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Research Article An Inventory Model under Trapezoidal Type Demand, Weibull-Distributed Deterioration, and Partial Backlogging Lianxia Zhao School of Management, Shanghai University, Shanghai 200444, China Correspondence should be addressed to Lianxia Zhao; zhaolianxia@staff.shu.edu.cn Received 7 November 2013; Revised 19 January 2014; Accepted 21 January 2014; Published 6 March 2014 Academic Editor: Nachamada Blamah Copyright © 2014 Lianxia Zhao. is is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited. is paper studies an inventory model for Weibull-distributed deterioration items with trapezoidal type demand rate, in which shortages are allowed and partially backlogging depends on the waiting time for the next replenishment. e inventory models starting with no shortage is are to be discussed, and an optimal inventory replenishment policy of the model is proposed. Finally, numerical examples are provided to illustrate the theoretical results, and a sensitivity analysis of the major parameters with respect to the optimal solution is also carried out. 1. Introduction e effect of deteriorating for items cannot be disregarded in many inventory systems and it is a general phenomenon in real life. Deterioration is defined as any process that decreases the usefulness or the value of the original item, such as decay or physical depletion. For example, fruits, vegetables, or foodstuffs are subject to spoilage directly while being kept in store, and electronic products, radioactive substances, and photographic film deteriorate through a gradual loss of potential or utility with the passage of time. Due to the variability in economic circumstances, the basic assumptions of the EOQ model should be constantly modified according to the studied inventory model. In recent years, many researchers have studied kinds of EOQ models for deteriorating items. Ghare and Schrader [1] established the classical no-shortage inventory model with a constant rate of decay. Wu et al. [2] studied an inventory model with a Weibull-distributed deteriorating rate for items and assumed the demand rate with a continuous function of time. Wee [3] developed an inventory model with quantity discount, pricing, and partial backordering when the product in stock deteriorates with time. Related literature also includes Skouri and Papachristos [4], Wee [5], and Dye et al. [6]. practically, the demand rate of deterioration items is impossible to increase continuously all the time. Hill [7] proposed an inventory model with ramp type demand rate. Mandal and Pal [8] extended the inventory model with ramp type demand for deterioration items and allowed shortage. Wu [9] considered an inventory model with Weibull distribution deterioration and ramp type demand rate in which shortages are allowed and the backlogging rate is dependent on waiting time. Giri et al. [10] extended the ramp type demand inventory model with a more generalized Weibull deterioration distribution. Manna and Chaudhuri [11] developed an inventory model for time-dependent dete- riorating items with ramp type demand rate. Skouri et al. [12] considered an inventory model with general ramp type demand rate, partial backlogging, and Weibull deterioration rate. Hung [13] extended their inventory model from ramp type demand rate and Weibull deterioration rate to arbitrary demand rate and arbitrary deterioration rate. Kumar et al. [14] studied fuzzy EOQ models with ramp type demand rate, partial backlogging, and time-dependent deterioration rat. Cheng et al. [15] considered an inventory model for time-dependent deteriorating items with trapezoidal type demand rate and partial backlogging. Uthayakumar and Rameswari [16] studied an inventory model for defective items with trapezoidal type demand rate to determine the optimal product reliability. Tan and Weng [17] considered a discrete-in-time inventory model for deteriorating items with partially backlogged. Ahmed et al. [18] proposed a method for Hindawi Publishing Corporation Journal of Applied Mathematics Volume 2014, Article ID 747419, 10 pages http://dx.doi.org/10.1155/2014/747419
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Page 1: Research Article An Inventory Model under Trapezoidal Type ...downloads.hindawi.com/journals/jam/2014/747419.pdf · an inventory model with Weibull-distributed deterioration items,

Research ArticleAn Inventory Model under Trapezoidal Type DemandWeibull-Distributed Deterioration and Partial Backlogging

Lianxia Zhao

School of Management Shanghai University Shanghai 200444 China

Correspondence should be addressed to Lianxia Zhao zhaolianxiastaffshueducn

Received 7 November 2013 Revised 19 January 2014 Accepted 21 January 2014 Published 6 March 2014

Academic Editor Nachamada Blamah

Copyright copy 2014 Lianxia ZhaoThis is an open access article distributed under the Creative Commons Attribution License whichpermits unrestricted use distribution and reproduction in any medium provided the original work is properly cited

This paper studies an inventory model for Weibull-distributed deterioration items with trapezoidal type demand rate in whichshortages are allowed and partially backlogging depends on the waiting time for the next replenishment The inventory modelsstarting with no shortage is are to be discussed and an optimal inventory replenishment policy of the model is proposed Finallynumerical examples are provided to illustrate the theoretical results and a sensitivity analysis of the major parameters with respectto the optimal solution is also carried out

1 Introduction

The effect of deteriorating for items cannot be disregarded inmany inventory systems and it is a general phenomenon inreal life Deterioration is defined as any process that decreasesthe usefulness or the value of the original item such asdecay or physical depletion For example fruits vegetablesor foodstuffs are subject to spoilage directly while beingkept in store and electronic products radioactive substancesand photographic film deteriorate through a gradual loss ofpotential or utility with the passage of time

Due to the variability in economic circumstances thebasic assumptions of the EOQ model should be constantlymodified according to the studied inventory model In recentyears many researchers have studied kinds of EOQ modelsfor deteriorating items Ghare and Schrader [1] establishedthe classical no-shortage inventorymodelwith a constant rateof decay Wu et al [2] studied an inventory model with aWeibull-distributed deteriorating rate for items and assumedthe demand rate with a continuous function of time Wee[3] developed an inventory model with quantity discountpricing and partial backordering when the product in stockdeteriorates with time Related literature also includes Skouriand Papachristos [4] Wee [5] and Dye et al [6]

practically the demand rate of deterioration items isimpossible to increase continuously all the time Hill [7]

proposed an inventory model with ramp type demand rateMandal and Pal [8] extended the inventory model withramp type demand for deterioration items and allowedshortageWu [9] considered an inventorymodelwithWeibulldistribution deterioration and ramp type demand rate inwhich shortages are allowed and the backlogging rate isdependent on waiting time Giri et al [10] extended theramp type demand inventory model with a more generalizedWeibull deterioration distribution Manna and Chaudhuri[11] developed an inventory model for time-dependent dete-riorating items with ramp type demand rate Skouri et al[12] considered an inventory model with general ramp typedemand rate partial backlogging and Weibull deteriorationrate Hung [13] extended their inventory model from ramptype demand rate and Weibull deterioration rate to arbitrarydemand rate and arbitrary deterioration rate Kumar et al[14] studied fuzzy EOQ models with ramp type demandrate partial backlogging and time-dependent deteriorationrat Cheng et al [15] considered an inventory model fortime-dependent deteriorating items with trapezoidal typedemand rate and partial backlogging Uthayakumar andRameswari [16] studied an inventory model for defectiveitems with trapezoidal type demand rate to determine theoptimal product reliability Tan and Weng [17] considered adiscrete-in-time inventorymodel for deteriorating itemswithpartially backloggedAhmed et al [18] proposed amethod for

Hindawi Publishing CorporationJournal of Applied MathematicsVolume 2014 Article ID 747419 10 pageshttpdxdoiorg1011552014747419

2 Journal of Applied Mathematics

finding the economic order quantity for an inventory modelwith ramp type demand rate partial backlogging and generaldeterioration rate Lin [19] explored the inventorymodel witha general demand rate in which both the Weibull-distributeddeterioration and partial backlogging are considered

In the above mentioned research one of assumptionswas considered the ramp type demand rate partial back-logging andWeibull-distributed deterioration rateHoweverfor fashionable commodities high-tech products and othershort life cycle products the demand rate should increasewith the time up to certain point at first stage then reacha stabilized period and finally the demand rate decreaseto zero and the products retreat from market in theirproduct life cycle that is the demand rate with continuoustrapezoidal function of time On the other hand inmany realsituations customers encountering shortages will responddifferently Some customers are willing to wait until thenext replenishment while others may be impatient and goelsewhere as waiting time increases that is the willingnessfor a customer to wait for backlogging is diminishing withthe length of the waiting time In this paper we consideran inventory model with Weibull-distributed deteriorationitems trapezoidal type demand rate and time-dependentpartial backlogging By analyzing the inventory model auseful inventory replenishment policy is proposed Finallynumerical examples are provided to illustrate the theoreticalresults and a sensitivity analysis of the optimal solution withrespect to major parameters is also carried out

The rest of the paper is organized as follows Section 2describes the notation and assumptions used throughout thispaper Section 3 analyzes the inventory model and somenumerical examples to illustrate the solution procedure areprovided Sensitivity analysis of the major parameters is alsocarried out in Section 4 and the final Section concludes thispaper

2 Notations and Assumptions

The fundamental notations and assumptions used in inven-tory model and considered in this paper are given as below

(i) 119868(119905) the level of inventory at time 119905 0 le 119905 le 119879(ii) 119879 the fixed length of each ordering cycle(iii) 1199051the time when the inventory level reaches zero for

the inventory model(iv) 119905lowast1the optimal point

(v) 119878 the maximum inventory level for each orderingcycle

(vi) 119876lowast the optimal ordering quantity(vii) 119860

0the fixed cost per order

(viii) 1198881the cost of each deteriorated item

(ix) 1198882the inventory holding cost per unit per unit of time

(x) 1198883the shortage cost per unit per unit of time

(xi) 1198884the lost sales cost per unit

(xii) 119862119894(1199051) 119894 = 1 2 3 the average total cost per unit time

under different conditions respectively

(xiii) 119879119862(1199051) the average total cost per unit time

(xiv) The demand rate 119863(119905) which is positive and consec-utive is assumed to be a trapezoidal type function oftime that is

119863 (119905) =

119891 (119905) 119905 le 1205831

1198630 120583

1lt 119905 lt 120583

2

119892 (119905) 1205832le 119905 lt 119879

(1)

where 1205831is time point changing from the increasing

demand function119891(119905) to constant demand1198630 and 120583

2

is time point changing from the constant demand1198630

to the decreasing demand function 119892(119905)(xv) The replenishment rate is infinite that is replenish-

ment is instantaneous(xvi) The deterioration rate of the item is defined as

Weibull (120572 120573) that is the deterioration rate is 120579(119905) =120572120573119905120573minus1

(120572 gt 0 120573 gt 0 119905 gt 0)(xvii) Shortages are allowed and they adopt the notation

used in Abad [20] where the unsatisfied demandis backlogged and the fraction of shortages backo-rdered is 119890minus120575119905 where 119905 is the waiting time up to thenext replenishment We also assume that 119905119890minus120575119905 is anincreasing function which had appeared in Skouri etal [12]

(xviii) The time horizon of the inventory model is finite

3 Model Formulation

In this section we consider an inventory model startingwith no shortage The behavior of the model during a givencycle is depicted in Figure 1 Replenishment occurs at time119905 = 0 and the inventory level attains its maximum From119905 = 0 to 119905

1 the inventory level reduces due to demand

and deterioration At 1199051 the inventory level achieves zero

then shortage is allowed to occur during the time interval(1199051 119879) and all of the demand during the shortage period

(1199051 119879) is partially backlogged According to the notations and

assumptions mentioned above the behavior of the modelat any time can be described by the following differentialequations

119889119868 (119905)

119889119905=

minus120579 (119905) 119868 (119905) minus 119863 (119905) 0 lt 119905 lt 1199051

minus119890minus120575(119879minus119905)

119863 (119905) 1199051lt 119905 lt 119879

(2)

with boundary conditions 119868(0) = 119878 119868(1199051) = 0

In the following we consider three possible cases basedon the values of 119905

1 1205831 and 120583

2 These three cases are shown

Case 1 (0 lt 1199051le 1205831) Due to the deteriorating and trapezoidal

type demand rate the inventory level gradually diminishesduring the time interval [0 119905

1] and ultimately falls to zero at

time 1199051 Thus from (2) we have

119889119868 (119905)

119889119905=

minus120572120573119905120573minus1

119868 (119905) minus 119891 (119905) 0 lt 119905 lt 1199051

minus119890minus120575(119879minus119905)

119891 (119905) 1199051lt 119905 lt 120583

1

minus119890minus120575(119879minus119905)

1198630 120583

1lt 119905 lt 120583

2

minus119890minus120575(119879minus119905)

119892 (119905) 1205832lt 119905 lt 119879

(3)

Journal of Applied Mathematics 3

0

S

Inventorylevel

TimeT

0

S

Inventorylevel

TimeT

0

S

Inventorylevel

TimeT1205831

t1

1205832 t11205831

1205832 t11205831 1205832

Case 1 0 lt t1 le 1205831 Case 2 1205831 le t1 le 1205832 Case 3 1205832 le t1 lt T

Figure 1 Graphical representation of inventory level over the cycle

By using the boundary condition 119868(1199051) = 0 the solutions of

(3) are given by

119868 (119905) =

int

1199051

119905

119891 (119909) 119890120572(119909120573minus119905120573)119889119909 0 lt 119905 lt 119905

1

minusint

119905

1199051

119890120575(119909minus119879)

119891 (119909) 119889119909 1199051lt 119905 lt 120583

1

1198630

120575(119890120575(1205831minus119879)

minus 119890120575(119905minus119879)

)

minusint

1205831

1199051

119890120575(119909minus119879)

119891 (119909) 119889119909 1205831lt 119905 lt 120583

2

minusint

119905

1205832

119892 (119909) 119890120575(119909minus119879)

119889119909

+1198630

120575(119890120575(1205831minus119879)

minus 119890120575(1205832minus119879)

)

minusint

1205831

1199051

119890120575(119909minus119879)

119891 (119909) 119889119909 1205832lt 119905 lt 119879

(4)

The maximum inventory level per cycle is

119878 = 119868 (0) = int

1199051

0

119891 (119909) 119890120572119909120573

119889119909 (5)

Then the total number of deteriorated items 119863119879in the

interval [0 1199051] is

119863119879= 119878 minus int

1199051

0

119863 (119905) 119889119905 = int

1199051

0

119891 (119909) (119890120572119909120573

minus 1) 119889119909 (6)

The total number of inventory119867119879carried during the interval

[0 1199051] is

119867119879= int

1199051

0

119868 (119905) 119889119905 = int

1199051

0

int

1199051

119905

119891 (119909) 119890120572(119909120573minus119905120573)119889119909 119889119905 (7)

The total shortage quantity 119861119879during the interval [119905

1 119879] is

119861119879= minusint

119879

1199051

119868 (119905) 119889119905

= int

1205831

1199051

[int

119905

1199051

119890120575(119909minus119879)

119891 (119909) 119889119909] 119889119905

minus int

1205832

1205831

[1198630

120575(119890120575(1205831minus119879)

minus 119890120575(119905minus119879)

)

minusint

1205831

1199051

119890120575(119909minus119879)

119891 (119909) 119889119909] 119889119905

+ int

119879

1205832

[int

119905

1205832

119890120575(119909minus119879)

119892 (119909) 119889119909

minus1198630

120575(119890120575(1205831minus119879)

minus 119890120575(1205832minus119879)

)

+int

1205831

1199051

119890120575(119909minus119879)

119891 (119909) 119889119909] 119889119905

= int

1205831

1199051

(119879 minus 119905) 119890120575(119905minus119879)

119891 (119905) 119889119905

+ int

119879

1205832

(119879 minus 119905) 119890120575(119905minus119879)

119892 (119905) 119889119905

+1198630

1205752(119890120575(1205832minus119879)

minus 119890120575(1205831minus119879)

)

+1198630

120575[(119879 minus 120583

2) 119890120575(1205832minus119879)

minus (119879 minus 1205831) 119890120575(1205831minus119879)

]

(8)

The total of lost sales 119871119879during the interval [119905

1 119879] is

119871119879= int

1205831

1199051

(1 minus 119890120575(119905minus119879)

) 119891 (119905) 119889119905 + int

1205832

1205831

(1 minus 119890120575(119905minus119879)

)1198630119889119905

+ int

119879

1205832

(1 minus 119890120575(119905minus119879)

) 119892 (119905) 119889119905

(9)

4 Journal of Applied Mathematics

Therefore the average total cost per unit time under thecondition 119905

1le 1205831can be given by

1198621(1199051) =

1

119879[1198600+ 1198881119863119879+ 1198882119867119879+ 1198883119861119879+ 1198884119871119879]

=1

1198791198600+ 1198881int

1199051

0

119891 (119909) (119890120572119909120573

minus 1) 119889119909

+ 1198882int

1199051

0

int

1199051

119905

119891 (119909) 119890120572(119909120573minus119905120573)119889119909 119889119905

+ 1198884[int

1205831

1199051

(1 minus 119890120575(119905minus119879)

) 119891 (119905) 119889119905

+ int

1205832

1205831

(1 minus 119890120575(119905minus119879)

)1198630119889119905

+int

119879

1205832

(1 minus 119890120575(119905minus119879)

) 119892 (119905) 119889119905]

+ 1198883[int

1205831

1199051

119890120575(119905minus119879)

(119879 minus 119905) 119891 (119905) 119889119905

+ int

119879

1205832

119890120575(119905minus119879)

(119879 minus 119905) 119892 (119905) 119889119905

+1198630

1205752(119890120575(1205832minus119879)

minus 119890120575(1205831minus119879)

)

+1198630

120575((119879 minus 120583

2) 119890120575(1205832minus119879)

minus (119879 minus 1205831) 119890120575(1205831minus119879)

) ]

(10)

Case 2 (1205831le 1199051le 1205832) The differential equations governing

the inventory model can be expressed as follows

119889119868 (119905)

119889119905=

minus120572120573119905120573minus1

119868 (119905) minus 119891 (119905) 0 lt 119905 lt 1205831

minus120572120573119905120573minus1

119868 (119905) minus 1198630 120583

1lt 119905 lt 119905

1

minus119890minus120575(119879minus119905)

1198630 119905

1lt 119905 lt 120583

2

minus119890minus120575(119879minus119905)

119892 (119905) 1205832lt 119905 lt 119879

(11)

Solving the differential equation (11) with 119868(1199051) = 0 we have

119868 (119905) =

int

1205831

119905

119891 (119909) 119890120572(119909120573minus119905120573)119889119909

+1198630int

1199051

1205831

119890120572(119909120573minus119905120573)119889119909 0 lt 119905 lt 120583

1

1198630int

1199051

119905

119890120572(119909120573minus119905120573)119889119909 120583

1lt 119905 lt 119905

1

1198630

120575(119890120575(1199051minus119879)

minus 119890120575(119905minus119879)

) 1199051lt 119905 lt 120583

2

minusint

119905

1205832

119890120575(119909minus119879)

119892 (119909) 119889119909

+1198630

120575(119890120575(1199051minus119879)

minus 119890120575(1205832minus119879)

) 1205832lt 119905 lt 119879

(12)

The beginning inventory level can be computed as

119878 = 119868 (0) = int

1205831

0

119891 (119909) 119890120572119909120573

119889119909 + 1198630int

1199051

1205831

119890120572119909120573

119889119909 (13)

The total number of items which perish in the interval [0 1199051]

is

119863119879= int

1205831

0

119891 (119909) (119890120572119909120573

minus 1) 119889119909 + 1198630int

1199051

1205831

(119890120572119909120573

minus 1) 119889119909 (14)

The total number of inventory carried during the interval[0 1199051] is

119867119879= int

1205831

0

int

1205831

119905

119890120572(119909120573minus119905120573)119891 (119909) 119889119909 119889119905 + 119863

0int

1199051

1205831

int

1199051

119905

119890120572(119909120573minus119905120573)119889119909 119889119905

(15)

The total shortage quantity during the interval [1199051 119879] is

119861119879= int

119879

1205832

(119879 minus 119905) 119890120575(119905minus119879)

119892 (119905) 119889119905

+1198630

120575[119890120575(1199051minus119879)

(119879 minus 1199051+1

120575)

minus119890minus120575(1205832minus119879)

(119879 minus 1205832+1

120575)]

(16)

The total of lost sales during the interval [1199051 119879] is

119871119879= 1198630int

1205832

1199051

(1 minus 119890120575(119905minus119879)

) 119889119905 + int

119879

1205832

(1 minus 119890120575(119905minus119879)

) 119892 (119905) 119889119905

(17)

Therefore the average total cost per unit time under thecondition 120583

1le 1199051le 1205832can be given by

1198622(1199051) =

1

119879[1198600+ 1198881119863119879+ 1198882119867119879+ 1198883119861119879+ 1198884119871119879]

=1

1198791198600+ 1198881[int

1205831

0

119891 (119909) (119890120572119909120573

minus 1) 119889119909

+1198630int

1199051

1205831

(119890120572119909120573

minus 1) 119889119909]

+ 1198882[int

1205831

0

int

1205831

119905

119890120572(119909120573minus119905120573)119891 (119909) 119889119909 119889119905

+1198630int

1199051

0

int

1199051

119905

119890120572(119909120573minus119905120573)119889119909 119889119905]

Journal of Applied Mathematics 5

+ 1198883[int

119879

1205832

(119879 minus 119905) 119890120575(119905minus119879)

119892 (119905) 119889119905

+1198630

120575(119890120575(1199051minus119879)

(119879 minus 1199051+1

120575)

minus119890120575(1205832minus119879)

(119879 minus 1205832+1

120575)) ]

+ 1198884[1198630int

1205832

1199051

(1 minus 119890120575(119905minus119879)

) 119889119905

+int

119879

1205832

(1 minus 119890120575(119905minus119879)

) 119892 (119905) 119889119905]

(18)

Case 3 (1205832le 1199051lt 119879) The differential equations governing

the inventory model can be expressed as follows

119889119868 (119905)

119889119905=

minus120572120573119905120573minus1

119868 (119905) minus 119891 (119905) 0 lt 119905 lt 1205831

minus120572120573119905120573minus1

119868 (119905) minus 1198630 120583

1lt 119905 lt 120583

2

minus120572120573119905120573minus1

119868 (119905) minus 119892 (119905) 1205832lt 119905 lt 119905

1

minus119890minus120575(119879minus119905)

119892 (119905) 1199051lt 119905 lt 119879

(19)

Solving the differential equation (19) with 119868(1199051) = 0 we have

119868 (119905) =

int

1205831

119905

119890120572(119909120573minus119905120573)119891 (119909) 119889119909 + 119863

0int

1205832

1205831

119890120572(119909120573minus119905120573)119889119909 + int

1199051

1205832

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 0 lt 119905 lt 120583

1

1198630int

1205832

119905

119890120572(119909120573minus119905120573)119889119909 + int

1199051

1205832

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 120583

1lt 119905 lt 120583

2

int

1199051

119905

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 120583

2lt 119905 lt 119905

1

minusint

119905

1199051

119890120575(119909minus119879)

119892 (119909) 119889119909 1199051lt 119905 lt 119879

(20)

The beginning inventory level can be computed as

119878 = 119868 (0)

= int

1205831

0

119890120572119909120573

119891 (119909) 119889119909

+ 1198630int

1205832

1205831

119890120572119909120573

119889119909 + int

1199051

1205832

119890120572119909120573

119892 (119909) 119889119909

(21)

The total number of items which perish in the interval [0 1199051]

is

119863119879= int

1205831

0

(119890120572119909120573

minus 1)119891 (119909) 119889119909 + 1198630int

1205832

1205831

(119890120572119909120573

minus 1) 119889119909

+ int

1199051

1205832

(119890120572119909120573

minus 1) 119892 (119909) 119889119909

(22)

The total number of inventory carried during the interval[0 1199051] is

119867119879= int

1205831

0

int

1205831

119905

119890120572(119909120573minus119905120573)119891 (119909) 119889119909 119889119905

+ 1198630int

1205831

0

int

1205832

1205831

119890120572(119909120573minus119905120573)119889119909 119889119905

+ 1198630int

1205832

1205831

int

1205832

119905

119890120572(119909120573minus119905120573)119889119909 119889119905

+ int

1205832

0

int

1199051

1205832

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 119889119905

+ int

1199051

1205832

int

1199051

119905

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 119889119905

(23)

The total shortage quantity during the interval [1199051 119879] is

119861119879= int

119879

1199051

(119879 minus 119905) 119890minus120575(119879minus119905)

119892 (119905) 119889119905 (24)

The total of lost sales during the interval [1199051 119879] is

119871119879= int

119879

1199051

(1 minus 119890minus120575(119879minus119905)

) 119892 (119905) 119889119905 (25)

Therefore the average total cost per unit time under thecondition 120583

2le 1199051le 119879 can be given by

1198623(1199051) =

1

119879[1198600+ 1198881119863119879+ 1198882119867119879+ 1198883119861119879+ 1198884119871119879]

=1

1198791198600+ 1198881[int

1205831

0

(119890120572119909120573

minus 1)119891 (119909) 119889119909

+ 1198630int

1205832

1205831

(119890120572119909120573

minus 1) 119889119909

+int

1199051

1205832

(119890120572119909120573

minus 1) 119892 (119909) 119889119909]

6 Journal of Applied Mathematics

+ 1198882[int

1205831

0

int

1205831

119905

119890120572(119909120573minus119905120573)119891 (119909) 119889119909 119889119905

+ 1198630int

1205831

0

int

1205832

1205831

119890120572(119909120573minus119905120573)119889119909 119889119905

+ 1198630int

1205832

1205831

int

1205832

119905

119890120572(119909120573minus119905120573)119889119909 119889119905

+ int

1205832

0

int

1199051

1205832

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 119889119905

+int

1199051

1205832

int

1199051

119905

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 119889119905]

+ 1198883[int

119879

1199051

(119879 minus 119905) 119890120575(119905minus119879)

119892 (119905) 119889119905]

+ 1198884[int

119879

1199051

(1 minus 119890120575(119905minus119879)

) 119892 (119905) 119889119905]

(26)

From the above analysis we obtain that the total average costof the model over the time interval [0 119879] is

119879119862 (1199051) =

1198621(1199051) 0 lt 119905

1le 1205831

1198622(1199051) 120583

1lt 1199051le 1205832

1198623(1199051) 120583

2lt 1199051lt 119879

(27)

where 1198621(1199051) 1198622(1199051) and 119862

3(1199051) are obtained from (10) (18)

and (26) respectivelyIn the following we will provide the results which ensure

the existence of a unique 1199051 say 119905lowast1 so as to minimize the total

average cost for the model system starting with no shortagesIf 0 lt 119905

1le 1205831 taking the first-order derivative of 119862

1(1199051)

with respect to 1199051 we obtain

1198891198621(1199051)

1198891199051

=119891 (1199051)

119879ℎ (1199051) (28)

where

ℎ (1199051) = 1198881(119890120572119905120573

1 minus 1)

+ 1198882int

1199051

0

119890120572(119905120573

1minus119905120573)119889119905 + 119888

3(1199051minus 119879) 119890

120575(1199051minus119879)

+ 1198884(119890120575(1199051minus119879)

minus 1)

(29)

then we can obtain ℎ(0) lt 0 and ℎ(119879) gt 0 By using theassumption (119905119890minus120575119905 is an increasing function where 119905 is thewaiting time up to the next replenishment) we have

119889ℎ (1199051)

1198891199051

= 120572120573119905120573minus1

1(1198881119890120572119905120573

1 + 1198882int

1199051

0

119890120572(119905120573

1minus119905120573)119889119905)

+ [1198883(120575 (1199051minus 119879) + 1) + 119888

4120575] 119890120575(1199051minus119879)

+ 1198882gt 0

(30)

which implies that ℎ(1199051) is a strictly monotone increasing

function Therefore the equation

ℎ (1199051) = 1198881(119890120572119905120573

1 minus 1) + 1198882int

1199051

0

119890120572(119905120573

1minus119905120573)119889119905

+ 1198883(1199051minus 119879) 119890

120575(1199051minus119879)

+ 1198884(119890120575(1199051minus119879)

minus 1)

= 0

(31)

has a unique root 119905lowast1isin (0 119879) obtained by using Mathematica

90 Further 119905lowast1is the only zero-point of 119889119862

1(1199051)1198891199051= 0 since

119891(1199051) gt 0If 0 lt 119905

lowast

1le 1205831 for this 119905lowast

1 we have

11988921198621(1199051)

1198891199052

1

1003816100381610038161003816100381610038161003816100381610038161199051=119905lowast

1

= 119891 (119905lowast

1)119889ℎ (119905lowast

1)

119879119889119905lowast

1

gt 0 (32)

which means that the total average cost 1198621(1199051) can obtain its

minimum value at 119905lowast1

The optimal value of the order level 119878 = 119868(0) is

119878lowast= int

119905lowast

1

0

119891 (119909) 119890120572119909120573

119889119909 (33)

and the optimal order quantity 119876lowast is

119876lowast= 119878lowast+ int

1205831

119905lowast

1

119890120575(119905minus119879)

119891 (119905) 119889119905

+ 1198630int

1205832

1205831

119890120575(119905minus119879)

119889119905 + int

119879

1205832

119890120575(119905minus119879)

119892 (119905) 119889119905

(34)

If 119905lowast1

ge 1205831 then the optimal value of 119862

1(1199051) is obtained at

1199051= 1205831

If 1205831lt 1199051le 1205832 taking the first-order and second-order

derivative of 1198622(1199051) with respect to 119905

1 respectively we obtain

1198891198622(1199051)

1198891199051

=1198630

119879ℎ (1199051) (35)

If 1205831lt 119905lowast

1le 1205832 for this 119905lowast

1 we have

11988921198622(1199051)

1198891199052

1

1003816100381610038161003816100381610038161003816100381610038161199051=119905lowast

1

= 1198630

119889ℎ (119905lowast

1)

119879119889119905lowast

1

gt 0 (36)

where the function ℎ(1199051) is given by (31) and (36) implies

that 1198622(1199051) is a strictly convex function in 119905

1and obtained its

minimum value at 119905lowast1 Therefore the equation ℎ(119905

1) = 0 has a

unique root 119905lowast1in (0 119879)

The optimal value of the order level 119878 = 119868(0) is

119878lowast= int

1205831

0

119891 (119909) 119890120572119909120573

119889119909 + 1198630int

119905lowast

1

1205831

119890120572119909120573

119889119909 (37)

and the optimal order quantity 119876lowast is

119876lowast= 119878lowast+ int

1205832

119905lowast

1

119890120575(119905minus119879)

1198630119889119905 + int

119879

1205832

119890120575(119905minus119879)

119892 (119905) 119889119905 (38)

Journal of Applied Mathematics 7

If 119905lowast1le 1205831 then the optimal value of 119862

2(1199051) is obtained at

119905lowast

1= 1205831 and if 119905lowast

1ge 1205832 then the optimal value of 119862

2(1199051) is

obtained at 119905lowast1= 1205832

If 1205832lt 1199051le 119879 taking the first-order and second-order

derivative of 1198623(1199051) with respect to 119905

1 respectively we obtain

1198891198623(1199051)

1198891199051

=119892 (1199051)

119879ℎ (1199051) (39)

If 1205832lt 119905lowast

1le 119879 for this 119905lowast

1 we have

11988921198623(1199051)

1198891199052

1

1003816100381610038161003816100381610038161003816100381610038161199051=119905lowast

1

= 119892 (119905lowast

1)119889ℎ (119905lowast

1)

119879119889119905lowast

1

gt 0 (40)

The function ℎ(1199051) is given by (31) and (40) implies that

1198623(1199051) can obtain its minimum value at 119905lowast

1

The optimal value of the order level 119878 = 119868(0) is

119878lowast= int

1205831

0

119890120572119909120573

119891 (119909) 119889119909 + 1198630int

1205832

1205831

119890120572119909120573

119889119909 + int

119905lowast

1

1205832

119890120572119909120573

119892 (119909) 119889119909

(41)

and the optimal order quantity 119876lowast is

119876lowast= 119878lowast+ int

119879

119905lowast

1

119890120575(119905minus119879)

119892 (119905) 119889119905 (42)

If 119905lowast1

le 1205832 then the optimal value of 119862

3(1199051) is obtained at

119905lowast

1= 1205832

The above analysis shows that the three average cost func-tions 119862

1(1199051) 1198622(1199052) and 119862

3(1199051) can obtain their minimum

value at 119905lowast1isin (0 119879) which is determined by (31) Therefore

based on the results analyzed above this paper derives aprocedure to locate the optimal replenishment policy startingwith no shortage for the three cases The procedure is asfollowsStep 1 Solve 119905lowast

1from (31)

