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Physics 1A, Section 2

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Physics 1A, Section 2. November 1, 2010. Office Hours. Office hours will now be: Tuesday, 3:30 – 5:00 PM (half an hour later) still in Cahill 312. Today’s Agenda. Finish energy problem from Thursday forces and potential energy potential energy of a fictitious force? - PowerPoint PPT Presentation
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Physics 1A, Physics 1A, Section 2 Section 2 November 1, 2010 November 1, 2010
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Page 1: Physics 1A, Section 2

Physics 1A,Physics 1A,Section 2Section 2

November 1, 2010November 1, 2010

Page 2: Physics 1A, Section 2

Office Hours Office hours will now be:

Tuesday, 3:30 – 5:00 PM (half an hour later)

still in Cahill 312

Page 3: Physics 1A, Section 2

Today’s Agenda Finish energy problem from Thursday

forces and potential energy

potential energy of a fictitious force?

potential energy applied to orbits Lagrange points for Sun/Earth/satellite

Page 4: Physics 1A, Section 2

Quiz Problem 50

Page 5: Physics 1A, Section 2

Quiz Problem

50

• Answer:

• v = sqrt(2gh)

• F = -kx – mg, to the right

• W = -kxs2/2 – mgxs

• Wf = 2mgxs

• h’ = h – 2xs

• xs = [-mg + sqrt(2m2g2+2kmgh)]/k

Page 6: Physics 1A, Section 2

Conservative andNon-Conservative Forces

A conservative force F can be associated with a potential energy U F = –dU/dr or –dU/dx in Physics 1a

F = (–U/x, –U/y, –U/z) more generally

Force is a function of position only. example: uniform gravity: U = mgz example: Newtonian gravity: U = –GMm/r example: ideal spring: U = kx2/2

Non-conservative forces friction: force depends on direction of motion normal force: depends on other forces

but does no work because it has no component in direction of motion.

Page 7: Physics 1A, Section 2

Potential Energy from a Fictitious (Inertial) Force

It can be useful to associate the centrifugal force in a rotating frame with a potential energy:

Fcentrifugal = m2r (outward)

Page 8: Physics 1A, Section 2

Potential Energy from a Fictitious (Inertial) Force

It can be useful to associate the centrifugal force in a rotating frame with a potential energy:

Fcentrifugal = m2r (outward)

Ucentrifugal = –m2r2/2

Page 9: Physics 1A, Section 2

Consider circular orbits (again)

Work in the rotating (non-inertial) frame.

planet orbiting the Sun:

Utotal = Ugravity + Ucentrifugal

Equilibrium where dUtotal/dr = 0 GMSun = 2r3

Page 10: Physics 1A, Section 2

Consider circular orbits (again)

Work in the rotating (non-inertial) frame.

planet orbiting the Sun (Mplanet << Msun): Utotal = Ugravity + Ucentrifugal

Equilibrium where dUtotal/dr = 0 GMSun = 2r3

Satellite and Earth orbiting the Sun (Msatellite << MEarth << MSun) Utotal = Ugravity,Sun + Ugravity,Earth + Ucentrifugal

Equilibria at 5 Lagrange points

Page 11: Physics 1A, Section 2

Sun-Earth Lagrange Points

image from wikipedia

Page 12: Physics 1A, Section 2

Location of Lagrange points

L1,L2: R ≈ R(ME/3MS)1/3

about 0.01 A.U. from Earth toward or away from Sun

unstable equilibria

L3: orbital radius ≈ R[1 + (5ME/12Ms)]

very unstable equilibrium

L4,L5: three bodies form an equilateral triangle stable equilibria (via Coriolis force)

1 A.U. = astronomical unit = distance from Earth to Sun

Page 13: Physics 1A, Section 2

Advanced Composition Explorer – examines solar wind

Page 14: Physics 1A, Section 2

Planck satellite – examines relic radiation from Big Bang

Page 15: Physics 1A, Section 2

Thursday, November 4:

Quiz Problem 38 (collision)

Optional, but helpful, to try this in advance.


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