1) Type the following select statement at SQL prompt and examine the output. Select last name, job id, salary as sal from employees; SQL> SELECT LAST_NAME, JOB_ID, SALARY SAL FROM EMPLOYEES; 2) Type the following select statement at SQL prompt and examine the output. Select * from salgrade; SQL> SELECT * FROM SALGRADE; 3) There are four coding errors in this statement. Can you identify them? Select employee id, last name sal x 12 annual salary from employees; SQL> SELECT EMPLOYEE_ID, LAST_NAME, SALARY * 12 “Annual Salary” FROM EMPLOYEES; 4) Display the structure of the departments table. SQL> DESC DEPT 5) Display the last name concatenated with the job ID, separated by a comma and space, and name the column Employee and Title. SQL> SELECT LAST_NAME || ‘, ‘ || JOB_ID “Employee and Title” FROM EMPLOYEES; 6) Display department numbers and names from department table. SQL> SELECT DEPTNO, DNAME FROM DEPT; 7) Retrieve the list of employees’ names, employee ID, job and salary from EMP table. SQL> SELECT EMPNO, ENAME, JOB, SAL FROM EMP; 8) Retrieve the list of names, jobs with “Designation” heading, salary with “Basic Salary” heading from EMP table. SQL> SELECT ENAME, JOB DESIGNATION, SAL "Basic Salary" FROM EMP;

9) List out the names of all Tables. SQL> SELECT * FROM TAB; 10) Display employee name, job, 8% on sal as bonus , 9.75% on salary as DA. SQL> SELECT ENAME, JOB, SAL * 0.08 BONUS, SAL * .975 AS DA FROM EMP; 11) Display employee name, job, hiredate, salary, 9.25% on salary as Income Tax and Net Salary (salary – Tax). SQL> SELECT ENAME, JOB, HIREDATE, SAL, SAL * 9.25 / 100 "Income Tax", SAL - (SAL * 9.25 / 100) "Net Salary" FROM EMP; 12) Display employee name, salary, 8% on salary as bonus and 2% as Tax on (salary + bonus). SQL> SELECT ENAME, SAL, SAL * 8 / 100 BONUS, (SAL + SAL * 8 / 100) * 2 / 100 "Tax" FROM EMP; 13) Display the following formats a) {ename} working as a {job} with basic salary {sal} SQL> SELECT ENAME || ' working as a ' || JOB || ' with basic ' || SAL AS "EMPLOYEE INFORMATION" FROM EMP; b) {ename} working in {deptno} department as a {job} with basic {sal} SQL> SELECT ENAME || ' working in ' || DEPTNO || ' department as a ' || JOB || ' with basic ' || SAL EMP_INFO FROM EMP; c) The employee {ename}({job}) paying Income Tax {sal*9.75/100} SQL> SELECT ENAME || '(' || JOB || ')' || ' paying Income Tax ' || SAL * 9.75 / 100 TAX_INFO FROM EMP; 14) Produce the following output. EMPLOYEE ----------------

SMITH(Clerk) ALLEN(Salesman) WARD(Salesman) JONES(Manager) MARTIN(Salesman) and so on……………… SQL> SELECT ENAME || '(' || JOB || ')' FROM EMP; 15) Display all employees who were hired during 1983. SQL> SELECT * FROM EMP WHERE HIREDATE >= '01-JAN-1983' AND HIREDATE <= '31-DEC-1983'; 16) Display details who are working in the departments 10, 20 as a MANAGER. SQL> SELECT * FROM EMP WHERE JOB='MANAGER' AND (DEPTNO = 10 OR DEPTNO = 20); 17) Develop a query that will accept a given job name. Execute the query a number of times to test. SQL> SELECT * FROM EMP WHERE JOB = ‘&JOB’; 18) Display the name, job, salary and bonus (8 % of salary) with “BONUS” heading and output should be in the order of bonus. SQL> SELECT ENAME, JOB, SAL, SAL * 8 / 100 BONUS FROM EMP ORDER BY BONUS; 19) Display employee’s details, who are not getting commission. Write queries in possible methods. SQL> SELECT * FROM EMPLOYEES WHERE COMMISSION_PCT = 0 OR COMMISSION_PCT IS NULL; 20) Display details whose employee name contain ‘E’ as a second character from end of the string. SQL> SELECT * FROM EMP WHERE SUBSTR (ENAME,-2, 1) = 'E'; SQL> SELECT * FROM EMP WHERE ENAME LIKE '%E_';

