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Report No . 3 Submitted to Prof. Dr. Mahdi H. Jasim and Dr. Shafik S. Almola as a study report during their supervision on my Ph.D. Thesis. Level Density Calculations for the Nuclear Exciton States Ahmed A. Selman, Department of Physics, College of Science, University of Baghdad June 22 nd 2007 Final correction made: November 24 th 2007
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Page 1: State Density Calculations for the Exciton Levels · 2012. 12. 2. · particle state density per each MeV by g, then one can write the energy difference between any two successive

Report No. 3

Submitted to Prof. Dr. Mahdi H. Jasim and Dr. Shafik S. Almola

as a study report during their supervision on my Ph.D. Thesis.

Level Density Calculations for the Nuclear Exciton States

Ahmed A. Selman,

Department of Physics, College of Science, University of Baghdad

June 22nd 2007

Final correction made: November 24th 2007

Page 2: State Density Calculations for the Exciton Levels · 2012. 12. 2. · particle state density per each MeV by g, then one can write the energy difference between any two successive

Table of Contents

Table of Contents..................................................................................1

Introduction ..........................................................................................2

I. The Level Density of the Precompound Nucleus, ω(n,E) ...............2

II. Level Densities with no Corrections ..............................................6

III. Correction due to Pauli Principle ...............................................11

IV. Corrections due to Bound – States and the Nuclear Well Finite

Depth Correction ................................................................................16

V. Pairing Correction and Fermi Gas Formula...............................19

VI. Numerical Calculations ...............................................................20

VII. Results and Discussions..............................................................23

VII.A. Level density calculations with no corrections ..........................23

VII.B. Level density calculations with Pauli correction ......................26

VII.C. Level density calculations with corrections due to Pauli

principle and the nuclear potential well with finite depth ...................29

VII.D. A final comparison .......................................................................34

VIII. Suggestions ................................................................................36

IX. The Program.................................................................................36

IX.A. Description ......................................................................................36

IX.B. Testing the Program.......................................................................38

3-1

REFERENCES ........................................................................................39

Page 3: State Density Calculations for the Exciton Levels · 2012. 12. 2. · particle state density per each MeV by g, then one can write the energy difference between any two successive

Introduction

The present report focuses on level state density calculations for three

cases: uncorrected Ericson’s formula, Williams’ formula corrected to Pauli

blocking energy, and Williams’ formula corrected to Pauli blocking energy

and finite well depth of the nuclear potential. The systems considered here

are based on the ESM approximation.

An over review is presented for the different formulae used for this

purpose. The specific formulae are listed for one- and two-component Fermi

gas system. Numerical calculations are performed based on these formulae

for each system and the results are briefly discussed.

I. The Level Density of the Precompound Nucleus, ω(n,E)

The level density of the precompound nucleus, ω(n,E), is defined as [1]

the number of states per unit energy for a given state described by the

exciton number, n, and excitation energy E. In the exciton model, the level

density is the most important quantity where the main calculations of the

differential cross section and double differential cross section are based on.

Also the transition rates of the system during the equilibration process is

based on knowledge of the nuclear level density. This quantity is sometimes

called “partial level density, PLD” in order to distinguish it from the “total

level density”, ω(E). The total level density is the sum of the level density

for all possible exciton number, n, at a given excitation energy, E, i.e.,

).1(),()( EnEn

ωω ∑=

3-2

In the present report we use ω(n,E) or ω(p,h,E) to give the same

meaning. ω(n,E) is used herein for simplicity, but when it is needed, the

other term, i.e., ω(p,h,E) is used. The quantity ω(n,E) is a nuclear property

Page 4: State Density Calculations for the Exciton Levels · 2012. 12. 2. · particle state density per each MeV by g, then one can write the energy difference between any two successive

that is not easy to measure experimentally. This measurement difficulty

rises from the instability of the nuclear excited states. The theoretical

formulations can thus only approach the description of the nuclear level

density by approximate calculations. This is mainly due to the lack of the

knowledge about the exact nuclear structure [2]. Therefore, all the theoretical

calculations of the nuclear level density are limited to some certain

conditions.

However it was confirmed that the nuclear level density, ω(n,E),

increases rapidly with n and E. Theoretical treatment must also show this

property of the nuclear level density when using the statistical models to

describe the population of states. Therefore, it is acceptable to give the

relation between ω(n,E) and E as being an exponential relation with n.

