Date post: | 08-Apr-2018 |
Category: |
Documents |
Upload: | allimalar-rajendran |
View: | 220 times |
Download: | 0 times |
of 19
8/7/2019 PRINSIPLE CHEMISTRY NOTES
1/19
1
LECTURE 3
SCES1200
Dr Zaharah Aiyub
8/7/2019 PRINSIPLE CHEMISTRY NOTES
2/19
2
1.3 WRITING AND BALANCING
CHEMICAL EQUATIONS
Objectives
Write and balance chemical equations
Determine stoichiometric equivalence
Calculating reactants and products fora reaction
8/7/2019 PRINSIPLE CHEMISTRY NOTES
3/19
3
The formation of HF gas on the macroscopic and molecular levels
Fig 2.1
8/7/2019 PRINSIPLE CHEMISTRY NOTES
4/19
4
A three-level view of the chemical reaction in a flashbulbFig 2.2
8/7/2019 PRINSIPLE CHEMISTRY NOTES
5/19
5
BALANCE MOLECULAR
REACTIONS
H2(g) + F2(g) 2HF(g)
Mg(s) + O2(g) MgO2(s)
C3H8(g) + 5O2 (g) 3CO2(g) + 4H2O(l)
2NaOH (aq) + 2Al (s) + 2H2O(l) 3H2(g) +
2NaAlO2(aq)
8/7/2019 PRINSIPLE CHEMISTRY NOTES
6/19
6
BALANCE REDOX REACTIONS
4Na(s) + O2(g) 2N2O(s)
2HCl(aq) + Fe(s) FeCl2(aq) + H2(g)
2MnO4-(aq) + 10 Fe2+(aq) + 16 H+(aq)
permanganate ion ferrous ion
10Fe3+(aq) + 2Mn2+(aq) + 8H2O(l)
ferric ion manganous ion
8/7/2019 PRINSIPLE CHEMISTRY NOTES
7/19
7
BALANCE IONIC REACTIONS
Ba2+(aq) + SO42-(aq) 4(s)
sulphate ion
n
2S2O32-(aq) + I2(aq) S4O6
2- (aq) + 2I-(aq)
thiosulfate ion tetrathionate ion
8/7/2019 PRINSIPLE CHEMISTRY NOTES
8/19
8
QUIZ
Balance the following equations:
(a) CO(g) + O2(g) CO2(g)
(b) CH4(g) + Cl2(g) CCl4(l) + HCl(g)
(c) Ca(OH)2(aq) + H3PO4(aq) Ca3(PO4)2(s) +H2O(l)
8/7/2019 PRINSIPLE CHEMISTRY NOTES
9/19
9
translate the statement
Sample Problem 2.1 Balancing Chemical Equations
PROBLEM:
PLAN: SOLUTION:
balance the atoms
specify states of matter
Within the cylinders of a cars engine, the hydrocarbon octane
(C8H18), one of many components of gasoline, mixes with oxygenfrom the air and burns to form carbon dioxide and water vapor.Write a balanced equation for this reaction.
adjust the coefficients
check the atom balance
C8H18 + O2 CO2 + H2O
C8H18 + O2 CO2 + H2O825/2 9
2C8H18 + 25O2 16CO2 + 18H2O
2C8H18 + 25O2 16CO2 + 18H2O
2C8H18(l) + 25O2 (g) 16CO2 (g) + 18H2O (g)
8/7/2019 PRINSIPLE CHEMISTRY NOTES
10/19
10
1.4 CALCULATING THE AMOUNTSOF REACTANT AND PRODUCTS
To be able to calculate the numberof moles of substances in a balancechemical reaction if you know the
number of moles of one substance.
Objectives
8/7/2019 PRINSIPLE CHEMISTRY NOTES
11/19
11
STOICHIOMETRIC EQUIVALENCEAND REACTION STOICHIOMETRY
Chemical equations provide relationships betweensubstances that have been involved in a reaction. Thesestoichiometric relationships are used to predict the quantityof a product formed, the quantity of a reactant needed, or the
quantities of substances that will combine.
(g moles
8/7/2019 PRINSIPLE CHEMISTRY NOTES
12/19
12
Stoichiometric equivalence
C3H8(g) + 5O2 (g) 3CO2(g) + 4H2O(l)
1 mol of C3H
8is stoichiometrically equivalent to 5 mol of O
21 mol of C3H8 is stoichiometrically equivalent to 3mol of CO21 mol of C3H8 is stoichiometrically equivalent to 4 mol of H2O
or
3 mol of CO2 is stoichiometrically equivalent to 4 mol of H2O
5 mol of O2 is stoichiometrically equivalent to 3 mol of CO2
8/7/2019 PRINSIPLE CHEMISTRY NOTES
13/19
13
Consider the equation
4NH3(g) + 5O2(g) 4NO(g) + 6H2O(l)
This equation means that 4 mol NH3 (g) and 5 mol(g) react to form 4mol NO(g) and 6 mol H2O (l)
An amount of 6.48 mol of NH3(g) requires how many moles of O2(g)for complete reaction?
