khuksa gsrq

(3) fuEu oksYVrk] mPp /kkjk e'khuksa gsrq

(4) mPp oksYVrk] fuEu /kkjk e'khuksa gsrq

59. A double squirrel cage induction motor has two: (1) Rotors moving in opposite direction (2) Parallel windings on rotor (3) Parallel windings on stator (4) Series windings in stator

59. ,d ffiatjh izsjd eksVj esa gksrs gSa%

(1) foijhr fn”kkvksa esa pyus okys nks jksVj

(2) jksVj ij nks lekukarj okbafMax

(3) LVSVj ij lekukarj okbafMax

(4) LVSVj esa Js.kh okbafMax

60. No load test on a three-phase squirrel cage induction motor at rated voltage is performed to obtain: (1) Stator and rotor resistance and reactance (2) Series branch parameters of equivalent circuit (3) Copper and core losses (4) Shunt branch parameters of equivalent circuit

60. ,d rhu&Qsl okys LDoSjy fiatjh çsjd eksVj ij fu/kkZfjr oksYVrk nj

Hkkj ghu ijhk.k fd;k tkrk gSA blls çkIr fd;k tkrk gS%

(1) LVsVj vkSj jksVj dh çfrjks/kdrk rFkk çfrdkRedrk

(2) leku ifjiFk ds Js.kh “kk[kk dkjdksa dks

(3) rk¡ck vkSj ØksM gkfu

(4) leku ifjiFk ds “kaV “kk[kk dkjdksa dks

61. The maximum power that can be transmitted in a network between sources and loads when the system is subject to small disturbances is called: (1) Steady-State Stability Limit (2) Transient Stability Limit (3) Sub-Transient Stability Limit (4) None of the Above

61. ra= esa tc NksVs&NksVs fokksHk gks jgs gksa rc lzksr rFkk Hkkj ds chp

fdlh latky esa tks vf/kdre “kfä çsf’kr dh tk ldrh gS mls dgrs

gS%

(1) fLFkj&voLFkk LFkkf;Ro lhek

(2) kf.kd&LFkkf;Ro lhek

(3) mi kf.kd&LFkkf;Ro lhek

(4) buesa ls dksbZ ugha

62. During hunting of a synchronous motor: (1) Negative sequence currents are generated. (2) Harmonics are developed in the armature circuit. (3) Damper bars develop torque (4) Field excitation increases.

62. rqY;dkfyd eksVj ds pky nksyu ¼hunting½ ds nkSjku% (1) _.kkRed Øe /kkjk,a tfur gksrh gSa

(2) vkesZpj ifjiFk esa gkeksZfud fodflr gksrs gSa

(3) voeand naM cy&vk?kw.kZ fodflr djrs gSa

(4) ks= mÙkstu c<+rk gS

63. In an induction motor, if the air gap is increased,: (1) Speed will reduce (2) Efficiency will improve (3) Power factor will be lowered (4) Breakdown torque will reduce

63. fdlh çsj.k eksVj esa ;fn ok;q varjky c<+k;k tkrk gS rks%

(1) pky ?kV tk,xh

(2) nkrk lq/kjsxh

(3) 'kfä xq.kd de gksxh

(4) Hkatd cy&vk?kw.kZ ?kV tk,xk

64. To conduct Sumpners test on a transformer: (1) Only one transformer is sufficient (2) Two identical transformers are needed (3) Two un-identical transformers are needed (4) At least three transformers are necessary

64. VªkUlQkeZj dk lEiuj ijhk.k djus ds fy,%

(1) dsoy ,d VªkUlQkeZj i;kZIr gS

(2) nks leku VªkUlQkeZjksa dh vko”;drk iM+rh gS

(3) nks vleku VªkUlQkeZjksa dh vko”;drk iM+rh gS

(4) de ls de rhu VªkUlQkeZjksa dh vko”;drk iM+rh gS

65. Electrostatic instruments are suitable for the measurement of: (1) ac and dc voltages (2) ac voltage and current (3) dc voltage and current (4) ac and dc currents

65. fLFkj oS|qr ¼bysDVªksLVSfVd½ ;a= fdlds ekiu ds fy, mi;qä gksrs gSa\

(1) ac vkSj dc oksYVrk (2) ac oksYVrk vkSj /kkjk

(3) dc oksYVrk vkSj /kkjk (4) ac vkSj dc /kkjk

PAPER – II_Electrical [ 5 2 0 5 6 6 ] NFCX5 [ A–7 ]

66. Please refer figure showing oil pot with electrodes used for testing dielectric strength of transformer oil. The gap between two electrodes is 4 mm and the pot is filled with oil.