Step 2 Compare 119905lowast1to 1205831and 120583

2 respectively

Step 21 If 119905lowast1isin (0 120583

1] then the optimal total average cost and

the optimal order quantity can be obtained by (10) and (34)respectivelyStep 22 If 119905lowast

1isin (1205831 1205832] then the optimal total average cost

and the optimal order quantity can be obtained by (18) and(38) respectively

Step 23 If 119905lowast1isin (1205832 119879] then the optimal total average cost

and the optimal order quantity can be obtained by (26) and(42) respectively

Remark 1 In such considered inventory model starting withno shortage if 119905

1satisfies 120583

1lt 1199051le 119879 lt 120583

2 the considered

inventory model reduces to that of Skouri et al [12]

4 Numerical Example

In order to demonstrate the above procedure which can beapplied to obtain the optimal solution of the model this

paper presents several examples for the model respectivelyExamples are based on piecewise demand rate such as119891(119905) =1198861+ 1198871119905 and 119892(119905) = 119886

2119890minus1198872119905

Example 1 The parameter values are given as follows 119879 = 12

weeks1205831= 4weeks120583

2= 8weeks120572 = 0005120573 = 2120575 = 004

1198861= 30 unit 119887

1= 5 unit 119886

2= 100 unit 119860

0= $500 119888

1= $2

1198882= $3 119888

3= $12 and 119888

4= $8

The model starting with no shortage by solving theequation ℎ(119905

1) = 0 we have 119905

lowast

1= 87622 From (42) and

(26) we obtain 119876lowast

= 5825217 and 119879119862(119905lowast

1) = 7939986

respectively

Example 2 Theparameter values are given as follows119879 = 12

weeks1205831= 4weeks120583

2= 8weeks120572 = 0005120573 = 2120575 = 002

1198861= 30 unit 119887

1= 5 unit 119886

2= 100 unit 119860

0= $500 119888

1= $5

1198882= $10 119888

3= $12 and 119888

4= $8

The model starting with no shortage by solving theequation ℎ(119905

1) = 0 we have 119905

lowast

1= 58330 From (38) and

(18) we obtain 119876lowast

= 5284725 and 119879119862(119905lowast

1) = 16014013

respectively

Example 3 Theparameter values are given as follows119879 = 12

weeks 1205831= 4 weeks 120583

2= 6 weeks 120572 = 0005 120573 = 16

120575 = 02 1198861= 30 unit 119887

1= 5 unit 119886

2= 100 unit 119860

0= $500

1198881= $5 119888

2= $10 119888

3= $12 and 119888

4= $8

Themodel starting with no shortage solving the equationℎ(1199051) = 0 the optimal value of 119905

1is 119905lowast1= 23235 The optimal

ordering quantity is 119876lowast = 2726678 and the minimum cost119879119862(119905lowast

1) = 125882

In order to clearly indicate the effects of parameters suchas 120575 120572 120573 119888

1 1198882 1198883 and 119888

4on the optimal on-hand inventory

119878lowast the optimal ordering quantity 119876

lowast and the optimal totalcost 119879119862(119905lowast

1) respectively the paper will study the sensitivity

of the optimal solution to changes in the value of differentparameter associated with the studied inventory model Thesensitivity analysis is performed on the base of Example 1 andthe results are shown in Table 1ndash7

By studying the results of Table 1 it is found that theshortage time 119905

lowast

1 inventory level 119878

lowast order quantity 119876lowast

and the total average cost 119879119862(119905lowast1) gradually decrease as the

shortage parameter 120575 increases for the model respectivelyWe also find that the percentage increase of 120575 from 143to 100 causes 119879119862(119905

lowast

1) to decrease from 045 to 034

119876lowast decrease from 075 to 052 119905lowast

1decrease from 078

to 053 and 119878lowast decrease from 102 to 069 It is also

observed that the value of 119905lowast1 119878lowast119876lowast and 119879119862(119905lowast

1) all are lowly

sensitive to the changes of 120575 for the considered inventorymodel

By studying the results of Table 2 it is found that 119878lowast 119876lowastand 119879119862(119905lowast

1) coordinates to the deterioration parameter 120572 the

shortage time 119905lowast1decreases as 120572 increases for the model It is

also found that the percentage increase of 120572 from 167 to100 causes 119879119862(119905lowast

1) to decrease by 2066ndash2595 119876lowast to

increase by 1597ndash244 the shortage time 119905lowast1to decrease

by 1513ndash1455 and 119878lowast to increase by 0917ndash1651 It

also observes that the value of 119905lowast1 119878lowast 119876lowast and 119879119862(119905

lowast

1) all are

moderately sensitive to the changes of 120572 for the consideredinventory model

8 Journal of Applied Mathematics

Table 1 The sensitivity of 120575 for the models in Example 1

120575 0 001 002 003 004 005 006 007 008119905lowast

189664 89187 88689 88167 87622 87049 86449 85817 85152

119878lowast 4729889 4697083 4662823 4627001 4589498 4550167 4508910 4465519 4419829119876lowast 5956569 5925872 5893822 5860308 5825217 5788412 5749771 5709112 5666265

TC(119905lowast1) 8056323 8028699 8000139 7970588 7939986 7908268 7875365 7841200 7805690

Table 2 The sensitivity of 120572 for the models in Example 1

120572 0 0001 0002 0003 0004 0005 0006 0007119905lowast

194545 93115 91702 90312 88950 87622 86328 85072

119878lowast 4283286 4354002 4420048 4481317 4537785 4589498 4636555 4679088119876lowast 5238866 5366685 5489558 5607091 5719025 5825217 5925618 6020259

TC(119905lowast1) 7046045 7228867 7410107 7589297 7766035 7939986 8110872 8278474

Table 3 The sensitivity of 120573 for the models in Example 1

120573 14 16 18 20 22 24 26 28119905lowast

192876 91810 90142 87622 84047 79422 74073 68496

119878lowast 4429058 4475894 4531802 4589076 4628345 4616422 4534686 4388904119876lowast 5451340 5541055 5664485 5824772 6012274 7746099 7664364 7518582

TC(119905lowast1) 7457703 7643043 7917624 7907114 8293653 5887417 4731282 3911266

Table 4 The sensitivity of 1198881for the models in Example 1

1198881

0 04 1 16 2 24 26 3 36119905lowast

188225 88103 87921 87741 87622 87503 87443 87326 87150

119878lowast 4630980 4622595 4610101 4597707 4589498 4581333 4577266 4569164 4557090119876lowast 5841909 5838529 5833499 5828514 5825217 5821940 5825217 5817061 5812226

TC(119905lowast1) 7835429 7856518 7887984 7919251 7939986 7960633 7970925 7991443 8022061

Table 5 The sensitivity of 1198882for the model in Example 1

1198882

0 04 08 12 18 24 3 34 38119905lowast

1118343 11267 107698 10326 97377 92216 87622 84819 82196

119878lowast 6737217 6330852 5979589 5669228 5261187 4905382 4589498 4396922 4216606119876lowast 6796039 6594483 6427261 6284787 6104744 5954175 5825217 5748648 5678284

TC(119905lowast1) 672679 1939216 3088975 4139636 5558150 6816692 7939986 8623253 9259516

Table 6 The sensitivity of 1198883for the models in Example 1

1198883

104 106 108 11 112 116 12 124 128119905lowast

184424 84859 85284 85698 86102 86879 87622 88329 89005

119878lowast 4369771 4399713 442889 4457332 4485071 453854 4589498 4638114 4684587119876lowast 5737973 5749747 5761255 5772506 5783509 5804809 5825217 5844787 5863587

TC(119905lowast1) 7638057 7679203 7719299 7758387 7796505 7869976 7939986 8006779 8070579

Table 7 The sensitivity of 1198884for the models in Example 1

1198884

0 2 4 6 8 10 12 14 16119905lowast

186989 87150 87309 87466 87622 87775 87928 88078 882272

119878lowast 4546069 4557103 4568017 4578815 4589498 4600048 4610527 4620877 4631120119876lowast 5807818 5812231 5816601 5820929 5825217 5829455 583367 5837837 5841966

TC(119905lowast1) 7881626 7896445 7911109 7925621 7939986 7954203 7968276 7982207 7995999

Journal of Applied Mathematics 9

By studying the results of Table 3 it is found that 119878lowast119876lowast and 119879119862(119905

lowast

1) coordinate to the deterioration parameter 120573

while the shortage time 119905lowast

1decreases as 120573 increases for the

model It is also found that the increase of 120573 from 14 to 22causes 119878

lowast to increase while the increase of 120573 from 24 to28 causes 119878lowast to decrease 119876lowast to increase by 244ndash1597119879119862(119905lowast

1) to increase by 2595ndash2066 and the shortage time

119905lowast

1to decrease by 1513ndash1455 It is also observed that the

value of 119905lowast1 119878lowast119876lowast and 119879119862(119905lowast

1) all are moderately sensitive to

the changes of 120573 for the considered inventory modelBy studying the results of Table 4 it is found that 119879119862(119905lowast

1)

coordinate to 1198881 while the shortage time 119905

lowast

1 119878lowast and 119876

lowast

decrease as 1198881increases for the model It is also found that 119888

1

increases from 83 to 150 119879119862(119905lowast1) decreases by 0269ndash

0383 119876lowast decreases by 0083ndash0058 119905lowast1decreases by

0264ndash0181 and 119878lowast decreases by 0203ndash0138 respec-tively It is also observed that the values of 119905lowast

1 119878lowast 119876lowast and

119879119862(119905lowast

1) all are lowly sensitive to the changes of 119888

1for the

considered inventory modelBy studying the results of Table 5 it is found that

119879119862(119905lowast

1) coordinates to 119888

2 while 119878

lowast 119876lowastand 119905lowast

1decrease as

1198881increases for the model It is also found that 119888

2increases

by 100 119879119862(119905lowast1) decreases by 0269ndash0383 119876lowast decreases

by 0083ndash0058 119905lowast1decreases by 0264ndash0181 and 119878

lowast

decreases by 0203ndash0138By studying the results of Table 6 it is found that 119905lowast

1 119878lowast

119876lowast and 119879119862(119905

lowast

1) coordinate to 119888

3 It is also observed that the

value of 119905lowast1 119878lowast 119876lowast and 119879119862(119905

lowast

1) all are lowly sensitive to the

changes of 1198883for the inventory models that is 119888

3increases

from 19 to 32 the change of all the parameters is nomorethan 1

By studying the results of Table 7 it is found that 119905lowast1 119878lowast

119876lowast and 119879119862(119905

lowast

1) coordinate to 119888

4 It is also observed that the

value of 119905lowast1 119878lowast 119876lowast and 119879119862(119905

lowast

1) all are lowly sensitive to the

changes of 1198884for the inventory models that is 119888

4increases

from 143 to 100 the change of all the parameters is nomore than 1

5 Conclusion

An inventory model starting without shortage for Weibull-distributed deterioration with trapezoidal type demand rateand partial backlogging is considered in this paper Theoptimal replenishment policy for the inventory model isproposed and numerical examples are provided to illustratethe theoretical results A sensitivity analysis of the optimalsolution with respect to major parameters is also carried outFrom Table 1ndash7 it can be found that the shortage time point119905lowast

1 order quantity 119876lowast and the total average cost 119879119862(119905lowast

1) are

moderately sensitive to the changes of 120572 and 120573 and lowlysensitive to the changes of 120575 119888

119894(119894 = 1 2 3 4) respectively

The paper provides an interesting topic for further studysuch that the joint influence from some of these parametersmay be investigated to show the effects the model startingwith shortage will be studied and other types of models fordeteriorating items in supply chain situation are also to bestudied in the future

Conflict of Interests

The author declares that there is no conflict of interestsregarding the publication of this paper

Acknowledgments

The author is grateful to the anonymous referees who pro-vided valuable comments and suggestions to significantlyimprove the quality of the paper This work was supportedpartly byHumanities and Social Science Fund of theMinistryof Education of China (no 11YJCZH019)

References

[1] P M Ghare and G F Schrader ldquoA model for exponentiallydecaying inventoriesrdquo Journal of Industrial Engineering vol 14pp 238ndash243 1963

[2] J-W Wu C Lin B Tan and W-C Lee ldquoAn EOQ inventorymodel with time-varying demand and Weibull deteriorationwith shortagesrdquo International Journal of Systems Science vol 31no 6 pp 677ndash683 2000

[3] H-M Wee ldquoDeteriorating inventory model with quantity dis-count pricing and partial backorderingrdquo International Journalof Production Economics vol 59 no 1 pp 511ndash518 1999

[4] K Skouri and S Papachristos ldquoA continuous review inven-tory model with deteriorating items time-varying demandlinear replenishment cost partially time-varying backloggingrdquoApplied Mathematical Modelling vol 26 no 5 pp 603ndash6172002

[5] H-MWee J C P Yu and S T Law ldquoTwo-warehouse inventorymodel with partial backordering and Weibull distributiondeterioration under inflationrdquo Journal of the Chinese Institute ofIndustrial Engineers vol 22 no 6 pp 451ndash462 2005

[6] C-Y Dye T-P Hsieh and L-Y Ouyang ldquoDetermining optimalselling price and lot size with a varying rate of deteriorationand exponential partial backloggingrdquo European Journal ofOperational Research vol 181 no 2 pp 668ndash678 2007

[7] R M Hill ldquoInventory models for increasing demand followedby level demandrdquo Journal of the Operational Research Societyvol 46 no 10 pp 1250ndash1259 1995

[8] B Mandal and A K Pal ldquoOrder level inventory system withramp type demand rate for deteriorating itemsrdquo Journal ofInterdisciplinary Mathematics vol 1 no 1 pp 49ndash66 1998

[9] K-S Wu ldquoAn EOQ inventory model for items with Weibulldistribution deterioration ramp type demand rate and partialbackloggingrdquo Production Planning amp Control vol 12 no 8 pp787ndash793 2001

[10] B C Giri A K Jalan and K S Chaudhuri ldquoEconomic orderquantity model with Weibull deterioration distribution short-age and ramp-type demandrdquo International Journal of SystemsScience vol 34 no 4 pp 237ndash243 2003

[11] S K Manna and K S Chaudhuri ldquoAn EOQ model withramp type demand rate time dependent deterioration rate unitproduction cost and shortagesrdquoEuropean Journal ofOperationalResearch vol 171 no 2 pp 557ndash566 2006

[12] K Skouri I Konstantaras S Papachristos and I Ganas ldquoInven-tory models with ramp type demand rate partial backloggingandWeibull deterioration raterdquoEuropean Journal ofOperationalResearch vol 192 no 1 pp 79ndash92 2009

10 Journal of Applied Mathematics

[13] K-C Hung ldquoAn inventory model with generalized typedemand deterioration and backorder ratesrdquo European Journalof Operational Research vol 208 no 3 pp 239ndash242 2011

[14] R S Kumar S K De and A Goswami ldquoFuzzy EOQ modelswith ramp type demand rate partial backlogging and timedependent deterioration raterdquo International Journal of Mathe-matics in Operational Research vol 4 no 5 pp 473ndash502 2012

[15] M B Cheng B X Zhang and G QWang ldquoOptimal policy fordeteriorating items with trapezoidal type demand and partialbackloggingrdquoAppliedMathematical Modelling vol 35 no 7 pp3552ndash3560 2011

[16] R Uthayakumar and M Rameswari ldquoAn economic produc-tion quantity model for defective items with trapezoidal typedemand raterdquo Journal of Optimization Theory and Applicationsvol 154 no 3 pp 1055ndash1079 2012

[17] Y Tan and M X Weng ldquoA discrete-in-time deterioratinginventory model with time-varying demand variable deterio-ration rate and waiting-time-dependent partial backloggingrdquoInternational Journal of Systems Science vol 44 no 8 pp 1483ndash1493 2013

[18] M A Ahmed T A Al-Khamis and L Benkherouf ldquoInventorymodels with ramp type demand rate partial backlogging andgeneral deterioration raterdquo Applied Mathematics and Computa-tion vol 219 no 9 pp 4288ndash4307 2013

[19] K-P Lin ldquoAn extended inventory models with trapezoidal typedemandsrdquo Applied Mathematics and Computation vol 219 no24 pp 11414ndash11419 2013

[20] P L Abad ldquoOptimal pricing and lot-sizing under conditionsof perishability and partial backorderingrdquoManagement Sciencevol 42 no 8 pp 1093ndash1104 1996

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Page 2: Research Article An Inventory Model under Trapezoidal Type ...downloads.hindawi.com/journals/jam/2014/747419.pdf · an inventory model with Weibull-distributed deterioration items,

2 Journal of Applied Mathematics

finding the economic order quantity for an inventory modelwith ramp type demand rate partial backlogging and generaldeterioration rate Lin [19] explored the inventorymodel witha general demand rate in which both the Weibull-distributeddeterioration and partial backlogging are considered

In the above mentioned research one of assumptionswas considered the ramp type demand rate partial back-logging andWeibull-distributed deterioration rateHoweverfor fashionable commodities high-tech products and othershort life cycle products the demand rate should increasewith the time up to certain point at first stage then reacha stabilized period and finally the demand rate decreaseto zero and the products retreat from market in theirproduct life cycle that is the demand rate with continuoustrapezoidal function of time On the other hand inmany realsituations customers encountering shortages will responddifferently Some customers are willing to wait until thenext replenishment while others may be impatient and goelsewhere as waiting time increases that is the willingnessfor a customer to wait for backlogging is diminishing withthe length of the waiting time In this paper we consideran inventory model with Weibull-distributed deteriorationitems trapezoidal type demand rate and time-dependentpartial backlogging By analyzing the inventory model auseful inventory replenishment policy is proposed Finallynumerical examples are provided to illustrate the theoreticalresults and a sensitivity analysis of the optimal solution withrespect to major parameters is also carried out

The rest of the paper is organized as follows Section 2describes the notation and assumptions used throughout thispaper Section 3 analyzes the inventory model and somenumerical examples to illustrate the solution procedure areprovided Sensitivity analysis of the major parameters is alsocarried out in Section 4 and the final Section concludes thispaper

2 Notations and Assumptions

The fundamental notations and assumptions used in inven-tory model and considered in this paper are given as below

(i) 119868(119905) the level of inventory at time 119905 0 le 119905 le 119879(ii) 119879 the fixed length of each ordering cycle(iii) 1199051the time when the inventory level reaches zero for

the inventory model(iv) 119905lowast1the optimal point

(v) 119878 the maximum inventory level for each orderingcycle

(vi) 119876lowast the optimal ordering quantity(vii) 119860

0the fixed cost per order

(viii) 1198881the cost of each deteriorated item

(ix) 1198882the inventory holding cost per unit per unit of time

(x) 1198883the shortage cost per unit per unit of time

(xi) 1198884the lost sales cost per unit

(xii) 119862119894(1199051) 119894 = 1 2 3 the average total cost per unit time

under different conditions respectively

(xiii) 119879119862(1199051) the average total cost per unit time

(xiv) The demand rate 119863(119905) which is positive and consec-utive is assumed to be a trapezoidal type function oftime that is

119863 (119905) =

119891 (119905) 119905 le 1205831

1198630 120583

1lt 119905 lt 120583

2

119892 (119905) 1205832le 119905 lt 119879

(1)

where 1205831is time point changing from the increasing

demand function119891(119905) to constant demand1198630 and 120583

2

is time point changing from the constant demand1198630

to the decreasing demand function 119892(119905)(xv) The replenishment rate is infinite that is replenish-

ment is instantaneous(xvi) The deterioration rate of the item is defined as

Weibull (120572 120573) that is the deterioration rate is 120579(119905) =120572120573119905120573minus1

(120572 gt 0 120573 gt 0 119905 gt 0)(xvii) Shortages are allowed and they adopt the notation

used in Abad [20] where the unsatisfied demandis backlogged and the fraction of shortages backo-rdered is 119890minus120575119905 where 119905 is the waiting time up to thenext replenishment We also assume that 119905119890minus120575119905 is anincreasing function which had appeared in Skouri etal [12]

(xviii) The time horizon of the inventory model is finite

3 Model Formulation

In this section we consider an inventory model startingwith no shortage The behavior of the model during a givencycle is depicted in Figure 1 Replenishment occurs at time119905 = 0 and the inventory level attains its maximum From119905 = 0 to 119905

1 the inventory level reduces due to demand

and deterioration At 1199051 the inventory level achieves zero

then shortage is allowed to occur during the time interval(1199051 119879) and all of the demand during the shortage period

(1199051 119879) is partially backlogged According to the notations and

assumptions mentioned above the behavior of the modelat any time can be described by the following differentialequations

119889119868 (119905)

119889119905=

minus120579 (119905) 119868 (119905) minus 119863 (119905) 0 lt 119905 lt 1199051

minus119890minus120575(119879minus119905)

119863 (119905) 1199051lt 119905 lt 119879

(2)

with boundary conditions 119868(0) = 119878 119868(1199051) = 0

In the following we consider three possible cases basedon the values of 119905

1 1205831 and 120583

2 These three cases are shown

Case 1 (0 lt 1199051le 1205831) Due to the deteriorating and trapezoidal

type demand rate the inventory level gradually diminishesduring the time interval [0 119905

1] and ultimately falls to zero at

time 1199051 Thus from (2) we have

119889119868 (119905)

119889119905=

minus120572120573119905120573minus1

119868 (119905) minus 119891 (119905) 0 lt 119905 lt 1199051

minus119890minus120575(119879minus119905)

119891 (119905) 1199051lt 119905 lt 120583

1

minus119890minus120575(119879minus119905)

1198630 120583

1lt 119905 lt 120583

2

minus119890minus120575(119879minus119905)

119892 (119905) 1205832lt 119905 lt 119879

(3)

Journal of Applied Mathematics 3

0

S

Inventorylevel

TimeT

0

S

Inventorylevel

TimeT

0

S

Inventorylevel

TimeT1205831

t1

1205832 t11205831

1205832 t11205831 1205832

Case 1 0 lt t1 le 1205831 Case 2 1205831 le t1 le 1205832 Case 3 1205832 le t1 lt T

Figure 1 Graphical representation of inventory level over the cycle

By using the boundary condition 119868(1199051) = 0 the solutions of

(3) are given by

119868 (119905) =

int

1199051

119905

119891 (119909) 119890120572(119909120573minus119905120573)119889119909 0 lt 119905 lt 119905

1

minusint

119905

1199051

119890120575(119909minus119879)

119891 (119909) 119889119909 1199051lt 119905 lt 120583

1

1198630

120575(119890120575(1205831minus119879)

minus 119890120575(119905minus119879)

)

minusint

1205831

1199051

119890120575(119909minus119879)

119891 (119909) 119889119909 1205831lt 119905 lt 120583

2

minusint

119905

1205832

119892 (119909) 119890120575(119909minus119879)

119889119909

+1198630

120575(119890120575(1205831minus119879)

minus 119890120575(1205832minus119879)

)

minusint

1205831

1199051

119890120575(119909minus119879)

119891 (119909) 119889119909 1205832lt 119905 lt 119879

(4)

The maximum inventory level per cycle is

119878 = 119868 (0) = int

1199051

0

119891 (119909) 119890120572119909120573

119889119909 (5)

Then the total number of deteriorated items 119863119879in the

interval [0 1199051] is

119863119879= 119878 minus int

1199051

0

119863 (119905) 119889119905 = int

1199051

0

119891 (119909) (119890120572119909120573

minus 1) 119889119909 (6)

The total number of inventory119867119879carried during the interval

[0 1199051] is

119867119879= int

1199051

0

119868 (119905) 119889119905 = int

1199051

0

int

1199051

119905

119891 (119909) 119890120572(119909120573minus119905120573)119889119909 119889119905 (7)

The total shortage quantity 119861119879during the interval [119905

1 119879] is

119861119879= minusint

119879

1199051

119868 (119905) 119889119905

= int

1205831

1199051

[int

119905

1199051

119890120575(119909minus119879)

119891 (119909) 119889119909] 119889119905

minus int

1205832

1205831

[1198630

120575(119890120575(1205831minus119879)

minus 119890120575(119905minus119879)

)

minusint

1205831

1199051

119890120575(119909minus119879)

119891 (119909) 119889119909] 119889119905

+ int

119879

1205832

[int

119905

1205832

119890120575(119909minus119879)

119892 (119909) 119889119909

minus1198630

120575(119890120575(1205831minus119879)

minus 119890120575(1205832minus119879)

)

+int

1205831

1199051

119890120575(119909minus119879)

119891 (119909) 119889119909] 119889119905

= int

1205831

1199051

(119879 minus 119905) 119890120575(119905minus119879)

119891 (119905) 119889119905

+ int

119879

1205832

(119879 minus 119905) 119890120575(119905minus119879)

119892 (119905) 119889119905

+1198630

1205752(119890120575(1205832minus119879)

minus 119890120575(1205831minus119879)

)

+1198630

120575[(119879 minus 120583

2) 119890120575(1205832minus119879)

minus (119879 minus 1205831) 119890120575(1205831minus119879)

]

(8)

The total of lost sales 119871119879during the interval [119905

1 119879] is

119871119879= int

1205831

1199051

(1 minus 119890120575(119905minus119879)

) 119891 (119905) 119889119905 + int

1205832

1205831

(1 minus 119890120575(119905minus119879)

)1198630119889119905

+ int

119879

1205832

(1 minus 119890120575(119905minus119879)

) 119892 (119905) 119889119905

(9)

4 Journal of Applied Mathematics

Therefore the average total cost per unit time under thecondition 119905

1le 1205831can be given by

1198621(1199051) =

1

119879[1198600+ 1198881119863119879+ 1198882119867119879+ 1198883119861119879+ 1198884119871119879]

=1

1198791198600+ 1198881int

1199051

0

119891 (119909) (119890120572119909120573

minus 1) 119889119909

+ 1198882int

1199051

0

int

1199051

119905

119891 (119909) 119890120572(119909120573minus119905120573)119889119909 119889119905

+ 1198884[int

1205831

1199051

(1 minus 119890120575(119905minus119879)

) 119891 (119905) 119889119905

+ int

1205832

1205831

(1 minus 119890120575(119905minus119879)

)1198630119889119905

+int

119879

1205832

(1 minus 119890120575(119905minus119879)

) 119892 (119905) 119889119905]

+ 1198883[int

1205831

1199051

119890120575(119905minus119879)

(119879 minus 119905) 119891 (119905) 119889119905

+ int

119879

1205832

119890120575(119905minus119879)

(119879 minus 119905) 119892 (119905) 119889119905

+1198630

1205752(119890120575(1205832minus119879)

minus 119890120575(1205831minus119879)

)

+1198630

120575((119879 minus 120583

2) 119890120575(1205832minus119879)

minus (119879 minus 1205831) 119890120575(1205831minus119879)

) ]

(10)

Case 2 (1205831le 1199051le 1205832) The differential equations governing

the inventory model can be expressed as follows

119889119868 (119905)

119889119905=

minus120572120573119905120573minus1

119868 (119905) minus 119891 (119905) 0 lt 119905 lt 1205831

minus120572120573119905120573minus1

119868 (119905) minus 1198630 120583

1lt 119905 lt 119905

1

minus119890minus120575(119879minus119905)

1198630 119905

1lt 119905 lt 120583

2

minus119890minus120575(119879minus119905)

119892 (119905) 1205832lt 119905 lt 119879

(11)

Solving the differential equation (11) with 119868(1199051) = 0 we have

119868 (119905) =

int

1205831

119905

119891 (119909) 119890120572(119909120573minus119905120573)119889119909

+1198630int

1199051

1205831

119890120572(119909120573minus119905120573)119889119909 0 lt 119905 lt 120583

1

1198630int

1199051

119905

119890120572(119909120573minus119905120573)119889119909 120583

1lt 119905 lt 119905

1

1198630

120575(119890120575(1199051minus119879)

minus 119890120575(119905minus119879)

) 1199051lt 119905 lt 120583

2

minusint

119905

1205832

119890120575(119909minus119879)

119892 (119909) 119889119909

+1198630

120575(119890120575(1199051minus119879)

minus 119890120575(1205832minus119879)

) 1205832lt 119905 lt 119879

(12)

The beginning inventory level can be computed as

119878 = 119868 (0) = int

1205831

0

119891 (119909) 119890120572119909120573

119889119909 + 1198630int

1199051

1205831

119890120572119909120573

119889119909 (13)

The total number of items which perish in the interval [0 1199051]

is

119863119879= int

1205831

0

119891 (119909) (119890120572119909120573

minus 1) 119889119909 + 1198630int

1199051

1205831

(119890120572119909120573

minus 1) 119889119909 (14)

The total number of inventory carried during the interval[0 1199051] is

119867119879= int

1205831

0

int

1205831

119905

119890120572(119909120573minus119905120573)119891 (119909) 119889119909 119889119905 + 119863

0int

1199051

1205831

int

1199051

119905

119890120572(119909120573minus119905120573)119889119909 119889119905

(15)

The total shortage quantity during the interval [1199051 119879] is

119861119879= int

119879

1205832

(119879 minus 119905) 119890120575(119905minus119879)

119892 (119905) 119889119905

+1198630

120575[119890120575(1199051minus119879)

(119879 minus 1199051+1

120575)

minus119890minus120575(1205832minus119879)

(119879 minus 1205832+1

120575)]

(16)

The total of lost sales during the interval [1199051 119879] is

119871119879= 1198630int

1205832

1199051

(1 minus 119890120575(119905minus119879)

) 119889119905 + int

119879

1205832

(1 minus 119890120575(119905minus119879)

) 119892 (119905) 119889119905

(17)

Therefore the average total cost per unit time under thecondition 120583

1le 1199051le 1205832can be given by

1198622(1199051) =

1

119879[1198600+ 1198881119863119879+ 1198882119867119879+ 1198883119861119879+ 1198884119871119879]

=1

1198791198600+ 1198881[int

1205831

0

119891 (119909) (119890120572119909120573

minus 1) 119889119909

+1198630int

1199051

1205831

(119890120572119909120573

minus 1) 119889119909]

+ 1198882[int

1205831

0

int

1205831

119905

119890120572(119909120573minus119905120573)119891 (119909) 119889119909 119889119905

+1198630int

1199051

0

int

1199051

119905

119890120572(119909120573minus119905120573)119889119909 119889119905]

Journal of Applied Mathematics 5

+ 1198883[int

119879

1205832

(119879 minus 119905) 119890120575(119905minus119879)

119892 (119905) 119889119905

+1198630

120575(119890120575(1199051minus119879)

(119879 minus 1199051+1

120575)

minus119890120575(1205832minus119879)

(119879 minus 1205832+1

120575)) ]

+ 1198884[1198630int

1205832

1199051

(1 minus 119890120575(119905minus119879)

) 119889119905

+int

119879

1205832

(1 minus 119890120575(119905minus119879)

) 119892 (119905) 119889119905]

(18)

Case 3 (1205832le 1199051lt 119879) The differential equations governing

the inventory model can be expressed as follows

119889119868 (119905)

119889119905=

minus120572120573119905120573minus1

119868 (119905) minus 119891 (119905) 0 lt 119905 lt 1205831

minus120572120573119905120573minus1

119868 (119905) minus 1198630 120583

1lt 119905 lt 120583

2

minus120572120573119905120573minus1

119868 (119905) minus 119892 (119905) 1205832lt 119905 lt 119905

1

minus119890minus120575(119879minus119905)

119892 (119905) 1199051lt 119905 lt 119879

(19)

Solving the differential equation (19) with 119868(1199051) = 0 we have

119868 (119905) =

int

1205831

119905

119890120572(119909120573minus119905120573)119891 (119909) 119889119909 + 119863

0int

1205832

1205831

119890120572(119909120573minus119905120573)119889119909 + int

1199051

1205832

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 0 lt 119905 lt 120583

1

1198630int

1205832

119905

119890120572(119909120573minus119905120573)119889119909 + int

1199051

1205832

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 120583

1lt 119905 lt 120583

2

int

1199051

119905

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 120583

2lt 119905 lt 119905

1

minusint

119905

1199051

119890120575(119909minus119879)

119892 (119909) 119889119909 1199051lt 119905 lt 119879

(20)

The beginning inventory level can be computed as

119878 = 119868 (0)

= int

1205831

0

119890120572119909120573

119891 (119909) 119889119909

+ 1198630int

1205832

1205831

119890120572119909120573

119889119909 + int

1199051

1205832

119890120572119909120573

119892 (119909) 119889119909

(21)

