CONFIDENTIAL
2
NO. MARKING SCHEME
PAPER 2 (SECTION A)
MARK
SUB TOTAL
1
(a) (i)
(ii)
(iii)
M : soap
N : detergent
Cleansing agent Observation
M Oily stain remain //Cloth is still dirty
N No oily stain // Cloth is clean
N / Detergent
1
1
1
1
1
2
2
1
(b)(i)
(ii)
(iii)
P : Aspirin/ paracetamol/ codeine
Q : Antibiotic
To relieve/ reduce pain // as pain killer
[r: to cure pain]
To make sure all the bacteria are killed//bacteria become
immune/resistant to the given medicine
[r: virus/ microorganism/ germs/ fungi]
1
1
1
1
2
2
TOTAL 9
SKEMA MRSM2014
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CONFIDENTIAL
3
NO. MARKING SCHEME MARK
SUB TOTAL
2(a) Na / Mg / Al 1 1
(b) 2.8 / 2,8
[r : 2:8]
1 1
(c)(i)
(ii)
(iii)
Forces of attraction between nucleus and electrons is stronger in
chlorine atom // nuclei attraction towards electron is stronger in
chlorine atom
[r: is higher]
1. Correct number of electrons and shell with nucleus
2. Label the charge and symbol of atom (can infer from nucleus)
Ionic compound
[a : ionic]
[r : ionic bond]
1
1
1
1
1
2
1
(d) Semiconductor// to produce microchips// to make concrete /
cement / ceramic/ pottery/ enamels
1 1
(e) (i)
(ii)
Chemically inert // argon atom achieves stable octet electron
arrangement
Volume of argon gas = 0.002 x 24 / / 0.048 dm3 / / 48 cm3
1
1
2
TOTAL 9
CONFIDENTIAL
4
NO. MARKING SCHEME MARK
SUB TOTAL
3(a) Ionic compound/substance that can conduct electricity in molten
state or aqueous solution and undergoes chemical changes.
1 1
(b) K + , I- , H+ ,OH- 1 1
(c) (i)
(ii)
Iodide ion and hydroxide ion
2I- → I2 + 2e
1
1
2
(d) (i)
(ii)
(Colourless) gas bubbles releases
1. H+ ion is lower than K+ ion in the Electrochemical Series 2. H+ ion will be selectively discharged to form hydrogen
gas
1
1
1
1
2
(e) (i)
(ii)
Oxygen
1. No of mole = 24 / 24000 = 0.001 mol
2. No of molecule = 0.001 x 6.02 x 1023 = 6.02 x 1020
1
1
1
1
2
TOTAL 10
CONFIDENTIAL
5
NO. MARKING SCHEME MARK
SUB TOTAL
4(a)(i)
(ii)
(iii)
(iv)
Copper(II) oxide
[a: copper oxide]
Green
Sodium carbonate / potassium carbonate/ ammonium carbonate
[a : formula]
Na2CO3 + Cu (NO3)2 → CuCO3 + 2 NaNO3
[based on answer in a(iii)]
1. Correct formulae of reactants and products
2. Balanced equation
1
1
1
1
1
3
2
(b)
(c)
1. Blue precipitate 2. Dissolves in excess ammonia solution
1. Add 2 cm3 dilute sulphuric acid followed by 2 cm3 of iron ( II) sulphate solution and shake
2. Concentrated sulphuric acid is added slowly/drop by drop 3. Brown ring is formed
1
1
1
1
1
2
3
TOTAL 10
CONFIDENTIAL
6
No. MARKING SCHEME MARK
SUB TOTAL
5(a)
Volume of gas liberated // Mass of calcium carbonate 1
1
(b) (i)
(ii)
(iii)
(iv)
(v)
No of mole = 25 x 0.1 / 1000 = 0.0025 mol
1. 0.0025 mol HNO3 produce 0.00125 mol CO2
2. Volume of CO2 = 0.00125 x 24
= 0.03 dm3
Note : 1. [ecf from (b)(i)]
2. Point 2 must be correct with unit
1. Correct curves with label 2. Axis with label & units
1. Rate of reaction of Exp II is higher than Exp I
1. Exp II has higher temperature than Exp. I 2. Kinetic energy of particles is higher. 3. Frequency of collision between H + and CaCO3 / CO32-
is higher
4. Frequency of effective collision is higher
1
1
1
1
1
1
1
1
1
1
3
2
1
4
TOTAL 11
30 cm3
Volume of gas/ cm3
Isipadu gas / cm3
Time/ s
Masa /s
II
III
I
CONFIDENTIAL
7
NO MARKING SCHEME MARK
SUB TOTAL
6 (a) To allow the movement of ions 1 1
(b)
Shown in the diagram (from electrode L to electrode M
through external circuit).
