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Problems on Numbers.100

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PROBLEMS ON NUMBERS 1. The sum of the smallest six-digit number and the greatest five-digit number is: a. 199999 b. 201110 c. 211110 d. 1099999 Difficulty Level : Easy Moderately easy Difficult Basic Formula: Answer with Explanation: The smallest six digit number = 1,00,000 The greatest five digit number = 99,999 Therefore the sum of the smallest = 1,00,000 + 99,999 six digit number and the greatest five digit number = 1,99,999 Problems on numbers Page 1 www.aptitudecoach.com
Transcript
Page 1: Problems on Numbers.100

PROBLEMS ON NUMBERS

1. The sum of the smallest six-digit number and the greatest five-digit

number is:

a. 199999 b. 201110 c. 211110 d. 1099999

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

The smallest six digit number = 1,00,000

The greatest five digit number = 99,999

Therefore the sum of the smallest = 1,00,000 + 99,999six digit number and the greatest five digit number = 1,99,999

Problems on numbers Page 1 www.aptitudecoach.com

Page 2: Problems on Numbers.100

2. Which of the following has most number of divisors?

a. 99 b. 101 c. 176 d. 182

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

Divisiors of 99 = 1, 3, 9, 11, 33, 99

Divisors of 101 = 1,101

Divisors of 176 = 1, 2, 4, 8, 11, 22, 44, 88, 176

Divisors of 182 = 1, 2, 7, 13, 14, 26, 91, 182

Therefore 176 has most number of divisors.

Problems on numbers Page 2 www.aptitudecoach.com

Page 3: Problems on Numbers.100

3. Which of the following has fractions in ascending order?

a. b. c. d.

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

LCM of (1,3,7,9,8)= 1512 and

LCM of (2,3,7,8,9)= 3024

Therefore For (a) we have , , Not in ascending order

For (b) we have , , Not in ascending order

For (c) we have , , , ,

The fractions are in ascending order.

For (d), we have , , , ,

Not in ascending order.

Therefore the answer is (c)

Problems on numbers Page 3 www.aptitudecoach.com

Page 4: Problems on Numbers.100

4. If one-third of one-fourth of a number is 15, then three-tenth of that

number is:

a. 35 b. 36 c. 45 d. 54

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

Given one third of one fourth of a number (x) is 15.

( ( x x)) = 15

x = 15 x 12

x = 180

Three benth of x = x x

= x 180 = 54

Problems on numbers Page 4 www.aptitudecoach.com

Page 5: Problems on Numbers.100

5. (8 ÷ 88) × 8888088 =?

a. 808008 b. 808080 c. 808088 d. 8008008

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

x 8888088 =

= 808008

Note :

808008 x 11 = 8888088

Problems on numbers Page 5 www.aptitudecoach.com

Page 6: Problems on Numbers.100

6. The value of is:

a. 4 b. 5 c. 8 d. 10

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

= Therefore = 15

= Therefore =13

= Therefore = 11

= Therefore = 6

=

=

=4

Problems on numbers Page 6 www.aptitudecoach.com

Page 7: Problems on Numbers.100

7. 9548 + 7314 = 8362 + ?

a. 8230 b. 8410 c. 8500 d.

8600

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

9548 + 7314 = 9548 7314

___________ 16862 (-) 8362

___________ 8500

____________

Ans = 8500

(i.e) 9548 + 7314 = 8362 + 8500

Problems on numbers Page 7 www.aptitudecoach.com

Page 8: Problems on Numbers.100

8. The H.C.F of 24 × 33 × 55 × 24, 23 × 32 × 52 × 7 and 24 × 34 × 5 × 72 × 11 is a. 22 ×32 × 5 b. 22 ×32 ×5 ×7 ×11 c. 24 ×34 ×54

d. 24 ×34×55×7×77

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:Among the three factors

HCF of 24 x 24, 23, 24 is = 23

HCF of 33, 32, 34 is = 32

HCF of 55, 52, 5 = 5

7 & 11 are not in three terms

So we leave the values 7, 72, 11

HCF of three terms = 23 x 32 x 5

Problems on numbers Page 8 www.aptitudecoach.com

Page 9: Problems on Numbers.100

9. What is the difference between the biggest and the smallest fraction

among ?

a. b. c. d.

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

The biggest among , , , is =

The Smallest among , , , is =

The difference between the biggest and the smallest fraction = -

=

=

=

Problems on numbers Page 9 www.aptitudecoach.com

Page 10: Problems on Numbers.100

10. Find the number which when multiplied by 15 increased by 196.

a. 14 b. 20 c. 26 d. 28

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

15 x 14 = 210

Which is increased by 196 210 – 14

196 since we multiply it by 15

So the number is 14

Problems on numbers Page 10 www.aptitudecoach.com

Page 11: Problems on Numbers.100

11.

a. 1 b. 2 c. 6.65 d. 7.75

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

=

=

=

= 7.75

Problems on numbers Page 11 www.aptitudecoach.com

Page 12: Problems on Numbers.100

12. In the following sum, ‘?’ stands for which digit?

? + 1? + 2? + ?3 + ?1 = 21?

a. 4 b. 6 c. 8 d. 9

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

8+81+28+83+81 = 218

Answer is 8

Problems on numbers Page 12 www.aptitudecoach.com

Page 13: Problems on Numbers.100

13. Which of the following is a pair of co-primes?

a. (16, 62) b. (18, 25) c. (21, 35) d. (23, 92)

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Two numbers are said to be co-prime if their H.C.F is 1.

Answer with Explanation:

H.C.F of 16, 62 is 2

H.C.F of 18, 25 is 1

H.C.F. of 21, 35 is 7

Co-prime = (18, 25).

