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Slide R-1Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Basic Concepts of Algebra
Chapter R
Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
R.1 The Real-Number System
Identify various kinds of real numbers. Use interval notation to write a set of numbers. Identify the properties of real numbers. Find the absolute value of a real number.
Slide R-4Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Rational Numbers
Numbers that can be expressed in the form p/q, where p and q are integers and q 0.
Decimal notation for rational numbers either terminates (ends) or repeats.
Examples:
a) 0 b)
c) 9 d)
1
8
7
11
Slide R-5Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Irrational Numbers
The real numbers that are not rational are irrational numbers.
Decimal notation for irrational numbers neither terminates nor repeats.
Examples:
a) 7.123444443443344…
b) 5
Slide R-6Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Interval Notation
Slide R-7Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Examples
Write interval notation for each set and graph the set.a) {x|5 < x < 2}
Solution: {x|5 < x < 2} = (5, 2) ( )
b) {x|4 < x 3}Solution: {x|4 < x 3} = (4, 3]
( ]
Slide R-8Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Properties of the Real Numbers
Commutative propertya + b = b + a and ab = ba
Associative propertya + (b + c) = (a + b) + c anda(bc) = (ab)c
Additive identity propertya + 0 = 0 + a = a
Additive inverse propertya + a = a + (a) = 0
Slide R-9Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
More Properties
Multiplicative identity property
a • 1 = 1 • a = a Multiplicative inverse property
Distributive property
a(b + c) = ab + ac
1 11 ( 0)a a a
a a
Slide R-10Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Examples
State the property being illustrated in each sentence.
a) 7(6) = 6(7) Commutative
b) 3d + 3c = 3(d + c) Distributive
c) (3 + y) + x = 3 + (y + x) Associative
Slide R-11Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Absolute Value
The absolute value of a number a, denoted |a|, is its distance from 0 on the number line.
Example:
Simplify.
|6| = 6
|19| = 19
Slide R-12Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Distance Between Two Points on the Number Line
For any real numbers a and b, the distance between a and b is |a b|, or equivalently |b a|.
Example:
Find the distance between 4 and 3.
Solution: The distance is |4 3| = |7| = 7,
or |3 (4)| = |3 + 4| = |7| = 7.
Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
R.2 Integer Exponents, Scientific
Notation, and Order of Operations Simplify expressions with integer exponents. Solve problems using scientific notation. Use the rules for order of operations.
Slide R-14Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Integers as Exponents
When a positive integer is used as an exponent, it indicates the number of times a factor appears in a product.For any positive integer n,
where a is the base and n is the exponent.
Example: 84 = 8 • 8 • 8 • 8
For any nonzero real number a and any integer m,a0 = 1 and .
Example: a) 80 = 1 b)
factors
...n
base n
a a a a a a
1m
m
aa
2 52 5
5 5 2 2
1 1x yx y
y y x x
Slide R-15Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Properties of Exponents
Product rule
Quotient rule
Power rule
(am)n = amn
Raising a product to a power
(ab)m = ambm
Raising a quotient to a power
m n m na a a
( 0)m
m nn
aa a
a
( 0)m m
m
a ab
b b
Slide R-16Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Examples – Simplify.
a) r 2 • r 5
r (2 + 5) = r 3
b)
c) (p6)4 = p -24 or 1 p24
d) (3a3)4 = 34(a3)4
= 81a12 or 81 a12
e)
99 4 5
4
36 362
18 18
yy y
y 3 32 2 2 2
4 4
3 6 6 6 6
12 12
6
6 12
21 3
7
3
27
27
a b a b
c c
a b a b
c c
a
b c
Slide R-17Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Scientific Notation
Use scientific notation to name very large and very small positive numbers and to perform computations.
Scientific notation for a number is an expression of the type N 10m,
where 1 N < 10, N is in decimal notation, and m is an integer.
Slide R-18Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Examples
Convert to scientific notation.a) 17,432,000 = 1.7432 107
b) 0.00000000024 = 2.4 1010
Convert to decimal notation.a) 3.481 106 = 3,481,000
b) 5.874 105 = 0.00005874
Slide R-19Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Another Example
Chesapeake Bay Bridge-Tunnel. The 17.6-mile-long tunnel was completed in 1964. Construction costs were $210 million. Find the average cost per mile.