[r: answers in words]
1 1
(c) (i)
(ii)
Iron(III) ion / Ferum(III) ion / Iron(III) sulphate
[r: formula]
1
3
Alternative 1
1. Add sodium hydroxide/ammonia solution.
2. Brown precipitate is formed.
Alternative 2
1. Add potassium hexacyanoferrate(II) solution.
2. Dark blue precipitate is formed.
Alternative 3
1. Add potassium thiocyanate solution.
2. Blood red colouration is formed.
1
1
(d) Br2 + 2e 2Br-
1 3
(e) 1. Orange solution turns green
2. Cr2O72- ion undergoes reduction to form Cr3+ ion
1
1
(f)
Functional apparatus
Label apparatus and material
Label positive and negative terminal
1
1
1
3
TOTAL 11
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CONFIDENTIAL
8
NO MARKING SCHEME SUB
MARK
TOTAL
MARKS
7(a) (i)
(ii)
P1. Empirical formula is (chemical) formula that shows the
simplest ratio of hydrogen and carbon atoms in benzene //
Formula that shows the simplest ratio of hydrogen to
carbon atoms in benzene is 1:1
P2. Molecular formula is (chemical) formula that shows the
actual number of hydrogen and carbon atoms in benzene//
Formula that shows the actual number of atoms which are
6 hydrogen and 6 carbon in benzene.
1
1 4
ethanol,C2H5OH // water,H2O // magnesium oxide, MgO
[a: any compound where its empirical formula and molecular
formula is the same]
1+1
(b) (i)
(ii)
Empirical formula of the compound is CH3
[CH3]n = 30
[12+3(1)]n = 30
n = 2
Molecular formula of the compound is C2H6
C2H6 + 7/2 O2 2CO2 + 3H2O
Correct formula of reactants and products
Balanced equation
Element C H
Number of mole 80/12 = 6.67 20/1 = 20
Simplest ratio of
moles
6.67/6.67 = 1 20/6.67 = 3
1
1
1
1
1
Max 4
1+1
6
(c) (i)
(ii)
Hydrocarbon Homologous
series
General
formula Name
E alkane CnH2n+2
n=1,2.. butane
J alkene CnH2n
n = 2,3,… But-2-ene
3
3
6
P1. J produces more soot than E.
P2 & P3. Calculation
E J
% of carbon
4(12) x 100 = 82.76
58
4(12) x 100 = 85.71
56
% of carbon by mass in J is higher than E
1
1+1
1
4
TOTAL 20
CONFIDENTIAL
9
NO EXPLANATION SUB
MARK
TOTAL
MARKS
8 (a) (i)
(ii)
Substance P Q
Name Bronze Borosilicate glass
Specific
properties
Shiny surface //
Does not corrode
easily//hard and
strong
Withstand high
temperature//
Resistant to chemicals
//low thermal
expansion
1+1
1+1
4
P1& P2. Diagram
tin
Pure copper
copper
Alloy P
P3. Alloy P/bronze is harder than pure copper
P4. Atomic size in pure copper is the same , atomic size in
alloy P/bronze is different.
P5. Atoms in pure copper are orderly arranged while atoms in
alloy P/bronze are not orderly arranged.
P6. When force is applied, layer of atoms in pure copper is
easier to slide than in alloy P/ bronze.
1+1
1
1
1
1
6
(b) (i)
(ii)
(iii)
P1. Sulphur dioxide burnt/react with excess oxygen to produce
sulphur trioxide.
P2. Passed over vanadium(V) oxide catalyst at 450oC, 1 atm
P3. Chemical equation : 2SO2 + O2 2SO3
1
1
1
1
1
1
1
3
4
P1. Step 1: Sulphur trioxide is dissolved in concentrated
sulphuric acid to form oleum.
P2. SO3 + H2SO4 H2S2O7
P3. Step 2: Oleum is diluted with water to produce sulphuric
acid.