21) Display details whose employee name contains “S” or “s”. SQL> SELECT * FROM EMP WHERE UPPER (ENAME) LIKE '%S%'; 22) Display employee name, job, salary, commission and total salary (sal + comm) with ordering highest total salary first. SQL> SELECT ENAME, JOB, COMM, (SAL + COMM) "TOTAL SALARY" FROM EMP ORDER BY "TOTAL SALARY"; 23) Find the most recently hired employees in each department. SQL> SELECT * FROM EMP WHERE (HIREDATE, DEPTNO) IN (SELECT MAX (HIREDATE), DEPTNO FROM EMP GROUP BY DEPTNO) 24) Show all data of the clerks who have been hired after the year 1997. SQL> SELECT * FROM EMP WHERE UPPER (JOB) = 'CLERK' AND HIREDATE > '31-DEC-1997'; 25) Show the last name, job, salary, and commission of those employees who earn commission. Sort the data by the salary in descending order. SQL> SELECT LAST_NAME, JOB_ID, SALARY, COMMISSION_PCT FROM EMPLOYEES WHERE COMMISSION_PCT != 0 OR COMMISSION_PCT IS NOT NULL; 26) Show the employees that have no commission with a 10% raise in their salary (round off the salaries). SQL> SELECT EMPNO, ENAME, JOB, MGR, HIREDATE, ROUND (SAL + SAL * 10 / 100), COMM, DEPTNO FROM EMP WHERE COMM = 0 OR COMM IS NULL; 27) Show those employees that have a name starting with J, K, L, or M. SQL> SELECT * FROM EMP WHERE SUBSTR (ENAME, 1, 1) IN ('J','K','L','M');

SQL Assignments

Day 2 1) Replace ‘CLERKS’ as ‘MANAGER’, ‘MANAGER’ as ‘BOSS’ and rest undefined. SQL> SELECT ENAME, DECODE (RTRIM (UPPER (JOB)), 'CLERK', 'MANAGER', 'MANAGER', 'BOSS', JOB) JOB FROM EMP 2) Find the average salary for each job. Remember that salesman getting commission. SQL> SELECT JOB, AVG (SAL+NVL (COMM, 0)) FROM EMP GROUP BY JOB; 3) Display employee name, job, salary, department name and date of join. Sort latest joined first for every department. SQL> SELECT ENAME, JOB, SAL, DNAME, HIREDATE FROM EMP, DEPT WHERE EMP.DEPTNO = DEPT.DEPTNO ORDER BY EMP.DEPTNO, HIREDATE DESC 4) Display minimum, maximum and average salary for each department. SQL> SELECT DEPTNO, MIN (SAL) MINIMUM, MAX (SAL) MAXIMUM, AVG (SAL) AVERAGE FROM EMP GROUP BY DEPTNO; 5) List the ename, job, annual salary, department number, department name and grade for employees who earn more than 36000 a year and who are clerks. SQL> SELECT E.ENAME, E.JOB, E.SAL * 12 "Annual Salary", D.DEPTNO, D.DNAME, S.GRADE FROM EMP E, DEPT D, SALGRADE S WHERE E.DEPTNO = D.DEPTNO AND

(E.SAL * 12) > 12000 AND E.JOB = 'CLERK' AND E.SAL BETWEEN S.LOSAL AND S.HISAL

6) Count number of employee working in Chicago location. SQL> SELECT COUNT (*) FROM EMP WHERE DEPTNO = (SELECT DEPTNO

FROM DEPT

WHERE UPPER (RTRIM (LOC)) = ‘CHICAGO’) SQL> SELECT COUNT (*) FROM EMP, DEPT WHERE EMP.DEPTNO = DEPT.DEPTNO AND UPPER (RTRIM (LOC)) = ‘CHICAGO’; 7) Find out employee details whose salary is less than average salary of New York. SQL> SELECT E.* FROM EMP E, DEPT D WHERE E.DEPTNO = D.DEPTNO AND E.SAL < (SELECT AVG (SAL)

