Reinforcement of Openings on Tori-Dish (Trial).xls

7/29/2019 Reinforcement of Openings on Tori-Dish (Trial).xls

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MDC No. : 896 Client : RIL Page

Project No. : 130339 Consultant : Chemtex Rev : 0

Made by : JSB Eqpt. no. : 1222-H01 Date : 16/07/04 bhat

Nozzle Mark = Q1,2-Stub

Nozzle Location Shell

Size of Nozzle ( O/D ) do = 32 in

Thickness of nozzle neck provided tn' = 0.63 in

Internal corrosion of nozzle cin = 0.063 in

External Corrosion Allowance on Nozzle cen = 0 in `

Product form of nozzle - = Plate

Nozzle to vessel weld type - = Set in

Projection Length of Nozzle L = 1.9685 in

Joint Efficiency of Nozzle En = 1

Material of Nozzle Neck - = SA 516 Gr.70

Allowable Stress of Nozzle Neck(Design temp) Sn = 18800 psi

Allowable Stress of Nozzle Neck(Ambient temp) Sa = 20000 psi

Design Pressure Pi = 75.38 psi(g)

Liquid Head Hp = 0 in

Density of Operating liquid Fp = 0 lb/in

External Design Pressure Pe = 14.935 psi(g)Design Temperature Td = 650 F

Inside Diameter of shell (Uncorroded) }................................ Di = 103.86 in

Shell Thickness provided t' = 0.7874 in

Internal Corrosion Allowance of the Shell ci = 0 in

External Corrosion Allowance of the Shell ce = 0 in

Joint Efficency of Shell E = 0.85

Material of Vessel Part - = SA 240 Gr.304

Allowable Stress of Vessel Part at Td Sv = 16200 psi

Corroded shell Radius Ri = 51.929 in

Corroded Outer nozzle Radius ro = 16 in

Corroded nozzle diameter (internal) d = 30.99 in

Corroded Thickness of Shell t = 0.7874 inCorroded Thickness of Nozzle tn = 0.567 in

Pressure due to Liquid Height Pf = Hp * Fp

= 0 * 0

= 0 psi(g)

Total Design pressure P = Pi + Pf

= 75.38 + 0

= 75.38 psi(g)

Nozzle neck Thickness calculation

Required noz (internal pressure) trn = ( P x ro ) + ci + ce

(Sn En + 0.4 P)

= 75.38 x 16 + 0.063 + 0.000

(18800 x 1 + 0.4 x 75.38)

Required nozzle thickness (internal pressure) trn = 0.127 in

Corroded outer nozzle diameter do = 2.ro in

= 32 in

L/do = 0.062

Required nozzle thickness (external pressure) trne = 0.04 in

(using iterations)

Geometric chart factor from Table G A = 0.0013

Material chart factor from Table CS-2 B = 8970.7 psi

Pa = 4B/3.(do/trne)

GODREJ & BOYCE MFG.CO.LTD., PRODUCT ENGINEERING DEPT., P.E.D., MUMBAI, INDIA

NOZZLE NECK THICKNESS AND REINFORCEMENT CALCULATIONS


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= 4 * 8970.6982/ 3 * ( )

= #DIV/0! psi(g)

Pa = Pe Therefore the required thickness for trne = 0.04 in

external pressure is

Thickness for nozzle neck is Larger of 0.127 and 0.04

t1 = 0.04 in

Thickness as per UG-45(b)(1)(uncoroded)

Required she (internal pressure) tr = ( P Ri )/ (Sv En - 0.6 P) + ci + ce

= 75.38 * 51.929

16200 * 1 - 0.6 * 75.38

= 0.242 in

tr = 0.242 in

Thickness as per UG-45(b)(2)(uncoroded) t2 = (Pe Ri)/ (Sv En - 0.6 Pe) + ci + ce

(considering the internal design pressure

equal to the external pressure) 14.935 x + 0.00 + 0.00

= 16200 * 1 - 0.6 * 14.935

= 0.048 in

Thickness as per UG-45(b)(3)(uncoroded)