Indeed, almost all experimental calculations of the total level density,

ω(E), can be fitted to an exponential form [2]. Examples are,

[ ][ ]

[ ])2(

2exp)(

2exp)(

2exp)(

2

⎪⎪⎪

⎪⎪⎪

=

=

=

EaECE

EaECE

aECE

ω

ω

ω

,

3-3

where C and a are fitting constants. So, one can see that there are many

formulae used for level density calculations. However, we will focus only

on Ericson’s and Williams’ formulae for equally-spaced nuclear levels. This

equal-spacing assumption of nuclear level is described by the “Equi-distant

Spacing Model”, ESM. In the ESM, all nuclear energy levels are assumed to

be separated by an equal spacing. In other words, if one defines the single

Page 5: State Density Calculations for the Exciton Levels · 2012. 12. 2. · particle state density per each MeV by g, then one can write the energy difference between any two successive

particle state density per each MeV by g, then one can write the energy

difference between any two successive energy levels , En, as,

∆En = En+1 – En = 1/g = constant,

and the idea is illustrated in Fig.(1) schematically.

Fig.(1). Schematic representation of real (a) and ESM approximation (b) of the energy level structure of the nucleus. Note that at high energy both representations will be approximately the same. This justifies the validity of the ESM approximation for high excitation energies.

Although the ESM sounds like a crude approximation to describe the

nuclear level density, it gives acceptable results [1] when the interest is about

calculating the level density of the excited nucleus, ω(n,E). Later in the

3-4

∆Εn

Εn+1

Εn

(a) (b)

Page 6: State Density Calculations for the Exciton Levels · 2012. 12. 2. · particle state density per each MeV by g, then one can write the energy difference between any two successive

present report, we will see under what conditions the ESM fails to apply. In

general, the ESM approximation is valid for calculations performed on

nuclei with mass number A≥40 and excitation energy E≥15 MeV [1].

It is usual to use the expression “Fermi Gas system” to describe the

mechanism of nuclear system equilibration. This expression means that the

constituents of the nuclear matter are basically non interactive with each

other.

In the exciton model, one is mainly interested in defined calculations of

the level density ω(n,E). This quantity is specified by n and E. The exciton

number, n, is defined as

n=p + h (for one-component Fermi gas system) (3),

where p and h stand for the number of particles and holes, respectively. The

eq. (3) is for one-component Fermi gas system, i.e., it assumes that protons

and neutrons are indistinguishable particles.

For a two-component Fermi gas system, we have,

n = nπ + nν = pπ + hπ + pν + hν (for two-component Fermi gas system) (4),

where the subscripts ν and π stand for neutron and proton, respectively. We

shall denote the level density for one-component Fermi gas system by

ω1(n,E) and for two-component system by ω2(n,E).

3-5

In the following sections, the different expressions used to find ω(n,E)

are given for one- and two-component Fermi gas systems. At the end of this

report, several numerical calculations are performed for each case described

by the subsequent sections. To make the theory clear, a comparison is made

Page 7: State Density Calculations for the Exciton Levels · 2012. 12. 2. · particle state density per each MeV by g, then one can write the energy difference between any two successive

between examples of one- and two-component Fermi gas systems. Each

case is discussed briefly.

II. Level Densities with no Corrections

The simplest way to describe ω(n,E) is to exclude all possible (and

real) corrections during the calculations. The corrections of the level density

are,

1. Correction due to Pauli principle.

2. Spin, angular and linear momentum corrections.

3. Charge effects.

4. Finite depth of the nuclear potential well.

5. Nucleon-nucleon pairing effect.

6. Non-ESM (i.e., real) energy level spacing.

Using non of the above corrections, Ericson showed that the nuclear

level density of the excited state is given for one-component Fermi gas

system by the following relation, (Ericson’s formula for one-component

system)

)5()!1(!!

),(1

1 −=

nhpEgEn

nnω ,

where g is the single particle density, it corresponds to eq. (5) itself but with

exciton number set to one, i.e.,

g= ω1(1,E)= ω 1(1,0,Ep)= ω1(0,1,Eh) (6)

3-6

and here Ep (and Eh) stand for the particle’s (and hole’s) excitation energy

for a single particle (or hole), respectively.