88 1
1
7
2.1 101.19 10
1.76 10
$1.19 10
Slide R-20Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Rules for Order of Operations
Do all calculations within grouping symbols before operations outside. When nested grouping symbols are present, work from the inside out.
Evaluate all exponential expressions. Do all multiplications and divisions in order from left to
right. Do all additions and subtractions in order from left to
right.
Slide R-21Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Examples
a) 4(9 6)3 18 = 4 (3)3 18
= 4(27) 18
= 108 18
= 90
b) 3 2
15 (7 2) 20 15 5 20
3 2 27 43 20 23
31 31
Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
R.3 Addition, Subtraction, and
Multiplication of Polynomials Identify the terms, coefficients, and degree of a
polynomial. Add, subtract, and multiply polynomials.
Slide R-23Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Polynomials
Polynomials are a type of algebraic expression.
Examples: 5y 6t
3 17 4
2x x
9 7k
Slide R-24Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Polynomials in One Variable
A polynomial in one variable is any expression of the type
where n is a nonnegative integer, an,…, a0 are real numbers, called coefficients, and an 0. The parts of the polynomial separated by plus signs are called terms. The degree of the polynomial is n, the leading coefficient is an, and the constant term is a0. The polynomial is said to be written in descending order, because the exponents decrease from left to right.
1 21 2 1 0... ,n n
n na x a x a x a x a
Slide R-25Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Examples
Identify the terms.4x7 3x5 + 2x2 9
The terms are: 4x7, 3x5, 2x2, and 9.
Find the degree.a) 7x5 3 5b) x2 + 3x + 4x3 3c) 5 0
Slide R-26Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Addition and Subtraction
If two terms of an expression have the same variables raised to the same powers, they are called like terms, or similar terms.
Like Terms Unlike Terms
3y2 + 7y2 8c + 5b
4x3 2x3 9w 3y
We add or subtract polynomials by combining like terms.
Slide R-27Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Examples
Add: (4x4 + 3x2 x) + (3x4 5x2 + 7)
(4x4 + 3x4) + (3x2 5x2) x + 7
(4 + 3)x4 + (3 5)x2 x + 7
x4 2x2 x + 7
Subtract: 8x3y2 5xy (4x3y2 + 2xy)
8x3y2 5xy 4x3y2 2xy
4x3y2 7xy
Slide R-28Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Multiplication
To multiply two polynomials, we multiply each term of one by each term of the other and add the products.
Example: (3x3y 5x2y + 5y)(4y 6x2y)
3x3y(4y 6x2y) 5x2y(4y 6x2y) + 5y(4y 6x2y)
12x3y2 18x5y2 20x2y2 + 30x4y2 + 20y2 30x2y2
18x5y2 + 30x4y2 + 12x3y2 50x2y2 + 20y2
Slide R-29Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
More Examples
Multiply: (5x 1)(2x + 5)
= 10x2 + 25x 2x 5= 10x2 + 23x 5
Special Products of Binomials
Multiply: (6x 1)2
= (6x)2 + 2• 6x • 1 + (1)2
= 36x2 12x + 1
Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
R.4 Factoring
Factor polynomials by removing a common factor. Factor polynomials by grouping. Factor trinomials of the type x2 + bx + c. Factor trinomials of the type ax2 + bx + c, a 1, using the FOIL method and the grouping method. Factor special products of polynomials.
Slide R-31Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Terms with Common Factors
When factoring, we should always look first to factor out a factor that is common to all the terms.
Example: 18 + 12x 6x2
= 6 • 3 + 6 • 2x 6 • x2
= 6(3 + 2x x2)
Slide R-32Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Factoring by Grouping
In some polynomials, pairs of terms have a common binomial factor that can be removed in the process called factoring by grouping.
Example: x3 + 5x2 10x 50
= (x3 + 5x2) + (10x 50)
= x2(x + 5) 10(x + 5)
= (x2 10)(x + 5)
Slide R-33Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Trinomials of the Type x2 + bx + c
Factor: x2 + 9x + 14.
