PHYSICS, CHEMISTRY & MATHEMATICS · The diagram shows a small bead of mass m carrying charge q. The...

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PHYSICS, CHEMISTRY & MATHEMATICS

SET-A

Time Allotted: 3 Hours • Maximum Marks: 216

▪ Please read the instructions carefully. You are allotted 5 minutes specifically for this purpose.

▪ You are not allowed to leave the Examination Hall be fore the end of the test.

INSTRUCTIONS

Caution: Question Paper CODE as given above MUST be correctly marked in the answer OMR sheet before attempting the paper. Wrong CODE or no CODE will give wrong results.

A. General Instructions 1. Attempt ALL the questions. Answers have to be marked on the OMR sheets.

2. This question paper contains Three Parts.

3. Part-I is Physics, Part-II is Chemistry and Part-III is Mathematics.

4. Each part is further divided into three sections: Section-A, & B.

5. Rough spaces are provided for rough work inside the question paper. No additional sheets will be provided for rough work.

6. Blank Papers, clip boards, log tables, slide rule, calculator, cellular phones, pagers and electronic devices, in any form, are not allowed.

B. Filling of OMR Sheet 1. Ensure matching of OMR sheet with the Question paper before you start marking your answers on OMR

sheet.

2. On the OMR sheet, darken the appropriate bubble with Blue/Black Ball Point Pen for each

character of your Enrolment No. and write in ink your Name, Test Centre and other details at the designated places.

3. OMR sheet contains alphabets, numerals & special characters for marking answers.

C. Marking Scheme For All Three Parts. (i) Section-A (01 – 04) contains 4 multiple choice questions which have only one correct answer. Each

question carries +4 marks for correct answer and – 1 mark for wrong answer.

Section-A (05 – 08) contains 4 multiple choice questions which have one or more than one correct answer. Each question carries +4 marks for correct answer. No negative marks for wrong answer.

Section-A (09 – 12) contains 2 paragraphs. Based upon paragraph, 3 and 2 multiple choice questions have to be answered. Each question has only one correct answer and carries +4 marks for correct answer and – 1 mark for wrong answer.

(ii) Section-B (01) contains 1 Matrix Match Type question containing statements given in 2 columns. Statements in the first column have to be matched with statements in the second column. Each question carries +8 marks for all correct answer. For each correct row +2 mark will be awarded. There may be one or more than one correct choice. No marks will be given for any wrong match in any question.

(iii) Section-C (01 – 04) contains 4 Numerical based questions with single digit integer as answer, ranging from 0 to 9 and each question carries +4 marks for correct answer. No negative marks for wrong answer.

Name of the Candidate :__________________________________________

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Enrolment Number :_______________________________________________

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S –

17

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FIITJEE

CPT - 5

CODE: 1221.1

PAPER - 2

PHASE TEST – 5 AIS/BPS/PCMC CLASS XII SET A (1221.1)

FIITJEE PCMC CENTER, 4TH FLOOR, ABOVE VIJAY SALES, EMPIRE ESTATE, CHINCHWAD, PUNE – 411019 PH NO 020 46918686

2

PPPAAARRRTTT ––– III ::: PPPHHHYYYSSSIIICCCSSS

SECTION – A (Multiple Choice Type)

This section contains 4 multiple choice questions. Each question has four choices (A), (B), (C) and (D), out of which ONLY ONE is correct.

1. A potentiometer consisting of a uniform wire of length l and resistance R0 is connected to

a steady voltage source V0. The voltage supplied by it to a fixed load R as the function of

the distance ‘x’ of sliding contact from the higher potential end is (analyse the case when R

> > R0

A) 2

0

2

V x

l B)

( )0

2

V x x-l

l C) 0V x

l D)

( )

2

0V x

x-l l

2. Two identical capacitors 1 and 2 are connected in series to a battery as shown in fig.

Capacitor 2 contains a di-electric slab of di-electric constant k as shown. 1 2Q and Q are

the charges stored in the capacitors. Now the di-electric slab is removed and the

corresponding charges are 1 1

1 2Q and Q . Then

E

1 2

A) 1

1

1

1Q k

Q k

+= B)

1

2

2

1

2

Q k

Q

+= C)

1

2

2

1

2

Q k

Q k

+= D)

1

1

1 2

Q k

Q k=

Space for rough work



3

3. Electrically charged identical drops of mercury fall from altitude h into a spherical metal vessel of radius R in the upper part of which there is small opening . The mass of each drop is m and charge is q . What is the number ‘n’ of last drop that can still enter the sphere .

