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Chapter 2 Slide 1 of 85 Chapter Two Structures of Solids
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Chapter 2 Slide 1 of 85

Chapter Two

Structures of Solids

Chapter 2 Slide 2 of 85

States of Matter Compared

Chapter 2 Slide 3 of 85

Chapter 2 Slide 4 of 85

Some Characteristics of Crystalline Solids

Chapter 2 Slide 5 of 85

Network Covalent Solids• These substances contain a network of covalent bonds that extend

throughout a crystalline solid, holding it firmly together.• In material science, polymorphism is the ability of a solid material to

exist in more than one form or crystal structure. Diamond, graphite and the Buckyball are examples of polymorphs of carbon. α-ferrite, austenite, and δ-ferrite are polymorphs of iron. When found in elemental solids the condition is also called allotropy.

• The allotropes of carbon provide a good example1. Diamond has each carbon bonded to four other carbons in a

tetrahedral arrangement using sp3 hybridization.

2. Graphite has each carbon bonded to three other carbons in the same plane using sp2 hybridization.

3. Fullerenes and nanotubes are roughly spherical and cylindrical collections of carbon atoms using sp2 hybridization.

Chapter 2 Slide 6 of 85

Crystal Structure of Diamond

Covalent bond

Crystal Structure of Graphite

Covalent bond

van der Waalsforce

Structure of a Buckyball

sp2 hybrid Carbon

Chapter 2 Slide 9 of 85

sp2 hybrid Carbon

Carbon Nano-tube

A nanotube (also known as a buckytube) is a member of the fullerene structural family, which also includes buckyballs. Whereas buckyballs are spherical in shape, a nanotube is cylindrical, with at least one end typically capped with a hemisphere of the buckyball structure. Their name is derived from their size, since the diameter of a nanotube is on the order of a few nanometers , while they can be up to several centimeters in length. There are two main types of nanotubes: single-walled nanotubes (SWNTs) and multi-walled nanotubes (MWNTs).

Chapter 2 Slide 10 of 85

Experimental Determinationof Crystal Structures

Bragg’s Law2 d sinθ = n λ

Chapter 2 Slide 11 of 85

Chapter 2 Slide 12 of 85

X-Ray Diffraction Image & Pattern

Single crystal Powder

Chapter 2 Slide 13 of 85

Crystal Lattices

• To describe crystals, three-dimensional views must be used.• The repeating unit of the lattice is called the unit cell.• The simple cubic cell (primitive cubic) is the simplest unit

cell and has structural particles centered only at its corners.• The body-centered cubic (bcc) structure has an additional

structural particle at the center of the cube.• The face-centered cubic (fcc) structure has an additional

structural particle at the center of each face.

Chapter 2 Slide 14 of 85

Unit Cells InCubic Crystal Structures

simple cubic(primitive cubic)

bcc fcc

Chapter 2 Slide 15 of 85

Face-centered cubicBody-centered cubicPrimitive cubic

Chapter 2 Slide 16 of 85

Occupancies per Unit CellsPrimitive cubic: a = 2r

1 atom/unit celloccupancy = [4/3(πr3)]/a3 = [4/3(πr3)]/(2r)3

= 0.52 = 52%Body-centered cubic: a = 4r/(3)1/2

2 atom/unit celloccupancy = 2 x [4/3(πr3)]/a3 = 2 x [4/3(πr3)]/[4r/(3)1/2]3

= 0.68 = 68%Face-centered cubic: a = (8)1/2 r

4 atom/unit celloccupancy = 4 x [4/3(πr3)]/a3 = 4 x [4/3(πr3)]/[(8)1/2 r]3

= 0.74 = 74%Closest packed

Chapter 2 Slide 17 of 85

a

ab

aba abcunoccupied holes

Closest packed

Chapter 2 Slide 18 of 85

abab

abcabc

Cubic close-packed structure

= Face-centered cubic

Hexagonal close-packed structure

polytypes

Chapter 2 Slide 19 of 85

Crystal Structures of Metals

Interionic Forces of Attraction

E = (Z+Z-e2)/4πεr e = 1.6 x 10-19 C

In vacuum, ε0 = 8.85 x 10-12 C2m-1J-1

In water, εH2O = 7.25 x 10-10 C2m-1J-1= 82 ε0

In liquid ammonia, εNH3 = 2.2 x 10-10 C2m-1J-1= 25 ε0

Chapter 2 Slide 21 of 85

Unit Cell of Rock-Salt(Sodium Chloride)