The pot is placed in the oil testing kit and it is observed that breakdown occurs at 16KV. The dielectric strength of oil is: (1) 16KV/cm (2) 20 KV/cm (3) 40KV/cm (4) 50KV/cm

66. fuEufyf[kr lanfHkZr fp= esa VªkUlQkeZj rsy dh ijkoS|qr lkeF;Z

ijhk.k gsrq ç;qä bysDVªkM lfgr rsy dk crZu n”kkZ;k x;k gSA nks

bysDVªkWM ds e/; vUrjky gS 4 mm ,oa crZu rsy ls Hkjk gqvk gSA

crZu dks rsy ijhk.k fdV esa Mkyk tkrk gS ,oa ;g voyksfdr fd;k

tkrk gS fd czsd Mkmu 16 KV ij ?kfVr gksrk gSA rsy dk ijkoS|qr lkeF;Z gksxk%

(1) 16KV/cm (2) 20 KV/cm (3) 40KV/cm (4) 50KV/cm

67. To neglect a current source, the terminal across the sources are: (1) Open-circuited (2) Short-circuited (3) Replaced by some resistance (4) Replaced by capacitance

67. ,d /kkjk Jksr dh vogsyuk djus ds fy,] Jksrksa ds vkj&ikj VfeZuy

gksrk gS%

(1) eqä ifjifFkr

(2) y?kq ifjifFkr

(3) fdlh çfrjks/k kjk çfrLFkkfir

(4) /kkfj= kjk çfrLFkkfir

68. Which of the following combination of 3-phase transformers can be successfully operated in parallel: (1) ∆-Υ and ∆-Υ (2) Υ-Υ and ∆-Υ (3) ∆-∆ and ∆-Υ (4) Υ-∆ and ∆-∆

68. fuEufyf[kr esa ls dkSu&lk f=dyk VªkalQkeZj dk la;kstu lekukUrj esa

lQyrk iwoZd çpkfyr fd;k tk ldrk gS%

(1) ∆-Υ ,oa ∆-Υ (2) Υ-Υ ,oa ∆-Υ (3) ∆-∆ ,oa ∆-Υ (4) Υ-∆ ,oa ∆-∆

69. Three phase step-up transformer installed at power house, just before commencement of transmission line, have: (1) DELTA–DELTA connection (2) STAR–STAR connections (3) STAR–DELTA connections (4) DELTA–STAR connections

69. f=dyk LVsi&vi VªkalQkeZj esa] tks ikWoj gkml esa LFkkfir fd;s tkrs

gSa lapj.k ykbZuksa ds vkjEHk gksus ls Bhd iwoZ] gksrk gS%

(1) MsYVk&MYVk vkca/ku

(2) LVkj&LVkj vkca/ku

(3) LVkj&MsYVk vkca/ku

(4) MsYVk&LVkj vkca/ku

70. Which of the following theorem uses current generator: (1) Superposition theorem (2) Maximum power transfer theorem (3) Thevenin’s theorem (4) Norton’s theorem

70. fuEu esa ls dkSu&lk izes; /kkjk tsujsVj dk iz;ksx djrk gS\

(1) v/;kjksi.k izes;

(2) vf/kdre “kfDr varj.k izes;

(3) FkSofuu izes;

(4) ukVZu izes;

71. When the series field is so connected that its ampere-turns act in the same direction as those of shunt field, the generator is said to be: (1) Shunt generator (2) Differentially compound generator (3) Series generator (4) Cumulatively compound generator

71. tc Js.kh ks= dks bl izdkj la;ksftr fd;k tkrk gS fd blds ,sEih;j

Qsjs mlh fn”kk esa pyrs gSa tks “kaV ks= dh gS] rks tsujsVj dgk tkrk gS%

(1) “kaV tsujsVj

(2) foHksnh lfEeJ tsujsVj

(3) Js.kh tsujsVj

(4) lap;h lfEeJ tsujsVj

72. Voltage stress is maximum in a cable at the surface of the: (1) Sheath (2) Conductor (3) Insulator (4) None of these

72. dscy esa fuEu dh lrg ij oksYVrk izfrcy vf/kdre gksrk gS%

(1) “khFk (2) pkyd (3) fo|qr&jks/kh (4) bueas ls dksbZ ugha

73. Which of the following instruments is generally used for measuring d.c. current: (1) M. C. type (2) M. I. type (3) Dynamometer type (4) Induction type

73. d.c. /kkjk dks ekius ds fy, fuEukafdr midj.kksa esa ls dkSu&lk

lkekU;r% ç;ksx fd;k tkrk gS%

(1) M. C. Vkbi (2) M. I. Vkbi (3) Mk;ueksehVj Vkbi (4) çsj.k Vkbi

PAPER – II_Electrical [ 5 2 0 5 6 6 ] NFCX5 [ A–8 ]

74. Two capacitors of capacitances 3 µF and 6 µF in series will have a total capacitance of: (1) 9 µF (2) 2 µF (3) 18 µF (4) 24 µF

74. Js.kh esa 3 µF vkSj 6 µF /kkfjrk ds nks la/kkfj=ksa dh dqy /kkfjrk gksxh%

(1) 9 µF (2) 2 µF (3) 18 µF (4) 24 µF

75. A 3-phase delta connected motor is supplied at a line voltage of 400 V, the voltage across each winding of the motor will be: (1) 400 V (2) 200 V (3) 100 V (4) 300 V

75. ,d f=dyk MsYVk vkc) eksVj dks 400 V dh ykbZu oksYVrk vkiwfrZ

dh tkrh gS] eksVj ds çR;sd okbZfUMax ds vkj&ikj oksYVrk gksxh%

(1) 400 V (2) 200 V (3) 100 V (4) 300 V

76. A 6 pole Lap wound dc generator has 300 conductors. Emf induced per conductor is 5 volt. This generator will generate emf of: (1) 60 volt (2) 300 volt (3) 250 volt (4) 1800 volt