6.48 mol NH3(g) x 5 mol O2 = 8.10 mol O2(g)
4 mol NH3 A mass of 5.44 g O2(g) is sufficient to produce what mass of H2O(l)?
5.44 g O2(g) x 1 mol O2 x 6 mol H2O x 18.02 g H2O
32.00 g O2 5 mol O2 1 mol H2O
= 3.68 g H2O(l)
8/7/2019 PRINSIPLE CHEMISTRY NOTES
14/19
14
QUIZ
Determine the stoichiometric equivalence of reactants andproducts in the following reactions:
1. 4Na(s) + O2(g) 2Na2O(s)
2. 2HCl(aq) + Fe(s) FeCl2(aq) + H2(g)
3. 2MnO4-(aq) + 10 Fe2+(aq) + 16 H+(aq)
permanganate ion ferrous ion
10Fe3+(aq) + 2Mn2+(aq) + 8H2O(l)
ferric ion manganous ion
8/7/2019 PRINSIPLE CHEMISTRY NOTES
15/19
15
Sample Problem 2.2 Calculating Amounts of Reactants and Products
PROBLEM: In a lifetime, the average American uses 1750lb(794g) of copperin coins, plumbing, and wiring. Copper is obtained from sulfide
ores, such as chalcocite, or copper(I) sulfide, by a multistageprocess. After an initial grinding step, the first stage is to roast
the ore (heat it strongly with oxygen gas) to form powderedcopper(I) oxide and gaseous sulfur dioxide.
(a) How many moles of oxygen are required to roast 10.0mol of
copper(I) sulfide?(b) How many grams of sulfur dioxide are formed when 10.0molof copper(I) sulfide is roasted?
(c) How many kilograms of oxygen are required to form 2.86Kgof copper(I) oxide?
PLAN: write and balance equation
find mols O2 find mols SO2
find g SO2
find mols Cu2O
find mols O2 find kg O2
8/7/2019 PRINSIPLE CHEMISTRY NOTES
16/19
16
SOLUTION:
Sample Problem 2.3 Calculating Amounts of Reactants and Products
continued
2Cu2S(s) + 3O2(g) 2Cu2O(s) + 2SO2(g)
3mol O2
2mol Cu2S
10.0 mol Cu2S x = 15.0 mol O2
10.0 mol Cu2S x
2 mol SO2
X2 mol Cu2S
x 64.07g SO2
mol SO2
= 641 g SO2
2.86 kg Cu2O x103 g Cu2O x
kg Cu2O
= 0.960 kg O2kg O2
103 g O2
mol Cu2O
143.10 g Cu2O= 20.0 mol Cu2O
20.0 mol Cu2O x3 mol O2 X
2 mol Cu2O
32.00 g O2 X
mol O2
(a)
(b)
(c)
8/7/2019 PRINSIPLE CHEMISTRY NOTES
17/19
17
Sample Problem 2.4 Calculating Amounts of Reactants and Products in
a Reaction Sequence
PROBLEM: Roasting is the first step in extracting copper from chalcocite,
the ore used in the previous problem. In the next step, copper(I)oxide reacts with powdered carbon to yield copper metal andcarbon monoxide gas. Write a balanced overall equation for thetwo-step process.
PLAN:
write balanced equations for each step
cancel reactants and products common
to both sides of the equations
sum the equations
SOLUTION:
2Cu2S(s) + 3O2(g) 2Cu2O(s) + 2SO2(g)
Cu2O(s) + C(s) 2Cu(s) + CO(g)
2Cu2O(s) + 2C(s) 4Cu(s) + 2CO(g)
2Cu2S(s)+3O2(g)+2C(s) 4Cu(s)+2SO2(g)+2CO(g)
8/7/2019 PRINSIPLE CHEMISTRY NOTES
18/19
18
Figure 2.3
Summary of the Mass-Mole-Number
Relationships in a Chemical Reaction
8/7/2019 PRINSIPLE CHEMISTRY NOTES
19/19
19
QUIZ
If 10 grams of sodium chloride, NaCl is treatedwith excess silver nitrate, AgNO3, how muchsilver chloride is precipitated?(NaCl = 55.44)