Maximum of tr and t2, ie maximum of 0.242 and 0.048 t3 = 0.242 in

Standard nominal thickness of nozzle tstd = 0.375 in

Thickness as per UG-45(b)(4)(uncoroded) t4 = tstd+cin in

= 0.375 + in

= 0.438 in

The smaller of t3 & t4 t5 = 0.242 in

The lareger of t1 & t5 t6 = 0.242 in

Min required thickness of Nozzle Neck = t6 trn' = 0.242 in

Thickness of nozzle considered in calculation tn = 0.63 in

Since tn>trn', the Nozzle Neck Thickness is Adequate

Reinforcement CalculationFactor F F = 1

Required shell thickness (internal pressure) tr = 0.242 in

Required shell thickness (external pressure) tre = 0.539 in (refer pg.no. 21)

Required nozzle thickness (internal pressure) trn = 0.127 in

Required nozzle thickness (external pressure) trne = 0.04 in

Factor E1 Joint Efficency E1 = 1

Factor 1 (Stress reduction factor) fr1 = smaller of 1 or 18800 / 16200

(the smaller of 1.0 or Sn/Sv) = 1

Factor 2 fr2 = Sn / Sv

= 1.16

Vessel Shell and Nozzle fillet weld = 0.354 in

Factor 3 fr3 = 1

Internal Pressure According To UG 37 C

Corroded Internal diameter of nozzle d = 30.99 in

Area required for Reinforcement A = d.tr.F+2.tn.tr.F(1-fr1)

= 30.99 x 0.242 x 1 + 2 x 0.567 x 0.242 x 1 x (1 - 1 )

= 7.5 in

Area Availble in shell A1 ={ d.(E1.t - F.tr)-2.tn.(E1.t - F.tr)(1-fr1)

2(t+tn).(E1.t - F.tr) - 2.tn(E1.t-F.tr).(1-fr1)


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={ 30.99(1*0.7874-1*0.242) -2*0.242(1*0.7874-1*0.242).(1-1)

2(0.7874+0.63).(1*0.7874-1*0.242)-2.0.63(1*0.7874-1*0.242)

.(1-1)

={ 16.9020 in2

1.477 in

A1 = larger of 16.902 and 1.477

= 16.902 in

Area in Nozzle wall, No pad A2 ={ 5.(tn - trn).fr2.t

5.(tn - trn).fr2.tn

={ 5.(0.567-0.127).1.16*0.7874

5.(0.63-0.127).1.16*0.63

={ 2.009 in

1.4500 in

A2 = smaller of 2.009 and 1.45

= 1.450 in

Area in welds A41 = fr2.(leg)

= 0.044 in

Total Area Available without Pad = A1+A2+A41= 16.902 + 1.45 + 0.044

= 18.396 in

Area provided is Adequate, Pad is not Needed as for Internal Pressure reinforcement

External pressure According to UG 37 d

Area required for Reinforcement A = 0.5{d.tre.F + 2.tn.tre.F.(1-fr1)}

= 0.5 x {30.99 x 0.539 x 1+2*0.63 x 0.539 x 1(1 - 1)}

= 8.352 in

Area Available in shell A1 ={ d.(E1.t - Ftre)-2.tn(E1.t - F.tre)(1- fr1)

2.(t+tn).(E1.t - F.tre) - 2.tn(E1.t-F.tr).(1-fr1)

={ 30.99(1*0.7874-1*0.539)-2.0.63(1*0.7874-1*0.539).(1-1)

2.(0.7874+0.63).(1*0.7874-1*0.539-2.(1*0.7874-1*0.539).(1-1)

={ 7.698 in0.673 in

= larger of 7.698 and 0.673

A1 = 7.698 in

Area available in Nozzle wall , without Pad A2 ={ 5.(tn - trne).fr2.t

5.(tn - trne).fr2.tn

={ 5.(0.567-0.04).1.16*0.7874

5.(0.567-0.04).1.16*0.63

={ 2.407 in

2.156 in

= smaller of 2.407 and 2.156

A2 = 2.156 in

Area in welds A41 = fr2.(leg)2

= 0.044 in

Total Area without pad = A1+A2+A41

7.698+2.156+0.044

= 9.898 in

Reinforcement is Adequate for External pressure

Pad Data

Pad Material = SA 240 Gr.304

Pad Allowable stress at Ambient Temp Spa = 20000 psi

Pad Allowable stress at Design Temp Sp = 16200 psi


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Pad O/D dp = 38.189 in

Thickness of pad te = 0.7874 in

Pad I/D dpi = 6.189 in

Weld size between Pad and Shell Wp = 0.551 in

Factor fr4 fr4 = Sp/Sv

1

Area available in Nozzle,with Pad A2 ={ 5.(tn-trne) x fr2 x t

2.(tn-trne).(2.5.tn+te)

