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NEET-2020 CODE-E1 Page - 1 “Gyan Tower” Near Shivbari Circle, Old Shivbari Road, Bikaner (0151-2206735, 2233735, Mob. : 80030948-91/92/93, web.www.synthesis.ac.in) 136. For which one of the following, Bohr model is not valid : (1) Hydrogen atom (2) Singly ionised helium atom (He + ) (3) Deuteron atom (4) Singly ionised neon atom (Ne + ) Ans. (4) Singly ionised neon atom (Ne + ) Sol : Theroritical 137. The ratio of contributions made by the electric field and magnetic field components to the intensity an electromagnetic wave is : (c = speed electromagnetic waves) (1) c : 1 (2) 1 : 1 (3) 1 : c (4) 1 : c 2 Ans. (2) 1 : 1 Sol : 2 2 e 0 B 0 1 1B U E U 2 2 2 e 0 0 B U E U B 0 0 2 0 0 1 1 C C e B U 1 U 1 138. The Brewsters angle i b for an interface should : (1) 0º < i b < 30º (2) 30º < i b < 45º (3) 45º < i b < 90º (4) i b = 90º Ans. (3) 45º < i b < 90º Sol : Theroritical Paper Code : [E1] Test Date : 13.09.2020 NEET(UG) – 2020 (Question Paper with Answer & Solution) PHYSICS (with solution)
Transcript
Page 1: PHYSICS (with solution) NEET(UG) – 2020synthesis.ac.in/neet2020/pdf/PhysicsSolutionNeet2020_AnsKey.pdf · NEET(UG) – 2020 (Question Paper with Answer & Solution) PHYSICS (with

NEET-2020 CODE-E1

Page - 1“Gyan Tower” Near Shivbari Circle, Old Shivbari Road, Bikaner

(0151­2206735, 2233735, Mob. : 80030948­91/92/93, web.www.synthesis.ac.in)

136. For which one of the following, Bohr model is not valid :

(1) Hydrogen atom (2) Singly ionised helium atom (He+)

(3) Deuteron atom (4) Singly ionised neon atom (Ne+)

Ans. (4) Singly ionised neon atom (Ne+)

Sol : Theroritical

137. The ratio of contributions made by the electric field and magnetic field components to the intensity an

electromagnetic wave is : (c = speed electromagnetic waves)

(1) c : 1 (2) 1 : 1 (3) 1 : c (4) 1 : c2

Ans. (2) 1 : 1

Sol :

22

e 0 B

0

1 1 BU E U

2 2� � �

2

e0 0

B

U E

U B

� �� � � � �

0 0 2

0 0

1 1C

C� � � �� �

e

B

U 1

U 1�

138. The Brewsters angle ib for an interface should :

(1) 0º < ib < 30º (2) 30º < i

b < 45º (3) 45º < i

b < 90º (4) i

b = 90º

Ans. (3) 45º < ib < 90º

Sol : Theroritical

Paper Code : [E1] Test Date : 13.09.2020

NEET(UG) – 2020

(Question Paper with Answer & Solution)

PHYSICS (with solution)

Page 2: PHYSICS (with solution) NEET(UG) – 2020synthesis.ac.in/neet2020/pdf/PhysicsSolutionNeet2020_AnsKey.pdf · NEET(UG) – 2020 (Question Paper with Answer & Solution) PHYSICS (with

NEET-2020 CODE-E1

Page - 2“Gyan Tower” Near Shivbari Circle, Old Shivbari Road, Bikaner

(0151­2206735, 2233735, Mob. : 80030948­91/92/93, web.www.synthesis.ac.in)

139. A cylinder contains hydrogen gas at pressure of 249 kPa and temperature 27ºC. Its density is :

(R = 8.3 J mol–1 K–1)

(1) 0.5 kg/m3 (2) 0.2 kg/m3 (3) 0.1 kg/m3 (4) 0.02 kg/m3

Ans. (2) 0.2 kg/m3

Sol : P = 249 kPa T = 273 + 27º = 300 K

PV = nRT

mPV RT MW 2

MW� �� � ��

P RT2

��

32P 2 249 10

RT 8.3 300

� ��� �

� = 0.2 Kg/m3

140. A ray is incident at an angle of incidence i on one surface of a small angle prism (with angle of prism A)

and emerges normally from the opposite surface. If the refractive index of the material of the prism is �,

then the angle of incidence is nearly equal to :

(1) �A

2(2) �

2A(3) �A (4)

�A2

Ans. (3) �A

Sol : 1 sin i = � sin A

as angle is small i = �A

141. Two cy linders A and B of equal capacity are connected to each other via a stop cock. A contains an ideal

gas at standard temperature and pressure. B is completely evacuated. The entire system is thermally

insulated. The stop cock is suddenly opened. The process is :

(1) Isothermal (2) Adiabatic (3) Isochoric (4) Isobaric

Ans. (2) Adiabatic

Sol : Since system is insulated so �Q = 0. Adiabatic will be right choice.

