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Research Article Solution of the Differential-Difference Equations by Optimal Homotopy Asymptotic Method H. Ullah, S. Islam, M. Idrees, and M. Fiza Department of Mathematics, Abdul Wali Khan University, Mardan 23200, Pakistan Correspondence should be addressed to H. Ullah; [email protected] Received 20 January 2014; Revised 1 May 2014; Accepted 1 May 2014; Published 29 May 2014 Academic Editor: Fuding Xie Copyright © 2014 H. Ullah et al. is is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited. We applied a new analytic approximate technique, optimal homotopy asymptotic method (OHAM), for treatment of differential- difference equations (DDEs). To see the efficiency and reliability of the method, we consider Volterra equation in different form. It provides us with a convenient way to control the convergence of approximate solutions when it is compared with other methods of solution found in the literature. e obtained solutions show that OHAM is effective, simpler, easier, and explicit. 1. Introduction In physical science the DDEs play a vital role in modeling of the complex physical phenomena. e DDEs models are used in vibration of particles in lattices, the flow of current in a network, and the pulses in biological chains. e models containing DDEs have been investigated by numerical techniques such as discretizations in solid state physics and quantum mechanics. In the last decades most of the research work has been done on DDEs. Levi and Yamilov [1, 2] attribute their work to classification of DDEs and connection of integrable partial differential equation (PDEs) and DDEs [3, 4]. In [58] the exact solutions of the DDEs have been studied. For the solution of the DDEs, Zou et al. extended the homotopy analysis method (HAM) [9, 10]. Wang et al. extended Adomian decomposition method (ADM) for solving nonlinear difference-differential equations (NDDEs) and got a good accuracy with the analytic solution [11]. Recently, Marinca et al. introduced optimal homotopy asymptotic method (OHAM) [1216] for the solution of nonlinear problems. e validity of OHAM is independent of whether or not the nonlinear problems contain small parameters. e motivation of this paper is to extend OHAM for the solution of NDDEs. In [1720] OHAM has been proved to be useful for obtaining an approximate solution of nonlinear boundary value problems of differential equations. In this work, we have proved that OHAM is also useful and reliable for the solution of NDDEs, hence showing its validity and great potential for the solution of NDDEs phenomenon in science and engineering. In the succeeding section, the basic idea of OHAM [1216] is formulated for the solution of boundary value problems. In Section 3, the effectiveness of the modified formulation of OHAM for NDDEs has been studied. 2. Basic Mathematical Theory of OHAM for NDDE Let us take OHAM to the following differential-difference equation: A (V ()) + () = 0, ∈ Ω, (1) with boundary conditions: B (V () , V () ) = 0. ∈ Γ, (2) where A is a differential operator, V () is an unknown function, and denote spatial and temporal independent variables, respectively, Γ is the boundary of Ω, and () is a known analytic function. A can be divided into two parts L and N such that A = L + N, (3) Hindawi Publishing Corporation Abstract and Applied Analysis Volume 2014, Article ID 520467, 7 pages http://dx.doi.org/10.1155/2014/520467
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Research ArticleSolution of the Differential-Difference Equations byOptimal Homotopy Asymptotic Method

H Ullah S Islam M Idrees and M Fiza

Department of Mathematics Abdul Wali Khan University Mardan 23200 Pakistan

Correspondence should be addressed to H Ullah hakeemullah1gmailcom

Received 20 January 2014 Revised 1 May 2014 Accepted 1 May 2014 Published 29 May 2014

Academic Editor Fuding Xie

Copyright copy 2014 H Ullah et alThis is an open access article distributed under the Creative Commons Attribution License whichpermits unrestricted use distribution and reproduction in any medium provided the original work is properly cited

We applied a new analytic approximate technique optimal homotopy asymptotic method (OHAM) for treatment of differential-difference equations (DDEs) To see the efficiency and reliability of the method we consider Volterra equation in different form Itprovides us with a convenient way to control the convergence of approximate solutions when it is compared with other methods ofsolution found in the literature The obtained solutions show that OHAM is effective simpler easier and explicit

1 Introduction

In physical science the DDEs play a vital role in modelingof the complex physical phenomena The DDEs modelsare used in vibration of particles in lattices the flow ofcurrent in a network and the pulses in biological chainsThe models containing DDEs have been investigated bynumerical techniques such as discretizations in solid statephysics and quantum mechanics In the last decades mostof the research work has been done on DDEs Levi andYamilov [1 2] attribute their work to classification of DDEsand connection of integrable partial differential equation(PDEs) and DDEs [3 4] In [5ndash8] the exact solutionsof the DDEs have been studied For the solution of theDDEs Zou et al extended the homotopy analysis method(HAM) [9 10]Wang et al extendedAdomian decompositionmethod (ADM) for solving nonlinear difference-differentialequations (NDDEs) and got a good accuracy with theanalytic solution [11] Recently Marinca et al introducedoptimal homotopy asymptotic method (OHAM) [12ndash16] forthe solution of nonlinear problems The validity of OHAMis independent of whether or not the nonlinear problemscontain small parameters

The motivation of this paper is to extend OHAM for thesolution of NDDEs In [17ndash20] OHAM has been proved tobe useful for obtaining an approximate solution of nonlinearboundary value problems of differential equations In thiswork we have proved that OHAM is also useful and reliable

for the solution of NDDEs hence showing its validity andgreat potential for the solution of NDDEs phenomenon inscience and engineering

In the succeeding section the basic idea of OHAM [12ndash16] is formulated for the solution of boundary value problemsIn Section 3 the effectiveness of the modified formulation ofOHAM for NDDEs has been studied

2 Basic Mathematical Theory ofOHAM for NDDE

Let us take OHAM to the following differential-differenceequation

A (V119899(119905)) + 119891 (119905) = 0 119899 isin Ω (1)

with boundary conditions

B(V119899(119905)

120597V119899(119905)

120597119905) = 0 119899 isin Γ (2)

where A is a differential operator V119899(119905) is an unknown

function 119899 and 119905 denote spatial and temporal independentvariables respectively Γ is the boundary of Ω and 119891

119899(119905) is a

known analytic functionA can be divided into two partsLandN such that

A = L +N (3)

Hindawi Publishing CorporationAbstract and Applied AnalysisVolume 2014 Article ID 520467 7 pageshttpdxdoiorg1011552014520467

2 Abstract and Applied Analysis

where L is simpler part of the partial differential equationwhich is easier to solve andN contains the remaining part ofA So (1) can be written as

L (V119899(119905)) + 119891 (119905) +N (V

119899(119905) V119899minus119896

(119905) V119899+119896

(119905)) = 0 (4)

According to OHAM one can construct an optimal homo-topy 120601

119899(119905 119902) Ω times [0 1] rarr R satisfying

(1 minus 119902) [L (120601119899(119905 119902)) + 119891 (119905)]

= 119867 (119902) [L (120601119899(119905 119902)) + 119891 (119905)

+N (120601119899(119905 119902) 120601

119899minus119896(119905 119902) 120601

119899+119896(119905 119902))]

(5)

B(120601119899(119905 119902)

120597120601119899(119905 119902)

120597119905) = 0 (6)

where 119902 isin [0 1] is an embedding parameter 120601119899(119905 119902) is an

unknown function and119867(119902) is a nonzero auxiliary functionThe auxiliary function119867(119902) is nonzero for 119902 = 0 and119867(0) =0 Equation (5) is the structure of OHAM homotopy Clearlywe have

119902 = 0 997904rArr 119867(120601119899(119905 0) 0)

= L (120601119899(119905 0)) + 119891 (119905) = 0

119902 = 1 997904rArr 119867(120601119899(119905 1) 1)

= 119867 (1) A (120601119899(119905 1)) + 119891 (119905) = 0

(7)

Obviously when 119902 = 0 and 119902 = 1 we obtain

119902 = 0 997904rArr 120601119899(119905 0) = V

1198990(119905)

119902 = 1 997904rArr 120601119899(119905 1) = V

119899(119905)

(8)

respectivelyThus as 119902 varies from 0 to 1 the solution 120601119899(119905 119902)

varies from V1198990(119905) to V

119899(119905) where V

1198990(119905) is the zeroth order

solution and can be obtained from (10)Expanding 120601

119899(119905 119902 119862

119894) 120601119899minus119896

(119905 119902 119862119894) 120601119899+119896

(119905 119902 119862119894) by

Taylors series and choosing119867(119902) as given

119867(119902) = 1199021198621+ 1199022119862

2+ 1199023119862

3+ sdot sdot sdot + 119902119898119862

119898

120601119899minus119896

(119905 119902 119862119894) = V(119899minus119896)0

(119905)

+infin

sum119898=1

V(119899minus119896)119898

(119905 119862119894) 119902119898

120601119899(119905 119902 119862

119894) = V(119899)0

(119905)

+infin

sum119898=1

V(119899)119898

(119905 119862119894) 119902119898

120601119899+119896

(119905 119902 119862119894) = V(119899+119896)0

(119905)

+infin

sum119898=1

V(119899+119896)119898

(119905 119862119894) 119902119898

(9)

where 119862119894 119894 = 1 2 3 are constants and to be determined

and119898 isin 119873

Now substituting (9) into (5) and equating the coefficientof like powers of 119902 we obtain

L (V1198990(119905)) + 119891 (119905) = 0 B(V

1198990(119905)

120597V1198990(119905)

120597119905) = 0

(10)L (V1198991(119905)) minusL (V

1198990(119905))

= 1198621[L (V

1198990(119905)) +N (V

(119899minus119896)0(119905) V1198990(119905) V(119899+119896)0

(119905))]

B(V1198991(119905)

120597V1198991(119905)

120597119905) = 0

(11)L (V1198992(119905)) minusL (V

1198991(119905))

= 1198621[L (V

1198991(119905)) +N (V

(119899minus119896)1(119905) V1198991(119905) V(119899+119896)1

(119905))]

+ 1198622[L (V

1198990(119905)) +N (V

(119899minus119896)0(119905) V1198990(119905) V(119899+119896)0

(119905))]

B(1199061198992(119899 119905)

1205971199061198992(119899 119905)

120597119905) = 0

(12)L (V1198993(119905)) minusL (V

1198992(119905))

= 1198621[L (V

1198992(119905)) +N (V

(119899minus119896)2(119905) V1198992(119905) V(119899+119896)2

(119905))]

+ 1198622[L (V

1198991(119905)) +N (V

(119899minus119896)1(119905) V1198991(119905) V(119899+119896)1

(119905))]

+ 1198623[L (V

1198990(119905)) +N (V

(119899minus119896)0(119905) V1198990(119905) V(119899+119896)0

(119905))]

B(V1198993(119905)

120597V1198993(119905)

120597119905) = 0

(13)

L (V119899119895(119905)) minusL (V

119899(119895minus1)(119905))

=119898

sum119894=1

0

sum119895=119898minus1

119862119894[L (V

119899119895(119905))

+N (V119899119895(119905) V(119899minus119896)119895

(119905) V(119899+119896)119895

(119905))]

B(V119899119895(119905)

120597V119899119895(119905)

120597119905) = 0

(14)

We obtained the zeroth order solution and first second thirdand the general order solutions by solving (10)ndash(14) In thesame way the remaining solutions can be determined It hasbeen observed that the convergence of the series (9) dependson the auxiliary constants 119862

119894 If it is convergent at 119902 = 1 one

has

V119899(119905 119862119894) = V

1198990(119909 119905) + sum

119896ge1

V119899119896(119905 119862119894) (15)

Substituting (15) into (1) it results in the following expressionfor residual

119877 (119905 119862119894) = L (V

119899(119905 119862119894)) + 119891 (119905) +N (V

119899(119905 119862119894)) (16)

Abstract and Applied Analysis 3

If 119877(119905 119862119894) = 0 then V

119899(119905 119862119894) is the exact solution of

the problem Generally it does not happen especially innonlinear problems

For the determinations of auxiliary constants 119862119894 119894 =

1 2 3 there are different methods like Galerkinrsquos methodRitz method least squares method and collocation methodOne can apply the method of least squares as follows

119869 (119862119894) = int119887

119886

intΩ

1198772 (119905 119862119894) 119889119899 119889119905 (17)

where 119886 and 119887 are two values depending on the nature of thegiven problem

The auxiliary constants 119862119894can be optimally calculated as

120597119869

1205971198621

=120597119869

1205971198622

=120597119869

1205971198623

sdot sdot sdot120597119869

120597119862119898

= 0 (18)

The119898th order approximate solution can be obtained by theseobtained constants

The convergence of OHAM is directly proportional to thenumber of optimal constants 119862

119894

3 Application of OHAM toDifference-Differential Equations

To show the validity and effectiveness of OHAM formulationto difference-differential equation we apply it to Volteraequations in different form

Model 1 We consider Voltera equation of the form

120597V119899(119905)

120597119905= V119899(119905) (V119899minus1

(119905) minus V119899+1

(119905)) 119899 ≻ 0 119905 isin [0 1]

(19)

with initial conditions

V119899(0) = 119899 (20)

The exact solution of (31) is given by

V119899(119905) =

119899

1 + 119899119905 (21)

and we take

V119899(119905) = V

1198990(119905) + 119901V

1198991(119905) + 1199012V

1198992(119905) + 1199013V

1198993(119905)

V119899+1

(119905) = V(119899+1)0

(119905) + 119901V(119899+1)1

(119905)

+ 1199012V(119899+1)2

(119905) + 1199013V(119899+1)3

(119905)

V119899minus1

(119905) = V(119899minus1)0

(119905) + 119901V(119899minus1)1

(119905)

+ 1199012V(119899minus1)2

(119905) + 1199013V(119899minus1)3

(119905)

(22)

According to (1) we have

L =120597V119899(119905)

120597119905 119891 (119905) = 0

N = minusV119899(119905) (V119899minus1

(119905) minus V119899+1

(119905))

(23)

Using (19) (20) and (22) into (5) and using the methoddiscussed in Section 2 lead to the following

Zeroth Order Problem Consider120597V1198990(119905)

120597119905= 0 (24)

with

V1198990(0) =119899 (25)

from which we obtain

V1198990(119905) =119899 (26)

First Order Problem One has120597V1198991(119905)

120597119905= (1 + 119862

1)120597V1198990(119905)

120597119905

+ 1198621(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198990(119905)

(27)

with

V1198991(0) = 0 (28)

Its solution is

V1198991(119905) = 2119862

1119899119905 (29)

Second Order Problem Consider120597V1198992(119905)

120597119905= (1 + 119862

1)120597V1198991(119905)

120597119905+ 1198622

120597V1198990(119905)

120597119905

+ 1198621(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198991(119905)

+ 1198621(V(119899+1)1

(119905) minus V(119899minus1)1

(119905)) V1198990(119905)

+ 1198622(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198990(119905)

(30)

with

V1198992(0) = 0 (31)

V1198992(119905) = 2 (119862

1119899119905 + 1198622

1119899119905 + 119862

2119899119905 + 21198622

11198991199052) (32)

Third Order Problem One has120597V1198993(119905)

120597119905= (1 + 119862

1)120597V1198992(119905)

120597119905+ 1198622

120597V1198991(119905)

120597119905+ 1198623

120597V1198990(119905)

120597119905

+ 1198621(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198992(119905)

+ 1198621(V(119899+1)1

(119905) minus V(119899minus1)1

(119905)) V1198991(119905)

+ 1198622(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198991(119905)

+ 1198621(V(119899+1)2

(119905) minus V(119899minus1)2

(119905)) V1198990

+ 1198622(V(119899+1)1

(119905) minus V(119899minus1)1

(119905)) V1198990(119905)

+ 1198623(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198990(119905)

(33)

4 Abstract and Applied Analysis

Table 1 Comparisons of OHAM exact and ADM results atdifferent values of 119899 at 119905 = 1