A)

2

0

2

4 ( )mg h R

q

− B)

2

0

2

4 mgR

q

C)

2

0

2

4 mgh

q

D) 0

2

4 ( )mg h R R

q

−

4. The diagram shows a small bead of mass m carrying charge q. The bead can freely move on the smooth fixed ring placed on a smooth horizontal plane. In the same plane a charge +Q has also been fixed as shown. The potential at the point P due to +Q is V. The velocity with which the bead should projected from the point P so that it can complete a circle should be greater than

A) 6qV

m B)

qV

m C)

3qV

m D)

4qV

m




4

(One or More than One Correct Type) This section contains 4 multiple choice questions. Each question has four choices (A), (B), (C) and (D) out of which ONE OR MORE may be correct.

5. In the circuit shown in the figure, switch S is closed at Time t = 0. Select the correct statements (A) rate of increase of charge is same in both the capacitors (B) ratio of charge stored in capacitors C and 2C at any time would be 1: 2 (C) time constant of both the capacitors are equal (D) steady state charge in capacitors C and 2C are in the ratio of 1 : 2

6. In the circuit shown, A and B are equal resistances. When S is closed, the capacitor C charges from the cell of emf and reaches a steady state

(A) During charging, more heat is produced in A than in B (B) In steady state, heat is produced at the same rate in A and B

(C) In the steady state, energy stored in C is 21C

4

(D) In the steady state energy stored in C is 21C

8


S A

B

C

+

2R

R

C

2C

E

S



5

7. An ellipsodal cavity within a perfect conducter ( see figure). A positive charge q is placed at the center of the cavity. The points A and B are on the cavity surface as shown in figure. Then, (A) electric field near A in the cavity = electric field near B

in the cavity. (B) charge density at A = charge density at B (C) potential at A = potential at B (D) total electric flux through the surface of the cavity is

0

q

8. A conducting sphere of radius R, carrying charge Q, lies inside an uncharged conducting

shell of radius 2R. When joined by a metal wire.

(A) 3

Q amount of charge will flow from the sphere to the shell

(B) 2

3

Q amount of charge will flow from the sphere to the shell

(C) Q amount of charge will flow from the sphere to the shell

(D) 2

016

Q

R amount of heat will be produced




6

Comprehension Type

This section contains 2 paragraphs. Based upon each paragraph, 3 and 2 multiple choice questions have to be answered. Each question has 4 choices (A), (B), (C) and (D), out of which ONLY ONE is correct.

Paragraph for Questions 09 and 10

A solid conducting sphere of radius ‘a’ is surrounded by a thin uncharged concentric conducting shell of radius 2a. A point charge q is placed at a distance 4a from common centre of conducting sphere and shell. The inner sphere is then grounded.

9. The charge on solid sphere is

(A) 2

q− (B)

4

q−

(C) 8

q− (D)

16

q−

10. Pick up the correct statement

(A) Charge on surface of inner sphere is non-uniformly distributed (B) Charge on inner surface of outer shell is non-uniformly distributed.

(C) Charge on outer surface of outer shell is non-uniformly distributed (D) All the above statements are false.




7

Paragraph for Q. Nos. 11 to 12

Two small identical solid spheres of mass m each and charges Q, -Q respectively are initially held at a separation of x0 on a rigid fixed surface as shown. The balls and the surface are rough. Consider only electrostatic interaction between the balls and frictional interaction between the balls and rigid surface. Forces F as shown are normal to the surface and act through the centres of spheres through out their motion. Radius of spheres is much smaller compared to x0 . The system is released from rest. ‘x’ is the instantaneous separation between the spheres 11. Acceleration ‘a’ of one sphere with respect to the other may be given by

A)

2

20

5Q

14 mx B)

2

20

2Q

7 mx C)

2

20

Q

28 mx D)

2

20

5Q

2 mx

12. It is found that slipping starts when the separation between the spheres reduces to half of

their initial separation . Then coefficient of friction is given by

A)

2

20

2Q

7F x B)

2

20

Q

7F x C)

2

20

5Q

7F x D)

2

20

Q

14F x


m

F

m

F

Rigid surface



8

SECTION–B Matrix−Match Type

This Section contains 1 question. Each question has four statements (A, B, C and D) given in Column I and five statements (p, q, r, s and t) in Column II. Any given statement in Column I can have correct matching with ONE or MORE statement(s) given in Column II. For example, if for a given question, statement B matches with the statements given in q and r, then for the particular question, against statement B, darken the bubbles corresponding to q and r in the ORS.

p q r s

p q r s

p q r s

p q r s

A B C

D

p q r s t

t

t

t

t

1. Match the column:

In the circuit shown in fig, plates of capacitor 1C are gradually pulled apart.