Page 8: State Density Calculations for the Exciton Levels · 2012. 12. 2. · particle state density per each MeV by g, then one can write the energy difference between any two successive

By using successive application of the recursion relations one can get

eq.(5) for any number of particles or holes [1],

)7(

),,0(),0,(),(),,(

),1,0(1),,0(

),0,1(1),0,(

110

11

10

1

10

1

⎪⎪⎪⎪

⎪⎪⎪⎪

−==

−=

−=

dUUEhUpEnEhp

dUUhgh

Eh

dUUpgp

Ep

E

hE

h

pE

p

ωωωω

ωω

ωω

.

As an example, we have,

,22

1),0,1(21),0,2(

,),0,1(2

0

21

01

1

EgdUgdUUgE

gEEE

===

=

∫∫ ωω

ω

etcEgdUUgdUUgEEE

,...123

1),0,2(31),0,3(

22

0

31

01 === ∫∫ ωω

g in eq.(5) is given approximately by the relation,

)8()(23 1−= MeV

FAg ,

3-7

where F is the Fermi energy given as, 2

23/2

289

omrF h

⎟⎠⎞

⎜⎝⎛=

π (m is the nucleon

mass and ro is its radius). If A is the mass number of the nucleus then this

relation is usually approximated by the following phenomenological

approximation equation, g1513AtoA

≅ , which is used in most of the practical

present numerical calculations that include nucleon induced reactions.

Page 9: State Density Calculations for the Exciton Levels · 2012. 12. 2. · particle state density per each MeV by g, then one can write the energy difference between any two successive

For two-component Fermi gas system, the nuclear level density is

given by the following relation [3] (Ericson’s formula for two-component)

)9()!1(!!!!

),(1

2 −=

nhphpEgEn

vv

nn

ππω ,

where is the total exciton number. Also, the exciton

number of protons is

,vv hphpn +++= ππ

,πππ hpn += and that of neutrons is so,

again we have . Eq.(9) was written when one assumes that the

single particle density g is the same for protons and neutrons. If, however,

one assumes that the single particle density for the neutrons, gν , differs from

that of the protons, gπ, then eq.(9) will be written as [3],

,vvv hpn +=

vnnn += π

( ) ( ) )10()!1(!!!!

),(1

2 −=

nhphpEggEn

vv

nvnv

n

ππ

ππω ,

and in this case we define

)11()(, gANg

AZAgg

AZg v =

−≅≅π .

The total level density is given by eq.(1) in both cases of one- and two-

component Fermi gas systems. Also note that in both cases, the difference of

the exciton number is given as ∆n=2, i.e., we have:

ω(E)= ω(1,E)+ ω(3,E)+ ω(5,E)+ ω(7,E)+ ...etc.

3-8

This behavior of the nuclear level density was based originally on the

idea of the exciton model due to Griffin [4]. The exciton model is a semi-

classical model that depends on the states at which particles and holes can

occupy. As stated earlier in this report, the number of (particles + holes)

gives the exciton number, n. Excitons are created when the projectile

Page 10: State Density Calculations for the Exciton Levels · 2012. 12. 2. · particle state density per each MeV by g, then one can write the energy difference between any two successive

incident on the target nucleus excites one particle (or more), and the process

cascades from the initial configuration to higher configurations. The

development of the configurations is schematically shown in Fig.(2) below.

From Fig.(2) below, one can see the importance of some of the realistic

corrections that are needed to describe the nuclear reaction in a clear manner.

For example, and since nuclear reactions deal mainly with fermions, then the

correction due to Pauli principle prohibits the existence of two (or more)

identical particles in the same state. Therefore, this will force the

configuration of Fig.(2-c), for example, to be rearranged so that Pauli

principle is not violated. One also expects that for closed shells the particles

excitation energy would be higher than for particles in non-closed shells.

Another expected behavior is that paired nucleons would also require higher

energy to be excited than un-paired nucleons,…etc. Note that in Fig.(2) one

assumed that the nucleus is treated as an entity made of one type of particles.

When one is considering two-component system, the situation becomes more

complicated because then one needs to add other restrictions on the system

such as the difference in the binding energies and pairing correction terms,

added to those corrections mentioned above.

3-9

Another restriction is seen from the figure is that the maximum number

of excitons is limited to (2A+Aa), where Aa is the mass number of the

incident projectile. However, this is considered as a severe limit because it

requires that all the nucleon particles inside the nucleus are moved to

excited levels, which requires an extreme kinetic energy for the incident

projectile. Since there are many possibilities for the nucleus excited to this

high extent to go through spallation or disassociation emitting lighter

particles (evaporation process), then the limit of total excitation of the

nucleus is of very small probability.

