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of 7
MINOLOGY
source
1sion
e-throw ,Je-throw
)City
d
ments that
mected in
PROBLEMS
Figure Pl.S: Circuit for Problem 1.5.
1.6 For the circuit in Fig. P1.6: (a) Identify and label all distinct nodes. (b) Which of those nodes are extraordinary nodes? (c) Identify all combinations of2 or more circuit elements that
are connected in series. (d) Identify pairs of circuit elements that are connected in
parallel.
Figure P1.6: Circuit for Problem 1.6.
1.7 For the circuit in Fig. P1.7:
(a) Identify and label all distinct nodes. (b) Which of those nodes are extraordinary nodes? (c) Identify all combinations of 2 or more circuit elements that
are connected in series. (d) Identify pairs of circuit elements that are connected in
parallel.
lQ
4V +
Figure P1.7: Circuit for Problem 1.7.
43
1.8 For the circuit in Fig. Pl.S: (a) Identify and label all distinct nodes. (b) Which of those nodes are extraordinary nodes? (c) Identify all combinations of2 or more circuit elements that
are connected in series. (d) Identify pairs of circuit elements that are connected in
parallel.
25 n
60Q
15 n
Figure Pl.8: Circuit for Problem 1.8.
1.9 For the circuit in Fig. P1.9: (a) Identify and label all distinct nodes. (b) Which of those nodes are extraordinary nodes? (c) Identify all combinations of2 or more circuit elements that
are connected in series. (d) Identify pairs of circuit elements that are connected in
parallel.
4A
2Q 4Q
Figure Pl.9: Circuit for Problem 1.9.
1.10 For the circuit in Fig. PLIO: (a) Identify and label all distinct nodes . (b) Which of those nodes are extraordinary nodes? (c) Identify all combinations of2 or more circuit elements that
are connected in series.
4 4
( d ) I d e n t i f y p a i r s o f c i r c u i t e l e m e n t s t h a t a r e c o n n e c t e d i n
p a r a l l e l .
8 Q
1 2 V ( T } 4Q~ ""'-16Q~ 6 Q
F i g u r e P l . l O : C i r c u i t f o r P r o b l e m 1 . 1 0 .
1 . 1 1 F o r t h e c i r c u i t i n F i g . P l . l l :
( a ) I d e n t i f y a n d l a b e l a l l d i s t i n c t n o d e s .
( b ) W h i c h o f t h o s e n o d e s a r e e x t r a o r d i n a r y n o d e s ?
( c ) I d e n t i f y a l l c o m b i n a t i o n s o f 2 o r m o r e c i r c u i t e l e m e n t s t h a t
a r e c o n n e c t e d i n s e r i e s .
( d ) I d e n t i f y p a i r s o f c i r c u i t e l e m e n t s t h a t a r e c o n n e c t e d i n
p a r a l l e l .
F i g u r e P l . l l : C i r c u i t f o r P r o b l e m 1 . 1 1 .
1 . 1 2 T h e t o t a l c h a r g e c o n t a i n e d i n a c e r t a i n r e g i o n o f s p a c e
i s - 1 C . I f t h a t r e g i o n c o n t a i n s o n l y e l e c t r o n s , h o w m a n y d o e s
i t c o n t a i n ?
* 1 . 1 3 A c e r t a i n c r o s s s e c t i o n l i e s i n t h e x - y p l a n e . I f 3 x 1 0
2 0
e l e c t r o n s g o t h r o u g h t h e c r o s s s e c t i o n i n t h e z d i r e c t i o n i n 4
s e c o n d s , a n d s i m u l t a n e o u s l y 1 . 5 x 1 0
2 0
p r o t o n s g o t h r o u g h
t h e s a m e c r o s s s e c t i o n i n t h e n e g a t i v e z d i r e c t i o n , w h a t i s t h e
m a g n i t u d e a n d d i r e c t i o n o f t h e c u r r e n t f l o w i n g t h r o u g h t h e c r o s s
s e c t i o n ?