P4. H2S2O7 + H2O 2H2SO4
P1. Moles of S = 48 / 32 =1.5 mol
P2. 1 mol of S produce 1 mol SO2
Thus, 1.5 mol of S produce 1.5 mol SO2
P3.Volume of SO2 = 1.5 24 dm3 = 36 dm3
1
1
1
3
TOTAL 20
CONFIDENTIAL
10
NO EXPLANATION MARK ∑ MARKS
9 (a) (i) P1.Correct suggestion for solution T
Eg. Copper (II) sulphate solution /
Sodium chloride/ zinc sulphate solution /
sulphuric acid
P2. Correct suggestion for solution V
Eg. Glucose solution/benzene/ ethanol/methylbenzene
P3. Solution T has free moving ions.
P4. Solution V is made up of neutral molecules//
does not have free moving ions
1
1
1
1
4
(ii) P1. Zinc is more electropositive than copper.
P2. Zinc atom releases electron to form zinc ion Zn2+
P3. Half equation: Zn Zn2+ + 2e
P4. Electrons flow through external circuit to the copper
electrode
If T is copper(II) sulphate solution
P5. Copper(II) ion receives electron to form
copper atom
P6. Half equation: Cu2+ + 2e Cu
OR
If T is sodium chloride solution / sulphuric acid
P5. Hydrogen ion receives electron to form hydrogen
P6. Half equation: 2H+ + 2e H2
1
1
1
1
1
1
6
(b) P1. Materials : 2.0 mol dm-3 sodium hydroxide,
distilled water
P2. Apparatus : volumetric flask100 cm3, pipette 25 cm3,
[note : P1 & P2 can be inferred from procedure]
Calculation :
M1V1 = M2V2
P3. 2.0 x V1 = 0.5 x 100
P4. V1 = 25 cm3
Procedure :
P5. Pipette 25 cm3 2.0 mol dm-3 of sodium hydroxide
solution.
P6. Transfer the solution into a volumetric flask.
P7. Add distilled water into the volumetric flask.
P8. until reaches the calibration mark.
P9. Close/ Put stopper on the volumetric flask.
P10.Shake the volumetric flask.
1
1
1
1
1
1
1
1
1
1
10
TOTAL 20
CONFIDENTIAL
11
NO EXPLANATION MARK ∑ MARKS
10
(a)(i)
P1. L : Mg / Magnesium
P2. R : Zn / Zinc
[Note : 1. L must be more electropositive than R
2. Both L and R must be more electropositive than Cu]
P3. The heat of displacement for Experiment I is
higher than Experiment II.
P4. The distance between L / Cu is bigger/ further in the
Electrochemical Series // L is more electropositive
than R
1
1
1
1
4
(ii) Mg + CuSO4 MgSO4 + Cu P1. Correct chemical formula of reactant and product
P2. Balance chemical equation.
[adp metal L but should be more electropositive than Cu ]
P3. Number of mole of CuSO4 = 0.2 x 50 // 0.01
1000
P4. 1 mol of Cu displaced release 336000 J heat
P5. .: 0.01 mol of Cu 336000 J x 0.01 mol heat
1 mol
= 3360 J
P6. Change in temperature = 3360
50 X 4.2
= 16 oC
[ecf P5 from P3]
1+1
1
1
1
1
6
(b) P1. Apparatus: Polystyrene cup , thermometer,
measuring cylinder ( suitable volume)
P2. Materials : [suitable salt solutions to produce
precipitate/any insoluble salt]
Eg. Lead(II) nitrate solution, sodium
sulphate solution
Procedure:
P3. Measure [25-200] cm3 of [0.1-2.0] mol dm-3 lead(II)
nitrate solution.
P4. Pour into a polystyrene cup.
P5. Measure [25-200] cm3 of [0.1-2.0] mol dm-3 sodium
sulphate solution.
P6. Pour into a different polystyrene cup.
P7. Measure the initial temperature of both solutions.
P8. Pour sodium sulphate solution quickly into lead(II)
nitrate solution.[a: vice versa]
P9. Stir the mixture.
P10. Record the highest temperature.[r: final temperature]
1
1
1
1
1
1
1
1
1
1
10
TOTAL 20
4541/3 SULIT
3
QUESTION 1 (18 marks)
Question Mark Scheme Mark
1 (a)
[Able to record all the initial and final readings of the titration
accurately in 2 decimal places].