Page 11: State Density Calculations for the Exciton Levels · 2012. 12. 2. · particle state density per each MeV by g, then one can write the energy difference between any two successive

This extremely excited state limit is usually not considered in the

practical uses of the exciton model [1]. The density of the final accessible

states is given by the following equations for the case of one-component

system [1],

3-10

incident particle

empty levels

occupied levels

(a) before excitation (1p, 0h)

(b) first excitation (2p, 1h)

(c) second excitation (3p, 2h)

…etc…

Fig.(2) Schematic representation of the excitation process (for one component Fermi gas system) and exciton creation during nucleon-induced reaction.

Page 12: State Density Calculations for the Exciton Levels · 2012. 12. 2. · particle state density per each MeV by g, then one can write the energy difference between any two successive

)12(

121),(

)2(21),(

22

⎪⎪⎭

⎪⎪⎬

+=

−=

+

nEggEn

nhpgEn

f

f

ω

ω,

where the superscripts (+ and -) sand for the change in the exciton number,

∆n=±2.

III. Correction due to Pauli Principle

This correction is a very necessary one and should be taken into

account to perform accurate calculations. This correction applies for both

systems in the exciton model one- and two-component systems); and for

both particles and holes in each case. The inclusion of Pauli principle

correction complicates the calculations performed to find the level density

of the excited nucleus.

The effect of Pauli principle correction on the level density is that the

magnitude of the excitation will be lowered because there are several states

that will be blocked, thus decrease the contribution of such states in the

amount of the excitation energy. A net effect will be as if the excitation

energy E is shown to have the value of [E-Ap,h(p,h,E)], where Ap,h(p,h,E) is

the Pauli correction term. By including this term in the level density

calculations one can write [1,3],

)13()!1(!!)(

),(1

,1 −

−=

nhpAEg

nEn

hpn

ω ,

3-11

where the correction term, Ap,h is the Pauli blocking energy, given as [3]

Page 13: State Density Calculations for the Exciton Levels · 2012. 12. 2. · particle state density per each MeV by g, then one can write the energy difference between any two successive

).14(4

)3()1(, g

hhppA hp−++

=

Eq.(13) is Williams’ formula for finding the level density for one-

component Fermi system. For two-component system we have [3],

,)15()!1(!!!!

)(),(

1,,,

2 −

−=

nhphpAEgg

Envv

nvhvphp

vnv

n

ππ

πππ

πω

with the correction term given in this case by the following formula which

takes into account the different types of excitons participated in the amount

of blocked energy due to Pauli principle [3], (Pauli blocking energy)

),16(4

)3()1(4

)3()1(,,,

v

vvvvvhvphp g

hhppg

hhppA

−+++

−++=

π

ππππππ

where gπ and gν are given by eq.(11) above. The most difficulties in eq.(14

and 16) is that they are not symmetric in p and h, and not corrected for

energy, which may add some uncertainty in the calculations. Even though,

we will restrict ourselves on using these formulae and a slightly modified

formula (see below) in the present calculations because these formulae are

oftenly used in many papers [1,3 and references therein]. Eq.(15) is

Williams’ formula for two-component Fermi system.

When applying eq.(1) on both of eq.(13 and 15), one gets the total level

density of excitons as [1],

[ ] ),17(482exp),()( 11 E

aEEnEn

== ∑ ωω

3-12

for one-component and,

Page 14: State Density Calculations for the Exciton Levels · 2012. 12. 2. · particle state density per each MeV by g, then one can write the energy difference between any two successive

[ ] ),18()(

2exp12

),()( 4/1522 EaaEEnE

n

πωω == ∑

for two-component. The constant a in these equations is 6

2 ga π= .

The total level density can also be given by the renormalization of level

density for one-component [3]. This is done by calculating the ratio

ω1(U)/ω2(U), -see eq.(19) below- where U is the effective excitation energy,

[ ]

[ ]( )

)19(

)(

2exp12

)(

482exp)(

4/152

1

⎪⎪

⎪⎪

+=

=

tUa

aUU

UaUU

πω

ω

where the nuclear temperature t is related to U by the following [3],

U = a t2- t (20).

sometimes, the effective excitation energy U is related to the pairing energy.

This will be shown in report no.4.