The total number of items which perish in the interval [0 1199051]

is

119863119879= int

1205831

0

(119890120572119909120573

minus 1)119891 (119909) 119889119909 + 1198630int

1205832

1205831

(119890120572119909120573

minus 1) 119889119909

+ int

1199051

1205832

(119890120572119909120573

minus 1) 119892 (119909) 119889119909

(22)

The total number of inventory carried during the interval[0 1199051] is

119867119879= int

1205831

0

int

1205831

119905

119890120572(119909120573minus119905120573)119891 (119909) 119889119909 119889119905

+ 1198630int

1205831

0

int

1205832

1205831

119890120572(119909120573minus119905120573)119889119909 119889119905

+ 1198630int

1205832

1205831

int

1205832

119905

119890120572(119909120573minus119905120573)119889119909 119889119905

+ int

1205832

0

int

1199051

1205832

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 119889119905

+ int

1199051

1205832

int

1199051

119905

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 119889119905

(23)

The total shortage quantity during the interval [1199051 119879] is

119861119879= int

119879

1199051

(119879 minus 119905) 119890minus120575(119879minus119905)

119892 (119905) 119889119905 (24)

The total of lost sales during the interval [1199051 119879] is

119871119879= int

119879

1199051

(1 minus 119890minus120575(119879minus119905)

) 119892 (119905) 119889119905 (25)

Therefore the average total cost per unit time under thecondition 120583

2le 1199051le 119879 can be given by

1198623(1199051) =

1

119879[1198600+ 1198881119863119879+ 1198882119867119879+ 1198883119861119879+ 1198884119871119879]

=1

1198791198600+ 1198881[int

1205831

0

(119890120572119909120573

minus 1)119891 (119909) 119889119909

+ 1198630int

1205832

1205831

(119890120572119909120573

minus 1) 119889119909

+int

1199051

1205832

(119890120572119909120573

minus 1) 119892 (119909) 119889119909]

6 Journal of Applied Mathematics

+ 1198882[int

1205831

0

int

1205831

119905

119890120572(119909120573minus119905120573)119891 (119909) 119889119909 119889119905

+ 1198630int

1205831

0

int

1205832

1205831

119890120572(119909120573minus119905120573)119889119909 119889119905

+ 1198630int

1205832

1205831

int

1205832

119905

119890120572(119909120573minus119905120573)119889119909 119889119905

+ int

1205832

0

int

1199051

1205832

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 119889119905

+int

1199051

1205832

int

1199051

119905

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 119889119905]

+ 1198883[int

119879

1199051

(119879 minus 119905) 119890120575(119905minus119879)

119892 (119905) 119889119905]

+ 1198884[int

119879

1199051

(1 minus 119890120575(119905minus119879)

) 119892 (119905) 119889119905]

(26)

From the above analysis we obtain that the total average costof the model over the time interval [0 119879] is

119879119862 (1199051) =

1198621(1199051) 0 lt 119905

1le 1205831

1198622(1199051) 120583

1lt 1199051le 1205832

1198623(1199051) 120583

2lt 1199051lt 119879

(27)

where 1198621(1199051) 1198622(1199051) and 119862

3(1199051) are obtained from (10) (18)

and (26) respectivelyIn the following we will provide the results which ensure

the existence of a unique 1199051 say 119905lowast1 so as to minimize the total

average cost for the model system starting with no shortagesIf 0 lt 119905

1le 1205831 taking the first-order derivative of 119862

1(1199051)

with respect to 1199051 we obtain

1198891198621(1199051)

1198891199051

=119891 (1199051)

119879ℎ (1199051) (28)

where

ℎ (1199051) = 1198881(119890120572119905120573

1 minus 1)

+ 1198882int

1199051

0

119890120572(119905120573

1minus119905120573)119889119905 + 119888

3(1199051minus 119879) 119890

120575(1199051minus119879)

+ 1198884(119890120575(1199051minus119879)

minus 1)

(29)

then we can obtain ℎ(0) lt 0 and ℎ(119879) gt 0 By using theassumption (119905119890minus120575119905 is an increasing function where 119905 is thewaiting time up to the next replenishment) we have

119889ℎ (1199051)

1198891199051

= 120572120573119905120573minus1

1(1198881119890120572119905120573

1 + 1198882int

1199051

0

119890120572(119905120573

1minus119905120573)119889119905)

+ [1198883(120575 (1199051minus 119879) + 1) + 119888

4120575] 119890120575(1199051minus119879)

+ 1198882gt 0

(30)

which implies that ℎ(1199051) is a strictly monotone increasing

function Therefore the equation

ℎ (1199051) = 1198881(119890120572119905120573

1 minus 1) + 1198882int

1199051

0

119890120572(119905120573

1minus119905120573)119889119905

+ 1198883(1199051minus 119879) 119890

120575(1199051minus119879)

+ 1198884(119890120575(1199051minus119879)

minus 1)

= 0

(31)

has a unique root 119905lowast1isin (0 119879) obtained by using Mathematica

90 Further 119905lowast1is the only zero-point of 119889119862

1(1199051)1198891199051= 0 since

119891(1199051) gt 0If 0 lt 119905

lowast

1le 1205831 for this 119905lowast

1 we have

11988921198621(1199051)

1198891199052

1

1003816100381610038161003816100381610038161003816100381610038161199051=119905lowast

1

= 119891 (119905lowast

1)119889ℎ (119905lowast

1)

119879119889119905lowast

1

gt 0 (32)

which means that the total average cost 1198621(1199051) can obtain its

minimum value at 119905lowast1

The optimal value of the order level 119878 = 119868(0) is

119878lowast= int

119905lowast

1

0

119891 (119909) 119890120572119909120573

119889119909 (33)

and the optimal order quantity 119876lowast is

119876lowast= 119878lowast+ int

1205831

119905lowast

1

119890120575(119905minus119879)

119891 (119905) 119889119905

+ 1198630int

1205832

1205831

119890120575(119905minus119879)

119889119905 + int

119879

1205832

119890120575(119905minus119879)

119892 (119905) 119889119905

(34)

If 119905lowast1

ge 1205831 then the optimal value of 119862

1(1199051) is obtained at

1199051= 1205831

If 1205831lt 1199051le 1205832 taking the first-order and second-order

derivative of 1198622(1199051) with respect to 119905

1 respectively we obtain

1198891198622(1199051)

1198891199051

=1198630

119879ℎ (1199051) (35)

If 1205831lt 119905lowast

1le 1205832 for this 119905lowast

1 we have

11988921198622(1199051)

1198891199052

1

1003816100381610038161003816100381610038161003816100381610038161199051=119905lowast

1

= 1198630

119889ℎ (119905lowast

1)

119879119889119905lowast

1

gt 0 (36)

where the function ℎ(1199051) is given by (31) and (36) implies

that 1198622(1199051) is a strictly convex function in 119905

1and obtained its

minimum value at 119905lowast1 Therefore the equation ℎ(119905

1) = 0 has a

unique root 119905lowast1in (0 119879)

The optimal value of the order level 119878 = 119868(0) is

119878lowast= int

1205831

0

119891 (119909) 119890120572119909120573

119889119909 + 1198630int

119905lowast

1

1205831

119890120572119909120573

119889119909 (37)

and the optimal order quantity 119876lowast is

119876lowast= 119878lowast+ int

1205832

119905lowast

1

119890120575(119905minus119879)

1198630119889119905 + int

119879

1205832

119890120575(119905minus119879)

119892 (119905) 119889119905 (38)

Journal of Applied Mathematics 7

If 119905lowast1le 1205831 then the optimal value of 119862

2(1199051) is obtained at

119905lowast

1= 1205831 and if 119905lowast

1ge 1205832 then the optimal value of 119862

2(1199051) is

obtained at 119905lowast1= 1205832

If 1205832lt 1199051le 119879 taking the first-order and second-order

derivative of 1198623(1199051) with respect to 119905

1 respectively we obtain

1198891198623(1199051)

1198891199051

=119892 (1199051)

119879ℎ (1199051) (39)

If 1205832lt 119905lowast

1le 119879 for this 119905lowast

1 we have

11988921198623(1199051)

1198891199052

1

1003816100381610038161003816100381610038161003816100381610038161199051=119905lowast

1

= 119892 (119905lowast

1)119889ℎ (119905lowast

1)

119879119889119905lowast

1

gt 0 (40)

The function ℎ(1199051) is given by (31) and (40) implies that

1198623(1199051) can obtain its minimum value at 119905lowast

1

The optimal value of the order level 119878 = 119868(0) is

119878lowast= int

1205831

0

119890120572119909120573

119891 (119909) 119889119909 + 1198630int

1205832

1205831

119890120572119909120573

119889119909 + int

119905lowast

1

1205832

119890120572119909120573

119892 (119909) 119889119909

(41)

and the optimal order quantity 119876lowast is

119876lowast= 119878lowast+ int

119879

119905lowast

1

119890120575(119905minus119879)

119892 (119905) 119889119905 (42)

If 119905lowast1

le 1205832 then the optimal value of 119862

3(1199051) is obtained at

119905lowast

1= 1205832

The above analysis shows that the three average cost func-tions 119862

1(1199051) 1198622(1199052) and 119862

3(1199051) can obtain their minimum

value at 119905lowast1isin (0 119879) which is determined by (31) Therefore

based on the results analyzed above this paper derives aprocedure to locate the optimal replenishment policy startingwith no shortage for the three cases The procedure is asfollowsStep 1 Solve 119905lowast

1from (31)

Step 2 Compare 119905lowast1to 1205831and 120583

2 respectively

Step 21 If 119905lowast1isin (0 120583

1] then the optimal total average cost and

the optimal order quantity can be obtained by (10) and (34)respectivelyStep 22 If 119905lowast

1isin (1205831 1205832] then the optimal total average cost

and the optimal order quantity can be obtained by (18) and(38) respectively

Step 23 If 119905lowast1isin (1205832 119879] then the optimal total average cost

and the optimal order quantity can be obtained by (26) and(42) respectively

Remark 1 In such considered inventory model starting withno shortage if 119905

1satisfies 120583

1lt 1199051le 119879 lt 120583

2 the considered

inventory model reduces to that of Skouri et al [12]

4 Numerical Example

In order to demonstrate the above procedure which can beapplied to obtain the optimal solution of the model this

paper presents several examples for the model respectivelyExamples are based on piecewise demand rate such as119891(119905) =1198861+ 1198871119905 and 119892(119905) = 119886

2119890minus1198872119905

Example 1 The parameter values are given as follows 119879 = 12

weeks1205831= 4weeks120583

2= 8weeks120572 = 0005120573 = 2120575 = 004

1198861= 30 unit 119887

1= 5 unit 119886

2= 100 unit 119860

0= $500 119888

1= $2

1198882= $3 119888

3= $12 and 119888

4= $8

The model starting with no shortage by solving theequation ℎ(119905

1) = 0 we have 119905

lowast

1= 87622 From (42) and

(26) we obtain 119876lowast

= 5825217 and 119879119862(119905lowast

1) = 7939986

respectively

Example 2 Theparameter values are given as follows119879 = 12

weeks1205831= 4weeks120583

2= 8weeks120572 = 0005120573 = 2120575 = 002

1198861= 30 unit 119887

1= 5 unit 119886

2= 100 unit 119860

0= $500 119888

1= $5

1198882= $10 119888

3= $12 and 119888

4= $8

The model starting with no shortage by solving theequation ℎ(119905

1) = 0 we have 119905

lowast

1= 58330 From (38) and

(18) we obtain 119876lowast

= 5284725 and 119879119862(119905lowast

1) = 16014013

respectively

Example 3 Theparameter values are given as follows119879 = 12

weeks 1205831= 4 weeks 120583

2= 6 weeks 120572 = 0005 120573 = 16

120575 = 02 1198861= 30 unit 119887

1= 5 unit 119886

2= 100 unit 119860

0= $500

1198881= $5 119888

2= $10 119888

3= $12 and 119888

4= $8

Themodel starting with no shortage solving the equationℎ(1199051) = 0 the optimal value of 119905

1is 119905lowast1= 23235 The optimal

ordering quantity is 119876lowast = 2726678 and the minimum cost119879119862(119905lowast

1) = 125882

In order to clearly indicate the effects of parameters suchas 120575 120572 120573 119888

1 1198882 1198883 and 119888

4on the optimal on-hand inventory

119878lowast the optimal ordering quantity 119876

lowast and the optimal totalcost 119879119862(119905lowast

1) respectively the paper will study the sensitivity

of the optimal solution to changes in the value of differentparameter associated with the studied inventory model Thesensitivity analysis is performed on the base of Example 1 andthe results are shown in Table 1ndash7

By studying the results of Table 1 it is found that theshortage time 119905

lowast

1 inventory level 119878

lowast order quantity 119876lowast

and the total average cost 119879119862(119905lowast1) gradually decrease as the

shortage parameter 120575 increases for the model respectivelyWe also find that the percentage increase of 120575 from 143to 100 causes 119879119862(119905

lowast

1) to decrease from 045 to 034

119876lowast decrease from 075 to 052 119905lowast

1decrease from 078

to 053 and 119878lowast decrease from 102 to 069 It is also

observed that the value of 119905lowast1 119878lowast119876lowast and 119879119862(119905lowast

1) all are lowly

sensitive to the changes of 120575 for the considered inventorymodel

By studying the results of Table 2 it is found that 119878lowast 119876lowastand 119879119862(119905lowast

1) coordinates to the deterioration parameter 120572 the

shortage time 119905lowast1decreases as 120572 increases for the model It is

also found that the percentage increase of 120572 from 167 to100 causes 119879119862(119905lowast

1) to decrease by 2066ndash2595 119876lowast to

increase by 1597ndash244 the shortage time 119905lowast1to decrease

by 1513ndash1455 and 119878lowast to increase by 0917ndash1651 It

also observes that the value of 119905lowast1 119878lowast 119876lowast and 119879119862(119905

lowast

1) all are

moderately sensitive to the changes of 120572 for the consideredinventory model

8 Journal of Applied Mathematics

Table 1 The sensitivity of 120575 for the models in Example 1

120575 0 001 002 003 004 005 006 007 008119905lowast

189664 89187 88689 88167 87622 87049 86449 85817 85152

119878lowast 4729889 4697083 4662823 4627001 4589498 4550167 4508910 4465519 4419829119876lowast 5956569 5925872 5893822 5860308 5825217 5788412 5749771 5709112 5666265

TC(119905lowast1) 8056323 8028699 8000139 7970588 7939986 7908268 7875365 7841200 7805690

Table 2 The sensitivity of 120572 for the models in Example 1

120572 0 0001 0002 0003 0004 0005 0006 0007119905lowast

194545 93115 91702 90312 88950 87622 86328 85072

119878lowast 4283286 4354002 4420048 4481317 4537785 4589498 4636555 4679088119876lowast 5238866 5366685 5489558 5607091 5719025 5825217 5925618 6020259

TC(119905lowast1) 7046045 7228867 7410107 7589297 7766035 7939986 8110872 8278474

Table 3 The sensitivity of 120573 for the models in Example 1

120573 14 16 18 20 22 24 26 28119905lowast

192876 91810 90142 87622 84047 79422 74073 68496

119878lowast 4429058 4475894 4531802 4589076 4628345 4616422 4534686 4388904119876lowast 5451340 5541055 5664485 5824772 6012274 7746099 7664364 7518582

TC(119905lowast1) 7457703 7643043 7917624 7907114 8293653 5887417 4731282 3911266

Table 4 The sensitivity of 1198881for the models in Example 1

1198881

0 04 1 16 2 24 26 3 36119905lowast

188225 88103 87921 87741 87622 87503 87443 87326 87150

119878lowast 4630980 4622595 4610101 4597707 4589498 4581333 4577266 4569164 4557090119876lowast 5841909 5838529 5833499 5828514 5825217 5821940 5825217 5817061 5812226

TC(119905lowast1) 7835429 7856518 7887984 7919251 7939986 7960633 7970925 7991443 8022061

Table 5 The sensitivity of 1198882for the model in Example 1

1198882

0 04 08 12 18 24 3 34 38119905lowast

1118343 11267 107698 10326 97377 92216 87622 84819 82196

119878lowast 6737217 6330852 5979589 5669228 5261187 4905382 4589498 4396922 4216606119876lowast 6796039 6594483 6427261 6284787 6104744 5954175 5825217 5748648 5678284

TC(119905lowast1) 672679 1939216 3088975 4139636 5558150 6816692 7939986 8623253 9259516

Table 6 The sensitivity of 1198883for the models in Example 1

1198883

104 106 108 11 112 116 12 124 128119905lowast

184424 84859 85284 85698 86102 86879 87622 88329 89005

119878lowast 4369771 4399713 442889 4457332 4485071 453854 4589498 4638114 4684587119876lowast 5737973 5749747 5761255 5772506 5783509 5804809 5825217 5844787 5863587

TC(119905lowast1) 7638057 7679203 7719299 7758387 7796505 7869976 7939986 8006779 8070579

Table 7 The sensitivity of 1198884for the models in Example 1

1198884

0 2 4 6 8 10 12 14 16119905lowast

186989 87150 87309 87466 87622 87775 87928 88078 882272

119878lowast 4546069 4557103 4568017 4578815 4589498 4600048 4610527 4620877 4631120119876lowast 5807818 5812231 5816601 5820929 5825217 5829455 583367 5837837 5841966

TC(119905lowast1) 7881626 7896445 7911109 7925621 7939986 7954203 7968276 7982207 7995999

Journal of Applied Mathematics 9

By studying the results of Table 3 it is found that 119878lowast119876lowast and 119879119862(119905

lowast

1) coordinate to the deterioration parameter 120573

while the shortage time 119905lowast

1decreases as 120573 increases for the

model It is also found that the increase of 120573 from 14 to 22causes 119878

lowast to increase while the increase of 120573 from 24 to28 causes 119878lowast to decrease 119876lowast to increase by 244ndash1597119879119862(119905lowast

1) to increase by 2595ndash2066 and the shortage time

119905lowast

1to decrease by 1513ndash1455 It is also observed that the

value of 119905lowast1 119878lowast119876lowast and 119879119862(119905lowast

1) all are moderately sensitive to

the changes of 120573 for the considered inventory modelBy studying the results of Table 4 it is found that 119879119862(119905lowast

1)

coordinate to 1198881 while the shortage time 119905

lowast

1 119878lowast and 119876

lowast

decrease as 1198881increases for the model It is also found that 119888

1

increases from 83 to 150 119879119862(119905lowast1) decreases by 0269ndash

0383 119876lowast decreases by 0083ndash0058 119905lowast1decreases by

0264ndash0181 and 119878lowast decreases by 0203ndash0138 respec-tively It is also observed that the values of 119905lowast

1 119878lowast 119876lowast and

119879119862(119905lowast

1) all are lowly sensitive to the changes of 119888

1for the

considered inventory modelBy studying the results of Table 5 it is found that

119879119862(119905lowast

1) coordinates to 119888

2 while 119878

lowast 119876lowastand 119905lowast

1decrease as

1198881increases for the model It is also found that 119888

2increases

by 100 119879119862(119905lowast1) decreases by 0269ndash0383 119876lowast decreases

by 0083ndash0058 119905lowast1decreases by 0264ndash0181 and 119878

lowast

decreases by 0203ndash0138By studying the results of Table 6 it is found that 119905lowast

1 119878lowast

119876lowast and 119879119862(119905

lowast

1) coordinate to 119888

3 It is also observed that the

value of 119905lowast1 119878lowast 119876lowast and 119879119862(119905

lowast

1) all are lowly sensitive to the

changes of 1198883for the inventory models that is 119888

3increases

from 19 to 32 the change of all the parameters is nomorethan 1

By studying the results of Table 7 it is found that 119905lowast1 119878lowast

119876lowast and 119879119862(119905

lowast

1) coordinate to 119888

4 It is also observed that the

value of 119905lowast1 119878lowast 119876lowast and 119879119862(119905

lowast

1) all are lowly sensitive to the

changes of 1198884for the inventory models that is 119888

4increases

from 143 to 100 the change of all the parameters is nomore than 1

5 Conclusion

An inventory model starting without shortage for Weibull-distributed deterioration with trapezoidal type demand rateand partial backlogging is considered in this paper Theoptimal replenishment policy for the inventory model isproposed and numerical examples are provided to illustratethe theoretical results A sensitivity analysis of the optimalsolution with respect to major parameters is also carried outFrom Table 1ndash7 it can be found that the shortage time point119905lowast

1 order quantity 119876lowast and the total average cost 119879119862(119905lowast

1) are

moderately sensitive to the changes of 120572 and 120573 and lowlysensitive to the changes of 120575 119888

119894(119894 = 1 2 3 4) respectively

The paper provides an interesting topic for further studysuch that the joint influence from some of these parametersmay be investigated to show the effects the model startingwith shortage will be studied and other types of models fordeteriorating items in supply chain situation are also to bestudied in the future

Conflict of Interests

The author declares that there is no conflict of interestsregarding the publication of this paper

Acknowledgments

The author is grateful to the anonymous referees who pro-vided valuable comments and suggestions to significantlyimprove the quality of the paper This work was supportedpartly byHumanities and Social Science Fund of theMinistryof Education of China (no 11YJCZH019)

References

[1] P M Ghare and G F Schrader ldquoA model for exponentiallydecaying inventoriesrdquo Journal of Industrial Engineering vol 14pp 238ndash243 1963

[2] J-W Wu C Lin B Tan and W-C Lee ldquoAn EOQ inventorymodel with time-varying demand and Weibull deteriorationwith shortagesrdquo International Journal of Systems Science vol 31no 6 pp 677ndash683 2000

[3] H-M Wee ldquoDeteriorating inventory model with quantity dis-count pricing and partial backorderingrdquo International Journalof Production Economics vol 59 no 1 pp 511ndash518 1999

[4] K Skouri and S Papachristos ldquoA continuous review inven-tory model with deteriorating items time-varying demandlinear replenishment cost partially time-varying backloggingrdquoApplied Mathematical Modelling vol 26 no 5 pp 603ndash6172002

[5] H-MWee J C P Yu and S T Law ldquoTwo-warehouse inventorymodel with partial backordering and Weibull distributiondeterioration under inflationrdquo Journal of the Chinese Institute ofIndustrial Engineers vol 22 no 6 pp 451ndash462 2005

[6] C-Y Dye T-P Hsieh and L-Y Ouyang ldquoDetermining optimalselling price and lot size with a varying rate of deteriorationand exponential partial backloggingrdquo European Journal ofOperational Research vol 181 no 2 pp 668ndash678 2007

[7] R M Hill ldquoInventory models for increasing demand followedby level demandrdquo Journal of the Operational Research Societyvol 46 no 10 pp 1250ndash1259 1995

[8] B Mandal and A K Pal ldquoOrder level inventory system withramp type demand rate for deteriorating itemsrdquo Journal ofInterdisciplinary Mathematics vol 1 no 1 pp 49ndash66 1998

[9] K-S Wu ldquoAn EOQ inventory model for items with Weibulldistribution deterioration ramp type demand rate and partialbackloggingrdquo Production Planning amp Control vol 12 no 8 pp787ndash793 2001

[10] B C Giri A K Jalan and K S Chaudhuri ldquoEconomic orderquantity model with Weibull deterioration distribution short-age and ramp-type demandrdquo International Journal of SystemsScience vol 34 no 4 pp 237ndash243 2003

[11] S K Manna and K S Chaudhuri ldquoAn EOQ model withramp type demand rate time dependent deterioration rate unitproduction cost and shortagesrdquoEuropean Journal ofOperationalResearch vol 171 no 2 pp 557ndash566 2006

[12] K Skouri I Konstantaras S Papachristos and I Ganas ldquoInven-tory models with ramp type demand rate partial backloggingandWeibull deterioration raterdquoEuropean Journal ofOperationalResearch vol 192 no 1 pp 79ndash92 2009

10 Journal of Applied Mathematics

[13] K-C Hung ldquoAn inventory model with generalized typedemand deterioration and backorder ratesrdquo European Journalof Operational Research vol 208 no 3 pp 239ndash242 2011

[14] R S Kumar S K De and A Goswami ldquoFuzzy EOQ modelswith ramp type demand rate partial backlogging and timedependent deterioration raterdquo International Journal of Mathe-matics in Operational Research vol 4 no 5 pp 473ndash502 2012

[15] M B Cheng B X Zhang and G QWang ldquoOptimal policy fordeteriorating items with trapezoidal type demand and partialbackloggingrdquoAppliedMathematical Modelling vol 35 no 7 pp3552ndash3560 2011

[16] R Uthayakumar and M Rameswari ldquoAn economic produc-tion quantity model for defective items with trapezoidal typedemand raterdquo Journal of Optimization Theory and Applicationsvol 154 no 3 pp 1055ndash1079 2012

[17] Y Tan and M X Weng ldquoA discrete-in-time deterioratinginventory model with time-varying demand variable deterio-ration rate and waiting-time-dependent partial backloggingrdquoInternational Journal of Systems Science vol 44 no 8 pp 1483ndash1493 2013

[18] M A Ahmed T A Al-Khamis and L Benkherouf ldquoInventorymodels with ramp type demand rate partial backlogging andgeneral deterioration raterdquo Applied Mathematics and Computa-tion vol 219 no 9 pp 4288ndash4307 2013

[19] K-P Lin ldquoAn extended inventory models with trapezoidal typedemandsrdquo Applied Mathematics and Computation vol 219 no24 pp 11414ndash11419 2013

[20] P L Abad ldquoOptimal pricing and lot-sizing under conditionsof perishability and partial backorderingrdquoManagement Sciencevol 42 no 8 pp 1093ndash1104 1996

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Mathematical Problems in Engineering

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Differential EquationsInternational Journal of

Volume 2014

Applied MathematicsJournal of

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Probability and StatisticsHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

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Mathematical PhysicsAdvances in

Complex AnalysisJournal of

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OptimizationJournal of

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Page 3: Research Article An Inventory Model under Trapezoidal Type ...downloads.hindawi.com/journals/jam/2014/747419.pdf · an inventory model with Weibull-distributed deterioration items,

Journal of Applied Mathematics 3

0

S

Inventorylevel

TimeT

0

S

Inventorylevel

TimeT

0

S

Inventorylevel

TimeT1205831

t1

1205832 t11205831

1205832 t11205831 1205832

Case 1 0 lt t1 le 1205831 Case 2 1205831 le t1 le 1205832 Case 3 1205832 le t1 lt T

Figure 1 Graphical representation of inventory level over the cycle

By using the boundary condition 119868(1199051) = 0 the solutions of

(3) are given by

119868 (119905) =

int

1199051

119905

119891 (119909) 119890120572(119909120573minus119905120573)119889119909 0 lt 119905 lt 119905

1

minusint

119905

1199051

119890120575(119909minus119879)

119891 (119909) 119889119909 1199051lt 119905 lt 120583

1

1198630

120575(119890120575(1205831minus119879)

minus 119890120575(119905minus119879)

)

minusint

1205831

1199051

119890120575(119909minus119879)

119891 (119909) 119889119909 1205831lt 119905 lt 120583

2

minusint

119905

1205832

119892 (119909) 119890120575(119909minus119879)

119889119909

+1198630

120575(119890120575(1205831minus119879)

minus 119890120575(1205832minus119879)

)

minusint

1205831

1199051

119890120575(119909minus119879)

119891 (119909) 119889119909 1205832lt 119905 lt 119879

(4)

The maximum inventory level per cycle is

119878 = 119868 (0) = int

1199051

0

119891 (119909) 119890120572119909120573

119889119909 (5)

Then the total number of deteriorated items 119863119879in the

interval [0 1199051] is

119863119879= 119878 minus int

1199051

0

119863 (119905) 119889119905 = int

1199051

0

119891 (119909) (119890120572119909120573

minus 1) 119889119909 (6)

The total number of inventory119867119879carried during the interval

[0 1199051] is

119867119879= int

1199051

0

119868 (119905) 119889119905 = int

1199051

0

int

1199051

119905

119891 (119909) 119890120572(119909120573minus119905120573)119889119909 119889119905 (7)

The total shortage quantity 119861119879during the interval [119905

1 119879] is

119861119879= minusint

119879

1199051

119868 (119905) 119889119905

= int

1205831

1199051

[int

119905

1199051

119890120575(119909minus119879)

119891 (119909) 119889119909] 119889119905

minus int

1205832

1205831

[1198630

120575(119890120575(1205831minus119879)

minus 119890120575(119905minus119879)

)

minusint

1205831

1199051

119890120575(119909minus119879)

119891 (119909) 119889119909] 119889119905

+ int

119879

1205832

[int

119905

1205832

119890120575(119909minus119879)

119892 (119909) 119889119909

minus1198630

120575(119890120575(1205831minus119879)

minus 119890120575(1205832minus119879)

)

+int

1205831

1199051

119890120575(119909minus119879)

119891 (119909) 119889119909] 119889119905

= int

1205831

1199051

(119879 minus 119905) 119890120575(119905minus119879)

119891 (119905) 119889119905

+ int

119879

1205832

(119879 minus 119905) 119890120575(119905minus119879)

119892 (119905) 119889119905

+1198630

1205752(119890120575(1205832minus119879)

minus 119890120575(1205831minus119879)

)

+1198630

120575[(119879 minus 120583

2) 119890120575(1205832minus119879)

minus (119879 minus 1205831) 119890120575(1205831minus119879)

]

(8)

The total of lost sales 119871119879during the interval [119905

1 119879] is

119871119879= int

1205831

1199051

(1 minus 119890120575(119905minus119879)

) 119891 (119905) 119889119905 + int

1205832

1205831

(1 minus 119890120575(119905minus119879)

)1198630119889119905

+ int

119879

1205832

(1 minus 119890120575(119905minus119879)

) 119892 (119905) 119889119905

(9)

4 Journal of Applied Mathematics

Therefore the average total cost per unit time under thecondition 119905

1le 1205831can be given by

1198621(1199051) =

1

119879[1198600+ 1198881119863119879+ 1198882119867119879+ 1198883119861119879+ 1198884119871119879]

=1

1198791198600+ 1198881int

1199051

0

119891 (119909) (119890120572119909120573

minus 1) 119889119909

+ 1198882int

1199051

0

int

1199051

119905

119891 (119909) 119890120572(119909120573minus119905120573)119889119909 119889119905

+ 1198884[int

1205831

1199051

(1 minus 119890120575(119905minus119879)

) 119891 (119905) 119889119905

+ int

1205832

1205831

(1 minus 119890120575(119905minus119879)

)1198630119889119905

+int

119879

1205832

(1 minus 119890120575(119905minus119879)

) 119892 (119905) 119889119905]

+ 1198883[int

1205831

1199051

119890120575(119905minus119879)

(119879 minus 119905) 119891 (119905) 119889119905

+ int

119879

1205832

119890120575(119905minus119879)

(119879 minus 119905) 119892 (119905) 119889119905

+1198630

1205752(119890120575(1205832minus119879)

minus 119890120575(1205831minus119879)

)

+1198630

120575((119879 minus 120583

2) 119890120575(1205832minus119879)

minus (119879 minus 1205831) 119890120575(1205831minus119879)

) ]

(10)

Case 2 (1205831le 1199051le 1205832) The differential equations governing

the inventory model can be expressed as follows

119889119868 (119905)

119889119905=

minus120572120573119905120573minus1

119868 (119905) minus 119891 (119905) 0 lt 119905 lt 1205831

minus120572120573119905120573minus1

119868 (119905) minus 1198630 120583

1lt 119905 lt 119905

1

minus119890minus120575(119879minus119905)

1198630 119905

1lt 119905 lt 120583

2

minus119890minus120575(119879minus119905)

119892 (119905) 1205832lt 119905 lt 119879

(11)

Solving the differential equation (11) with 119868(1199051) = 0 we have

119868 (119905) =

int

1205831

119905

119891 (119909) 119890120572(119909120573minus119905120573)119889119909

+1198630int

1199051

1205831

119890120572(119909120573minus119905120573)119889119909 0 lt 119905 lt 120583

1

1198630int

1199051

119905

119890120572(119909120573minus119905120573)119889119909 120583

1lt 119905 lt 119905

1

1198630

120575(119890120575(1199051minus119879)

minus 119890120575(119905minus119879)

) 1199051lt 119905 lt 120583

2

minusint

119905

1205832

119890120575(119909minus119879)

119892 (119909) 119889119909

+1198630

120575(119890120575(1199051minus119879)

minus 119890120575(1205832minus119879)

