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Home > Documents >  · Question 11: xx2-3 + (x — 3) x2 for x > 3. Answer 11: and v = (x — 3)x2 therefore, y = Letu...

 · Question 11: xx2-3 + (x — 3) x2 for x > 3. Answer 11: and v = (x — 3)x2 therefore, y = Letu...

Date post: 04-Jun-2020
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Page 1:  · Question 11: xx2-3 + (x — 3) x2 for x > 3. Answer 11: and v = (x — 3)x2 therefore, y = Letu = Differentiating with respect to x, we have dy du dv dx dx dx x2-3 taking log
Page 2:  · Question 11: xx2-3 + (x — 3) x2 for x > 3. Answer 11: and v = (x — 3)x2 therefore, y = Letu = Differentiating with respect to x, we have dy du dv dx dx dx x2-3 taking log
Page 3:  · Question 11: xx2-3 + (x — 3) x2 for x > 3. Answer 11: and v = (x — 3)x2 therefore, y = Letu = Differentiating with respect to x, we have dy du dv dx dx dx x2-3 taking log
Page 4:  · Question 11: xx2-3 + (x — 3) x2 for x > 3. Answer 11: and v = (x — 3)x2 therefore, y = Letu = Differentiating with respect to x, we have dy du dv dx dx dx x2-3 taking log
Page 5:  · Question 11: xx2-3 + (x — 3) x2 for x > 3. Answer 11: and v = (x — 3)x2 therefore, y = Letu = Differentiating with respect to x, we have dy du dv dx dx dx x2-3 taking log
Page 6:  · Question 11: xx2-3 + (x — 3) x2 for x > 3. Answer 11: and v = (x — 3)x2 therefore, y = Letu = Differentiating with respect to x, we have dy du dv dx dx dx x2-3 taking log
Page 7:  · Question 11: xx2-3 + (x — 3) x2 for x > 3. Answer 11: and v = (x — 3)x2 therefore, y = Letu = Differentiating with respect to x, we have dy du dv dx dx dx x2-3 taking log
Page 8:  · Question 11: xx2-3 + (x — 3) x2 for x > 3. Answer 11: and v = (x — 3)x2 therefore, y = Letu = Differentiating with respect to x, we have dy du dv dx dx dx x2-3 taking log
Page 9:  · Question 11: xx2-3 + (x — 3) x2 for x > 3. Answer 11: and v = (x — 3)x2 therefore, y = Letu = Differentiating with respect to x, we have dy du dv dx dx dx x2-3 taking log

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