Then the renormalized density for one-component will be given as [3],

( )).22(

)(3)(

),21(),()(),(

4/15

11

tUa

UUf

EnUfEnR

+=

=

π

ωω

3-13

Another form of equations (13 and 15) is to include a slight correction

due to energy symmetry [1], that is to use the formula

Page 15: State Density Calculations for the Exciton Levels · 2012. 12. 2. · particle state density per each MeV by g, then one can write the energy difference between any two successive

)23()()!1(!!)(

),( ,

1,

1 hp

nhp

n

EnhpAEg

nE αω −Θ−

−=

where Θ(E-αp,h) is the Heaviside step function defined as,

⎪⎩

⎪⎨

>−

≤−

=−Θ01

)24(

00

)(

,

,

,

hp

hp

hp

E

E

α

α ,

and the correction term αp,h is given as [1],

)25(2

)1()1(, g

hhpphp

−++=α ,

for one-component and,

,)26()()!1(!!!!

)(),( ,,,

1,,,

2 vhvphpvv

nvhvphp

vnv

n

Enhphp

AEggEn ππ

ππ

πππ

π αω −Θ−

−=

for two-component with,

).27(2

)1()1(2

)1()1(,,,

v

vvvvvhvphp g

hhppg

hhpp −+++

−++=

π

ππππππα

When using the Pauli principle correction to the level density, the

density of the final accessible states will be given as [1], (for one-

component)

3-14

),28(

),(/),2(),(

),(/),(),(

),(/),(),(

1

100

1

⎪⎪⎭

⎪⎪⎬

−=

=

=

+−

++

EnEnCEn

EnEnCEn

EnEnCEn

f

f

f

ωω

ωω

ωω

Page 16: State Density Calculations for the Exciton Levels · 2012. 12. 2. · particle state density per each MeV by g, then one can write the energy difference between any two successive

where the constants C+ and C0 are the numbers of realizations of the final

states. An explicit form of eq.(28) at the highest powers of E, is given by

[1],

( )

)29()()1(4

)(2)2()1()1(

)(2)2()1()1(

2),(

)29()2)(1()2)(1()()2(8

)1(1

2)2(),(

,,

,

,0

,

bAEnphnph

AEhppnpp

AEpppnpp

nAE

En

ahhppAEn

n

nhpEn

hphp

hp

hpf

hp

f

⎥⎥⎦

−−

−+−

+−−−

⎢⎢⎣

⎡+

−+−

−−×−

⎥⎥⎦

⎢⎢⎣

⎡−−+−−×

−−−

×−

≅−

ω

ω

and finally,

( )

)29(2

)1(85)1(

85

)(11

)1(2),(

,

2,

cnhphhpp

AEnn

nAE

Enhp

hpf

⎥⎦

⎤⎟⎠⎞

⎜⎝⎛ ++−+−

⎢⎢⎣

⎡×

−+

−+

−≅+ω

The level density of final accessible states is important for calculating

the transition rates of the system in its course to equilibration. This subject is

important to our research, therefore, this subject should be considered in the

future. However, eq.(29) is not frequently. Instead a further approximation

is made by ignoring the information of Pauli principle on the ∆n=-2

transitions, then [1]

[ ][ ] )30(

)(

)()1(2

),( 1,

11,1

++++

+= n

hp

nhp

fAEg

AEgngEnω

3-15

which is comparable to eq.(12).

Page 17: State Density Calculations for the Exciton Levels · 2012. 12. 2. · particle state density per each MeV by g, then one can write the energy difference between any two successive

IV. Corrections due to Bound – States and the Nuclear Well Finite Depth Correction

When a pre-equilibrium state occurs, we know that exciton theory

assumes that there are certain decay probabilities to the continuum and to

other states (which we call internal system transition rates) from that exciton

state. The potential-type affect both of these transitions but it is important to

study this effect on emission rates rather than the internal transition rates for

simplicity. If one seeks the ideal case, the effect of the potential well should

be considered for all transition rates, i.e., decay and internal transition rates.

The energy of the emitted particles depends on many properties. The

most important effect in this case is the type of the nuclear potential that the

particle was located in. When we assume a nuclear potential with finite well

depth, the emitted particles will be expected to have more discriminated

energies in the continuum, corresponding to well separated (non-overlapped)

states. In general, when emission occurs from an excited nucleus having a

finite well potential properly defined, there a good probability for some

particles to have higher emission energy.