={ 5 x (0.63-0.04).1.16*0.7874

2.(0.63-0.04).(2.5*0.63+0.7874)

={ 2.407 in

2.324 in

A2 = smaller of 2.407 and 2.324

= 2.324 in

Area available in Nozzle to Shell welds A41 = 0.044 in

Area available in Pad to Shell welds A42 = fr4. (Wp)

= 0.304 in

Area Availble in reinforcing Pad A5 = (dp-d-2tn).te.fr4

(38.189 - 30.99 - 2 x 0.63) x 0.7874 x 1

= 4.7756 in

Total Area Provided Ap = A1+A2+A41+A42+A5

Total Area Provided Ap = A1+A2+A41+A42+A5

0 in

Reinforcement Area is Adequate


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Pipe

Plate

Set in

Set on


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A1 16.902

A2 1.45 1.45

A41 0.044 0.044

A42 0.304 0.304

A5 4.776 4.776


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2

Nozzle Mark A1 -

Nominal Size of Nozzle 22" -

Nozzle Location Tori-Dish end -

Distance between the centre lines of Vessel & Nozzle L' 0 inInternal Design Pressure Pi 110.661 psi(g)

External Design Pressure Pe 90.321 psi(g)

Design Temperature Td 650 C

Internal Corrosion Allowance on Vessel ci 0.000 in

External Corrosion Allowance on Vessel ce 0.063 in

Material of Vessel Part - SA 516 Gr.70

Allowable Stress of Vessel Part at Td Sv 18800 psi

Inside Radius of Shell or Inside Crown }

Radius of Head (Uncorroded) }................................ Ru 95.984 in

Inside Knuckle Radius (Uncorroded) ru 6.496 in

Minimum Thickness of Vessel Part (Uncorroded) tu 1.063 in

Minimum Thickness of Vessel Part (Corroded) tc 1 in

Nominal Thickness of Vessel Part (Uncorroded) tvu 1.26 in

Nominal Thickness of Vessel Part (Corroded) tv 1.197 in

Minimum Thickness as per UG-16 (b) ( including corrosion) t' 0.126 in

Head Thickness under Internal Pressure [Per 1-4 (d)]

Inside Crown Radius (Corroded) Ru + ci

95.984 + 0.000 in

R 95.984

Inside Knuckle Radius (Corroded)

= ru + ci in

= 6.496 + 0.000 r 6.496

-

Factor (as per UG-37 (a) (1)) M 1

Required Thickness (Unc where E = 1

= P.R.M / (2.S.E - 0.2 P) + ci + ce

110.661 x 95.984 x 1.000 + 0.00 + 0.063

( 2 x 18,800.00 x 1 - 0.2 x 110.66 ) tS 0.34566 in

Minimum Thickness of Head (Uncorroded)

= t' + ci + ce

= 0.126 + 0.000 + 0.063 t'u 0.189 in

Minimum Required Thickness

= The Larger of t'u or tS

= The Larger of 0.189 or 0.346 triu1 0.346 in

- Under Internal Pressure (Corroded) tri 0.283 in

Minimum required thickness treu 0.973 in

- Under Internal Pressure (Corroded) tre 0.91 in




eck : 1. Plate/Forging ; 2. Pipe ? - 1






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d Type: 1. Set-In; 2. Set-On ? - 1

of Nozzle (Uncorroded) dou in 22

Internal Corrosion Allowance on Nozzle cin in 0

External Corrosion Allowance on Nozzle cen in 0

Joint Efficiency of Nozzle En - 1

Material of Nozzle Neck - - SA-240 Gr.316

Allowable Stress of Nozzle Neck Sn psi 16600

Nozzle Wall Schedule - -

Nominal Thickness of Nozzle Neck (Uncorroded) tnu in 0.7874

Inside Diameter of Nozzle (Corroded) = dou-2tnu+2cin= 22.000 - 2 x 0.787 + 2 x 0.000... d in 20.425

Inside Radius of Shell (Corroded) = Ru + ci R in 95.984

Inside Radius of Nozzle (Corroded) = (dou-2 tnu+2cin)/2 Rn in 10.2126

Mean Radius at Midsurface = R + tri/2 Rm in 96.1255

Angle a = {cos-1[(L' - Rn)/Rm]} - {cos-1[(L' + Rn)/Rm]} a 12.1975

Finished Diameter or chord length of Opening at Midsurface (Corroded)

= 2Rm [1-cos(a/2)]^0.5......