119899 OHAM Exact ADM Abs error1 0333333 0333333 0333333 717103 times 10minus7

2 0666665 0666665 0666665 143421 times 10minus6

3 0999998 0999998 0999998 215131 times 10minus6

4 133333 133333 133333 286841 times 10minus6

5 166666 166666 166666 358551 times 10minus6

6 2 2 2 430262 times 10minus6

7 233333 233333 233333 501972 times 10minus6

8 266666 266666 266666 573682 times 10minus6

9 299999 299999 299999 645392 times 10minus6

10 333333 333333 333333 717103 times 10minus6

Table 2 Comparisons of first second and third order and exactsolutions at different values of 119899 at 119905 = 1

119899 First order Second order Third order Exact sol1 0527142 0858619 0333333 03333332 105428 171724 0666665 06666653 158143 257586 0999998 09999984 210857 343447 133333 1333335 263571 429309 166666 1666666 316285 515171 2 27 368999 601033 233333 2333338 421713 686895 266666 2666669 474428 772757 299999 29999910 527142 858619 333333 333333

with

V1198993(0) = 0 (34)

V1198993(119905) =

2

3(31198621119899119905 + 61198622

1119899119905 + 31198623

1119899119905 + 3119862

2119899119905 + 3119862

3119899119905

+12119862211198991199052 + 121198623

11198991199052 + 6119862

111986221198991199052 + 41198623

11198991199053)

(35)

Adding (26) (29) (32) and (35) we obtain

V119899(119905) = V

1198990(119905) + V

1198991(119905 1198621) + V1198992(119905 1198621 1198622)

+ V1198993(119905 1198621 1198622 1198623)

(36)

V119899(119905) = 119899 + 2119862

1119899119905 + 2 (119862

1119899119905 + 1198622

1119899119905 + 119862

2119899119905 + 21198622

11198991199052)

+2

3(31198621119899119905 + 61198622

1119899119905 + 31198623

1119899119905 + 3119862

2119899119905 + 3119862

3119899119905

+12119862211198991199052 + 121198623

11198991199052 + 6119862

111986221198991199052 + 41198623

11198991199053) (37)

For the computation of the constants1198621 1198622 and119862

3applying

the method of least square mentioned in (16)ndash(18) we get

1198621= minus023642908394894221

1198622= 02344713680405294

1198623= minus04015040325725273 for 119899 = 1

(38)

2 4 6 8 1000

05

10

15

20

25

30

ADMExactOHAM

n

n

Figure 1 Comparison ofOHAM exact andADMsolutions at 119905 = 1

2 4 6 8 10minus6

minus5

minus4

minus3

minus2

minus1

0Re

sidual

Residual

n

Figure 2 Residual of (19) at 119905 = 1

Putting these values in (37) we obtained the approximatesolution of the form

V119899(119905) = 119899 minus 0472858119899119905 + 2 (005119899119905 + 01117971198991199052)

+2

3(minus0914641119899119905 + 01795761198991199052 minus 005286431198991199053)

(39)

The exact solution of the problem (31) is [11]

V119899(119905) =

119899

1 + 119899119905 (40)

The Adomian solution with Pade approximation of (31) isgiven by [11]

V119899(119905) =

119899

1 + 119899119905 (41)

Abstract and Applied Analysis 5

Model 2 Now consider another form of Volterra equation

120597V119899(119905)

120597119905= V119899(119905) (V119899minus1

(119905) minus V119899+1

(119905))

+ V119899(119905) (V119899minus2

(119905) minus V119899+2

(119905)) 119899 ≻ 0 119905 isin [0 1] (42)

with initial conditions

V119899(0) = 119899 (43)

The exact solution of (42) is given by

V119899(119905) =

119899

1 + 6119905 (44)

We take

V119899(119905) = V

1198990(119905) + 119901V

1198991(119905) + 1199012V

1198992(119905)

+ 1199013V1198993(119905)

V119899+1

(119905) = V(119899+1)0

(119905) + 119901V(119899+1)1

(119905)

+ 1199012V(119899+1)2

(119905) + 1199013V(119899+1)3

(119905)

V119899minus1

(119905) = V(119899minus1)0

(119905) + 119901V(119899minus1)1

(119905)

+ 1199012V(119899minus1)2

(119905) + 1199013V(119899minus1)3

(119905)

V119899+2

(119905) = V(119899+2)0

(119905) + 119901V(119899+2)1

(119905)

+ 1199012V(119899+2)2

(119905) + 1199013V(119899+2)3

(119905)

V119899minus2

(119905) = V(119899minus2)0

(119905) + 119901V(119899minus2)1

(119905)

+ 1199012V(119899minus2)2

(119905) + 1199013V(119899minus2)3

(119905)

(45)

According to (1) we have

L =120597V119899(119905)

120597119905 119891 (119905) = 0

N = minusV119899(119905) (V119899minus1

(119905) minus V119899+1

(119905))

minus V119899(119905) (V119899minus2

(119905) minus V119899+2

(119905))

(46)

Using (42) (43) and (45) into (5) and using the methoddiscussed in Section 2 lead to the following

Zeroth Order Problem Consider

120597V1198990(119905)

120597119905= 0 (47)

with

V1198990(0) = 119899 (48)

from which we obtain

V1198990(119905) = 119899 (49)

First Order Problem One has the following

120597V1198991(119905)

120597119905= (1 + 119862

1)120597V1198990(119905)

120597119905

+ 1198621(V(119899+2)0

(119905) minus 1198621V(119899minus2)0

(119905)) V1198990(119905)

+ 1198621(V(119899+1)0

(119905) minus 1198621V(119899minus1)0

(119905)) V1198990(119905)

(50)

with

V1198991(0) = 0 (51)

Its solution is

V1198991(119905) = 6119862

1119899119905 (52)

Second Order Problem Consider

120597V1198992(119905)

120597119905= (1 + 119862

1)120597V1198991(119905)

120597119905+ 1198622

120597V1198990(119905)

120597119905

+ 1198621(V(119899+2)1

(119905) minus V(119899minus2)1

(119905)) V1198990(119905)

+ 1198622(V(119899+2)0

(119905) minus V(119899minus2)0

(119905)) V1198990

+ 1198621(V(119899+2)0

(119905) minus V(119899minus2)0

(119905)) V1198991(119905)

+ 1198621(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198991(119905)

+ 1198622(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198990(119905)

+ 1198621(V(119899+1)1

(119905) minus V(119899minus1)1

(119905)) V1198990(119905)

(53)

with

V1198992(0) = 0 (54)

V1198992(119905) = 6119899119905 (119862

1+ 1198622+ 11986221(1 + 6119905)) (55)

Third Order Problem One has

120597V1198993(119905)

120597119905= (1 + 119862

1)120597V1198992(119905)

120597119905+ 1198622

120597V1198991(119905)

120597119905+ 1198623

120597V1198990(119905)

120597119905

+ 1198621(V(119899+2)2

(119905) minus V(119899minus2)2

(119905)) V1198990(119905)

+ 1198622(V(119899+2)1

(119905) minus V(119899minus2)1

(119905)) V1198990(119905)

+ 1198623(V(119899+2)0

(119905) minus V(119899minus2)0

(119905)) V1198990(119905)

+ 1198621(V(119899+2)1

(119905) minus V(119899minus2)1

(119905)) V1198991(119905)

6 Abstract and Applied Analysis

+ 1198622(V(119899+2)0

(119905) minus V(119899minus2)0

(119905)) V1198991(119905)

+ 1198621(V(119899+2)0

(119905) minus V(119899minus2)0

(119905)) V1198992(119905)

+ 1198621(V(119899+1)2

(119905) minus V(119899minus1)2

(119905)) V1198990(119905)

+ 1198621(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198992(119905)

+ 1198621(V(119899+1)1

(119905) minus V(119899minus1)1

(119905)) V1198991(119905)

+ 1198622(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198991(119905)

+ 1198621(V(119899+1)2

(119905) minus V(119899minus1)2

(119905)) V1198990(119905)

+ 1198622(V(119899+1)1

minus V(119899minus1)1

) V1198990(119899 119905)

+ 1198623(V(119899+1)0

(119899 119905) minus V(119899minus1)0

(119899 119905)) V1198990(119905)

(56)

with

V1198993(0) = 0 (57)

V1198993(119905) = 6119899119905 (119862

2+ 1198623+ 211986221(1 + 6119905)

+11986231(1 + 6119905)2 + 119862

1(1 + 2119862

2(1 + 6119905)))

(58)

Adding (49) (52) (55) and (58) we obtain

V119899(119905) = V

1198990(119905) + V

1198991(119905 1198621) + V1198992(119905 1198621 1198622)

+ V1198993(119905 1198621 1198622 1198623)

V1198993(119905) = 119899 + 6119862

1119899119905 + 6119899119905 (119862

1+ 1198622+ 11986221(1 + 6119905))

+ 6119899119905 (1198622+ 1198623+ 211986221(1 + 6119905) + 1198623

1(1 + 6119905)2

+ 11986231(1 + 6119905)2 + 119862

1(1 + 2119862

2(1 + 6119905)))

(59)

For the computation of the constants11986211198622 and119862

3applying

the method of least square mentioned in (16)ndash(18) we get

1198621= minus023640805995815892

1198622= minus0039496242739004025

1198623= minus0012135699742215487 for 119899 = 1

(60)

The exact solution of problem (42) is [9]

V119899(119905) =

119899

1 + 6119905 (61)

The HAM solution of (42) is given by [9]

V119899(119905) = (119899 + 119905) + ℎ (119899 + 1) 119905 + 3ℎ1199052 + 119905ℎ (1 + ℎ) (1 + 6119899)

+ (36ℎ2119899 + 6ℎ2 + 3ℎ) 1199052 + 18ℎ21199053(62)

2 4 6 8 1000

02

04

06

08

10

12

14

HAMExactOHAM

n

n

Figure 3 Comparisons of OHAM HAM and exact solutions at 119905 =1 ℎ = minus1

0 2 4 6 8 1000

05

10

15

20

25

ExactThird

SecondFirst

n

n

Figure 4 Comparison of first second third of OHAM HAM andexact solutions at 119905 = 1 ℎ = minus1

0 2 4 6 8 10minus7

minus6

minus5

minus4

minus3

minus2

minus1

0

Resid

ual

Residual

n

Figure 5 Residual of (42) at 119905 = 1

Abstract and Applied Analysis 7

4 Results and Discussions

The formulation presented in Section 2 provides highly accu-rate solutions for the problems demonstrated in Section 3We have used Mathematica 7 for most of our computationalwork Table 1 and Figure 1 give the comparisons of OHAMwith ADM and exact solutions for Model 1 Also the absoluteerrors at different values of 119899 at 119905 = 1 are given (Figure 4)Figure 3 shows the comparisons ofOHAMresults withHAMexact at different values of 119899 at 119905 = 1 for Model 2 Theconvergence of approximate orders to exact solutions is givenin Table 2 for Model 1 and Figure 5 for Model 2The residualshave been plotted for Model 1 in Figure 2 and for Model 2in Figure 5 We have concluded that the results obtained byOHAM are identical to the results obtained by ADM HAMand exact OHAM converges rapidly with increasing of theorder of approximation

5 Conclusion

In this work we have seen the effectiveness of OHAM[12ndash16] to differential-difference equations By applying thebasic idea of OHAM to differential-difference equations wefound it simpler in applicability more convenient to con-trol convergence and involved less computational overheadTherefore OHAM shows its validity and great potential forthe differential-difference equations arising in science andengineering

Conflict of Interests

The authors declare that there is no conflict of interestsregarding the publication of this paper

Acknowledgment

Theauthors are thankful to the anonymous reviewers for theirconstructive and valuable suggestions

References

[1] D Levi and R Yamilov ldquoConditions for the existence of highersymmetries of evolutionary equations on the latticerdquo Journal ofMathematical Physics vol 38 no 12 pp 6648ndash6674 1997

[2] R I Yamilov ldquoConstruction scheme for discreteMiura transfor-mationsrdquo Journal of Physics A Mathematical and General vol27 no 20 pp 6839ndash6851 1994

[3] I Yu Cherdantsev and R I Yamilov ldquoMaster symmetries fordifferential-difference equations of the Volterra typerdquo PhysicaD Nonlinear Phenomena vol 87 no 1ndash4 pp 140ndash144 1995

[4] A B Shabat and R I Yamilov ldquoSymmetries of nonlinearlatticesrdquo Leningrad Mathematical Journal vol 2 p 377 1991

[5] D-J Zhang ldquoSingular solutions in Casoratian form for twodifferential-difference equationsrdquo Chaos Solitons and Fractalsvol 23 no 4 pp 1333ndash1350 2005

[6] K Narita ldquoSoliton solution for a highly nonlinear difference-differential equationrdquo Chaos Solitons and Fractals vol 3 no 3pp 279ndash283 1993

[7] Z Wang and H-Q Zhang ldquoNew exact solutions to somedifference differential equationsrdquoChinese Physics vol 15 no 10pp 2210ndash2215 2006

[8] W Zhen and H Zhang ldquoA symbolic computational methodfor constructing exact solutions to difference-differential equa-tionsrdquoAppliedMathematics andComputation vol 178 no 2 pp431ndash440 2006

[9] L Zou Z Zong and G H Dong ldquoGeneralizing homotopyanalysis method to solve Lotka-Volterra equationrdquo Computersamp Mathematics with Applications vol 56 no 9 pp 2289ndash22932008

[10] Z Wang L Zou and H Zhang ldquoApplying homotopy analysismethod for solving differential-difference equationrdquo PhysicsLetters A General Atomic and Solid State Physics vol 369 no1-2 pp 77ndash84 2007

[11] Z Wang L Zou and Z Zong ldquoAdomian decomposition andPade approximate for solving differential-difference equationrdquoApplied Mathematics and Computation vol 218 no 4 pp 1371ndash1378 2011

[12] N Herisanu and VMarinca ldquoExplicit analytical approximationto large-amplitude non-linear oscillations of a uniform can-tilever beam carrying an intermediate lumped mass and rotaryinertiardquoMeccanica vol 45 no 6 pp 847ndash855 2010

[13] V Marinca and N Herisanu ldquoApplication of optimal homotopyasymptotic method for solving nonlinear equations arising inheat transferrdquo International Communications in Heat and MassTransfer vol 35 no 6 pp 710ndash715 2008

[14] V Marinca N Herisanu C Bota and B Marinca ldquoAn optimalhomotopy asymptotic method applied to the steady flow of afourth-grade fluid past a porous platerdquo Applied MathematicsLetters vol 22 no 2 pp 245ndash251 2009

[15] V Marinca N Herisanu and I Nemes ldquoA new analyticapproach to nonlinear vibration of an electrical machinerdquoProceedings of the RomanianAcademy vol 9 pp 229ndash236 2008

[16] V Marinca and N Herisanu ldquoDetermination of periodicsolutions for the motion of a particle on a rotating parabola bymeans of the optimal homotopy asymptotic methodrdquo Journal ofSound and Vibration vol 329 no 9 pp 1450ndash1459 2010

[17] M Idrees S Islam and A M Tirmizi ldquoApplication of optimalhomotopy asymptotic method of the Korteqag-de-Varies equa-tionrdquo Computers amp Mathematics with Applications vol 63 pp695ndash707 2012

[18] HUllah S IslamM Idrees andMArif ldquoSolution of boundarylayer problems with heat transfer by optimal homotopy asymp-totic methodrdquo Abstract and Applied Analysis vol 2013 ArticleID 324869 10 pages 2013

[19] R Nawaz H Ullah S Islam and M Idrees ldquoApplication ofoptimal homotopy asymptotic method to Burger equationsrdquoJournal of Applied Mathematics vol 2013 Article ID 387478 8pages 2013

[20] H Ullah S Islam M Idrees and R Nawaz ldquoApplicationof optimal homotopy asymptotic method to doubly wavesolutions of the coupled Drinfelrsquod-Sokolov-Wilson EquationsrdquoMathematical Problems in Engineering vol 2013 Article ID362816 8 pages 2013

Submit your manuscripts athttpwwwhindawicom

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Mathematical Problems in Engineering