142. The energy equivalent of 0.5 g of a substance is :

(1) 4.5 × 106 J (2) 4.5 × 1013 J (3) 1.5 × 1013 J (4) 0.5 × 13 J

Ans. (2) 4.5 × 1013 J

Sol : E = mC2

E = 0.5 × 10–3 × 9 × 1016

= 4.5 × 1013 J.

Page 3: PHYSICS (with solution) NEET(UG) – 2020synthesis.ac.in/neet2020/pdf/PhysicsSolutionNeet2020_AnsKey.pdf · NEET(UG) – 2020 (Question Paper with Answer & Solution) PHYSICS (with

NEET-2020 CODE-E1

Page - 3“Gyan Tower” Near Shivbari Circle, Old Shivbari Road, Bikaner

(0151­2206735, 2233735, Mob. : 80030948­91/92/93, web.www.synthesis.ac.in)

143 A body weigns 72 N on the surface of the earth. What is the gravitational force on it, at a height equal

to half the radius of the earth :

(1) 48 N (2) 32 N (3) 30 N (4) 24 N

Ans. (2) 32 N

Sol :

2

Rg' g

RR

2

� �� �

� � �� �� �

4g' g

9

� �� � � �

m = 7.2 kg

4gW ' mg' 7.2 32N

9� � � �

144. The solids which have the negative temperature coefficient of resistance are :

(1) Metals (2) Insulators only

(3) Semiconductors only (4) Insulators and semiconductors

Ans. (4) Insulators and semiconductors

Sol : Theoritical

145. The phase difference between displacement and acceleration of a particle in a simple harmonic motion is:

(1) � rad (2) �3

rad2

(3) �

rad2

(4) Zero

Ans. (1) � rad

Sol : x = A sin �t

a = –A�2 sin �t

So phase difference is �

146. A screw gauge has least count of 0.01 mm and there are 50 divisions in its circular scale. The pitch of the

screw gauge is :

(1) 0.01 mm (2) 0.25 mm (3) 0.5 mm (4) 1.0 mm

Ans. (3) 0.5 mm

Sol : Pitch of screw gauge = 0.01 mm × 50 .5 mm

147. In a guitar, two strings A and B made of same material are slightly out of tune and proeuce be of

frequency 6 Hz. When tension in B is slightly decreased, the beat frequency increase to 7. If the frequency

of A is 530 Hz, the original frequency of B will be :

(1) 523 Hz (2) 524 Hz (3) 536 Hz (4) 537 Hz

Ans. (2) 524 Hz

Sol : A � 530 Hz

When T increase then frequency of B increases. So possible value of B which can give 7 Hz beat will

524 Hz.

Page 4: PHYSICS (with solution) NEET(UG) – 2020synthesis.ac.in/neet2020/pdf/PhysicsSolutionNeet2020_AnsKey.pdf · NEET(UG) – 2020 (Question Paper with Answer & Solution) PHYSICS (with

NEET-2020 CODE-E1

Page - 4“Gyan Tower” Near Shivbari Circle, Old Shivbari Road, Bikaner

(0151­2206735, 2233735, Mob. : 80030948­91/92/93, web.www.synthesis.ac.in)

148. Two particles of mass 5 kg and 10 kg respectively are attached to the two ends of a rigid rod of length

1 m with negligible mass. The centre of mass of the system from the particles is nearly at a distance of :

(1) 33 cm (2) 50 cm (3) 67 cm (4) 80 cm

Ans. (3) 67 cm

Sol :10 1

COM 67cm15

�� �

149. Find the torque about the origin when a force of 3̂jN acts on a particle whose position vector is ˆ2k m :

(1) ˆ6i Nm (2) ˆ6 jNm (3) ˆ-6iNm (4) ˆ6k Nm

Ans. (3) ˆ-6i Nm

Sol : r F� � ����

ˆ ˆ2k 3j� �

ˆ6i Nm��

150. Light with an average flux of 20 W/cm2 falls on a non-reflecting surface at normal incidence having

surface area 20 cm2. The energy received by the surface during time span of 1 minute is :