) 1205832lt 119905 lt 119879

(12)

The beginning inventory level can be computed as

119878 = 119868 (0) = int

1205831

0

119891 (119909) 119890120572119909120573

119889119909 + 1198630int

1199051

1205831

119890120572119909120573

119889119909 (13)

The total number of items which perish in the interval [0 1199051]

is

119863119879= int

1205831

0

119891 (119909) (119890120572119909120573

minus 1) 119889119909 + 1198630int

1199051

1205831

(119890120572119909120573

minus 1) 119889119909 (14)

The total number of inventory carried during the interval[0 1199051] is

119867119879= int

1205831

0

int

1205831

119905

119890120572(119909120573minus119905120573)119891 (119909) 119889119909 119889119905 + 119863

0int

1199051

1205831

int

1199051

119905

119890120572(119909120573minus119905120573)119889119909 119889119905

(15)

The total shortage quantity during the interval [1199051 119879] is

119861119879= int

119879

1205832

(119879 minus 119905) 119890120575(119905minus119879)

119892 (119905) 119889119905

+1198630

120575[119890120575(1199051minus119879)

(119879 minus 1199051+1

120575)

minus119890minus120575(1205832minus119879)

(119879 minus 1205832+1

120575)]

(16)

The total of lost sales during the interval [1199051 119879] is

119871119879= 1198630int

1205832

1199051

(1 minus 119890120575(119905minus119879)

) 119889119905 + int

119879

1205832

(1 minus 119890120575(119905minus119879)

) 119892 (119905) 119889119905

(17)

Therefore the average total cost per unit time under thecondition 120583

1le 1199051le 1205832can be given by

1198622(1199051) =

1

119879[1198600+ 1198881119863119879+ 1198882119867119879+ 1198883119861119879+ 1198884119871119879]

=1

1198791198600+ 1198881[int

1205831

0

119891 (119909) (119890120572119909120573

minus 1) 119889119909

+1198630int

1199051

1205831

(119890120572119909120573

minus 1) 119889119909]

+ 1198882[int

1205831

0

int

1205831

119905

119890120572(119909120573minus119905120573)119891 (119909) 119889119909 119889119905

+1198630int

1199051

0

int

1199051

119905

119890120572(119909120573minus119905120573)119889119909 119889119905]

Journal of Applied Mathematics 5

+ 1198883[int

119879

1205832

(119879 minus 119905) 119890120575(119905minus119879)

119892 (119905) 119889119905

+1198630

120575(119890120575(1199051minus119879)

(119879 minus 1199051+1

120575)

minus119890120575(1205832minus119879)

(119879 minus 1205832+1

120575)) ]

+ 1198884[1198630int

1205832

1199051

(1 minus 119890120575(119905minus119879)

) 119889119905

+int

119879

1205832

(1 minus 119890120575(119905minus119879)

) 119892 (119905) 119889119905]

(18)

Case 3 (1205832le 1199051lt 119879) The differential equations governing

the inventory model can be expressed as follows

119889119868 (119905)

119889119905=

minus120572120573119905120573minus1

119868 (119905) minus 119891 (119905) 0 lt 119905 lt 1205831

minus120572120573119905120573minus1

119868 (119905) minus 1198630 120583

1lt 119905 lt 120583

2

minus120572120573119905120573minus1

119868 (119905) minus 119892 (119905) 1205832lt 119905 lt 119905

1

minus119890minus120575(119879minus119905)

119892 (119905) 1199051lt 119905 lt 119879

(19)

Solving the differential equation (19) with 119868(1199051) = 0 we have

119868 (119905) =

int

1205831

119905

119890120572(119909120573minus119905120573)119891 (119909) 119889119909 + 119863

0int

1205832

1205831

119890120572(119909120573minus119905120573)119889119909 + int

1199051

1205832

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 0 lt 119905 lt 120583

1

1198630int

1205832

119905

119890120572(119909120573minus119905120573)119889119909 + int

1199051

1205832

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 120583

1lt 119905 lt 120583

2

int

1199051

119905

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 120583

2lt 119905 lt 119905

1

minusint

119905

1199051

119890120575(119909minus119879)

119892 (119909) 119889119909 1199051lt 119905 lt 119879

(20)

The beginning inventory level can be computed as

119878 = 119868 (0)

= int

1205831

0

119890120572119909120573

119891 (119909) 119889119909

+ 1198630int

1205832

1205831

119890120572119909120573

119889119909 + int

1199051

1205832

119890120572119909120573

119892 (119909) 119889119909

(21)

The total number of items which perish in the interval [0 1199051]

is

119863119879= int

1205831

0

(119890120572119909120573

minus 1)119891 (119909) 119889119909 + 1198630int

1205832

1205831

(119890120572119909120573

minus 1) 119889119909

+ int

1199051

1205832

(119890120572119909120573

minus 1) 119892 (119909) 119889119909

(22)

The total number of inventory carried during the interval[0 1199051] is

119867119879= int

1205831

0

int

1205831

119905

119890120572(119909120573minus119905120573)119891 (119909) 119889119909 119889119905

+ 1198630int

1205831

0

int

1205832

1205831

119890120572(119909120573minus119905120573)119889119909 119889119905

+ 1198630int

1205832

1205831

int

1205832

119905

119890120572(119909120573minus119905120573)119889119909 119889119905

+ int

1205832

0

int

1199051

1205832

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 119889119905

+ int

1199051

1205832

int

1199051

119905

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 119889119905

(23)

The total shortage quantity during the interval [1199051 119879] is

119861119879= int

119879

1199051

(119879 minus 119905) 119890minus120575(119879minus119905)

119892 (119905) 119889119905 (24)

The total of lost sales during the interval [1199051 119879] is

119871119879= int

119879

1199051

(1 minus 119890minus120575(119879minus119905)

) 119892 (119905) 119889119905 (25)

Therefore the average total cost per unit time under thecondition 120583

2le 1199051le 119879 can be given by

1198623(1199051) =

1

119879[1198600+ 1198881119863119879+ 1198882119867119879+ 1198883119861119879+ 1198884119871119879]

=1

1198791198600+ 1198881[int

1205831

0

(119890120572119909120573

minus 1)119891 (119909) 119889119909

+ 1198630int

1205832

1205831

(119890120572119909120573

minus 1) 119889119909

+int

1199051

1205832

(119890120572119909120573

minus 1) 119892 (119909) 119889119909]

6 Journal of Applied Mathematics

+ 1198882[int

1205831

0

int

1205831

119905

119890120572(119909120573minus119905120573)119891 (119909) 119889119909 119889119905

+ 1198630int

1205831

0

int

1205832

1205831

119890120572(119909120573minus119905120573)119889119909 119889119905

+ 1198630int

1205832

1205831

int

1205832

119905

119890120572(119909120573minus119905120573)119889119909 119889119905

+ int

1205832

0

int

1199051

1205832

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 119889119905

+int

1199051

1205832

int

1199051

119905

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 119889119905]

+ 1198883[int

119879

1199051

(119879 minus 119905) 119890120575(119905minus119879)

119892 (119905) 119889119905]

+ 1198884[int

119879

1199051

(1 minus 119890120575(119905minus119879)

) 119892 (119905) 119889119905]

(26)

From the above analysis we obtain that the total average costof the model over the time interval [0 119879] is

119879119862 (1199051) =

1198621(1199051) 0 lt 119905

1le 1205831

1198622(1199051) 120583

1lt 1199051le 1205832

1198623(1199051) 120583

2lt 1199051lt 119879

(27)

where 1198621(1199051) 1198622(1199051) and 119862

3(1199051) are obtained from (10) (18)

and (26) respectivelyIn the following we will provide the results which ensure

the existence of a unique 1199051 say 119905lowast1 so as to minimize the total

average cost for the model system starting with no shortagesIf 0 lt 119905

1le 1205831 taking the first-order derivative of 119862

1(1199051)

with respect to 1199051 we obtain

1198891198621(1199051)

1198891199051

=119891 (1199051)

119879ℎ (1199051) (28)

where

ℎ (1199051) = 1198881(119890120572119905120573

1 minus 1)

+ 1198882int

1199051

0

119890120572(119905120573

1minus119905120573)119889119905 + 119888

3(1199051minus 119879) 119890

120575(1199051minus119879)

+ 1198884(119890120575(1199051minus119879)

minus 1)

(29)

then we can obtain ℎ(0) lt 0 and ℎ(119879) gt 0 By using theassumption (119905119890minus120575119905 is an increasing function where 119905 is thewaiting time up to the next replenishment) we have

119889ℎ (1199051)

1198891199051

= 120572120573119905120573minus1

1(1198881119890120572119905120573

1 + 1198882int

1199051

0

119890120572(119905120573

1minus119905120573)119889119905)

+ [1198883(120575 (1199051minus 119879) + 1) + 119888

4120575] 119890120575(1199051minus119879)

+ 1198882gt 0

(30)

which implies that ℎ(1199051) is a strictly monotone increasing

function Therefore the equation

ℎ (1199051) = 1198881(119890120572119905120573

1 minus 1) + 1198882int

1199051

0

119890120572(119905120573

1minus119905120573)119889119905

+ 1198883(1199051minus 119879) 119890

120575(1199051minus119879)

+ 1198884(119890120575(1199051minus119879)

minus 1)

= 0

(31)

has a unique root 119905lowast1isin (0 119879) obtained by using Mathematica

90 Further 119905lowast1is the only zero-point of 119889119862

1(1199051)1198891199051= 0 since

119891(1199051) gt 0If 0 lt 119905

lowast

1le 1205831 for this 119905lowast

1 we have

11988921198621(1199051)

1198891199052

1

1003816100381610038161003816100381610038161003816100381610038161199051=119905lowast

1

= 119891 (119905lowast

1)119889ℎ (119905lowast

1)

119879119889119905lowast

1

gt 0 (32)

which means that the total average cost 1198621(1199051) can obtain its

minimum value at 119905lowast1

The optimal value of the order level 119878 = 119868(0) is

119878lowast= int

119905lowast

1

0

119891 (119909) 119890120572119909120573

119889119909 (33)

and the optimal order quantity 119876lowast is

119876lowast= 119878lowast+ int

1205831

119905lowast

1

119890120575(119905minus119879)

119891 (119905) 119889119905

+ 1198630int

1205832

1205831

119890120575(119905minus119879)

119889119905 + int

119879

1205832

119890120575(119905minus119879)

119892 (119905) 119889119905

(34)

If 119905lowast1

ge 1205831 then the optimal value of 119862

1(1199051) is obtained at

1199051= 1205831

If 1205831lt 1199051le 1205832 taking the first-order and second-order

derivative of 1198622(1199051) with respect to 119905

1 respectively we obtain

1198891198622(1199051)

1198891199051

=1198630

119879ℎ (1199051) (35)

If 1205831lt 119905lowast

1le 1205832 for this 119905lowast

1 we have

11988921198622(1199051)

1198891199052

1

1003816100381610038161003816100381610038161003816100381610038161199051=119905lowast

1

= 1198630

119889ℎ (119905lowast

1)

119879119889119905lowast

1

gt 0 (36)

where the function ℎ(1199051) is given by (31) and (36) implies

that 1198622(1199051) is a strictly convex function in 119905

1and obtained its

minimum value at 119905lowast1 Therefore the equation ℎ(119905

1) = 0 has a

unique root 119905lowast1in (0 119879)

The optimal value of the order level 119878 = 119868(0) is

119878lowast= int

1205831

0

119891 (119909) 119890120572119909120573

119889119909 + 1198630int

119905lowast

1

1205831

119890120572119909120573

119889119909 (37)

and the optimal order quantity 119876lowast is

119876lowast= 119878lowast+ int

1205832

119905lowast

1

119890120575(119905minus119879)

1198630119889119905 + int

119879

1205832

119890120575(119905minus119879)

119892 (119905) 119889119905 (38)

Journal of Applied Mathematics 7

If 119905lowast1le 1205831 then the optimal value of 119862

2(1199051) is obtained at

119905lowast

1= 1205831 and if 119905lowast

1ge 1205832 then the optimal value of 119862

2(1199051) is

obtained at 119905lowast1= 1205832

If 1205832lt 1199051le 119879 taking the first-order and second-order

derivative of 1198623(1199051) with respect to 119905

1 respectively we obtain

1198891198623(1199051)

1198891199051

=119892 (1199051)

119879ℎ (1199051) (39)

If 1205832lt 119905lowast

1le 119879 for this 119905lowast

1 we have

11988921198623(1199051)

1198891199052

1

1003816100381610038161003816100381610038161003816100381610038161199051=119905lowast

1

= 119892 (119905lowast

1)119889ℎ (119905lowast

1)

119879119889119905lowast

1

gt 0 (40)

The function ℎ(1199051) is given by (31) and (40) implies that

1198623(1199051) can obtain its minimum value at 119905lowast

1

The optimal value of the order level 119878 = 119868(0) is

119878lowast= int

1205831

0

119890120572119909120573

119891 (119909) 119889119909 + 1198630int

1205832

1205831

119890120572119909120573

119889119909 + int

119905lowast

1

1205832

119890120572119909120573

119892 (119909) 119889119909

(41)

and the optimal order quantity 119876lowast is

119876lowast= 119878lowast+ int

119879

119905lowast

1

119890120575(119905minus119879)

119892 (119905) 119889119905 (42)

If 119905lowast1

le 1205832 then the optimal value of 119862

3(1199051) is obtained at

119905lowast

1= 1205832

The above analysis shows that the three average cost func-tions 119862

1(1199051) 1198622(1199052) and 119862

3(1199051) can obtain their minimum

value at 119905lowast1isin (0 119879) which is determined by (31) Therefore

based on the results analyzed above this paper derives aprocedure to locate the optimal replenishment policy startingwith no shortage for the three cases The procedure is asfollowsStep 1 Solve 119905lowast

1from (31)

Step 2 Compare 119905lowast1to 1205831and 120583

2 respectively

Step 21 If 119905lowast1isin (0 120583

1] then the optimal total average cost and

the optimal order quantity can be obtained by (10) and (34)respectivelyStep 22 If 119905lowast

1isin (1205831 1205832] then the optimal total average cost

and the optimal order quantity can be obtained by (18) and(38) respectively

Step 23 If 119905lowast1isin (1205832 119879] then the optimal total average cost

and the optimal order quantity can be obtained by (26) and(42) respectively

Remark 1 In such considered inventory model starting withno shortage if 119905

1satisfies 120583

1lt 1199051le 119879 lt 120583

2 the considered

inventory model reduces to that of Skouri et al [12]

4 Numerical Example

In order to demonstrate the above procedure which can beapplied to obtain the optimal solution of the model this

paper presents several examples for the model respectivelyExamples are based on piecewise demand rate such as119891(119905) =1198861+ 1198871119905 and 119892(119905) = 119886

2119890minus1198872119905

Example 1 The parameter values are given as follows 119879 = 12

weeks1205831= 4weeks120583

2= 8weeks120572 = 0005120573 = 2120575 = 004

1198861= 30 unit 119887

1= 5 unit 119886

2= 100 unit 119860

0= $500 119888

1= $2

1198882= $3 119888

3= $12 and 119888

4= $8

The model starting with no shortage by solving theequation ℎ(119905

1) = 0 we have 119905

lowast

1= 87622 From (42) and

(26) we obtain 119876lowast

= 5825217 and 119879119862(119905lowast

1) = 7939986

respectively

Example 2 Theparameter values are given as follows119879 = 12

weeks1205831= 4weeks120583

2= 8weeks120572 = 0005120573 = 2120575 = 002

1198861= 30 unit 119887

1= 5 unit 119886

2= 100 unit 119860

0= $500 119888

1= $5

1198882= $10 119888

3= $12 and 119888

4= $8

The model starting with no shortage by solving theequation ℎ(119905

1) = 0 we have 119905

lowast

1= 58330 From (38) and

(18) we obtain 119876lowast

= 5284725 and 119879119862(119905lowast

1) = 16014013

respectively

Example 3 Theparameter values are given as follows119879 = 12

weeks 1205831= 4 weeks 120583

2= 6 weeks 120572 = 0005 120573 = 16

120575 = 02 1198861= 30 unit 119887

1= 5 unit 119886

2= 100 unit 119860

0= $500

1198881= $5 119888

2= $10 119888

3= $12 and 119888

4= $8

Themodel starting with no shortage solving the equationℎ(1199051) = 0 the optimal value of 119905

1is 119905lowast1= 23235 The optimal

ordering quantity is 119876lowast = 2726678 and the minimum cost119879119862(119905lowast

1) = 125882

In order to clearly indicate the effects of parameters suchas 120575 120572 120573 119888

1 1198882 1198883 and 119888

4on the optimal on-hand inventory

119878lowast the optimal ordering quantity 119876

lowast and the optimal totalcost 119879119862(119905lowast

1) respectively the paper will study the sensitivity

of the optimal solution to changes in the value of differentparameter associated with the studied inventory model Thesensitivity analysis is performed on the base of Example 1 andthe results are shown in Table 1ndash7

By studying the results of Table 1 it is found that theshortage time 119905

lowast

1 inventory level 119878

lowast order quantity 119876lowast

and the total average cost 119879119862(119905lowast1) gradually decrease as the

shortage parameter 120575 increases for the model respectivelyWe also find that the percentage increase of 120575 from 143to 100 causes 119879119862(119905

lowast

1) to decrease from 045 to 034

119876lowast decrease from 075 to 052 119905lowast

1decrease from 078

to 053 and 119878lowast decrease from 102 to 069 It is also

observed that the value of 119905lowast1 119878lowast119876lowast and 119879119862(119905lowast

1) all are lowly

sensitive to the changes of 120575 for the considered inventorymodel

By studying the results of Table 2 it is found that 119878lowast 119876lowastand 119879119862(119905lowast

1) coordinates to the deterioration parameter 120572 the

shortage time 119905lowast1decreases as 120572 increases for the model It is

also found that the percentage increase of 120572 from 167 to100 causes 119879119862(119905lowast

1) to decrease by 2066ndash2595 119876lowast to

increase by 1597ndash244 the shortage time 119905lowast1to decrease

by 1513ndash1455 and 119878lowast to increase by 0917ndash1651 It

also observes that the value of 119905lowast1 119878lowast 119876lowast and 119879119862(119905

lowast

1) all are

moderately sensitive to the changes of 120572 for the consideredinventory model

8 Journal of Applied Mathematics

Table 1 The sensitivity of 120575 for the models in Example 1

120575 0 001 002 003 004 005 006 007 008119905lowast

189664 89187 88689 88167 87622 87049 86449 85817 85152

119878lowast 4729889 4697083 4662823 4627001 4589498 4550167 4508910 4465519 4419829119876lowast 5956569 5925872 5893822 5860308 5825217 5788412 5749771 5709112 5666265

TC(119905lowast1) 8056323 8028699 8000139 7970588 7939986 7908268 7875365 7841200 7805690

Table 2 The sensitivity of 120572 for the models in Example 1

120572 0 0001 0002 0003 0004 0005 0006 0007119905lowast

194545 93115 91702 90312 88950 87622 86328 85072

119878lowast 4283286 4354002 4420048 4481317 4537785 4589498 4636555 4679088119876lowast 5238866 5366685 5489558 5607091 5719025 5825217 5925618 6020259

TC(119905lowast1) 7046045 7228867 7410107 7589297 7766035 7939986 8110872 8278474

Table 3 The sensitivity of 120573 for the models in Example 1

120573 14 16 18 20 22 24 26 28119905lowast

192876 91810 90142 87622 84047 79422 74073 68496

119878lowast 4429058 4475894 4531802 4589076 4628345 4616422 4534686 4388904119876lowast 5451340 5541055 5664485 5824772 6012274 7746099 7664364 7518582

TC(119905lowast1) 7457703 7643043 7917624 7907114 8293653 5887417 4731282 3911266

Table 4 The sensitivity of 1198881for the models in Example 1

1198881

0 04 1 16 2 24 26 3 36119905lowast

188225 88103 87921 87741 87622 87503 87443 87326 87150

119878lowast 4630980 4622595 4610101 4597707 4589498 4581333 4577266 4569164 4557090119876lowast 5841909 5838529 5833499 5828514 5825217 5821940 5825217 5817061 5812226

TC(119905lowast1) 7835429 7856518 7887984 7919251 7939986 7960633 7970925 7991443 8022061

Table 5 The sensitivity of 1198882for the model in Example 1

1198882

0 04 08 12 18 24 3 34 38119905lowast

1118343 11267 107698 10326 97377 92216 87622 84819 82196

119878lowast 6737217 6330852 5979589 5669228 5261187 4905382 4589498 4396922 4216606119876lowast 6796039 6594483 6427261 6284787 6104744 5954175 5825217 5748648 5678284

TC(119905lowast1) 672679 1939216 3088975 4139636 5558150 6816692 7939986 8623253 9259516

Table 6 The sensitivity of 1198883for the models in Example 1

1198883

104 106 108 11 112 116 12 124 128119905lowast

184424 84859 85284 85698 86102 86879 87622 88329 89005

119878lowast 4369771 4399713 442889 4457332 4485071 453854 4589498 4638114 4684587119876lowast 5737973 5749747 5761255 5772506 5783509 5804809 5825217 5844787 5863587

TC(119905lowast1) 7638057 7679203 7719299 7758387 7796505 7869976 7939986 8006779 8070579

Table 7 The sensitivity of 1198884for the models in Example 1

1198884

0 2 4 6 8 10 12 14 16119905lowast

186989 87150 87309 87466 87622 87775 87928 88078 882272

119878lowast 4546069 4557103 4568017 4578815 4589498 4600048 4610527 4620877 4631120119876lowast 5807818 5812231 5816601 5820929 5825217 5829455 583367 5837837 5841966

TC(119905lowast1) 7881626 7896445 7911109 7925621 7939986 7954203 7968276 7982207 7995999

Journal of Applied Mathematics 9

By studying the results of Table 3 it is found that 119878lowast119876lowast and 119879119862(119905

lowast

1) coordinate to the deterioration parameter 120573

while the shortage time 119905lowast

1decreases as 120573 increases for the

model It is also found that the increase of 120573 from 14 to 22causes 119878

lowast to increase while the increase of 120573 from 24 to28 causes 119878lowast to decrease 119876lowast to increase by 244ndash1597119879119862(119905lowast

1) to increase by 2595ndash2066 and the shortage time

119905lowast

1to decrease by 1513ndash1455 It is also observed that the

value of 119905lowast1 119878lowast119876lowast and 119879119862(119905lowast

1) all are moderately sensitive to

the changes of 120573 for the considered inventory modelBy studying the results of Table 4 it is found that 119879119862(119905lowast

1)

coordinate to 1198881 while the shortage time 119905

lowast

1 119878lowast and 119876

lowast

decrease as 1198881increases for the model It is also found that 119888

1

increases from 83 to 150 119879119862(119905lowast1) decreases by 0269ndash

0383 119876lowast decreases by 0083ndash0058 119905lowast1decreases by

0264ndash0181 and 119878lowast decreases by 0203ndash0138 respec-tively It is also observed that the values of 119905lowast

1 119878lowast 119876lowast and

119879119862(119905lowast

1) all are lowly sensitive to the changes of 119888

1for the

considered inventory modelBy studying the results of Table 5 it is found that

119879119862(119905lowast

1) coordinates to 119888

2 while 119878

lowast 119876lowastand 119905lowast

1decrease as

1198881increases for the model It is also found that 119888

2increases

by 100 119879119862(119905lowast1) decreases by 0269ndash0383 119876lowast decreases

by 0083ndash0058 119905lowast1decreases by 0264ndash0181 and 119878

lowast

decreases by 0203ndash0138By studying the results of Table 6 it is found that 119905lowast

1 119878lowast

119876lowast and 119879119862(119905

lowast

1) coordinate to 119888

3 It is also observed that the

value of 119905lowast1 119878lowast 119876lowast and 119879119862(119905

lowast

1) all are lowly sensitive to the

changes of 1198883for the inventory models that is 119888

3increases

from 19 to 32 the change of all the parameters is nomorethan 1

By studying the results of Table 7 it is found that 119905lowast1 119878lowast

119876lowast and 119879119862(119905

lowast

1) coordinate to 119888

4 It is also observed that the

value of 119905lowast1 119878lowast 119876lowast and 119879119862(119905

lowast

1) all are lowly sensitive to the

changes of 1198884for the inventory models that is 119888

4increases

from 143 to 100 the change of all the parameters is nomore than 1

5 Conclusion

An inventory model starting without shortage for Weibull-distributed deterioration with trapezoidal type demand rateand partial backlogging is considered in this paper Theoptimal replenishment policy for the inventory model isproposed and numerical examples are provided to illustratethe theoretical results A sensitivity analysis of the optimalsolution with respect to major parameters is also carried outFrom Table 1ndash7 it can be found that the shortage time point119905lowast

1 order quantity 119876lowast and the total average cost 119879119862(119905lowast

1) are

moderately sensitive to the changes of 120572 and 120573 and lowlysensitive to the changes of 120575 119888

119894(119894 = 1 2 3 4) respectively

The paper provides an interesting topic for further studysuch that the joint influence from some of these parametersmay be investigated to show the effects the model startingwith shortage will be studied and other types of models fordeteriorating items in supply chain situation are also to bestudied in the future

Conflict of Interests

The author declares that there is no conflict of interestsregarding the publication of this paper

Acknowledgments

The author is grateful to the anonymous referees who pro-vided valuable comments and suggestions to significantlyimprove the quality of the paper This work was supportedpartly byHumanities and Social Science Fund of theMinistryof Education of China (no 11YJCZH019)

References

[1] P M Ghare and G F Schrader ldquoA model for exponentiallydecaying inventoriesrdquo Journal of Industrial Engineering vol 14pp 238ndash243 1963

[2] J-W Wu C Lin B Tan and W-C Lee ldquoAn EOQ inventorymodel with time-varying demand and Weibull deteriorationwith shortagesrdquo International Journal of Systems Science vol 31no 6 pp 677ndash683 2000

[3] H-M Wee ldquoDeteriorating inventory model with quantity dis-count pricing and partial backorderingrdquo International Journalof Production Economics vol 59 no 1 pp 511ndash518 1999

[4] K Skouri and S Papachristos ldquoA continuous review inven-tory model with deteriorating items time-varying demandlinear replenishment cost partially time-varying backloggingrdquoApplied Mathematical Modelling vol 26 no 5 pp 603ndash6172002

[5] H-MWee J C P Yu and S T Law ldquoTwo-warehouse inventorymodel with partial backordering and Weibull distributiondeterioration under inflationrdquo Journal of the Chinese Institute ofIndustrial Engineers vol 22 no 6 pp 451ndash462 2005

[6] C-Y Dye T-P Hsieh and L-Y Ouyang ldquoDetermining optimalselling price and lot size with a varying rate of deteriorationand exponential partial backloggingrdquo European Journal ofOperational Research vol 181 no 2 pp 668ndash678 2007

[7] R M Hill ldquoInventory models for increasing demand followedby level demandrdquo Journal of the Operational Research Societyvol 46 no 10 pp 1250ndash1259 1995

[8] B Mandal and A K Pal ldquoOrder level inventory system withramp type demand rate for deteriorating itemsrdquo Journal ofInterdisciplinary Mathematics vol 1 no 1 pp 49ndash66 1998

[9] K-S Wu ldquoAn EOQ inventory model for items with Weibulldistribution deterioration ramp type demand rate and partialbackloggingrdquo Production Planning amp Control vol 12 no 8 pp787ndash793 2001

[10] B C Giri A K Jalan and K S Chaudhuri ldquoEconomic orderquantity model with Weibull deterioration distribution short-age and ramp-type demandrdquo International Journal of SystemsScience vol 34 no 4 pp 237ndash243 2003

[11] S K Manna and K S Chaudhuri ldquoAn EOQ model withramp type demand rate time dependent deterioration rate unitproduction cost and shortagesrdquoEuropean Journal ofOperationalResearch vol 171 no 2 pp 557ndash566 2006

[12] K Skouri I Konstantaras S Papachristos and I Ganas ldquoInven-tory models with ramp type demand rate partial backloggingandWeibull deterioration raterdquoEuropean Journal ofOperationalResearch vol 192 no 1 pp 79ndash92 2009

10 Journal of Applied Mathematics

[13] K-C Hung ldquoAn inventory model with generalized typedemand deterioration and backorder ratesrdquo European Journalof Operational Research vol 208 no 3 pp 239ndash242 2011

[14] R S Kumar S K De and A Goswami ldquoFuzzy EOQ modelswith ramp type demand rate partial backlogging and timedependent deterioration raterdquo International Journal of Mathe-matics in Operational Research vol 4 no 5 pp 473ndash502 2012

[15] M B Cheng B X Zhang and G QWang ldquoOptimal policy fordeteriorating items with trapezoidal type demand and partialbackloggingrdquoAppliedMathematical Modelling vol 35 no 7 pp3552ndash3560 2011

[16] R Uthayakumar and M Rameswari ldquoAn economic produc-tion quantity model for defective items with trapezoidal typedemand raterdquo Journal of Optimization Theory and Applicationsvol 154 no 3 pp 1055ndash1079 2012

[17] Y Tan and M X Weng ldquoA discrete-in-time deterioratinginventory model with time-varying demand variable deterio-ration rate and waiting-time-dependent partial backloggingrdquoInternational Journal of Systems Science vol 44 no 8 pp 1483ndash1493 2013

[18] M A Ahmed T A Al-Khamis and L Benkherouf ldquoInventorymodels with ramp type demand rate partial backlogging andgeneral deterioration raterdquo Applied Mathematics and Computa-tion vol 219 no 9 pp 4288ndash4307 2013

[19] K-P Lin ldquoAn extended inventory models with trapezoidal typedemandsrdquo Applied Mathematics and Computation vol 219 no24 pp 11414ndash11419 2013

[20] P L Abad ldquoOptimal pricing and lot-sizing under conditionsof perishability and partial backorderingrdquoManagement Sciencevol 42 no 8 pp 1093ndash1104 1996

Submit your manuscripts athttpwwwhindawicom

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Mathematical Problems in Engineering

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Differential EquationsInternational Journal of

Volume 2014

Applied MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

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Complex AnalysisJournal of

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OptimizationJournal of

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CombinatoricsHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

International Journal of

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Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Function Spaces

Abstract and Applied AnalysisHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

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Discrete Dynamics in Nature and Society

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Volume 2014 Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Stochastic AnalysisInternational Journal of

Page 4: Research Article An Inventory Model under Trapezoidal Type ...downloads.hindawi.com/journals/jam/2014/747419.pdf · an inventory model with Weibull-distributed deterioration items,

4 Journal of Applied Mathematics

Therefore the average total cost per unit time under thecondition 119905

1le 1205831can be given by

1198621(1199051) =

1

119879[1198600+ 1198881119863119879+ 1198882119867119879+ 1198883119861119879+ 1198884119871119879]

=1

1198791198600+ 1198881int

1199051

0

119891 (119909) (119890120572119909120573

minus 1) 119889119909

+ 1198882int

1199051

0

int

1199051

119905

119891 (119909) 119890120572(119909120573minus119905120573)119889119909 119889119905

+ 1198884[int

1205831

1199051

(1 minus 119890120575(119905minus119879)

) 119891 (119905) 119889119905

+ int

1205832

1205831

(1 minus 119890120575(119905minus119879)

)1198630119889119905

+int

119879

1205832

(1 minus 119890120575(119905minus119879)

) 119892 (119905) 119889119905]

+ 1198883[int

1205831

1199051

119890120575(119905minus119879)

(119879 minus 119905) 119891 (119905) 119889119905

+ int

119879

1205832

119890120575(119905minus119879)

(119879 minus 119905) 119892 (119905) 119889119905

+1198630

1205752(119890120575(1205832minus119879)

minus 119890120575(1205831minus119879)

)

+1198630

120575((119879 minus 120583

2) 119890120575(1205832minus119879)

minus (119879 minus 1205831) 119890120575(1205831minus119879)

) ]

(10)

Case 2 (1205831le 1199051le 1205832) The differential equations governing

the inventory model can be expressed as follows

119889119868 (119905)

119889119905=

minus120572120573119905120573minus1

119868 (119905) minus 119891 (119905) 0 lt 119905 lt 1205831

minus120572120573119905120573minus1

119868 (119905) minus 1198630 120583

1lt 119905 lt 119905

1

minus119890minus120575(119879minus119905)