76. ,d 6 /kzqo okyh ySi okmUM dc tfu= esa 300 pkyd gSaA çfr pkyd esa çsfjr emf 5 oksYV gSA ;g tfu= emf mRié djsxk% (1) 60 oksYV (2) 300 oksYV (3) 250 oksYV (4) 1800 oksYV

77. Holes are drilled on opposite site of the disc of an induction type energy meter to: (1) Prevent creeping (2) Balance the disc (3) Dissipate energy due to eddy current (4) Increase the deflecting torque

77. çsj.k çdkj ds ÅtkZ ehVj ds ,d fMLd ds foijhr LFky ij fNæ

fNfær fd;s tkrs gSa%

(1) Øhfiax dks jksdus ds fy,

(2) fMLd dks larqfyr djus ds fy,

(3) ÅtkZ dks ,ìh /kkjk ds dkj.k folfjr djus ds fy,

(4) voksi.k cy vk?kw.kZ esa o`f) djus ds fy,

78. When a hot-plate is connected to the mains, its element becomes red hot, but copper wire in the leads remain cool. This is due to: (1) The element is coiled, but the copper wire is not (2) Length of the element is more than the copper wire (3) Copper wire is thinner than the element (4) The element has a high resistance than the copper

wire

78. ;fn ,d rIr&IysV esUl ls vkc) gS] rks bldk rRo yky xje gks

tkrk gS] ysfdu yhM rkez esa rkjsa “khryhr jgrh gSaA ;g blds dkj.k

gS%

(1) rRo dqaMfyr gSa ysfdu rkez rkjsa ugha

(2) rRo dh yEckbZ rkez rkjksa ls T;knk gS

(3) rkez rkjsa rRoksa ls iryh gSa

(4) rkez rkjksa ls rRoksa dk çfrjks/k mPp gS

79. The iron losses in a 100 kvA transformer are 1 kw and the full load copper losses are 2 kw, then maximum efficiency occurs at a load of: (1) 100√2 kvA (2) 100/√2 (3) 50 kvA (4) None of these

79. 100 kvA VªkUlQkeZj esa ykSg gkfu 1 kw gS ,oa iw.kZ Hkkj rkez gkfu

2 kw gS] rks vf/kdre nkrk fdl Hkkj ?kfVr gksxh%

(1) 100√2 kvA (2) 100/√2 (3) 50 kvA (4) buesa ls dksbZ ugha

80. Which is the correct statement: (1) In a dc commutator motor, the rotor has permanent magnet (2) In a brush less dc motor, the rotor has permanent magnet (3) In a hybrid stepper motor, the stator has a permanent

magnet (4) Multi stack variable reluctance motor has permanent

magnet on rotor

80. buesa ls dkSu&lk dFku lgh gS%

(1) ,d Mh-lh- dE;wVsVj eksVj esa ?kw.kZd esa LFkkbZ pqEcd gksrk gS

(2) fcuk cz”k okyh Mh-lh- eksVj esa ?kw.kZd esa LFkkbZ pqEcd gksrk gS

(3) ,d ladj LVsij eksVj esa LVsVj esa LFkkbZ pqEcd gksrk gS%

(4) eYVh LVsd pj çfr’VEHk eksVj esa ?kw.kZd esa LFkkbZ pqEcd gksrk gS

81. Which of the following 1-phase induction motor has highest starting torque: (1) Split-Phase (2) Capacitor-Start (3) Capacitor-Run (4) Capacitor-Start, Capacitor-Run

81. fuEukafdr esa ls dkSu lh 1&Qst okyh çsj.k eksVj esa mPpre çorZu cy vk?kw.kZ gksrk gS%

(1) foHkä&Qst

(2) la/kkfj=&çofrZr

(3) la/kkfj=&pfyr

(4) la/kkfj=&çofrZr] la/kkfj=&pfyr

82. A system has the transfer function s1s–1

+, known as:

(1) Low pass system (2) High pass system (3) All pass system (4) Band pass system

82. fdlh ra= dk vUrj.k Qyu gS s1s–1

+] fdl uke ls tkuk tkrk gS\

(1) fuEu ikjd ra= (2) mPp ikjd ra= (3) loZ ikjd ra= (4) cSaM ikjd ra=

PAPER – II_Electrical [ 5 2 0 5 6 6 ] NFCX5 [ A–9 ]

83. For the grounding of an entire sub–station: (1) Counterpoises are used (2) Grounding rods are used (3) Grounding mats are used (4) Peterson coil is used

83. laiw.kZ lc&LVs'ku ds Hkw&laidZu ds fy,%

(1) çfrrksy ç;ksx fd, tkrs gSa

(2) Hkw&laidZu NM+ ç;ksx fd, tkrs gSa

(3) Hkw&laidZu eSV ç;ksx fd, tkrs gSa

(4) ihVjlu dqaMyh ç;ksx dh tkrh gS

84. Gain margin is the reciprocal of gain at the frequency at which the phase angle becomes: (1) 0° (2) 90° (3) 180° (4) 270°