(1) 10 × 103 J (2) 12 × 103 J (3) 24 × 103 J (4) 48 × 103 J

Ans. (3) 24 × 103 J

Sol : 2

P 20

A m

��

P = 20 × 20

E = 20 × 20 × 60

= 24 × 103 J

151. A spherical conductor of radius 10 cm has a charge of 3.2 × 10–7 C distritubed uniformly. What is the

magnitude of electric field at a point 15 cm from the centre of the sphere : � �

� �� ����

9 2 2

0

19 10 Nm / C

4

(1) 1.28 × 104 N/C (2) 1.28 × 105 N/C (3) 1.28 × 106 N/C (4) 1.28 × 107 N/C

Ans. (2) 1.28 × 105 N/C

Sol : 2

kQE

r�

9 7

2

9 10 3.2 10

.15

�� � ��

= 1.28 × 105 N/C

Page 5: PHYSICS (with solution) NEET(UG) – 2020synthesis.ac.in/neet2020/pdf/PhysicsSolutionNeet2020_AnsKey.pdf · NEET(UG) – 2020 (Question Paper with Answer & Solution) PHYSICS (with

NEET-2020 CODE-E1

Page - 5“Gyan Tower” Near Shivbari Circle, Old Shivbari Road, Bikaner

(0151­2206735, 2233735, Mob. : 80030948­91/92/93, web.www.synthesis.ac.in)

152. In a certain region of space with volume 0.2 m3 the electric potentials is found to be 5 V throughout. The

magnitude of electric field in this region is :

(1) Zero (2) 0.5 N/C (3) 1 N/C (4) 5 N/C

Ans. (1) Zero

Sol : V 0� ��

VE 0

r

��� ��

153. The increase in the width of the depeltion region in a p-n junction diode is due to :

(1) Forward bias only

(2) Reverse bias only

(3) Both forward bias and reverse bias

(4) Increase in forward current

Ans. (2) Reverse bias only

Sol : Only in reverse bias the width increases.

154. A 40 �F capacitor is connected to a 200 V, 50 H ac supply. The rms value of the current in the circuit is,

nearly :

(1) 1.7 A (2) 2.05 A (3) 2.5 A (4) 25.1 A

Ans. (3) 2.5 A

Sol : C

1x

2 fC�

C

VI 200 2 fC

x� � � �

= 200 × 2 × 3.14 × 50 × 40 × 10–6

155. The mean free path for a gas, with molecular diameter d and number density n can be expressed as :

(1) �

1

2n d(2) 2

1

2n d�(3)

�2 2

1

2n d(4)

�2 2 2

1

2n d

Ans. (2) 2

1

2n d�

Sol : 2

1

2 nd� �

Page 6: PHYSICS (with solution) NEET(UG) – 2020synthesis.ac.in/neet2020/pdf/PhysicsSolutionNeet2020_AnsKey.pdf · NEET(UG) – 2020 (Question Paper with Answer & Solution) PHYSICS (with

NEET-2020 CODE-E1

Page - 6“Gyan Tower” Near Shivbari Circle, Old Shivbari Road, Bikaner

(0151­2206735, 2233735, Mob. : 80030948­91/92/93, web.www.synthesis.ac.in)

156. For transistor action, which of the following statements is correct :

(1) Base, emitter and collector regions should have same doping concentrations

(2) Base, emitter and collector regions should have same size

(3) Both emitter junctions as well as the collector junction are forward biased

(4) The base region must be very thin and light doped

Ans. (4) The base region must be very thin and light doped

Sol :

157. Light of frequency 1.5 times the threshold frequency is incident on a photosensitive materials . What will

be the photoelectric current if the frequency is halved and intensity is doubled :

(1) Doubled (2) Four times (3) One-fourth (4) Zero

Ans. (4) Zero

Sol : �0 = Threshold frequency

1.5 h�0 = �

0 + KE

but for � = 0.75 �0

KE = 0

I = 0

158. When a uranium siotope 235

92U is bombarded with a neutron, it generates 89

36Kr , three neutrons and :

(1) 144

56Ba (2) 91

40Zr (3) 101

36Kr (4) 103

36Kr

Ans. (1) 144

56Ba

Sol : Another atom’s Z = 92 – 36 = 56

So, 144

56Ba

159. The energy required to break one bond in DNA is 10–20 J. This value in eV is nearly :

(1) 6 (2) 0.6 (3) 0.06 (4) 0.006

Ans. (3) 0.06

Sol :