FROM EMP, DEPT WHERE EMP.DEPTNO = DEPT.DEPTNOAND UPPER (RTRIM (LOC)) = 'NEW YORK'))

8) Display employee name, job, sal, comm and total salary (sal+comm) whose total salary more than maximum total salary of SALES department. SQL> SELECT ENAME, JOB, SAL, NVL (COMM, 0), SAL + NVL (COMM, 0) “Total Salary” FROM EMP WHERE (SAL + NVL (COMM, 0)) > (SELECT MAX (SAL)

FROM EMP WHERE DEPTNO = (SELECT DEPTNO

FROM DEPT WHERE DNAME = ‘SALES’));

SQL> SELECT ENAME, JOB, SAL, NVL (COMM, 0), SAL + NVL (COMM, 0) “Total Salary” FROM EMP WHERE (SAL + NVL (COMM, 0)) > (SELECT MAX (EMP.SAL)

FROM EMP, DEPT WHERE EMP.DEPTNO = DEPT.DEPTNO AND DEPT.DNAME = ‘SALES’));

9) Display department name and location in which department not have employees. Write this query with SET operators. SQL> SELECT DNAME, LOC FROM DEPT MINUS SELECT DNAME, LOC FROM DEPT , EMP WHERE DEPT.DEPTNO =EMP.DEPTNO ; The following queries by using Employees, Departments, Locations, etc. 10) Show the department names, locations, names, job titles, and salaries of employees who work in location 1800.

SQL> SELECT DEPT.DEPARTMENT_NAME, LOC.CITY, EMP.FIRST_NAME || ‘ ‘ || EMP.LAST_NAME NAME, JOBS.JOB_TITLE, EMP.SALARY FROM EMPLOYEES EMP, DEPARTMENTS DEPT, LOCATIONS LOC, JOBS WHERE EMP.DEPARTMENT_ID = DEPT.DEPARTMENT_ID AND EMP.JOB_ID = JOBS.JOB_ID AND DEPT.LOCATION_ID = LOC.LOCATION_ID AND DEPT.LOCATION_ID = 1800; 11) How many employees have a name that ends with an n? Create two possible solutions. SELECT COUNT (*) FROM EMPLOYEES WHERE UPPER (SUBSTR (TRIM (FIRST_NAME), -1)) = ‘N’ OR UPPER (SUBSTR (TRIM (LAST_NAME), -1)) = ‘N’; SELECT COUNT (*) FROM EMPLOYEES WHERE UPPER (TRIM (FIRST_NAME)) LIKE ‘%N’ OR UPPER (TRIM (LAST_NAME)) LIKE ‘%N’ SELECT ‘FIRST NAME’,COUNT (*) FROM EMPLOYEES WHERE UPPER (SUBSTR (TRIM (FIRST_NAME), -1)) = ‘N’

UNION SELECT ‘LAST NAME’,COUNT (*) FROM EMPLOYEES WHERE UPPER (SUBSTR (TRIM (LAST_NAME), -1)) = ‘N’; 12) Which jobs are found in departments 10 and 20? SELECT JOBS.JOB_TITLE FROM EMPLOYEES EMP, JOBS WHERE EMP.JOB_ID = JOBS.JOB_ID AND EMP.DEPARTMENT_ID IN (10, 20); 13) Show all employees who were hired in the first half of the month (before the 16th of the month) SQL> SELECT * FROM EMPLOYEES WHERE TO_CHAR (HIRE_DATE,’DD’) < 16; 14) Find the job that was filled in the first half of 1990 and the same job that was filled during in 1991.