Cl- at fcc

Na+ at Oh holesCoord. #: Na+: 6; Cl-: 6atom/ unit cellNa: Cl= 4: 4 = 1: 1 NaCl

Chapter 2 Slide 22 of 85

Unit Cell of Cesium Chloride

Cl- at primitive cubicCs+ at Cubic holes

Coord. #: Cs+: 8; Cl-: 8atom/ unit cellCs: Cl= 1: 1 CsCl

Chapter 2 Slide 23 of 85

Unit Cell of Cubic Zinc Sulfide(Sphalerite or Zinc blende)

Coord. #: Zn2+: 4; S2-: 4atom/ unit cellZn: S = 4: 4 = 1: 1 ZnS

S2- at fccZn2+ at ½ Td holes

Chapter 2 Slide 24 of 85

A Born-Haber Cycle to CalculateLattice Energy

1/2D(Cl-Cl)

∆Ηsublimation (Na)

IE(Na) -EA(Cl)

lattice energy U0 = - ∆Ηf0(NaCl) + ∆Ηsublimation (Na) + 1/2D(Cl-Cl)

+ IE(Na) - EA(Cl)

= (+411 +107 +122 + 496 –349) kJ/mol

= +787 kJ/mol

∆Ηf0(NaCl)

U0NaCl(s) Na+(g) + Cl-(g)

Na(g) + Cl(g)Na(s) + 1/2Cl2(g)

Chapter 2 Slide 25 of 85

Lattice Energy & Madelung Constant

( ) ( ) ( ) 0 U- H 0 <=∆→+ −+sgg MXXM

U0: lattice energy

Factors contributed to Lattice energy•electrostatic energy ~90%•repulsion of close shells ~8%•dispersion forces ~1% •zero-point energy (lattice vibration at 0K)•correction for heat capacity ~1%

Chapter 2 Slide 26 of 85

Electrostatic energy in a crystal lattice, between a pair of ions

For NaCl crystal, Z+ =Z- =1r = d

( )reA

0

2

c 4ZZ

Eπε

−+

= A : Madelung Constant

Chapter 2 Slide 27 of 85

The value of Madelung constant is determined only by the “geometry of the lattice”, and independent of the “ionic radius” and “charge”.

Chapter 2 Slide 28 of 85

electrostatic energy repulsion of close shells

B: constantn: Born exponent

Born equation

12Xe, Au+

10Kr, Ag+

9Ar, Cu+

7Ne

5He

nIon configuration

Chapter 2 Slide 29 of 85

Let U0 = -(PE)0 N N: Avogadro’s number

Born-Lande equation

At minimum PE, attractive and repulsive forces are balanced, and d= d0.

0)(

=∂

∂d

PE

Chapter 2 Slide 30 of 85

For NaCl

A = 1.74756Z1 = 1, Z2 = -1d0 = rNa+ + rCl- = 2.81 x10-10 mn = (nNa+ + nCl-) /2 = (7+9)/2 = 8

⇒ U0= 755.2 kJ/mol

experimental U0= 770 kJ/mol

Chapter 2 Slide 31 of 85

Modification of Born-Lande equation

)345.0

1(4

ZZ

000

2

0 ddeNA

U −=−+

πε

Unit in ? , 10-10 m

2. Kapustinskii equation

Improving the repulsion

)345.0

1(ZZ

00

0 ddn

U −−

=−+κ

κ = 1.21 MJ. ? mol-1

n= ions per formulae.g. n= 2 for NaCl

n= 5 for Al2O3

A ? crystal lattice ? r+/r- ? r0A/n ~constant

1. Born-Mayer equation

Chapter 2 Slide 32 of 85

+218.1+183.8+130.4+48.3∆G0 (kJ/mol)

13001100840300T (?C)+172.1+171.0+160.6+175.0∆S0 (J/K mol)

+269.3+234.6+178.3+100.6∆H0 (kJ/mol)

BaSrCaMgData at 298K

( ) ( ) ( )g2ss3 CO MO MCO +→

A small cation increases the lattice enthalpy of the oxide more than that of a carbonate.

0

0

000

Tion decomposit

T-

SH

SHG

∆∆

=

∆∆=∆

Chapter 2 Slide 33 of 85

< 0 > 0

Solubility of ionic compounds

0000 T- T- SLSHG ∆=∆∆=∆

Enthalpy of solution Hydration enthalpy

Free energy of solution

Chapter 2 Slide 34 of 85

Hydration enthalpy

−+

−+

+∞=∆+∆=∆

+∞

−+

rrHHH

rrU

XMhydration11

1 0

−−=∆

ε1

12

2

rZ

Hhyd

•In general, difference in ionic size favors solubility in water.

•Ionic compound MX tends to be most soluble when rX-rM > 0.8?