1 . 1 4 D e t e r m i n e t h e c u r r e n t i ( t ) f l o w i n g t h r o u g h a r e s i s t o r i f
t h e c u m u l a t i v e c h a r g e t h a t h a s f l o w e d t h r o u g h i t u p t o t i m e t i s
g i v e n b y
C H A P T E R 1 C I R C U I T T E R M I N O L O G Y
( a ) q ( t ) = 3 . 6 t m C
( b ) q ( t ) = 5 s i n ( 3 7 7 t ) p . , C
* ( c ) q ( t ) = 0 . 3 [ 1 - e -
0
. 4
1
] p C
( d ) q ( t ) = 0 . 2 t s i n ( l 2 0 7 r t ) n C
1 . 1 5 D e t e r m i n e t h e c u r r e n t i ( t ) f l o w i n g t h r o u g h a c e r t a i n
d e v i c e i f t h e c u m u l a t i v e c h a r g e t h a t h a s f l o w e d t h r o u g h i t u p t o
t i m e t i s g i v e n b y
( a ) q ( t ) = - 0 . 4 5 t
3
p . , C
( b ) q ( t ) = 1 2 s i n
2
( 8 0 0 m ) m C
( c ) q ( t ) = - 3 . 2 s i n ( 3 7 7 t ) c o s ( 3 7 7 t ) p C
* ( d ) q ( t ) = 1 . 7 t [ l - e - 1 .
2 1
] n C
1 . 1 6 D e t e r m i n e t h e n e t c h a r g e 1 1 Q t h a t f l o w e d t h r o u g h a
r e s i s t o r o v e r t h e s p e c i f i e d t i m e i n t e r v a l f o r e a c h o f t h e f o l l o w i n g
c u r r e n t s :
( a ) i ( t ) = 0 . 3 6 A , f r o m t = 0 t o t = 3 s
* ( b ) i ( t ) = [ 4 0 t + 8 ] r n A , f r o m t = 1 s t o t = 1 2 s
( c ) i ( t ) = 5 s i n ( 4 7 r t ) n A , f r o m t = 0 t o t = 0 . 0 5 s
( d ) i ( t ) = 1 2 e -
0
3 1
r n A , f r o m t = 0 t o t = o o
1 . 1 7 D e t e r m i n e t h e n e t c h a r g e 1 1 Q t h a t f l o w e d t h r o u g h a
c e r t a i n d e v i c e o v e r t h e s p e c i f i e d t i m e i n t e r v a l s f o r e a c h o f t h e
f o l l o w i n g c u r r e n t s :
( a ) i ( t ) = [ 3 t + 6 t
3
] r n A , f r o m t = 0 t o t = 4 s
* ( b ) i ( t ) = 4 s i n ( 4 0 7 r t ) c o s ( 4 0 7 r t ) p . , A , f r o m t = 0 t o
t = 0 . 0 5 s
( c ) i ( t ) = [ 4 e - t - 3 e -
2 1
] A , f r o m t = 0 t o t = o o
( d ) i ( t ) = 1 2 e -
3 1
c o s ( 4 0 7 r t ) n A , f r o m t = 0 t o t = 0 . 0 5 s
1 . 1 8 I f t h e c u r r e n t f l o w i n g t h r o u g h a w i r e i s g i v e n b y
i ( t ) = 3 e -
0
1 1
r n A , h o w m a n y e l e c t r o n s p a s s t h r o u g h t h e w i r e ' s
c r o s s s e c t i o n o v e r t h e t i m e i n t e r v a l f r o m t = 0 t o t = 0 . 3 m s ?
1 . 1 9 T h e c u m u l a t i v e c h a r g e i n m C t h a t e n t e r e d a c e r t a i n
d e v i c e i s g i v e n b y
q ( t ) = ~~t
6 0 - t
f o r t < 0 ,
f o r 0 : : : : t : : : : 1 0 s ,
f o r 1 0 s : : : : t : : : : 6 0 s
( a ) P l o t q ( t ) v e r s u s t f r o m t = 0 t o t = 6 0 s .
( b ) P l o t t h e c o r r e s p o n d i n g c u r r e n t i ( t ) e n t e r i n g t h e d e v i c e .
* 1 . 2 0 A s t e a d y f l o w r e s u l t e d i n 3 x 1 0
1 5
e l e c t r o n s e n t e r i n g a
d e v i c e i n 0 . 1 m s . W h a t i s t h e c u r r e n t ?
P R O
1 . 2 1
g i v e n
( a ) ,
( b )
1 . 2 2
o f c h
-OGY
!rtain up to
~h a 1ing
1 a
the
to
'Y 's
?
n
PROBLEMS
1.21 Given that the current in (rnA) flowing through a wire is given by:
i (t) = 6t for 0 _:::: t _:::: 5 s 10 fort < 0
30e-06
4 6
v
3
= 6 V
R 2 I I
1 0 v { : )
I ~
R ,
I
V
2
= 4 V
I
2 o v { )
J
I I
R 3
v
4
= 1 2 v
F i g u r e P 1 . 2 6 : q ( t ) f o r P r o b l e m 1 . 2 6 .