SQL> SELECT JOB_TITLE FROM JOBS WHERE JOB_ID IN (SELECT JOB_ID

FROM EMPLOYEES WHERE TO_NUMBER (TO_CHAR (HIRE_DATE, ’MMYYYY’)) BETWEEN 011990 AND 061990)

INTERSECT SELECT JOB_TITLE FROM JOBS WHERE JOB_ID IN (SELECT JOB_ID

FROM EMPLOYEES WHERE TO_CHAR (HIRE_DATE, ‘YYYY’) = 1991);

15) Show the department number, department name, and the number of employees working in each department ordered by count. SQL> SELECT EMP.DEPARTMENT_ID, DEPT.DEPARTMENT_NAME, COUNT (*) FROM EMPLOYEES EMP, DEPARTMENTS DEPT WHERE EMP.DEPARTMENT_ID = DEPT.DEPARTMENT_ID GROUP BY EMP.DEPARTMENT_ID, DEPT.DEPARTMENT_NAME ORDER BY 3 DESC;

SQL Assignments

Day 3 1) Update the salaries by adding their commission to salary in EMP table; SQL> UPDATE EMP SET SAL = NVL (SAL, 0) + NVL (COMM, 0); 2) Update commission as 200 for department number 20 SQL> UPDATE EMP SET COMM = 200 WHERE DEPTNO = 20 AND

NVL (COMM,0) = 0; 3) Update salary by 1000 of employees who are working in accounting department and whose job experience is more than 225 months. SQL> UPDATE EMP SET SAL = NVL (SAL, 0) + 1000 WHERE DEPTNO IN (SELECT DEPTNO

FROM DEPT WHERE UPPER (TRIM (DNAME)) = 'ACCOUNTING')

AND MONTHS_BETWEEN (SYSDATE, HIREDATE) > 225 4) Delete the rows from EMP table who are working as a clerk in the department SALES. SQL> DELETE FROM EMP WHERE UPPER (TRIM (JOB)) ='CLERK' AND DEPTNO IN (SELECT DEPTNO

FROM DEPT WHERE UPPER (TRIM (DNAME)) = 'SALES')

5) Create the following tables with appropriate constraints and insert the following data. SALESPEOPLE: SNUM SNAME CITY COMM 1001 PEEL LONDON 0.12 1002 SSERRES SAN JOSE 0.13 1003 MOTIKA LONDON 0.11 1004 AXELROD NEW YORK 0.10 CUSTOMERS: CNUM CNAME CITY RATING SNUM 2001 HOFFMAN LONDON 100 1001

2002 GIOVANNI ROME 200 1003 2003 LIU SAN JOSE 200 1002 2004 GRASS SAN JOSE 300 1002 ORDERS: ONUM AMT ODATE CNUM 3001 18.69 10/03/90 2001 3003 767.19 12/08/90 2001 3002 1900.10 15/01/91 2004 3005 5150.45 03/10/90 2003 3006 1098.16 02/03/92 2002 SQL> CREATE TABLE SALESPEOPLE (SNUM NUMBER (4) CONSTRAINT PK_SNUM PRIMARY KEY, SNAME VARCHAR2 (10), CITY VARCHAR2 (10), COMM NUMBER (2, 2)); INSERT INTO SALESPEOPLE VALUES (&SNUM, UPPER ('&SNAME'), UPPER ('&CITY'), &COMM); INSERT INTO SALESPEOPLE VALUES (1001, UPPER ('PEEL'), UPPER ('LONDON'), 0.12); INSERT INTO SALESPEOPLE VALUES (1002, UPPER ('SSERRES'), UPPER ('SAN JOSE'), 0.13); INSERT INTO SALESPEOPLE VALUES (1003, UPPER ('MOTIKA'), UPPER ('LONDON'), 0.11) INSERT INTO SALESPEOPLE VALUES (1004, UPPER ('AXELROD'), UPPER ('NEW YORK'),

0.10) CREATE TABLE CUSTOMERS (CNUM NUMBER (4) CONSTRAINT PK_CNUM PRIMARY KEY, CNAME VARCHAR2 (10), CITY VARCHAR2 (10), RATING NUMBER (3), SNUM NUMBER (4) CONSTRAINT FK_SNUM REFERENCES