Column – I Column – II

A) Potential difference across 2C p) will increase

B) charge on 2C q) will decrease

C) Potential energy stored in 2C r) will remains same

D) Electric field between plates of 1C s) some times will increase and

some times decrease. t) Nothing can be said




9

PART – C (Integer Type)

This section contains 4 questions. The answer to each question is a single-digit integer, ranging from 0 to 9. The correct digit below the question number in the ORS is to be bubbled.

N1. A capacitor stores 50 C charge when connected across a battery. When the gap

between the plates is filled with a dielectric, a charge of 100 C flows through the battery. Find the dielectric constant of the material inserted.

N2. Two identical particles, each having a charge of 2.0 10–4 C and mass of 10g, are kept

N3. A parallel-plate capacitor is filled with a dielectric material having resistivity and dielectric constant K. The capacitor is charged and disconnected from the charging source. The capacitor is slowly discharged through the dielectric. This time constant of

discharging is 0

nk.

2 Find ‘n’

N4. A capacitor of capacitance 10 F is connected to a battery of emf 2 V. It is found that it

takes 50 ms for the charge on the capacitor to become 12.6 C. Find the resistance of

the circuit. (in k)


at a separation of 10 cm and then released. The speeds of the particles when the separation becomes very large, is 100 n. Find ‘n’

(A) H C2

CH3

CH3

H C3

and H C3

CH3

CH3

H C3

(B) H C2

CH3

CH3

H C3

and

H C3

CH3

(C) andH C3

CH3

H C3

H C3 CH3

CH3

(D) H C2

CH3

CH3

H C3

and H C2

CH3

CH3

2

2 3 2

i) alc. KOH NaNHii) NaNH CH CH Cl → A B. A and B →

Br

Br

(A) A ≡CH2

B ≡CH3

(B) A ≡CH2

B ≡CH3

(C) A ≡CH

B ≡ CH3

(D) None of these

1: An alkyl halide of formula C6H13Cl on treatment with potassium t-butoxide gives two isomericalkenes (C6H12). Both alkenes on hydrogenation give 2, 3, dimethyl butane. Isomeric alkenes are

2:

(A) (B)

(C) (D)

H ?+

∆C →6H5

OH

C6H5

OH

CH3

CH3

(A) C6H5 C

O

C

CH3

CH3

CH3 (B)C6H5 C

CH3

C6H5

C

O

CH3

(C) C6H5 C

C6H5

C

CH3

CH3 (D) None of these

3: Mononitration of phenyl benzoate gives:

4: Identify the final product

CH3

CH3

(A) (B) (C) DilKmnO4 HIO4 O H–

(A) OH

CH3

CH3

OH (B)H C3 CH3

O O

(C)

OH

O

(D)

HO

O

CH3

aldehydes (D) C2H4O and (E) C2H2O2 and formed. On ozonolysis of (B) only propanal is formed.Compound (A), (D) & (E) are

(A) H C3CH3 (B)

CHO

CHO

(C) H C3CH3 (D) CH3CHO

5: Suggest appropriate structures for the missing compounds. (The number of carbon atoms remains

the same throughout the reactions). Compound (A), (B) & (C) can be

6: An organic compound (A) reacts with H2 to give (B) and (C) successively. On ozonolysis of (A),

two

Cl

NaOH

3600CIntermediate H2O

Phenol + (A) + (B)AromaticHigh pressure Side products

Which of the following statements are correct for above reaction ?

(A) Phenol is formed via an intermediate that is aromatic.

(B) Diphenylether is also formed as by product.

(C) p-phenylphenol is also formed as by product.

(D) Biphenylene is also formed as by-product.