1 . 2 7 F o r e a c h o f t h e e i g h t d e v i c e s i n t h e c i r c u i t o f F i g . P 1 . 2 7 ,
d e t e r m i n e w h e t h e r t h e d e v i c e i s a s u p p l i e r o r a r e c i p i e n t o f
p o w e r a n d h o w m u c h p o w e r i t i s s u p p l y i n g o r r e c e i v i n g .
+ 6 V -
2
+
l O Y 1 3
6
+ 1 2 V -
- 7 V +
8
F i g u r e P 1 . 2 7 : C i r c u i t f o r P r o b l e m 1 . 2 7 .
3 A +
9 V I 7
+
1 . 2 8 F o r e a c h o f t h e s e v e n d e v i c e s i n t h e c i r c u i t o f F i g . P 1 . 2 8 ,
d e t e r m i n e w h e t h e r t h e d e v i c e i s a s u p p l i e r o r a r e c i p i e n t o f
p o w e r a n d h o w m u c h p o w e r i t i s s u p p l y i n g o r r e c e i v i n g .
* 1 . 2 9 A n e l e c t r i c o v e n o p e r a t e s a t 1 2 0 V . I f i t s p o w e r r a t i n g i s
0 . 6 k W , w h a t a m o u n t o f c u r r e n t d o e s i t d r a w , a n d h o w m u c h
e n e r g y d o e s i t c o n s u m e i n 1 2 m i n u t e s o f o p e r a t i o n ?
1 . 3 0 A 9 V f l a s h l i g h t b a t t e r y h a s a r a t i n g o f 1 . 8 k W h . I f
t h e b u l b d r a w s a c u r r e n t o f 1 0 0 r n A w h e n l i t ; d e t e r m i n e t h e
f o l l o w i n g :
( a ) F o r h o w l o n g w i l l t h e f l a s h l i g h t p r o v i d e i l l u m i n a t i o n ?
I
I
I
I
C H A P T E R 1 C I R C U I T T E R M I N O L O G Y
+ 6 V -
I
~
s A t
+
2 4 v
I
X~'\
/ " _ X
F i g u r e P 1 . 2 8 : C i r c u i t f o r P r o b l e m 1 . 2 8 .
( b ) H o w m u c h e n e r g y i n j o u l e s i s c o n t a i n e d i n t h e b a t t e r y ?
( c ) W h a t i s t h e b a t t e r y ' s r a t i n g i n a m p e r e - h o u r s ?
I ~
1 . 3 1 T h e v o l t a g e a c r o s s a n d c u r r e n t t h r o u g h a c e r t a i n d e v i c e
a r e g i v e n b y
v ( t ) = 5 c o s ( 4 n t ) V ,
i ( t ) = 0 . 1 c o s ( 4 n t ) A .
D e t e r m i n e :
* ( a ) T h e i n s t a n t a n e o u s p o w e r p ( t ) a t t = 0 a n d t = 0 . 2 5 s .
( b ) T h e a v e r a g e p o w e r P a v . d e f i n e d a s t h e a v e r a g e v a l u e o f
p ( t ) o v e r a f u l l t i m e p e r i o d o f t h e c o s i n e f u n c t i o n ( 0 t o
0 . 5 s ) .
1 . 3 2 T h e v o l t a g e a c r o s s a n d c u r r e n t t h r o u g h a c e r t a i n d e v i c e
a r e g i v e n b y
v ( t ) = 1 0 0 ( 1 - e -
0
-
2 1
) V ,
i ( t ) = 3 0 e -
0 2 1
r n A .
D e t e r m i n e :
( a ) T h e i n s t a n t a n e o u s p o w e r p ( t ) a t t = 0 a n d t = 3 s .
( b ) T h e c u m u l a t i v e e n e r g y d e l i v e r e d t o t h e d e v i c e f r o m t = 0
t o t = o o .
1 . 3 3 T h e v o l t a g e a c r o s s a d e v i c e a n d t h e c u r r e n t t h r o u g h i t
a r e s h o w n g r a p h i c a l l y i n F i g . P 1 . 3 3 . S k e t c h t h e c o r r e s p o n d i n g
p o w e r d e l i v e r e d t o t h e d e v i c e a n d c a l c u l a t e t h e e n e r g y a b s o r b e d
b y i t .
