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Splash Screen. Lesson Menu Five-Minute Check (over Chapter 7) Then/Now New Vocabulary Key Concept:...

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Page 1: Splash Screen. Lesson Menu Five-Minute Check (over Chapter 7) Then/Now New Vocabulary Key Concept: Geometric Mean Example 1:Geometric Mean Theorem 8.1.
Page 2: Splash Screen. Lesson Menu Five-Minute Check (over Chapter 7) Then/Now New Vocabulary Key Concept: Geometric Mean Example 1:Geometric Mean Theorem 8.1.

Five-Minute Check (over Chapter 7)

Then/Now

New Vocabulary

Key Concept: Geometric Mean

Example 1: Geometric Mean

Theorem 8.1

Example 2: Identify Similar Right Triangles

Theorems: Right Triangle Geometric Mean Theorems

Example 3: Use Geometric Mean with Right Triangles

Example 4: Real-World Example: Indirect Measurement

Page 3: Splash Screen. Lesson Menu Five-Minute Check (over Chapter 7) Then/Now New Vocabulary Key Concept: Geometric Mean Example 1:Geometric Mean Theorem 8.1.

Over Chapter 7

A. A

B. B

C. C

D. D A B C D

0% 0%0%0%

Solve the proportion

A. 15

B. 16.5

C.

D. 18

Page 4: Splash Screen. Lesson Menu Five-Minute Check (over Chapter 7) Then/Now New Vocabulary Key Concept: Geometric Mean Example 1:Geometric Mean Theorem 8.1.

Over Chapter 7

A. A

B. B

C. C

D. D A B C D

0% 0%0%0%

A. x = 16.1, y = 1.6

B. x = 15.6, y = 2.1

C. x = 7.8, y = 8.4

D. x = 17.6, y = 3.7

The triangles at the right are similar. Find x and y.

Page 5: Splash Screen. Lesson Menu Five-Minute Check (over Chapter 7) Then/Now New Vocabulary Key Concept: Geometric Mean Example 1:Geometric Mean Theorem 8.1.

Over Chapter 7

A. A

B. B

C. C

D. D A B C D

0% 0%0%0%

A. yes, ΔABC ~ ΔEDF

B. yes, ΔABC ~ ΔDEF

C. yes, ΔABC ~ ΔEFD

D. No, sides are not proportional.

Determine whether the triangles are similar. If so, write a similarity statement.

Page 6: Splash Screen. Lesson Menu Five-Minute Check (over Chapter 7) Then/Now New Vocabulary Key Concept: Geometric Mean Example 1:Geometric Mean Theorem 8.1.

Over Chapter 7

A. A

B. B

C. C

D. D A B C D

0% 0%0%0%

A. 66.25

B. 64.5

C. 12.4

D. 10.6

Find the perimeter of DEF if ΔABC ~ ΔDEF, AB = 6.3, DE = 15.75, and the perimeter of ABC is 26.5.

Page 7: Splash Screen. Lesson Menu Five-Minute Check (over Chapter 7) Then/Now New Vocabulary Key Concept: Geometric Mean Example 1:Geometric Mean Theorem 8.1.

You used proportional relationships of corresponding angle bisectors, altitudes, and medians of similar triangles. (Lesson 7–5)

• Find the geometric mean between two numbers.

• Solve problems involving relationships between parts of a right triangle and the altitude to its hypotenuse.

Page 10: Splash Screen. Lesson Menu Five-Minute Check (over Chapter 7) Then/Now New Vocabulary Key Concept: Geometric Mean Example 1:Geometric Mean Theorem 8.1.

Geometric Mean

Find the geometric mean between 2 and 50.

Answer: The geometric mean is 10.

Definition of geometric mean

Let x represent the geometric mean.

Cross products

Take the positive square root of each side.

Simplify.

Page 11: Splash Screen. Lesson Menu Five-Minute Check (over Chapter 7) Then/Now New Vocabulary Key Concept: Geometric Mean Example 1:Geometric Mean Theorem 8.1.

A. A

B. B

C. C

D. D A B C D

0% 0%0%0%

A. 3.9

B. 6

C. 7.5

D. 4.5

A. Find the geometric mean between 3 and 12.

Page 13: Splash Screen. Lesson Menu Five-Minute Check (over Chapter 7) Then/Now New Vocabulary Key Concept: Geometric Mean Example 1:Geometric Mean Theorem 8.1.

Identify Similar Right Triangles

Write a similarity statement identifying the three similar triangles in the figure.

Separate the triangles into two triangles along the altitude.

Page 14: Splash Screen. Lesson Menu Five-Minute Check (over Chapter 7) Then/Now New Vocabulary Key Concept: Geometric Mean Example 1:Geometric Mean Theorem 8.1.

Identify Similar Right Triangles

Then sketch the three triangles, reorienting the smaller ones so that their corresponding angles and sides are in the same position as the original triangle.