84. mikUr yfC/k ¼gain margin½] yfC/k dh vU;ksU; ml vko`fÙk ij

gksrh gS ftl ij dyk dks.k%

(1) 0° gksrk gS (2) 90° gksrk gS (3) 180° gksrk gS (4) 270° gksrk gS

85. To limit short circuit currents, use: (1) Series reactor (2) Series capacitors (3) Shunt reactors (4) Shunt capacitors

85. “kkWVZ lfdZV /kkjk dks lhfer djus ds fy;s ç;ksx djrs gSa%

(1) Js.kh fj,DVj (2) Js.kh la/kkfj= (3) ik”oZiFk fj,DVj (4) ik”oZiFk la/kkfj=

86. An electron has: (1) Negative charge (2) Fixed positive charge (3) Variable positive charge (4) None of these

86. ,d bysDVªksu esa gksrk gS%

(1) _.kkRed vkos”k (2) fu;r /kukRed vkos”k (3) ifjorhZ /kukRed vkos”k (4) buesa ls dksbZ ugha

87. Two bulbs of rating 60W, 250V and 100W, 250V are connected in series across a supply of 250V in a room. What will be the total power dissipation in the circuit? (1) 37.5 W (2) 60.0 W (3) 100.0 W (4) 160.0 W

87. 60W, 250V rFkk 100W, 250V ds fu/kkZj okys nks cYc ,d dejs esa 250V dh vkiwfrZ ds chp Ja`[kyk esa tksM+s tkrs gSaA ifjiFk esa dqy

fo|qr k; fdruk gksxk\

(1) 37.5 W (2) 60.0 W (3) 100.0 W (4) 160.0 W

88. How is the burden of current transformer expressed? (1) Secondary winding current (2) VA rating of transformer (3) Voltage, current and power factor of secondary

winding circuit (4) Turns ratio

88. ,d /kkjk VªkalQkeZj dk Hkkj dSls O;ä fd;k tkrk gS\

(1) frh;d okb±fMax /kkjk

(2) VªkalQkeZj dk VA fu/kkZj.k (3) frh;d okb±fMax ifjiFk dh oksYVrk] /kkjk vkSj 'kfä xq.kd

(4) Qsjk vuqikr

89. Main purpose of using oil in oil circuit breaker is to: (1) Provide insulation between oil circuit breaker contacts (2) Provide cooling of contacts (3) Quenching arc (4) None of these

89. vk;y lfdZV cszdj esa vk;y dk ç;ksx djus dk eq[; mn~ns'; gksrk gS%

(1) vk;y lfdZV czsdj dkUVSDV~l ds e/; bUlwys'ku çnku djuk

(2) dkUVSDV~l dks dwfyax çnku djuk

(3) DoSfUpx vkdZ

(4) buesa ls dksbZ ugha

90. A capacitor opposes: (1) Change in current (2) Change in voltage (3) Both change in current and voltage (4) None of these

90. ,d dSisflVj fojks/k djrk gS%

(1) /kkjk esa ifjorZu

(2) oksYVrk esa ifjorZu

(3) /kkjk ,oa oksYVrk nksuksa esa ifjorZu

(4) buesa ls dksbZ ugha

91. What is the cause of occurrence of stray load losses in transformer? (1) Leakage flux (2) Poor cooling (3) Overloading (4) Under frequency operation

91. VªkalQkeZj esa LVªs Hkkj gkfu dk D;k dkj.k gS\

(1) kj.k ¶yDl (2) U;wu 'khru (3) vf/kHkkj (4) vYi vko`fÙk çpkyu

92. The sag of a transmission line depends upon: (1) Weight of conductor and directly proportional to span

length (2) Weight of conductor and inversely proportional to span

length (3) Weight of conductor and directly proportional to

square of span length (4) Weight of conductor and inversely proportional to

square of span length

92. ,d lapj.k ykbu dk >ksy ¼lSx½ fuEu ij fuHkZj djrk gS%

(1) pkyd dk Hkkj vkSj foLr`fr yEckbZ ds çfr vuqØekuqikr

(2) pkyd dk Hkkj vkSj foLr`fr yEckbZ ds çfr O;qrØekuqikr

(3) pkyd dk Hkkj vkSj foLr`fr yEckbZ ds oxZ ds çfr vuqØekuqikr

(4) pkyd dk Hkkj vkSj foLr`fr yEckbZ ds oxZ ds çfr O;qrØekuqikr

PAPER – II_Electrical [ 5 2 0 5 6 6 ] NFCX5 [ A–10 ]

93. In a Kelvin’s double bridge, two set of readings are taken when measuring a low resistance, one with the current in one direction and the other with direction of current reversed. This is done to: (1) Eliminate the effect of contact resistance (2) Eliminate the effect of resistance of leads (3) Correct for changes in battery voltage (4) Eliminate the effect of thermo-electric effects