Hindawi Publishing Corporationhttpwwwhindawicom

Differential EquationsInternational Journal of

Volume 2014

Applied MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Probability and StatisticsHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Mathematical PhysicsAdvances in

Complex AnalysisJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

OptimizationJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

CombinatoricsHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

International Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Operations ResearchAdvances in

Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Function Spaces

Abstract and Applied AnalysisHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

International Journal of Mathematics and Mathematical Sciences

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

The Scientific World JournalHindawi Publishing Corporation httpwwwhindawicom Volume 2014

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Algebra

Discrete Dynamics in Nature and Society

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Decision SciencesAdvances in

Discrete MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom

Volume 2014 Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Stochastic AnalysisInternational Journal of

2 Abstract and Applied Analysis

where L is simpler part of the partial differential equationwhich is easier to solve andN contains the remaining part ofA So (1) can be written as

L (V119899(119905)) + 119891 (119905) +N (V

119899(119905) V119899minus119896

(119905) V119899+119896

(119905)) = 0 (4)

According to OHAM one can construct an optimal homo-topy 120601

119899(119905 119902) Ω times [0 1] rarr R satisfying

(1 minus 119902) [L (120601119899(119905 119902)) + 119891 (119905)]

= 119867 (119902) [L (120601119899(119905 119902)) + 119891 (119905)

+N (120601119899(119905 119902) 120601

119899minus119896(119905 119902) 120601

119899+119896(119905 119902))]

(5)

B(120601119899(119905 119902)

120597120601119899(119905 119902)

120597119905) = 0 (6)

where 119902 isin [0 1] is an embedding parameter 120601119899(119905 119902) is an

unknown function and119867(119902) is a nonzero auxiliary functionThe auxiliary function119867(119902) is nonzero for 119902 = 0 and119867(0) =0 Equation (5) is the structure of OHAM homotopy Clearlywe have

119902 = 0 997904rArr 119867(120601119899(119905 0) 0)

= L (120601119899(119905 0)) + 119891 (119905) = 0

119902 = 1 997904rArr 119867(120601119899(119905 1) 1)

= 119867 (1) A (120601119899(119905 1)) + 119891 (119905) = 0

(7)

Obviously when 119902 = 0 and 119902 = 1 we obtain

119902 = 0 997904rArr 120601119899(119905 0) = V

1198990(119905)

119902 = 1 997904rArr 120601119899(119905 1) = V

119899(119905)

(8)

respectivelyThus as 119902 varies from 0 to 1 the solution 120601119899(119905 119902)

varies from V1198990(119905) to V

119899(119905) where V

1198990(119905) is the zeroth order

solution and can be obtained from (10)Expanding 120601

119899(119905 119902 119862

119894) 120601119899minus119896

(119905 119902 119862119894) 120601119899+119896

(119905 119902 119862119894) by

Taylors series and choosing119867(119902) as given

119867(119902) = 1199021198621+ 1199022119862

2+ 1199023119862

3+ sdot sdot sdot + 119902119898119862

119898

120601119899minus119896

(119905 119902 119862119894) = V(119899minus119896)0

(119905)

+infin

sum119898=1

V(119899minus119896)119898

(119905 119862119894) 119902119898

120601119899(119905 119902 119862

119894) = V(119899)0

(119905)

+infin

sum119898=1

V(119899)119898

(119905 119862119894) 119902119898

120601119899+119896

(119905 119902 119862119894) = V(119899+119896)0

(119905)

+infin

sum119898=1

V(119899+119896)119898

(119905 119862119894) 119902119898

(9)

where 119862119894 119894 = 1 2 3 are constants and to be determined

and119898 isin 119873

Now substituting (9) into (5) and equating the coefficientof like powers of 119902 we obtain

L (V1198990(119905)) + 119891 (119905) = 0 B(V

1198990(119905)

120597V1198990(119905)

120597119905) = 0

(10)L (V1198991(119905)) minusL (V

1198990(119905))

= 1198621[L (V

1198990(119905)) +N (V

(119899minus119896)0(119905) V1198990(119905) V(119899+119896)0

(119905))]

B(V1198991(119905)

120597V1198991(119905)

120597119905) = 0

(11)L (V1198992(119905)) minusL (V

1198991(119905))

= 1198621[L (V

1198991(119905)) +N (V

(119899minus119896)1(119905) V1198991(119905) V(119899+119896)1

(119905))]

+ 1198622[L (V

1198990(119905)) +N (V

(119899minus119896)0(119905) V1198990(119905) V(119899+119896)0

(119905))]

B(1199061198992(119899 119905)

1205971199061198992(119899 119905)

120597119905) = 0

(12)L (V1198993(119905)) minusL (V

1198992(119905))

= 1198621[L (V

1198992(119905)) +N (V

(119899minus119896)2(119905) V1198992(119905) V(119899+119896)2

(119905))]

+ 1198622[L (V

1198991(119905)) +N (V

(119899minus119896)1(119905) V1198991(119905) V(119899+119896)1

(119905))]

+ 1198623[L (V

1198990(119905)) +N (V

(119899minus119896)0(119905) V1198990(119905) V(119899+119896)0

(119905))]

B(V1198993(119905)

120597V1198993(119905)

120597119905) = 0

(13)

L (V119899119895(119905)) minusL (V

119899(119895minus1)(119905))

=119898

sum119894=1

0

sum119895=119898minus1

119862119894[L (V

119899119895(119905))

+N (V119899119895(119905) V(119899minus119896)119895

(119905) V(119899+119896)119895

(119905))]

B(V119899119895(119905)

120597V119899119895(119905)

120597119905) = 0

(14)

We obtained the zeroth order solution and first second thirdand the general order solutions by solving (10)ndash(14) In thesame way the remaining solutions can be determined It hasbeen observed that the convergence of the series (9) dependson the auxiliary constants 119862

119894 If it is convergent at 119902 = 1 one

has

V119899(119905 119862119894) = V

1198990(119909 119905) + sum

119896ge1

V119899119896(119905 119862119894) (15)

Substituting (15) into (1) it results in the following expressionfor residual

119877 (119905 119862119894) = L (V

119899(119905 119862119894)) + 119891 (119905) +N (V

119899(119905 119862119894)) (16)

Abstract and Applied Analysis 3

If 119877(119905 119862119894) = 0 then V

119899(119905 119862119894) is the exact solution of

the problem Generally it does not happen especially innonlinear problems

For the determinations of auxiliary constants 119862119894 119894 =

1 2 3 there are different methods like Galerkinrsquos methodRitz method least squares method and collocation methodOne can apply the method of least squares as follows

119869 (119862119894) = int119887

119886

intΩ

1198772 (119905 119862119894) 119889119899 119889119905 (17)

where 119886 and 119887 are two values depending on the nature of thegiven problem

The auxiliary constants 119862119894can be optimally calculated as

120597119869

1205971198621

=120597119869

1205971198622

=120597119869

1205971198623

sdot sdot sdot120597119869

120597119862119898

= 0 (18)

The119898th order approximate solution can be obtained by theseobtained constants

The convergence of OHAM is directly proportional to thenumber of optimal constants 119862

119894

3 Application of OHAM toDifference-Differential Equations

To show the validity and effectiveness of OHAM formulationto difference-differential equation we apply it to Volteraequations in different form

Model 1 We consider Voltera equation of the form

120597V119899(119905)

120597119905= V119899(119905) (V119899minus1

(119905) minus V119899+1

(119905)) 119899 ≻ 0 119905 isin [0 1]

(19)

with initial conditions

V119899(0) = 119899 (20)

The exact solution of (31) is given by

V119899(119905) =

119899

1 + 119899119905 (21)

and we take

V119899(119905) = V

1198990(119905) + 119901V

1198991(119905) + 1199012V

1198992(119905) + 1199013V

1198993(119905)

V119899+1

(119905) = V(119899+1)0

(119905) + 119901V(119899+1)1

(119905)

+ 1199012V(119899+1)2

(119905) + 1199013V(119899+1)3

(119905)

V119899minus1

(119905) = V(119899minus1)0

(119905) + 119901V(119899minus1)1

(119905)

+ 1199012V(119899minus1)2

(119905) + 1199013V(119899minus1)3

(119905)

(22)

According to (1) we have

L =120597V119899(119905)

120597119905 119891 (119905) = 0

N = minusV119899(119905) (V119899minus1

(119905) minus V119899+1

(119905))

(23)

Using (19) (20) and (22) into (5) and using the methoddiscussed in Section 2 lead to the following

Zeroth Order Problem Consider120597V1198990(119905)

120597119905= 0 (24)

with

V1198990(0) =119899 (25)

from which we obtain

V1198990(119905) =119899 (26)

First Order Problem One has120597V1198991(119905)

120597119905= (1 + 119862

1)120597V1198990(119905)

120597119905

+ 1198621(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198990(119905)

(27)

with

V1198991(0) = 0 (28)

Its solution is

V1198991(119905) = 2119862

1119899119905 (29)

Second Order Problem Consider120597V1198992(119905)

120597119905= (1 + 119862

1)120597V1198991(119905)

120597119905+ 1198622

120597V1198990(119905)

120597119905

+ 1198621(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198991(119905)

+ 1198621(V(119899+1)1

(119905) minus V(119899minus1)1

(119905)) V1198990(119905)

+ 1198622(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198990(119905)

(30)

with

V1198992(0) = 0 (31)

V1198992(119905) = 2 (119862

1119899119905 + 1198622

1119899119905 + 119862

2119899119905 + 21198622

11198991199052) (32)

Third Order Problem One has120597V1198993(119905)

120597119905= (1 + 119862

1)120597V1198992(119905)

120597119905+ 1198622

120597V1198991(119905)

120597119905+ 1198623

120597V1198990(119905)

120597119905

+ 1198621(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198992(119905)

+ 1198621(V(119899+1)1

(119905) minus V(119899minus1)1

(119905)) V1198991(119905)

+ 1198622(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198991(119905)

+ 1198621(V(119899+1)2

(119905) minus V(119899minus1)2

(119905)) V1198990

+ 1198622(V(119899+1)1

(119905) minus V(119899minus1)1

(119905)) V1198990(119905)

+ 1198623(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198990(119905)

(33)

4 Abstract and Applied Analysis

Table 1 Comparisons of OHAM exact and ADM results atdifferent values of 119899 at 119905 = 1

119899 OHAM Exact ADM Abs error1 0333333 0333333 0333333 717103 times 10minus7

2 0666665 0666665 0666665 143421 times 10minus6

3 0999998 0999998 0999998 215131 times 10minus6

4 133333 133333 133333 286841 times 10minus6

5 166666 166666 166666 358551 times 10minus6

6 2 2 2 430262 times 10minus6

7 233333 233333 233333 501972 times 10minus6

8 266666 266666 266666 573682 times 10minus6

9 299999 299999 299999 645392 times 10minus6

10 333333 333333 333333 717103 times 10minus6

Table 2 Comparisons of first second and third order and exactsolutions at different values of 119899 at 119905 = 1

119899 First order Second order Third order Exact sol1 0527142 0858619 0333333 03333332 105428 171724 0666665 06666653 158143 257586 0999998 09999984 210857 343447 133333 1333335 263571 429309 166666 1666666 316285 515171 2 27 368999 601033 233333 2333338 421713 686895 266666 2666669 474428 772757 299999 29999910 527142 858619 333333 333333

with

V1198993(0) = 0 (34)

V1198993(119905) =

2

3(31198621119899119905 + 61198622

1119899119905 + 31198623

1119899119905 + 3119862

2119899119905 + 3119862

3119899119905

+12119862211198991199052 + 121198623

11198991199052 + 6119862

111986221198991199052 + 41198623

11198991199053)

(35)

Adding (26) (29) (32) and (35) we obtain

V119899(119905) = V

1198990(119905) + V

1198991(119905 1198621) + V1198992(119905 1198621 1198622)

+ V1198993(119905 1198621 1198622 1198623)

(36)

V119899(119905) = 119899 + 2119862

1119899119905 + 2 (119862

1119899119905 + 1198622

1119899119905 + 119862

2119899119905 + 21198622

11198991199052)

+2

3(31198621119899119905 + 61198622

1119899119905 + 31198623

1119899119905 + 3119862

2119899119905 + 3119862

3119899119905

+12119862211198991199052 + 121198623

11198991199052 + 6119862

111986221198991199052 + 41198623

11198991199053) (37)

For the computation of the constants1198621 1198622 and119862

3applying

the method of least square mentioned in (16)ndash(18) we get

1198621= minus023642908394894221

1198622= 02344713680405294

1198623= minus04015040325725273 for 119899 = 1

(38)

2 4 6 8 1000

05

10

15

20

25

30

ADMExactOHAM

n

n

Figure 1 Comparison ofOHAM exact andADMsolutions at 119905 = 1

2 4 6 8 10minus6

minus5

minus4

minus3

minus2

minus1

0Re

sidual

Residual

n

Figure 2 Residual of (19) at 119905 = 1

Putting these values in (37) we obtained the approximatesolution of the form

V119899(119905) = 119899 minus 0472858119899119905 + 2 (005119899119905 + 01117971198991199052)

+2

3(minus0914641119899119905 + 01795761198991199052 minus 005286431198991199053)

(39)

The exact solution of the problem (31) is [11]

V119899(119905) =

119899

1 + 119899119905 (40)

The Adomian solution with Pade approximation of (31) isgiven by [11]

V119899(119905) =

119899

1 + 119899119905 (41)

Abstract and Applied Analysis 5

Model 2 Now consider another form of Volterra equation

120597V119899(119905)

120597119905= V119899(119905) (V119899minus1

(119905) minus V119899+1

(119905))

+ V119899(119905) (V119899minus2

(119905) minus V119899+2

(119905)) 119899 ≻ 0 119905 isin [0 1] (42)

with initial conditions

V119899(0) = 119899 (43)

The exact solution of (42) is given by

V119899(119905) =

119899

1 + 6119905 (44)

We take

V119899(119905) = V

1198990(119905) + 119901V

1198991(119905) + 1199012V

1198992(119905)

+ 1199013V1198993(119905)

V119899+1

(119905) = V(119899+1)0

(119905) + 119901V(119899+1)1

(119905)

+ 1199012V(119899+1)2

(119905) + 1199013V(119899+1)3

(119905)

V119899minus1

(119905) = V(119899minus1)0

(119905) + 119901V(119899minus1)1

(119905)

+ 1199012V(119899minus1)2

(119905) + 1199013V(119899minus1)3

(119905)

V119899+2

(119905) = V(119899+2)0

(119905) + 119901V(119899+2)1

(119905)

+ 1199012V(119899+2)2

(119905) + 1199013V(119899+2)3

(119905)

V119899minus2

(119905) = V(119899minus2)0

(119905) + 119901V(119899minus2)1

(119905)

+ 1199012V(119899minus2)2

(119905) + 1199013V(119899minus2)3

(119905)

(45)

According to (1) we have

L =120597V119899(119905)

120597119905 119891 (119905) = 0

N = minusV119899(119905) (V119899minus1

(119905) minus V119899+1

(119905))

minus V119899(119905) (V119899minus2

(119905) minus V119899+2

(119905))

(46)

Using (42) (43) and (45) into (5) and using the methoddiscussed in Section 2 lead to the following

Zeroth Order Problem Consider

120597V1198990(119905)

120597119905= 0 (47)

with

V1198990(0) = 119899 (48)

from which we obtain

V1198990(119905) = 119899 (49)

First Order Problem One has the following

120597V1198991(119905)

120597119905= (1 + 119862

1)120597V1198990(119905)

120597119905

+ 1198621(V(119899+2)0

(119905) minus 1198621V(119899minus2)0

(119905)) V1198990(119905)

+ 1198621(V(119899+1)0

(119905) minus 1198621V(119899minus1)0

(119905)) V1198990(119905)

(50)

with

V1198991(0) = 0 (51)

Its solution is

V1198991(119905) = 6119862

1119899119905 (52)

Second Order Problem Consider

120597V1198992(119905)

120597119905= (1 + 119862

1)120597V1198991(119905)