2020

19

1010 J eV 0.062eV

1.6 10

��

�� ��

= 0.06 eV

Page 7: PHYSICS (with solution) NEET(UG) – 2020synthesis.ac.in/neet2020/pdf/PhysicsSolutionNeet2020_AnsKey.pdf · NEET(UG) – 2020 (Question Paper with Answer & Solution) PHYSICS (with

NEET-2020 CODE-E1

Page - 7“Gyan Tower” Near Shivbari Circle, Old Shivbari Road, Bikaner

(0151­2206735, 2233735, Mob. : 80030948­91/92/93, web.www.synthesis.ac.in)

160. Two bodies of mass 4 kg and 6 kg are tied to the ends of a massless string. The string passes over a

pulley which is frictionless (see figure). The acceleration of the system in terms of acceleration due to

gravity (g) is :

(1) g (2) g/2 (3) g/5 (4) g/10

Ans. (3) g/5

Sol :1 2

1 2

m ma g

m m

��

6 4 g 2g g

6 10 10 5

�� � �

161. A wire of length L, area of cross section A is hanging from a fixed support. The length of the wire changes

to L1 when mass M is suspended from its free end. The expression for Young’s modulus is :

(1) 1

MgL

AL(2)

�1

Mg L L

AL(3)

1

MgL

AL (4)1

MgL

A L -L

Ans. (4)1

MgL

A L -L

Sol : �l = L1 – L

mg Ly

A L

�� �� �� ��

1

MgLy

A L L�

Page 8: PHYSICS (with solution) NEET(UG) – 2020synthesis.ac.in/neet2020/pdf/PhysicsSolutionNeet2020_AnsKey.pdf · NEET(UG) – 2020 (Question Paper with Answer & Solution) PHYSICS (with

NEET-2020 CODE-E1

Page - 8“Gyan Tower” Near Shivbari Circle, Old Shivbari Road, Bikaner

(0151­2206735, 2233735, Mob. : 80030948­91/92/93, web.www.synthesis.ac.in)

162. The average thermal energy for a mono-atomic gas is : (kB is Boltzmann constant and T, absolute

temperature)

(1) B

1k T

2(2) B

3k T

2(3) B

5k T

2(4) B

7k T

2

Ans. (2) B

3k T

2

Sol : B

fKE k T

2�

F = 3 (mono-atomic)

B

3KE k T

2�

163. Which of the following graph represents the variation of resistivity (�) with temperature (T) for copper:

(1) (2) (3) (4)

Ans. (3)

Sol :

Page 9: PHYSICS (with solution) NEET(UG) – 2020synthesis.ac.in/neet2020/pdf/PhysicsSolutionNeet2020_AnsKey.pdf · NEET(UG) – 2020 (Question Paper with Answer & Solution) PHYSICS (with

NEET-2020 CODE-E1

Page - 9“Gyan Tower” Near Shivbari Circle, Old Shivbari Road, Bikaner

(0151­2206735, 2233735, Mob. : 80030948­91/92/93, web.www.synthesis.ac.in)

164. The color code of a resistance is given below :

The values of resistance and tolerance, respectively are :

(1) 470 k , 5% (2) 47 k , 10% (3) 4.7 k , 5% (4) 470 , 5%

Ans. (4) 470 , 5%

Sol : Yellow = 4, Violet = 7, Brown = 10’, Gold = ±5%, R = 47 × 10’ ± 5%

470, 5%

165. In Young’s double slit experiment, if the separation between coherent sources is halved and the distance

of the screen from the coherent sources doubled, then the fringe wiegth becomes :

(1) Double (2) Half (3) Four times (4) One-fourth

Ans. (3) Four times

Sol :D

d

�!� ......... (1)

2D 4 D' 4

d d

2

� �! � � � !

� �� ��

!’ = 4!