93. ,d dSfYou flsrq esa] ,d U;wu çfrjks/k ekirs le; iBuksa ds nks lsV

fy, tkrs gSa ftlesa ls ,d esa /kkjk ,d fn'kk esa gksrh gS vkSj nwljs esa

/kkjk dh fn'kk iyV nh tkrh gSA ;g fuEu ç;kstu ls fd;k tkrk gS%

(1) lEidZ çfrjks/k ds çHkko dks fujLr djuk

(2) yhMksa ds çfrjks/k ds çHkko dh fujLr djuk

(3) cSVjh oksYVrk esa cnykoksa ds fy, 'kq) djuk

(4) rkih;&fo|qr çHkkoksa ds vlj dks fujLr djuk

94. If two supply terminals of a 3φ induction motor are interchanged, then the: (1) Speed of the motor will become zero (2) Speed of the motor will increase (3) Motor will continue to run in the same direction with

less speed (4) Motor will rotate in the opposite direction

94. ;fn 3φ izsj.k eksVj ds nks vkiwfrZ VfeZuyksa dks vkil esa cny fn;k

tkrk gS rks%

(1) eksVj dh pky “kwU; gks tk,xh

(2) eksVj dh pky c<+ tk,xh

(3) eksVj de pky ij mlh fn”kk esa pyrh jgsxh

(4) eksVj mYVh fn”kk esa ?kwerh jgsxh

95. The function of conservator in a transformer is to: (1) Store extra oil to be used in emergency (2) Prevent entry of moisture (3) Cool transformer (4) Take care of expansion and contraction of oil due to

change in temperature of oil

95. VªkalQkeZj esa datjosVj dk dk;Z gksrk gS%

(1) vkikrdkyhu n”kkvksa esa ç;ksx djus ds fy, vfrfjä rsy dk HkaMkj.k

(2) vkæZrk ds ços”k dks jksduk

(3) VªkalQkeZj dks “khryhr djuk

(4) rsy ds rkiØe esa ifjorZu ds dkj.k rsy esa QSyko ,oa ladqpu

dh ns[kHkky djuk

96. Critical speed of a DC shunt generator is the speed below which: (1) The generator fails to build up voltage (2) The generator build up voltage (3) The generator can not take load (4) The generator can take load

96. DC ik”oZiFk tfu= dh ØkfUrd pky og pky gksrh gS ftl pky ds

uhps%

(1) tfu= oksYVst cukus esa vlQy jgrk gS

(2) tfu= oksYVst cukrk gS

(3) tfu= Hkkj ugha ys ldrk

(4) tfu= Hkkj ys ldrk gS

97. A cylindrical rotor synchronous motor is switched on to the supply with its field winding shorted on themselves. It will: (1) Not start. (2) Start but not run at synchronous speed. (3) Start as an induction motor and then run run as a

synchronous motor. (4) Start and run as a synchronous motor.

97. ,d csyukdkj jksVj rqY;dkfyd eksVj bldh ks= dqaMyh ftls mu ij

de dj fn;k x;k gS] pkyw gSA ;g%

(1) LVkVZ ugha gksxh

(2) LVkVZ gksxh fdUrq rqY;dkfyd xfr ij ugha pysxh

(3) çsj.k eksVj dh Hkk¡fr LVkVZ gksxh vkSj rc ckn esa rqY; dkfyd

eksVj dh Hkk¡fr pysxh

(4) LVkVZ gksxh vkSj ks= mÙkstu c<+sxk

98. Core of transformer is made of good quality material like CRGO steel to minimize: (1) Eddy current loss (2) Full load copper loss (3) Hysteresis loss (4) No load copper loss

98. VªkalQkeZj dk dksj vPNh xq.koÙkk okys inkFkZ dk cuk gksrk gS tSls fd

CRGO bLikr rkfd fuEufyf[kr U;wure fd;k tk lds%

(1) ,ìh /kkjk gkfu (2) iw.kZ Hkkj rkez gkfu (3) fgLVsjsfll gkfu (4) “kwU; Hkkj rkez gkfu

99. Megger is an instrument for: (1) Measuring current (2) Measuring voltage (3) Testing insulation (4) Measuring power

99. esxj ,d midj.k gS%

(1) /kkjk ekius dk (2) oksYVrk ekius dk (3) bUlqys'ku ijhk.k dk (4) 'kfä ekius dk

100. For the measurement of the earth resistance of a given earth electrode: (1) Collecting electrode should be very near to the

electrode under test (2) Collecting electrode should touch the electrode under

test (3) Collecting electrode should be far away the electrode

under test (4) None of these

100. fdlh ,d HkkSe&bysDVªksM dk Hkw&izfrjks/k ekius ds fy,% (1) xzkgh bysDVªksM ijhk.kk/khu bysDVªksM ds cgqr fudV gksuk pkfg,%

(2) xzkgh bysDVªksM dks ijhk.kk/khu bysDVªksM dk Li”kZ djuk pkfg,

(3) xzkgh bysDVªksM ijhk.kk/khu bysDVªksM ls cgqr nwj gksuk pkfg,

(4) buesa ls dksbZ ugha

PAPER – II_Electrical [ 5 2 0 5 6 6 ] NFCX5 [ A–11 ]

101. The material used for fuse wire should have the following characteristics: (1) Low melting point, high conductivity (2) High melting point, low conductivity (3) Highly malleable and coercive (4) High resistance, low melting point