Problems on numbers Page 13 www.aptitudecoach.com

Page 14: Problems on Numbers.100

14. 34.95 + 240.016 + 23.98 = ?

a. 298.0946 b. 298.111 c. 298.946 d. 299.09

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Ordinary Addition

Answer with Explanation:

34.95

240.016

23.98 (+)

_________________

298.946

_________________

Problems on numbers Page 14 www.aptitudecoach.com

Page 15: Problems on Numbers.100

15. If the sum of one-half and one-fifth of a number exceeds one-third

of that number by , the number is:

a. 15 b. 18 c. 20 d. 30

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

Let the unknown number be x

x + x – (7 ) = x

+ - =

+ - =

30

10615 xxx =

3

22

=

= 2

x = 20

Problems on numbers Page 15 www.aptitudecoach.com

Page 16: Problems on Numbers.100

16. is equal to:

a. b. c. d. None of these

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

+

= +

= +

=

= 1

The Answer is None of these.

Problems on numbers Page 16 www.aptitudecoach.com

Page 17: Problems on Numbers.100

17.

a. b. c. d.

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

=

= = 4/9

Problems on numbers Page 17 www.aptitudecoach.com

Page 18: Problems on Numbers.100

18. The value of 112 × 54 is:

a. 6700 b. 70000 c. 76500 d.

77200

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

54 = 5 x 5 x 5 x 5 = 25 x 25

= 625

112 x 54 = 112 x 625 _______________

560 224 672

________________ 70000 _________________

The Answer is 70000

Problems on numbers Page 18 www.aptitudecoach.com

Page 19: Problems on Numbers.100

19. The L.C.M of 23 × 32 × 5 × 11, 24 ×34 × 52 × 7 and 25 × 33 × 53 × 72 × 11

is :

a. 23 × 32 × 5 b. 25 ×34 × 53

c. 23 ×32 × 5 × 7 × 11 d. 25 ×34 × 53 ×72 × 11

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

Since the multipliers are all in multiplication we can take the L.C.M. of each

number separately.

LCM of 23, 24, 25 = 25

LCM of 32, 34, 33 = 34

LCM of 5, 52, 53 = 53

LCM of 7, 72 = 72

LCM of 11, 11 = 11

LCM of 23 x 32 x 5 x 11, 24 x 34 x 52 x 7, 25 x 33 x 53 x 72 x 11 is

= 25 x 34 x 53 x 72 x 11

Problems on numbers Page 19 www.aptitudecoach.com

Page 20: Problems on Numbers.100

20. 12.1212 + 17.0005 – 9.1102 = ?

a. 20.0015 b. 20.0105 c. 20.0115 d. 20.1015

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

12.1212 +

17.0005

______________

29.1217

9.1102

______________

20.0115

______________

Problems on numbers Page 20 www.aptitudecoach.com

Page 21: Problems on Numbers.100

21. The sum of a number and its reciprocal is one-eight of 34. What is

the product of the number and its square root?

a. 8 b. 27 c. 32 d. None of these

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:Let the unknown number be x

The sum of a number x & its reciprocal is (34)

Given x + = (34) x =

= a = 4, b= -17, c=4

4x2 – 17x + 4 = 0 x =

Taking x = 4 =

The product of x & it’s square root = x x =

= 4 x = ,

= 4 x 2 = x = 4,

= 8

Problems on numbers Page 21 www.aptitudecoach.com

Page 22: Problems on Numbers.100

22. of 168 × 15 ÷ 5 + ? = 549 ÷ 9 + 235

a. 107 b. 174 c. 189 d. 296

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

R.H.S. = + 235

= 61 + 235

R.H.S. = 296

L.H.S. = ( x168) x + x Where x has to be found

L.H.S. = 189 = x

L.H.S. = R.H.S. 189 + x = 296

x = 296 – 189

x = 107

Problems on numbers Page 22 www.aptitudecoach.com

Page 23: Problems on Numbers.100

23. equals:

a. 0.00069 b. 0.0069 c. 0.0609 d. 0.069

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

=

= ( = 69 )

=

=

= 0.0069

Problems on numbers Page 23 www.aptitudecoach.com

Page 24: Problems on Numbers.100

24. The average of five consecutive odd numbers is 61. What is the

difference between of these highest and lowest numbers?

a. 2 b. 5 c. 8 d. None of these

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

Let the Consecutive odd numbers be

x, x +2, x +4, x +6, x +8

Given = 61

= 61

x+4 =61

x = 57

The numbers are 57, 59, 61, 63, 65

Difference between the highest and lowest number is 65 – 57 = 8.

Problems on numbers Page 24 www.aptitudecoach.com

Page 25: Problems on Numbers.100

25. A positive integer, which when added to 1000, gives a sum which is

greater than when it is multiplies by 1000. This positive integer is:

a. 1 b. 3 c. 5 d. 7

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

Let us take the positive integes as x.

Then x+1000 1000 x (Given)

1000 x x+1000

1000 x- x 1000

(1000-1) x 1000

999 x 1000

x

x 1.00

x = 1

Problems on numbers Page 25 www.aptitudecoach.com

Page 26: Problems on Numbers.100

26. The H.C.F of is:

a. b. c. d.

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

The numerators are : 9, 12, 18, 21.

3, 9, 12, 18, 21

3, 4, 6, 7 Here common divisor = 3

The denominators are : 10, 25, 35, 40

5 10, 25, 35, 40

2, 5, 7, 8

5 x 2 x 5 x 7 x 8 = 2800

H.C.F =

Problems on numbers Page 26 www.aptitudecoach.com

Page 27: Problems on Numbers.100

Problems on numbers Page 27 www.aptitudecoach.com

Page 28: Problems on Numbers.100

27. Which of the following is equal to 3.14 × 106 ?

a. 314 b. 3140 c. 3140000 d. None of

these

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

3.14 x 10 6

= 3.14 x 10,00,000

= 31,40,000

Problems on numbers Page 28 www.aptitudecoach.com

Page 29: Problems on Numbers.100

28. The product of two natural numbers is 17. Then, the sum of the

reciprocals of their squares is:

a. b. c. d. 289

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

Let the take the natural numbers as 1 and 17.