120597119905+ 1198622

120597V1198990(119905)

120597119905

+ 1198621(V(119899+2)1

(119905) minus V(119899minus2)1

(119905)) V1198990(119905)

+ 1198622(V(119899+2)0

(119905) minus V(119899minus2)0

(119905)) V1198990

+ 1198621(V(119899+2)0

(119905) minus V(119899minus2)0

(119905)) V1198991(119905)

+ 1198621(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198991(119905)

+ 1198622(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198990(119905)

+ 1198621(V(119899+1)1

(119905) minus V(119899minus1)1

(119905)) V1198990(119905)

(53)

with

V1198992(0) = 0 (54)

V1198992(119905) = 6119899119905 (119862

1+ 1198622+ 11986221(1 + 6119905)) (55)

Third Order Problem One has

120597V1198993(119905)

120597119905= (1 + 119862

1)120597V1198992(119905)

120597119905+ 1198622

120597V1198991(119905)

120597119905+ 1198623

120597V1198990(119905)

120597119905

+ 1198621(V(119899+2)2

(119905) minus V(119899minus2)2

(119905)) V1198990(119905)

+ 1198622(V(119899+2)1

(119905) minus V(119899minus2)1

(119905)) V1198990(119905)

+ 1198623(V(119899+2)0

(119905) minus V(119899minus2)0

(119905)) V1198990(119905)

+ 1198621(V(119899+2)1

(119905) minus V(119899minus2)1

(119905)) V1198991(119905)

6 Abstract and Applied Analysis

+ 1198622(V(119899+2)0

(119905) minus V(119899minus2)0

(119905)) V1198991(119905)

+ 1198621(V(119899+2)0

(119905) minus V(119899minus2)0

(119905)) V1198992(119905)

+ 1198621(V(119899+1)2

(119905) minus V(119899minus1)2

(119905)) V1198990(119905)

+ 1198621(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198992(119905)

+ 1198621(V(119899+1)1

(119905) minus V(119899minus1)1

(119905)) V1198991(119905)

+ 1198622(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198991(119905)

+ 1198621(V(119899+1)2

(119905) minus V(119899minus1)2

(119905)) V1198990(119905)

+ 1198622(V(119899+1)1

minus V(119899minus1)1

) V1198990(119899 119905)

+ 1198623(V(119899+1)0

(119899 119905) minus V(119899minus1)0

(119899 119905)) V1198990(119905)

(56)

with

V1198993(0) = 0 (57)

V1198993(119905) = 6119899119905 (119862

2+ 1198623+ 211986221(1 + 6119905)

+11986231(1 + 6119905)2 + 119862

1(1 + 2119862

2(1 + 6119905)))

(58)

Adding (49) (52) (55) and (58) we obtain

V119899(119905) = V

1198990(119905) + V

1198991(119905 1198621) + V1198992(119905 1198621 1198622)

+ V1198993(119905 1198621 1198622 1198623)

V1198993(119905) = 119899 + 6119862

1119899119905 + 6119899119905 (119862

1+ 1198622+ 11986221(1 + 6119905))

+ 6119899119905 (1198622+ 1198623+ 211986221(1 + 6119905) + 1198623

1(1 + 6119905)2

+ 11986231(1 + 6119905)2 + 119862

1(1 + 2119862

2(1 + 6119905)))

(59)

For the computation of the constants11986211198622 and119862

3applying

the method of least square mentioned in (16)ndash(18) we get

1198621= minus023640805995815892

1198622= minus0039496242739004025

1198623= minus0012135699742215487 for 119899 = 1

(60)

The exact solution of problem (42) is [9]

V119899(119905) =

119899

1 + 6119905 (61)

The HAM solution of (42) is given by [9]

V119899(119905) = (119899 + 119905) + ℎ (119899 + 1) 119905 + 3ℎ1199052 + 119905ℎ (1 + ℎ) (1 + 6119899)

+ (36ℎ2119899 + 6ℎ2 + 3ℎ) 1199052 + 18ℎ21199053(62)

2 4 6 8 1000

02

04

06

08

10

12

14

HAMExactOHAM

n

n

Figure 3 Comparisons of OHAM HAM and exact solutions at 119905 =1 ℎ = minus1

0 2 4 6 8 1000

05

10

15

20

25

ExactThird

SecondFirst

n

n

Figure 4 Comparison of first second third of OHAM HAM andexact solutions at 119905 = 1 ℎ = minus1

0 2 4 6 8 10minus7

minus6

minus5

minus4

minus3

minus2

minus1

0

Resid

ual

Residual

n

Figure 5 Residual of (42) at 119905 = 1

Abstract and Applied Analysis 7

4 Results and Discussions

The formulation presented in Section 2 provides highly accu-rate solutions for the problems demonstrated in Section 3We have used Mathematica 7 for most of our computationalwork Table 1 and Figure 1 give the comparisons of OHAMwith ADM and exact solutions for Model 1 Also the absoluteerrors at different values of 119899 at 119905 = 1 are given (Figure 4)Figure 3 shows the comparisons ofOHAMresults withHAMexact at different values of 119899 at 119905 = 1 for Model 2 Theconvergence of approximate orders to exact solutions is givenin Table 2 for Model 1 and Figure 5 for Model 2The residualshave been plotted for Model 1 in Figure 2 and for Model 2in Figure 5 We have concluded that the results obtained byOHAM are identical to the results obtained by ADM HAMand exact OHAM converges rapidly with increasing of theorder of approximation

5 Conclusion

In this work we have seen the effectiveness of OHAM[12ndash16] to differential-difference equations By applying thebasic idea of OHAM to differential-difference equations wefound it simpler in applicability more convenient to con-trol convergence and involved less computational overheadTherefore OHAM shows its validity and great potential forthe differential-difference equations arising in science andengineering

Conflict of Interests

The authors declare that there is no conflict of interestsregarding the publication of this paper

Acknowledgment

Theauthors are thankful to the anonymous reviewers for theirconstructive and valuable suggestions

References

[1] D Levi and R Yamilov ldquoConditions for the existence of highersymmetries of evolutionary equations on the latticerdquo Journal ofMathematical Physics vol 38 no 12 pp 6648ndash6674 1997

[2] R I Yamilov ldquoConstruction scheme for discreteMiura transfor-mationsrdquo Journal of Physics A Mathematical and General vol27 no 20 pp 6839ndash6851 1994

[3] I Yu Cherdantsev and R I Yamilov ldquoMaster symmetries fordifferential-difference equations of the Volterra typerdquo PhysicaD Nonlinear Phenomena vol 87 no 1ndash4 pp 140ndash144 1995

[4] A B Shabat and R I Yamilov ldquoSymmetries of nonlinearlatticesrdquo Leningrad Mathematical Journal vol 2 p 377 1991

[5] D-J Zhang ldquoSingular solutions in Casoratian form for twodifferential-difference equationsrdquo Chaos Solitons and Fractalsvol 23 no 4 pp 1333ndash1350 2005

[6] K Narita ldquoSoliton solution for a highly nonlinear difference-differential equationrdquo Chaos Solitons and Fractals vol 3 no 3pp 279ndash283 1993

[7] Z Wang and H-Q Zhang ldquoNew exact solutions to somedifference differential equationsrdquoChinese Physics vol 15 no 10pp 2210ndash2215 2006

[8] W Zhen and H Zhang ldquoA symbolic computational methodfor constructing exact solutions to difference-differential equa-tionsrdquoAppliedMathematics andComputation vol 178 no 2 pp431ndash440 2006

[9] L Zou Z Zong and G H Dong ldquoGeneralizing homotopyanalysis method to solve Lotka-Volterra equationrdquo Computersamp Mathematics with Applications vol 56 no 9 pp 2289ndash22932008

[10] Z Wang L Zou and H Zhang ldquoApplying homotopy analysismethod for solving differential-difference equationrdquo PhysicsLetters A General Atomic and Solid State Physics vol 369 no1-2 pp 77ndash84 2007

[11] Z Wang L Zou and Z Zong ldquoAdomian decomposition andPade approximate for solving differential-difference equationrdquoApplied Mathematics and Computation vol 218 no 4 pp 1371ndash1378 2011

[12] N Herisanu and VMarinca ldquoExplicit analytical approximationto large-amplitude non-linear oscillations of a uniform can-tilever beam carrying an intermediate lumped mass and rotaryinertiardquoMeccanica vol 45 no 6 pp 847ndash855 2010

[13] V Marinca and N Herisanu ldquoApplication of optimal homotopyasymptotic method for solving nonlinear equations arising inheat transferrdquo International Communications in Heat and MassTransfer vol 35 no 6 pp 710ndash715 2008

[14] V Marinca N Herisanu C Bota and B Marinca ldquoAn optimalhomotopy asymptotic method applied to the steady flow of afourth-grade fluid past a porous platerdquo Applied MathematicsLetters vol 22 no 2 pp 245ndash251 2009

[15] V Marinca N Herisanu and I Nemes ldquoA new analyticapproach to nonlinear vibration of an electrical machinerdquoProceedings of the RomanianAcademy vol 9 pp 229ndash236 2008

[16] V Marinca and N Herisanu ldquoDetermination of periodicsolutions for the motion of a particle on a rotating parabola bymeans of the optimal homotopy asymptotic methodrdquo Journal ofSound and Vibration vol 329 no 9 pp 1450ndash1459 2010

[17] M Idrees S Islam and A M Tirmizi ldquoApplication of optimalhomotopy asymptotic method of the Korteqag-de-Varies equa-tionrdquo Computers amp Mathematics with Applications vol 63 pp695ndash707 2012

[18] HUllah S IslamM Idrees andMArif ldquoSolution of boundarylayer problems with heat transfer by optimal homotopy asymp-totic methodrdquo Abstract and Applied Analysis vol 2013 ArticleID 324869 10 pages 2013

[19] R Nawaz H Ullah S Islam and M Idrees ldquoApplication ofoptimal homotopy asymptotic method to Burger equationsrdquoJournal of Applied Mathematics vol 2013 Article ID 387478 8pages 2013

[20] H Ullah S Islam M Idrees and R Nawaz ldquoApplicationof optimal homotopy asymptotic method to doubly wavesolutions of the coupled Drinfelrsquod-Sokolov-Wilson EquationsrdquoMathematical Problems in Engineering vol 2013 Article ID362816 8 pages 2013

Submit your manuscripts athttpwwwhindawicom

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

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Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Mathematical Problems in Engineering

Hindawi Publishing Corporationhttpwwwhindawicom

Differential EquationsInternational Journal of

Volume 2014

Applied MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Probability and StatisticsHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Mathematical PhysicsAdvances in

Complex AnalysisJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

OptimizationJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

CombinatoricsHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

International Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Operations ResearchAdvances in

Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Function Spaces

Abstract and Applied AnalysisHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

International Journal of Mathematics and Mathematical Sciences

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

The Scientific World JournalHindawi Publishing Corporation httpwwwhindawicom Volume 2014

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Algebra

Discrete Dynamics in Nature and Society

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Decision SciencesAdvances in

Discrete MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom

Volume 2014 Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Stochastic AnalysisInternational Journal of

Abstract and Applied Analysis 3

If 119877(119905 119862119894) = 0 then V

119899(119905 119862119894) is the exact solution of

the problem Generally it does not happen especially innonlinear problems

For the determinations of auxiliary constants 119862119894 119894 =

1 2 3 there are different methods like Galerkinrsquos methodRitz method least squares method and collocation methodOne can apply the method of least squares as follows

119869 (119862119894) = int119887

119886

intΩ

1198772 (119905 119862119894) 119889119899 119889119905 (17)

where 119886 and 119887 are two values depending on the nature of thegiven problem

The auxiliary constants 119862119894can be optimally calculated as

120597119869

1205971198621

=120597119869

1205971198622

=120597119869

1205971198623

sdot sdot sdot120597119869

120597119862119898

= 0 (18)

The119898th order approximate solution can be obtained by theseobtained constants

The convergence of OHAM is directly proportional to thenumber of optimal constants 119862

119894

3 Application of OHAM toDifference-Differential Equations

To show the validity and effectiveness of OHAM formulationto difference-differential equation we apply it to Volteraequations in different form

Model 1 We consider Voltera equation of the form

120597V119899(119905)

120597119905= V119899(119905) (V119899minus1

(119905) minus V119899+1

(119905)) 119899 ≻ 0 119905 isin [0 1]

(19)

with initial conditions

V119899(0) = 119899 (20)

The exact solution of (31) is given by

V119899(119905) =

119899

1 + 119899119905 (21)

and we take

V119899(119905) = V

1198990(119905) + 119901V

1198991(119905) + 1199012V

1198992(119905) + 1199013V

1198993(119905)

V119899+1

(119905) = V(119899+1)0

(119905) + 119901V(119899+1)1

(119905)

+ 1199012V(119899+1)2

(119905) + 1199013V(119899+1)3

(119905)

V119899minus1

(119905) = V(119899minus1)0

(119905) + 119901V(119899minus1)1

(119905)

+ 1199012V(119899minus1)2

(119905) + 1199013V(119899minus1)3

(119905)

(22)

According to (1) we have

L =120597V119899(119905)

120597119905 119891 (119905) = 0

N = minusV119899(119905) (V119899minus1

(119905) minus V119899+1

(119905))

(23)

Using (19) (20) and (22) into (5) and using the methoddiscussed in Section 2 lead to the following

Zeroth Order Problem Consider120597V1198990(119905)

120597119905= 0 (24)

with

V1198990(0) =119899 (25)

from which we obtain

V1198990(119905) =119899 (26)

First Order Problem One has120597V1198991(119905)

120597119905= (1 + 119862

1)120597V1198990(119905)

120597119905

+ 1198621(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198990(119905)

(27)

with

V1198991(0) = 0 (28)

Its solution is

V1198991(119905) = 2119862

1119899119905 (29)

Second Order Problem Consider120597V1198992(119905)

120597119905= (1 + 119862

1)120597V1198991(119905)

120597119905+ 1198622

120597V1198990(119905)

120597119905

+ 1198621(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198991(119905)

+ 1198621(V(119899+1)1

(119905) minus V(119899minus1)1

(119905)) V1198990(119905)

+ 1198622(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198990(119905)

(30)

with

V1198992(0) = 0 (31)

V1198992(119905) = 2 (119862

1119899119905 + 1198622

1119899119905 + 119862

2119899119905 + 21198622

11198991199052) (32)

Third Order Problem One has120597V1198993(119905)

120597119905= (1 + 119862

1)120597V1198992(119905)

120597119905+ 1198622

120597V1198991(119905)

120597119905+ 1198623

120597V1198990(119905)

120597119905

+ 1198621(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198992(119905)

+ 1198621(V(119899+1)1

(119905) minus V(119899minus1)1

(119905)) V1198991(119905)

+ 1198622(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198991(119905)

+ 1198621(V(119899+1)2

(119905) minus V(119899minus1)2

(119905)) V1198990

+ 1198622(V(119899+1)1

(119905) minus V(119899minus1)1

(119905)) V1198990(119905)

+ 1198623(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198990(119905)

(33)

4 Abstract and Applied Analysis

Table 1 Comparisons of OHAM exact and ADM results atdifferent values of 119899 at 119905 = 1

119899 OHAM Exact ADM Abs error1 0333333 0333333 0333333 717103 times 10minus7

2 0666665 0666665 0666665 143421 times 10minus6

3 0999998 0999998 0999998 215131 times 10minus6

4 133333 133333 133333 286841 times 10minus6

5 166666 166666 166666 358551 times 10minus6

6 2 2 2 430262 times 10minus6

7 233333 233333 233333 501972 times 10minus6

8 266666 266666 266666 573682 times 10minus6

9 299999 299999 299999 645392 times 10minus6

10 333333 333333 333333 717103 times 10minus6

Table 2 Comparisons of first second and third order and exactsolutions at different values of 119899 at 119905 = 1