101. ¶;wt rkj ds fy, ç;qä lkexzh esa fuEu fo'ks"krk,a gksuh pkfg,%

(1) U;wu xyukad] mPp pkydrk

(2) mPp xyukad] U;wu pkydrk

(3) vR;Ur vk?kkro/;Z vkSj fuxzkgh

(4) mPp çfrjks/k] U;wu xyukad

102. Which of the following insulators will be selected for high voltage transmission? (1) Pin (2) Strain (3) Shackle (4) Suspension

102. mPp oksYVrk lapkj.k ds fy, fuEukafdr esa ls fdl fo|qrjks/kh dk p;u fd;k tk,xk\

(1) fiu (2) foÑfr (3) 'kSdy (4) fuyaEcu

103. In d.c. generator armature reaction is produced by: (1) Field or armature current (2) Field and armature current (3) Field current (4) Armature current

103. d.c. tfu= esa vkesZpj vfHkfØ;k fuEu kjk mRiUu dh tkrh gS%

(1) ks= vFkok vkesZpj /kkjk kjk

(2) ks= rFkk vkesZpj /kkjk kjk

(3) ks= /kkjk kjk

(4) vkesZpj /kkjk kjk

104. A dc motor works on the principle of: (1) Fleming’s right hand rule (2) Fleming’s left hand rule (3) Right hand thumb rule (4) Cork screw rule

104. dc eksVj fuEu ds fl)kar ij dke djrh gS%

(1) ¶ysfeax dk nfk.k gLrfu;e

(2) ¶ysfeax dk oke gLrfu;e

(3) nfk.k gLr FkEc fu;e

(4) dkdZ LØw fu;e

105. A fuse is provided in an electrical circuit to: (1) Reduce the power consumption in the circuit (2) Limit the current in the circuit (3) Safeguard the circuit against heavy current (4) Increase the current in the circuit

105. fo|qr ifjiFk esa ¶;wt fuEu iz;kstu ls yxk;k tkrk gS% (1) ifjiFk esa fctyh dh [kir de djuk

(2) ifjiFk esa /kkjk lhfer djuk

(3) ifjiFk dks Hkkjh /kkjk ls lqjfkr j[kuk

(4) ifjiFk esa /kkjk c<+kuk

106. The e.m.f induced is 2V when current is changing at the rate of 0.5A/s. The self inductance of coil is: (1) 4 (2) 2 (3) 1 (4) None of these

106. tc /kkjk 0.5A/s dh xfr ls cny jgh gS] gzkflr emf 2V gSA dkW;y dk Lo&izsjdRo gS%

(1) 4 (2) 2 (3) 1 (4) buesa ls dksbZ ugha

107. Resistivity of copper is: (1) Less than aluminium (2) More than aluminium (3) Equal to aluminium (4) Exactly twice than aluminium

107. rkez dh jsflLVhfoVh gksrh gS% (1) ,Y;wfefu;e ls de

(2) ,Y;wfefu;e ls vf/kd

(3) ,Y;wfefu;e ds cjkcj

(4) ,Y;wfefu;e ds Bhd nqxquk

108. In a a.c. circuit , then the power

factor of a.c. circuit will be: )wtcos(10i

)60wtsin(50=

+=υ o

(1) 0.5 lag (2) 0.5 lead (3) 0.866 lag (4) 0.866 lead

108. ,d a.c. ifjiFk esa] a.c. ifjiFk dk “kfDr

xq.kd gksxk%

)wtcos(10i)60wtsin(50

=+=υ o

(1) 0.5 i”p (2) 0.5 vxz

(3) 0.866 i”p (4) 0.866 vxz

109. An inductor L is connected across the 220 volts d.c. supply. What will be the reactance? (1) L (2) wL (3) Zero (4) None of these

109. izsjd L dks 220 oksYV Mhlh vkiwfrZ esa la;ksftr fd;k tkrk gSA bldk

izfr?kkr fdruk gksxk\

(1) L (2) wL (3) “kwU; (4) buesa ls dksbZ ugha

110. Magnitude of the electric shock on human body depends upon: (1) The line voltage (2) The line current (3) The line voltage and line current (4) Current flowing through human body

110. euq’; ds “kjhj ij fctyh ds >Vds dh ek=k fuEu ij fuHkZj djrh gS%

(1) ykbu oksYVrk

(2) ykbu /kkjk

(3) ykbu oksYVrk rFkk ykbu /kkjk

(4) euq’; ds “kjhj esa izokfgr gks jgh /kkjk

PAPER – II_Electrical [ 5 2 0 5 6 6 ] NFCX5 [ A–12 ]

111. 40 ampere hour capacity would deliver a current of: (1) 40 amps for 1 hour (2) 20 amps for 2 hour (3) 5 amps for 8 hour (4) 1 amp for 40 hour

111. 40 ,Eih;j ?kaVk kerk uhps of.kZr /kkjk miyC/k djk,xh% (1) 1 ?kaVs ds fy, 40 ,Eih;j (2) 2 ?kaVs ds fy, 20 ,Eih;j (3) 8 ?kaVs ds fy, 5 ,Eih;j (4) 40 ?kaVs ds fy, 1 ,Eih;j