Given that, xy = 17 where x = 1 y = 17

+ =

=

=

Problems on numbers Page 29 www.aptitudecoach.com

Page 30: Problems on Numbers.100

29. If a * b = , fine the value of 3 * (3 * -1).

a. -3 b. -1.5 c. -1 d. 2 /

3

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

a*b = (given)

Answer with Explanation:

Now 3 * (3 * -1) = ?

Here a = 3 b=3 *-1 = =

3* (3*-1) = ( by given)

=

= -

= - 3

Problems on numbers Page 30 www.aptitudecoach.com

Page 31: Problems on Numbers.100

30. = ?

a. 1.05 b. 1.25 c. 1.45

d. 1.55

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

= 1.25

Problems on numbers Page 31 www.aptitudecoach.com

Page 32: Problems on Numbers.100

31. If -1 < x < 2 and 1 < x < 3, then least possible value of (2y – 3x) is:

a. 0 b. -3 c. -4 d. -5

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

-1 x 2 1 y 3-3 3x 6 2 2y 63 -3x -6

i.e. -6 -3x 3 -4 2y - 3 x 9

The least possible value of

(2y – 3x) is -4.

Problems on numbers Page 32 www.aptitudecoach.com

Page 33: Problems on Numbers.100

32. The G.C.D. of 1.08, 0.36 and 0.9 is

a. 0.03 b. 0.9 c. 0.18

d. 0.108

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

0.2 1.08, 0.36, 0.9 (or) 2 108, 36, 90

3 54, 18, 45

0.9 5.4, 1.8, 4.5 3 18, 6, 15

6, 2, 5 6, 2, 5

G.C.D = 0.2 x 0.9 = 0.18 2 x 3 x 3 = = 0.18

Problems on numbers Page 33 www.aptitudecoach.com

Page 34: Problems on Numbers.100

33. 40.83 × 1.02 × 1.2 = ?

a. 41.64660 b. 49.97592 c. 42.479532 d.

58.7952

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

x x

= x

=

= 49.97592

Problems on numbers Page 34 www.aptitudecoach.com

Page 35: Problems on Numbers.100

34. The sum of three numbers is 264. If the first number be twice the second

and third number be one-third of the first, then the second number is:

a. 48 b. 54 c. 84 d. 72

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

x+y+z = 264

2y+y+ (2y) = 264

3y+ y = 264

= 264

11y =792

y=72

Problems on numbers Page 35 www.aptitudecoach.com

Page 36: Problems on Numbers.100

35. A student was asked to solve the fraction and his answer was

. By how much was his answer wrong?

a. 1 b. c. d. None of these

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

= = x =

The answer is

i.e. - = = =

Ans: None of these.

Problems on numbers Page 36 www.aptitudecoach.com

Page 37: Problems on Numbers.100

36. Which number can replace both the question marks in the equation?

?

a. 12 b. 7 c. 6 d. None of these

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

=

X2 = x 32 16

X2 = 144

x = 12

Problems on numbers Page 37 www.aptitudecoach.com

Page 38: Problems on Numbers.100

37. For the integer n, if n3 is odd, then which of the following statements are

true?

I. n is odd II. n2 is odd II. n2 is even

a. I only b. II only c. I and II only d. I and III

only382. Three numbers are in the ratio 1 : 2 : 3 and their H.C.F. is 12. The

numbers are:

a. 4, 8, 12 b. 5, 10, 15 c. 10, 20, 30 d. 12, 24, 36

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Product of two odd number is oddProduct of an old and an even number is even Product of two even numbers is even

Answer with Explanation:

n3 = n .n2

n3 is odd = n .n2 is odd

= both n & n2 are odd.

Problems on numbers Page 38 www.aptitudecoach.com

Page 39: Problems on Numbers.100

38. How many digits will be there to the right of the decimal point in the

product of 95.75 and 0.2554?

a. 5 b. 6 c. 7 d. 9

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

95.75 x 0.2554

= 24.45455

Ans: 5

Problems on numbers Page 39 www.aptitudecoach.com

Page 40: Problems on Numbers.100

39. The sum of two numbers is 25 and their difference is 13. Find their

product.

a. 104 b. 114 c. 315 d. 325

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

(x + y)2 = (x-y)2 + 4xy

Answer with Explanation:

Given x +y = 25 & x-y = 13

(x + y)2 = (x-y)2 + 4xy

252 = 132 + 4xy

4xy = 252 - 132

=625-169

4xy = 456

xy =

xy = 114

Problems on numbers Page 40 www.aptitudecoach.com

Page 41: Problems on Numbers.100

40. On simplification, 3034 – (1002÷20.04) is equal to:

a. 2543 b. 2984 c. 2993

d. 3029

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

3034 – (1002 -20.04)

= 3034 -

= 3034 – 1002 x 100

20.04 x 100

= 3034 – 1002 x 100

2004

= 3034 -

= 3034 – 50

= 2984

Problems on numbers Page 41 www.aptitudecoach.com

Page 42: Problems on Numbers.100

41. If , then the value of n is:

a. 6 b. 8 c. 10 d. 12

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

Given = 729

i.e) 3 n/2 = 729

Taking log on both sides,

log 3 n/2 = log 729

n/2 log 3 = log 729

n/2 = = =

n/2 = 6

n= 2 x 6

n = 12

Problems on numbers Page 42 www.aptitudecoach.com

Page 43: Problems on Numbers.100

42. There are four prime numbers written in ascending order. The product of

the first three is 385 and that of the last three is 1001. The last number is:

a. 11 b. 13 c. 17 d. 19

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

Let a, b, c, d be the Four Prime numbers

Then abc = 385 1 & bcd = 1001 2

Now gcd of abc & bcd i.e., (abc, bcd)