(A)

OH

HCH3 2C CH+

+ − = →

H

+

→H

(C) Phenol + Isobutyl chloride ∆→3AlCl (D) Phenol + Tert butyl chloride →3AlCl

7. In the Dow process for the manufacture of phenol, chlorobenzene is fused with NaOH at hightemp and under pressure.

8. Which of the following gives p-tert butyl phenol ?

(B) Phenol + Tert butyl alcohol

Although chlorobenzene is inert to nucleophilic substitution, it gives quantitative yield of phenolwhen heated with aq. NaOH at high temperature and under high pressure. Phenol, so formed, isa weaker acid than the cabroxylic acid; hence it dissolves only in strong bases like NaOH, butnot in weak bases like NaHCO3. It reacts with acid chlorides and acid anhydrides in the absenceof AlCl3 to form esters. As far as electrophilic substitution in phenol is concerned, the –OH is anactivating group, hence its presence enhances the electrophilic substitution in the o- and p-positions.

Condensation with formaldehyde is one of the important property of phenol. The condensationmay take place in presence of acids or alkalis and leads to the formation of bakelite, an importantindustrial polymer.

6 5 3C H CO H HCl→A B→CH2

(A)O

(B)Cl

OH

(C)OH

Cl

(D)OH

O

3 2 4

2

Mg dust H O H SOEt O A B

+−→ → →O

(A)

OH

(B)

O

(C)

OH

(D)

O

9: The product (B) in the following sequence of reaction is:

10:

an alcohol with molecular formula 3 6C H O and G is a yellow colour compound.

11: Compound A is(A) Methanal (B) Ethanal(C) Propanone (D) Propanal

12: Compound D is(A) Lactic Acid (B) Aspartic Acid(C) Tataric Acid (D) Succinic Acid

According to following reaction steps find out the product. A Compound is a carbonyl compoundwith lowest Molecular mass & can show positive Iodoform Test. D is acid with optical activity. F is

(A)4LiAlH

H+H C →3 C

CH3

CH2

(B) 2 4H SO

CH2OH

(q) H C3

OH

CH3

CH3

CH2OH

(r)

(D) 3C 3H OH MgI

+

+ →

O

(s)

CH3

∆→

(C)

(p)O

1. Number of possible isomers for 2 2 2C H Cl

2. Total number of isomers formed when 2-methyl butane is subjected to monochlorination

3. 9.2 mg of an organic compound (A) reacts with excess CH3CH2MgBr to give 6.72 mL of a gasat STP. What is the number of active hydrogen present in the compound (A) if its mol.wt. is 92.

4. What is the number of compounds having a benzene nucleus can have the molecular formulaC7H8O?

SECTION – A (Multiple Choice Type)

This section contains 4 multiple choice questions. Each question has four choices (A), (B), (C) and (D), out of which ONLY ONE is correct.

1. If 𝑓(𝑥). 𝑓(𝑦) = 𝑓(𝑥) + 𝑓(𝑦) + 𝑓(𝑥𝑦) − 2∀ 𝑥, 𝑦 ∈ 𝑅 and 𝑖𝑓 𝑓(𝑥) is not a constant function,

then the value of 𝑓(1) is equal to (A) 1 (B) 2 (C) 0 (D) -1 2. where [.] denotes greates integer function, is equal to (A) 0 (B) 1 (C) does not exist (D) sin 1

3. 𝑓(𝑥) = {𝑥 + 2 𝑥 < 0

−𝑥2 − 2 0 ≤ 𝑥 < 1𝑥 𝑥 ≥ 1

Then the number of points of discontinuity of |𝑓(𝑥)| is (A) 1 (B) 2 (C) 3 (D) none of these 4. 𝐼𝑓 𝑓(𝑥) = log 𝑥, then 𝑓′(log 𝑥) equals :

(A) 𝑥

log 𝑥 (B)

log 𝑥

𝑥 (C)

1

𝑥 𝑙𝑜𝑔 𝑥 (D)

1

log 𝑥


(One or More than One Correct Type) This section contains 4 multiple choice questions. Each question has four choices (A), (B), (C) and (D) out of which ONE OR MORE may be correct.