Answer:
Titration
I
Titration
II
Titration
III
Initial 0.10 24.90
1.00
Final 24.90 49.50
25.70
3
[Able to record (any five of the initial and final readings of the
titration accurately) // (six readings in one decimal place)]
2
[Able to record (any four of the initial and final readings of the
titration accurately) // (six readings with no decimal place)] 1
No response or wrong response 0
Question Mark Scheme Mark
1 (b)
[Able to construct a table with correct headings and units to
record the initial and final readings of the titration ]
Answer:
Titration I II III
Final reading of burette /cm3 24.90 49.50
25.70
Initial reading of burette /cm3 0.10 24.90
1.00
Volume of hydrochloric acid /cm3 24.80 24.60 24.70
3
[Able to construct a table that contains the following]
1. Title without unit
2. Reading
[Note: 1. If data in 1(a) not accurate/incorrect, maximum score 2]
2
[Able to construct a table that contains the following ]
1. at least one title with one set of reading
1
No response or wrong response 0
SKEMA MRSM2014
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4541/3 SULIT
4
Question Mark Scheme Mark
1 (c)(i)
[Able to show the calculation for the average volume (with
unit) of hydrochloric acid accurately with the answer given in
2 decimal places]
Answer : 24.80 + 24.60 + 24.70 = 24.70 cm3
3
3
[Able to show the calculation for the average volume (without
unit) of hydrochloric acid less accurately with the answer
given in 2 decimal places]
//[Able to show the volume (with unit) of hydrochloric acid
used without showing the calculation steps]
Sample answer :
1. 24.80 + 24.60 + 24.70 = 24.70
3
2. 24.70 cm3
3. 24.7 cm3
2
[Able to show the volume (without unit) of hydrochloric acid
used, without showing the calculation steps]
Sample answer : 24.7
1
No response or wrong response 0
Question Marc Scheme Mark
1 (c)(ii)
[Able to write chemical equation and calculate the
concentration of sodium hydroxide with units accurately]
Answer :
P1. HCl + NaOH NaCl + H2O
P2. Number of mole of NaOH = number of mole of HCl
= 0.1 x 24.7 = 0.00247 mol
1000
P3. Concentration of NaOH = 0.00247 mol = 0.0988 mol dm-3
0.025 dm3
[a: P2 = 0.0025 mol , P3 = 0.1 mol dm-3]
3
[Able to state any two steps correctly]
Note : [ecf number of mole from P2]
2
[Able to state any step correctly] 1
No response or wrong response 0
4541/3 SULIT
5
Question Mark Scheme Mark
1(d)
[Able to predict the volume of sulphuric acid accurately to
2 decimal places with unit and explain correctly]
Answer :
P1. 12.35 cm3
P2. Hydrochloric acid is a monoprotic/monobasic acid while
sulphuric acid is a diprotic/dibasic acid
P3. The concentration of H+ ions in sulphuric acid is twice the
concentration of H+ ions in hydrochloric acid
3
[Able to predict the volume of sulphuric acid without unit and
state any step P2/P3 correctly] 2
[Able to state P2 or /and P3 correctly] 1
No response or wrong response 0
Question Mark scheme Mark
1 (e)
[Able to classify all the 6 acids into strong acids and weak
acids correctly]
Answer :
Strong Acid Weak Acid
Nitric acid
Sulphuric acid
Hydrochloric acid
Methanoic acid
Ethanoic acid
Carbonic acid
3
[Able to classify at least four acids into strong acids and weak
acids correctly] 2
[Able to classify at least two of the acids into strong acids and
weak acids correctly// able to classify the two groups of acids
inaccurately]
Sample answer:
Strong Acid Weak Acid
Methanoic acid
Ethanoic acid
Carbonic acid
Nitric acid
Sulphuric acid
Hydrochloric acid
1
No response or wrong response 0
4541/3 SULIT
6
QUESTION 2 (15 MARKS)
Question Mark scheme Mark
2(a) [Able to state the inference for both experiments correctly]
Sample answer :
Rate of reaction of experiment II is higher//vice versa
// Reaction in Experiment II is faster // vice versa.
3
[Able to state the inference for both experiments less correctly]
Sample answer :
1. Rate of reaction of experiment II is faster// vice versa
2. Frequency of effective collision is higher in Experiment II//vice
versa
2
[Able to state an idea of inference]
Sample answer :
1. Rate of reaction is affected by the size.
2. Experiment II use smaller/ powdered marble chips // vice versa
3. Time taken for Experiment II is shorter // vice versa
1
No response given / wrong response. 0
Question Mark Scheme Mark
2(b) [Able to state all the three variables for both experiment correctly]
Sample answer:
P1. Manipulated variable : Size of marble chips // total surface
area of marble chips/ calcium
carbonate // large marble chips and
marble chips powder
P2. Responding variable : Rate of reaction// Time taken for a
10 cm3 carbon dioxide is collected.