= bc (a,d)

= bc x 1 ( a & d are prime)

Also (abc, bcd) = (gcd 385, 1001 ) = 77

bc = 77

From 2 bcd = 1001

d = = = 13

IIIly From 1, a = = = 5

Four Prime no’s are 5, 7, 11, 13

The last no. is 13

Problems on numbers Page 43 www.aptitudecoach.com

Page 44: Problems on Numbers.100

43. The sum of two numbers is 528 and their H.C.F. is 33. The number of

pairs of numbers satisfying the above conditions is:

a. 4 b. 6 c. 8 d. 12

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Given x + y = 528 Greatest common divisor of x, y i.e HCF of (x, y) = 33

Answer with Explanation:

Considering the multiples of 33 we have (33, 66, 99, 132, 165, 198, 231,

264, 297, 330, 363, 396, 429, 462, 495) we can stop here because the next

factor of 33 is 528.

Since we have the sum of multiples of 33 are 528, we will combine these

multiples as to get their sum as 528.

we get (33, 495) (66, 462) (99, 429) (132, 396) (165, 363) (198, 330)

(231,297)

But we have a condition that HCF of (x, y) = 33

Eliminating the one’s which does not satisfies the condition we get (33,

495) (99, 429) (165, 363) (231, 297)

The number of pairs of numbers satisfying the above condition is 4 .

Problems on numbers Page 44 www.aptitudecoach.com

Page 45: Problems on Numbers.100

44.

a. .0009 b. 009 c. 9 d. 9

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

Let = 0.1

x =

x = x

x =

x = 0.09

Problems on numbers Page 45 www.aptitudecoach.com

Page 46: Problems on Numbers.100

45. Two numbers differ by 5. If their product is 336, then the sum of the two

numbers is:

a. 21 b. 28 c. 37 d. 51

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

(x+y)2 = (x-y)2 + 4xy

Answer with Explanation:

Given x-y = 5 and xy =336

We know that

(x+y)2 = (x-y)2 + 4xy

= 52 +4 (336)

= 25+1344

(x+y)2 = 1369

x+y = 37

Problems on numbers Page 46 www.aptitudecoach.com

Page 47: Problems on Numbers.100

46. 3 – [1.6 – {3.2 – (3.2 + 2.25 ÷ X)}] = .65. The value of X is:

a. 0.3 b. 0.7 c. 3 d. 7

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

Given 3-[1.6-{3.2-(3.2+2.25 ÷ x)}] = 0.65

-[1.6-{3.2-(3.2+2.25÷ x)}] = 0.65-3

-1.6+{3.2-(3.2+2.25÷ x)} = 0.65-3

3.2- (3.2+2.25÷ x) = - 0.75

- 3.2-2.25÷ x = -0.75-3.2

-2.25÷ x = -0.75-3/2 + 3/2

-2.25÷ x = - 0.75

= -0.75

x =

x = 3

Problems on numbers Page 47 www.aptitudecoach.com

Page 48: Problems on Numbers.100

47. If , then the value of x is:

a. 0.1764 b. 1.764 c. 1.64 d.

2.64

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation: ÷ = 0.02

= 0.02

Squaring on both sides

= (0.02)2

= 0.004

x = 0.004 x 441

x = 0.1764

Problems on numbers Page 48 www.aptitudecoach.com

Page 49: Problems on Numbers.100

48. In dividing a number by 585, a student employees the method of short

division. He divided the number successively by 5, 9 and 13 (factors of 585)

and got the remainders 4, 8 and 12. If he had divided the number by 585, the

remainder would have been:

a. 24 b. 144 c. 292 d. 584

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

+ (number-1) = same number

(i.e.) +(x-1) = x where (x-1) is remainder here.

Answer with Explanation:

Given a unknown number x when divided by 5,9,13. We get remainders 4,8

&12 .

(i.e.) +4 = x x = 5 & 4 = x-1 (remainder)

+8 = x x = 9 & 8 = x-1 (remainder)

+12 = x x =13 & 12 = x-1 (remainder)

IIIly +(585-1) = x (i.e.) +(x-1) = x x-1 = 584 (remainder)

The remainder would have been 584.

Problems on numbers Page 49 www.aptitudecoach.com

Page 50: Problems on Numbers.100

49. The least number which when divided by 5, 6, 7 and 8 leaves a

remainder 3, but when divided by 9 leaves no remainder, is:

a. 1677 b. 1683 c. 2523

d. 3363

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation: 336 28 24 21 187

5 1683 6 1683 7 1683 8 1683 9 1683

15 12 14 16 9

18 48 28 8 78

15 48 28 8 72

33 3 3 3 63

30 63

3 0

Ans: L.C.M of 5,6,7,8 is 840

Let the required number be 840k+3,

Which is divisible by 9.

Least value of k for which (90k+4)

is divisible by 9 is k=2

840 x 2 +3 = 1680 +3

= 1683

Problems on numbers Page 50 www.aptitudecoach.com

Page 51: Problems on Numbers.100

50. The value of is:

a. 0.08 b. 0.2 c. 0.8 d. 1

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

= = a+b

Answer with Explanation:

=

=

= 0.5 + 0.3

= 0.8

Problems on numbers Page 51 www.aptitudecoach.com

Page 52: Problems on Numbers.100

51. What will be the sum of two numbers?

I. Among the two numbers, the bigger number is greater than the smaller

number by 6

II. 40% of the smaller number is equal to 30% of the bigger number

III. The ratio between half of the bigger number and one-third of the smaller number

is 2 : 1

a. I and II only b. II and III only c. All I, II and III d. None of these

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

Let x be bigger number and y be smaller number I x –y = 6

II x = y

3x = 4y

III - = 2 3x-4y = 0

Ans I & II only.