119899 First order Second order Third order Exact sol1 0527142 0858619 0333333 03333332 105428 171724 0666665 06666653 158143 257586 0999998 09999984 210857 343447 133333 1333335 263571 429309 166666 1666666 316285 515171 2 27 368999 601033 233333 2333338 421713 686895 266666 2666669 474428 772757 299999 29999910 527142 858619 333333 333333

with

V1198993(0) = 0 (34)

V1198993(119905) =

2

3(31198621119899119905 + 61198622

1119899119905 + 31198623

1119899119905 + 3119862

2119899119905 + 3119862

3119899119905

+12119862211198991199052 + 121198623

11198991199052 + 6119862

111986221198991199052 + 41198623

11198991199053)

(35)

Adding (26) (29) (32) and (35) we obtain

V119899(119905) = V

1198990(119905) + V

1198991(119905 1198621) + V1198992(119905 1198621 1198622)

+ V1198993(119905 1198621 1198622 1198623)

(36)

V119899(119905) = 119899 + 2119862

1119899119905 + 2 (119862

1119899119905 + 1198622

1119899119905 + 119862

2119899119905 + 21198622

11198991199052)

+2

3(31198621119899119905 + 61198622

1119899119905 + 31198623

1119899119905 + 3119862

2119899119905 + 3119862

3119899119905

+12119862211198991199052 + 121198623

11198991199052 + 6119862

111986221198991199052 + 41198623

11198991199053) (37)

For the computation of the constants1198621 1198622 and119862

3applying

the method of least square mentioned in (16)ndash(18) we get

1198621= minus023642908394894221

1198622= 02344713680405294

1198623= minus04015040325725273 for 119899 = 1

(38)

2 4 6 8 1000

05

10

15

20

25

30

ADMExactOHAM

n

n

Figure 1 Comparison ofOHAM exact andADMsolutions at 119905 = 1

2 4 6 8 10minus6

minus5

minus4

minus3

minus2

minus1

0Re

sidual

Residual

n

Figure 2 Residual of (19) at 119905 = 1

Putting these values in (37) we obtained the approximatesolution of the form

V119899(119905) = 119899 minus 0472858119899119905 + 2 (005119899119905 + 01117971198991199052)

+2

3(minus0914641119899119905 + 01795761198991199052 minus 005286431198991199053)

(39)

The exact solution of the problem (31) is [11]

V119899(119905) =

119899

1 + 119899119905 (40)

The Adomian solution with Pade approximation of (31) isgiven by [11]

V119899(119905) =

119899

1 + 119899119905 (41)

Abstract and Applied Analysis 5

Model 2 Now consider another form of Volterra equation

120597V119899(119905)

120597119905= V119899(119905) (V119899minus1

(119905) minus V119899+1

(119905))

+ V119899(119905) (V119899minus2

(119905) minus V119899+2

(119905)) 119899 ≻ 0 119905 isin [0 1] (42)

with initial conditions

V119899(0) = 119899 (43)

The exact solution of (42) is given by

V119899(119905) =

119899

1 + 6119905 (44)

We take

V119899(119905) = V

1198990(119905) + 119901V

1198991(119905) + 1199012V

1198992(119905)

+ 1199013V1198993(119905)

V119899+1

(119905) = V(119899+1)0

(119905) + 119901V(119899+1)1

(119905)

+ 1199012V(119899+1)2

(119905) + 1199013V(119899+1)3

(119905)

V119899minus1

(119905) = V(119899minus1)0

(119905) + 119901V(119899minus1)1

(119905)

+ 1199012V(119899minus1)2

(119905) + 1199013V(119899minus1)3

(119905)

V119899+2

(119905) = V(119899+2)0

(119905) + 119901V(119899+2)1

(119905)

+ 1199012V(119899+2)2

(119905) + 1199013V(119899+2)3

(119905)

V119899minus2

(119905) = V(119899minus2)0

(119905) + 119901V(119899minus2)1

(119905)

+ 1199012V(119899minus2)2

(119905) + 1199013V(119899minus2)3

(119905)

(45)

According to (1) we have

L =120597V119899(119905)

120597119905 119891 (119905) = 0

N = minusV119899(119905) (V119899minus1

(119905) minus V119899+1

(119905))

minus V119899(119905) (V119899minus2

(119905) minus V119899+2

(119905))

(46)

Using (42) (43) and (45) into (5) and using the methoddiscussed in Section 2 lead to the following

Zeroth Order Problem Consider

120597V1198990(119905)

120597119905= 0 (47)

with

V1198990(0) = 119899 (48)

from which we obtain

V1198990(119905) = 119899 (49)

First Order Problem One has the following

120597V1198991(119905)

120597119905= (1 + 119862

1)120597V1198990(119905)

120597119905

+ 1198621(V(119899+2)0

(119905) minus 1198621V(119899minus2)0

(119905)) V1198990(119905)

+ 1198621(V(119899+1)0

(119905) minus 1198621V(119899minus1)0

(119905)) V1198990(119905)

(50)

with

V1198991(0) = 0 (51)

Its solution is

V1198991(119905) = 6119862

1119899119905 (52)

Second Order Problem Consider

120597V1198992(119905)

120597119905= (1 + 119862

1)120597V1198991(119905)

120597119905+ 1198622

120597V1198990(119905)

120597119905

+ 1198621(V(119899+2)1

(119905) minus V(119899minus2)1

(119905)) V1198990(119905)

+ 1198622(V(119899+2)0

(119905) minus V(119899minus2)0

(119905)) V1198990

+ 1198621(V(119899+2)0

(119905) minus V(119899minus2)0

(119905)) V1198991(119905)

+ 1198621(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198991(119905)

+ 1198622(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198990(119905)

+ 1198621(V(119899+1)1

(119905) minus V(119899minus1)1

(119905)) V1198990(119905)

(53)

with

V1198992(0) = 0 (54)

V1198992(119905) = 6119899119905 (119862

1+ 1198622+ 11986221(1 + 6119905)) (55)

Third Order Problem One has

120597V1198993(119905)

120597119905= (1 + 119862

1)120597V1198992(119905)

120597119905+ 1198622

120597V1198991(119905)

120597119905+ 1198623

120597V1198990(119905)

120597119905

+ 1198621(V(119899+2)2

(119905) minus V(119899minus2)2

(119905)) V1198990(119905)

+ 1198622(V(119899+2)1

(119905) minus V(119899minus2)1

(119905)) V1198990(119905)

+ 1198623(V(119899+2)0

(119905) minus V(119899minus2)0

(119905)) V1198990(119905)

+ 1198621(V(119899+2)1

(119905) minus V(119899minus2)1

(119905)) V1198991(119905)

6 Abstract and Applied Analysis

+ 1198622(V(119899+2)0

(119905) minus V(119899minus2)0

(119905)) V1198991(119905)

+ 1198621(V(119899+2)0

(119905) minus V(119899minus2)0

(119905)) V1198992(119905)

+ 1198621(V(119899+1)2

(119905) minus V(119899minus1)2

(119905)) V1198990(119905)

+ 1198621(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198992(119905)

+ 1198621(V(119899+1)1

(119905) minus V(119899minus1)1

(119905)) V1198991(119905)

+ 1198622(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198991(119905)

+ 1198621(V(119899+1)2

(119905) minus V(119899minus1)2

(119905)) V1198990(119905)

+ 1198622(V(119899+1)1

minus V(119899minus1)1

) V1198990(119899 119905)

+ 1198623(V(119899+1)0

(119899 119905) minus V(119899minus1)0

(119899 119905)) V1198990(119905)

(56)

with

V1198993(0) = 0 (57)

V1198993(119905) = 6119899119905 (119862

2+ 1198623+ 211986221(1 + 6119905)

+11986231(1 + 6119905)2 + 119862

1(1 + 2119862

2(1 + 6119905)))

(58)

Adding (49) (52) (55) and (58) we obtain

V119899(119905) = V

1198990(119905) + V

1198991(119905 1198621) + V1198992(119905 1198621 1198622)

+ V1198993(119905 1198621 1198622 1198623)

V1198993(119905) = 119899 + 6119862

1119899119905 + 6119899119905 (119862

1+ 1198622+ 11986221(1 + 6119905))

+ 6119899119905 (1198622+ 1198623+ 211986221(1 + 6119905) + 1198623

1(1 + 6119905)2

+ 11986231(1 + 6119905)2 + 119862

1(1 + 2119862

2(1 + 6119905)))

(59)

For the computation of the constants11986211198622 and119862

3applying

the method of least square mentioned in (16)ndash(18) we get

1198621= minus023640805995815892

1198622= minus0039496242739004025

1198623= minus0012135699742215487 for 119899 = 1

(60)

The exact solution of problem (42) is [9]

V119899(119905) =

119899

1 + 6119905 (61)

The HAM solution of (42) is given by [9]

V119899(119905) = (119899 + 119905) + ℎ (119899 + 1) 119905 + 3ℎ1199052 + 119905ℎ (1 + ℎ) (1 + 6119899)

+ (36ℎ2119899 + 6ℎ2 + 3ℎ) 1199052 + 18ℎ21199053(62)

2 4 6 8 1000

02

04

06

08

10

12

14

HAMExactOHAM

n

n

Figure 3 Comparisons of OHAM HAM and exact solutions at 119905 =1 ℎ = minus1

0 2 4 6 8 1000

05

10

15

20

25

ExactThird

SecondFirst

n

n

Figure 4 Comparison of first second third of OHAM HAM andexact solutions at 119905 = 1 ℎ = minus1

0 2 4 6 8 10minus7

minus6

minus5

minus4

minus3

minus2

minus1

0

Resid

ual

Residual

n

Figure 5 Residual of (42) at 119905 = 1

Abstract and Applied Analysis 7

4 Results and Discussions

The formulation presented in Section 2 provides highly accu-rate solutions for the problems demonstrated in Section 3We have used Mathematica 7 for most of our computationalwork Table 1 and Figure 1 give the comparisons of OHAMwith ADM and exact solutions for Model 1 Also the absoluteerrors at different values of 119899 at 119905 = 1 are given (Figure 4)Figure 3 shows the comparisons ofOHAMresults withHAMexact at different values of 119899 at 119905 = 1 for Model 2 Theconvergence of approximate orders to exact solutions is givenin Table 2 for Model 1 and Figure 5 for Model 2The residualshave been plotted for Model 1 in Figure 2 and for Model 2in Figure 5 We have concluded that the results obtained byOHAM are identical to the results obtained by ADM HAMand exact OHAM converges rapidly with increasing of theorder of approximation

5 Conclusion

In this work we have seen the effectiveness of OHAM[12ndash16] to differential-difference equations By applying thebasic idea of OHAM to differential-difference equations wefound it simpler in applicability more convenient to con-trol convergence and involved less computational overheadTherefore OHAM shows its validity and great potential forthe differential-difference equations arising in science andengineering

Conflict of Interests

The authors declare that there is no conflict of interestsregarding the publication of this paper

Acknowledgment

Theauthors are thankful to the anonymous reviewers for theirconstructive and valuable suggestions

References

[1] D Levi and R Yamilov ldquoConditions for the existence of highersymmetries of evolutionary equations on the latticerdquo Journal ofMathematical Physics vol 38 no 12 pp 6648ndash6674 1997

[2] R I Yamilov ldquoConstruction scheme for discreteMiura transfor-mationsrdquo Journal of Physics A Mathematical and General vol27 no 20 pp 6839ndash6851 1994

[3] I Yu Cherdantsev and R I Yamilov ldquoMaster symmetries fordifferential-difference equations of the Volterra typerdquo PhysicaD Nonlinear Phenomena vol 87 no 1ndash4 pp 140ndash144 1995

[4] A B Shabat and R I Yamilov ldquoSymmetries of nonlinearlatticesrdquo Leningrad Mathematical Journal vol 2 p 377 1991

[5] D-J Zhang ldquoSingular solutions in Casoratian form for twodifferential-difference equationsrdquo Chaos Solitons and Fractalsvol 23 no 4 pp 1333ndash1350 2005

[6] K Narita ldquoSoliton solution for a highly nonlinear difference-differential equationrdquo Chaos Solitons and Fractals vol 3 no 3pp 279ndash283 1993

[7] Z Wang and H-Q Zhang ldquoNew exact solutions to somedifference differential equationsrdquoChinese Physics vol 15 no 10pp 2210ndash2215 2006

[8] W Zhen and H Zhang ldquoA symbolic computational methodfor constructing exact solutions to difference-differential equa-tionsrdquoAppliedMathematics andComputation vol 178 no 2 pp431ndash440 2006

[9] L Zou Z Zong and G H Dong ldquoGeneralizing homotopyanalysis method to solve Lotka-Volterra equationrdquo Computersamp Mathematics with Applications vol 56 no 9 pp 2289ndash22932008

[10] Z Wang L Zou and H Zhang ldquoApplying homotopy analysismethod for solving differential-difference equationrdquo PhysicsLetters A General Atomic and Solid State Physics vol 369 no1-2 pp 77ndash84 2007

[11] Z Wang L Zou and Z Zong ldquoAdomian decomposition andPade approximate for solving differential-difference equationrdquoApplied Mathematics and Computation vol 218 no 4 pp 1371ndash1378 2011

[12] N Herisanu and VMarinca ldquoExplicit analytical approximationto large-amplitude non-linear oscillations of a uniform can-tilever beam carrying an intermediate lumped mass and rotaryinertiardquoMeccanica vol 45 no 6 pp 847ndash855 2010

[13] V Marinca and N Herisanu ldquoApplication of optimal homotopyasymptotic method for solving nonlinear equations arising inheat transferrdquo International Communications in Heat and MassTransfer vol 35 no 6 pp 710ndash715 2008

[14] V Marinca N Herisanu C Bota and B Marinca ldquoAn optimalhomotopy asymptotic method applied to the steady flow of afourth-grade fluid past a porous platerdquo Applied MathematicsLetters vol 22 no 2 pp 245ndash251 2009

[15] V Marinca N Herisanu and I Nemes ldquoA new analyticapproach to nonlinear vibration of an electrical machinerdquoProceedings of the RomanianAcademy vol 9 pp 229ndash236 2008

[16] V Marinca and N Herisanu ldquoDetermination of periodicsolutions for the motion of a particle on a rotating parabola bymeans of the optimal homotopy asymptotic methodrdquo Journal ofSound and Vibration vol 329 no 9 pp 1450ndash1459 2010

[17] M Idrees S Islam and A M Tirmizi ldquoApplication of optimalhomotopy asymptotic method of the Korteqag-de-Varies equa-tionrdquo Computers amp Mathematics with Applications vol 63 pp695ndash707 2012

[18] HUllah S IslamM Idrees andMArif ldquoSolution of boundarylayer problems with heat transfer by optimal homotopy asymp-totic methodrdquo Abstract and Applied Analysis vol 2013 ArticleID 324869 10 pages 2013

[19] R Nawaz H Ullah S Islam and M Idrees ldquoApplication ofoptimal homotopy asymptotic method to Burger equationsrdquoJournal of Applied Mathematics vol 2013 Article ID 387478 8pages 2013

[20] H Ullah S Islam M Idrees and R Nawaz ldquoApplicationof optimal homotopy asymptotic method to doubly wavesolutions of the coupled Drinfelrsquod-Sokolov-Wilson EquationsrdquoMathematical Problems in Engineering vol 2013 Article ID362816 8 pages 2013

Submit your manuscripts athttpwwwhindawicom

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

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Mathematical Problems in Engineering

Hindawi Publishing Corporationhttpwwwhindawicom

Differential EquationsInternational Journal of

Volume 2014

Applied MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Probability and StatisticsHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Mathematical PhysicsAdvances in

Complex AnalysisJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

OptimizationJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

CombinatoricsHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

International Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Operations ResearchAdvances in

Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Function Spaces

Abstract and Applied AnalysisHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

International Journal of Mathematics and Mathematical Sciences

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

The Scientific World JournalHindawi Publishing Corporation httpwwwhindawicom Volume 2014

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Algebra

Discrete Dynamics in Nature and Society

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Decision SciencesAdvances in