112. The power of an inductive series circuit is 0.8 lag. If the magnitude of current is 15 Amp then it can be expressed in complex form as: (1) 12-j9 (2) 9-j12 (3) 12+j9 (4) 9+j12

112. ,d izsjd Js.kh ifjiFk dh “kfDr 0.8 lag gSA ;fn /kkjk dh ek=k 15 Amp gS rks mls lfEeJ :i esa fuEukuqlkj O;Dr fd;k tk ldrk gS%

(1) 12-j9 (2) 9-j12 (3) 12+j9 (4) 9+j12

113. When localizing ground fault with the help of a loop test, the resistance of a fault: (1) Affects the balance condition (2) Affects the value of the cable resistance (3) Affects the sensitivity of the bridge (4) All of these

113. ywi ijhk.k ds ek/;e ls Hkwnks’k dks LFkkuxr djrs le;] nks’k dk izfrjks/k%

(1) larqyu fLFkfr dks izHkkfor djrk gS

(2) dscy izfrjks/k ds eku dks izHkkfor djrk gS

(3) lsrq dh laos|rk dks izHkkfor djrk gS

(4) mi;qZDr lHkh

114. The advantage of the Varley loop test over Murray loop test is: (1) Can be used for localizing the short circuit fault (2) Loop resistance can be determined (3) Can be used for localizing the earth fault (4) Their accuracy is higher

114. ejsZ ywi ijhk.k dh rqyuk esa okjys ywi ijhk.k dk ykHk gS% (1) bldk iz;ksx y?kqiFk nks’k dks LFkkuxr djus ds fy, fd;k tk ldrk gS

(2) ywi izfrjks/k dk fu/kkZj.k fd;k tk ldrk gS

(3) bldk iz;ksx Hkwnks’k dks LFkkuxr djus ds fy, fd;k tk ldrk gS

(4) mudh “kq)rk mPprj gksrh gS

115. The addition of ground rods in the earthing grid: (1) Decrease the earth resistance (2) Has no effect on earth resistance (3) Slightly decrease the earth resistance (4) Slightly increase the earth resistance

115. Hkw&laidZu fxzM esa Hkw&NM+ksa dh o`f)%

(1) Hkw&izfrjks/k de djrh gS

(2) Hkw&izfrjks/k ij dksbZ izHkko ugha iM+rk

(3) Hkw&izfrjks/k rfud de djrh gS

(4) Hkw&izfrjks/k rfud c<+k nsrh gS

116. A horn load unit: (1) Increase the acoustic output (2) Decrease the acoustic output (3) Multiplies the acoustic output (4) None of these

116. gkuZ Hkkj ;wfuV% (1) /ofud mRiknu c<+k nsrk gS

(2) /ofud mRiknu ?kVk nsrk gS

(3) /ofud mRiknu dbZ xquk dj nsrk gS

(4) buesa ls dksbZ ugha

117. The relation between the frequency n, wavelength λ and velocity of propagation v of the wave is: (1) v=n λ (2) λ=nv (3) n=v/ λ (4) None of these

117. rjax dh vko`fRr n, rjaxnS/;Z λ rFkk lapj.k ds osx v ds chp dk laca/k gksrk gS%

(1) v=n λ (2) λ=nv (3) n=v/ λ (4) buesa ls dksbZ ugha

118. In AM: (1) The phase remains constant (2) The amplitude remains constant (3) The frequency remains constant (4) None of these

118. AM esa% (1) izkoLFkk vifjorhZ jgrh gS

(2) vk;ke vifjorhZ jgrk gS

(3) vko`fRr vifjorhZ jgrh gS

(4) mi;qZDr esa ls dksbZ ugha

119. The band width of AM signal is: (1) Directly proportional to the frequency of modulation signal (2) Inversely proportional to the frequency of modulation signal (3) Not related to the frequency of modulation signal (4) 10 KHz

119. AM ladsr dh cSaM pkSM+kbZ gksrh gS% (1) ekMwyu ladsr dh vko`fRr ds vuqØekuqikrh

(2) ekMwyu ladsr dh vko`fRr ds O;qRØekuqikrh

(3) ekMwyu ladsr dh vko`fRr ls lacaf/kr ugha gS

(4) 10 KHz

120. In case of electric fire, use: (1) CO2 (2) N2S (3) SO2 (4) Cl2

120. fctyh dh vkx yxus ij fuEu dk iz;ksx djsa%

(1) CO2 (2) N2S (3) SO2 (4) Cl2

PAPER – II_Electrical [ 5 2 0 5 6 6 ] NFCX5 [ A–13 ]

bl iqfLrdk ij dqN Hkh fy[kus ls igys fuEufyf[kr funsZ'k /;kuiwoZd i<+sa

egRoiw.kZ%& fuEufyf[kr funsZ'k /;kuiwoZd i<+saA vius ç”uksa ds mÙkj ç”u&iqfLrdk esa u yxk,a vU;Fkk p;u çfØ;k ls vkidh ik=rk oafpr dj

nh tk;sxhA 1. viuk mÙkj fy[kuk çkjEHk djus ls igys viuh ç'u iqfLrdk dh Hkyh&Hkk¡fr tk¡p dj ysa] ns[k ysa fd blesa 120 ç'u gSaA çR;sd ç'u

iqfLrdk dh fljht fHké gksxh ¼ç”u&iqfLrdk la[;k ,oa ç”u&iqfLrdk fljht dk la;kstu½A vkidks OMR mÙkj if=dk ij lgh ç'u&iqfLrdk

fljht ,oa ç”u&iqfLrdk la[;k fy[kuk gSA iqu% ;g Hkh ij[k ysa fd blesa fçafVax laca/kh vFkok vU; fdLe dh dksbZ deh ugha gSA ;fn fdlh