P3. Constant variable : Volume and concentration of
hydrochloric acid //
Mass of marble chips /calcium
carbonate// Temperature
3
[Able to state any two variables correctly] 2
[Able to state any one variable correctly] 1
No response given / wrong response. 0
4541/3 SULIT
7
Question Mark Scheme Mark
2(c) [Able to state the hypothesis correctly by stating the two following
information]
Manipulated variable:
Size of calcium carbonate/marble chips//total surface area of calcium
carbonate/marble chips
Direction of responding variable:
Increase / Decrease in the rate of reaction
// Increase / Decrease in time taken for the reaction to be complete
Sample answer:
1. The smaller the size of calcium carbonate/marble chips, the higher
the rate of reaction//vice versa.
2. The larger the total surface area of calcium carbonate, the
higher the rate of reaction//vice versa.
3. When the size of calcium carbonate is smaller, the rate of
reaction increases// vice versa.
3
[Able to state the hypothesis less correctly by stating the relation
between the manipulated variable and the responding variable]
Sample answer:
1. The smaller the size of calcium carbonate/marble chips, the faster / slower the rate reaction.
2. The larger the total surface area of calcium carbonate/marble
chips, the faster / slower the rate reaction.
3. The smaller the size, the higher the rate of reaction
4. The rate of reaction is higher when the size of calcium
carbonate /marble chips is smaller
2
[Able to give an idea of the hypothesis]
Sample answer:
1.The size /total surface area affects / changes the rate of
reaction
2. Different size of calcium carbonate/marble chips , different rate of
reaction
1
No response given / wrong response. 0
4541/3 SULIT
8
Question Mark scheme Mark
2(d) [Able to give the operational definition for rate of reaction with the
following aspects:]
1. what you do
2. what you observe with direction
Sample answer:
1.When marble chips powder is reacted with hydrochloric acid, the
time taken to collect 10 cm3 /certain volume of gas is shorter //
2.When large marble chips is reacted with hydrochloric acid, the
time taken to collect 10 cm3 /certain volume of gas is longer
3
[Able to state the operational definition for rate of reaction
incompletely with any one of the following aspects]
1. what you do
2. what you observe with direction
Sample answer:
1. Marble chips powder/large marble chips is reacted with
hydrochloric acid //
2. Time taken to collect 10 cm3 /certain volume of gas in Experiment
II is shorter //
3. Time taken for a 10 cm3 /certain volume of gas collected when the Marble chips is reacted with hydrochloric acid //
4. The change of volume of gas per unit time
2
[Able to give an idea of operational definition for rate of reaction]
Sample answer:
The change of amount of reactant per time taken // rate of reaction is
influenced by the size of marble chips
// Rate of reaction = volume of gas
Time taken
1
No response given / wrong response. 0
4541/3 SULIT
9
Question Mark scheme Mark
2(e) [Able to state the relationship between temperature of surrounding
and the rate of drying clothes correctly].
Sample answers:
The higher the temperature of the surrounding, the higher the rate of
drying.//
The lower the temperature of the surrounding, the lower the rate of
drying.
3
[Able to state the relationship between temperature of surrounding
and the rate of drying clothes less correctly].
Sample answer:
The higher the temperature, the higher the rate of drying// vice versa
// The temperature is directly proportional to the rate of drying //
Clothes dry faster at higher temperature
2
[Able to give an idea of relationship between temperature of
surrounding and the rate of drying clothes].
Sample answer:
Different temperature, different rate of drying
//Temperature affect the rate of drying // Clothes dry at different
time at different temperature
1
No response given / wrong response 0
4541/3 SULIT
10
QUESTION 3 (17 MARKS)
Question Mark Scheme Mark
3 (a) [Able to give the problem statement correctly].
Sample answer:
How to differentiate hexane and hexene/ liquid P and liquid Q using
chemical test/bromine water/ acidified potassium manganate(VII)
solution?
Note: P and Q could be either hexane or hexene [vice versa]
3
[Able to give the problem statement incorrectly or able to give the
aim of experiment].
Sample answers :
1. How to differentiate hexane and hexene /liquid P and liquid Q?//
2. To differentiate between hexane and hexene/liquid P and liquid Q//
3. How to differentiate hexane and hexene/ liquid P and liquid Q
using chemical test/bromine water/ acidified potassium
manganate(VII) solution.//
4. How to identify hexane and hexene/ liquid P and liquid Q
using chemical test/bromine water/ acidified potassium
manganate(VII) solution?