Answer: So, by Theorem 8.1, ΔEGF ~ ΔFGH ~ ΔEFH.

Page 15: Splash Screen. Lesson Menu Five-Minute Check (over Chapter 7) Then/Now New Vocabulary Key Concept: Geometric Mean Example 1:Geometric Mean Theorem 8.1.

A. A

B. B

C. C

D. D A B C D

0% 0%0%0%

A. ΔLNM ~ ΔMLO ~ ΔNMO

B. ΔNML ~ ΔLOM ~ ΔMNO

C. ΔLMN ~ ΔLOM ~ ΔMON

D. ΔLMN ~ ΔLMO ~ ΔMNO

Write a similarity statement identifying the three similar triangles in the figure.

Page 17: Splash Screen. Lesson Menu Five-Minute Check (over Chapter 7) Then/Now New Vocabulary Key Concept: Geometric Mean Example 1:Geometric Mean Theorem 8.1.

Use Geometric Mean with Right Triangles

Find c, d, and e.

Page 18: Splash Screen. Lesson Menu Five-Minute Check (over Chapter 7) Then/Now New Vocabulary Key Concept: Geometric Mean Example 1:Geometric Mean Theorem 8.1.

Use Geometric Mean with Right Triangles

Since e is the measure of the altitude drawn to the hypotenuse of right ΔJKL, e is the geometric mean of the lengths of the two segments that make up the hypotenuse, JM and ML.

Geometric Mean(Altitude) Theorem

Substitution

Simplify.

Page 19: Splash Screen. Lesson Menu Five-Minute Check (over Chapter 7) Then/Now New Vocabulary Key Concept: Geometric Mean Example 1:Geometric Mean Theorem 8.1.

Use Geometric Mean with Right Triangles

Geometric Mean(Leg) Theorem

Substitution

Use a calculator tosimplify.

Since d is the measure of leg JK, d is the geometric mean of JM, the measure of the segment adjacent to this leg, and the measure of the hypotenuse JL.

Page 20: Splash Screen. Lesson Menu Five-Minute Check (over Chapter 7) Then/Now New Vocabulary Key Concept: Geometric Mean Example 1:Geometric Mean Theorem 8.1.

Use Geometric Mean with Right Triangles

Geometric Mean(Leg) Theorem

Substitution

Use a calculator tosimplify.

Answer: e = 12, d ≈ 13.4, c ≈ 26.8

Since c is the measure of leg KL, c is the geometric mean of ML, the measure of the segment adjacent to KL, and the measure of the hypotenuse JL.

Page 21: Splash Screen. Lesson Menu Five-Minute Check (over Chapter 7) Then/Now New Vocabulary Key Concept: Geometric Mean Example 1:Geometric Mean Theorem 8.1.

A. A

B. B

C. C

D. D A B C D

0% 0%0%0%

A. 13.9

B. 24

C. 17.9

D. 11.3

Find e to the nearest tenth.

Page 22: Splash Screen. Lesson Menu Five-Minute Check (over Chapter 7) Then/Now New Vocabulary Key Concept: Geometric Mean Example 1:Geometric Mean Theorem 8.1.

Indirect Measurement

KITES Ms. Alspach is constructing a kite for her son. She has to arrange two support rods so that they are perpendicular. The shorter rod is 27 inches long. If she has to place the short rod 7.25 inches from one end of the long rod in order to form two right triangles with the kite fabric, what is the length of the long rod?

Page 23: Splash Screen. Lesson Menu Five-Minute Check (over Chapter 7) Then/Now New Vocabulary Key Concept: Geometric Mean Example 1:Geometric Mean Theorem 8.1.

Indirect Measurement

Draw a diagram of one of the right triangles formed.

Let be the altitude drawn from the right angle of ΔWYZ.

Page 24: Splash Screen. Lesson Menu Five-Minute Check (over Chapter 7) Then/Now New Vocabulary Key Concept: Geometric Mean Example 1:Geometric Mean Theorem 8.1.

Indirect Measurement

Answer: The length of the long rod is 7.25 + 25.14, or about 32.39 inches long.

Geometric Mean(Altitude) Theorem

Substitution

Square each side.

Divide each side by 7.25.

Page 25: Splash Screen. Lesson Menu Five-Minute Check (over Chapter 7) Then/Now New Vocabulary Key Concept: Geometric Mean Example 1:Geometric Mean Theorem 8.1.

A. A

B. B

C. C

D. D A B C D

0% 0%0%0%

A. 68.3 ft

B. 231.3 ft

C. 273.1 ft

D. 436.1 ft

AIRPLANES A jetliner has a wingspan, BD, of 211 feet. The segment drawn from the front of the plane to the tail, at point E. If AE is 163 feet, what is the length of the aircraft to the nearest tenth of a foot?


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