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INTRODUCTION Prestressed Concrete: - A creation of internal stresses in a structure in order to improve its performance. Such stresses are designed to counter-act stresses induced by external loads. - Concrete is strong and ductile in compression, it is weak and brittle in tension, and hence its response to external loads is improved by pre-compression. - Prestressed concrete is a type of Reinforced Concrete in which steel has been tensioned against the concrete.
Transcript
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INTRODUCTION

Prestressed Concrete:

- A creation of internal stresses in a structure in order to improve its

performance. Such stresses are designed to counter-act stresses

induced by external loads.

- Concrete is strong and ductile in compression, it is weak and

brittle in tension, and hence its response to external loads is

improved by pre-compression.

- Prestressed concrete is a type of Reinforced Concrete in which

steel has been tensioned against the concrete.

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In this method, the prestressing tendons are initially tensioned between

fixed abutments and anchored.

With the formwork in place, the concrete is cast around the highly

stressed steel tendons and cured.

When the concrete has reached its required strength, the wires are cut or

otherwise released from the abutments.

As the highly stressed steel attempts to contract, the concrete is

compressed.

Prestress is imparted via bond between the steel and the concrete.

Pretensioned concrete members are often precast in pretensioning beds

long enough to accommodate many identical units simultaneously.

Prestressed Methods:

Two different procedures for prestressing concrete were developed:

(a) Pretensioned Concrete

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Pretensioning

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b- Post-tensioned concrete

In this method, the concrete is cast around hollow ducts which are fixed to any

desired profile.

The steel tendons are usually in place, unstressed in the ducts during the concrete

pour.

When the concrete has reached its required strength, the tendons are tensioned.

Tendons may be stressed from one end with the other end anchored or may be

stressed from both ends.

The tendons are then anchored at each stressing end.

The concrete is compressed during the stressing operation and the prestress is

maintained after the tendons are anchored by bearing of the end anchorage plates

onto the concrete.

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After the tendons have been anchored and no further stressing is required, the

ducts containing the tendons are often filled with grout under pressure.

In this way, the tendons are bonded to the concrete and are more efficient in

controlling cracks and providing ultimate strength.

In some situations, however, tendons are not grouted for reasons of economy

and remain permanently unbonded.

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Stresses Calculations

P prestressing force

Pj prestressing force at the jack before transfer

Pi prestressing force immediately after transfer

Pe effective prestressing force after time-dependent losses

Stages

a - Initial Stage, Pi, MD (self weight moment)

b- Final Stage, Service, Pe, Mtotal = MD+MSD+ML

MD = Self weight moment

MSD = Super imposed D.L.

ML = Live load moment

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Tendon profiles

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1- Basic Concept

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2- C-line Method

- Line of pressure or thrust concept

- The beam is analyzed as if it were plain concrete

- The prestressing force is assumed as external load

- Use statics to find stresses

Reinforced Concrete Prestressed Concrete

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is almost constant aIn Reinforced Concrete

maxvaries from zero to a aIn Prestressed Concrete

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3- Load Balancing Method

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Example- 1

A pre-tensioned T-beam (8ST24) will carry load WSD + WL = 420 b/ft

AP = Prestressing Area = 12 (1/2″ diameter strands)

fpu = ultimate strength of the prestressing strands = 270 ksi

fpi = 0.7 fpu = 189 ksi

fpe = 150 ksi.

Page 23: pre1-1

Given the properties of the section 8ST24 are as follows:

AC = 474 in2

r2 = 45.44 in2

ct = 5.94 in

cb = 18.06 in

St = 3626 in3

Sb = 1193 in3

WD = 494 lb/ft

Find the concrete fiber stresses at mid span due to:

a) Initial Conditions

b) Final Conditions

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Solution

1. Basic Concept

• Initial Conditions Pi, MD

Pi = fPi x Ap =0.7(270,000)(1.836) = 347,004 lb

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Final Service Stage Pe, MT

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2- C-Line Method

a) Initial conditions Pi, MD

Pi = 347004 lb.

MD = 3035136 in-lb.

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b) Final stage Pe, MT

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3- Load Balancing Method

Initial conditions Pi, WD

WD = 494

wub = 494 - 824.59 = - 330.59 lb/ft

lbinl

wM ubub . 4.2031122128

6459.330

8

22

Page 29: pre1-1

b) Final stage

Pe = 275400 lb.

wT = wD + wSD + wL

= 494 +420 = 914 lb/ft

= 654.3 lb/ft

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Example -2

A pretensioned simply supported 10LDT24 double T-beam without topping has

a span of 64 ft and the geometry is shown below.

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The beam is subjected to a uniform superimposed gravity dead load (WSD)

and live load (WL) summing to 420 plf. The initial prestress before losses is

fpi = 0.7 fu=189,000 psi, and the effective prestress after losses is fpe=150,000

psi.