Solution:
1. Look for a common factor.
2. Find the factors of 14, whose sum is 9.
Pairs of Factors Sum
1, 14 15 2, 7 9 The numbers we need.
3. The factorization is (x + 2)(x + 7).
Slide R-34Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Another Example
Factor: 2y2 20y + 48.1. First, we look for a common factor.
2(y2 10y + 24)2. Look for two numbers whose product is 24 and whose
sum is 10.Pairs Sum Pairs Sum 1, 24 25 2, 12 14 3, 8 11 4, 6 10
3. Complete the factorization: 2(y 4)(y 6).
Slide R-35Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Trinomials of the Type ax2 + bx + c, a 1
Method 1: Using FOIL
1. Factor out the largest common factor.
2. Find two First terms whose product is ax2.
3. Find two Last terms whose product is c.
4. Repeat steps (2) and (3) until a combination is found
for which the sum of the Outside and Inside products
is bx.
Slide R-36Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Example
Factor: 8x2 + 10x + 3.
(8x + )(x + )
(8x + 1)(x + 3) middle terms are wrong 24x + x = 25x
(4x + )(2x + )
(4x + 1)(2x + 3) middle terms are wrong 12x + 2x = 14x
(4x + 3)(2x + 1) Correct! 4x + 6x = 10x
Slide R-37Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Grouping Method
1. Factor out the largest common factor.
2. Multiply the leading coefficient a and the constant c.
3. Try to factor the product ac so that the sum of the factors is b.
4. Split the middle term. That is, write it as a sum using the factors found in step (3).
5. Factor by grouping.
Slide R-38Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Example
Factor: 12a3 4a2 16a.1. Factor out the largest common factor, 4a.
4a(3a2 a 4)2. Multiply a and c: (3)(4) = 12.3. Try to factor 12 so that the sum of the factors is the coefficient of
the middle term, 1. (3)(4) = 12 and 3 + (4) = 1
4. Split the middle term using the numbers found in (3). 3a2 + 3a 4a 4
5. Factor by grouping. 3a2 + 3a 4a 4 = (3a2 + 3a) + (4a 4) = 3a(a + 1) 4(a + 1)
= (3a 4)(a + 1)Be sure to include the common factor to get the complete factorization. 4a(3a 4)(a + 1)
Slide R-39Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Special Factorizations
Difference of Squares
A2 B2 = (A + B)(A B)
Example: x2 25 = (x + 5)(x 5)
Squares of Binomials
A2 + 2AB + B2 = (A + B)2
A2 2AB + B2 = (A B)2
Example: x2 + 12x + 36 = (x + 6)2
Slide R-40Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
More Factorizations
Sum or Difference of Cubes
A3 + B3 = (A + B)(A2 AB + B2)
A3 B3 = (A B)(A2 + AB + B2)
Example: 8y3 + 125 = (2y)3 + (5)3
= (2y + 5)(4y2 10y + 25)
Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
R.5 Rational Expressions
Determine the domain of a rational expression. Simplify rational expressions. Multiply, divide, add, and subtract rational expressions. Simplify complex rational expressions.
Slide R-42Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Domain of Rational Expressions
The domain of an algebraic expression is the set of all real numbers for which the expression is defined.
Example: Find the domain of .
Solution: To determine the domain, we factor the denominator.
x2 + 3x 4 = (x + 4)(x 1) and set each equal to zero.
x + 4 = 0 x 1 = 0
x = 4 x = 1
The domain is the set of all real numbers except 4 and 1.
2
2
9
3 4
x
x x
Slide R-43Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Simplifying, Multiplying, and Dividing Rational Expressions
Simplify:
Solution:
Simplify:
Solution:
2
2
1
2 1
x
x x
2
2
1 ( 1)( 1)
2 1 (2 1)( 1)
( 1)
x x x
x x x x
x ( 1)
(2 1) ( 1)
x
x x
1
2 1
x
x
2 2
2 2
9 6 3
12 12
a ab b
a b
2 2 2 2
2 2 2 2
9 6 3 3(3 2 )
12 12 12( )
3(3 )( )
12( )( )
3
a ab b a ab b
a b a b
a b a b
a b a b
(3 ) ( ) a b a b
12 4 ( ) ( ) a b a b
3
4( )
a b
a b
Slide R-44Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Another Example
Multiply:
Solution:
2
2
2 4
3 3 2
x x
x x x
2
2
2 4 2 ( 2)( 2)
3 3 2 3 ( 2)( 1)
( 2)
x x x x x
x x x x x x
x
( 2)( 2)
( 3) ( 2)
x x
x x
( 1)
( 2)( 2)
( 3)( 1)
x
x x
x x
Slide R-45Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Adding and Subtracting Rational Expressions
When rational expressions have the same denominator, we can add or subtract the numerators and retain the common denominator. If the denominators are different, we must find equivalent rational expressions that have a common denominator.