1198630 119905

1lt 119905 lt 120583

2

minus119890minus120575(119879minus119905)

119892 (119905) 1205832lt 119905 lt 119879

(11)

Solving the differential equation (11) with 119868(1199051) = 0 we have

119868 (119905) =

int

1205831

119905

119891 (119909) 119890120572(119909120573minus119905120573)119889119909

+1198630int

1199051

1205831

119890120572(119909120573minus119905120573)119889119909 0 lt 119905 lt 120583

1

1198630int

1199051

119905

119890120572(119909120573minus119905120573)119889119909 120583

1lt 119905 lt 119905

1

1198630

120575(119890120575(1199051minus119879)

minus 119890120575(119905minus119879)

) 1199051lt 119905 lt 120583

2

minusint

119905

1205832

119890120575(119909minus119879)

119892 (119909) 119889119909

+1198630

120575(119890120575(1199051minus119879)

minus 119890120575(1205832minus119879)

) 1205832lt 119905 lt 119879

(12)

The beginning inventory level can be computed as

119878 = 119868 (0) = int

1205831

0

119891 (119909) 119890120572119909120573

119889119909 + 1198630int

1199051

1205831

119890120572119909120573

119889119909 (13)

The total number of items which perish in the interval [0 1199051]

is

119863119879= int

1205831

0

119891 (119909) (119890120572119909120573

minus 1) 119889119909 + 1198630int

1199051

1205831

(119890120572119909120573

minus 1) 119889119909 (14)

The total number of inventory carried during the interval[0 1199051] is

119867119879= int

1205831

0

int

1205831

119905

119890120572(119909120573minus119905120573)119891 (119909) 119889119909 119889119905 + 119863

0int

1199051

1205831

int

1199051

119905

119890120572(119909120573minus119905120573)119889119909 119889119905

(15)

The total shortage quantity during the interval [1199051 119879] is

119861119879= int

119879

1205832

(119879 minus 119905) 119890120575(119905minus119879)

119892 (119905) 119889119905

+1198630

120575[119890120575(1199051minus119879)

(119879 minus 1199051+1

120575)

minus119890minus120575(1205832minus119879)

(119879 minus 1205832+1

120575)]

(16)

The total of lost sales during the interval [1199051 119879] is

119871119879= 1198630int

1205832

1199051

(1 minus 119890120575(119905minus119879)

) 119889119905 + int

119879

1205832

(1 minus 119890120575(119905minus119879)

) 119892 (119905) 119889119905

(17)

Therefore the average total cost per unit time under thecondition 120583

1le 1199051le 1205832can be given by

1198622(1199051) =

1

119879[1198600+ 1198881119863119879+ 1198882119867119879+ 1198883119861119879+ 1198884119871119879]

=1

1198791198600+ 1198881[int

1205831

0

119891 (119909) (119890120572119909120573

minus 1) 119889119909

+1198630int

1199051

1205831

(119890120572119909120573

minus 1) 119889119909]

+ 1198882[int

1205831

0

int

1205831

119905

119890120572(119909120573minus119905120573)119891 (119909) 119889119909 119889119905

+1198630int

1199051

0

int

1199051

119905

119890120572(119909120573minus119905120573)119889119909 119889119905]

Journal of Applied Mathematics 5

+ 1198883[int

119879

1205832

(119879 minus 119905) 119890120575(119905minus119879)

119892 (119905) 119889119905

+1198630

120575(119890120575(1199051minus119879)

(119879 minus 1199051+1

120575)

minus119890120575(1205832minus119879)

(119879 minus 1205832+1

120575)) ]

+ 1198884[1198630int

1205832

1199051

(1 minus 119890120575(119905minus119879)

) 119889119905

+int

119879

1205832

(1 minus 119890120575(119905minus119879)

) 119892 (119905) 119889119905]

(18)

Case 3 (1205832le 1199051lt 119879) The differential equations governing

the inventory model can be expressed as follows

119889119868 (119905)

119889119905=

minus120572120573119905120573minus1

119868 (119905) minus 119891 (119905) 0 lt 119905 lt 1205831

minus120572120573119905120573minus1

119868 (119905) minus 1198630 120583

1lt 119905 lt 120583

2

minus120572120573119905120573minus1

119868 (119905) minus 119892 (119905) 1205832lt 119905 lt 119905

1

minus119890minus120575(119879minus119905)

119892 (119905) 1199051lt 119905 lt 119879

(19)

Solving the differential equation (19) with 119868(1199051) = 0 we have

119868 (119905) =

int

1205831

119905

119890120572(119909120573minus119905120573)119891 (119909) 119889119909 + 119863

0int

1205832

1205831

119890120572(119909120573minus119905120573)119889119909 + int

1199051

1205832

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 0 lt 119905 lt 120583

1

1198630int

1205832

119905

119890120572(119909120573minus119905120573)119889119909 + int

1199051

1205832

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 120583

1lt 119905 lt 120583

2

int

1199051

119905

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 120583

2lt 119905 lt 119905

1

minusint

119905

1199051

119890120575(119909minus119879)

119892 (119909) 119889119909 1199051lt 119905 lt 119879

(20)

The beginning inventory level can be computed as

119878 = 119868 (0)

= int

1205831

0

119890120572119909120573

119891 (119909) 119889119909

+ 1198630int

1205832

1205831

119890120572119909120573

119889119909 + int

1199051

1205832

119890120572119909120573

119892 (119909) 119889119909

(21)

The total number of items which perish in the interval [0 1199051]

is

119863119879= int

1205831

0

(119890120572119909120573

minus 1)119891 (119909) 119889119909 + 1198630int

1205832

1205831

(119890120572119909120573

minus 1) 119889119909

+ int

1199051

1205832

(119890120572119909120573

minus 1) 119892 (119909) 119889119909

(22)

The total number of inventory carried during the interval[0 1199051] is

119867119879= int

1205831

0

int

1205831

119905

119890120572(119909120573minus119905120573)119891 (119909) 119889119909 119889119905

+ 1198630int

1205831

0

int

1205832

1205831

119890120572(119909120573minus119905120573)119889119909 119889119905

+ 1198630int

1205832

1205831

int

1205832

119905

119890120572(119909120573minus119905120573)119889119909 119889119905

+ int

1205832

0

int

1199051

1205832

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 119889119905

+ int

1199051

1205832

int

1199051

119905

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 119889119905

(23)

The total shortage quantity during the interval [1199051 119879] is

119861119879= int

119879

1199051

(119879 minus 119905) 119890minus120575(119879minus119905)

119892 (119905) 119889119905 (24)

The total of lost sales during the interval [1199051 119879] is

119871119879= int

119879

1199051

(1 minus 119890minus120575(119879minus119905)

) 119892 (119905) 119889119905 (25)

Therefore the average total cost per unit time under thecondition 120583

2le 1199051le 119879 can be given by

1198623(1199051) =

1

119879[1198600+ 1198881119863119879+ 1198882119867119879+ 1198883119861119879+ 1198884119871119879]

=1

1198791198600+ 1198881[int

1205831

0

(119890120572119909120573

minus 1)119891 (119909) 119889119909

+ 1198630int

1205832

1205831

(119890120572119909120573

minus 1) 119889119909

+int

1199051

1205832

(119890120572119909120573

minus 1) 119892 (119909) 119889119909]

6 Journal of Applied Mathematics

+ 1198882[int

1205831

0

int

1205831

119905

119890120572(119909120573minus119905120573)119891 (119909) 119889119909 119889119905

+ 1198630int

1205831

0

int

1205832

1205831

119890120572(119909120573minus119905120573)119889119909 119889119905

+ 1198630int

1205832

1205831

int

1205832

119905

119890120572(119909120573minus119905120573)119889119909 119889119905

+ int

1205832

0

int

1199051

1205832

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 119889119905

+int

1199051

1205832

int

1199051

119905

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 119889119905]

+ 1198883[int

119879

1199051

(119879 minus 119905) 119890120575(119905minus119879)

119892 (119905) 119889119905]

+ 1198884[int

119879

1199051

(1 minus 119890120575(119905minus119879)

) 119892 (119905) 119889119905]

(26)

From the above analysis we obtain that the total average costof the model over the time interval [0 119879] is

119879119862 (1199051) =

1198621(1199051) 0 lt 119905

1le 1205831

1198622(1199051) 120583

1lt 1199051le 1205832

1198623(1199051) 120583

2lt 1199051lt 119879

(27)

where 1198621(1199051) 1198622(1199051) and 119862

3(1199051) are obtained from (10) (18)

and (26) respectivelyIn the following we will provide the results which ensure

the existence of a unique 1199051 say 119905lowast1 so as to minimize the total

average cost for the model system starting with no shortagesIf 0 lt 119905

1le 1205831 taking the first-order derivative of 119862

1(1199051)

with respect to 1199051 we obtain

1198891198621(1199051)

1198891199051

=119891 (1199051)

119879ℎ (1199051) (28)

where

ℎ (1199051) = 1198881(119890120572119905120573

1 minus 1)

+ 1198882int

1199051

0

119890120572(119905120573

1minus119905120573)119889119905 + 119888

3(1199051minus 119879) 119890

120575(1199051minus119879)

+ 1198884(119890120575(1199051minus119879)

minus 1)

(29)

then we can obtain ℎ(0) lt 0 and ℎ(119879) gt 0 By using theassumption (119905119890minus120575119905 is an increasing function where 119905 is thewaiting time up to the next replenishment) we have

119889ℎ (1199051)

1198891199051

= 120572120573119905120573minus1

1(1198881119890120572119905120573

1 + 1198882int

1199051

0

119890120572(119905120573

1minus119905120573)119889119905)

+ [1198883(120575 (1199051minus 119879) + 1) + 119888

4120575] 119890120575(1199051minus119879)

+ 1198882gt 0

(30)

which implies that ℎ(1199051) is a strictly monotone increasing

function Therefore the equation

ℎ (1199051) = 1198881(119890120572119905120573

1 minus 1) + 1198882int

1199051

0

119890120572(119905120573

1minus119905120573)119889119905

+ 1198883(1199051minus 119879) 119890

120575(1199051minus119879)

+ 1198884(119890120575(1199051minus119879)

minus 1)

= 0

(31)

has a unique root 119905lowast1isin (0 119879) obtained by using Mathematica

90 Further 119905lowast1is the only zero-point of 119889119862

1(1199051)1198891199051= 0 since

119891(1199051) gt 0If 0 lt 119905

lowast

1le 1205831 for this 119905lowast

1 we have

11988921198621(1199051)

1198891199052

1

1003816100381610038161003816100381610038161003816100381610038161199051=119905lowast

1

= 119891 (119905lowast

1)119889ℎ (119905lowast

1)

119879119889119905lowast

1

gt 0 (32)

which means that the total average cost 1198621(1199051) can obtain its

minimum value at 119905lowast1

The optimal value of the order level 119878 = 119868(0) is

119878lowast= int

119905lowast

1

0

119891 (119909) 119890120572119909120573

119889119909 (33)

and the optimal order quantity 119876lowast is

119876lowast= 119878lowast+ int

1205831

119905lowast

1

119890120575(119905minus119879)

119891 (119905) 119889119905

+ 1198630int

1205832

1205831

119890120575(119905minus119879)

119889119905 + int

119879

1205832

119890120575(119905minus119879)

119892 (119905) 119889119905

(34)

If 119905lowast1

ge 1205831 then the optimal value of 119862

1(1199051) is obtained at

1199051= 1205831

If 1205831lt 1199051le 1205832 taking the first-order and second-order

derivative of 1198622(1199051) with respect to 119905

1 respectively we obtain

1198891198622(1199051)

1198891199051

=1198630

119879ℎ (1199051) (35)

If 1205831lt 119905lowast

1le 1205832 for this 119905lowast

1 we have

11988921198622(1199051)

1198891199052

1

1003816100381610038161003816100381610038161003816100381610038161199051=119905lowast

1

= 1198630

119889ℎ (119905lowast

1)

119879119889119905lowast

1

gt 0 (36)

where the function ℎ(1199051) is given by (31) and (36) implies

that 1198622(1199051) is a strictly convex function in 119905

1and obtained its

minimum value at 119905lowast1 Therefore the equation ℎ(119905

1) = 0 has a

unique root 119905lowast1in (0 119879)

The optimal value of the order level 119878 = 119868(0) is

119878lowast= int

1205831

0

119891 (119909) 119890120572119909120573

119889119909 + 1198630int

119905lowast

1

1205831

119890120572119909120573

119889119909 (37)

and the optimal order quantity 119876lowast is

119876lowast= 119878lowast+ int

1205832

119905lowast

1

119890120575(119905minus119879)

1198630119889119905 + int

119879

1205832

119890120575(119905minus119879)

119892 (119905) 119889119905 (38)

Journal of Applied Mathematics 7

If 119905lowast1le 1205831 then the optimal value of 119862

2(1199051) is obtained at

119905lowast

1= 1205831 and if 119905lowast

1ge 1205832 then the optimal value of 119862

2(1199051) is

obtained at 119905lowast1= 1205832

If 1205832lt 1199051le 119879 taking the first-order and second-order

derivative of 1198623(1199051) with respect to 119905

1 respectively we obtain

1198891198623(1199051)

1198891199051

=119892 (1199051)

119879ℎ (1199051) (39)

If 1205832lt 119905lowast

1le 119879 for this 119905lowast

1 we have

11988921198623(1199051)

1198891199052

1

1003816100381610038161003816100381610038161003816100381610038161199051=119905lowast

1

= 119892 (119905lowast

1)119889ℎ (119905lowast

1)

119879119889119905lowast

1

gt 0 (40)

The function ℎ(1199051) is given by (31) and (40) implies that

1198623(1199051) can obtain its minimum value at 119905lowast

1

The optimal value of the order level 119878 = 119868(0) is

119878lowast= int

1205831

0

119890120572119909120573

119891 (119909) 119889119909 + 1198630int

1205832

1205831

119890120572119909120573

119889119909 + int

119905lowast

1

1205832

119890120572119909120573

119892 (119909) 119889119909

(41)

and the optimal order quantity 119876lowast is

119876lowast= 119878lowast+ int

119879

119905lowast

1

119890120575(119905minus119879)

119892 (119905) 119889119905 (42)

If 119905lowast1

le 1205832 then the optimal value of 119862

3(1199051) is obtained at

119905lowast

1= 1205832

The above analysis shows that the three average cost func-tions 119862

1(1199051) 1198622(1199052) and 119862

3(1199051) can obtain their minimum

value at 119905lowast1isin (0 119879) which is determined by (31) Therefore

based on the results analyzed above this paper derives aprocedure to locate the optimal replenishment policy startingwith no shortage for the three cases The procedure is asfollowsStep 1 Solve 119905lowast

1from (31)

Step 2 Compare 119905lowast1to 1205831and 120583

2 respectively

Step 21 If 119905lowast1isin (0 120583

1] then the optimal total average cost and

the optimal order quantity can be obtained by (10) and (34)respectivelyStep 22 If 119905lowast

1isin (1205831 1205832] then the optimal total average cost

and the optimal order quantity can be obtained by (18) and(38) respectively

Step 23 If 119905lowast1isin (1205832 119879] then the optimal total average cost

and the optimal order quantity can be obtained by (26) and(42) respectively

Remark 1 In such considered inventory model starting withno shortage if 119905

1satisfies 120583

1lt 1199051le 119879 lt 120583

2 the considered

inventory model reduces to that of Skouri et al [12]

4 Numerical Example

In order to demonstrate the above procedure which can beapplied to obtain the optimal solution of the model this

paper presents several examples for the model respectivelyExamples are based on piecewise demand rate such as119891(119905) =1198861+ 1198871119905 and 119892(119905) = 119886

2119890minus1198872119905

Example 1 The parameter values are given as follows 119879 = 12

weeks1205831= 4weeks120583

2= 8weeks120572 = 0005120573 = 2120575 = 004

1198861= 30 unit 119887

1= 5 unit 119886

2= 100 unit 119860

0= $500 119888

1= $2

1198882= $3 119888

3= $12 and 119888

4= $8

The model starting with no shortage by solving theequation ℎ(119905

1) = 0 we have 119905

lowast

1= 87622 From (42) and

(26) we obtain 119876lowast

= 5825217 and 119879119862(119905lowast

1) = 7939986

respectively

Example 2 Theparameter values are given as follows119879 = 12

weeks1205831= 4weeks120583

2= 8weeks120572 = 0005120573 = 2120575 = 002

1198861= 30 unit 119887

1= 5 unit 119886

2= 100 unit 119860

0= $500 119888

1= $5

1198882= $10 119888

3= $12 and 119888

4= $8

The model starting with no shortage by solving theequation ℎ(119905

1) = 0 we have 119905

lowast

1= 58330 From (38) and

(18) we obtain 119876lowast

= 5284725 and 119879119862(119905lowast

1) = 16014013

respectively

Example 3 Theparameter values are given as follows119879 = 12

weeks 1205831= 4 weeks 120583

2= 6 weeks 120572 = 0005 120573 = 16

120575 = 02 1198861= 30 unit 119887

1= 5 unit 119886

2= 100 unit 119860

0= $500

1198881= $5 119888

2= $10 119888

3= $12 and 119888

4= $8

Themodel starting with no shortage solving the equationℎ(1199051) = 0 the optimal value of 119905

1is 119905lowast1= 23235 The optimal

ordering quantity is 119876lowast = 2726678 and the minimum cost119879119862(119905lowast

1) = 125882

In order to clearly indicate the effects of parameters suchas 120575 120572 120573 119888

1 1198882 1198883 and 119888

4on the optimal on-hand inventory

119878lowast the optimal ordering quantity 119876

lowast and the optimal totalcost 119879119862(119905lowast

1) respectively the paper will study the sensitivity

of the optimal solution to changes in the value of differentparameter associated with the studied inventory model Thesensitivity analysis is performed on the base of Example 1 andthe results are shown in Table 1ndash7

By studying the results of Table 1 it is found that theshortage time 119905

lowast

1 inventory level 119878

lowast order quantity 119876lowast

and the total average cost 119879119862(119905lowast1) gradually decrease as the

shortage parameter 120575 increases for the model respectivelyWe also find that the percentage increase of 120575 from 143to 100 causes 119879119862(119905

lowast

1) to decrease from 045 to 034

119876lowast decrease from 075 to 052 119905lowast

1decrease from 078

to 053 and 119878lowast decrease from 102 to 069 It is also

observed that the value of 119905lowast1 119878lowast119876lowast and 119879119862(119905lowast

1) all are lowly

sensitive to the changes of 120575 for the considered inventorymodel

By studying the results of Table 2 it is found that 119878lowast 119876lowastand 119879119862(119905lowast

1) coordinates to the deterioration parameter 120572 the

shortage time 119905lowast1decreases as 120572 increases for the model It is

also found that the percentage increase of 120572 from 167 to100 causes 119879119862(119905lowast

1) to decrease by 2066ndash2595 119876lowast to

increase by 1597ndash244 the shortage time 119905lowast1to decrease

by 1513ndash1455 and 119878lowast to increase by 0917ndash1651 It

also observes that the value of 119905lowast1 119878lowast 119876lowast and 119879119862(119905

lowast

1) all are

moderately sensitive to the changes of 120572 for the consideredinventory model

8 Journal of Applied Mathematics

Table 1 The sensitivity of 120575 for the models in Example 1

120575 0 001 002 003 004 005 006 007 008119905lowast

189664 89187 88689 88167 87622 87049 86449 85817 85152

119878lowast 4729889 4697083 4662823 4627001 4589498 4550167 4508910 4465519 4419829119876lowast 5956569 5925872 5893822 5860308 5825217 5788412 5749771 5709112 5666265

TC(119905lowast1) 8056323 8028699 8000139 7970588 7939986 7908268 7875365 7841200 7805690

Table 2 The sensitivity of 120572 for the models in Example 1

120572 0 0001 0002 0003 0004 0005 0006 0007119905lowast

194545 93115 91702 90312 88950 87622 86328 85072

119878lowast 4283286 4354002 4420048 4481317 4537785 4589498 4636555 4679088119876lowast 5238866 5366685 5489558 5607091 5719025 5825217 5925618 6020259

TC(119905lowast1) 7046045 7228867 7410107 7589297 7766035 7939986 8110872 8278474

Table 3 The sensitivity of 120573 for the models in Example 1

120573 14 16 18 20 22 24 26 28119905lowast

192876 91810 90142 87622 84047 79422 74073 68496

119878lowast 4429058 4475894 4531802 4589076 4628345 4616422 4534686 4388904119876lowast 5451340 5541055 5664485 5824772 6012274 7746099 7664364 7518582

TC(119905lowast1) 7457703 7643043 7917624 7907114 8293653 5887417 4731282 3911266

Table 4 The sensitivity of 1198881for the models in Example 1

1198881

0 04 1 16 2 24 26 3 36119905lowast

188225 88103 87921 87741 87622 87503 87443 87326 87150

119878lowast 4630980 4622595 4610101 4597707 4589498 4581333 4577266 4569164 4557090119876lowast 5841909 5838529 5833499 5828514 5825217 5821940 5825217 5817061 5812226

TC(119905lowast1) 7835429 7856518 7887984 7919251 7939986 7960633 7970925 7991443 8022061

Table 5 The sensitivity of 1198882for the model in Example 1

1198882

0 04 08 12 18 24 3 34 38119905lowast

1118343 11267 107698 10326 97377 92216 87622 84819 82196

119878lowast 6737217 6330852 5979589 5669228 5261187 4905382 4589498 4396922 4216606119876lowast 6796039 6594483 6427261 6284787 6104744 5954175 5825217 5748648 5678284

TC(119905lowast1) 672679 1939216 3088975 4139636 5558150 6816692 7939986 8623253 9259516

Table 6 The sensitivity of 1198883for the models in Example 1

1198883

104 106 108 11 112 116 12 124 128119905lowast

184424 84859 85284 85698 86102 86879 87622 88329 89005

119878lowast 4369771 4399713 442889 4457332 4485071 453854 4589498 4638114 4684587119876lowast 5737973 5749747 5761255 5772506 5783509 5804809 5825217 5844787 5863587

TC(119905lowast1) 7638057 7679203 7719299 7758387 7796505 7869976 7939986 8006779 8070579

Table 7 The sensitivity of 1198884for the models in Example 1

1198884

0 2 4 6 8 10 12 14 16119905lowast

186989 87150 87309 87466 87622 87775 87928 88078 882272

119878lowast 4546069 4557103 4568017 4578815 4589498 4600048 4610527 4620877 4631120119876lowast 5807818 5812231 5816601 5820929 5825217 5829455 583367 5837837 5841966

TC(119905lowast1) 7881626 7896445 7911109 7925621 7939986 7954203 7968276 7982207 7995999

Journal of Applied Mathematics 9

By studying the results of Table 3 it is found that 119878lowast119876lowast and 119879119862(119905

lowast

1) coordinate to the deterioration parameter 120573

while the shortage time 119905lowast

1decreases as 120573 increases for the

model It is also found that the increase of 120573 from 14 to 22causes 119878

lowast to increase while the increase of 120573 from 24 to28 causes 119878lowast to decrease 119876lowast to increase by 244ndash1597119879119862(119905lowast

1) to increase by 2595ndash2066 and the shortage time

119905lowast

1to decrease by 1513ndash1455 It is also observed that the

value of 119905lowast1 119878lowast119876lowast and 119879119862(119905lowast

1) all are moderately sensitive to

the changes of 120573 for the considered inventory modelBy studying the results of Table 4 it is found that 119879119862(119905lowast

1)

coordinate to 1198881 while the shortage time 119905

lowast

1 119878lowast and 119876

lowast

decrease as 1198881increases for the model It is also found that 119888

1

increases from 83 to 150 119879119862(119905lowast1) decreases by 0269ndash

0383 119876lowast decreases by 0083ndash0058 119905lowast1decreases by

0264ndash0181 and 119878lowast decreases by 0203ndash0138 respec-tively It is also observed that the values of 119905lowast

1 119878lowast 119876lowast and

119879119862(119905lowast

1) all are lowly sensitive to the changes of 119888

1for the

considered inventory modelBy studying the results of Table 5 it is found that

119879119862(119905lowast

1) coordinates to 119888

2 while 119878

lowast 119876lowastand 119905lowast

1decrease as

1198881increases for the model It is also found that 119888

2increases

by 100 119879119862(119905lowast1) decreases by 0269ndash0383 119876lowast decreases

by 0083ndash0058 119905lowast1decreases by 0264ndash0181 and 119878

lowast

decreases by 0203ndash0138By studying the results of Table 6 it is found that 119905lowast

1 119878lowast

119876lowast and 119879119862(119905

lowast

1) coordinate to 119888

3 It is also observed that the

value of 119905lowast1 119878lowast 119876lowast and 119879119862(119905

lowast

1) all are lowly sensitive to the

changes of 1198883for the inventory models that is 119888

3increases

from 19 to 32 the change of all the parameters is nomorethan 1

By studying the results of Table 7 it is found that 119905lowast1 119878lowast

119876lowast and 119879119862(119905

lowast

1) coordinate to 119888

4 It is also observed that the

value of 119905lowast1 119878lowast 119876lowast and 119879119862(119905

lowast

1) all are lowly sensitive to the

changes of 1198884for the inventory models that is 119888

4increases

from 143 to 100 the change of all the parameters is nomore than 1

5 Conclusion

An inventory model starting without shortage for Weibull-distributed deterioration with trapezoidal type demand rateand partial backlogging is considered in this paper Theoptimal replenishment policy for the inventory model isproposed and numerical examples are provided to illustratethe theoretical results A sensitivity analysis of the optimalsolution with respect to major parameters is also carried outFrom Table 1ndash7 it can be found that the shortage time point119905lowast

1 order quantity 119876lowast and the total average cost 119879119862(119905lowast

1) are

moderately sensitive to the changes of 120572 and 120573 and lowlysensitive to the changes of 120575 119888

119894(119894 = 1 2 3 4) respectively

The paper provides an interesting topic for further studysuch that the joint influence from some of these parametersmay be investigated to show the effects the model startingwith shortage will be studied and other types of models fordeteriorating items in supply chain situation are also to bestudied in the future

Conflict of Interests

The author declares that there is no conflict of interestsregarding the publication of this paper

Acknowledgments

The author is grateful to the anonymous referees who pro-vided valuable comments and suggestions to significantlyimprove the quality of the paper This work was supportedpartly byHumanities and Social Science Fund of theMinistryof Education of China (no 11YJCZH019)

References

[1] P M Ghare and G F Schrader ldquoA model for exponentiallydecaying inventoriesrdquo Journal of Industrial Engineering vol 14pp 238ndash243 1963

[2] J-W Wu C Lin B Tan and W-C Lee ldquoAn EOQ inventorymodel with time-varying demand and Weibull deteriorationwith shortagesrdquo International Journal of Systems Science vol 31no 6 pp 677ndash683 2000

[3] H-M Wee ldquoDeteriorating inventory model with quantity dis-count pricing and partial backorderingrdquo International Journalof Production Economics vol 59 no 1 pp 511ndash518 1999

[4] K Skouri and S Papachristos ldquoA continuous review inven-tory model with deteriorating items time-varying demandlinear replenishment cost partially time-varying backloggingrdquoApplied Mathematical Modelling vol 26 no 5 pp 603ndash6172002

[5] H-MWee J C P Yu and S T Law ldquoTwo-warehouse inventorymodel with partial backordering and Weibull distributiondeterioration under inflationrdquo Journal of the Chinese Institute ofIndustrial Engineers vol 22 no 6 pp 451ndash462 2005

[6] C-Y Dye T-P Hsieh and L-Y Ouyang ldquoDetermining optimalselling price and lot size with a varying rate of deteriorationand exponential partial backloggingrdquo European Journal ofOperational Research vol 181 no 2 pp 668ndash678 2007

[7] R M Hill ldquoInventory models for increasing demand followedby level demandrdquo Journal of the Operational Research Societyvol 46 no 10 pp 1250ndash1259 1995

[8] B Mandal and A K Pal ldquoOrder level inventory system withramp type demand rate for deteriorating itemsrdquo Journal ofInterdisciplinary Mathematics vol 1 no 1 pp 49ndash66 1998

[9] K-S Wu ldquoAn EOQ inventory model for items with Weibulldistribution deterioration ramp type demand rate and partialbackloggingrdquo Production Planning amp Control vol 12 no 8 pp787ndash793 2001

[10] B C Giri A K Jalan and K S Chaudhuri ldquoEconomic orderquantity model with Weibull deterioration distribution short-age and ramp-type demandrdquo International Journal of SystemsScience vol 34 no 4 pp 237ndash243 2003

[11] S K Manna and K S Chaudhuri ldquoAn EOQ model withramp type demand rate time dependent deterioration rate unitproduction cost and shortagesrdquoEuropean Journal ofOperationalResearch vol 171 no 2 pp 557ndash566 2006

[12] K Skouri I Konstantaras S Papachristos and I Ganas ldquoInven-tory models with ramp type demand rate partial backloggingandWeibull deterioration raterdquoEuropean Journal ofOperationalResearch vol 192 no 1 pp 79ndash92 2009

10 Journal of Applied Mathematics

[13] K-C Hung ldquoAn inventory model with generalized typedemand deterioration and backorder ratesrdquo European Journalof Operational Research vol 208 no 3 pp 239ndash242 2011

[14] R S Kumar S K De and A Goswami ldquoFuzzy EOQ modelswith ramp type demand rate partial backlogging and timedependent deterioration raterdquo International Journal of Mathe-matics in Operational Research vol 4 no 5 pp 473ndash502 2012

[15] M B Cheng B X Zhang and G QWang ldquoOptimal policy fordeteriorating items with trapezoidal type demand and partialbackloggingrdquoAppliedMathematical Modelling vol 35 no 7 pp3552ndash3560 2011

[16] R Uthayakumar and M Rameswari ldquoAn economic produc-tion quantity model for defective items with trapezoidal typedemand raterdquo Journal of Optimization Theory and Applicationsvol 154 no 3 pp 1055ndash1079 2012

[17] Y Tan and M X Weng ldquoA discrete-in-time deterioratinginventory model with time-varying demand variable deterio-ration rate and waiting-time-dependent partial backloggingrdquoInternational Journal of Systems Science vol 44 no 8 pp 1483ndash1493 2013

[18] M A Ahmed T A Al-Khamis and L Benkherouf ldquoInventorymodels with ramp type demand rate partial backlogging andgeneral deterioration raterdquo Applied Mathematics and Computa-tion vol 219 no 9 pp 4288ndash4307 2013

[19] K-P Lin ldquoAn extended inventory models with trapezoidal typedemandsrdquo Applied Mathematics and Computation vol 219 no24 pp 11414ndash11419 2013

[20] P L Abad ldquoOptimal pricing and lot-sizing under conditionsof perishability and partial backorderingrdquoManagement Sciencevol 42 no 8 pp 1093ndash1104 1996

Submit your manuscripts athttpwwwhindawicom

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Mathematical Problems in Engineering

Hindawi Publishing Corporationhttpwwwhindawicom

Differential EquationsInternational Journal of

Volume 2014

Applied MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

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Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Mathematical PhysicsAdvances in

Complex AnalysisJournal of

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OptimizationJournal of

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CombinatoricsHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

International Journal of

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Operations ResearchAdvances in

Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Function Spaces

Abstract and Applied AnalysisHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

International Journal of Mathematics and Mathematical Sciences

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The Scientific World JournalHindawi Publishing Corporation httpwwwhindawicom Volume 2014

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Discrete Dynamics in Nature and Society

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Volume 2014 Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Stochastic AnalysisInternational Journal of

Page 5: Research Article An Inventory Model under Trapezoidal Type ...downloads.hindawi.com/journals/jam/2014/747419.pdf · an inventory model with Weibull-distributed deterioration items,

Journal of Applied Mathematics 5

+ 1198883[int

119879

1205832

(119879 minus 119905) 119890120575(119905minus119879)

119892 (119905) 119889119905

+1198630

120575(119890120575(1199051minus119879)

(119879 minus 1199051+1

120575)

minus119890120575(1205832minus119879)

(119879 minus 1205832+1

120575)) ]

+ 1198884[1198630int

1205832

1199051

(1 minus 119890120575(119905minus119879)

) 119889119905

+int

119879

1205832

(1 minus 119890120575(119905minus119879)