5. 𝐼𝑓: 𝑅 → 𝑅, 𝑓(𝑥) = 𝑒−|𝑥| − 𝑒𝑥 is a given function, then which of the following are correct: (A) f is many – one into function (B) f is many one onto function (C) range of f is [0, ∞] (D) range of f is (−∞, 0] 6. Which of the following limits tend to unity ? (A) (B) (B) (C) (D) 7. A function f (x) satisfies the realtion 𝑓(𝑥 + 𝑦) = 𝑓(𝑥) + 𝑓(𝑦) + 𝑥𝑦(𝑥 + 𝑦)∀ 𝑥, 𝑦 ∈ 𝑅. if 𝑓′(0) = −1, then (A) f(x) is a polynomial function (B) f(x) is an exponential function (C) f (x) is twice differentiable for all 𝑥 ∈ 𝑅 (D) f’(3)= 8

8. if 𝑓(𝑥) = 𝑥3 − 𝑥2 + 100𝑥 + 1001, then

(A) 𝑓(2000) > 𝑓(2001) (B) 𝑓 (1

1999) > 𝑓 (

1

2000)

(C) 𝑓(𝑥 + 1) > 𝑓(𝑥 − 1) (D) 𝑓(3𝑥 − 5) > 𝑓(3𝑥)


lim𝑡→0

sin(tan 𝑡)

sin 𝑡

lim𝑡→𝜋/2

sin (cos 𝑥)

cos 𝑥

lim𝑥→0

√𝑥2

𝑥

lim𝑥→𝜋/2

(1−cos 𝑥

𝑥2 )

Comprehension Type

This section contains 2 paragraphs. Based upon each paragraph, 3 and 2 multiple choice questions have to be answered. Each question has 4 choices (A), (B), (C) and (D), out of which ONLY ONE is correct.

Paragraph for Questions 09 and 10

Let a function is defined as 𝑓(𝑥) = {

[𝑥] , −2 ≤ 𝑥 −1

2

2𝑥2 − 1 , −1

2< 𝑥 ≤ 2

, where [.] denotes greatest integer

function. Answer the follwing question by using the above information. 9. The number of points of discontinuity of f(x) is (A) 1 (B) 2 (C) 3 (D) None of these 10. Number of points where |f(x)|is not differentiable is (A) 1 (B) 2 (C) 3 (D) 4

for rough work

Paragraph for Q. Nos. 11 to 12

If a continuous function f defined on the real line R, assumes positive and negative values in the R then the equation f (x) =0 has a root in R. For example, if it is known that a continoues function f on R is positive at some point and its minimum value is negative then the equation f (x) =0 has a root in R consider f (x) 𝑘𝑒𝑥 − 𝑥 for all real X where k is a real constant. 11. The line 𝑦 = 𝑥 meets 𝑦 = 𝑘𝑒𝑥 for 𝑘 ≤ 0 at (A) no point (B) one point (C) two points (D) more than two ponts 12. The positive value of k for which 𝑘𝑒𝑥 − 𝑥 = 0 has only one roots is

(A) 1

𝑒 (B) 1 (C) e (D) loge 2


SECTION–B Matrix−Match Type

This Section contains 1 question. Each question has four statements (A, B, C and D) given in Column I and five statements (p, q, r, s and t) in Column II. Any given statement in Column I can have correct matching with ONE or MORE statement(s) given in Column II. For example, if for a given question, statement B matches with the statements given in q and r, then for the particular question, against statement B, darken the bubbles corresponding to q and r in the ORS.

p q r s

p q r s

p q r s

p q r s

A B C

D

p q r s t

t

t

t

t

Match the columns.

Column I Column II

(A) Value of x satisfying sin−1 𝑥 − cos−1𝑥 = 𝑐𝑜𝑠−1 (√3

2) 𝑖𝑠

(p) < 0

(B) Value of sec2(tan−1 2) + 𝑐𝑜𝑠𝑒𝑐2(cot−13) 𝑖𝑠

(q) < 1

(C) Greatest value of x, satisfying sin−1 𝑥 −cos−1x = sin−1(3𝑥 − 2) is

(r) ≥ 1

(D) Value of sin−1(sin 5) is (s) > 0

(t) > 2


PART – C (Integer Type)

This section contains 4 questions. The answer to each question is a single-digit integer, ranging from 0 to 9. The correct digit below the question number in the ORS is to be bubbled.

