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# PETE 411 Well Drilling

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PETE 411 Well Drilling. Lesson 3 The Rig - Drilling Equipment. Contents . Rig Pumps Solids Control Equipment Air Drilling The Rotary System The Swivel The Well Control System The Well Monitoring System Offshore Drilling. Assignments:. READ: ADE Ch. 1, to p.30 - PowerPoint PPT Presentation
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1 PETE 411 Well Drilling Lesson 3 The Rig - Drilling Equipment
Transcript

1

PETE 411 Well Drilling

Lesson 3

The Rig - Drilling Equipment

2

Contents Rig Pumps Solids Control Equipment Air Drilling The Rotary System The Swivel The Well Control System The Well Monitoring System Offshore Drilling

3

Assignments:

HW #1: ADE 1.1, 1.2, 1.3 Due Monday, Sept. 9, 2002

at the beginning of class

NOTE: Answers in book are not always correct...

4

Schematic of Rig

Circulating System for

liquid drilling fluid

5

6

Example 1.3

Compute the pump factor in units of barrels per stroke for a double-acting duplex pump having:

6.5-inch liners (dL)

2.5 inch rods (dr)

18-inch strokes (LS)

and a volumetric efficiency of 90%. (EV)

7

Solution:The pump factor for a duplex pump can be determined using Equation 1.10

stroke/in 1991

5.25.629.0182

dd2EL2

F

3

22

2r

2LVSp

8

Recall:There are 231 in.3 in an U. S. gallon and 42 U.S. gallons in a U.S. barrel. Thus converting to the desired field units yields:

1991 in.3/stroke * gal/231 in.3 * bbl/42 gal.= 0.2052 bbl/stroke.

Thus: Pump Factor = 0.2052 bbl/stroke

9

Pump Factor = 3 * /4 dL2 LS EV/(231 * 42)

10

Example:

Pump Factor for Triplex Pump

bbl/stroke 09442.0

.in42231

bblstroke

in90.01264

3

ELd 4

3

32

VS 2

L

11

Example: Pump Rate

= Pump Factor * Strokes/min

= 0.09442

= 7.554 bbl/min= 317.3 gal/min

minstks80

stkbbl

Pump Rate = 317 gal/min

12

Hydrocyclone• desander• desilter

* No moving parts* Low cost* Pressure drop

* Diameter

13 Decanting Centrifuge Use?

14

l

l

Use?

15

Fig. 1.33 Schematic of Rotary System

16

Fig. 1.34 Cutaway View of Swivel

ROTATING* Seals* Bearings

17

Fig. 1.38 Cutaway View and

Dimensions for Example Tool Joint

PINBOX

TJShoulder

18

Fig. 1.39 Stabilizer

* Keeps pipe in center of hole* Aids in drilling straight hole* Prolongs bit life

19

Fig. 1.41 Kick Detection During Drilling

Operations

1

2

3

KICK

GAIN IN PITVOLUME EQUAL

TO KICK VOLUME

20

Fig. 1.46 Remote Control

Panel for operating Blowout

Preventers CHOKE

What to do if KICK occurs?

21Fig. 1.44 Annular Blowout Preventer

DPTJDCOH

Press

22Ram Blowout Preventer

23Ram Blowout Preventer - cont’d

SHEAR / BLINDRAM ASSEMBLY

24Fig. 1.48 Rotating Blowout Preventer

25

Fig. 1.51 High-

Pressure Circulating System for

Well Control

Operations

Keep BHP const.

Kick

26

Fig. 1.56 Subsurface

Well Monitoring

System

MWD

OFFSHORE DRILLING

28

Fig. 1.58 Schematic of Equipment for Marine Drilling

29

Fig. 1.59 Operation of a Heave Compensator

30

Fig. 1.60 Subsea

BOP Stack

31

Fig. 1.63 Subsea Equipment Installation Procedure

32

Typical Casing Strings

Water Level Depth

Seafloor Below ML

Conductor pile 36” 30” 200’

Conductor Casing 26” 20” 1000’

Surface Casing 17 1/2” 13 3/8” 4000’

Hole Csg. Depth

33

Some Typical Casing Strings

Depth Below

ML

Conductor pile 36” 30” 200’

Conductor Casing 26” 20” 1000’

Surface Casing 17 1/2” 13 3/8” 4000’

Hole Csg. Depth

34Capacity = Area * Length

35

What is the capacity of 10,000 ft of 5” OD, 19.50 lb/ft drillpipe?

Capacity = Area * Length

Area = /4 d2 = /4 * 4.2762 = 14.36 in2

Length = 10,000 ft = 120,000 in

Capacity = 14.36 *120,000 in3 /(231*42 in3 /bbl)

Capacity = 177.6 bbls

36

What is the displacement of 10,000 ft of 5” OD, 19.50 lb/ft drillpipe?

Capacity = Area * Length

Area = /4 (od2 - id2 ) = /4 * (52 - 4.2762)

= 5.275 in2

Length = 10,000 ft = 120,000 in

Displ. = 5.276 * 120,000 in3 /(231 * 42 in3 /bbl)

Displacement = ? Bbls

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