Chapter 2 Slide 35 of 85

Correlation between ∆Hsolution and the differences between the hydration enthalpy of the ions

Chapter 2 Slide 36 of 85

Fajan's rules

Fajan's Rule: the degree of covalent character of ionicbond

Polarization effects: (a) idealized ion pair with no polarization; (b) mutually polarized ion pair; (c) polarization sufficient to formcovalent bond. Dashed lines represent hypothetical unpolarized ions.

Chapter 2 Slide 37 of 85

In 1923, Fajan suggested rules to predict the degree of covalent character in ionic compounds:

The polarization of an ionic bond and thus the degree of covalency is high if :1) the charges on the ions are high.eg., Al3+ ; Ti4+ ----- favors covalent character.

Na+ ; K+ ----- favors ionic character.

2) the cation is small.e.g., Na+ ion is larger than that of Al3+

Thus, Al3+ favors covalent character.

3) the anion is large.e.g. F- ionic radius : 0.136 nm favors ionic character.

I- ionic radius : 0.216 nm favors covalent character.

Chapter 2 Slide 38 of 85

4) An incomplete valence shell electron configurationNoble gas configuration of the cation better shielding and less polarizing power e.g. Hg2+ (r = 102 pm) is more polarizing than Ca 2+ (r = 100 pm)

HgO decomposed at 500 ?CCaO m.p. 2613 ?C

783

742

775

1418

m.p. (?C)

hexagonal

rhom.

cubic

cubic

Crys str

259

236

276

645 (dec)

m.p. (?C)

tetragonal

rhombohedral

orthorhombic

cubic

Crys str

CaI2

CaBr2

CaCl2

CaF2

Halides

HgI2

HgBr2

HgCl2

HgF2

Halides

Chapter 2 Slide 39 of 85

a) Charge factori) Cations

Na+ Mg2+ Al3+

Examples:For ions with noble gas (ns2 np6 ) structure, the only factor that have to be considered are size and charge factor.

ii) AnionsN3- O2- F-

Increasing charge : increase in polarizing power

Increase in ionic charge, more ready to be polarized

Chapter 2 Slide 40 of 85

1.5 x 10-5183sublimationAlCl3

57-70SiCl4

14101440

boiling point /°C

715800

melting point /°C

Conductance in molten state

Chlorides

29MgCl2

133NaCl

AlCl3 has covalent character. In fact, AlCl3 exists as dimer Al2Cl6at room conditions.

covalency

Chapter 2 Slide 41 of 85

b) Size factor

i) CationsBe2+ Mg2+ Ca2+ Sr2+ Ba2+

The smaller the cation, the higher is its polarizing power

52774CaCl2

56870SrCl2

Conductance in molten state

melting point /°CChlorides

955BaCl2

29715MgCl2

0.056404BeCl2

covalency

Chapter 2 Slide 42 of 85

ii) Anions

F- Cl- Br- I-

The larger the anion, the more polarizable is the anion.

eg.,NaF NaCl NaBr NaI

melting point /°C 990 800 755 651

covalency

Chapter 2 Slide 43 of 85

( ) ( ) ( )g2ss3 CO MO MCO +→

1360BaCO3

1289SrCO3

900CaCO3

540MgCO3

250BeCO3

Decomp. Temp. (?C)Carbonates

1923BaO

2430SrO2613CaO

2826MgO

2530BeO

m.p. (?C)Oxides

Ionic compounds

covalency

wurtzitestructure

NaClstructure

Some covalent character

Chapter 2 Slide 44 of 85

Close-packing of Spheresin Three Dimensions

Chapter 2 Slide 45 of 85

Octahedral holesTetrahedral holes Cubic holes

Close packed structure

Chapter 2 Slide 46 of 85

rh/r = 0.156

rh/r = 0.225

rh/r = 0.414

Chapter 2 Slide 47 of 85

Chapter 2 Slide 48 of 85

Chapter 2 Slide 49 of 85

Considering anion-anion

repulsion

Chapter 2 Slide 50 of 85

Unit Cell of Rock-Salt(Sodium Chloride)

Cl- at fcc

Na+ at Oh holesCoord. #: Na+: 6; Cl-: 6atom/ unit cellNa: Cl= 4: 4 = 1: 1 NaCl

Chapter 2 Slide 51 of 85

Rock-salt structure

Chapter 2 Slide 52 of 85

Unit Cell of NiAS

As3- at hcp

Ni3+ at Oh holesPolariable cation& anion

Chapter 2 Slide 53 of 85

Unit Cell of Cesium Chloride

Cl- at primitive cubicCs+ at Cubic holes

Coord. #: Cs+: 8; Cl-: 8atom/ unit cellCs: Cl= 1: 1 CsCl

Chapter 2 Slide 54 of 85

Unit Cell of Cubic Zinc Sulfide(Sphalerite or Zinc blende)