= 2 x 96.126 [ 1 - cos-1( 12.20 / 2) ]^0.5..... di in 20.4252

Inside Radius of Nozzle (Corroded) = di/2 = 20.425 / 2 ri in 10.2126

Min . Thickness of Nozzle Neck for Internal Pressure

={ Pi.ri/[Sn.En-0.6 Pi] }+ci+ce

= { 110.661x10.213/[16600.000x1.000- 0.6 x 110.661 ] } +0.000 + 0.000 trnu in 0.06835

Required Nozzle Neck Thickness (corroded)

= trnu - cin

= 0.068 - 0.000 trn in 0.06835

Design of Nozzle under external pressure

Nozzle projection L in 25.394

Nozzle outside diameter (corroded)

= dou - cen

= 22.00 - 0.00 do in 22

L/do 1.15427

do/(tnu-cen) 27.9401

Value of A from Table G A 0.00093

Value of B from Table HA-1 B [ psi 7912.21

Minimum thickness required under external pressure

= 3 Pe do/ (4 B) + cin + cen

= [3 x 90.32 x 22.00 / (4 x 7,912.21 )] + 0.00 + 0.00 trenu [ in 0.18835

Required Nozzle Neck Thickness (corroded)

= trenu - cin - cen

= 0.188 - 0.000 - 0.000 tren [ in ] 0.18835

Minimum required thickness is Maximum of trnu & trenu t1 [ in ] 0.1884




M = ( 3 + (L/r)^0.5 )x 0.25 M 1.711

oded)

i + ce

1.711 + 0.000 + 0.063 [ in ] 0.5472

0.66 )

GODREJ & BOYCE MFG.CO.LTD., PRODUCT ENGINEERING DEPT., P.E.D., MUMBAI, INDIANOZZLE NECK THICKNESS AND REINFORCEMENT CALCULATIONS


15/23

= Larger of 0.547 & t' t2 [ in ] 0.5472

Thickness perUG-45(b)(2) (Uncorroded)

= [ Pe.R.M / (2.Sv.E - 0.2 Pe) ] + ci + ce

= 90.321 x 95.984 x 1. + 0.000 + 0.063 [ in : ] 0.4581

0.32 )

= Larger of 0.458 & 0.126 t3 [ in ] 0.4581

oded)

& t3

= Maximum of 0.547 & 0.458 t4 [ in ] 0.5472Standard Wall Thk. of Nozzle (Uncorroded) Sw [ in ] 0.375

Thickness perUG-45(b)(4) (Uncorroded)

= Sw + cin + cen

= 0.375 + 0.000 + 0.000 t5 [ in ] 0.375

The Smaller of t4 or t5 t6 [ in ] 0.375

The Larger of t1 or t6 t7 [ in ] 0.375

Min. Required Thickness of Nozzle Neck (Uncorroded) tnm [ in ] 0.375

Nominal Thickness of Nozzle Neck (Uncorroded) tnu [ in ] 0.7874

Since provided thickness tnu > tnm, the Nozzle Neck Thickness is Adequate.

Maximum Diameter of the Opening that does not }

require additional reinforcement per UG-(36)(c)(3)(a) }............ do [ in ] 2.362

Since di > do, further Reinforcement Check is Required.