3-16

There is also some quantum effect that is called “Continuum Effect”,

which leads to decreasing of the level density as the particle emission energy

increases. This phenomenon occurs because there is energy sharing between

nucleons in the nucleus with the emitted particle [5]. The continuum effect

may change the emission rates significantly in some cases when the energy

of the emitted particles is of order of the excitation energy of the nucleus,

which may be due to better overlapping probability between states of the

emitted particles and the nucleons inside the nucleus. Then, in order to

correct the level density for bound-states and finite depth of the nuclear

potential well, one will need to define the shape of the nuclear potential. If

Page 18: State Density Calculations for the Exciton Levels · 2012. 12. 2. · particle state density per each MeV by g, then one can write the energy difference between any two successive

the potential well was properly defined, one will have more accurate and

reliable calculations.

This important feature of correcting the calculations performed in the

exciton model was first pointed out by Blann [6,7]. Many types of potential

shapes are used to achieve this, of which the Woods-Saxon is the most

popular one [5].

For a system described by one-component configuration, the finite well

depth and bound state correction on the level density will be given as [3],

[ ] )31()(

)1()!1(!!

),(

,1

,

001

jFiBEjFiBAE

CCnhp

gEn

hpn

hp

ip

jh

jih

j

p

i

n

−−−Θ−−−

×−−

=

+

==∑∑

α

ω

where Chj and Cp

i are numerical coefficients, Cpi =p!/i!(p-i)! and similar

equation for Chj. F and B are Fermi energy and the nucleon binding energy,

respectively. Pauli correction Ap,h and energy symmetry αp,h terms are given

by reference [3] in the following forms

).33(2

),32(4

)1()1(

22

,

,

ghp

ghhppA

hp

hp

+=

−+−=

α

We shall use eq.(31) in the present report because it gives reliable

results that are adopted widely [3]. Some other different formulae are given,

for example ref. [1]

3-17

( )[ ] ( )( ) )34(

)1(),(

,,

,

001

jihgiFEjihgiFAE

Cgg

En

hphp

jiih

j

p

i

hh

pp

−+−−Θ−+−−

×−= ∑∑==

ππ α

ω

Page 19: State Density Calculations for the Exciton Levels · 2012. 12. 2. · particle state density per each MeV by g, then one can write the energy difference between any two successive

where gp and gh are the single particle level density for particles and holes,

respectively, and Ci,j are numerical coefficients that differ from Cip and Cj

h .

the new coefficients are given as [1],

⎪⎪⎪

⎪⎪⎪

+≤≤

−−

==

= ∑<<<<

=+++

otherwise

ijiiihfor

jifor

C

hkkjkkk

jih

j

0

),35(2

)11(2

)1(1

01

...0...

,

21

21

which can be approximated as [1]

).36()!(!

!

00

,

ihih

ih

Ch

j

h

j

jih −

=⎟⎟⎠

⎞⎜⎜⎝

⎛= ∑∑

==

Using this, and neglecting the terms corresponding to [gπ (ih-j)], then

the eq.(34) above can be written in the approximated form [1] (assuming that

gp=gh=g, and n=p+h),

( ) ).37()()!1(!!

)1(),(1

01 jFE

nhpjFE

jh

gEnn

jh

j

n −Θ−

−−⎟⎟

⎞⎜⎜⎝

⎛≅

=∑ω

Yet there is another form to include the finite depth and bound state

correction which is [1] (we give these formulae for better review of the

theory, although not used in the present calculations performed here)

( )

).38()(

)!1(!!)1(

)!1(!!),(

,

1,

001

jFiBE

nhpjFiBAE

ip

jh

nhpgg

En

hp

nhpj

p

i

h

j

hh

pp

−−−Θ

×−

−−−−⎟⎟

⎞⎜⎜⎝

⎛⎟⎟⎠

⎞⎜⎜⎝

⎛−

=−

==∑∑

α

ω

3-18

For a two-component Fermi gas system we have the massive formula [3],

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[ ]

( ) ),39(

)1()!1(!!!!