To find the least common denominator of rational expressions, factor each denominator and form the product that uses each factor the greatest number of times it occurs in any factorization.
Slide R-46Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Example
Add:
Solution:
The LCD is (3x + 4)(x 1)(x 2).
2 2
9 2 7
3 2 8 3 4
x
x x x x
9 2 7
(3 4)( 2) (3 4)( 1)
x
x x x x
2
2
9 2 ( 1) 7 ( 2)
(3 4)( 2) ( 1) (3 4)( 1) ( 2)
9 7 2 7 14
(3 4)( 2)( 1) (3 4)( 2)( 1)
(3 4) (3 4)9 16
(3 4)( 2)( 1)
x x x
x x x x x x
x x x
x x x x x x
x xx
x x x (3 4)x ( 2)( 1)
3 4
( 2)( 1)
x x
x
x x
Slide R-47Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Complex Rational Expressions
A complex rational expression has rational expressions in its numerator or its denominator or both.
To simplify a complex rational expression: Method 1. Find the LCD of all the denominators
within the complex rational expression. Then multiply by 1 using the LCD as the numerator and the denominator of the expression for 1.
Method 2. First add or subtract, if necessary, to get a single rational expression in the numerator and in the denominator. Then divide by multiplying by the reciprocal of the denominator.
Slide R-48Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Example: Method 1
Simplify:
The LCD of the four expressions is x2y2.
2 2
1 1
1 1x y
x y
2 2
2 2
2 2
2 2
2 2
2 2 2 22 2
2 2
1 1
1 1
1 1( )
( )
( )1 1( )
x yx y
x yx y
x yx y xy x y xy y x
y x x yx y
x y
Slide R-49Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Example: Method 2
Simplify:
2 2
1 1
1 1x y
x y
2 2
2 2 2 2 2 2
2 2 2 2
2 2 2 2 2 2
2 2
2 2
1 1 1 1
1 1 1 1
y x
x y x y y xy x
x y x y y x
y x y x
xy xy xyy x y x
x y x y x y
y x x y y x
xy y x x
y
2x
2y2 2 2 2
( )xy y x
y x y x
Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
R.6 Radical Notation and Rational
Exponents Simplify radical expressions. Rationalize denominators or numerators in rational expressions. Convert between exponential and radical notation. Simplify expressions with rational exponents.
Slide R-51Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Notation
A number c is said to be a square root of a if c2 = a.
nth Root
A number c is said to be an nth root of a if cn = a.
The symbol denotes the nth root of a. The symbol is called a radical. The number n is called the index.
n a
Slide R-52Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Examples
Simplify each of the following:
a) = 7, because 72 = 49.
b) = 7, because 72 = 49 and .
c) because .
d) because (4)3 = 64.
e) is not a real number.
49
49
327 3
125 5
3 64 4
4 25
49 (7) 7 3 3
3
3 3 27
5 5 125
Slide R-53Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Properties of Radicals
Let a and b be any real numbers or expression for which the given roots exist. For any natural numbers m and n (n 1):
1. If n is even,
2. If n is odd,
3.
4.
5.
n na an na a
n n na b ab
( 0)n
nn
a ab
b b
mn m na a
Slide R-54Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Examples
a)
b)
c)
d)
e)
f)
g)
h)
2( 7) 7 7
33 ( 7) 7
44 43 7 21
72 36 2 6 2
81 819 3
99
53 5 5327 27 3 243
6 5 6 4
6 4
3 2 2 3
245 49 5
49 5
7 5 7 5
x y x y y
x y y
x y y y x y
22
25 525
yyy
Slide R-55Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Another Example
Perform the operation.