Assume that ten ½ in. diameter seven –wire strand tendons with 108-D1

strand pattern are used to prestress the beam. Compute the extreme fiber stresses at the midspan due to:

a- the initial full prestress and no external gravity load. (using the basic

concept method)

b- the final service load conditions when prestress losses have taken place.

(using the three methods)

Solution

Section properties are as follows:

plfW

ininS

inin

ininC

inrinIinA

D

b

b

cc

359

607,3S 264,1

77.7e 77.14e

23.6C 77.17

04.50 469,22 449

3t3

ec

t

2242

Page 34: pre1-1

a- initial Conditions at Prestressing

lbP

lbfAPinA

e

pipsips

500,229000,15053.1

170,289000,18953.1 53.1153.010 2

The midspan self-weight dead-load moment is

lbinwl

M D 696,205,2128

)64(359

8

22

)( 70607,3

696,205,2)

04.50

23.677.141(

449

170,289)1(

2Cpsi

S

M

r

ec

A

Pf

t

Dt

c

it

)( 277,2264,1

696,205,2)

04.50

77.1777.141(

449

170,289)1(

2Cpsi

S

M

r

ec

A

Pf

b

Db

c

ib

Page 35: pre1-1

b - Final Conditions at Service Load

Midspan moment due to superimposed dead and live load is

lbinMMomentTotal

lbinMM

T

LSD

. 176,786,4480,580,2696,205,2

. 480,580,2128

)64(420 2

)( 898607,3

176,786,4)

04.50

23.677.141(

449

500,229)1(

2Cpsi

S

M

r

ec

A

Pf

t

Tt

c

et

)( 594264,1

176,786,4)

04.50

77.1777.141(

449

500,229)1(

2Tpsi

S

M

r

ec

A

Pf

b

Tb

c

eb

i- Basic Method

Page 36: pre1-1

ii- C-line Method

. 08.677.1485.20e . 85.20500,229

176,786,4ineain

P

Ma

e

T

)(594)04.50

77.1708.61(

449

500,229)1(

)(898)04.50

23.608.61(

449

500,229)1(

2

2

Tpsir

ce

A

Pf

Cpsir

ce

A

Pf

b

c

eb

t

c

et

iii- Load Balancing Method

plfl

PaW

fteamidspanat

b

c

552)64(

231.1500,22988

231.177.14 ,

22

lbinlW

MplfW

plfWWWW

ububub

LSDDT

.688,394,1128

)64(227

8 227552779

779420359

22

)(594264,1

688,394,1

449

500,229

)(898607,3

688,394,1

449

500,229

TpsiS

M

A

Pf

CpsiS

M

A

Pf

b

ub

c

b

t

ub

c

t

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2 -Example

A T-shaped simply supported beam has the cross-section shown in the given

figure below. It has a span of 36 ft (11m), is loaded with a

gravity live-load unit intensity WL = 2,500 plf (36.5 kN ), and is

prestressed with twelve ½ -in.-dia seven wire stress-relieved strands.

Compute the concrete fiber stresses a service load by each of the following

methods:

(a) Basic concept

(b) C-line

(c) Load balancing

Assuming that the tendon eccentricity at midspan is ec = 9.6 in.

Page 38: pre1-1

f 'c = 7,000 psi

ft = 12 = 1004 psi (max. allowable tensile stress in concrete)

fc = 0.45 f '́c = 0.45 (7000) = 3150 psi (max. allowable compressive stress)

fpe = 160 ksi

'

cf

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Solution

(a) Basic Concept Method

Aps = 12 x 0.153 = 1.836 in2

Pe = Aps . fpe = 1.836 x 160000 = 293760 lb.

.. 600,020,1128

36525 2

inlbM D

0.0SDM

inlbM L . 000,860,4128

362500 2

inlbMMMM LSDDT . 600,880,5

Page 40: pre1-1

OK 3150)(4.20362109

600,880,5

5.73

57.176.91

504

293760psiCpsift

OK 1004)(8.4432908

600,880,5

5.73

43.126.91

504

293760psiTpsifb

Page 41: pre1-1

(b) C-Line Method

ineP

Me

e

T 42.106.9760,293

600,880,5'

OK 3150)(7.20345.73

57.1742.101

504

293760psiCpsift

OK 1004)(3.4445.73

57.1742.101

504

293760psiTpsifb

Page 42: pre1-1

(c) Load Balancing Method

ftlbwwww LSDDT / 302525000.0525

ftlbl

aPwb / 6.1450

36

12

6.92937608

822

'

ftlbwub / 3.15746.14503025

inlblw

M ubub . 504,060,312

8

363.1574

8

22

Page 43: pre1-1

OK 3150)(0.20342109

504,060,3

504

293760psiCpsift

OK 1004)(0.4442981

504,060,3

504

293760psiTpsift


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