166. The capacitance of a parallel plate capacitor with air as medium is 6 �F. With the introduction of a

dielectric medium, the capacitance becomes 30 �F. The permittivity of the medium is :

( –12 2 –1 –2

08.85 10 C N m� � � )

(1) 0.44 × 10–13 C2 N–1 m–2 (2) 1.77 × 10–12 C2 N–1 m–2

(3) 0.44 × 10–10 C2 N–1 m–2 (4) 5.00 C2 N–1 m–2

Ans. (3) 0.44 × 10–10 C2 N–1 m–2

Sol :0

0

AC 6 F

d

�� � �

0r

AC '

d

���

30 �F = �r × 6 �F

�r = 5

� = �0�r = 8.85 × 10–12 × 5

= 0.44 × 10–10 C2N–1m–2

Page 10: PHYSICS (with solution) NEET(UG) – 2020synthesis.ac.in/neet2020/pdf/PhysicsSolutionNeet2020_AnsKey.pdf · NEET(UG) – 2020 (Question Paper with Answer & Solution) PHYSICS (with

NEET-2020 CODE-E1

Page - 10“Gyan Tower” Near Shivbari Circle, Old Shivbari Road, Bikaner

(0151­2206735, 2233735, Mob. : 80030948­91/92/93, web.www.synthesis.ac.in)

167. Dimensions of stress ae :

(1) [MLT–2] (2) [ML2T–2] (3) [ML0T–2] (4) [ML–1T–2]

Ans. (4) [ML–1T–2]

Sol :

1 1 2

2

M L TFStress

A L

�� �� � � �� �� � � � �� � � �

= [M1L–1T–2]

168. Assume that light of wavelength 600 nm is coming from a star. The limit of resolution of telescope whose

objective has a diameter of 2 m is :

(1) 3.66 × 10–7 rad (2) 1.83 × 10–7 rad (3) 7.32 × 10–7 rad (4) 6.00 × 10–7 rad

Ans. (1) 3.66 × 10–7 rad

Sol : Limit of resolution = 1.22

a

91.22 600 10

2

�� ��

= 3.66 × 10–7 rad

169. A series LCR circuit is connected to an ac voltage source. When L is removed from the circuit, the phase

difference between current and voltage is 3

�. If instead C is removed from the circuit, the phase difference

is again 3

� between current and voltage. The power factor of the circuit is :

(1) zero (2) 0.5 (3) 1.0 (4) –1.0

Ans. (3) 1.0

Sol : XL = X

C Resonance condition

cos� = 1

170. A short electric dipole has a dipole moment of 16 × 10–9 C m. The electric potential due to the dipole at

a point at a distance of 0.6 m from the centre of the dipole, situated on a line making an angle of 60º

with the dipole axis is :9 2 2

0

19 10 N m / C

4

� �� �� �

���

(1) 50 V (2) 200 V (3) 400 V (4) zero

Ans. (2) 200 V

Sol :

9 9

2

kP cos 9 10 16 10 cos 60ºV

0.36r

�" � � � �� �

= 200 V

Page 11: PHYSICS (with solution) NEET(UG) – 2020synthesis.ac.in/neet2020/pdf/PhysicsSolutionNeet2020_AnsKey.pdf · NEET(UG) – 2020 (Question Paper with Answer & Solution) PHYSICS (with

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Page - 11“Gyan Tower” Near Shivbari Circle, Old Shivbari Road, Bikaner

(0151­2206735, 2233735, Mob. : 80030948­91/92/93, web.www.synthesis.ac.in)

171. An iron red of susceptibility 599 is subjected to magnetising field of 1200 A m–1. The permeability of the

material of the rod is : (�0 = 4�#× 10–7 T m A–1)

(1) 2.4� × 10–4 T m A–1 (2) 8.0 × 10–5 T m A–1

(3) 2.4� × 10–5 T m A–1 (4) 2.4� × 10–7 T m A–1

Ans. (1) 2.4� × 10–4 T m A–1

Sol : �r = (1 + x)

�r = 1 + 599 = 600

� = �0�

r = 4 × 10–7 × 600

= 2400 � × 10–7

= 2.4 � × 10–4 TmA–1

172. A long solenoid of 50 cm length having 100 turn carries a current of 2.5 A. The magnetic field the centre

of the solenoid is : (�0 = 4�#× 10–7 T m A–1)

(1) 6.28 × 10–4 T (2) 3.14 × 10–4 T (3) 6.28 × 10–5 T (4) 3.14 × 10–5 T

Ans. (1) 6.28 × 10–4 T

Sol : B = �0ni

7 1004 10 2.5

0.5

�� �� � �

= 20 � × 10–7 × 100

= 2� × 10–4

= 6.28 × 10–4 T

173. A charged particle having drift velocity 7.5 × 10–4 m s–1 in an electric field 3 × 10–10 Vm–1. has a mobility

in m2 V–1 s–1 of :