Discrete MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom

Volume 2014 Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Stochastic AnalysisInternational Journal of

4 Abstract and Applied Analysis

Table 1 Comparisons of OHAM exact and ADM results atdifferent values of 119899 at 119905 = 1

119899 OHAM Exact ADM Abs error1 0333333 0333333 0333333 717103 times 10minus7

2 0666665 0666665 0666665 143421 times 10minus6

3 0999998 0999998 0999998 215131 times 10minus6

4 133333 133333 133333 286841 times 10minus6

5 166666 166666 166666 358551 times 10minus6

6 2 2 2 430262 times 10minus6

7 233333 233333 233333 501972 times 10minus6

8 266666 266666 266666 573682 times 10minus6

9 299999 299999 299999 645392 times 10minus6

10 333333 333333 333333 717103 times 10minus6

Table 2 Comparisons of first second and third order and exactsolutions at different values of 119899 at 119905 = 1

119899 First order Second order Third order Exact sol1 0527142 0858619 0333333 03333332 105428 171724 0666665 06666653 158143 257586 0999998 09999984 210857 343447 133333 1333335 263571 429309 166666 1666666 316285 515171 2 27 368999 601033 233333 2333338 421713 686895 266666 2666669 474428 772757 299999 29999910 527142 858619 333333 333333

with

V1198993(0) = 0 (34)

V1198993(119905) =

2

3(31198621119899119905 + 61198622

1119899119905 + 31198623

1119899119905 + 3119862

2119899119905 + 3119862

3119899119905

+12119862211198991199052 + 121198623

11198991199052 + 6119862

111986221198991199052 + 41198623

11198991199053)

(35)

Adding (26) (29) (32) and (35) we obtain

V119899(119905) = V

1198990(119905) + V

1198991(119905 1198621) + V1198992(119905 1198621 1198622)

+ V1198993(119905 1198621 1198622 1198623)

(36)

V119899(119905) = 119899 + 2119862

1119899119905 + 2 (119862

1119899119905 + 1198622

1119899119905 + 119862

2119899119905 + 21198622

11198991199052)

+2

3(31198621119899119905 + 61198622

1119899119905 + 31198623

1119899119905 + 3119862

2119899119905 + 3119862

3119899119905

+12119862211198991199052 + 121198623

11198991199052 + 6119862

111986221198991199052 + 41198623

11198991199053) (37)

For the computation of the constants1198621 1198622 and119862

3applying

the method of least square mentioned in (16)ndash(18) we get

1198621= minus023642908394894221

1198622= 02344713680405294

1198623= minus04015040325725273 for 119899 = 1

(38)

2 4 6 8 1000

05

10

15

20

25

30

ADMExactOHAM

n

n

Figure 1 Comparison ofOHAM exact andADMsolutions at 119905 = 1

2 4 6 8 10minus6

minus5

minus4

minus3

minus2

minus1

0Re

sidual

Residual

n

Figure 2 Residual of (19) at 119905 = 1

Putting these values in (37) we obtained the approximatesolution of the form

V119899(119905) = 119899 minus 0472858119899119905 + 2 (005119899119905 + 01117971198991199052)

+2

3(minus0914641119899119905 + 01795761198991199052 minus 005286431198991199053)

(39)

The exact solution of the problem (31) is [11]

V119899(119905) =

119899

1 + 119899119905 (40)

The Adomian solution with Pade approximation of (31) isgiven by [11]

V119899(119905) =

119899

1 + 119899119905 (41)

Abstract and Applied Analysis 5

Model 2 Now consider another form of Volterra equation

120597V119899(119905)

120597119905= V119899(119905) (V119899minus1

(119905) minus V119899+1

(119905))

+ V119899(119905) (V119899minus2

(119905) minus V119899+2

(119905)) 119899 ≻ 0 119905 isin [0 1] (42)

with initial conditions

V119899(0) = 119899 (43)

The exact solution of (42) is given by

V119899(119905) =

119899

1 + 6119905 (44)

We take

V119899(119905) = V

1198990(119905) + 119901V

1198991(119905) + 1199012V

1198992(119905)

+ 1199013V1198993(119905)

V119899+1

(119905) = V(119899+1)0

(119905) + 119901V(119899+1)1

(119905)

+ 1199012V(119899+1)2

(119905) + 1199013V(119899+1)3

(119905)

V119899minus1

(119905) = V(119899minus1)0

(119905) + 119901V(119899minus1)1

(119905)

+ 1199012V(119899minus1)2

(119905) + 1199013V(119899minus1)3

(119905)

V119899+2

(119905) = V(119899+2)0

(119905) + 119901V(119899+2)1

(119905)

+ 1199012V(119899+2)2

(119905) + 1199013V(119899+2)3

(119905)

V119899minus2

(119905) = V(119899minus2)0

(119905) + 119901V(119899minus2)1

(119905)

+ 1199012V(119899minus2)2

(119905) + 1199013V(119899minus2)3

(119905)

(45)

According to (1) we have

L =120597V119899(119905)

120597119905 119891 (119905) = 0

N = minusV119899(119905) (V119899minus1

(119905) minus V119899+1

(119905))

minus V119899(119905) (V119899minus2

(119905) minus V119899+2

(119905))

(46)

Using (42) (43) and (45) into (5) and using the methoddiscussed in Section 2 lead to the following

Zeroth Order Problem Consider

120597V1198990(119905)

120597119905= 0 (47)

with

V1198990(0) = 119899 (48)

from which we obtain

V1198990(119905) = 119899 (49)

First Order Problem One has the following

120597V1198991(119905)

120597119905= (1 + 119862

1)120597V1198990(119905)

120597119905

+ 1198621(V(119899+2)0

(119905) minus 1198621V(119899minus2)0

(119905)) V1198990(119905)

+ 1198621(V(119899+1)0

(119905) minus 1198621V(119899minus1)0

(119905)) V1198990(119905)

(50)

with

V1198991(0) = 0 (51)

Its solution is

V1198991(119905) = 6119862

1119899119905 (52)

Second Order Problem Consider

120597V1198992(119905)

120597119905= (1 + 119862

1)120597V1198991(119905)

120597119905+ 1198622

120597V1198990(119905)

120597119905

+ 1198621(V(119899+2)1

(119905) minus V(119899minus2)1

(119905)) V1198990(119905)

+ 1198622(V(119899+2)0

(119905) minus V(119899minus2)0

(119905)) V1198990

+ 1198621(V(119899+2)0

(119905) minus V(119899minus2)0

(119905)) V1198991(119905)

+ 1198621(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198991(119905)

+ 1198622(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198990(119905)

+ 1198621(V(119899+1)1

(119905) minus V(119899minus1)1

(119905)) V1198990(119905)

(53)

with

V1198992(0) = 0 (54)

V1198992(119905) = 6119899119905 (119862

1+ 1198622+ 11986221(1 + 6119905)) (55)

Third Order Problem One has

120597V1198993(119905)

120597119905= (1 + 119862

1)120597V1198992(119905)

120597119905+ 1198622

120597V1198991(119905)

120597119905+ 1198623

120597V1198990(119905)

120597119905

+ 1198621(V(119899+2)2

(119905) minus V(119899minus2)2

(119905)) V1198990(119905)

+ 1198622(V(119899+2)1

(119905) minus V(119899minus2)1

(119905)) V1198990(119905)

+ 1198623(V(119899+2)0

(119905) minus V(119899minus2)0

(119905)) V1198990(119905)

+ 1198621(V(119899+2)1

(119905) minus V(119899minus2)1

(119905)) V1198991(119905)

6 Abstract and Applied Analysis

+ 1198622(V(119899+2)0

(119905) minus V(119899minus2)0

(119905)) V1198991(119905)

+ 1198621(V(119899+2)0

(119905) minus V(119899minus2)0

(119905)) V1198992(119905)

+ 1198621(V(119899+1)2

(119905) minus V(119899minus1)2

(119905)) V1198990(119905)

+ 1198621(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198992(119905)

+ 1198621(V(119899+1)1

(119905) minus V(119899minus1)1

(119905)) V1198991(119905)

+ 1198622(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198991(119905)

+ 1198621(V(119899+1)2

(119905) minus V(119899minus1)2

(119905)) V1198990(119905)

+ 1198622(V(119899+1)1

minus V(119899minus1)1

) V1198990(119899 119905)

+ 1198623(V(119899+1)0

(119899 119905) minus V(119899minus1)0

(119899 119905)) V1198990(119905)

(56)

with

V1198993(0) = 0 (57)

V1198993(119905) = 6119899119905 (119862

2+ 1198623+ 211986221(1 + 6119905)

+11986231(1 + 6119905)2 + 119862

1(1 + 2119862

2(1 + 6119905)))

(58)

Adding (49) (52) (55) and (58) we obtain

V119899(119905) = V

1198990(119905) + V

1198991(119905 1198621) + V1198992(119905 1198621 1198622)

+ V1198993(119905 1198621 1198622 1198623)

V1198993(119905) = 119899 + 6119862

1119899119905 + 6119899119905 (119862

1+ 1198622+ 11986221(1 + 6119905))

+ 6119899119905 (1198622+ 1198623+ 211986221(1 + 6119905) + 1198623

1(1 + 6119905)2

+ 11986231(1 + 6119905)2 + 119862

1(1 + 2119862

2(1 + 6119905)))

(59)

For the computation of the constants11986211198622 and119862

3applying

the method of least square mentioned in (16)ndash(18) we get

1198621= minus023640805995815892

1198622= minus0039496242739004025

1198623= minus0012135699742215487 for 119899 = 1

(60)

The exact solution of problem (42) is [9]

V119899(119905) =

119899

1 + 6119905 (61)

The HAM solution of (42) is given by [9]

V119899(119905) = (119899 + 119905) + ℎ (119899 + 1) 119905 + 3ℎ1199052 + 119905ℎ (1 + ℎ) (1 + 6119899)

+ (36ℎ2119899 + 6ℎ2 + 3ℎ) 1199052 + 18ℎ21199053(62)

2 4 6 8 1000

02

04

06

08

10

12

14

HAMExactOHAM

n

n

Figure 3 Comparisons of OHAM HAM and exact solutions at 119905 =1 ℎ = minus1

0 2 4 6 8 1000

05

10

15

20

25

ExactThird

SecondFirst

n

n

Figure 4 Comparison of first second third of OHAM HAM andexact solutions at 119905 = 1 ℎ = minus1

0 2 4 6 8 10minus7

minus6

minus5

minus4

minus3

minus2

minus1

0

Resid

ual

Residual

n

Figure 5 Residual of (42) at 119905 = 1

Abstract and Applied Analysis 7

4 Results and Discussions

The formulation presented in Section 2 provides highly accu-rate solutions for the problems demonstrated in Section 3We have used Mathematica 7 for most of our computationalwork Table 1 and Figure 1 give the comparisons of OHAMwith ADM and exact solutions for Model 1 Also the absoluteerrors at different values of 119899 at 119905 = 1 are given (Figure 4)Figure 3 shows the comparisons ofOHAMresults withHAMexact at different values of 119899 at 119905 = 1 for Model 2 Theconvergence of approximate orders to exact solutions is givenin Table 2 for Model 1 and Figure 5 for Model 2The residualshave been plotted for Model 1 in Figure 2 and for Model 2in Figure 5 We have concluded that the results obtained byOHAM are identical to the results obtained by ADM HAMand exact OHAM converges rapidly with increasing of theorder of approximation

5 Conclusion

In this work we have seen the effectiveness of OHAM[12ndash16] to differential-difference equations By applying thebasic idea of OHAM to differential-difference equations wefound it simpler in applicability more convenient to con-trol convergence and involved less computational overheadTherefore OHAM shows its validity and great potential forthe differential-difference equations arising in science andengineering

Conflict of Interests

The authors declare that there is no conflict of interestsregarding the publication of this paper

Acknowledgment

Theauthors are thankful to the anonymous reviewers for theirconstructive and valuable suggestions

References

[1] D Levi and R Yamilov ldquoConditions for the existence of highersymmetries of evolutionary equations on the latticerdquo Journal ofMathematical Physics vol 38 no 12 pp 6648ndash6674 1997

[2] R I Yamilov ldquoConstruction scheme for discreteMiura transfor-mationsrdquo Journal of Physics A Mathematical and General vol27 no 20 pp 6839ndash6851 1994

[3] I Yu Cherdantsev and R I Yamilov ldquoMaster symmetries fordifferential-difference equations of the Volterra typerdquo PhysicaD Nonlinear Phenomena vol 87 no 1ndash4 pp 140ndash144 1995

[4] A B Shabat and R I Yamilov ldquoSymmetries of nonlinearlatticesrdquo Leningrad Mathematical Journal vol 2 p 377 1991

[5] D-J Zhang ldquoSingular solutions in Casoratian form for twodifferential-difference equationsrdquo Chaos Solitons and Fractalsvol 23 no 4 pp 1333ndash1350 2005

[6] K Narita ldquoSoliton solution for a highly nonlinear difference-differential equationrdquo Chaos Solitons and Fractals vol 3 no 3pp 279ndash283 1993

[7] Z Wang and H-Q Zhang ldquoNew exact solutions to somedifference differential equationsrdquoChinese Physics vol 15 no 10pp 2210ndash2215 2006

[8] W Zhen and H Zhang ldquoA symbolic computational methodfor constructing exact solutions to difference-differential equa-tionsrdquoAppliedMathematics andComputation vol 178 no 2 pp431ndash440 2006

[9] L Zou Z Zong and G H Dong ldquoGeneralizing homotopyanalysis method to solve Lotka-Volterra equationrdquo Computersamp Mathematics with Applications vol 56 no 9 pp 2289ndash22932008

[10] Z Wang L Zou and H Zhang ldquoApplying homotopy analysismethod for solving differential-difference equationrdquo PhysicsLetters A General Atomic and Solid State Physics vol 369 no1-2 pp 77ndash84 2007

[11] Z Wang L Zou and Z Zong ldquoAdomian decomposition andPade approximate for solving differential-difference equationrdquoApplied Mathematics and Computation vol 218 no 4 pp 1371ndash1378 2011

[12] N Herisanu and VMarinca ldquoExplicit analytical approximationto large-amplitude non-linear oscillations of a uniform can-tilever beam carrying an intermediate lumped mass and rotaryinertiardquoMeccanica vol 45 no 6 pp 847ndash855 2010

[13] V Marinca and N Herisanu ldquoApplication of optimal homotopyasymptotic method for solving nonlinear equations arising inheat transferrdquo International Communications in Heat and MassTransfer vol 35 no 6 pp 710ndash715 2008

[14] V Marinca N Herisanu C Bota and B Marinca ldquoAn optimalhomotopy asymptotic method applied to the steady flow of afourth-grade fluid past a porous platerdquo Applied MathematicsLetters vol 22 no 2 pp 245ndash251 2009

[15] V Marinca N Herisanu and I Nemes ldquoA new analyticapproach to nonlinear vibration of an electrical machinerdquoProceedings of the RomanianAcademy vol 9 pp 229ndash236 2008

[16] V Marinca and N Herisanu ldquoDetermination of periodicsolutions for the motion of a particle on a rotating parabola bymeans of the optimal homotopy asymptotic methodrdquo Journal ofSound and Vibration vol 329 no 9 pp 1450ndash1459 2010

[17] M Idrees S Islam and A M Tirmizi ldquoApplication of optimalhomotopy asymptotic method of the Korteqag-de-Varies equa-tionrdquo Computers amp Mathematics with Applications vol 63 pp695ndash707 2012

[18] HUllah S IslamM Idrees andMArif ldquoSolution of boundarylayer problems with heat transfer by optimal homotopy asymp-totic methodrdquo Abstract and Applied Analysis vol 2013 ArticleID 324869 10 pages 2013

[19] R Nawaz H Ullah S Islam and M Idrees ldquoApplication ofoptimal homotopy asymptotic method to Burger equationsrdquoJournal of Applied Mathematics vol 2013 Article ID 387478 8pages 2013