SALESPEOPLE (SNUM)); INSERT INTO CUSTOMERS VALUES (&CNUM, UPPER ('&CNAME'), UPPER ('&CITY'), &RATING, &SNUM); INSERT INTO CUSTOMERS VALUES (2001, UPPER ('HOFFMAN'), UPPER ('LONDON'), 100, 1001) INSERT INTO CUSTOMERS VALUES (2002, UPPER ('GIOVANNI'), UPPER ('ROME'), 200, 1003) INSERT INTO CUSTOMERS VALUES (2003, UPPER ('LIU'), UPPER ('SAN JOSE'), 200, 1002) INSERT INTO CUSTOMERS VALUES (2004, UPPER ('GRASS'), UPPER ('SAN JOSE'), 300, 1002)

CREATE TABLE ORDERS (ONUM NUMBER (4) CONSTRAINT PK_ONUM PRIMARY KEY, AMT NUMBER (7, 2), ODATE DATE, CNUM NUMBER (4) CONSTRAINT FK_CNUM REFERENCES

CUSTOMERS); INSERT INTO ORDERS VALUES (&ONUM, &AMT, ‘&ODATE’, &CNUM); INSERT INTO ORDERS VALUES (3001, 18.69, '10-DEC-1990', 2001) INSERT INTO ORDERS VALUES (3002, 1900.10, '15-JAN-1991', 2004) INSERT INTO ORDERS VALUES (3003, 767.19, '12-AUG-1990', 2001) INSERT INTO ORDERS VALUES (3005, 5150.45, '03-OCT-1990', 2003) INSERT INTO ORDERS VALUES (3006, 1098.16, '02-MAR-1992', 2002) 6) Find the largest order taken by each salesperson.

SQL> SELECT S.SNUM SALESPERSON, MAX (O.AMT) “ORDER AMOUNT” FROM SALESPEOPLE S, CUSTOMERS C, ORDERS O WHERE O.CNUM = C.CNUM AND C.SNUM = S.SNUM AND (C.CNUM, O.AMT) IN (SELECT O.CNUM, MAX (O.AMT)

FROM ORDERS O GROUP BY O.CNUM)

GROUP BY S.SNUM UNION SELECT S.SNUM, 0 FROM SALESPEOPLE S WHERE NOT EXISTS (SELECT * FROM CUSTOMERS C

WHERE S.SNUM = C.SNUM); 7) Find which salespeople currently have orders in the Orders table. SQL> SELECT DISTINCT S.SNUM, S.SNAME FROM SALESPEOPLE S, CUSTOMERS C, ORDERS O WHERE O.CNUM = C.CNUM AND C.SNUM = S.SNUM; 8) List names of all customers matched with the salespeople serving them. SQL> SELECT DISTINCT C.CNUM, C.CNAME, S.SNUM, S.SNAME FROM SALESPEOPLE S, CUSTOMERS C, ORDERS O WHERE O.CNUM = C.CNUM AND C.SNUM = S.SNUM;

9) Count the orders of each of the salespeople and output the result descending order. SQL> SELECT S.SNUM, COUNT (*) “No. of Orders placed” FROM SALESPEOPLE S, CUSTOMERS C, ORDERS O WHERE O.CNUM = C.CNUM AND C.SNUM = S.SNUM GROUP BY S.SNUM UNION SELECT S.SNUM, 0 FROM SALESPEOPLE S WHERE NOT EXISTS (SELECT * FROM CUSTOMERS C

WHERE S.SNUM = C.SNUM) ORDER BY 2 DESC;

10) List the customer table if and only if one or more of the customer located in San Jose. SQL> SELECT * FROM CUSTOMERS WHERE (SELECT COUNT (*) FROM CUSTOMERS WHERE UPPER (TRIM (CITY)) = ‘SAN JOSE’) > 1; 11) Display customer name, order amount, year for largest order amount taken in each year. SQL> SELECT C.CNAME, O.AMT, TO_CHAR (O.ODATE,’YYYY’) “Year” FROM CUSTOMERS C, ORDERS O WHERE O.CNUM = C.CNUM AND (TO_CHAR (O.ODATE,’YYYY’), O.AMT) IN

(SELECT TO_CHAR (ODATE,'YYYY'), MAX (AMT) FROM ORDERS GROUP BY TO_CHAR (ODATE,'YYYY'));