çdkj dh dksbZ deh gks rks i;Zoskd dks lwfpr djsa vkSj ç”u&iqfLrdk cnydj ,d u;h iqfLrdk ,oa ,d u;h OMR ysaA bl lanHkZ esa fdlh

Hkh çdkj dh dksbZ f'kdk;r ij ckn esa dksbZ fopkj ugha fd;k tk,xkA

egRoiw.kZ uksV% vks-,e-vkj- mÙkj if=dk vH;FkÊ ds ç”u&iqfLrdk fljht ,oa ç”u&iqfLrdk la[;k ds la;kstu ls ewY;kafdr dh tk;sxhA

vr% vkidks vks-,e-vkj- mÙkj if=dk ij lgh ç”u&iqfLrdk fljht ,oa ç”u&iqfLrdk la[;k fy[kuh pkfg,A buesa ls fdlh ,d esa Hkh

xyrh gksus ij vkidh vks-,e-vkj- mÙkj if=dk fujLr gks ldrh gSA vks-,e-vkj- mÙkj if=dk esa ç”u&iqfLrdk la[;k ,oa ç”u&iqfLrdk

fljht ugha Hkjus ij vH;FkÊ ds mÙkj if=dk dk ewY;kadu ugha fd;k tk;sxk ftldh ftEesnkjh Lor% vH;FkÊ dh gksxhA

2. ç”u i= fHkk’kh; ¼fgUnh ,oa vaxzsth½ esa gSA fgUnh laLdj.k esa fdlh Hkh fHkérk gksus ij ewY;kadu ds fy, vaxzsth laLdj.k dks vfUre ekuk

tk;sxkA

3. lqfuf”pr djsa fd vkids ços”k&i= ,oa vks-,e-vkj “khV dks vkids kjk ,oa dk fujhkd ds kjk gLrkkj fd;k x;k gSA ;fn gLrkkj

ugha fd;k@djok;k x;k gS rks ik=rk fujLr gks tk;sxhA

4. lHkh cgq&fodYi ç”uksa ds 1 vad gSaA vuqÙkfjr ç”uksa ds fy, u rks dksbZ vad fn;k tk,xk vkSj u gh dkVk tk,xkA çR;sd mÙkj ds fy,

dsoy ,d vksoy dks dkyk djsaA ;fn vki ,d ls T;knk vksoy dkyk djrs gSa ;k ,d ls T;knk vksoy ij dksbZ LVªs ekDZl feyrk gS] ,sls

vksoy ds fy, dksbZ vad ugha feysxkA

5. ;g ,d oLrqijd fdLe dh ijhkk gS ftlesa çR;sd ç'u ds uhps Øekad (1) ls (4) rd pkj çLrkfor mÙkj fn;s gSaA vkids fopkj esa tks

Hkh mÙkj lgh@loZJs"B gS mldks vks-,e-vkj- mÙkj i= esa fn;s funsZ'k ds vuqlkj fpfUgr dhft,A vius mÙkj ç'u iqfLrdk esa u yxk,A

6. vks-,e-vkj- mÙkj if=dk ij lHkh dk;ks± ds fy, uhys@dkys ckWy Iokb±V isu ls fy[ksaA vks-,e-vkj mÙkj if=dk ij vksoy dks iw.kZ :i

ls dsoy uhys@dkys ckWy Iokb±V isu ls HkjsaA ,d ckj fn, x, mÙkj dks cnyk ugha tk ldrkA mÙkj dh dfVax ,oa vksojjkbZfVax dh

vuqefr ugha gSA 7. dsYdqysVj] LykbM:y] eksckbZy] dsYdqysVj ?kfM+;k¡ ;k bl çdkj dh dksbZ Hkh ;qfä ,oa fdlh Hkh v/;;u@lanHkZ lkexzh vkfn dk ç;ksx

ijhkk dk esa oftZr gS ,oa nUMuh; vijk/k gSA 8. jQ+ dk;Z iqfLrdk esa fdlh Hkh [kkyh LFkku esa fd;k tkuk pkfg,] vks-,e-vkj- mÙkj if=dk ij dksbZ Hkh jQ+ dk;Z u djsaA fdlh vU;

dkx+t ij bls djus dh vuqefr ugha gSA 9. ijhkk dh lekfIr ds i'pkr~ viuh mÙkj&if=dk ¼OMR½ i;Zoskd dks lkSai nsaA vks-,e-vkj- ¼OMR½ mÙkj&if=dk dks ijhkk dk ls

ckgj ys tkuk oftZr gS ,slk djuk nUMuh; vijk/k gSA ijhkkFkÊ ijhkk ds mijkUr viuk ç”u&i= ys tk ldrk gSA


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