[20] H Ullah S Islam M Idrees and R Nawaz ldquoApplicationof optimal homotopy asymptotic method to doubly wavesolutions of the coupled Drinfelrsquod-Sokolov-Wilson EquationsrdquoMathematical Problems in Engineering vol 2013 Article ID362816 8 pages 2013

Submit your manuscripts athttpwwwhindawicom

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Mathematical Problems in Engineering

Hindawi Publishing Corporationhttpwwwhindawicom

Differential EquationsInternational Journal of

Volume 2014

Applied MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Probability and StatisticsHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Mathematical PhysicsAdvances in

Complex AnalysisJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

OptimizationJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

CombinatoricsHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

International Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Operations ResearchAdvances in

Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Function Spaces

Abstract and Applied AnalysisHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

International Journal of Mathematics and Mathematical Sciences

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

The Scientific World JournalHindawi Publishing Corporation httpwwwhindawicom Volume 2014

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Algebra

Discrete Dynamics in Nature and Society

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Decision SciencesAdvances in

Discrete MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom

Volume 2014 Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Stochastic AnalysisInternational Journal of

Abstract and Applied Analysis 5

Model 2 Now consider another form of Volterra equation

120597V119899(119905)

120597119905= V119899(119905) (V119899minus1

(119905) minus V119899+1

(119905))

+ V119899(119905) (V119899minus2

(119905) minus V119899+2

(119905)) 119899 ≻ 0 119905 isin [0 1] (42)

with initial conditions

V119899(0) = 119899 (43)

The exact solution of (42) is given by

V119899(119905) =

119899

1 + 6119905 (44)

We take

V119899(119905) = V

1198990(119905) + 119901V

1198991(119905) + 1199012V

1198992(119905)

+ 1199013V1198993(119905)

V119899+1

(119905) = V(119899+1)0

(119905) + 119901V(119899+1)1

(119905)

+ 1199012V(119899+1)2

(119905) + 1199013V(119899+1)3

(119905)

V119899minus1

(119905) = V(119899minus1)0

(119905) + 119901V(119899minus1)1

(119905)

+ 1199012V(119899minus1)2

(119905) + 1199013V(119899minus1)3

(119905)

V119899+2

(119905) = V(119899+2)0

(119905) + 119901V(119899+2)1

(119905)

+ 1199012V(119899+2)2

(119905) + 1199013V(119899+2)3

(119905)

V119899minus2

(119905) = V(119899minus2)0

(119905) + 119901V(119899minus2)1

(119905)

+ 1199012V(119899minus2)2

(119905) + 1199013V(119899minus2)3

(119905)

(45)

According to (1) we have

L =120597V119899(119905)

120597119905 119891 (119905) = 0

N = minusV119899(119905) (V119899minus1

(119905) minus V119899+1

(119905))

minus V119899(119905) (V119899minus2

(119905) minus V119899+2

(119905))

(46)

Using (42) (43) and (45) into (5) and using the methoddiscussed in Section 2 lead to the following

Zeroth Order Problem Consider

120597V1198990(119905)

120597119905= 0 (47)

with

V1198990(0) = 119899 (48)

from which we obtain

V1198990(119905) = 119899 (49)

First Order Problem One has the following

120597V1198991(119905)

120597119905= (1 + 119862

1)120597V1198990(119905)

120597119905

+ 1198621(V(119899+2)0

(119905) minus 1198621V(119899minus2)0

(119905)) V1198990(119905)

+ 1198621(V(119899+1)0

(119905) minus 1198621V(119899minus1)0

(119905)) V1198990(119905)

(50)

with

V1198991(0) = 0 (51)

Its solution is

V1198991(119905) = 6119862

1119899119905 (52)

Second Order Problem Consider

120597V1198992(119905)

120597119905= (1 + 119862

1)120597V1198991(119905)

120597119905+ 1198622

120597V1198990(119905)

120597119905

+ 1198621(V(119899+2)1

(119905) minus V(119899minus2)1

(119905)) V1198990(119905)

+ 1198622(V(119899+2)0

(119905) minus V(119899minus2)0

(119905)) V1198990

+ 1198621(V(119899+2)0

(119905) minus V(119899minus2)0

(119905)) V1198991(119905)

+ 1198621(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198991(119905)

+ 1198622(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198990(119905)

+ 1198621(V(119899+1)1

(119905) minus V(119899minus1)1

(119905)) V1198990(119905)

(53)

with

V1198992(0) = 0 (54)

V1198992(119905) = 6119899119905 (119862

1+ 1198622+ 11986221(1 + 6119905)) (55)

Third Order Problem One has

120597V1198993(119905)

120597119905= (1 + 119862

1)120597V1198992(119905)

120597119905+ 1198622

120597V1198991(119905)

120597119905+ 1198623

120597V1198990(119905)

120597119905

+ 1198621(V(119899+2)2

(119905) minus V(119899minus2)2

(119905)) V1198990(119905)

+ 1198622(V(119899+2)1

(119905) minus V(119899minus2)1

(119905)) V1198990(119905)

+ 1198623(V(119899+2)0

(119905) minus V(119899minus2)0

(119905)) V1198990(119905)

+ 1198621(V(119899+2)1

(119905) minus V(119899minus2)1

(119905)) V1198991(119905)

6 Abstract and Applied Analysis

+ 1198622(V(119899+2)0

(119905) minus V(119899minus2)0

(119905)) V1198991(119905)

+ 1198621(V(119899+2)0

(119905) minus V(119899minus2)0

(119905)) V1198992(119905)

+ 1198621(V(119899+1)2

(119905) minus V(119899minus1)2

(119905)) V1198990(119905)

+ 1198621(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198992(119905)

+ 1198621(V(119899+1)1

(119905) minus V(119899minus1)1

(119905)) V1198991(119905)

+ 1198622(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198991(119905)

+ 1198621(V(119899+1)2

(119905) minus V(119899minus1)2

(119905)) V1198990(119905)

+ 1198622(V(119899+1)1

minus V(119899minus1)1

) V1198990(119899 119905)

+ 1198623(V(119899+1)0

(119899 119905) minus V(119899minus1)0

(119899 119905)) V1198990(119905)

(56)

with

V1198993(0) = 0 (57)

V1198993(119905) = 6119899119905 (119862

2+ 1198623+ 211986221(1 + 6119905)

+11986231(1 + 6119905)2 + 119862

1(1 + 2119862

2(1 + 6119905)))

(58)

Adding (49) (52) (55) and (58) we obtain

V119899(119905) = V

1198990(119905) + V

1198991(119905 1198621) + V1198992(119905 1198621 1198622)

+ V1198993(119905 1198621 1198622 1198623)

V1198993(119905) = 119899 + 6119862

1119899119905 + 6119899119905 (119862

1+ 1198622+ 11986221(1 + 6119905))

+ 6119899119905 (1198622+ 1198623+ 211986221(1 + 6119905) + 1198623

1(1 + 6119905)2

+ 11986231(1 + 6119905)2 + 119862

1(1 + 2119862

2(1 + 6119905)))

(59)

For the computation of the constants11986211198622 and119862

3applying

the method of least square mentioned in (16)ndash(18) we get

1198621= minus023640805995815892

1198622= minus0039496242739004025

1198623= minus0012135699742215487 for 119899 = 1

(60)

The exact solution of problem (42) is [9]

V119899(119905) =

119899

1 + 6119905 (61)

The HAM solution of (42) is given by [9]

V119899(119905) = (119899 + 119905) + ℎ (119899 + 1) 119905 + 3ℎ1199052 + 119905ℎ (1 + ℎ) (1 + 6119899)

+ (36ℎ2119899 + 6ℎ2 + 3ℎ) 1199052 + 18ℎ21199053(62)

2 4 6 8 1000

02

04

06

08

10

12

14

HAMExactOHAM

n

n

Figure 3 Comparisons of OHAM HAM and exact solutions at 119905 =1 ℎ = minus1

0 2 4 6 8 1000

05

10

15

20

25

ExactThird

SecondFirst

n

n

Figure 4 Comparison of first second third of OHAM HAM andexact solutions at 119905 = 1 ℎ = minus1

0 2 4 6 8 10minus7

minus6

minus5

minus4

minus3

minus2

minus1

0

Resid

ual

Residual

n

Figure 5 Residual of (42) at 119905 = 1

Abstract and Applied Analysis 7

4 Results and Discussions

The formulation presented in Section 2 provides highly accu-rate solutions for the problems demonstrated in Section 3We have used Mathematica 7 for most of our computationalwork Table 1 and Figure 1 give the comparisons of OHAMwith ADM and exact solutions for Model 1 Also the absoluteerrors at different values of 119899 at 119905 = 1 are given (Figure 4)Figure 3 shows the comparisons ofOHAMresults withHAMexact at different values of 119899 at 119905 = 1 for Model 2 Theconvergence of approximate orders to exact solutions is givenin Table 2 for Model 1 and Figure 5 for Model 2The residualshave been plotted for Model 1 in Figure 2 and for Model 2in Figure 5 We have concluded that the results obtained byOHAM are identical to the results obtained by ADM HAMand exact OHAM converges rapidly with increasing of theorder of approximation

5 Conclusion

In this work we have seen the effectiveness of OHAM[12ndash16] to differential-difference equations By applying thebasic idea of OHAM to differential-difference equations wefound it simpler in applicability more convenient to con-trol convergence and involved less computational overheadTherefore OHAM shows its validity and great potential forthe differential-difference equations arising in science andengineering

Conflict of Interests

The authors declare that there is no conflict of interestsregarding the publication of this paper

Acknowledgment

Theauthors are thankful to the anonymous reviewers for theirconstructive and valuable suggestions

References

[1] D Levi and R Yamilov ldquoConditions for the existence of highersymmetries of evolutionary equations on the latticerdquo Journal ofMathematical Physics vol 38 no 12 pp 6648ndash6674 1997

[2] R I Yamilov ldquoConstruction scheme for discreteMiura transfor-mationsrdquo Journal of Physics A Mathematical and General vol27 no 20 pp 6839ndash6851 1994

[3] I Yu Cherdantsev and R I Yamilov ldquoMaster symmetries fordifferential-difference equations of the Volterra typerdquo PhysicaD Nonlinear Phenomena vol 87 no 1ndash4 pp 140ndash144 1995

[4] A B Shabat and R I Yamilov ldquoSymmetries of nonlinearlatticesrdquo Leningrad Mathematical Journal vol 2 p 377 1991

[5] D-J Zhang ldquoSingular solutions in Casoratian form for twodifferential-difference equationsrdquo Chaos Solitons and Fractalsvol 23 no 4 pp 1333ndash1350 2005

[6] K Narita ldquoSoliton solution for a highly nonlinear difference-differential equationrdquo Chaos Solitons and Fractals vol 3 no 3pp 279ndash283 1993

[7] Z Wang and H-Q Zhang ldquoNew exact solutions to somedifference differential equationsrdquoChinese Physics vol 15 no 10pp 2210ndash2215 2006

[8] W Zhen and H Zhang ldquoA symbolic computational methodfor constructing exact solutions to difference-differential equa-tionsrdquoAppliedMathematics andComputation vol 178 no 2 pp431ndash440 2006

[9] L Zou Z Zong and G H Dong ldquoGeneralizing homotopyanalysis method to solve Lotka-Volterra equationrdquo Computersamp Mathematics with Applications vol 56 no 9 pp 2289ndash22932008

[10] Z Wang L Zou and H Zhang ldquoApplying homotopy analysismethod for solving differential-difference equationrdquo PhysicsLetters A General Atomic and Solid State Physics vol 369 no1-2 pp 77ndash84 2007

[11] Z Wang L Zou and Z Zong ldquoAdomian decomposition andPade approximate for solving differential-difference equationrdquoApplied Mathematics and Computation vol 218 no 4 pp 1371ndash1378 2011

[12] N Herisanu and VMarinca ldquoExplicit analytical approximationto large-amplitude non-linear oscillations of a uniform can-tilever beam carrying an intermediate lumped mass and rotaryinertiardquoMeccanica vol 45 no 6 pp 847ndash855 2010

[13] V Marinca and N Herisanu ldquoApplication of optimal homotopyasymptotic method for solving nonlinear equations arising inheat transferrdquo International Communications in Heat and MassTransfer vol 35 no 6 pp 710ndash715 2008

[14] V Marinca N Herisanu C Bota and B Marinca ldquoAn optimalhomotopy asymptotic method applied to the steady flow of afourth-grade fluid past a porous platerdquo Applied MathematicsLetters vol 22 no 2 pp 245ndash251 2009

[15] V Marinca N Herisanu and I Nemes ldquoA new analyticapproach to nonlinear vibration of an electrical machinerdquoProceedings of the RomanianAcademy vol 9 pp 229ndash236 2008

[16] V Marinca and N Herisanu ldquoDetermination of periodicsolutions for the motion of a particle on a rotating parabola bymeans of the optimal homotopy asymptotic methodrdquo Journal ofSound and Vibration vol 329 no 9 pp 1450ndash1459 2010

[17] M Idrees S Islam and A M Tirmizi ldquoApplication of optimalhomotopy asymptotic method of the Korteqag-de-Varies equa-tionrdquo Computers amp Mathematics with Applications vol 63 pp695ndash707 2012

[18] HUllah S IslamM Idrees andMArif ldquoSolution of boundarylayer problems with heat transfer by optimal homotopy asymp-totic methodrdquo Abstract and Applied Analysis vol 2013 ArticleID 324869 10 pages 2013

[19] R Nawaz H Ullah S Islam and M Idrees ldquoApplication ofoptimal homotopy asymptotic method to Burger equationsrdquoJournal of Applied Mathematics vol 2013 Article ID 387478 8pages 2013

[20] H Ullah S Islam M Idrees and R Nawaz ldquoApplicationof optimal homotopy asymptotic method to doubly wavesolutions of the coupled Drinfelrsquod-Sokolov-Wilson EquationsrdquoMathematical Problems in Engineering vol 2013 Article ID362816 8 pages 2013

Submit your manuscripts athttpwwwhindawicom

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Mathematical Problems in Engineering

Hindawi Publishing Corporationhttpwwwhindawicom

Differential EquationsInternational Journal of

Volume 2014

Applied MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Probability and StatisticsHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Mathematical PhysicsAdvances in

Complex AnalysisJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

OptimizationJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

CombinatoricsHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

International Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Operations ResearchAdvances in

Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Function Spaces

Abstract and Applied AnalysisHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

International Journal of Mathematics and Mathematical Sciences

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

The Scientific World JournalHindawi Publishing Corporation httpwwwhindawicom Volume 2014

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Algebra

Discrete Dynamics in Nature and Society

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Decision SciencesAdvances in

Discrete MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom

Volume 2014 Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Stochastic AnalysisInternational Journal of

6 Abstract and Applied Analysis

+ 1198622(V(119899+2)0

(119905) minus V(119899minus2)0

(119905)) V1198991(119905)

+ 1198621(V(119899+2)0

(119905) minus V(119899minus2)0

(119905)) V1198992(119905)

+ 1198621(V(119899+1)2

(119905) minus V(119899minus1)2

(119905)) V1198990(119905)

+ 1198621(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198992(119905)

+ 1198621(V(119899+1)1

(119905) minus V(119899minus1)1

(119905)) V1198991(119905)

+ 1198622(V(119899+1)0

(119905) minus V(119899minus1)0

(119905)) V1198991(119905)

+ 1198621(V(119899+1)2

(119905) minus V(119899minus1)2

(119905)) V1198990(119905)

+ 1198622(V(119899+1)1

minus V(119899minus1)1

) V1198990(119899 119905)

+ 1198623(V(119899+1)0

(119899 119905) minus V(119899minus1)0

(119899 119905)) V1198990(119905)

(56)

with

V1198993(0) = 0 (57)

V1198993(119905) = 6119899119905 (119862

2+ 1198623+ 211986221(1 + 6119905)

+11986231(1 + 6119905)2 + 119862

1(1 + 2119862

2(1 + 6119905)))