12) Find all the customers with orders on October 3. SQL> SELECT * FROM CUSTOMERS C, ORDERS O WHERE O.CNUM = C.CNUM AND O.ODATE LIKE ’03-OCT%’;

SQL Assignments

Day 5 1) Update the salaries by adding their commission to salary in EMP table; SQL> UPDATE EMP SET SAL = NVL (SAL, 0) + NVL (COMM, 0); 2) Update commission as 200 for department number 20 SQL> UPDATE EMP SET COMM = 200 WHERE DEPTNO = 20 AND

NVL (COMM,0) = 0; 3) Update salary by 1000 of employees who are working in accounting department and whose job experience is more than 225 months. SQL> UPDATE EMP SET SAL = NVL (SAL, 0) + 1000 WHERE DEPTNO IN (SELECT DEPTNO

FROM DEPT WHERE UPPER (TRIM (DNAME)) = 'ACCOUNTING')

AND MONTHS_BETWEEN (SYSDATE, HIREDATE) > 225 4) Delete the rows from EMP table who are working as a clerk in the department SALES. SQL> DELETE FROM EMP WHERE UPPER (TRIM (JOB)) ='CLERK' AND DEPTNO IN (SELECT DEPTNO

FROM DEPT WHERE UPPER (TRIM (DNAME)) = 'SALES')

5) Create the following tables with appropriate constraints and insert the following data. SALESPEOPLE: SNUM SNAME CITY COMM 1001 PEEL LONDON 0.12 1002 SSERRES SAN JOSE 0.13 1003 MOTIKA LONDON 0.11 1004 AXELROD NEW YORK 0.10 CUSTOMERS: CNUM CNAME CITY RATING SNUM 2001 HOFFMAN LONDON 100 1001

2002 GIOVANNI ROME 200 1003 2003 LIU SAN JOSE 200 1002 2004 GRASS SAN JOSE 300 1002 ORDERS: ONUM AMT ODATE CNUM 3001 18.69 10/03/90 2001 3003 767.19 12/08/90 2001 3002 1900.10 15/01/91 2004 3005 5150.45 03/10/90 2003 3006 1098.16 02/03/92 2002 SQL> CREATE TABLE SALESPEOPLE (SNUM NUMBER (4) CONSTRAINT PK_SNUM PRIMARY KEY, SNAME VARCHAR2 (10), CITY VARCHAR2 (10), COMM NUMBER (2, 2)); INSERT INTO SALESPEOPLE VALUES (&SNUM, UPPER ('&SNAME'), UPPER ('&CITY'), &COMM); INSERT INTO SALESPEOPLE VALUES (1001, UPPER ('PEEL'), UPPER ('LONDON'), 0.12); INSERT INTO SALESPEOPLE VALUES (1002, UPPER ('SSERRES'), UPPER ('SAN JOSE'), 0.13); INSERT INTO SALESPEOPLE VALUES (1003, UPPER ('MOTIKA'), UPPER ('LONDON'), 0.11) INSERT INTO SALESPEOPLE VALUES (1004, UPPER ('AXELROD'), UPPER ('NEW YORK'),

0.10) CREATE TABLE CUSTOMERS (CNUM NUMBER (4) CONSTRAINT PK_CNUM PRIMARY KEY, CNAME VARCHAR2 (10), CITY VARCHAR2 (10), RATING NUMBER (3), SNUM NUMBER (4) CONSTRAINT FK_SNUM REFERENCES

SALESPEOPLE (SNUM)); INSERT INTO CUSTOMERS VALUES (&CNUM, UPPER ('&CNAME'), UPPER ('&CITY'), &RATING, &SNUM); INSERT INTO CUSTOMERS VALUES (2001, UPPER ('HOFFMAN'), UPPER ('LONDON'), 100, 1001) INSERT INTO CUSTOMERS VALUES (2002, UPPER ('GIOVANNI'), UPPER ('ROME'), 200, 1003) INSERT INTO CUSTOMERS VALUES (2003, UPPER ('LIU'), UPPER ('SAN JOSE'), 200, 1002) INSERT INTO CUSTOMERS VALUES (2004, UPPER ('GRASS'), UPPER ('SAN JOSE'), 300, 1002)