),(

,,,

1,,,

2

vvvvvhvphp

nvvvvvhvphp

vjvh

vivp

jh

ip

vjvijivh

vj

vp

vi

h

j

p

ivv

vnv

n

BjBiFjBiE

BjBiFjBiAECCCC

nhphpgg

En

−−−−−Θ

×−−−−−

×−−

=

+++∑∑∑∑

ππππππ

ππππππππ

ππ

πππ

π

π

πππ

ππ

α

ω

with Pauli term given as,

),40()1()1()1()1(41

,,, ⎥⎦

⎤⎢⎣

⎡ −+−+

−+−=

v

vvvvvhvphp g

hhppg

hhppAπ

ππππππ

and finally the energy symmetry term

).41(22

2222

,,,v

vvvhvphp g

hpg

hp ++

+=

π

ππππ

α

It is common to sum over all possible values of the exciton number, n, to see

the behavior of the eq.(39) above.

V. Pairing Correction and Fermi Gas Formula

In order to have a more realistic frame to describe nuclear level

density, one should introduce as many as possible of the realistic corrections.

So far we are dealing here with the ESM concept. Although this

approximation gives good agreement with experiment, it still has some

difficulties.

3-19

The most important defect in the ESM is that it ignores the

considerable shift in the energy levels due to nucleon-nucleon interaction.

This shift of energy is not essentially included in the idea of the ESM, so one

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needs to add some correction factor that deals with energy shift due to

nucleon-nucleon interaction.

Experimentally, it is confirmed that nucleons of the same type tend to

couple together in pairs. This is seen from the higher nucleon separation

energy for even Z and even N nuclei. Moreover, the even-even nuclei have

their position on the top when concerning nucleon separation energy or

excitation energy. This is a natural phenomenon that characterizes the

nuclear forces. To break this pairing between nucleons, one needs an extra

energy about 1~2 MeV.

Pairing energy also affects the level density, because the amount of

energy added to the excitation energy will highly influence the excitation

process and exciton formation, thus level density of the excited nucleus. In

experiments dealing with level density calculations it is very useful to add

the pairing energy as a leading parameter [2].

The correction of pairing energy will be left for the next report

(Repot No.4) because it possesses a somewhat prolonged formalism used for

the practical calculations.

VI. Numerical Calculations

As an application for the purpose of better understanding the present

approximations, three numerical examples are performed here to calculate

the level density of the precompound nucleus. The present report presents

different equations used to calculate the level density according to the theory

of the exciton model with three corrections for the cases of one- and two-

component Fermi systems.

3-20

The present corrections include:

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1-Pauli principle effect,

2- Finite depth of the nuclear potential well and bound state effects.

In order to make more meaningful use of the presentation above, three

examples were studied numerically using codes written for this purpose.

The code used is named “PEESM”-see paragraph IX at the end of the present

report-, and it consists of many subroutines that are written in (MATLAB

R2006b), and are compatible to work on any other (older or newer) version

of MATLAB. The present programs can be compiled via the mcc MATLAB

compiler and distributed as stand-alone application programs (just as any

code written in FORTRAN language); so that users who do no have

MATLAB program installed on their computers can also operate the present

codes. The programs written here, however, also include direct plotting of

the results by the MATLAB GUI (Graphical-User Interface). However,

stand-alone versions can be made to produce numerical output that are saved

in text files.

Using the MATLAB program; therefore, guarantees the two most

important conditions and specifications met by FORTRAN and C/C++

languages, which are compatibility (work on any computer machine) and

portability (application with extension of .exe which have a relatively small

size and can be saved on floppy diskettes).

The examples which are considered in the present report include the

following three main cases:

1- Level density calculations for one- and two-component systems with no corrections,

3-21

2- Level density calculations for one- and two-component systems with Pauli principle corrections,

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3- Level density calculations for one- and two-component systems with corrections due to finite depth of the nuclear potential well and bound states.

and the target nucleus and other specifications of the numerical study of

level density calculations are listed in Table (1) below.

Table(1). The parameters used in the present numerical study of level density calculations

Target nucleus under investigation 28

5426

Fe

Mass number, A 54 Atomic number, Z 26 Maximum excitation energy, E 100 MeV Exciton number 5

Exciton number configurations one-component: (3,2) [= p,h] two-component: (3,2,0,0) [=pπ, hπ, pv, hv]

Single particle density, g A/13 (MeV-1)

Nucleon’s binding energy Proton: 8 (MeV) Neuron: 10 (MeV)

Finite depth of the nuclear potential well (this equals to the Fermi Energy)

Proton:38 (MeV) Neutron: 40 MeV

3-22

The results of each example are given in the next paragraph. Future

reports will include further corrections of the nuclear level density such as

pairing and charge corrections.