) 119892 (119905) 119889119905]

(18)

Case 3 (1205832le 1199051lt 119879) The differential equations governing

the inventory model can be expressed as follows

119889119868 (119905)

119889119905=

minus120572120573119905120573minus1

119868 (119905) minus 119891 (119905) 0 lt 119905 lt 1205831

minus120572120573119905120573minus1

119868 (119905) minus 1198630 120583

1lt 119905 lt 120583

2

minus120572120573119905120573minus1

119868 (119905) minus 119892 (119905) 1205832lt 119905 lt 119905

1

minus119890minus120575(119879minus119905)

119892 (119905) 1199051lt 119905 lt 119879

(19)

Solving the differential equation (19) with 119868(1199051) = 0 we have

119868 (119905) =

int

1205831

119905

119890120572(119909120573minus119905120573)119891 (119909) 119889119909 + 119863

0int

1205832

1205831

119890120572(119909120573minus119905120573)119889119909 + int

1199051

1205832

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 0 lt 119905 lt 120583

1

1198630int

1205832

119905

119890120572(119909120573minus119905120573)119889119909 + int

1199051

1205832

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 120583

1lt 119905 lt 120583

2

int

1199051

119905

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 120583

2lt 119905 lt 119905

1

minusint

119905

1199051

119890120575(119909minus119879)

119892 (119909) 119889119909 1199051lt 119905 lt 119879

(20)

The beginning inventory level can be computed as

119878 = 119868 (0)

= int

1205831

0

119890120572119909120573

119891 (119909) 119889119909

+ 1198630int

1205832

1205831

119890120572119909120573

119889119909 + int

1199051

1205832

119890120572119909120573

119892 (119909) 119889119909

(21)

The total number of items which perish in the interval [0 1199051]

is

119863119879= int

1205831

0

(119890120572119909120573

minus 1)119891 (119909) 119889119909 + 1198630int

1205832

1205831

(119890120572119909120573

minus 1) 119889119909

+ int

1199051

1205832

(119890120572119909120573

minus 1) 119892 (119909) 119889119909

(22)

The total number of inventory carried during the interval[0 1199051] is

119867119879= int

1205831

0

int

1205831

119905

119890120572(119909120573minus119905120573)119891 (119909) 119889119909 119889119905

+ 1198630int

1205831

0

int

1205832

1205831

119890120572(119909120573minus119905120573)119889119909 119889119905

+ 1198630int

1205832

1205831

int

1205832

119905

119890120572(119909120573minus119905120573)119889119909 119889119905

+ int

1205832

0

int

1199051

1205832

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 119889119905

+ int

1199051

1205832

int

1199051

119905

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 119889119905

(23)

The total shortage quantity during the interval [1199051 119879] is

119861119879= int

119879

1199051

(119879 minus 119905) 119890minus120575(119879minus119905)

119892 (119905) 119889119905 (24)

The total of lost sales during the interval [1199051 119879] is

119871119879= int

119879

1199051

(1 minus 119890minus120575(119879minus119905)

) 119892 (119905) 119889119905 (25)

Therefore the average total cost per unit time under thecondition 120583

2le 1199051le 119879 can be given by

1198623(1199051) =

1

119879[1198600+ 1198881119863119879+ 1198882119867119879+ 1198883119861119879+ 1198884119871119879]

=1

1198791198600+ 1198881[int

1205831

0

(119890120572119909120573

minus 1)119891 (119909) 119889119909

+ 1198630int

1205832

1205831

(119890120572119909120573

minus 1) 119889119909

+int

1199051

1205832

(119890120572119909120573

minus 1) 119892 (119909) 119889119909]

6 Journal of Applied Mathematics

+ 1198882[int

1205831

0

int

1205831

119905

119890120572(119909120573minus119905120573)119891 (119909) 119889119909 119889119905

+ 1198630int

1205831

0

int

1205832

1205831

119890120572(119909120573minus119905120573)119889119909 119889119905

+ 1198630int

1205832

1205831

int

1205832

119905

119890120572(119909120573minus119905120573)119889119909 119889119905

+ int

1205832

0

int

1199051

1205832

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 119889119905

+int

1199051

1205832

int

1199051

119905

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 119889119905]

+ 1198883[int

119879

1199051

(119879 minus 119905) 119890120575(119905minus119879)

119892 (119905) 119889119905]

+ 1198884[int

119879

1199051

(1 minus 119890120575(119905minus119879)

) 119892 (119905) 119889119905]

(26)

From the above analysis we obtain that the total average costof the model over the time interval [0 119879] is

119879119862 (1199051) =

1198621(1199051) 0 lt 119905

1le 1205831

1198622(1199051) 120583

1lt 1199051le 1205832

1198623(1199051) 120583

2lt 1199051lt 119879

(27)

where 1198621(1199051) 1198622(1199051) and 119862

3(1199051) are obtained from (10) (18)

and (26) respectivelyIn the following we will provide the results which ensure

the existence of a unique 1199051 say 119905lowast1 so as to minimize the total

average cost for the model system starting with no shortagesIf 0 lt 119905

1le 1205831 taking the first-order derivative of 119862

1(1199051)

with respect to 1199051 we obtain

1198891198621(1199051)

1198891199051

=119891 (1199051)

119879ℎ (1199051) (28)

where

ℎ (1199051) = 1198881(119890120572119905120573

1 minus 1)

+ 1198882int

1199051

0

119890120572(119905120573

1minus119905120573)119889119905 + 119888

3(1199051minus 119879) 119890

120575(1199051minus119879)

+ 1198884(119890120575(1199051minus119879)

minus 1)

(29)

then we can obtain ℎ(0) lt 0 and ℎ(119879) gt 0 By using theassumption (119905119890minus120575119905 is an increasing function where 119905 is thewaiting time up to the next replenishment) we have

119889ℎ (1199051)

1198891199051

= 120572120573119905120573minus1

1(1198881119890120572119905120573

1 + 1198882int

1199051

0

119890120572(119905120573

1minus119905120573)119889119905)

+ [1198883(120575 (1199051minus 119879) + 1) + 119888

4120575] 119890120575(1199051minus119879)

+ 1198882gt 0

(30)

which implies that ℎ(1199051) is a strictly monotone increasing

function Therefore the equation

ℎ (1199051) = 1198881(119890120572119905120573

1 minus 1) + 1198882int

1199051

0

119890120572(119905120573

1minus119905120573)119889119905

+ 1198883(1199051minus 119879) 119890

120575(1199051minus119879)

+ 1198884(119890120575(1199051minus119879)

minus 1)

= 0

(31)

has a unique root 119905lowast1isin (0 119879) obtained by using Mathematica

90 Further 119905lowast1is the only zero-point of 119889119862

1(1199051)1198891199051= 0 since

119891(1199051) gt 0If 0 lt 119905

lowast

1le 1205831 for this 119905lowast

1 we have

11988921198621(1199051)

1198891199052

1

1003816100381610038161003816100381610038161003816100381610038161199051=119905lowast

1

= 119891 (119905lowast

1)119889ℎ (119905lowast

1)

119879119889119905lowast

1

gt 0 (32)

which means that the total average cost 1198621(1199051) can obtain its

minimum value at 119905lowast1

The optimal value of the order level 119878 = 119868(0) is

119878lowast= int

119905lowast

1

0

119891 (119909) 119890120572119909120573

119889119909 (33)

and the optimal order quantity 119876lowast is

119876lowast= 119878lowast+ int

1205831

119905lowast

1

119890120575(119905minus119879)

119891 (119905) 119889119905

+ 1198630int

1205832

1205831

119890120575(119905minus119879)

119889119905 + int

119879

1205832

119890120575(119905minus119879)

119892 (119905) 119889119905

(34)

If 119905lowast1

ge 1205831 then the optimal value of 119862

1(1199051) is obtained at

1199051= 1205831

If 1205831lt 1199051le 1205832 taking the first-order and second-order

derivative of 1198622(1199051) with respect to 119905

1 respectively we obtain

1198891198622(1199051)

1198891199051

=1198630

119879ℎ (1199051) (35)

If 1205831lt 119905lowast

1le 1205832 for this 119905lowast

1 we have

11988921198622(1199051)

1198891199052

1

1003816100381610038161003816100381610038161003816100381610038161199051=119905lowast

1

= 1198630

119889ℎ (119905lowast

1)

119879119889119905lowast

1

gt 0 (36)

where the function ℎ(1199051) is given by (31) and (36) implies

that 1198622(1199051) is a strictly convex function in 119905

1and obtained its

minimum value at 119905lowast1 Therefore the equation ℎ(119905

1) = 0 has a

unique root 119905lowast1in (0 119879)

The optimal value of the order level 119878 = 119868(0) is

119878lowast= int

1205831

0

119891 (119909) 119890120572119909120573

119889119909 + 1198630int

119905lowast

1

1205831

119890120572119909120573

119889119909 (37)

and the optimal order quantity 119876lowast is

119876lowast= 119878lowast+ int

1205832

119905lowast

1

119890120575(119905minus119879)

1198630119889119905 + int

119879

1205832

119890120575(119905minus119879)

119892 (119905) 119889119905 (38)

Journal of Applied Mathematics 7

If 119905lowast1le 1205831 then the optimal value of 119862

2(1199051) is obtained at

119905lowast

1= 1205831 and if 119905lowast

1ge 1205832 then the optimal value of 119862

2(1199051) is

obtained at 119905lowast1= 1205832

If 1205832lt 1199051le 119879 taking the first-order and second-order

derivative of 1198623(1199051) with respect to 119905

1 respectively we obtain

1198891198623(1199051)

1198891199051

=119892 (1199051)

119879ℎ (1199051) (39)

If 1205832lt 119905lowast

1le 119879 for this 119905lowast

1 we have

11988921198623(1199051)

1198891199052

1

1003816100381610038161003816100381610038161003816100381610038161199051=119905lowast

1

= 119892 (119905lowast

1)119889ℎ (119905lowast

1)

119879119889119905lowast

1

gt 0 (40)

The function ℎ(1199051) is given by (31) and (40) implies that

1198623(1199051) can obtain its minimum value at 119905lowast

1

The optimal value of the order level 119878 = 119868(0) is

119878lowast= int

1205831

0

119890120572119909120573

119891 (119909) 119889119909 + 1198630int

1205832

1205831

119890120572119909120573

119889119909 + int

119905lowast

1

1205832

119890120572119909120573

119892 (119909) 119889119909

(41)

and the optimal order quantity 119876lowast is

119876lowast= 119878lowast+ int

119879

119905lowast

1

119890120575(119905minus119879)

119892 (119905) 119889119905 (42)

If 119905lowast1

le 1205832 then the optimal value of 119862

3(1199051) is obtained at

119905lowast

1= 1205832

The above analysis shows that the three average cost func-tions 119862

1(1199051) 1198622(1199052) and 119862

3(1199051) can obtain their minimum

value at 119905lowast1isin (0 119879) which is determined by (31) Therefore

based on the results analyzed above this paper derives aprocedure to locate the optimal replenishment policy startingwith no shortage for the three cases The procedure is asfollowsStep 1 Solve 119905lowast

1from (31)

Step 2 Compare 119905lowast1to 1205831and 120583

2 respectively

Step 21 If 119905lowast1isin (0 120583

1] then the optimal total average cost and

the optimal order quantity can be obtained by (10) and (34)respectivelyStep 22 If 119905lowast

1isin (1205831 1205832] then the optimal total average cost

and the optimal order quantity can be obtained by (18) and(38) respectively

Step 23 If 119905lowast1isin (1205832 119879] then the optimal total average cost

and the optimal order quantity can be obtained by (26) and(42) respectively

Remark 1 In such considered inventory model starting withno shortage if 119905

1satisfies 120583

1lt 1199051le 119879 lt 120583

2 the considered

inventory model reduces to that of Skouri et al [12]

4 Numerical Example

In order to demonstrate the above procedure which can beapplied to obtain the optimal solution of the model this

paper presents several examples for the model respectivelyExamples are based on piecewise demand rate such as119891(119905) =1198861+ 1198871119905 and 119892(119905) = 119886

2119890minus1198872119905

Example 1 The parameter values are given as follows 119879 = 12

weeks1205831= 4weeks120583

2= 8weeks120572 = 0005120573 = 2120575 = 004

1198861= 30 unit 119887

1= 5 unit 119886

2= 100 unit 119860

0= $500 119888

1= $2

1198882= $3 119888

3= $12 and 119888

4= $8

The model starting with no shortage by solving theequation ℎ(119905

1) = 0 we have 119905

lowast

1= 87622 From (42) and

(26) we obtain 119876lowast

= 5825217 and 119879119862(119905lowast

1) = 7939986

respectively

Example 2 Theparameter values are given as follows119879 = 12

weeks1205831= 4weeks120583

2= 8weeks120572 = 0005120573 = 2120575 = 002

1198861= 30 unit 119887

1= 5 unit 119886

2= 100 unit 119860

0= $500 119888

1= $5

1198882= $10 119888

3= $12 and 119888

4= $8

The model starting with no shortage by solving theequation ℎ(119905

1) = 0 we have 119905

lowast

1= 58330 From (38) and

(18) we obtain 119876lowast

= 5284725 and 119879119862(119905lowast

1) = 16014013

respectively

Example 3 Theparameter values are given as follows119879 = 12

weeks 1205831= 4 weeks 120583

2= 6 weeks 120572 = 0005 120573 = 16

120575 = 02 1198861= 30 unit 119887

1= 5 unit 119886

2= 100 unit 119860

0= $500

1198881= $5 119888

2= $10 119888

3= $12 and 119888

4= $8

Themodel starting with no shortage solving the equationℎ(1199051) = 0 the optimal value of 119905

1is 119905lowast1= 23235 The optimal

ordering quantity is 119876lowast = 2726678 and the minimum cost119879119862(119905lowast

1) = 125882

In order to clearly indicate the effects of parameters suchas 120575 120572 120573 119888

1 1198882 1198883 and 119888

4on the optimal on-hand inventory

119878lowast the optimal ordering quantity 119876

lowast and the optimal totalcost 119879119862(119905lowast

1) respectively the paper will study the sensitivity

of the optimal solution to changes in the value of differentparameter associated with the studied inventory model Thesensitivity analysis is performed on the base of Example 1 andthe results are shown in Table 1ndash7

By studying the results of Table 1 it is found that theshortage time 119905

lowast

1 inventory level 119878

lowast order quantity 119876lowast

and the total average cost 119879119862(119905lowast1) gradually decrease as the

shortage parameter 120575 increases for the model respectivelyWe also find that the percentage increase of 120575 from 143to 100 causes 119879119862(119905

lowast

1) to decrease from 045 to 034

119876lowast decrease from 075 to 052 119905lowast

1decrease from 078

to 053 and 119878lowast decrease from 102 to 069 It is also

observed that the value of 119905lowast1 119878lowast119876lowast and 119879119862(119905lowast

1) all are lowly

sensitive to the changes of 120575 for the considered inventorymodel

By studying the results of Table 2 it is found that 119878lowast 119876lowastand 119879119862(119905lowast

1) coordinates to the deterioration parameter 120572 the

shortage time 119905lowast1decreases as 120572 increases for the model It is

also found that the percentage increase of 120572 from 167 to100 causes 119879119862(119905lowast

1) to decrease by 2066ndash2595 119876lowast to

increase by 1597ndash244 the shortage time 119905lowast1to decrease

by 1513ndash1455 and 119878lowast to increase by 0917ndash1651 It

also observes that the value of 119905lowast1 119878lowast 119876lowast and 119879119862(119905

lowast

1) all are

moderately sensitive to the changes of 120572 for the consideredinventory model

8 Journal of Applied Mathematics

Table 1 The sensitivity of 120575 for the models in Example 1

120575 0 001 002 003 004 005 006 007 008119905lowast

189664 89187 88689 88167 87622 87049 86449 85817 85152

119878lowast 4729889 4697083 4662823 4627001 4589498 4550167 4508910 4465519 4419829119876lowast 5956569 5925872 5893822 5860308 5825217 5788412 5749771 5709112 5666265

TC(119905lowast1) 8056323 8028699 8000139 7970588 7939986 7908268 7875365 7841200 7805690

Table 2 The sensitivity of 120572 for the models in Example 1

120572 0 0001 0002 0003 0004 0005 0006 0007119905lowast

194545 93115 91702 90312 88950 87622 86328 85072

119878lowast 4283286 4354002 4420048 4481317 4537785 4589498 4636555 4679088119876lowast 5238866 5366685 5489558 5607091 5719025 5825217 5925618 6020259

TC(119905lowast1) 7046045 7228867 7410107 7589297 7766035 7939986 8110872 8278474

Table 3 The sensitivity of 120573 for the models in Example 1

120573 14 16 18 20 22 24 26 28119905lowast

192876 91810 90142 87622 84047 79422 74073 68496

119878lowast 4429058 4475894 4531802 4589076 4628345 4616422 4534686 4388904119876lowast 5451340 5541055 5664485 5824772 6012274 7746099 7664364 7518582

TC(119905lowast1) 7457703 7643043 7917624 7907114 8293653 5887417 4731282 3911266

Table 4 The sensitivity of 1198881for the models in Example 1

1198881

0 04 1 16 2 24 26 3 36119905lowast

188225 88103 87921 87741 87622 87503 87443 87326 87150

119878lowast 4630980 4622595 4610101 4597707 4589498 4581333 4577266 4569164 4557090119876lowast 5841909 5838529 5833499 5828514 5825217 5821940 5825217 5817061 5812226

TC(119905lowast1) 7835429 7856518 7887984 7919251 7939986 7960633 7970925 7991443 8022061

Table 5 The sensitivity of 1198882for the model in Example 1

1198882

0 04 08 12 18 24 3 34 38119905lowast

1118343 11267 107698 10326 97377 92216 87622 84819 82196

119878lowast 6737217 6330852 5979589 5669228 5261187 4905382 4589498 4396922 4216606119876lowast 6796039 6594483 6427261 6284787 6104744 5954175 5825217 5748648 5678284

TC(119905lowast1) 672679 1939216 3088975 4139636 5558150 6816692 7939986 8623253 9259516

Table 6 The sensitivity of 1198883for the models in Example 1

1198883

104 106 108 11 112 116 12 124 128119905lowast

184424 84859 85284 85698 86102 86879 87622 88329 89005

119878lowast 4369771 4399713 442889 4457332 4485071 453854 4589498 4638114 4684587119876lowast 5737973 5749747 5761255 5772506 5783509 5804809 5825217 5844787 5863587

TC(119905lowast1) 7638057 7679203 7719299 7758387 7796505 7869976 7939986 8006779 8070579

Table 7 The sensitivity of 1198884for the models in Example 1

1198884

0 2 4 6 8 10 12 14 16119905lowast

186989 87150 87309 87466 87622 87775 87928 88078 882272

119878lowast 4546069 4557103 4568017 4578815 4589498 4600048 4610527 4620877 4631120119876lowast 5807818 5812231 5816601 5820929 5825217 5829455 583367 5837837 5841966

TC(119905lowast1) 7881626 7896445 7911109 7925621 7939986 7954203 7968276 7982207 7995999

Journal of Applied Mathematics 9

By studying the results of Table 3 it is found that 119878lowast119876lowast and 119879119862(119905

lowast

1) coordinate to the deterioration parameter 120573

while the shortage time 119905lowast

1decreases as 120573 increases for the

model It is also found that the increase of 120573 from 14 to 22causes 119878

lowast to increase while the increase of 120573 from 24 to28 causes 119878lowast to decrease 119876lowast to increase by 244ndash1597119879119862(119905lowast

1) to increase by 2595ndash2066 and the shortage time

119905lowast

1to decrease by 1513ndash1455 It is also observed that the

value of 119905lowast1 119878lowast119876lowast and 119879119862(119905lowast

1) all are moderately sensitive to

the changes of 120573 for the considered inventory modelBy studying the results of Table 4 it is found that 119879119862(119905lowast

1)

coordinate to 1198881 while the shortage time 119905

lowast

1 119878lowast and 119876

lowast

decrease as 1198881increases for the model It is also found that 119888

1

increases from 83 to 150 119879119862(119905lowast1) decreases by 0269ndash

0383 119876lowast decreases by 0083ndash0058 119905lowast1decreases by

0264ndash0181 and 119878lowast decreases by 0203ndash0138 respec-tively It is also observed that the values of 119905lowast

1 119878lowast 119876lowast and

119879119862(119905lowast

1) all are lowly sensitive to the changes of 119888

1for the

considered inventory modelBy studying the results of Table 5 it is found that

119879119862(119905lowast

1) coordinates to 119888

2 while 119878

lowast 119876lowastand 119905lowast

1decrease as

1198881increases for the model It is also found that 119888

2increases

by 100 119879119862(119905lowast1) decreases by 0269ndash0383 119876lowast decreases

by 0083ndash0058 119905lowast1decreases by 0264ndash0181 and 119878

lowast

decreases by 0203ndash0138By studying the results of Table 6 it is found that 119905lowast

1 119878lowast

119876lowast and 119879119862(119905

lowast

1) coordinate to 119888

3 It is also observed that the

value of 119905lowast1 119878lowast 119876lowast and 119879119862(119905

lowast

1) all are lowly sensitive to the

changes of 1198883for the inventory models that is 119888

3increases

from 19 to 32 the change of all the parameters is nomorethan 1

By studying the results of Table 7 it is found that 119905lowast1 119878lowast

119876lowast and 119879119862(119905

lowast

1) coordinate to 119888

4 It is also observed that the

value of 119905lowast1 119878lowast 119876lowast and 119879119862(119905

lowast

1) all are lowly sensitive to the

changes of 1198884for the inventory models that is 119888

4increases

from 143 to 100 the change of all the parameters is nomore than 1

5 Conclusion

An inventory model starting without shortage for Weibull-distributed deterioration with trapezoidal type demand rateand partial backlogging is considered in this paper Theoptimal replenishment policy for the inventory model isproposed and numerical examples are provided to illustratethe theoretical results A sensitivity analysis of the optimalsolution with respect to major parameters is also carried outFrom Table 1ndash7 it can be found that the shortage time point119905lowast

1 order quantity 119876lowast and the total average cost 119879119862(119905lowast

1) are

moderately sensitive to the changes of 120572 and 120573 and lowlysensitive to the changes of 120575 119888

119894(119894 = 1 2 3 4) respectively

The paper provides an interesting topic for further studysuch that the joint influence from some of these parametersmay be investigated to show the effects the model startingwith shortage will be studied and other types of models fordeteriorating items in supply chain situation are also to bestudied in the future

Conflict of Interests

The author declares that there is no conflict of interestsregarding the publication of this paper

Acknowledgments

The author is grateful to the anonymous referees who pro-vided valuable comments and suggestions to significantlyimprove the quality of the paper This work was supportedpartly byHumanities and Social Science Fund of theMinistryof Education of China (no 11YJCZH019)

References

[1] P M Ghare and G F Schrader ldquoA model for exponentiallydecaying inventoriesrdquo Journal of Industrial Engineering vol 14pp 238ndash243 1963

[2] J-W Wu C Lin B Tan and W-C Lee ldquoAn EOQ inventorymodel with time-varying demand and Weibull deteriorationwith shortagesrdquo International Journal of Systems Science vol 31no 6 pp 677ndash683 2000

[3] H-M Wee ldquoDeteriorating inventory model with quantity dis-count pricing and partial backorderingrdquo International Journalof Production Economics vol 59 no 1 pp 511ndash518 1999

[4] K Skouri and S Papachristos ldquoA continuous review inven-tory model with deteriorating items time-varying demandlinear replenishment cost partially time-varying backloggingrdquoApplied Mathematical Modelling vol 26 no 5 pp 603ndash6172002

[5] H-MWee J C P Yu and S T Law ldquoTwo-warehouse inventorymodel with partial backordering and Weibull distributiondeterioration under inflationrdquo Journal of the Chinese Institute ofIndustrial Engineers vol 22 no 6 pp 451ndash462 2005

[6] C-Y Dye T-P Hsieh and L-Y Ouyang ldquoDetermining optimalselling price and lot size with a varying rate of deteriorationand exponential partial backloggingrdquo European Journal ofOperational Research vol 181 no 2 pp 668ndash678 2007

[7] R M Hill ldquoInventory models for increasing demand followedby level demandrdquo Journal of the Operational Research Societyvol 46 no 10 pp 1250ndash1259 1995

[8] B Mandal and A K Pal ldquoOrder level inventory system withramp type demand rate for deteriorating itemsrdquo Journal ofInterdisciplinary Mathematics vol 1 no 1 pp 49ndash66 1998

[9] K-S Wu ldquoAn EOQ inventory model for items with Weibulldistribution deterioration ramp type demand rate and partialbackloggingrdquo Production Planning amp Control vol 12 no 8 pp787ndash793 2001

[10] B C Giri A K Jalan and K S Chaudhuri ldquoEconomic orderquantity model with Weibull deterioration distribution short-age and ramp-type demandrdquo International Journal of SystemsScience vol 34 no 4 pp 237ndash243 2003

[11] S K Manna and K S Chaudhuri ldquoAn EOQ model withramp type demand rate time dependent deterioration rate unitproduction cost and shortagesrdquoEuropean Journal ofOperationalResearch vol 171 no 2 pp 557ndash566 2006

[12] K Skouri I Konstantaras S Papachristos and I Ganas ldquoInven-tory models with ramp type demand rate partial backloggingandWeibull deterioration raterdquoEuropean Journal ofOperationalResearch vol 192 no 1 pp 79ndash92 2009

10 Journal of Applied Mathematics

[13] K-C Hung ldquoAn inventory model with generalized typedemand deterioration and backorder ratesrdquo European Journalof Operational Research vol 208 no 3 pp 239ndash242 2011

[14] R S Kumar S K De and A Goswami ldquoFuzzy EOQ modelswith ramp type demand rate partial backlogging and timedependent deterioration raterdquo International Journal of Mathe-matics in Operational Research vol 4 no 5 pp 473ndash502 2012

[15] M B Cheng B X Zhang and G QWang ldquoOptimal policy fordeteriorating items with trapezoidal type demand and partialbackloggingrdquoAppliedMathematical Modelling vol 35 no 7 pp3552ndash3560 2011

[16] R Uthayakumar and M Rameswari ldquoAn economic produc-tion quantity model for defective items with trapezoidal typedemand raterdquo Journal of Optimization Theory and Applicationsvol 154 no 3 pp 1055ndash1079 2012

[17] Y Tan and M X Weng ldquoA discrete-in-time deterioratinginventory model with time-varying demand variable deterio-ration rate and waiting-time-dependent partial backloggingrdquoInternational Journal of Systems Science vol 44 no 8 pp 1483ndash1493 2013

[18] M A Ahmed T A Al-Khamis and L Benkherouf ldquoInventorymodels with ramp type demand rate partial backlogging andgeneral deterioration raterdquo Applied Mathematics and Computa-tion vol 219 no 9 pp 4288ndash4307 2013

[19] K-P Lin ldquoAn extended inventory models with trapezoidal typedemandsrdquo Applied Mathematics and Computation vol 219 no24 pp 11414ndash11419 2013

[20] P L Abad ldquoOptimal pricing and lot-sizing under conditionsof perishability and partial backorderingrdquoManagement Sciencevol 42 no 8 pp 1093ndash1104 1996

Submit your manuscripts athttpwwwhindawicom

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Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Mathematical Problems in Engineering

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Differential EquationsInternational Journal of

Volume 2014

Applied MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

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CombinatoricsHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

International Journal of

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Journal of

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Function Spaces

Abstract and Applied AnalysisHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

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Volume 2014 Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Stochastic AnalysisInternational Journal of

Page 6: Research Article An Inventory Model under Trapezoidal Type ...downloads.hindawi.com/journals/jam/2014/747419.pdf · an inventory model with Weibull-distributed deterioration items,

6 Journal of Applied Mathematics

+ 1198882[int

1205831

0

int

1205831

119905

119890120572(119909120573minus119905120573)119891 (119909) 119889119909 119889119905

+ 1198630int

1205831

0

int

1205832

1205831

119890120572(119909120573minus119905120573)119889119909 119889119905

+ 1198630int

1205832

1205831

int

1205832

119905

119890120572(119909120573minus119905120573)119889119909 119889119905

+ int

1205832

0

int

1199051

1205832

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 119889119905

+int

1199051

1205832

int

1199051

119905

119890120572(119909120573minus119905120573)119892 (119909) 119889119909 119889119905]

+ 1198883[int

119879

1199051

(119879 minus 119905) 119890120575(119905minus119879)

119892 (119905) 119889119905]

+ 1198884[int

119879

1199051

(1 minus 119890120575(119905minus119879)

) 119892 (119905) 119889119905]

(26)

From the above analysis we obtain that the total average costof the model over the time interval [0 119879] is

119879119862 (1199051) =

1198621(1199051) 0 lt 119905

1le 1205831

1198622(1199051) 120583

1lt 1199051le 1205832

1198623(1199051) 120583

2lt 1199051lt 119879

(27)

where 1198621(1199051) 1198622(1199051) and 119862

3(1199051) are obtained from (10) (18)

and (26) respectivelyIn the following we will provide the results which ensure

the existence of a unique 1199051 say 119905lowast1 so as to minimize the total

average cost for the model system starting with no shortagesIf 0 lt 119905

1le 1205831 taking the first-order derivative of 119862

1(1199051)

with respect to 1199051 we obtain

1198891198621(1199051)

1198891199051

=119891 (1199051)

119879ℎ (1199051) (28)

where

ℎ (1199051) = 1198881(119890120572119905120573

1 minus 1)

+ 1198882int

1199051

0

119890120572(119905120573

1minus119905120573)119889119905 + 119888

3(1199051minus 119879) 119890

120575(1199051minus119879)

+ 1198884(119890120575(1199051minus119879)

minus 1)

(29)

then we can obtain ℎ(0) lt 0 and ℎ(119879) gt 0 By using theassumption (119905119890minus120575119905 is an increasing function where 119905 is thewaiting time up to the next replenishment) we have

119889ℎ (1199051)

1198891199051

= 120572120573119905120573minus1

1(1198881119890120572119905120573

1 + 1198882int

1199051

0

119890120572(119905120573

1minus119905120573)119889119905)

+ [1198883(120575 (1199051minus 119879) + 1) + 119888

4120575] 119890120575(1199051minus119879)

+ 1198882gt 0

(30)

which implies that ℎ(1199051) is a strictly monotone increasing

function Therefore the equation

ℎ (1199051) = 1198881(119890120572119905120573

1 minus 1) + 1198882int

1199051

0

119890120572(119905120573

1minus119905120573)119889119905

+ 1198883(1199051minus 119879) 119890

120575(1199051minus119879)

+ 1198884(119890120575(1199051minus119879)

minus 1)

= 0

(31)

has a unique root 119905lowast1isin (0 119879) obtained by using Mathematica

90 Further 119905lowast1is the only zero-point of 119889119862

1(1199051)1198891199051= 0 since

119891(1199051) gt 0If 0 lt 119905

lowast

1le 1205831 for this 119905lowast

1 we have

11988921198621(1199051)

1198891199052

1

1003816100381610038161003816100381610038161003816100381610038161199051=119905lowast

1

= 119891 (119905lowast

1)119889ℎ (119905lowast

1)

119879119889119905lowast

1

gt 0 (32)

which means that the total average cost 1198621(1199051) can obtain its

minimum value at 119905lowast1

The optimal value of the order level 119878 = 119868(0) is

119878lowast= int

119905lowast

1

0

119891 (119909) 119890120572119909120573

119889119909 (33)

and the optimal order quantity 119876lowast is

119876lowast= 119878lowast+ int

1205831

119905lowast

1

119890120575(119905minus119879)

119891 (119905) 119889119905

+ 1198630int

1205832

1205831

119890120575(119905minus119879)

119889119905 + int

119879

1205832

119890120575(119905minus119879)

119892 (119905) 119889119905

(34)

If 119905lowast1

ge 1205831 then the optimal value of 119862

1(1199051) is obtained at

1199051= 1205831

If 1205831lt 1199051le 1205832 taking the first-order and second-order

derivative of 1198622(1199051) with respect to 119905

1 respectively we obtain

1198891198622(1199051)

1198891199051

=1198630

119879ℎ (1199051) (35)

If 1205831lt 119905lowast

1le 1205832 for this 119905lowast

1 we have

11988921198622(1199051)

1198891199052

1

1003816100381610038161003816100381610038161003816100381610038161199051=119905lowast