2
[Able to give an idea of the problem statement]
Sample answer:
How to identify/determine/differentiate alkane and alkene /
To identify/determine/differentiate alkane and alkene.
Hexane and hexene can cause changes to bromine water/ acidified
potassium manganate(VII) solution
1
No response given or wrong response 0
Question Mark Scheme Mark
3(b) [Able to state the three variables correctly].
Sample answer:
P1. Manipulated variable: Hexane and Hexene/ Liquid P and Q/ Type
of hydrocarbon
P2. Responding variable : Colour change of bromine water/ acidified
potassium manganate(VII) solution
P3. Constant variable : bromine water/ acidified
potassium manganate(VII) solution
3
Able to state any two variables correctly 2
Able to state any one variables correctly 1
No response given or wrong response 0
4541/3 SULIT
11
Question Mark Scheme Mark
3(c)
[Able to state the relationship between the manipulated variable and
the responding variable correctly].
Sample answer:
1. If hexane is used, purple colour of acidified potassium
manganate(VII) solution remains unchanged.
If hexene is used, purple colour of acidified potassium
manganate(VII) solution becomes colourless. //
2. If hexane is used, brown bromine water remains unchanged.
If hexene is used, brown bromine water becomes colourless.
[Note : P and Q can replace hexane and hexene]
3
[Able to state the relationship between the manipulated variable and
the responding variable less correctly].
Sample answer:
1. If hexane is used, purple colour of acidified potassium
manganate(VII) solution remains unchanged.//
2. If hexene is used, purple colour of acidified potassium
manganate(VII) solution becomes colourless. //
3. If hexane is used, brown bromine water remains unchanged.//
4. If hexene is used, brown bromine water becomes colourless.//
5. Purple colour of acidified potassium manganate(VII) solution
remains unchanged if hexane is used.//
6. Purple colour of acidified potassium manganate(VII) solution
becomes colourless if hexene is used. //
7. Brown bromine water remains unchanged if hexane is used.//
8. Brown bromine water becomes colourless if hexene is used.
2
[Able to state the idea of hypothesis].
Sample answer:
1. Change of colour of acidified potassium manganate(Vll) //
2. Hexane does not change the colour of acidified potassium
manganate(VII) solution //
3. Hexene will decolourised colour of acidified potassium
manganate(VlI) solution
1
No response given or wrong response 0
4541/3 SULIT
12
Question Mark Scheme Mark
3(d) [Able to give list of materials and apparatus completely].
Sample answer:
Materials:
1. Liquid P/ hexane
2. Liquid Q/ hexene
3. Acidified potassium manganate(VII) solution / bromine water
Apparatus:
1. Test tube / boiling tube
2. Dropper
Note: P and Q could be either hexane or hexene [vice versa]
3
[Able to give a list of all materials and suitable container].
Sample answer:
Materials:
1. Liquid P/ hexane
2. Liquid Q/ hexene
3. Acidified potassium manganate(VII) solution / bromine water
Apparatus:
1. Test tube / boiling tube / beaker
2
[Able to give an idea of materials and apparatus].
Sample answer:
Materials:
1. Liquid P/ Q / hexane/hexene
2. Acidified potassium manganate(VII) solution / bromine water
Apparatus:
1. [Any suitable container]
1
No response given or wrong response 0
4541/3 SULIT
13
Question Mark Scheme Mark
3(e) [Able to state all steps of procedure correctly]
Sample answer:
1. Pour [1-5] cm3 of liquid P/ hexane into a test tube/ boiling tube
2. Add a few drops of acidified potassium manganate(VII) solution /
bromine water.
3. Shake/ stir the mixture.
4. Record the observation.
5. Repeat steps 1 to 4 by using liquid Q/ hexene to replace liquid P/
hexane
Note: P and Q could be either hexane or hexene [vice versa]
3
[Able to state steps 1, 2, 4 and 5] 2
[Able to state steps 1 and 2] 1
No response given or wrong response 0
Question Mark Scheme Mark
3(f)
[Able to construct a table that consist of the following information]
1. Heading for manipulated variable
2. Heading for observation
Sample answer:
Liquid Observation
P/ hexane
Q/ hexene
Note: P and Q could be either hexane or hexene [vice versa]
2
[Able to exhibit the tabulation of data that includes the following
three information:]
1. Heading for manipulated variable [only 1 liquid listed]
2. Heading for observation
Sample answer :
Liquid Observation
P
1
No response given or wrong response 0
END OF MARKING SCHEME
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Skema P2 MRSM 2014Skema P3 MRSM 2014