CREATE TABLE ORDERS (ONUM NUMBER (4) CONSTRAINT PK_ONUM PRIMARY KEY, AMT NUMBER (7, 2), ODATE DATE, CNUM NUMBER (4) CONSTRAINT FK_CNUM REFERENCES

CUSTOMERS); INSERT INTO ORDERS VALUES (&ONUM, &AMT, ‘&ODATE’, &CNUM); INSERT INTO ORDERS VALUES (3001, 18.69, '10-DEC-1990', 2001) INSERT INTO ORDERS VALUES (3002, 1900.10, '15-JAN-1991', 2004) INSERT INTO ORDERS VALUES (3003, 767.19, '12-AUG-1990', 2001) INSERT INTO ORDERS VALUES (3005, 5150.45, '03-OCT-1990', 2003) INSERT INTO ORDERS VALUES (3006, 1098.16, '02-MAR-1992', 2002) 6) Find the largest order taken by each salesperson.

SQL> SELECT S.SNUM SALESPERSON, MAX (O.AMT) “ORDER AMOUNT” FROM SALESPEOPLE S, CUSTOMERS C, ORDERS O WHERE O.CNUM = C.CNUM AND C.SNUM = S.SNUM AND (C.CNUM, O.AMT) IN (SELECT O.CNUM, MAX (O.AMT)

FROM ORDERS O GROUP BY O.CNUM)

GROUP BY S.SNUM UNION SELECT S.SNUM, 0 FROM SALESPEOPLE S WHERE NOT EXISTS (SELECT * FROM CUSTOMERS C

WHERE S.SNUM = C.SNUM); 7) Find which salespeople currently have orders in the Orders table. SQL> SELECT DISTINCT S.SNUM, S.SNAME FROM SALESPEOPLE S, CUSTOMERS C, ORDERS O WHERE O.CNUM = C.CNUM AND C.SNUM = S.SNUM; 8) List names of all customers matched with the salespeople serving them. SQL> SELECT DISTINCT C.CNUM, C.CNAME, S.SNUM, S.SNAME FROM SALESPEOPLE S, CUSTOMERS C, ORDERS O WHERE O.CNUM = C.CNUM AND C.SNUM = S.SNUM;

9) Count the orders of each of the salespeople and output the result descending order. SQL> SELECT S.SNUM, COUNT (*) “No. of Orders placed” FROM SALESPEOPLE S, CUSTOMERS C, ORDERS O WHERE O.CNUM = C.CNUM AND C.SNUM = S.SNUM GROUP BY S.SNUM UNION SELECT S.SNUM, 0 FROM SALESPEOPLE S WHERE NOT EXISTS (SELECT * FROM CUSTOMERS C

WHERE S.SNUM = C.SNUM) ORDER BY 2 DESC;

10) List the customer table if and only if one or more of the customer located in San Jose. SQL> SELECT * FROM CUSTOMERS WHERE (SELECT COUNT (*) FROM CUSTOMERS WHERE UPPER (TRIM (CITY)) = ‘SAN JOSE’) > 1; 11) Display customer name, order amount, year for largest order amount taken in each year. SQL> SELECT C.CNAME, O.AMT, TO_CHAR (O.ODATE,’YYYY’) “Year” FROM CUSTOMERS C, ORDERS O WHERE O.CNUM = C.CNUM AND (TO_CHAR (O.ODATE,’YYYY’), O.AMT) IN

(SELECT TO_CHAR (ODATE,'YYYY'), MAX (AMT) FROM ORDERS GROUP BY TO_CHAR (ODATE,'YYYY'));

12) Find all the customers with orders on October 3. SQL> SELECT * FROM CUSTOMERS C, ORDERS O WHERE O.CNUM = C.CNUM AND O.ODATE LIKE ’03-OCT%’; 10. Write a program to generate even numbers from 1 to 50 horizontally. DECLARE n NUMBER(2):=0; c VARCHAR2(100):=’’; BEGIN WHILE N < 51 LOOP CONCAT (C||’,’, TO_CHAR(N)); END LOOP; dbms_output.put_line (susstr(c,1,length(c) – 1) END;