(58)

Adding (49) (52) (55) and (58) we obtain

V119899(119905) = V

1198990(119905) + V

1198991(119905 1198621) + V1198992(119905 1198621 1198622)

+ V1198993(119905 1198621 1198622 1198623)

V1198993(119905) = 119899 + 6119862

1119899119905 + 6119899119905 (119862

1+ 1198622+ 11986221(1 + 6119905))

+ 6119899119905 (1198622+ 1198623+ 211986221(1 + 6119905) + 1198623

1(1 + 6119905)2

+ 11986231(1 + 6119905)2 + 119862

1(1 + 2119862

2(1 + 6119905)))

(59)

For the computation of the constants11986211198622 and119862

3applying

the method of least square mentioned in (16)ndash(18) we get

1198621= minus023640805995815892

1198622= minus0039496242739004025

1198623= minus0012135699742215487 for 119899 = 1

(60)

The exact solution of problem (42) is [9]

V119899(119905) =

119899

1 + 6119905 (61)

The HAM solution of (42) is given by [9]

V119899(119905) = (119899 + 119905) + ℎ (119899 + 1) 119905 + 3ℎ1199052 + 119905ℎ (1 + ℎ) (1 + 6119899)

+ (36ℎ2119899 + 6ℎ2 + 3ℎ) 1199052 + 18ℎ21199053(62)

2 4 6 8 1000

02

04

06

08

10

12

14

HAMExactOHAM

n

n

Figure 3 Comparisons of OHAM HAM and exact solutions at 119905 =1 ℎ = minus1

0 2 4 6 8 1000

05

10

15

20

25

ExactThird

SecondFirst

n

n

Figure 4 Comparison of first second third of OHAM HAM andexact solutions at 119905 = 1 ℎ = minus1

0 2 4 6 8 10minus7

minus6

minus5

minus4

minus3

minus2

minus1

0

Resid

ual

Residual

n

Figure 5 Residual of (42) at 119905 = 1

Abstract and Applied Analysis 7

4 Results and Discussions

The formulation presented in Section 2 provides highly accu-rate solutions for the problems demonstrated in Section 3We have used Mathematica 7 for most of our computationalwork Table 1 and Figure 1 give the comparisons of OHAMwith ADM and exact solutions for Model 1 Also the absoluteerrors at different values of 119899 at 119905 = 1 are given (Figure 4)Figure 3 shows the comparisons ofOHAMresults withHAMexact at different values of 119899 at 119905 = 1 for Model 2 Theconvergence of approximate orders to exact solutions is givenin Table 2 for Model 1 and Figure 5 for Model 2The residualshave been plotted for Model 1 in Figure 2 and for Model 2in Figure 5 We have concluded that the results obtained byOHAM are identical to the results obtained by ADM HAMand exact OHAM converges rapidly with increasing of theorder of approximation

5 Conclusion

In this work we have seen the effectiveness of OHAM[12ndash16] to differential-difference equations By applying thebasic idea of OHAM to differential-difference equations wefound it simpler in applicability more convenient to con-trol convergence and involved less computational overheadTherefore OHAM shows its validity and great potential forthe differential-difference equations arising in science andengineering

Conflict of Interests

The authors declare that there is no conflict of interestsregarding the publication of this paper

Acknowledgment

Theauthors are thankful to the anonymous reviewers for theirconstructive and valuable suggestions

References

[1] D Levi and R Yamilov ldquoConditions for the existence of highersymmetries of evolutionary equations on the latticerdquo Journal ofMathematical Physics vol 38 no 12 pp 6648ndash6674 1997

[2] R I Yamilov ldquoConstruction scheme for discreteMiura transfor-mationsrdquo Journal of Physics A Mathematical and General vol27 no 20 pp 6839ndash6851 1994

[3] I Yu Cherdantsev and R I Yamilov ldquoMaster symmetries fordifferential-difference equations of the Volterra typerdquo PhysicaD Nonlinear Phenomena vol 87 no 1ndash4 pp 140ndash144 1995

[4] A B Shabat and R I Yamilov ldquoSymmetries of nonlinearlatticesrdquo Leningrad Mathematical Journal vol 2 p 377 1991

[5] D-J Zhang ldquoSingular solutions in Casoratian form for twodifferential-difference equationsrdquo Chaos Solitons and Fractalsvol 23 no 4 pp 1333ndash1350 2005

[6] K Narita ldquoSoliton solution for a highly nonlinear difference-differential equationrdquo Chaos Solitons and Fractals vol 3 no 3pp 279ndash283 1993

[7] Z Wang and H-Q Zhang ldquoNew exact solutions to somedifference differential equationsrdquoChinese Physics vol 15 no 10pp 2210ndash2215 2006

[8] W Zhen and H Zhang ldquoA symbolic computational methodfor constructing exact solutions to difference-differential equa-tionsrdquoAppliedMathematics andComputation vol 178 no 2 pp431ndash440 2006

[9] L Zou Z Zong and G H Dong ldquoGeneralizing homotopyanalysis method to solve Lotka-Volterra equationrdquo Computersamp Mathematics with Applications vol 56 no 9 pp 2289ndash22932008

[10] Z Wang L Zou and H Zhang ldquoApplying homotopy analysismethod for solving differential-difference equationrdquo PhysicsLetters A General Atomic and Solid State Physics vol 369 no1-2 pp 77ndash84 2007

[11] Z Wang L Zou and Z Zong ldquoAdomian decomposition andPade approximate for solving differential-difference equationrdquoApplied Mathematics and Computation vol 218 no 4 pp 1371ndash1378 2011

[12] N Herisanu and VMarinca ldquoExplicit analytical approximationto large-amplitude non-linear oscillations of a uniform can-tilever beam carrying an intermediate lumped mass and rotaryinertiardquoMeccanica vol 45 no 6 pp 847ndash855 2010

[13] V Marinca and N Herisanu ldquoApplication of optimal homotopyasymptotic method for solving nonlinear equations arising inheat transferrdquo International Communications in Heat and MassTransfer vol 35 no 6 pp 710ndash715 2008

[14] V Marinca N Herisanu C Bota and B Marinca ldquoAn optimalhomotopy asymptotic method applied to the steady flow of afourth-grade fluid past a porous platerdquo Applied MathematicsLetters vol 22 no 2 pp 245ndash251 2009

[15] V Marinca N Herisanu and I Nemes ldquoA new analyticapproach to nonlinear vibration of an electrical machinerdquoProceedings of the RomanianAcademy vol 9 pp 229ndash236 2008

[16] V Marinca and N Herisanu ldquoDetermination of periodicsolutions for the motion of a particle on a rotating parabola bymeans of the optimal homotopy asymptotic methodrdquo Journal ofSound and Vibration vol 329 no 9 pp 1450ndash1459 2010

[17] M Idrees S Islam and A M Tirmizi ldquoApplication of optimalhomotopy asymptotic method of the Korteqag-de-Varies equa-tionrdquo Computers amp Mathematics with Applications vol 63 pp695ndash707 2012

[18] HUllah S IslamM Idrees andMArif ldquoSolution of boundarylayer problems with heat transfer by optimal homotopy asymp-totic methodrdquo Abstract and Applied Analysis vol 2013 ArticleID 324869 10 pages 2013

[19] R Nawaz H Ullah S Islam and M Idrees ldquoApplication ofoptimal homotopy asymptotic method to Burger equationsrdquoJournal of Applied Mathematics vol 2013 Article ID 387478 8pages 2013

[20] H Ullah S Islam M Idrees and R Nawaz ldquoApplicationof optimal homotopy asymptotic method to doubly wavesolutions of the coupled Drinfelrsquod-Sokolov-Wilson EquationsrdquoMathematical Problems in Engineering vol 2013 Article ID362816 8 pages 2013

Submit your manuscripts athttpwwwhindawicom

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Mathematical Problems in Engineering

Hindawi Publishing Corporationhttpwwwhindawicom

Differential EquationsInternational Journal of

Volume 2014

Applied MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Probability and StatisticsHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Mathematical PhysicsAdvances in

Complex AnalysisJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

OptimizationJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

CombinatoricsHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

International Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Operations ResearchAdvances in

Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Function Spaces

Abstract and Applied AnalysisHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

International Journal of Mathematics and Mathematical Sciences

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

The Scientific World JournalHindawi Publishing Corporation httpwwwhindawicom Volume 2014

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Algebra

Discrete Dynamics in Nature and Society

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Decision SciencesAdvances in

Discrete MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom

Volume 2014 Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Stochastic AnalysisInternational Journal of

Abstract and Applied Analysis 7

4 Results and Discussions

The formulation presented in Section 2 provides highly accu-rate solutions for the problems demonstrated in Section 3We have used Mathematica 7 for most of our computationalwork Table 1 and Figure 1 give the comparisons of OHAMwith ADM and exact solutions for Model 1 Also the absoluteerrors at different values of 119899 at 119905 = 1 are given (Figure 4)Figure 3 shows the comparisons ofOHAMresults withHAMexact at different values of 119899 at 119905 = 1 for Model 2 Theconvergence of approximate orders to exact solutions is givenin Table 2 for Model 1 and Figure 5 for Model 2The residualshave been plotted for Model 1 in Figure 2 and for Model 2in Figure 5 We have concluded that the results obtained byOHAM are identical to the results obtained by ADM HAMand exact OHAM converges rapidly with increasing of theorder of approximation

5 Conclusion

In this work we have seen the effectiveness of OHAM[12ndash16] to differential-difference equations By applying thebasic idea of OHAM to differential-difference equations wefound it simpler in applicability more convenient to con-trol convergence and involved less computational overheadTherefore OHAM shows its validity and great potential forthe differential-difference equations arising in science andengineering

Conflict of Interests

The authors declare that there is no conflict of interestsregarding the publication of this paper

Acknowledgment

Theauthors are thankful to the anonymous reviewers for theirconstructive and valuable suggestions

References

[1] D Levi and R Yamilov ldquoConditions for the existence of highersymmetries of evolutionary equations on the latticerdquo Journal ofMathematical Physics vol 38 no 12 pp 6648ndash6674 1997

[2] R I Yamilov ldquoConstruction scheme for discreteMiura transfor-mationsrdquo Journal of Physics A Mathematical and General vol27 no 20 pp 6839ndash6851 1994

[3] I Yu Cherdantsev and R I Yamilov ldquoMaster symmetries fordifferential-difference equations of the Volterra typerdquo PhysicaD Nonlinear Phenomena vol 87 no 1ndash4 pp 140ndash144 1995

[4] A B Shabat and R I Yamilov ldquoSymmetries of nonlinearlatticesrdquo Leningrad Mathematical Journal vol 2 p 377 1991

[5] D-J Zhang ldquoSingular solutions in Casoratian form for twodifferential-difference equationsrdquo Chaos Solitons and Fractalsvol 23 no 4 pp 1333ndash1350 2005

[6] K Narita ldquoSoliton solution for a highly nonlinear difference-differential equationrdquo Chaos Solitons and Fractals vol 3 no 3pp 279ndash283 1993

[7] Z Wang and H-Q Zhang ldquoNew exact solutions to somedifference differential equationsrdquoChinese Physics vol 15 no 10pp 2210ndash2215 2006

[8] W Zhen and H Zhang ldquoA symbolic computational methodfor constructing exact solutions to difference-differential equa-tionsrdquoAppliedMathematics andComputation vol 178 no 2 pp431ndash440 2006

[9] L Zou Z Zong and G H Dong ldquoGeneralizing homotopyanalysis method to solve Lotka-Volterra equationrdquo Computersamp Mathematics with Applications vol 56 no 9 pp 2289ndash22932008

[10] Z Wang L Zou and H Zhang ldquoApplying homotopy analysismethod for solving differential-difference equationrdquo PhysicsLetters A General Atomic and Solid State Physics vol 369 no1-2 pp 77ndash84 2007

[11] Z Wang L Zou and Z Zong ldquoAdomian decomposition andPade approximate for solving differential-difference equationrdquoApplied Mathematics and Computation vol 218 no 4 pp 1371ndash1378 2011

[12] N Herisanu and VMarinca ldquoExplicit analytical approximationto large-amplitude non-linear oscillations of a uniform can-tilever beam carrying an intermediate lumped mass and rotaryinertiardquoMeccanica vol 45 no 6 pp 847ndash855 2010

[13] V Marinca and N Herisanu ldquoApplication of optimal homotopyasymptotic method for solving nonlinear equations arising inheat transferrdquo International Communications in Heat and MassTransfer vol 35 no 6 pp 710ndash715 2008

[14] V Marinca N Herisanu C Bota and B Marinca ldquoAn optimalhomotopy asymptotic method applied to the steady flow of afourth-grade fluid past a porous platerdquo Applied MathematicsLetters vol 22 no 2 pp 245ndash251 2009

[15] V Marinca N Herisanu and I Nemes ldquoA new analyticapproach to nonlinear vibration of an electrical machinerdquoProceedings of the RomanianAcademy vol 9 pp 229ndash236 2008

[16] V Marinca and N Herisanu ldquoDetermination of periodicsolutions for the motion of a particle on a rotating parabola bymeans of the optimal homotopy asymptotic methodrdquo Journal ofSound and Vibration vol 329 no 9 pp 1450ndash1459 2010

[17] M Idrees S Islam and A M Tirmizi ldquoApplication of optimalhomotopy asymptotic method of the Korteqag-de-Varies equa-tionrdquo Computers amp Mathematics with Applications vol 63 pp695ndash707 2012

[18] HUllah S IslamM Idrees andMArif ldquoSolution of boundarylayer problems with heat transfer by optimal homotopy asymp-totic methodrdquo Abstract and Applied Analysis vol 2013 ArticleID 324869 10 pages 2013

[19] R Nawaz H Ullah S Islam and M Idrees ldquoApplication ofoptimal homotopy asymptotic method to Burger equationsrdquoJournal of Applied Mathematics vol 2013 Article ID 387478 8pages 2013

[20] H Ullah S Islam M Idrees and R Nawaz ldquoApplicationof optimal homotopy asymptotic method to doubly wavesolutions of the coupled Drinfelrsquod-Sokolov-Wilson EquationsrdquoMathematical Problems in Engineering vol 2013 Article ID362816 8 pages 2013

Submit your manuscripts athttpwwwhindawicom

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Mathematical Problems in Engineering

Hindawi Publishing Corporationhttpwwwhindawicom

Differential EquationsInternational Journal of

Volume 2014

Applied MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Probability and StatisticsHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Mathematical PhysicsAdvances in

Complex AnalysisJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

OptimizationJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

CombinatoricsHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

International Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Operations ResearchAdvances in

Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Function Spaces

Abstract and Applied AnalysisHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

International Journal of Mathematics and Mathematical Sciences

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

The Scientific World JournalHindawi Publishing Corporation httpwwwhindawicom Volume 2014

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Algebra

Discrete Dynamics in Nature and Society

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Decision SciencesAdvances in

Discrete MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom

Volume 2014 Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Stochastic AnalysisInternational Journal of

Submit your manuscripts athttpwwwhindawicom

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Mathematical Problems in Engineering

Hindawi Publishing Corporationhttpwwwhindawicom

Differential EquationsInternational Journal of

Volume 2014

Applied MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Probability and StatisticsHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Mathematical PhysicsAdvances in

Complex AnalysisJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

OptimizationJournal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

CombinatoricsHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

International Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Operations ResearchAdvances in

Journal of

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Function Spaces

Abstract and Applied AnalysisHindawi Publishing Corporationhttpwwwhindawicom Volume 2014

International Journal of Mathematics and Mathematical Sciences

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

The Scientific World JournalHindawi Publishing Corporation httpwwwhindawicom Volume 2014

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Algebra

Discrete Dynamics in Nature and Society

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Decision SciencesAdvances in

Discrete MathematicsJournal of

Hindawi Publishing Corporationhttpwwwhindawicom

Volume 2014 Hindawi Publishing Corporationhttpwwwhindawicom Volume 2014

Stochastic AnalysisInternational Journal of


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