Problems on numbers Page 52 www.aptitudecoach.com

Page 53: Problems on Numbers.100

52. The taxi charges in a city comprise of a fixed charge, together with the

charge of the distance covered. For a journey of 16 km, the charges paid are

Rs.156 and for a journey of 24 km, the charges paid are Rs.204. What will a

person have to pay for traveling a distance of 30 km?

a. Rs.236 b. Rs.240 c. Rs.248 d. Rs.252

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

For 16 km the charge = Rs.156

1 km the charge = Rs.9.75

For 24 Km the charge = Rs.204

1 Km the charge = Rs.8.5

For 1 Km the fixed charge = Rs.8

For 30 the charge = 30 x 8

= Rs.240

Problems on numbers Page 53 www.aptitudecoach.com

Page 54: Problems on Numbers.100

53.

a. b. c. d.

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

=

=

=

= 1

Problems on numbers Page 54 www.aptitudecoach.com

Page 55: Problems on Numbers.100

54. A number when divided by 114 leaves the remainder 21. If the same

number is divided by 19, then the remainder will be:

a. 1 b. 2 c. 7 d. 21

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:Given

114 x 19 x

21 ?

114 is a Multiple of 19 (19 x 6 = 114)

So the remainder obtained by when divided by 114 is subtracted from 19

will give the remainder when the same number is divided by 19.

(i.e.) 21 – 19 gives 2.

Problems on numbers Page 55 www.aptitudecoach.com

Page 56: Problems on Numbers.100

55. The least multiple of 7, which leaves a remainder of 4, when divided by

6, 9, 15 and 18 is:

a. 74 b. 94 c. 184 d. 364

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:L.C.M of 6,9,15 & 18 is 90

Let required number be 90 k + 4,

which is a multiple of 7

Least value of k for which (90k+4) is divisible by 7 is k = 4

Required number = 90 x 4 +4

= 360 + 4

= 364

Problems on numbers Page 56 www.aptitudecoach.com

Page 57: Problems on Numbers.100

56. The value of is:

a. 0 b. 1.6 c. 2 d. 3.4

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

=

= a-b

=

a = 2.3, b=.3

a-b = 2.3 – 0.3

= 2.

Problems on numbers Page 57 www.aptitudecoach.com

Page 58: Problems on Numbers.100

57. What is the two-digit number?

I. Sum of the digits is 7.

II. Difference between the number and the number obtained by interchanging the

digits is 9.

III. Digit in the ten’s place is bigger than the digit in the unit’s place by 1.

a. I & II only b. II & III only c. All I, II & III d.

None of these

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:I x +y= 7

II (10x +y) – (10y +x) = 9

9(x-y) = 9

x-y =1

III x-y =1

I & III, I & II

Ans: None of these.

Problems on numbers Page 58 www.aptitudecoach.com

Page 59: Problems on Numbers.100

58. In and examination, a student scores 4 marks for every correct answer

and loses 1 mark for every wrong answer. If he attempts in all 60 questions

and secures 130 marks, the number of questions he attempts correctly, is:

a. 35 b. 38 c. 40 d. 42

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:x be the correct answer

y be the wrong answer

x+y = 60

4x –y = 130

x+y = 60

4x-y=130

_____________

5x =190 x = 38

_____________

y= 60-38 y = 22

The number of correct question is 38.

Problems on numbers Page 59 www.aptitudecoach.com

Page 60: Problems on Numbers.100

59.

a. 3 b. c. 6 d. None of these

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

=

=

= x

=

=

=

None of these.

Problems on numbers Page 60 www.aptitudecoach.com

Page 61: Problems on Numbers.100

60. On dividing a number by 999, the quotient is

366 and the remainder is 103. The number is:

a. 364724 b. 365387 c. 365737 d. 366757

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

x = Quotient x Dividend + Remainder

Answer with Explanation:

x = 366 x 999+103

= 365634 +103

x = 365737

Problems on numbers Page 61 www.aptitudecoach.com

Page 62: Problems on Numbers.100

61. The smallest number which when diminished by 7, is divisible by 12, 16,

18, 21 and 28 is:

a. 1008 b. 1015 c. 1022

d. 1032

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

1015-7 = 1008

1008 is divisible by 12, 16, 18, 21 & 28

i.e.

12 1008 (84 16 1008 18) 1008 (56 21) 1008 (48

96 63 90 84

48 36 108 168

48 28 ) 1008 108 168

0 84 0 0

168

168

0 1008-7 = 1001 which is not divisible by 2.

Hence which is not divisible by 12, 16, 18, 21 & 28

Similarly, 1022-7 = 1015 also. 1032-7 = 1025

Problems on numbers Page 62 www.aptitudecoach.com

Page 63: Problems on Numbers.100

62. is equal to:

a. 30 b. 60 c. 80 d. 100

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

(7.5 x 7.5 + 37.5 + 2.5 x 2.5)

= 7.5 x 7.5 + 2 x 7.5 x 2.5 + 2.5 x 2.5

= (7.5) 2 + 2 x 7.5 x 2.5 + (2.5) 2

Which is in the form of a2 + 2ab + b2 = (a+b)2

Here a = 7.5 & b=2.5

(a+b)2 = (7.5 + 2.5)2

= 10 2

= 100

Problems on numbers Page 63 www.aptitudecoach.com

Page 64: Problems on Numbers.100

63. 54 is to be divided into two parts such that the sum of 10 times the first

and 22 times the second is 780. The bigger part is:

a. 24 b. 34 c. 30 d. 32

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

Here a+b = 54 1

54 is divided in to two parts

Hence = 27

10 times the first part is 27 x a = 27a

22 times the second part is 27 x b = 27b

their sum = 780

Hence 10a + 22b = 780 2

1 x 10 10a + 10b = 540

2

b = = 20

put b = 20 in 1,

a +b = 54 a + 20 = 54

a = 54-20 = 34

Problems on numbers Page 64 www.aptitudecoach.com

Page 65: Problems on Numbers.100

Problems on numbers Page 65 www.aptitudecoach.com

Page 66: Problems on Numbers.100

64. A fires 5 shots to B’s 3 but A kills only once in 3 shots while B kills

once in 2 shots. When B has missed 27 times, A has killed:

a. 30 birds b. 60 birds c. 72 birds d. 90 birds

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Trial and Error Method

Answer with Explanation:

When A = 50 shots

By Trial and error methods A Shots 30 birds

and B Shots 20 birds.