Size of Nozzle Neck-to-Vessel Weld : [Per UW-16]

The Smaller of 0.75" or (the Thinner of tvu or tnu) tmin [ in ] 0.75

Weld Throat = The Smaller of 0.25" or 0.7 tmin tc [ in ] 0.25

Weld Leg Size = tc / 0.707 = 0.250 / 0.707 w1m [ in ] 0.3536

Actual Weld Leg Size w1 [ in ] 0.4724

Inward projection of nozzle neck h [ in ] 0

Factor F [ - ] 1

The Required Thickness of a Seamless Shell (corroded) tri [ in ] 0.3457

Required Thickness of Nozzle (Corroded) = tnm-cin-cen trn [ in ] 0.375

Nominal Thickness of Nozzle (Corroded) = tnu-cin-cen tn [ in ] 0.7874




Limit of Reinforcement Along the Vessel Wall : [Per UG-40]

= The Larger of 2di or 2(di/2+tv+tn)

= Larger of 2 x 20.425 or 2 x (20.425/2+1.197+0.787) L1 [ in ] 40.85

Limit of Reinforcement Normal to the Vessel Wall : [Per UG-40]

= The Smaller of (2.5*tv) or (2.5*tn+te)

= The Smaller of (2.5 x 1.197) or (2.5 x 0.346 + 1.000). L3 [ in ] 2.9685

Strength Reduction Factors, not Greater than 1.0:

fr1 = Sn/Sv; 1.0 for set-on nozzles fr1 [ - ] 0.883

fr2 = (Lesser of Sn or Sp)/Sv fr2 [ - ] 1




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fr3 = Sp/Sv fr3 [ - ] 1

Required Area of Reinforcement : [Per UG-37]

Required Area for Internal Pressure = di.tri.F +2.tn.tri.F (1-fr1)

= (20.425 x 0.346 x 1.000 + 2 x 0.787 x 0.346 x 1.000 (1 - 1.00 ) Ari [ in ] 7.1238

Required Area for External Pressure = 0.5(di.tre.F +2.tn.tre.F (1-fr1)) Are [ in ] ####

The larger of Ari or Are Ar [ in ] 10.0100

Area Available Without Reinforcing Pad:

Area Available in Shell:

= The Larger of (di-2tn) (tv-F.tri) OR 2tv(tv-F.tri) A1 [ in ] 19.395Area Available in Outward Nozzle:

= The Smaller of 2(tn-trn) (2.5tv.fr1) OR2(tn-trn) (2.5tn+te)fr1 A2 [ in ] 2.1619

Area Available in Inward Nozzle = 2.h.tn.fr1 A3 [ in ] 0

Area Available in Outward Nozzle-to-Vessel Weld = w1.fr2 A41 [ in ] 0.223

Area Available in Inward Nozzle-to-Vessel Weld = w32.fr2 A43 [ in ] 0

Total Available Area of Reinforcement = A1+A2+A3+A41+A43 Aa [ in ] 21.8

Is the Opening Adequately Reinforced WITHOUT the Pad? ? [ - ] Yes

Area Available With Reinforcing Pad:

Outside Diameter of Reinforcing Pad Dp [ in ] 31.889

Thickness of Reinforcement Pad te [ in ] 1Allowable Stress of Reinforcement Pad Sp [ psi ] 18800

Minimum Outward Nozzle-to-Pad Fillet Weld Size w2m [ in ] 0.3536

Actual Outward Nozzle-to-Pad Fillet Weld Size w2 [ in ] 0.472

Minimum Inward Nozzle-to-Pad Fillet Weld Size w3m [ in ] 0

Actual Inward Nozzle-to-Pad Fillet Weld Size w3 [ in ] 0

Minimum Pad-to-Vessel Fillet Weld Size w4m [ in ] -




Actual Pad-to-Vessel Fillet Weld Size w4 [ in ] -

Area Available With Reinforcing Pad:

Area Available in Shell = A1 A1' [ in ] -

Area Available in Outward Nozzle

= The Larger of 2(tn-trn) (2.5t.fr1) OR2(tn-trn) (2.5tn+te)fr1 A2' [ in ] -

Area Available in Inward Nozzle = A3 A3' [ in ] -

Area Available in Nozzle-to-Pad Weld = A41 A41' [ in ] -

Area Available in Pad-to-Vessel Weld A42' [ in ] -

Area Available in Inward Nozzle-to-Vessel Weld = w3.fr1 A43' [ in ] -

Area Available in Reinforcing Pad = (Dp-di-2tn)te.fr3 A5 [ in ] -

Total Available Area of Reinforcement

= A1'+A2'+A3'+A41'+A42'+A43+A5 Aa' [ in ] -

Is the Opening Adequately Reinforced WITH the Pad? ? [ - ] -




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Reinforcement of Openings on Tori-Dish (Trial).xls

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