1

PETE 411 Well Drilling

Lesson 3

The Rig - Drilling Equipment

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Contents Rig Pumps Solids Control Equipment Air Drilling The Rotary System The Swivel The Well Control System The Well Monitoring System Offshore Drilling

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Assignments:

READ: ADE Ch. 1, to p.30

HW #1: ADE 1.1, 1.2, 1.3 Due Monday, Sept. 9, 2002

at the beginning of class

NOTE: Answers in book are not always correct...

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Schematic of Rig

Circulating System for

liquid drilling fluid

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6

Example 1.3

Compute the pump factor in units of barrels per stroke for a double-acting duplex pump having:

6.5-inch liners (dL)

2.5 inch rods (dr)

18-inch strokes (LS)

and a volumetric efficiency of 90%. (EV)

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Solution:The pump factor for a duplex pump can be determined using Equation 1.10

stroke/in 1991

5.25.629.0182

dd2EL2

F

3

22

2r

2LVSp

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Recall:There are 231 in.3 in an U. S. gallon and 42 U.S. gallons in a U.S. barrel. Thus converting to the desired field units yields:

1991 in.3/stroke * gal/231 in.3 * bbl/42 gal.= 0.2052 bbl/stroke.

Thus: Pump Factor = 0.2052 bbl/stroke

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Pump Factor = 3 * /4 dL2 LS EV/(231 * 42)

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Example:

Pump Factor for Triplex Pump

bbl/stroke 09442.0

.in42231

bblstroke

in90.01264

3

ELd 4

3

32

VS 2

L

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Example: Pump Rate

= Pump Factor * Strokes/min

= 0.09442

= 7.554 bbl/min= 317.3 gal/min

minstks80

stkbbl

Pump Rate = 317 gal/min

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Hydrocyclone• desander• desilter

* No moving parts* Low cost* Pressure drop

* Diameter

13 Decanting Centrifuge Use?

14

l

l

Use?

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Fig. 1.33 Schematic of Rotary System

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Fig. 1.34 Cutaway View of Swivel

ROTATING* Seals* Bearings

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Fig. 1.38 Cutaway View and

Dimensions for Example Tool Joint

PINBOX

TJShoulder

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Fig. 1.39 Stabilizer

* Keeps pipe in center of hole* Aids in drilling straight hole* Prolongs bit life

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Fig. 1.41 Kick Detection During Drilling

Operations

1

2

3

KICK

GAIN IN PITVOLUME EQUAL

TO KICK VOLUME

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Fig. 1.46 Remote Control

Panel for operating Blowout

Preventers CHOKE

What to do if KICK occurs?

21Fig. 1.44 Annular Blowout Preventer

DPTJDCOH

Press

22Ram Blowout Preventer

23Ram Blowout Preventer - cont’d

SHEAR / BLINDRAM ASSEMBLY

24Fig. 1.48 Rotating Blowout Preventer

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Fig. 1.51 High-

Pressure Circulating System for

Well Control

Operations

Keep BHP const.

Kick

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Fig. 1.56 Subsurface

Well Monitoring

System

MWD

27Fig. 1.57 Spread Mooring Systems

OFFSHORE DRILLING

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Fig. 1.58 Schematic of Equipment for Marine Drilling

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Fig. 1.59 Operation of a Heave Compensator

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Fig. 1.60 Subsea

BOP Stack

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Fig. 1.63 Subsea Equipment Installation Procedure

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Typical Casing Strings

Water Level Depth

Seafloor Below ML

Conductor pile 36” 30” 200’

Conductor Casing 26” 20” 1000’

Surface Casing 17 1/2” 13 3/8” 4000’

Hole Csg. Depth

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Some Typical Casing Strings

Depth Below

ML

Conductor pile 36” 30” 200’

Conductor Casing 26” 20” 1000’

Surface Casing 17 1/2” 13 3/8” 4000’

Hole Csg. Depth

34Capacity = Area * Length

35

What is the capacity of 10,000 ft of 5” OD, 19.50 lb/ft drillpipe?

Capacity = Area * Length

Area = /4 d2 = /4 * 4.2762 = 14.36 in2

Length = 10,000 ft = 120,000 in

Capacity = 14.36 *120,000 in3 /(231*42 in3 /bbl)

Capacity = 177.6 bbls

36

What is the displacement of 10,000 ft of 5” OD, 19.50 lb/ft drillpipe?

Capacity = Area * Length

Area = /4 (od2 - id2 ) = /4 * (52 - 4.2762)

= 5.275 in2

Length = 10,000 ft = 120,000 in

Displ. = 5.276 * 120,000 in3 /(231 * 42 in3 /bbl)

Displacement = ? Bbls