Problems on numbers Page 66 www.aptitudecoach.com

Page 67: Problems on Numbers.100

65. The greatest four-digit perfect square number is:

a. 9000 b. 9801 c. 9900 d.

9981

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:To find the square root of 9000

3 9000 9000 = 3 x 3 x 10 x 10 x 10

3 3000 = 3 x 10

10 1000 = 30

10 100

10

which is not a perfect square

To find the square root of 9900

3 9900

3 3300 9900 = 3 x 3 x 10 x 10 x 11

10 1100 = 3 x 10 x

10 110 = 30

11 which is also not a perfect square 3 9981

To find 9981 3 3327

1109

Which is also not a perfect square

Problems on numbers Page 67 www.aptitudecoach.com

Page 68: Problems on Numbers.100

66. What least number must be subtracted from 427398 so that the

remaining number is divisible by 15?

a. 3 b. 6 c. 11 d. 16

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation 15 427398 (28493

30

127

120

73

60

139

135

48

45

3

Remainder is 3.

When we subtract the remainder from 427398. We will get 427395

which is divisible by 15.

Problems on numbers Page 68 www.aptitudecoach.com

Page 69: Problems on Numbers.100

67. The greatest number of hour digits which is divisible by 15, 25, 40 and

75 is:

a. 1008 b. 1015 c. 1022 d.

1032

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

The largest number of four digits is 9999

Required number must be divisible by L.C.M of 15, 25, 40 and 75 by 600

on dividing 9999 by 600 we get 399

Required number = (9999-399) = 9600

Problems on numbers Page 69 www.aptitudecoach.com

Page 70: Problems on Numbers.100

68.

a. 3.308 b. 4 c. 33.08 d. 330.8

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

Let = 40

= x

x =

x =

x = 33.08

Answer is 33.08

Problems on numbers Page 70 www.aptitudecoach.com

Page 71: Problems on Numbers.100

69. The denominator of a fraction is 3 more than the numerator. If the

numerator as well as the denominator is increased by 4, the fraction becomes

. What was the original fraction?

a. b. c. d.

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

Let the fraction be

Now, =

5(x+4) = 4 (x+7)

5x + 20 = 4x +28

x= 28-20

x=8

The fraction is = =

The Answer is

Problems on numbers Page 71 www.aptitudecoach.com

Page 72: Problems on Numbers.100

70. A boy read th of a book on one day and th of the remainder on

another day. If there were 30 pages unread, how many pages did the book

contain?

a. 240 b. 300 c. 600 d. None of

these

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

Let x be the total number of pages in a book (i) (x) read on 1st day

Remaining page = (x- )

th of those remaining page read on 2nd day

(i.e) (x - ) = pages on 2nd time

The Remaining page left = - = 30 (given)

= 30

x = 240

Problems on numbers Page 72 www.aptitudecoach.com

Page 73: Problems on Numbers.100

71. The least number by which 1470 must be divided to get a number which

is a perfect square, is:

a. 5 b. 6 c. 15 d. 30

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

1470 = 7x7x5x6

To make it a perfect square it must be divided by 5x6 (i.e) 30

Required number = 30

The Answer is 30

Problems on numbers Page 73 www.aptitudecoach.com

Page 74: Problems on Numbers.100

72. If x and y are positive integers such that (3x+7y) is a multiple of 11, then

which of the following will also be divisible by 11?

a. 4x + 6y b. x + y + 4 c. 9x + 4y d. 4x – 9y

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

Keeping y=1, for x=5, we have 3x + 7y=22

which is divisible by 11

Now, substitute x = 5 and y=1 in each alternative and find out which

expression becomes a multiple of 11.

Now, 4x + 6y = 4x5+6 = 26

x+y+4 = 5+1+4 = 10

9x +4y = 9x5+4 =49

4x-9y= 4x5-9 = 20-9 = 11

Which is divisible by 11.

4x-9y is the answer.

Problems on numbers Page 74 www.aptitudecoach.com

Page 75: Problems on Numbers.100

73. Which of the following fraction is the largest?

a. b. c. d.

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

We have = 0.875

= 0.8125

= 0.775

= 0.7875

The largest of these is

Problems on numbers Page 75 www.aptitudecoach.com

Page 76: Problems on Numbers.100

74. The value of (4.7 × 13.26 + 4.7 × 9.43 + 4.7 × 7731) is:

a. 0.47 b. 47 c. 470 d.

4700

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

(4.7 x 13.26 + 4.7 x 9.43 + 4.7 x 77.31)

= 4.7 (13.26 + 9.43 + 77.31)

= 4.7 x 100

= 470

Problems on numbers Page 76 www.aptitudecoach.com

Page 77: Problems on Numbers.100

75. The denominator of a fraction is 3 more than the numerator. If the

numerator as well as the denominator is increased by 4, the fraction becomes

. What was the original fraction?

a. b. c. d.