1

= 1198630

119889ℎ (119905lowast

1)

119879119889119905lowast

1

gt 0 (36)

where the function ℎ(1199051) is given by (31) and (36) implies

that 1198622(1199051) is a strictly convex function in 119905

1and obtained its

minimum value at 119905lowast1 Therefore the equation ℎ(119905

1) = 0 has a

unique root 119905lowast1in (0 119879)

The optimal value of the order level 119878 = 119868(0) is

119878lowast= int

1205831

0

119891 (119909) 119890120572119909120573

119889119909 + 1198630int

119905lowast

1

1205831

119890120572119909120573

119889119909 (37)

and the optimal order quantity 119876lowast is

119876lowast= 119878lowast+ int

1205832

119905lowast

1

119890120575(119905minus119879)

1198630119889119905 + int

119879

1205832

119890120575(119905minus119879)

119892 (119905) 119889119905 (38)

Journal of Applied Mathematics 7

If 119905lowast1le 1205831 then the optimal value of 119862

2(1199051) is obtained at

119905lowast

1= 1205831 and if 119905lowast

1ge 1205832 then the optimal value of 119862

2(1199051) is

obtained at 119905lowast1= 1205832

If 1205832lt 1199051le 119879 taking the first-order and second-order

derivative of 1198623(1199051) with respect to 119905

1 respectively we obtain

1198891198623(1199051)

1198891199051

=119892 (1199051)

119879ℎ (1199051) (39)

If 1205832lt 119905lowast

1le 119879 for this 119905lowast

1 we have

11988921198623(1199051)

1198891199052

1

1003816100381610038161003816100381610038161003816100381610038161199051=119905lowast

1

= 119892 (119905lowast

1)119889ℎ (119905lowast

1)

119879119889119905lowast

1

gt 0 (40)

The function ℎ(1199051) is given by (31) and (40) implies that

1198623(1199051) can obtain its minimum value at 119905lowast

1

The optimal value of the order level 119878 = 119868(0) is

119878lowast= int

1205831

0

119890120572119909120573

119891 (119909) 119889119909 + 1198630int

1205832

1205831

119890120572119909120573

119889119909 + int

119905lowast

1

1205832

119890120572119909120573

119892 (119909) 119889119909

(41)

and the optimal order quantity 119876lowast is

119876lowast= 119878lowast+ int

119879

119905lowast

1

119890120575(119905minus119879)

119892 (119905) 119889119905 (42)

If 119905lowast1

le 1205832 then the optimal value of 119862

3(1199051) is obtained at

119905lowast

1= 1205832

The above analysis shows that the three average cost func-tions 119862

1(1199051) 1198622(1199052) and 119862

3(1199051) can obtain their minimum

value at 119905lowast1isin (0 119879) which is determined by (31) Therefore

based on the results analyzed above this paper derives aprocedure to locate the optimal replenishment policy startingwith no shortage for the three cases The procedure is asfollowsStep 1 Solve 119905lowast

1from (31)

Step 2 Compare 119905lowast1to 1205831and 120583

2 respectively

Step 21 If 119905lowast1isin (0 120583

1] then the optimal total average cost and

the optimal order quantity can be obtained by (10) and (34)respectivelyStep 22 If 119905lowast

1isin (1205831 1205832] then the optimal total average cost

and the optimal order quantity can be obtained by (18) and(38) respectively

Step 23 If 119905lowast1isin (1205832 119879] then the optimal total average cost

and the optimal order quantity can be obtained by (26) and(42) respectively

Remark 1 In such considered inventory model starting withno shortage if 119905

1satisfies 120583

1lt 1199051le 119879 lt 120583

2 the considered

inventory model reduces to that of Skouri et al [12]

4 Numerical Example

In order to demonstrate the above procedure which can beapplied to obtain the optimal solution of the model this

paper presents several examples for the model respectivelyExamples are based on piecewise demand rate such as119891(119905) =1198861+ 1198871119905 and 119892(119905) = 119886

2119890minus1198872119905

Example 1 The parameter values are given as follows 119879 = 12

weeks1205831= 4weeks120583

2= 8weeks120572 = 0005120573 = 2120575 = 004

1198861= 30 unit 119887

1= 5 unit 119886

2= 100 unit 119860

0= $500 119888

1= $2

1198882= $3 119888

3= $12 and 119888

4= $8

The model starting with no shortage by solving theequation ℎ(119905

1) = 0 we have 119905

lowast

1= 87622 From (42) and

(26) we obtain 119876lowast

= 5825217 and 119879119862(119905lowast

1) = 7939986

respectively

Example 2 Theparameter values are given as follows119879 = 12

weeks1205831= 4weeks120583

2= 8weeks120572 = 0005120573 = 2120575 = 002

1198861= 30 unit 119887

1= 5 unit 119886

2= 100 unit 119860

0= $500 119888

1= $5

1198882= $10 119888

3= $12 and 119888

4= $8

The model starting with no shortage by solving theequation ℎ(119905

1) = 0 we have 119905

lowast

1= 58330 From (38) and

(18) we obtain 119876lowast

= 5284725 and 119879119862(119905lowast

1) = 16014013

respectively

Example 3 Theparameter values are given as follows119879 = 12

weeks 1205831= 4 weeks 120583

2= 6 weeks 120572 = 0005 120573 = 16

120575 = 02 1198861= 30 unit 119887

1= 5 unit 119886

2= 100 unit 119860

0= $500

1198881= $5 119888

2= $10 119888

3= $12 and 119888

4= $8

Themodel starting with no shortage solving the equationℎ(1199051) = 0 the optimal value of 119905

1is 119905lowast1= 23235 The optimal

ordering quantity is 119876lowast = 2726678 and the minimum cost119879119862(119905lowast

1) = 125882

In order to clearly indicate the effects of parameters suchas 120575 120572 120573 119888

1 1198882 1198883 and 119888

4on the optimal on-hand inventory

119878lowast the optimal ordering quantity 119876

lowast and the optimal totalcost 119879119862(119905lowast

1) respectively the paper will study the sensitivity

of the optimal solution to changes in the value of differentparameter associated with the studied inventory model Thesensitivity analysis is performed on the base of Example 1 andthe results are shown in Table 1ndash7

By studying the results of Table 1 it is found that theshortage time 119905

lowast

1 inventory level 119878

lowast order quantity 119876lowast

and the total average cost 119879119862(119905lowast1) gradually decrease as the

shortage parameter 120575 increases for the model respectivelyWe also find that the percentage increase of 120575 from 143to 100 causes 119879119862(119905

lowast

1) to decrease from 045 to 034

119876lowast decrease from 075 to 052 119905lowast

1decrease from 078

to 053 and 119878lowast decrease from 102 to 069 It is also

observed that the value of 119905lowast1 119878lowast119876lowast and 119879119862(119905lowast

1) all are lowly

sensitive to the changes of 120575 for the considered inventorymodel

By studying the results of Table 2 it is found that 119878lowast 119876lowastand 119879119862(119905lowast

1) coordinates to the deterioration parameter 120572 the

shortage time 119905lowast1decreases as 120572 increases for the model It is

also found that the percentage increase of 120572 from 167 to100 causes 119879119862(119905lowast

1) to decrease by 2066ndash2595 119876lowast to

increase by 1597ndash244 the shortage time 119905lowast1to decrease

by 1513ndash1455 and 119878lowast to increase by 0917ndash1651 It

also observes that the value of 119905lowast1 119878lowast 119876lowast and 119879119862(119905

lowast

1) all are

moderately sensitive to the changes of 120572 for the consideredinventory model

8 Journal of Applied Mathematics

Table 1 The sensitivity of 120575 for the models in Example 1

120575 0 001 002 003 004 005 006 007 008119905lowast

189664 89187 88689 88167 87622 87049 86449 85817 85152

119878lowast 4729889 4697083 4662823 4627001 4589498 4550167 4508910 4465519 4419829119876lowast 5956569 5925872 5893822 5860308 5825217 5788412 5749771 5709112 5666265

TC(119905lowast1) 8056323 8028699 8000139 7970588 7939986 7908268 7875365 7841200 7805690

Table 2 The sensitivity of 120572 for the models in Example 1

120572 0 0001 0002 0003 0004 0005 0006 0007119905lowast

194545 93115 91702 90312 88950 87622 86328 85072

119878lowast 4283286 4354002 4420048 4481317 4537785 4589498 4636555 4679088119876lowast 5238866 5366685 5489558 5607091 5719025 5825217 5925618 6020259

TC(119905lowast1) 7046045 7228867 7410107 7589297 7766035 7939986 8110872 8278474

Table 3 The sensitivity of 120573 for the models in Example 1

120573 14 16 18 20 22 24 26 28119905lowast

192876 91810 90142 87622 84047 79422 74073 68496

119878lowast 4429058 4475894 4531802 4589076 4628345 4616422 4534686 4388904119876lowast 5451340 5541055 5664485 5824772 6012274 7746099 7664364 7518582

TC(119905lowast1) 7457703 7643043 7917624 7907114 8293653 5887417 4731282 3911266

Table 4 The sensitivity of 1198881for the models in Example 1

1198881

0 04 1 16 2 24 26 3 36119905lowast

188225 88103 87921 87741 87622 87503 87443 87326 87150

119878lowast 4630980 4622595 4610101 4597707 4589498 4581333 4577266 4569164 4557090119876lowast 5841909 5838529 5833499 5828514 5825217 5821940 5825217 5817061 5812226

TC(119905lowast1) 7835429 7856518 7887984 7919251 7939986 7960633 7970925 7991443 8022061

Table 5 The sensitivity of 1198882for the model in Example 1

1198882

0 04 08 12 18 24 3 34 38119905lowast

1118343 11267 107698 10326 97377 92216 87622 84819 82196

119878lowast 6737217 6330852 5979589 5669228 5261187 4905382 4589498 4396922 4216606119876lowast 6796039 6594483 6427261 6284787 6104744 5954175 5825217 5748648 5678284

TC(119905lowast1) 672679 1939216 3088975 4139636 5558150 6816692 7939986 8623253 9259516

Table 6 The sensitivity of 1198883for the models in Example 1

1198883

104 106 108 11 112 116 12 124 128119905lowast

184424 84859 85284 85698 86102 86879 87622 88329 89005

119878lowast 4369771 4399713 442889 4457332 4485071 453854 4589498 4638114 4684587119876lowast 5737973 5749747 5761255 5772506 5783509 5804809 5825217 5844787 5863587

TC(119905lowast1) 7638057 7679203 7719299 7758387 7796505 7869976 7939986 8006779 8070579

Table 7 The sensitivity of 1198884for the models in Example 1

1198884

0 2 4 6 8 10 12 14 16119905lowast

186989 87150 87309 87466 87622 87775 87928 88078 882272

119878lowast 4546069 4557103 4568017 4578815 4589498 4600048 4610527 4620877 4631120119876lowast 5807818 5812231 5816601 5820929 5825217 5829455 583367 5837837 5841966

TC(119905lowast1) 7881626 7896445 7911109 7925621 7939986 7954203 7968276 7982207 7995999

Journal of Applied Mathematics 9

By studying the results of Table 3 it is found that 119878lowast119876lowast and 119879119862(119905

lowast

1) coordinate to the deterioration parameter 120573

while the shortage time 119905lowast

1decreases as 120573 increases for the

model It is also found that the increase of 120573 from 14 to 22causes 119878

lowast to increase while the increase of 120573 from 24 to28 causes 119878lowast to decrease 119876lowast to increase by 244ndash1597119879119862(119905lowast

1) to increase by 2595ndash2066 and the shortage time

119905lowast

1to decrease by 1513ndash1455 It is also observed that the

value of 119905lowast1 119878lowast119876lowast and 119879119862(119905lowast

1) all are moderately sensitive to

the changes of 120573 for the considered inventory modelBy studying the results of Table 4 it is found that 119879119862(119905lowast

1)

coordinate to 1198881 while the shortage time 119905

lowast

1 119878lowast and 119876

lowast

decrease as 1198881increases for the model It is also found that 119888

1

increases from 83 to 150 119879119862(119905lowast1) decreases by 0269ndash

0383 119876lowast decreases by 0083ndash0058 119905lowast1decreases by

0264ndash0181 and 119878lowast decreases by 0203ndash0138 respec-tively It is also observed that the values of 119905lowast

1 119878lowast 119876lowast and

119879119862(119905lowast

1) all are lowly sensitive to the changes of 119888

1for the

considered inventory modelBy studying the results of Table 5 it is found that

119879119862(119905lowast

1) coordinates to 119888

2 while 119878

lowast 119876lowastand 119905lowast

1decrease as

1198881increases for the model It is also found that 119888

2increases

by 100 119879119862(119905lowast1) decreases by 0269ndash0383 119876lowast decreases

by 0083ndash0058 119905lowast1decreases by 0264ndash0181 and 119878

lowast

decreases by 0203ndash0138By studying the results of Table 6 it is found that 119905lowast

1 119878lowast

119876lowast and 119879119862(119905

lowast

1) coordinate to 119888

3 It is also observed that the

value of 119905lowast1 119878lowast 119876lowast and 119879119862(119905

lowast

1) all are lowly sensitive to the

changes of 1198883for the inventory models that is 119888

3increases

from 19 to 32 the change of all the parameters is nomorethan 1

By studying the results of Table 7 it is found that 119905lowast1 119878lowast

119876lowast and 119879119862(119905

lowast

1) coordinate to 119888

4 It is also observed that the

value of 119905lowast1 119878lowast 119876lowast and 119879119862(119905

lowast

1) all are lowly sensitive to the

changes of 1198884for the inventory models that is 119888

4increases

from 143 to 100 the change of all the parameters is nomore than 1

5 Conclusion

An inventory model starting without shortage for Weibull-distributed deterioration with trapezoidal type demand rateand partial backlogging is considered in this paper Theoptimal replenishment policy for the inventory model isproposed and numerical examples are provided to illustratethe theoretical results A sensitivity analysis of the optimalsolution with respect to major parameters is also carried outFrom Table 1ndash7 it can be found that the shortage time point119905lowast

1 order quantity 119876lowast and the total average cost 119879119862(119905lowast

1) are

moderately sensitive to the changes of 120572 and 120573 and lowlysensitive to the changes of 120575 119888

119894(119894 = 1 2 3 4) respectively

The paper provides an interesting topic for further studysuch that the joint influence from some of these parametersmay be investigated to show the effects the model startingwith shortage will be studied and other types of models fordeteriorating items in supply chain situation are also to bestudied in the future

Conflict of Interests

The author declares that there is no conflict of interestsregarding the publication of this paper

Acknowledgments

The author is grateful to the anonymous referees who pro-vided valuable comments and suggestions to significantlyimprove the quality of the paper This work was supportedpartly byHumanities and Social Science Fund of theMinistryof Education of China (no 11YJCZH019)

References

[1] P M Ghare and G F Schrader ldquoA model for exponentiallydecaying inventoriesrdquo Journal of Industrial Engineering vol 14pp 238ndash243 1963

[2] J-W Wu C Lin B Tan and W-C Lee ldquoAn EOQ inventorymodel with time-varying demand and Weibull deteriorationwith shortagesrdquo International Journal of Systems Science vol 31no 6 pp 677ndash683 2000

[3] H-M Wee ldquoDeteriorating inventory model with quantity dis-count pricing and partial backorderingrdquo International Journalof Production Economics vol 59 no 1 pp 511ndash518 1999

[4] K Skouri and S Papachristos ldquoA continuous review inven-tory model with deteriorating items time-varying demandlinear replenishment cost partially time-varying backloggingrdquoApplied Mathematical Modelling vol 26 no 5 pp 603ndash6172002

[5] H-MWee J C P Yu and S T Law ldquoTwo-warehouse inventorymodel with partial backordering and Weibull distributiondeterioration under inflationrdquo Journal of the Chinese Institute ofIndustrial Engineers vol 22 no 6 pp 451ndash462 2005

[6] C-Y Dye T-P Hsieh and L-Y Ouyang ldquoDetermining optimalselling price and lot size with a varying rate of deteriorationand exponential partial backloggingrdquo European Journal ofOperational Research vol 181 no 2 pp 668ndash678 2007

[7] R M Hill ldquoInventory models for increasing demand followedby level demandrdquo Journal of the Operational Research Societyvol 46 no 10 pp 1250ndash1259 1995

[8] B Mandal and A K Pal ldquoOrder level inventory system withramp type demand rate for deteriorating itemsrdquo Journal ofInterdisciplinary Mathematics vol 1 no 1 pp 49ndash66 1998

[9] K-S Wu ldquoAn EOQ inventory model for items with Weibulldistribution deterioration ramp type demand rate and partialbackloggingrdquo Production Planning amp Control vol 12 no 8 pp787ndash793 2001

[10] B C Giri A K Jalan and K S Chaudhuri ldquoEconomic orderquantity model with Weibull deterioration distribution short-age and ramp-type demandrdquo International Journal of SystemsScience vol 34 no 4 pp 237ndash243 2003

[11] S K Manna and K S Chaudhuri ldquoAn EOQ model withramp type demand rate time dependent deterioration rate unitproduction cost and shortagesrdquoEuropean Journal ofOperationalResearch vol 171 no 2 pp 557ndash566 2006

[12] K Skouri I Konstantaras S Papachristos and I Ganas ldquoInven-tory models with ramp type demand rate partial backloggingandWeibull deterioration raterdquoEuropean Journal ofOperationalResearch vol 192 no 1 pp 79ndash92 2009

10 Journal of Applied Mathematics

[13] K-C Hung ldquoAn inventory model with generalized typedemand deterioration and backorder ratesrdquo European Journalof Operational Research vol 208 no 3 pp 239ndash242 2011

[14] R S Kumar S K De and A Goswami ldquoFuzzy EOQ modelswith ramp type demand rate partial backlogging and timedependent deterioration raterdquo International Journal of Mathe-matics in Operational Research vol 4 no 5 pp 473ndash502 2012

[15] M B Cheng B X Zhang and G QWang ldquoOptimal policy fordeteriorating items with trapezoidal type demand and partialbackloggingrdquoAppliedMathematical Modelling vol 35 no 7 pp3552ndash3560 2011

[16] R Uthayakumar and M Rameswari ldquoAn economic produc-tion quantity model for defective items with trapezoidal typedemand raterdquo Journal of Optimization Theory and Applicationsvol 154 no 3 pp 1055ndash1079 2012

[17] Y Tan and M X Weng ldquoA discrete-in-time deterioratinginventory model with time-varying demand variable deterio-ration rate and waiting-time-dependent partial backloggingrdquoInternational Journal of Systems Science vol 44 no 8 pp 1483ndash1493 2013

[18] M A Ahmed T A Al-Khamis and L Benkherouf ldquoInventorymodels with ramp type demand rate partial backlogging andgeneral deterioration raterdquo Applied Mathematics and Computa-tion vol 219 no 9 pp 4288ndash4307 2013

[19] K-P Lin ldquoAn extended inventory models with trapezoidal typedemandsrdquo Applied Mathematics and Computation vol 219 no24 pp 11414ndash11419 2013

[20] P L Abad ldquoOptimal pricing and lot-sizing under conditionsof perishability and partial backorderingrdquoManagement Sciencevol 42 no 8 pp 1093ndash1104 1996

Submit your manuscripts athttpwwwhindawicom

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

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Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Mathematical Problems in Engineering

Hindawi Publishing Corporationhttpwwwhindawicom

Differential EquationsInternational Journal of

Volume 2014

Applied MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Probability and StatisticsHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

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Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Mathematical PhysicsAdvances in

Complex AnalysisJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

OptimizationJournal of

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CombinatoricsHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

International Journal of

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Operations ResearchAdvances in

Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Function Spaces

Abstract and Applied AnalysisHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

International Journal of Mathematics and Mathematical Sciences

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The Scientific World JournalHindawi Publishing Corporation httpwwwhindawicom Volume 2014

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Algebra

Discrete Dynamics in Nature and Society

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Volume 2014 Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Stochastic AnalysisInternational Journal of

Page 7: Research Article An Inventory Model under Trapezoidal Type ...downloads.hindawi.com/journals/jam/2014/747419.pdf · an inventory model with Weibull-distributed deterioration items,

Journal of Applied Mathematics 7

If 119905lowast1le 1205831 then the optimal value of 119862

2(1199051) is obtained at

119905lowast

1= 1205831 and if 119905lowast

1ge 1205832 then the optimal value of 119862

2(1199051) is

obtained at 119905lowast1= 1205832

If 1205832lt 1199051le 119879 taking the first-order and second-order

derivative of 1198623(1199051) with respect to 119905

1 respectively we obtain

1198891198623(1199051)

1198891199051

=119892 (1199051)

119879ℎ (1199051) (39)

If 1205832lt 119905lowast

1le 119879 for this 119905lowast

1 we have

11988921198623(1199051)

1198891199052

1

1003816100381610038161003816100381610038161003816100381610038161199051=119905lowast

1

= 119892 (119905lowast

1)119889ℎ (119905lowast

1)

119879119889119905lowast

1

gt 0 (40)

The function ℎ(1199051) is given by (31) and (40) implies that

1198623(1199051) can obtain its minimum value at 119905lowast

1

The optimal value of the order level 119878 = 119868(0) is

119878lowast= int

1205831

0

119890120572119909120573

119891 (119909) 119889119909 + 1198630int

1205832

1205831

119890120572119909120573

119889119909 + int

119905lowast

1

1205832

119890120572119909120573

119892 (119909) 119889119909

(41)

and the optimal order quantity 119876lowast is

119876lowast= 119878lowast+ int

119879

119905lowast

1

119890120575(119905minus119879)

119892 (119905) 119889119905 (42)

If 119905lowast1

le 1205832 then the optimal value of 119862

3(1199051) is obtained at

119905lowast

1= 1205832

The above analysis shows that the three average cost func-tions 119862

1(1199051) 1198622(1199052) and 119862

3(1199051) can obtain their minimum

value at 119905lowast1isin (0 119879) which is determined by (31) Therefore

based on the results analyzed above this paper derives aprocedure to locate the optimal replenishment policy startingwith no shortage for the three cases The procedure is asfollowsStep 1 Solve 119905lowast

1from (31)

Step 2 Compare 119905lowast1to 1205831and 120583

2 respectively

Step 21 If 119905lowast1isin (0 120583

1] then the optimal total average cost and

the optimal order quantity can be obtained by (10) and (34)respectivelyStep 22 If 119905lowast

1isin (1205831 1205832] then the optimal total average cost

and the optimal order quantity can be obtained by (18) and(38) respectively

Step 23 If 119905lowast1isin (1205832 119879] then the optimal total average cost

and the optimal order quantity can be obtained by (26) and(42) respectively

Remark 1 In such considered inventory model starting withno shortage if 119905

1satisfies 120583

1lt 1199051le 119879 lt 120583

2 the considered

inventory model reduces to that of Skouri et al [12]

4 Numerical Example

In order to demonstrate the above procedure which can beapplied to obtain the optimal solution of the model this

paper presents several examples for the model respectivelyExamples are based on piecewise demand rate such as119891(119905) =1198861+ 1198871119905 and 119892(119905) = 119886

2119890minus1198872119905

Example 1 The parameter values are given as follows 119879 = 12

weeks1205831= 4weeks120583

2= 8weeks120572 = 0005120573 = 2120575 = 004

1198861= 30 unit 119887

1= 5 unit 119886

2= 100 unit 119860

0= $500 119888

1= $2

1198882= $3 119888

3= $12 and 119888

4= $8

The model starting with no shortage by solving theequation ℎ(119905

1) = 0 we have 119905

lowast

1= 87622 From (42) and

(26) we obtain 119876lowast

= 5825217 and 119879119862(119905lowast

1) = 7939986

respectively

Example 2 Theparameter values are given as follows119879 = 12

weeks1205831= 4weeks120583

2= 8weeks120572 = 0005120573 = 2120575 = 002

1198861= 30 unit 119887

1= 5 unit 119886

2= 100 unit 119860

0= $500 119888

1= $5

1198882= $10 119888

3= $12 and 119888

4= $8

The model starting with no shortage by solving theequation ℎ(119905

1) = 0 we have 119905

lowast

1= 58330 From (38) and

(18) we obtain 119876lowast

= 5284725 and 119879119862(119905lowast

1) = 16014013

respectively

Example 3 Theparameter values are given as follows119879 = 12

weeks 1205831= 4 weeks 120583

2= 6 weeks 120572 = 0005 120573 = 16

120575 = 02 1198861= 30 unit 119887

1= 5 unit 119886

2= 100 unit 119860

0= $500

1198881= $5 119888

2= $10 119888

3= $12 and 119888

4= $8

Themodel starting with no shortage solving the equationℎ(1199051) = 0 the optimal value of 119905

1is 119905lowast1= 23235 The optimal

ordering quantity is 119876lowast = 2726678 and the minimum cost119879119862(119905lowast

1) = 125882

In order to clearly indicate the effects of parameters suchas 120575 120572 120573 119888

1 1198882 1198883 and 119888

4on the optimal on-hand inventory

119878lowast the optimal ordering quantity 119876

lowast and the optimal totalcost 119879119862(119905lowast

1) respectively the paper will study the sensitivity

of the optimal solution to changes in the value of differentparameter associated with the studied inventory model Thesensitivity analysis is performed on the base of Example 1 andthe results are shown in Table 1ndash7

By studying the results of Table 1 it is found that theshortage time 119905

lowast

1 inventory level 119878

lowast order quantity 119876lowast

and the total average cost 119879119862(119905lowast1) gradually decrease as the

shortage parameter 120575 increases for the model respectivelyWe also find that the percentage increase of 120575 from 143to 100 causes 119879119862(119905

lowast

1) to decrease from 045 to 034

119876lowast decrease from 075 to 052 119905lowast

1decrease from 078

to 053 and 119878lowast decrease from 102 to 069 It is also

observed that the value of 119905lowast1 119878lowast119876lowast and 119879119862(119905lowast

1) all are lowly

sensitive to the changes of 120575 for the considered inventorymodel

By studying the results of Table 2 it is found that 119878lowast 119876lowastand 119879119862(119905lowast

1) coordinates to the deterioration parameter 120572 the

shortage time 119905lowast1decreases as 120572 increases for the model It is

also found that the percentage increase of 120572 from 167 to100 causes 119879119862(119905lowast

1) to decrease by 2066ndash2595 119876lowast to

increase by 1597ndash244 the shortage time 119905lowast1to decrease

by 1513ndash1455 and 119878lowast to increase by 0917ndash1651 It

also observes that the value of 119905lowast1 119878lowast 119876lowast and 119879119862(119905

lowast

1) all are

moderately sensitive to the changes of 120572 for the consideredinventory model

8 Journal of Applied Mathematics

Table 1 The sensitivity of 120575 for the models in Example 1

120575 0 001 002 003 004 005 006 007 008119905lowast

189664 89187 88689 88167 87622 87049 86449 85817 85152

119878lowast 4729889 4697083 4662823 4627001 4589498 4550167 4508910 4465519 4419829119876lowast 5956569 5925872 5893822 5860308 5825217 5788412 5749771 5709112 5666265

TC(119905lowast1) 8056323 8028699 8000139 7970588 7939986 7908268 7875365 7841200 7805690

Table 2 The sensitivity of 120572 for the models in Example 1

120572 0 0001 0002 0003 0004 0005 0006 0007119905lowast

194545 93115 91702 90312 88950 87622 86328 85072

119878lowast 4283286 4354002 4420048 4481317 4537785 4589498 4636555 4679088119876lowast 5238866 5366685 5489558 5607091 5719025 5825217 5925618 6020259

TC(119905lowast1) 7046045 7228867 7410107 7589297 7766035 7939986 8110872 8278474

Table 3 The sensitivity of 120573 for the models in Example 1

120573 14 16 18 20 22 24 26 28119905lowast

192876 91810 90142 87622 84047 79422 74073 68496

119878lowast 4429058 4475894 4531802 4589076 4628345 4616422 4534686 4388904119876lowast 5451340 5541055 5664485 5824772 6012274 7746099 7664364 7518582

TC(119905lowast1) 7457703 7643043 7917624 7907114 8293653 5887417 4731282 3911266

Table 4 The sensitivity of 1198881for the models in Example 1

1198881

0 04 1 16 2 24 26 3 36119905lowast

188225 88103 87921 87741 87622 87503 87443 87326 87150

119878lowast 4630980 4622595 4610101 4597707 4589498 4581333 4577266 4569164 4557090119876lowast 5841909 5838529 5833499 5828514 5825217 5821940 5825217 5817061 5812226

TC(119905lowast1) 7835429 7856518 7887984 7919251 7939986 7960633 7970925 7991443 8022061

Table 5 The sensitivity of 1198882for the model in Example 1

1198882

0 04 08 12 18 24 3 34 38119905lowast

1118343 11267 107698 10326 97377 92216 87622 84819 82196

119878lowast 6737217 6330852 5979589 5669228 5261187 4905382 4589498 4396922 4216606119876lowast 6796039 6594483 6427261 6284787 6104744 5954175 5825217 5748648 5678284

TC(119905lowast1) 672679 1939216 3088975 4139636 5558150 6816692 7939986 8623253 9259516

Table 6 The sensitivity of 1198883for the models in Example 1

1198883

104 106 108 11 112 116 12 124 128119905lowast

184424 84859 85284 85698 86102 86879 87622 88329 89005

119878lowast 4369771 4399713 442889 4457332 4485071 453854 4589498 4638114 4684587119876lowast 5737973 5749747 5761255 5772506 5783509 5804809 5825217 5844787 5863587

TC(119905lowast1) 7638057 7679203 7719299 7758387 7796505 7869976 7939986 8006779 8070579

Table 7 The sensitivity of 1198884for the models in Example 1

1198884

0 2 4 6 8 10 12 14 16119905lowast

186989 87150 87309 87466 87622 87775 87928 88078 882272

119878lowast 4546069 4557103 4568017 4578815 4589498 4600048 4610527 4620877 4631120119876lowast 5807818 5812231 5816601 5820929 5825217 5829455 583367 5837837 5841966

TC(119905lowast1) 7881626 7896445 7911109 7925621 7939986 7954203 7968276 7982207 7995999

Journal of Applied Mathematics 9

By studying the results of Table 3 it is found that 119878lowast119876lowast and 119879119862(119905

lowast

1) coordinate to the deterioration parameter 120573

while the shortage time 119905lowast

1decreases as 120573 increases for the

model It is also found that the increase of 120573 from 14 to 22causes 119878

lowast to increase while the increase of 120573 from 24 to28 causes 119878lowast to decrease 119876lowast to increase by 244ndash1597119879119862(119905lowast

1) to increase by 2595ndash2066 and the shortage time

119905lowast

1to decrease by 1513ndash1455 It is also observed that the

value of 119905lowast1 119878lowast119876lowast and 119879119862(119905lowast

1) all are moderately sensitive to

the changes of 120573 for the considered inventory modelBy studying the results of Table 4 it is found that 119879119862(119905lowast

1)

coordinate to 1198881 while the shortage time 119905

lowast

1 119878lowast and 119876

lowast

decrease as 1198881increases for the model It is also found that 119888

1

increases from 83 to 150 119879119862(119905lowast1) decreases by 0269ndash

0383 119876lowast decreases by 0083ndash0058 119905lowast1decreases by

0264ndash0181 and 119878lowast decreases by 0203ndash0138 respec-tively It is also observed that the values of 119905lowast

1 119878lowast 119876lowast and

119879119862(119905lowast

1) all are lowly sensitive to the changes of 119888

1for the

considered inventory modelBy studying the results of Table 5 it is found that

119879119862(119905lowast

1) coordinates to 119888

2 while 119878

lowast 119876lowastand 119905lowast

1decrease as

1198881increases for the model It is also found that 119888

2increases

by 100 119879119862(119905lowast1) decreases by 0269ndash0383 119876lowast decreases

by 0083ndash0058 119905lowast1decreases by 0264ndash0181 and 119878

lowast

decreases by 0203ndash0138By studying the results of Table 6 it is found that 119905lowast