(1) 2.25 × 1015 (2) 2.5 × 106 (3) 2.5 × 10–6 (4) 2.25 × 10–15

Ans. (2) 2.5 × 106

Sol :d

V

E��

46

10

7.5 102.25 10

3 10

��� � �

174. The quantities of heat required to raise temperature of two solid copper spheres of r1 and r

2 (r

1 = 1.5 r

2)

through 1 K are in ratio :

(1) 27

8(2)

9

4(3)

3

2(4)

5

3

Ans. (1)27

8

Sol : �Q = mS�"

�Q $ m34

m r3

�� �

�Q $ r3

3

1 1

2 2

Q r 27

Q r 8

� ��� �� �

� �

Page 12: PHYSICS (with solution) NEET(UG) – 2020synthesis.ac.in/neet2020/pdf/PhysicsSolutionNeet2020_AnsKey.pdf · NEET(UG) – 2020 (Question Paper with Answer & Solution) PHYSICS (with

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Page - 12“Gyan Tower” Near Shivbari Circle, Old Shivbari Road, Bikaner

(0151­2206735, 2233735, Mob. : 80030948­91/92/93, web.www.synthesis.ac.in)

175. An electron is accelerated from rest through potential difference of V volt. If the de Broglie wavelength of

the electron is 1.227 × 10–2 nm potential difference is :

(1) 10 V (2) 102 V (3) 103 V (4) 104 V

Ans. (4) 104 V

Sol :12.27

Åv

� � 1 12.271.227 10

V�� �

1 1100 V

� V = 104 V

176. Taking into account of the significant figures is the value of 9.99 m – 0.0099 m ?

(1) 9.9801 m (2) 9.98 m (3) 9.980 m (4) 9.9 m

Ans. (2) 9.98 m

Sol : 9.99 – 0.0099 = 9.9801.

Last digit after decimal in 9.99 are two.

9.99 – 0.0099 = 9.98

177. A ball is thrown vertically downward with a velocity of 20 m/s from the top of a tower. It hits the ground

after some time with a velocity of 80 m/s. The height of the tower is : (g = 10 m/s2)

(1) 360 m (2) 340 m (3) 320 m (4) 300 m

Ans. (4) 300 m

Sol : v2 = u2 + 2as

2 280 20

S2 10

��

S = 300 m

178. A capillary tube of radius r is immersed in water and water rises in it to a height h. The mass of the water

in capillary is 5g. Another capillary tube of radius 2r is immersed in water. The mass of water that will rise

in this tube is :

(1) 2.5 g (2) 5.0 g (3) 10.0 g (4) 20.0 g

Ans. (3) 10.0 g

Sol : M1 = �r2h hr = constant

2

2

hM 2r

2�� � 2M1 = 10 g

179. A resistance wire connected in the left gap of a metre bridge balances a 10 resistance in the right gap

at a point which divides the bridge wire in the ratio 3 : 2. If the length of the resistance wire is 1.5 m, then

the length of 1 #of the resistance wire is :

(1) 1.0 × 10–2 m (2) 1.0 × 10–1 m (3) 1.5 × 10–1 m (4) 1.5 × 10–2 m

Ans. (2) 1.0 × 10–1 m

Sol :R 310 2� R = 15

15 resistance having length 1.5 m and

1 resistance having length 1.5

0.1m15� = 1.0 × 10–1 m

Page 13: PHYSICS (with solution) NEET(UG) – 2020synthesis.ac.in/neet2020/pdf/PhysicsSolutionNeet2020_AnsKey.pdf · NEET(UG) – 2020 (Question Paper with Answer & Solution) PHYSICS (with

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180. For the logic circuit showsn, the truth table is :

(1) A B Y

0 0 0

0 1 0

1 0 0

1 1 1

(2) A B Y

0 0 0

0 1 1

1 0 1

1 1 1

(3) A B Y

0 0 1

0 1 1

1 0 1

1 1 0

(4) A B Y

0 0 1

0 1 0

1 0 0

1 1 0

Ans. (1) A B Y

0 0 0

0 1 0

1 0 0

1 1 1

Sol : A B A.B AB� � �

AND gate

Page 14: PHYSICS (with solution) NEET(UG) – 2020synthesis.ac.in/neet2020/pdf/PhysicsSolutionNeet2020_AnsKey.pdf · NEET(UG) – 2020 (Question Paper with Answer & Solution) PHYSICS (with

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