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In 1995, the population of Calgary was 828 500, and was increasing at the rate of 2.2% per year.(a) Write an equation to represent the population of Calgary, P, as a function of the number of years, y, since 1995.
In 1995, the population of Calgary was 828 500, and was increasing at the rate of 2.2% per year.(b) Calculate how many years it would take for the population to double.
In 1995, the population of Calgary was 828 500, and was increasing at the rate of 2.2% per year.
(c) Calculate when the population would reach 1 million.
In 1995, the population of Calgary was 828 500, and was increasing at the rate of 2.2% per year.
(e) Write the equation in part (a) as an exponential function with base e.
(d) Write the equation in part (a) as an exponential function with base 2.
Calculate the number of years for an investment of $1000 to double at an interest rate of 7.2% for each compunding period.
(d) daily
Polonium-210 is a radioactive element with a half-life of 20 weeks. From a sample of 25 g, how much would remain after each length of time?
(a) 30 weeks (b) 14 weeks (c) 1 year (d) 511 days
Solve each of the following ...
change of base law
Graphing
Natural Logarithms [ln]
Word problems
27^log[base3]9
"A=Pe^rt" method or the "A=P(1+r/n)^tn" method
Feedback From BOB
change of base law
Graphing
Natural Logarithms [ln]
Word problems
27^log[base3]9
"A=Pe^rt" method or the "A=P(1+r/n)^tn" method
Feedback From BOB
change of base law
Graphing
Natural Logarithms [ln]
Word problems
27^log[base3]9
"A=Pe^rt" method or the "A=P(1+r/n)^tn" method
Feedback From BOB
change of base law
Graphing
Natural Logarithms [ln]
Word problems
27^log[base3]9
"A=Pe^rt" method or the "A=P(1+r/n)^tn" method
Feedback From BOB
1. Find the domain and range of f.2. Find the horizontal asymptote of the graph.3. Find the x and y intercepts of the graph. of f if there are any.4. Sketch the graph of f.
1. Find the domain and range of f.2. Find the horizontal asymptote of the graph.3. Find the x and y intercepts of the graph. of f if there are any.4. Sketch the graph of f.
ANSWER: 10 000 times
gives the decibal level of a sound whose intensity is I; I0 is the intensity of barely audible sound. Some decibal levels and intensities are shown in the table below; the intensity is given in watts per square meter.
(b) If the decibal levels of a subway train entering a station and normal conversation are 100 dB and 60 dB, respectively, how many times as intense as normal conversation is the noise of the subway train?
(a) The intensity of thunder is 1012 times the intensity of barey audible sound. What is the decibal level of thunder?
The decibal (dB) is used to measure the loudness of sound. Barely audible sound has a decibal level of 0 and an intensity level of 10-12 W/m2 (watts per square meter). Sound painful to the ear has a decibal level of 130 and an intensity of 10 W/m2. The formula
The answer is here ...
ANSWER: 10 000 times
(b) If the decibal levels of a subway train entering a station and normal conversation are 100 dB and 60 dB, respectively, how many times as intense as normal conversation is the noise of the subway train?
(a) The intensity of thunder is 1012 times the intensity of barey audible sound. What is the decibal level of thunder?
The answer is here ...
ANSWER: 10 000 times
(b) If the decibal levels of a subway train entering a station and normal conversation are 100 dB and 60 dB, respectively, how many times as intense as normal conversation is the noise of the subway train?
The answer is here ...