1. Find the number of solution of the equation |𝑥 − 1| = 2[𝑥] − 3{𝑥} (𝑤ℎ𝑒𝑟𝑒 [𝑥]& {𝑥} denotes integral and fractional part of x)

2. 𝑖𝑓 (√𝑥4 + 𝑎𝑥3 + 3𝑥2 + 𝑏𝑥 + 2 − √𝑥4 + 2𝑥3 − 𝑐𝑥2 + 3𝑥 − 𝑑) = 4, then (a + c )

3. 𝐿𝑒𝑡 𝑓(𝑥) = {𝑥𝑒𝑎𝑥 , 𝑥 ≤ 0

𝑥 + 𝑎𝑥2 − 𝑥3, 𝑥 > 0 where a is positive constant and the interval in which

f ’ (x) is increasing is (−𝜆1

𝑎,

𝑎

𝜆2), then find (𝜆1 + 𝜆2)

4. Find number of solution of the equation (tan−1 𝑥)2 + (cot−1 𝑥)2 =5𝜋2

8.


lim𝑥→∞

ANSWER KEY

PHYSICS

ANSWER KEY

Single choice 4 question

1. C

2.C

3. D

4. A

More than one choice 4 question

1. B,C,D

2. A,B,D

3. C,D

4. C,D

Passage – I 1.B

2.C

Passage – II 1. A

2. D

Integer type 4 question

1. 3

2. 6

3. 2

4. 5

Match the column

A – Q , B – Q

C – Q , D – Q

Hint and Solutions

Single choice

3.

0

2q

2 2Knq Knq+mgh= +mg2R

h-R R

4 mg( h-R) Rsolving we will get n=

4. Applying conservation of energy

21V.q mu 4V.q 0

2

6Vqu

m

+ = +

=

More than one

3. C, D

Charge density at A < Charge density at B. Since field inside cavity is zero, hence potential at

A =

potential at B = a constant value

By Gauss theorem total electric flux = 0

1

Passage I

The inner sphere is grounded, hence its potential is zero. The net charge on isolated

outer

sphere

is zero. Let the charge on inner sphere be q .

Potential at centre of inner sphere is

0 0

1 10 0

4 4 4

q q

a a

+ + =

4

qq = −

The region in between conducting sphere and shell is shielded from charges on and outside

the

outer surface of shell. Hence charge distribution on surface of sphere and inner sueface of

shell is uniform.The distribution of induced charge on outer surface of shell depends only

on point charge q. hence is non-uniform.

passageII

2

r r2

2 2 2

2 2 2

0

2

2

0

2 2

r 2 2

0 0

2

r2

0

KQ 2f ma ; f = ma

x 5

KQ 7 5KQ 5Qso ma ; a=

x 5 7mx 28 mx

5Qso relative acceeptence is

14 mx

2 2 5Q 2Qf ma m

5 5 28 mx 28 x

Q when slipping occurs f = F

14 x

− =

= =

= = =

=

H C C C C− ≡ − −

1.

2. C6 5

3. Mono Nitration (Any Electrophylic substitution) reaction determine by +M group present in Benzenenucleus.

4. Pinacolone

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Typewritten text

HINTS & SOLUTIONS

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Typewritten text

PART - A

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Typewritten text

CHEMISTRY

(A) = OH

CH3

CH3

OH (B) = H C3 CH3

O O

(C) =

HO

O

CH3

Aldol

A =H C3CH3 B = H C3

CH3

C = H C3CH3 D = H3C — CHO

E =

CHO

CHO

COMPREHENSIONS

OH Cl+ −

→O

+H

Cl−→

Cl

5. (A), (B), (D)

6. (B), (C), (D)

9

10. pinacool- Pmacolone rearrangement

11. Conceptual

OH

(A)

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7.BC 8.BCD

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B

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B

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B

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12. A

MATRIX-MATCH TYPE QUESTIONS

MATRIX-MATCH TYPE QUESTIONS

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PART - C

1. C C

H

H Cl

Cl

C C

Cl

H H

Cl

C C

H

Cl H

Cl

2. | |2C /l h

C CC − C C C υ C C C C Cl− − → − − − −

|

|

C*

C C C CCl

− − −

|

*

CC l C C C C− − − −

|

|

CC C C C

Cl− − −

INTEGER TYPE QUESTIONS

3

4

9.2Number of moles 10

9210

X

mol

−

−

=

=

Coresponding volume of gas

10 4 322.4 103

n X X Xn

= −

⇒ =

3. 3

4. 5

(i) Anisole

(ii) Benzyl aleohol

(iii) 2 Methyl phenol

(iv) 3 Methyl phenol

(v) 4 Methyl phenol

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