1 . 3 4 T h e v o l t a g e a c r o s s a d e v i c e a n d t h e c u r r e n t t h r o u g h i t
a r e s h o w n g r a p h i c a l l y i n F i g . P 1 . 3 4 . S k e t c h t h e c o r r e s p o n d i n g
p o w e r d e l i v e r e d t o t h e d e v i c e a n d c a l c u l a t e t h e e n e r g y a b s o r b e d
b y i t .
I
5
IVE CIRCUITS
ill 10 em
m
:50
50
PROBLEMS 103
what fraction of the power generated by the generating station *2.15 Determine Ix in the circuit of Fig. P2.15. is used by the city.
RL (city)
Figure P2.12: Diagram for Problem 2.12.
2.13 Determine the current I in the circuit of Fig. P2.13 given that Io = 0.
3Q
24 v +
Figure P2.13: Circuit for Problem 2.13.
2.14 Determine currents I 1 to I3 in the circuit of Fig. P2.14.
IA
2Q
70
Figure P2.14: Circuit for Problem 2.14.
Figure P2.15: Circuit for Problem 2.15 .
2.16 Determine currents It to I4 in the circuit of Fig. P2.16.
5V
Figure P2.16: Circuit for Problem 2.16.
*2.17 Determine currents I 1 to !4 in the circuit of Fig. P2.17.
6A
Figure P2.17: Circuit for Problem 2.17.
2.18 Determine the amount of power dissipated in the 3 kQ resistor in the circuit of Fig. P2.18.
Figure P2,18: Circuit for Pro~lem 2.18.
1 0 4
* 2 . 1 9
D e t e r m i n e f x a n d f y i n t h e c i r c u i t o f F i g . P 2 . 1 9 .
2 Q
1
x 6 n I y
.---~NV' ~ N V ' . . . . . . . . .
w v e ! ) f n ~4I,
F i g u r e P 2 . 1 9 : C i r c u i t f o r P r o b l e m 2 . 1 9 .
2 . 2 0 F i n d V a b i n t h e c i r c u i t o f F i g . P 2 . 2 0 .
2 Q
a
+
V a b
b
F i g u r e P 2 . 2 0 : C i r c u i t f o r P r o b l e m 2 . 2 0 .
2 . 2 1 F i n d /
1
t o f ) i n t h e c i r c u i t o f F i g . P 2 . 2 1 .
8 V
!
1
! 3
3 k Q - - - +
~
~h
4 k Q
2 k Q
F i g u r e P 2 . 2 1 : C i r c u i t f o r P r o b l e m 2 . 2 1 .
2 . 2 2 F i n d I i n t h e c i r c u i t o f F i g . P 2 . 2 2 .
~ ~~----~
l O V e ! ) ~30
F i g u r e P 2 . 2 2 : C i r c u i t f o r P r o b l e m 2 . 2 2 .
* 2 . 2 3 D e t e r m i n e t h e a m o u n t o f p o w e r s u p p l i e d b y t h e
i n d e p e n d e n t c u r r e n t s o u r c e i n t h e c i r c u i t o f F i g . P 2 . 2 3 .
C H A P T E R 2 R E S I S T I V E C I R C U I T S
02A~ ~~~:~ f~l
F i g u r e P 2 . 2 3 : C i r c u i t f o r P r o b l e m 2 . 2 3 .
2 . 2 4 G i v e n t h a t i n t h e c i r c u i t o f F i g . P 2 . 2 4 , /
1
= 4 A
/ 2 = I A , a n d / 3 = 1 A , d e t e r m i n e n o d e v o l t a g e s v , , V 2 , a n d V J
I
1
. . 1 . . - R , = 1 8 n
- -
-
! 3
F i g u r e P 2 . 2 4 : C i r c u i t f o r P r o b l e m 2 . 2 4 .
v3
1 8 n
* 2 . 2 5 A f t e r a s s i g n i n g n o d e V 4 i n t h e c i r c u i t o f F i g . P 2 . 2 5 i l l
t h e g r o u n d n o d e , d e t e r m i n e n o d e v o l t a g e s v , , V 2 , a n d V 3 .
3 A
1 2 v
- -
_ _ _ , L N V ' ! V 3
v , ; N V ' ' 6 n
-
l A
V 4
6 Q
-
l A
F i g u r e P 2 . 2 5 : C i r c u i t f o r P r o b l e m s 2 . 2 5 a n d 2 . 2 6 .
