Date post: | 20-Jan-2016 |
Category: |
Documents |
Upload: | byron-tyler |
View: | 219 times |
Download: | 0 times |
Solving polynomial equations
Today we will use factoring techniques to solve polynomial equations of higher order. The degree of the equation will help determine the number of roots.
Degree of a polynomial
• We determine the degree by arranging the equation in standard form and look at the largest exponent.
Polynomial Function- BackgroundPattern Development
Linear Function: f(x) = ax + b, a 02Quadratic Function: f(x) = ax +bx+c, a 0
3 2Cubic Function: f(x) = ax +bx +cx+d, a 0
4 3 2Quartic Function: f(x) = ax +bx +cx +dx+e, a 0
Degree = 1
Degree = 2
(3)
(4)
The Number of Real Zeros of a Polynomial Function
Polynomial DegreeMinimum # of
Real ZerosMaximum # of
Real Zeros
Linear 1 1 1
Quadratic 2 0 2
Cubic 3 1 3
Quartic 4 0 4
Quintic 5 1 5
Some roots can be repeated
Finding the roots with algebra
• We can try factoring to find roots…• Examples:
1) f (x) =x3 +6x2
2) f(x) =x3 +2x2 + x
Finding the roots with algebra
• We can try factoring to find roots…• Examples:
1) f (x) =x3 +6x2
x2 (x+6)=0x=0,−6
2) f(x) =x3 +2x2 + x
x(x2 +2x+1)→ x(x+1)2 =0x=0,−1
Third degree equation
• Factor by grouping:
x3 −4x−5x2 +20 =0
Third degree equation
• Factor by grouping: x3 −4x−5x2 +20 =0x3 −4x−5x2 +20 =0
(x3 −5x2 )−(4x−20) =0
x2 (x−5)−4(x−5) =0
(x2 −4)(x−5) =0(x−2)(x+2)(x−5) =0x=2,−2,5