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Solving Systems of Equations

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Solving Systems of Equations. By Substitution. Objective. The student will solve systems of equations by substitution. Essential Questions. Why will solving for x first rather than for y give the same solution? - PowerPoint PPT Presentation
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Solving Systems of Equations By Substitution
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Page 1: Solving Systems of Equations

Solving Systems of Equations

By Substitution

Page 2: Solving Systems of Equations

Objective

The student will solve systems of equations by substitution.

Page 3: Solving Systems of Equations

Essential Questions

• Why will solving for x first rather than for y give the same solution?

• After solving for one variable, how will you choose an equation to solve for the second value?

Page 4: Solving Systems of Equations

Methods Used to Solve Systems of Equations• Graphing• Substitution• Elimination (Linear Combination)

Page 5: Solving Systems of Equations

A Word About Substitution

• Substitution is a good method to use if one variable in one of the equations is already isolated or has a coefficient of one.

• Substitution can be used for systems of two or three equations, but many prefer other methods for three equation systems.

Page 6: Solving Systems of Equations

Let’s Work Some Problems Using

Substitution.

Page 7: Solving Systems of Equations

Substitution

The goal in substitution is to combine the twoequations so that there is just one equation with one variable.

Page 8: Solving Systems of Equations

Substitution

Solve the system using substitution.

y = 4x x + 3y = –39

x + 3(4x) = – 39

x + 12x = –39

13x = –39

x = – 3 Continued on next slide.

Since y is already isolated in the first equation,substitute the value of y for y in the second equation.

The result is one equation with one variable.

Page 9: Solving Systems of Equations

Substitution

After solving for x, solve for y by substitutingthe value for x in any equation that contains 2 variables.

y = 4x y = 4(–3) y = –12

Write the solution as an ordered pair. (–3, –12)

There’s more on the next slide.

Page 10: Solving Systems of Equations

Substitution

Check the solution in BOTH equations.

y = 4x x + 3y = –39

–12 = 4(–3) –12 = –12

–3 + 3(– 12) = –39 –3 – 36 = –39 –39 = –39

P

P

The solution is (– 3, –12).

Page 11: Solving Systems of Equations

Substitution

Solve the system using substitution.

x – 3y = –5 2x + 7y = 16

x = 3y – 5 2x + 7y = 16

2(3y – 5) + 7y = 16

If a variable is not already isolated, solve for one variable in one of the equations. Choose to solve for a variable with a coefficient of one,if possible.

Page 12: Solving Systems of Equations

Substitution

2(3y – 5) + 7y = 16

6y – 10 + 7y = 16

13y – 10 = 16

13y = 26

y = 2

x = 3y – 5 2x + 7y = 16

x = 3(2) – 5 x = 6 – 5 x = 1

The solution is (1, 2).

* Be sure to check!

Page 13: Solving Systems of Equations

Substitution

A zookeeper needs to mix feed for the prairie dogs So that the feed has the right amount of protein. Feed A has 12% protein. Feed B has 5% protein. How many pounds of each does he need to mix toget 100 lb of feed that is 8% protein?

Page 14: Solving Systems of Equations

Substitution


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