SQL Assignments

DAY3 1) Update the salaries by adding their commission to them in EMP table. 2) Update employee commission in EMP table by giving 200 who are not getting commission in 20th department. 3) Update salaries in EMP table by adding 1000 who are working in ACCOUNTING department and job experience is more then 225 months. 4) Delete the rows from EMP table who are working as a clerk in the department SALES. 5) Create the following tables with appropriate constraints and insert the following data. SALESPEOPLE: SNUM SNAME CITY COMM 1001 PEEL LONDON 0.12 1002 SSERRES SAN JOSE 0.13 1003 MOTIKA LONDON 0.11 1004 AXELROD NEW YORK 0.10 CUSTOMERS: CNUM CNAME CITY RATING SNUM 2001 HOFFMAN LONDON 100 1001 2002 GIOVANNI ROME 200 1003 2003 LIU SAN JOSE 200 1002 2004 GRASS SAN JOSE 300 1002 ORDERS: ONUM AMT ODATE CNUM 3001 18.69 10/03/90 2001 3003 767.19 12/08/90 2001 3002 1900.10 15/01/91 2004 3005 5150.45 03/10/90 2003 3006 1098.16 02/03/92 2002 6) Find the largest order taken by each salesperson. 7) Find which salespeople currently have orders in the Orders table. 8) List names of all customers matched with the salespeople serving them. 9) Count the orders of each of the salespeople and output the result descending order.

10) List the customer table if and only if one or more of the customer located in San Jose. 11) Display customer name, order amount, year for largest order amount taken in each year. 12) Find all the customers with orders on October 3.

SQL Assignments

Day 1 1) Type the following select statement at SQL prompt and examine the output. Select last_name, job_id, salary as sal from employees; 2) Type the following select statement at SQL prompt and examine the output. Select * from job_grades; 3) There are four coding errors in this statement. Can you identify them? Select employee_id, last_name sal x 12 annual salary from employees; 4) Display the structure of the departments table. 5) Display the last name concatenated with the job ID, separated by a comma and space, and name the column Employee and Title. 6) Display department numbers and names from department table. 7) Retrieve the list of employees names, employee ID, job and salary from EMP table. 8) Retrieve the list of names, jobs with “Designation” heading , salary with “Basic Salary” heading from EMP table. 9) List out the names of all Tables. 10) Display employee name, job, 8% on sal as bonus , 9.75% on salary as DA. 11) Display employee name, job, hiredate, salary, 9.25% on salary as Income Tax and Net Salary ( salary – Tax ). 12) Display employee name, salary, 8% on salary as bonus and 2% as Tax on (salary + bonus). 13) Display the following formats a) {ename} working as a {job} with basic salary {sal} b) {ename} working in {deptno} department as a {job} with basic {sal} c) The employee {ename}({job}) paying Income Tax {sal*9.75/100}

14) Produce the following output. EMPLOYEE ---------------- SMITH(Clerk) ALLEN(Salesman) WARD(Salesman) JONES(Manager) MARTIN(Salesman) and so on……………… 15) Display all employees who were hired during 1983. 16) Display details who are working in the departments 10, 20 as a MANAGER. 17) Develop a query that will accept a given job name. Execute the query a number of times to test. 18) Display the name, job, salary and bonus (8 % of salary) with “BONUS” heading and output should be in the order of bonus. 19) Display employees details who are not getting commission. Write queries in possible methods. 20) Display details whose employee name contain ‘E’ as a second character from end of the string. 21) Display details whose employee name contain “S” or “s”. 22) Display employee name, job, salary, commission and total salary (sal + comm) with ordering highest total salary first. 23) Find the most recently hired employees in each department. 24) Show all data of the clerks who have been hired after the year 1997. 25) Show the last name, job, salary, and commission of those employees who earn commission. Sort the data by the salary in descending order. 26) Show the employees that have no commission with a 10% raise in their salary (round off the salaries). 27) Show those employees that have a name starting with J, K, L, or M.

Day 2 1)