Coord. #: Zn2+: 4; S2-: 4atom/ unit cellZn: S = 4: 4 = 1: 1 ZnS

S2- at fccZn2+ at ½ Td holes

Chapter 2 Slide 55 of 85

Unit Cell of Hexagonal Zinc Sulfide (Wurtzite)

S2- at hcp

Zn2+ at ½ Td holesPolymorph of ZnS

Chapter 2 Slide 56 of 85

Pt2+ at fccS2- at ½ Td holesPtS4 unit is planar Pt-S more covalent

PtS

Chapter 2 Slide 57 of 85

Unit Cell of Fluorite Structure(Calcium Fluoride)

Ca2+ at fccF- at Td holesCoord. #: Ca2+: 8; F-: 4

atom/ unit cellCa: F= 4: 8 = 1: 2 CaF2

Chapter 2 Slide 58 of 85

•Fluorite Structure- MX2 Large M

•Antifluorite structure- M2XLarge X, e.g. Na2O

Chapter 2 Slide 59 of 85

Unit Cell of Rutile TiO2

O2- at hcpTi4+ at ½ Oh holes

Coord. #: Ti: 6; O: 3atom/ unit cellTi: O= 2: 4 = 1: 2

Chapter 2 Slide 60 of 85

Chapter 2 Slide 61 of 85

Chapter 2 Slide 62 of 85

A Structural Map for compounds of MX

Increasing covalency

Chapter 2 Slide 63 of 85

Chapter 2 Slide 64 of 85

Chapter 2 Slide 65 of 85

Chapter 2 Slide 66 of 85

Chapter 2 Slide 67 of 85

A Structural Map for compounds of MX2

Increasing covalency

Chapter 2 Slide 68 of 85

Salts of highly polarizing cations and easily polarizable anions have layered structures.

Chapter 2 Slide 69 of 85

Salts of highly polarizing cations and easily polarizable anions have layered structures.

CdCl2Cl- at ccpCd 2+ at ½ Oh sites

(alternate O layers)

van der Waals force

Chapter 2 Slide 70 of 85

CdI2I- at hcpCd 2+ at ½ Oh sites

(alternate O layer)

Chapter 2 Slide 71 of 85

MoS2Mo4+ at hcpS2- at Td sites

298pm

366pm

Chapter 2 Slide 72 of 85

Unit Cell of PerovskiteCaTiO3

AIIBIVO3

AIIIBIIIO3

Coord. #: A: 12; B: 6atom/ unit cellA: B: O= 1: 1: 3

A and O together at ccpB at 1/4 Oh holes

Chapter 2 Slide 73 of 85

Unit Cell of ReO3

Perovskite structure CaTiO3 without Ca

Chapter 2 Slide 74 of 85

Unit Cell of SpinelMgAl2O4

Normal SpinelAII[BIII]2O4, AIV[BII]2O4 , AVI[BI]2O4

e.g. NiCr2O4, Co3O4 , Mn3O4

Inverse SpinelB[AB]O4e.g. Fe3O4

O 2- at fccA at 1/8 Td holesB at 1/2 Oh holes

Chapter 2 Slide 75 of 85

Chapter 2 Slide 76 of 85

YBa2Cu3O7

Chapter 2 Slide 77 of 85

Quartz SiO2

Chapter 2 Slide 78 of 85

Chapter 2 Slide 79 of 85

Chapter 2 Slide 80 of 85

Chapter 2 Slide 81 of 85

Chapter 2 Slide 82 of 85

Mineral Ideal formulab CECc (meq/100 g)

Dioctahedral minerals Pyrophyllite Al2(Si4O10)(OH)2 0 Montmorillonite Nax(Al2-xMgx)(Si4O10)

(OH)2.zH2O 60 - 120

Beidellite Mx(Al2)(AlxSi4-xO10) (OH)2.zH2O

60 - 120

Nontronite Mx(Fe3+,Al)2(AlxSi4-xO10) (OH)2.zH2O

60 - 120

Trioctahedral minerals

Talc Mg3(Si4O10)(OH)2 0 Hectorite (Na2Ca)x/2(LixMg3-x)

(Si4O10)(OH)2.zH2O 60 - 120

Saponite Cax/2Mg3(AlxSi4-xO10) .zH2O

60 - 120

Sauconite Mx(Zn,Mg)3(AlxSi4-xO10) .zH2O

a: Only major cations are shown. b: x depends on the origin of the mineral; montmorillonites can show a degree of substitution x in the octahedral sheet in the range 0.05- 0.52. Natural samples generally show substitutions in both octahedral and tetrahedral sheets, which renders the real situations more complex. c: Cation-exchange capacity.

Chapter 2 Slide 83 of 85

Chapter 2 Slide 84 of 85

Chapter 2 Slide 85 of 85


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