2 . 2 6 A f t e r a s s i g n i n g n o d e V
1
i n t h e c i r c u i t o f F i g . P 2 . 2 5 a '
t h e g r o u n d n o d e , d e t e r m i n e n o d e v o l t a g e s V 2 , V 3 , a n d V 4 .
2 . 2 7 I n t h e c i r c u i t o f F i g . P 2 . 2 7 , / 1 = 4 2 / 8 1 A
/ 2 = 4 2 / 8 1 A , a n d / 3 = 2 4 / 8 1 A . D e t e r m i n e n o d e voltag~
V 2 , V 3 , a n d V 4 a f t e r a s s i g n i n g n o d e v , a s t h e g r o u n d n o d e .
P R O B L E M S
V J E I
9 0 h
-
p o w e r .
S e c t i o n 2 - 3 :
2 . 2 9 G i v e n l
d e t e r m i n e I o .
I o
2 . 3 0 W h a t
R e q = 4 Q ?
a
R e q
b
I i l l
1 0 6
2 . 3 5 I f R = 1 2 r . ! i n t h e c i r c u i t o f F i g . P 2 . 3 S , f i n d I .
F i g u r e P 2 . 3 5 : C i r c u i t f o r P r o b l e m 2 . 3 5 .
* 2 . 3 6 U s e r e s i s t a n c e r e d u c t i o n a n d s o u r c e t r a n s f o r m a t i o n t o
f i n d V x i n t h e c i r c u i t o f F i g . P 2 . 3 6 . A l l r e s i s t a n c e v a l u e s a r e i n
o h m s .
4 + V : y -
~....----16 - - - - . . F v i 1 2 ( ! ) 1 o A i 6 ~'---r6 i - - - - - , 1 6 }
F i g u r e P 2 . 3 6 : C i r c u i t f o r P r o b l e m 2 . 3 6 .
2 . 3 7 D e t e r m i n e A i f V o u t ! V
5
= 9 i n t h e c i r c u i t o f F i g . P 2 . 3 7 .
3 0
1 2 Q
p ,
1 2 0
3 0
F i g u r e P 2 . 3 7 : C i r c u i t f o r P r o b l e m 2 . 3 7 .
+
6 0 V o u t
* 2 . 3 8 F o r t h e c i r c u i t i n F i g . P 2 . 3 8 , f i n d R e q a t t e r m i n a l s ( a , b ) .
~0-------r---NV------;----vvv-~ c
3 0 5 0
I b e 6 0 3 0 d
L F i g u r e P 2 . 3 8 : C i r c u i t f o r P r o b l e m s 2 . 3 8 a n d 2 . 3 9 .
C H A P T E R 2 R E S I S T I V E C I R C U I
2 . 3 9 F i n d R e q a t t e r m i n a l s ( c , d ) i n t h e c i r c u i t o f F i g . P 2
2 . 4 0 S i m p l i f y t h e c i r c u i t t o t h e r i g h t o f t e r m i n a l s ( a , b )
F i g . P 2 . 4 0 t o f i n d R e q . a n d t h e n d e t e r m i n e t h e a m o u n t ofpo~
s u p p l i e d b y t h e v o l t a g e s o u r c e . A l l r e s i s t a n c e s a r e i n o h m s .
a
b
F i g u r e P 2 . 4 0 : C i r c u i t f o r P r o b l e m 2 . 4 0 .
2 . 4 1 F o r t h e c i r c u i t i n F i g . P 2 . 4 1 , d e t e r m i n e R e q a t
* ( a ) T e r m i n a l s ( a , b )
( b ) T e r m i n a l s ( a , c )
( c ) T e r m i n a l s ( a , d )
( d ) T e r m i n a l s ( a , f )
I
2 0
d o - A N I - A N I
2 0
c o - A N I - A N I
F i g u r e P 2 . 4 1 : C i r c u i t f o r P r o b l e m 2 . 4 1 .
I
2 0
2 0
2 0
b
2 . 4 2 F i n d R e q f o r t h e c i r c u i t i n F i g . P 2 . 4 2 . A l l r e s i s t a n c e s a r c
i n o h m s .
R , q - : ~ 10~
5 1 0
F i g u r e P 2 . 4 2 : C i r c u i t f o r P r o b l e m 2 . 4 2 .
2 . 4 3
t h e c
2 . 4 4
t o
i n t o
( a ,