2 2
3 2 3 2 3 3 3 2 9 6 6 3 3
3 2 ( 9 1) 6 3 3
6 8 6 9
3 8 6
Slide R-56Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
The Pythagorean Theorem
The sum of the squares of the lengths of the legs of a right triangle is equal to the square of the length of the hypotenuse:
a2 + b2 = c2.
b
c a
Slide R-57Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Example
Juanita paddled her canoe across a river 525 feet wide. A strong current carried her canoe 810 feet downstream as she paddled. Find the distance Juanita actually paddled, to the nearest foot.
Solution: 2 2 2
2 2525 810
275,625 656,100
931,725
965.3 ft
c a b
c
c
c
c
525 ft
810 ft
x
Slide R-58Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Rationalizing Denominators or Numerators
Rationalizing the denominator (or numerator) is done by multiplying by 1 in such a way as to obtain a perfect nth power.
Example: Rationalize the denominator.
Example: Rationalize
the numerator.
6 6 7 42 42
7 7 7 749
2 2
4 4
4 4
4 4
a b a b a b
a b
a b
a ba b
a b
Slide R-59Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Rational Exponents
For any real number a and any natural numbers m and n for which exists,
n a
1/
/
//
, and
1
n n
mnm n m n
m nm n
a a
a a a
aa
Slide R-60Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Examples
Convert to radical notation and, if possible, simplify.
a)
b)
c)
3/ 4 4 311 11
1/ 21/ 2
1 1 19
9 39
4 / 3 4 33
44 / 3 43
27 ( 27) 531441 81, or
27 27 ( 3) 81
Slide R-61Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
More Examples
Convert each to exponential notation.a)
b)
Simplify.a)
b)
6 6 / 55 8 8ab ab
12 4 4 /12 1/ 3x x x
7 / 3 1/ 3/ 3 1/ 3 27( 2) ( 2) ( 2) ( 2) x x x x
8 8 8 813/7 /8 3/ 4 7 /8 3/ 4 8 13 8 5 5x x x x x x x x x
Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
R.7 The Basics of Equation Solving
Solve linear equations. Solve quadratic
Slide R-63Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Linear and Quadratic Equations
A linear equation in one variable is an equation that is equivalent to one of the form ax + b = 0, where a and b are real numbers and a 0.
A quadratic equation is an equation that is equivalent to one of the form ax2 + bx + c = 0, where a, b, and c are real numbers and a 0.
Slide R-64Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Equation Solving Principles
For any real numbers a, b, and c, The Addition Principle:
If a = b is true, then a + c = b + c is true. The Multiplication Principle:
If a = b is true, then ac = bc is true. The Principle of Zero Products:
If ab = 0 is true, then a = 0 or b = 0, and if a = 0 or
b = 0, then ab = 0. The Principle of Square Roots:
If x2 = k, then or x k .x k
Slide R-65Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Example: Solve 2x + 5 = 7 4(x 2)
2 5 7 4( 2)
2 5 7 4 8 Using the distributive property.
2 5 15 4 Combine like terms.
6 5 15 Using the addition principle.
6 10 Using the addi
x x
x x
x x
x
x
tion principle.
10 Using the multiplication principle.
65
Simplifying.3
x
x
Slide R-66Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Check:
We check the result
in the original equation.
2 5 7 4( 2)
5 52 5 7 4 2
3 3
10 5 65 7 4
3 3 3
10 15 21 14
3 3 3 3
25 21 4
3 3 325 25
3 3
x x
Slide R-67Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Example: Solve x2 3x = 10
Write the equation with 0 on one side.2
2
3 10
3 10 0
( 2)( 5) 0
2 0 or 5 0
2 or 5
x x
x x
x x
x x
x x
Slide R-68Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Check: x2 3x = 10
For x = 2 For x = 5
2
2
3 10
( ) 3( ) 10
4 6 10
10
2
10
2
x x
2
2
3 10
( ) 3( ) 10
25 15
5 5
10
10 10
x x
Slide R-69Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Example: Solve 5x2 25 = 0
We will use the principle of square roots.
2
2
2
5 25 0
5 25
5
5 or 5
x
x
x
x x