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

Let the fraction be

Now =

5 (x+4) = 4 (x+7)

5x +20 = 4x +28

x = 28-20

x = 8

The fraction is = =

The Answer is

Problems on numbers Page 77 www.aptitudecoach.com

Page 78: Problems on Numbers.100

76. A sum of Rs.1360 has been divided among A B and C such that A gets

of what B gets and B gets of what C gets. B’s share is:

a. Rs.120 b. Rs.160 c. Rs.240 d. Rs.300

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

Let c= x then B= x and A = x x = x

A : B : C = x : x : x

A : B : C = 2 : 3: 12

B’s share = Rs. (1360 x )

= Rs.

= Rs.240

Answer is Rs.240

Problems on numbers Page 78 www.aptitudecoach.com

Page 79: Problems on Numbers.100

77. if = 2.236, then the value of is equal to :

a. 5.59 b. 7.826 c. 98.994 d.

10.062

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:Given = 2.236

- +

= - +5

= - + 5 x 2.236

= 1.118 – 4.4727 + 11.18

= 7.826

Ans is 7.826

Problems on numbers Page 79 www.aptitudecoach.com

Page 80: Problems on Numbers.100

78. The sum of three consecutive odd numbers is always divisible by:

I. 2 II. 3 III. 5 IV. 6

a. Only I b. Only II c. III. Only I & II d. Only II and IV

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

For example, the first three consecutive odd numbers in natural numbers are

1, 3, 5 and their sum is 9

Which is divisible by 3 alone.

Ans is 3

In general the first three odd consecutive numbers are n, n+2, n+4 then their

sum is 3n +6 which is equal to 3 (n+2)

Which is always divisible by 3.

Problems on numbers Page 80 www.aptitudecoach.com

Page 81: Problems on Numbers.100

79. A rectangular courtyard 3.78 metres long and 5.25 metres wide is to be

paved exactly with square tiles, all of the same size. What is the largest size

of the tile which could be used for the purpose?

a. 14 cms b. 21 cms c. 42 cms d. None of these

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

G.C.D

Answer with Explanation:

Length of the rectangular courtyard = 3.78 m

= 378 cm

breadth = 5.25 m

= 525 cm

GCD =

3 525, 378

7 175, 126

25, 18

3 x 7 = 21 cms.

Problems on numbers Page 81 www.aptitudecoach.com

Page 82: Problems on Numbers.100

80.

a. 0.8 b. 1.45 c. 2.40

d. 3.25

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

=

= 0.8

Problems on numbers Page 82 www.aptitudecoach.com

Page 83: Problems on Numbers.100

81. The different between a tow-digit number and the number obtained by

interchanging the digits is 36. What is the difference between the sum and

the difference of the digits of the number if the ratio between the digits of

the number is 1 : 2 ?

a. 4 b. 8 c. 16 d. 18

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Let the two digit number be 10x + y

Answer with Explanation:

10y + x – 10x –y = 36

9y-9x = 36

y-x = 4

ratio x : y = 1:2

y = 2x

2x-x = 4

x = 4

Sub x = 4 in y-x = 4

y-4 = 4

y = 8

x+y - (x-y) = 12+4

= 16

Problems on numbers Page 83 www.aptitudecoach.com

Page 84: Problems on Numbers.100

82. A person travels 3.5 km form place A to place B. Out of this distance, he

travels km on bicycle, km on scooter and the rest on foot. What

portion of the whole distance does he cover on foot?

a. b. c. d.

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

The distance travels by

bicycle is = 1 =

Scooter is = 1 =

Foot is = 3.5 – ( + )

= 3.5 – ( )

= 3.5 -

= 0.6633

Problems on numbers Page 84 www.aptitudecoach.com

Page 85: Problems on Numbers.100

83. The value of is close to:

a. 0.6 b. 1.1 c. 1.6 d. 1.7

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

=

=

= 1.6

Problems on numbers Page 85 www.aptitudecoach.com

Page 86: Problems on Numbers.100

84. The digits indicated * and $ in 3422213*$ so that this number is

divisible by 99, are respectively:

a. 1, 9 b. 3, 7 c. 4, 6 d. 5, 5

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Trial and Error Method.

Answer with Explanation: 345678

99 3422213 xy 9

297 1

452

396

562

495

671

594

773

693

801

792

99 Ans. is 1, 9 99

0

Problems on numbers Page 86 www.aptitudecoach.com

Page 87: Problems on Numbers.100

85. The greatest possible length which can be used to measure exactly the

lengths 7 m, 3 m 85 cm, 12 m 95 cm is :

a. 15 cm b. 25 cm c. 35 cm d. 42 cm

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

Convert cm to m

1 m = 100 cm

85 cm = 0.85 m

95 cm = 0.95 m

To find the LCM of 7m, 3.85m and 12.95m

7 7, 3.85, 12.95

5 1, 0.55, 1.85

1, 0.11, 0.37

LCM of 7, 3.85 and 12.95 is

7 x 5 = 35

Problems on numbers Page 87 www.aptitudecoach.com

Page 88: Problems on Numbers.100

86. If 1.5 x = 0.04y, then the value of is:

a. b. c. d. None of these

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

x=

=

=

=

= = =

Problems on numbers Page 88 www.aptitudecoach.com

Page 89: Problems on Numbers.100

87. The difference between a two-digit number and the number obtained by

interchanging the two digits is 63. Which is the smaller of the two numbers?

a. 29 b. 70 c. 92 d. None of these

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

70-7 = 63 (i.e) two digit No. = 70

The interchanged No. = 07

Then 70-07 = 63

But smallest of those two No. (70, 07) is 07.

Since it is not here.

Ans is None of these.

Problems on numbers Page 89 www.aptitudecoach.com

Page 90: Problems on Numbers.100

88. A pineapple costs Rs.7 each. A watermelon costs Rs.5 each. X spends

Rs.38 on these fruits. The number f pineapples and purchased is:

a. 2 b. 3 c. 4 d. 5

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

Given Pineapple costs = Rs.7

Watermelon costs = Rs.5

Suppose 2 Pineapples are purchased the remaining amount is 24. From this

amount we can get 4 watermelons. The remaining amount is 4.