1 119878lowast

119876lowast and 119879119862(119905

lowast

1) coordinate to 119888

3 It is also observed that the

value of 119905lowast1 119878lowast 119876lowast and 119879119862(119905

lowast

1) all are lowly sensitive to the

changes of 1198883for the inventory models that is 119888

3increases

from 19 to 32 the change of all the parameters is nomorethan 1

By studying the results of Table 7 it is found that 119905lowast1 119878lowast

119876lowast and 119879119862(119905

lowast

1) coordinate to 119888

4 It is also observed that the

value of 119905lowast1 119878lowast 119876lowast and 119879119862(119905

lowast

1) all are lowly sensitive to the

changes of 1198884for the inventory models that is 119888

4increases

from 143 to 100 the change of all the parameters is nomore than 1

5 Conclusion

An inventory model starting without shortage for Weibull-distributed deterioration with trapezoidal type demand rateand partial backlogging is considered in this paper Theoptimal replenishment policy for the inventory model isproposed and numerical examples are provided to illustratethe theoretical results A sensitivity analysis of the optimalsolution with respect to major parameters is also carried outFrom Table 1ndash7 it can be found that the shortage time point119905lowast

1 order quantity 119876lowast and the total average cost 119879119862(119905lowast

1) are

moderately sensitive to the changes of 120572 and 120573 and lowlysensitive to the changes of 120575 119888

119894(119894 = 1 2 3 4) respectively

The paper provides an interesting topic for further studysuch that the joint influence from some of these parametersmay be investigated to show the effects the model startingwith shortage will be studied and other types of models fordeteriorating items in supply chain situation are also to bestudied in the future

Conflict of Interests

The author declares that there is no conflict of interestsregarding the publication of this paper

Acknowledgments

The author is grateful to the anonymous referees who pro-vided valuable comments and suggestions to significantlyimprove the quality of the paper This work was supportedpartly byHumanities and Social Science Fund of theMinistryof Education of China (no 11YJCZH019)

References

[1] P M Ghare and G F Schrader ldquoA model for exponentiallydecaying inventoriesrdquo Journal of Industrial Engineering vol 14pp 238ndash243 1963

[2] J-W Wu C Lin B Tan and W-C Lee ldquoAn EOQ inventorymodel with time-varying demand and Weibull deteriorationwith shortagesrdquo International Journal of Systems Science vol 31no 6 pp 677ndash683 2000

[3] H-M Wee ldquoDeteriorating inventory model with quantity dis-count pricing and partial backorderingrdquo International Journalof Production Economics vol 59 no 1 pp 511ndash518 1999

[4] K Skouri and S Papachristos ldquoA continuous review inven-tory model with deteriorating items time-varying demandlinear replenishment cost partially time-varying backloggingrdquoApplied Mathematical Modelling vol 26 no 5 pp 603ndash6172002

[5] H-MWee J C P Yu and S T Law ldquoTwo-warehouse inventorymodel with partial backordering and Weibull distributiondeterioration under inflationrdquo Journal of the Chinese Institute ofIndustrial Engineers vol 22 no 6 pp 451ndash462 2005

[6] C-Y Dye T-P Hsieh and L-Y Ouyang ldquoDetermining optimalselling price and lot size with a varying rate of deteriorationand exponential partial backloggingrdquo European Journal ofOperational Research vol 181 no 2 pp 668ndash678 2007

[7] R M Hill ldquoInventory models for increasing demand followedby level demandrdquo Journal of the Operational Research Societyvol 46 no 10 pp 1250ndash1259 1995

[8] B Mandal and A K Pal ldquoOrder level inventory system withramp type demand rate for deteriorating itemsrdquo Journal ofInterdisciplinary Mathematics vol 1 no 1 pp 49ndash66 1998

[9] K-S Wu ldquoAn EOQ inventory model for items with Weibulldistribution deterioration ramp type demand rate and partialbackloggingrdquo Production Planning amp Control vol 12 no 8 pp787ndash793 2001

[10] B C Giri A K Jalan and K S Chaudhuri ldquoEconomic orderquantity model with Weibull deterioration distribution short-age and ramp-type demandrdquo International Journal of SystemsScience vol 34 no 4 pp 237ndash243 2003

[11] S K Manna and K S Chaudhuri ldquoAn EOQ model withramp type demand rate time dependent deterioration rate unitproduction cost and shortagesrdquoEuropean Journal ofOperationalResearch vol 171 no 2 pp 557ndash566 2006

[12] K Skouri I Konstantaras S Papachristos and I Ganas ldquoInven-tory models with ramp type demand rate partial backloggingandWeibull deterioration raterdquoEuropean Journal ofOperationalResearch vol 192 no 1 pp 79ndash92 2009

10 Journal of Applied Mathematics

[13] K-C Hung ldquoAn inventory model with generalized typedemand deterioration and backorder ratesrdquo European Journalof Operational Research vol 208 no 3 pp 239ndash242 2011

[14] R S Kumar S K De and A Goswami ldquoFuzzy EOQ modelswith ramp type demand rate partial backlogging and timedependent deterioration raterdquo International Journal of Mathe-matics in Operational Research vol 4 no 5 pp 473ndash502 2012

[15] M B Cheng B X Zhang and G QWang ldquoOptimal policy fordeteriorating items with trapezoidal type demand and partialbackloggingrdquoAppliedMathematical Modelling vol 35 no 7 pp3552ndash3560 2011

[16] R Uthayakumar and M Rameswari ldquoAn economic produc-tion quantity model for defective items with trapezoidal typedemand raterdquo Journal of Optimization Theory and Applicationsvol 154 no 3 pp 1055ndash1079 2012

[17] Y Tan and M X Weng ldquoA discrete-in-time deterioratinginventory model with time-varying demand variable deterio-ration rate and waiting-time-dependent partial backloggingrdquoInternational Journal of Systems Science vol 44 no 8 pp 1483ndash1493 2013

[18] M A Ahmed T A Al-Khamis and L Benkherouf ldquoInventorymodels with ramp type demand rate partial backlogging andgeneral deterioration raterdquo Applied Mathematics and Computa-tion vol 219 no 9 pp 4288ndash4307 2013

[19] K-P Lin ldquoAn extended inventory models with trapezoidal typedemandsrdquo Applied Mathematics and Computation vol 219 no24 pp 11414ndash11419 2013

[20] P L Abad ldquoOptimal pricing and lot-sizing under conditionsof perishability and partial backorderingrdquoManagement Sciencevol 42 no 8 pp 1093ndash1104 1996

Submit your manuscripts athttpwwwhindawicom

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Mathematical Problems in Engineering

Hindawi Publishing Corporationhttpwwwhindawicom

Differential EquationsInternational Journal of

Volume 2014

Applied MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Probability and StatisticsHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Mathematical PhysicsAdvances in

Complex AnalysisJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

OptimizationJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

CombinatoricsHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

International Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Operations ResearchAdvances in

Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Function Spaces

Abstract and Applied AnalysisHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

International Journal of Mathematics and Mathematical Sciences

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

The Scientific World JournalHindawi Publishing Corporation httpwwwhindawicom Volume 2014

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Algebra

Discrete Dynamics in Nature and Society

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Decision SciencesAdvances in

Discrete MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom

Volume 2014 Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Stochastic AnalysisInternational Journal of

Page 8: Research Article An Inventory Model under Trapezoidal Type ...downloads.hindawi.com/journals/jam/2014/747419.pdf · an inventory model with Weibull-distributed deterioration items,

8 Journal of Applied Mathematics

Table 1 The sensitivity of 120575 for the models in Example 1

120575 0 001 002 003 004 005 006 007 008119905lowast

189664 89187 88689 88167 87622 87049 86449 85817 85152

119878lowast 4729889 4697083 4662823 4627001 4589498 4550167 4508910 4465519 4419829119876lowast 5956569 5925872 5893822 5860308 5825217 5788412 5749771 5709112 5666265

TC(119905lowast1) 8056323 8028699 8000139 7970588 7939986 7908268 7875365 7841200 7805690

Table 2 The sensitivity of 120572 for the models in Example 1

120572 0 0001 0002 0003 0004 0005 0006 0007119905lowast

194545 93115 91702 90312 88950 87622 86328 85072

119878lowast 4283286 4354002 4420048 4481317 4537785 4589498 4636555 4679088119876lowast 5238866 5366685 5489558 5607091 5719025 5825217 5925618 6020259

TC(119905lowast1) 7046045 7228867 7410107 7589297 7766035 7939986 8110872 8278474

Table 3 The sensitivity of 120573 for the models in Example 1

120573 14 16 18 20 22 24 26 28119905lowast

192876 91810 90142 87622 84047 79422 74073 68496

119878lowast 4429058 4475894 4531802 4589076 4628345 4616422 4534686 4388904119876lowast 5451340 5541055 5664485 5824772 6012274 7746099 7664364 7518582

TC(119905lowast1) 7457703 7643043 7917624 7907114 8293653 5887417 4731282 3911266

Table 4 The sensitivity of 1198881for the models in Example 1

1198881

0 04 1 16 2 24 26 3 36119905lowast

188225 88103 87921 87741 87622 87503 87443 87326 87150

119878lowast 4630980 4622595 4610101 4597707 4589498 4581333 4577266 4569164 4557090119876lowast 5841909 5838529 5833499 5828514 5825217 5821940 5825217 5817061 5812226

TC(119905lowast1) 7835429 7856518 7887984 7919251 7939986 7960633 7970925 7991443 8022061

Table 5 The sensitivity of 1198882for the model in Example 1

1198882

0 04 08 12 18 24 3 34 38119905lowast

1118343 11267 107698 10326 97377 92216 87622 84819 82196

119878lowast 6737217 6330852 5979589 5669228 5261187 4905382 4589498 4396922 4216606119876lowast 6796039 6594483 6427261 6284787 6104744 5954175 5825217 5748648 5678284

TC(119905lowast1) 672679 1939216 3088975 4139636 5558150 6816692 7939986 8623253 9259516

Table 6 The sensitivity of 1198883for the models in Example 1

1198883

104 106 108 11 112 116 12 124 128119905lowast

184424 84859 85284 85698 86102 86879 87622 88329 89005

119878lowast 4369771 4399713 442889 4457332 4485071 453854 4589498 4638114 4684587119876lowast 5737973 5749747 5761255 5772506 5783509 5804809 5825217 5844787 5863587

TC(119905lowast1) 7638057 7679203 7719299 7758387 7796505 7869976 7939986 8006779 8070579

Table 7 The sensitivity of 1198884for the models in Example 1

1198884

0 2 4 6 8 10 12 14 16119905lowast

186989 87150 87309 87466 87622 87775 87928 88078 882272

119878lowast 4546069 4557103 4568017 4578815 4589498 4600048 4610527 4620877 4631120119876lowast 5807818 5812231 5816601 5820929 5825217 5829455 583367 5837837 5841966

TC(119905lowast1) 7881626 7896445 7911109 7925621 7939986 7954203 7968276 7982207 7995999

Journal of Applied Mathematics 9

By studying the results of Table 3 it is found that 119878lowast119876lowast and 119879119862(119905

lowast

1) coordinate to the deterioration parameter 120573

while the shortage time 119905lowast

1decreases as 120573 increases for the

model It is also found that the increase of 120573 from 14 to 22causes 119878

lowast to increase while the increase of 120573 from 24 to28 causes 119878lowast to decrease 119876lowast to increase by 244ndash1597119879119862(119905lowast

1) to increase by 2595ndash2066 and the shortage time

119905lowast

1to decrease by 1513ndash1455 It is also observed that the

value of 119905lowast1 119878lowast119876lowast and 119879119862(119905lowast

1) all are moderately sensitive to

the changes of 120573 for the considered inventory modelBy studying the results of Table 4 it is found that 119879119862(119905lowast

1)

coordinate to 1198881 while the shortage time 119905

lowast

1 119878lowast and 119876

lowast

decrease as 1198881increases for the model It is also found that 119888

1

increases from 83 to 150 119879119862(119905lowast1) decreases by 0269ndash

0383 119876lowast decreases by 0083ndash0058 119905lowast1decreases by

0264ndash0181 and 119878lowast decreases by 0203ndash0138 respec-tively It is also observed that the values of 119905lowast

1 119878lowast 119876lowast and

119879119862(119905lowast

1) all are lowly sensitive to the changes of 119888

1for the

considered inventory modelBy studying the results of Table 5 it is found that

119879119862(119905lowast

1) coordinates to 119888

2 while 119878

lowast 119876lowastand 119905lowast

1decrease as

1198881increases for the model It is also found that 119888

2increases

by 100 119879119862(119905lowast1) decreases by 0269ndash0383 119876lowast decreases

by 0083ndash0058 119905lowast1decreases by 0264ndash0181 and 119878

lowast

decreases by 0203ndash0138By studying the results of Table 6 it is found that 119905lowast

1 119878lowast

119876lowast and 119879119862(119905

lowast

1) coordinate to 119888

3 It is also observed that the

value of 119905lowast1 119878lowast 119876lowast and 119879119862(119905

lowast

1) all are lowly sensitive to the

changes of 1198883for the inventory models that is 119888

3increases

from 19 to 32 the change of all the parameters is nomorethan 1

By studying the results of Table 7 it is found that 119905lowast1 119878lowast

119876lowast and 119879119862(119905

lowast

1) coordinate to 119888

4 It is also observed that the

value of 119905lowast1 119878lowast 119876lowast and 119879119862(119905

lowast

1) all are lowly sensitive to the

changes of 1198884for the inventory models that is 119888

4increases

from 143 to 100 the change of all the parameters is nomore than 1

5 Conclusion

An inventory model starting without shortage for Weibull-distributed deterioration with trapezoidal type demand rateand partial backlogging is considered in this paper Theoptimal replenishment policy for the inventory model isproposed and numerical examples are provided to illustratethe theoretical results A sensitivity analysis of the optimalsolution with respect to major parameters is also carried outFrom Table 1ndash7 it can be found that the shortage time point119905lowast

1 order quantity 119876lowast and the total average cost 119879119862(119905lowast

1) are

moderately sensitive to the changes of 120572 and 120573 and lowlysensitive to the changes of 120575 119888

119894(119894 = 1 2 3 4) respectively

The paper provides an interesting topic for further studysuch that the joint influence from some of these parametersmay be investigated to show the effects the model startingwith shortage will be studied and other types of models fordeteriorating items in supply chain situation are also to bestudied in the future

Conflict of Interests

The author declares that there is no conflict of interestsregarding the publication of this paper

Acknowledgments

The author is grateful to the anonymous referees who pro-vided valuable comments and suggestions to significantlyimprove the quality of the paper This work was supportedpartly byHumanities and Social Science Fund of theMinistryof Education of China (no 11YJCZH019)

References

[1] P M Ghare and G F Schrader ldquoA model for exponentiallydecaying inventoriesrdquo Journal of Industrial Engineering vol 14pp 238ndash243 1963

[2] J-W Wu C Lin B Tan and W-C Lee ldquoAn EOQ inventorymodel with time-varying demand and Weibull deteriorationwith shortagesrdquo International Journal of Systems Science vol 31no 6 pp 677ndash683 2000

[3] H-M Wee ldquoDeteriorating inventory model with quantity dis-count pricing and partial backorderingrdquo International Journalof Production Economics vol 59 no 1 pp 511ndash518 1999

[4] K Skouri and S Papachristos ldquoA continuous review inven-tory model with deteriorating items time-varying demandlinear replenishment cost partially time-varying backloggingrdquoApplied Mathematical Modelling vol 26 no 5 pp 603ndash6172002

[5] H-MWee J C P Yu and S T Law ldquoTwo-warehouse inventorymodel with partial backordering and Weibull distributiondeterioration under inflationrdquo Journal of the Chinese Institute ofIndustrial Engineers vol 22 no 6 pp 451ndash462 2005

[6] C-Y Dye T-P Hsieh and L-Y Ouyang ldquoDetermining optimalselling price and lot size with a varying rate of deteriorationand exponential partial backloggingrdquo European Journal ofOperational Research vol 181 no 2 pp 668ndash678 2007

[7] R M Hill ldquoInventory models for increasing demand followedby level demandrdquo Journal of the Operational Research Societyvol 46 no 10 pp 1250ndash1259 1995

[8] B Mandal and A K Pal ldquoOrder level inventory system withramp type demand rate for deteriorating itemsrdquo Journal ofInterdisciplinary Mathematics vol 1 no 1 pp 49ndash66 1998

[9] K-S Wu ldquoAn EOQ inventory model for items with Weibulldistribution deterioration ramp type demand rate and partialbackloggingrdquo Production Planning amp Control vol 12 no 8 pp787ndash793 2001

[10] B C Giri A K Jalan and K S Chaudhuri ldquoEconomic orderquantity model with Weibull deterioration distribution short-age and ramp-type demandrdquo International Journal of SystemsScience vol 34 no 4 pp 237ndash243 2003

[11] S K Manna and K S Chaudhuri ldquoAn EOQ model withramp type demand rate time dependent deterioration rate unitproduction cost and shortagesrdquoEuropean Journal ofOperationalResearch vol 171 no 2 pp 557ndash566 2006

[12] K Skouri I Konstantaras S Papachristos and I Ganas ldquoInven-tory models with ramp type demand rate partial backloggingandWeibull deterioration raterdquoEuropean Journal ofOperationalResearch vol 192 no 1 pp 79ndash92 2009

10 Journal of Applied Mathematics

[13] K-C Hung ldquoAn inventory model with generalized typedemand deterioration and backorder ratesrdquo European Journalof Operational Research vol 208 no 3 pp 239ndash242 2011

[14] R S Kumar S K De and A Goswami ldquoFuzzy EOQ modelswith ramp type demand rate partial backlogging and timedependent deterioration raterdquo International Journal of Mathe-matics in Operational Research vol 4 no 5 pp 473ndash502 2012

[15] M B Cheng B X Zhang and G QWang ldquoOptimal policy fordeteriorating items with trapezoidal type demand and partialbackloggingrdquoAppliedMathematical Modelling vol 35 no 7 pp3552ndash3560 2011

[16] R Uthayakumar and M Rameswari ldquoAn economic produc-tion quantity model for defective items with trapezoidal typedemand raterdquo Journal of Optimization Theory and Applicationsvol 154 no 3 pp 1055ndash1079 2012

[17] Y Tan and M X Weng ldquoA discrete-in-time deterioratinginventory model with time-varying demand variable deterio-ration rate and waiting-time-dependent partial backloggingrdquoInternational Journal of Systems Science vol 44 no 8 pp 1483ndash1493 2013

[18] M A Ahmed T A Al-Khamis and L Benkherouf ldquoInventorymodels with ramp type demand rate partial backlogging andgeneral deterioration raterdquo Applied Mathematics and Computa-tion vol 219 no 9 pp 4288ndash4307 2013

[19] K-P Lin ldquoAn extended inventory models with trapezoidal typedemandsrdquo Applied Mathematics and Computation vol 219 no24 pp 11414ndash11419 2013

[20] P L Abad ldquoOptimal pricing and lot-sizing under conditionsof perishability and partial backorderingrdquoManagement Sciencevol 42 no 8 pp 1093ndash1104 1996

Submit your manuscripts athttpwwwhindawicom

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Mathematical Problems in Engineering

Hindawi Publishing Corporationhttpwwwhindawicom

Differential EquationsInternational Journal of

Volume 2014

Applied MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Probability and StatisticsHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Mathematical PhysicsAdvances in

Complex AnalysisJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

OptimizationJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

CombinatoricsHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

International Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Operations ResearchAdvances in

Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Function Spaces

Abstract and Applied AnalysisHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

International Journal of Mathematics and Mathematical Sciences

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

The Scientific World JournalHindawi Publishing Corporation httpwwwhindawicom Volume 2014

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Algebra

Discrete Dynamics in Nature and Society

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Decision SciencesAdvances in

Discrete MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom

Volume 2014 Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Stochastic AnalysisInternational Journal of

Page 9: Research Article An Inventory Model under Trapezoidal Type ...downloads.hindawi.com/journals/jam/2014/747419.pdf · an inventory model with Weibull-distributed deterioration items,

Journal of Applied Mathematics 9

By studying the results of Table 3 it is found that 119878lowast119876lowast and 119879119862(119905

lowast

1) coordinate to the deterioration parameter 120573

while the shortage time 119905lowast

1decreases as 120573 increases for the

model It is also found that the increase of 120573 from 14 to 22causes 119878

lowast to increase while the increase of 120573 from 24 to28 causes 119878lowast to decrease 119876lowast to increase by 244ndash1597119879119862(119905lowast

1) to increase by 2595ndash2066 and the shortage time

119905lowast

1to decrease by 1513ndash1455 It is also observed that the

value of 119905lowast1 119878lowast119876lowast and 119879119862(119905lowast

1) all are moderately sensitive to

the changes of 120573 for the considered inventory modelBy studying the results of Table 4 it is found that 119879119862(119905lowast

1)

coordinate to 1198881 while the shortage time 119905

lowast

1 119878lowast and 119876

lowast

decrease as 1198881increases for the model It is also found that 119888

1

increases from 83 to 150 119879119862(119905lowast1) decreases by 0269ndash

0383 119876lowast decreases by 0083ndash0058 119905lowast1decreases by

0264ndash0181 and 119878lowast decreases by 0203ndash0138 respec-tively It is also observed that the values of 119905lowast

1 119878lowast 119876lowast and

119879119862(119905lowast

1) all are lowly sensitive to the changes of 119888

1for the

considered inventory modelBy studying the results of Table 5 it is found that

119879119862(119905lowast

1) coordinates to 119888

2 while 119878

lowast 119876lowastand 119905lowast

1decrease as

1198881increases for the model It is also found that 119888

2increases

by 100 119879119862(119905lowast1) decreases by 0269ndash0383 119876lowast decreases

by 0083ndash0058 119905lowast1decreases by 0264ndash0181 and 119878

lowast

decreases by 0203ndash0138By studying the results of Table 6 it is found that 119905lowast

1 119878lowast

119876lowast and 119879119862(119905

lowast

1) coordinate to 119888

3 It is also observed that the

value of 119905lowast1 119878lowast 119876lowast and 119879119862(119905

lowast

1) all are lowly sensitive to the

changes of 1198883for the inventory models that is 119888

3increases

from 19 to 32 the change of all the parameters is nomorethan 1

By studying the results of Table 7 it is found that 119905lowast1 119878lowast

119876lowast and 119879119862(119905

lowast

1) coordinate to 119888

4 It is also observed that the

value of 119905lowast1 119878lowast 119876lowast and 119879119862(119905

lowast

1) all are lowly sensitive to the

changes of 1198884for the inventory models that is 119888

4increases

from 143 to 100 the change of all the parameters is nomore than 1

5 Conclusion

An inventory model starting without shortage for Weibull-distributed deterioration with trapezoidal type demand rateand partial backlogging is considered in this paper Theoptimal replenishment policy for the inventory model isproposed and numerical examples are provided to illustratethe theoretical results A sensitivity analysis of the optimalsolution with respect to major parameters is also carried outFrom Table 1ndash7 it can be found that the shortage time point119905lowast

1 order quantity 119876lowast and the total average cost 119879119862(119905lowast

1) are

moderately sensitive to the changes of 120572 and 120573 and lowlysensitive to the changes of 120575 119888

119894(119894 = 1 2 3 4) respectively

The paper provides an interesting topic for further studysuch that the joint influence from some of these parametersmay be investigated to show the effects the model startingwith shortage will be studied and other types of models fordeteriorating items in supply chain situation are also to bestudied in the future

Conflict of Interests

The author declares that there is no conflict of interestsregarding the publication of this paper

Acknowledgments

The author is grateful to the anonymous referees who pro-vided valuable comments and suggestions to significantlyimprove the quality of the paper This work was supportedpartly byHumanities and Social Science Fund of theMinistryof Education of China (no 11YJCZH019)

References

[1] P M Ghare and G F Schrader ldquoA model for exponentiallydecaying inventoriesrdquo Journal of Industrial Engineering vol 14pp 238ndash243 1963

[2] J-W Wu C Lin B Tan and W-C Lee ldquoAn EOQ inventorymodel with time-varying demand and Weibull deteriorationwith shortagesrdquo International Journal of Systems Science vol 31no 6 pp 677ndash683 2000

[3] H-M Wee ldquoDeteriorating inventory model with quantity dis-count pricing and partial backorderingrdquo International Journalof Production Economics vol 59 no 1 pp 511ndash518 1999

[4] K Skouri and S Papachristos ldquoA continuous review inven-tory model with deteriorating items time-varying demandlinear replenishment cost partially time-varying backloggingrdquoApplied Mathematical Modelling vol 26 no 5 pp 603ndash6172002

[5] H-MWee J C P Yu and S T Law ldquoTwo-warehouse inventorymodel with partial backordering and Weibull distributiondeterioration under inflationrdquo Journal of the Chinese Institute ofIndustrial Engineers vol 22 no 6 pp 451ndash462 2005

[6] C-Y Dye T-P Hsieh and L-Y Ouyang ldquoDetermining optimalselling price and lot size with a varying rate of deteriorationand exponential partial backloggingrdquo European Journal ofOperational Research vol 181 no 2 pp 668ndash678 2007

[7] R M Hill ldquoInventory models for increasing demand followedby level demandrdquo Journal of the Operational Research Societyvol 46 no 10 pp 1250ndash1259 1995

[8] B Mandal and A K Pal ldquoOrder level inventory system withramp type demand rate for deteriorating itemsrdquo Journal ofInterdisciplinary Mathematics vol 1 no 1 pp 49ndash66 1998

[9] K-S Wu ldquoAn EOQ inventory model for items with Weibulldistribution deterioration ramp type demand rate and partialbackloggingrdquo Production Planning amp Control vol 12 no 8 pp787ndash793 2001

[10] B C Giri A K Jalan and K S Chaudhuri ldquoEconomic orderquantity model with Weibull deterioration distribution short-age and ramp-type demandrdquo International Journal of SystemsScience vol 34 no 4 pp 237ndash243 2003

[11] S K Manna and K S Chaudhuri ldquoAn EOQ model withramp type demand rate time dependent deterioration rate unitproduction cost and shortagesrdquoEuropean Journal ofOperationalResearch vol 171 no 2 pp 557ndash566 2006

[12] K Skouri I Konstantaras S Papachristos and I Ganas ldquoInven-tory models with ramp type demand rate partial backloggingandWeibull deterioration raterdquoEuropean Journal ofOperationalResearch vol 192 no 1 pp 79ndash92 2009

10 Journal of Applied Mathematics

[13] K-C Hung ldquoAn inventory model with generalized typedemand deterioration and backorder ratesrdquo European Journalof Operational Research vol 208 no 3 pp 239ndash242 2011

[14] R S Kumar S K De and A Goswami ldquoFuzzy EOQ modelswith ramp type demand rate partial backlogging and timedependent deterioration raterdquo International Journal of Mathe-matics in Operational Research vol 4 no 5 pp 473ndash502 2012

[15] M B Cheng B X Zhang and G QWang ldquoOptimal policy fordeteriorating items with trapezoidal type demand and partialbackloggingrdquoAppliedMathematical Modelling vol 35 no 7 pp3552ndash3560 2011

[16] R Uthayakumar and M Rameswari ldquoAn economic produc-tion quantity model for defective items with trapezoidal typedemand raterdquo Journal of Optimization Theory and Applicationsvol 154 no 3 pp 1055ndash1079 2012

[17] Y Tan and M X Weng ldquoA discrete-in-time deterioratinginventory model with time-varying demand variable deterio-ration rate and waiting-time-dependent partial backloggingrdquoInternational Journal of Systems Science vol 44 no 8 pp 1483ndash1493 2013

[18] M A Ahmed T A Al-Khamis and L Benkherouf ldquoInventorymodels with ramp type demand rate partial backlogging andgeneral deterioration raterdquo Applied Mathematics and Computa-tion vol 219 no 9 pp 4288ndash4307 2013

[19] K-P Lin ldquoAn extended inventory models with trapezoidal typedemandsrdquo Applied Mathematics and Computation vol 219 no24 pp 11414ndash11419 2013

[20] P L Abad ldquoOptimal pricing and lot-sizing under conditionsof perishability and partial backorderingrdquoManagement Sciencevol 42 no 8 pp 1093ndash1104 1996

Submit your manuscripts athttpwwwhindawicom

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Mathematical Problems in Engineering

Hindawi Publishing Corporationhttpwwwhindawicom

Differential EquationsInternational Journal of

Volume 2014

Applied MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Probability and StatisticsHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Mathematical PhysicsAdvances in

Complex AnalysisJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

OptimizationJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

CombinatoricsHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

International Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Operations ResearchAdvances in

Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Function Spaces

Abstract and Applied AnalysisHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

International Journal of Mathematics and Mathematical Sciences

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

The Scientific World JournalHindawi Publishing Corporation httpwwwhindawicom Volume 2014

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Algebra

Discrete Dynamics in Nature and Society

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Decision SciencesAdvances in

Discrete MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom

Volume 2014 Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Stochastic AnalysisInternational Journal of

Page 10: Research Article An Inventory Model under Trapezoidal Type ...downloads.hindawi.com/journals/jam/2014/747419.pdf · an inventory model with Weibull-distributed deterioration items,

10 Journal of Applied Mathematics

[13] K-C Hung ldquoAn inventory model with generalized typedemand deterioration and backorder ratesrdquo European Journalof Operational Research vol 208 no 3 pp 239ndash242 2011

[14] R S Kumar S K De and A Goswami ldquoFuzzy EOQ modelswith ramp type demand rate partial backlogging and timedependent deterioration raterdquo International Journal of Mathe-matics in Operational Research vol 4 no 5 pp 473ndash502 2012

[15] M B Cheng B X Zhang and G QWang ldquoOptimal policy fordeteriorating items with trapezoidal type demand and partialbackloggingrdquoAppliedMathematical Modelling vol 35 no 7 pp3552ndash3560 2011

[16] R Uthayakumar and M Rameswari ldquoAn economic produc-tion quantity model for defective items with trapezoidal typedemand raterdquo Journal of Optimization Theory and Applicationsvol 154 no 3 pp 1055ndash1079 2012

[17] Y Tan and M X Weng ldquoA discrete-in-time deterioratinginventory model with time-varying demand variable deterio-ration rate and waiting-time-dependent partial backloggingrdquoInternational Journal of Systems Science vol 44 no 8 pp 1483ndash1493 2013

[18] M A Ahmed T A Al-Khamis and L Benkherouf ldquoInventorymodels with ramp type demand rate partial backlogging andgeneral deterioration raterdquo Applied Mathematics and Computa-tion vol 219 no 9 pp 4288ndash4307 2013

[19] K-P Lin ldquoAn extended inventory models with trapezoidal typedemandsrdquo Applied Mathematics and Computation vol 219 no24 pp 11414ndash11419 2013

[20] P L Abad ldquoOptimal pricing and lot-sizing under conditionsof perishability and partial backorderingrdquoManagement Sciencevol 42 no 8 pp 1093ndash1104 1996

Submit your manuscripts athttpwwwhindawicom

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Mathematical Problems in Engineering

Hindawi Publishing Corporationhttpwwwhindawicom

Differential EquationsInternational Journal of

Volume 2014

Applied MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Probability and StatisticsHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Mathematical PhysicsAdvances in

Complex AnalysisJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

OptimizationJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

CombinatoricsHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

International Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Operations ResearchAdvances in

Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Function Spaces

Abstract and Applied AnalysisHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

International Journal of Mathematics and Mathematical Sciences

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

The Scientific World JournalHindawi Publishing Corporation httpwwwhindawicom Volume 2014

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Algebra

Discrete Dynamics in Nature and Society

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Decision SciencesAdvances in

Discrete MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom

Volume 2014 Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Stochastic AnalysisInternational Journal of

Page 11: Research Article An Inventory Model under Trapezoidal Type ...downloads.hindawi.com/journals/jam/2014/747419.pdf · an inventory model with Weibull-distributed deterioration items,

Submit your manuscripts athttpwwwhindawicom

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Mathematical Problems in Engineering

Hindawi Publishing Corporationhttpwwwhindawicom

Differential EquationsInternational Journal of

Volume 2014

Applied MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Probability and StatisticsHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Mathematical PhysicsAdvances in

Complex AnalysisJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

OptimizationJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

CombinatoricsHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

International Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Operations ResearchAdvances in

Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Function Spaces

Abstract and Applied AnalysisHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

International Journal of Mathematics and Mathematical Sciences

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

The Scientific World JournalHindawi Publishing Corporation httpwwwhindawicom Volume 2014

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Algebra

Discrete Dynamics in Nature and Society

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Decision SciencesAdvances in

Discrete MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom

Volume 2014 Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Stochastic AnalysisInternational Journal of


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