So the answer 2 is impossible.

It is similar for the case 3 and 5.

If 4 Pineapples are purchased the remaining amount is 10. From this we can

get 2 watermelons.

So the answer is 4.

Problems on numbers Page 90 www.aptitudecoach.com

Page 91: Problems on Numbers.100

89. Which one of the following numbers has rational square root?

a. 0.4 b. 0.09 c. 0.9 d.

0.025

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

= __ not rational

= __ 0.3 which is rational

= __ not rational

= __ not rational

Ans is 0.09

Problems on numbers Page 91 www.aptitudecoach.com

Page 92: Problems on Numbers.100

90. Which of the following numbers is divisible by 3, 7, 9 and 11?

a. 639 b. 2079 c. 3791 d.

37911

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

Since 3, 7 and 11 are Prime numbers

9 is not a Prime number

So, we multiply all the given numbers

3 x 7 x 9 x 11 = 2079

Problems on numbers Page 92 www.aptitudecoach.com

Page 93: Problems on Numbers.100

91. About the number of pairs which have 16 as their H.C.F. and 136 as their

L.C.M., we can definitely say that:

a. No such pair exists b. Only one such pair exists

c. Only two such pairs exist d. Many such pairs exist

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

H.C.F of two numbers divides their L.C.M exactly.

Since 16 is not a factor of 136, it follows that there does not exist any pair of

numbers with H.C.F. 16 and L.C.M. 136.

Problems on numbers Page 93 www.aptitudecoach.com

Page 94: Problems on Numbers.100

92.

a. 10-2 b. 10-1 c. 10 d. None of these

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

÷

= ÷

= 0.0371166 ÷ 3.71166

= 0.010000

= 10-2

Problems on numbers Page 94 www.aptitudecoach.com

Page 95: Problems on Numbers.100

93. The sum of the digits of a two-digit number is 15 and the difference

between the digits is 3. What is the two-digit number?

a. 69 b. 78 c. 96 d. 87

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

x+y =15

x-y =3

2x = 18

x = 9

x + y = 15

y = 15-9

y = 6

The two digit number = 96

Problems on numbers Page 95 www.aptitudecoach.com

Page 96: Problems on Numbers.100

94. Income of a company doubles after every one year. If the initial income

was Rs.4 lakhs, what would be the income after 5 years?

a. Rs.1.24 crores b. Rs.1.28 crores c. Rs.2.56 crores d. None of these

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:Income in 1st year = Rs.4 Lakhs

( Income of a company doubles every 1 year)

Income in 2nd year = Rs.8 Lakhs

” in 3rd year = Rs.16 Lakhs

” in 4th year = Rs.32 Lakhs

” in 5th year = Rs.64 Lakhs

” in 6th year = Rs.12.8 Lakhs

(i.e.) after 5 year = Rs.1.28 crores

Problems on numbers Page 96 www.aptitudecoach.com

Page 97: Problems on Numbers.100

95. If a = 0.1039, then the value of is:

a. 0.1039 b. 0.2078 c. 1.1039 d. 2.1039

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:Let a = 0.1039 then

+ 3a = +3a

= +3(0.1039)

= +0.3117

= + 0.3117

= 0.79220 + 0.3117

= 1.1039

Problems on numbers Page 97 www.aptitudecoach.com

Page 98: Problems on Numbers.100

96. What least value must be assigned to * so that the number 63576*2 is

divisible by 8?

a. 1 b. 2 c. 3 d. 4

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

A number is divisible by 8, if the number formed by the last 3 digitsof the given number is divisible by 8.

Answer with Explanation:

6 * 2 must be divisible by 8

So * must be replaced by 3

Problems on numbers Page 98 www.aptitudecoach.com

Page 99: Problems on Numbers.100

97. The product of two numbers is 1320 and their H.C.F. is 6. The L.C.M. of

the numbers is:

a. 220 b. 1314 c. 1326 d.

7920

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

(a, b) [a,b] = ab

Answer with Explanation:

ab = 1320, (a, b) = 6

[a, b] = ?

6 x [a, b] = 1320

[a,b] = = 220

Problems on numbers Page 99 www.aptitudecoach.com

Page 100: Problems on Numbers.100

98. If 213 × 16 = 3408, then the 1.6 × 21.3 is equal to:

a. 0.3408 b. 3.408 c. 34.08 d. 340.8

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:1.6 x 21.3

= 16 x 10-1 x 213 x 10-1

= x

=

=

= 34.08

Problems on numbers Page 100 www.aptitudecoach.com

Page 101: Problems on Numbers.100

99. The sum of the squares of three consecutive natural numbers is 2030.

What is the middle number?

a. 25 b. 26 c. 27 d. 28

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

Let a = x b = x+1 c = x +2

Given a2 + b2 +c2 = 2030 x2 + (x +1)2 + (x+2)2 = 2030 x2 + x2 + 2x+1+x2 +4+4x = 2030

3x2 + 6x + 5 = 2030

3x2 + 6x – 2025 = 0

x2 + 2x – 675 = 0

x =

=

x =

x = = = 25

x =25; x+1 = 26 ; x+2 = 27

100. How many times are the hands of a clock at right angel in a day?

Problems on numbers Page 101 www.aptitudecoach.com

Page 102: Problems on Numbers.100

a. 22 b. 44 c. 24 d. 48

Difficulty Level : Easy Moderately easy Difficult

Basic Formula:

Answer with Explanation:

The hands of a clock at right angle comes twice in an hour.

For a day (i.e) for 24 hours. The hands of a clock at right angle comes

24 x 2 = 48 times.

Problems on numbers Page 102 www.aptitudecoach.com


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