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VII. Results and Discussions

VII.A. Level density calculations with no corrections

The one- and two-component nuclear level density calculated using

Ericson’s formula (with no corrections) is shown in Fig.(3), based on eq.(5) -

for one-component) and on eq.(10) -for two component-. The specific

calculation parameters are those taken from Table(1).

Fig.(3). The results of the level density for one- and two-component Fermi gas system based on Ericson’s formula. The two-component configuration is (3,2,0,0).

3-23

From Fig.(3) one can see clearly that the two-component results are

less than those of the one-component. This behavior is expected physically

because, as the nature of calculations suggests, two-component system will

have to share the energy with more entities. The extra entities are those due

to the neutron particle and holes. The effect is apparent from the concept of

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the single-particle density, g, where for one-component only one entity

(indistinguishable particles or holes) will share the excitation energy. For

two-components, on the other hand, to have the ability to distinguish the type

of the exciton particle or hole, we need to give different population of states

for each type of fermions (neutrons or protons), thus we define gπ and gν.

Although pν and hν are set to zero, the effect is still clear. Let’s take an

example here. In the present calculations, the system under study was taken

as, n=5 for both cases, in the configurations (3,2)-for one-component- and

(3,2,0,0)-for two-component-. Now since -see eq.( 11)-,

( )( )

( )38.6

10.02587/

14814.05426

5

5

5

1

2 ≈=⎟⎠⎞

⎜⎝⎛===⇒

<===⇒≅

AZ

gAZg

gg

AZ

gg

gAZg

n

nππ

ππ

ωω

3-24

so even if we set pν and hν equal zero, Ericson’s formula for two-component

system will still give less value of the level density than that of one-

component system. The ratio between ω2/ω1 is large, but this difference is

accepted [1,3]. Some researchers try to overcome this by defining a single-

particle density for each exciton individually. This means that we define (gp,

gh) for one-component system and (gpπ, ghπ, gpν, ghν) for two-component

system [1]. However, this will add extra effort in programming and is not

improving the calculations. It is known that Ericson’s formulae for one- and

two-component systems actually overestimates the level density in a

considerable manner [1,3]. So practical calculations should give as much

less of these formulae as possible. We shall see when adding Pauli and the

finite depth corrections that the level density will be decreased as we add

more corrections.

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Fig.(4) shows a comparison between different configurations for Ericson’s

formula for two-component system, all have n=5. The configurations

(3,2,0,0) and (2,3,0,0) give the same results so they are undistinguished in

Fig.(4). The configuration (4,1,0,0) is the lowest while the configuration

(2,1,1,1) is the highest.

Fig.(4). A comparison of the level density for two-component Fermi gas system based on Ericson’s formula, eq.(9). Different configurations are considered. The exciton number is n=5, and the case of n=3 is also added for comparison.

The plot for one-component for n=3 was also added for comparison,

where one see that n=3 is higher than any configuration of n=5. The case of

one-component with n=5 is even higher that n=3, indicating the effect of

level density reduction for the two-component than that of one-component in

a very clear manner.

3-25

n=3

n=5 26

54Fe28

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VII.B. Level density calculations with Pauli correction

The results are shown in Fig.(5). These results are based on,

respectively for one- and two-component, eq.(23) and eq.(26), using Pauli

factor from eq.(14) and (16) and the energy symmetry term from eq.(25) and

eq.(27).

Fig.(5). The results of the level density for one- and two-component Fermi gas system based on Williams’ formula, with Pauli correction added. The two-component configuration is (3,2,0,0).

Here the other form of Williams’ formulae, eq.(13) and eq.(15) were

not used because they are not corrected for energy symmetry term, αp, h.

3-26

In this case one can also see that for a Fermi gas system made of one-

component the results of the nuclear level density are higher than those for

two-component, and this is similar to the case of Ericson’s results. A

comparison between the two lines shown in Fig.(5) also show that the

maximum value for one-component is to be somewhat higher than that of

Fig.(4) above, which is as expected since in Williams’ formulae corrected to

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Pauli principle, the correction will apply for the energy. Pauli energy, Apπ,, hπ,

pν, hν, for the case (pν=hν=0) of the two-component, eq.(15), is actually not

the same for one-component. The effect here is, again, to the single-particle

density difference, gπ and g. Consider the example:

1

1

,

,,,

1

2

,

,,,

4)3()1(

4)3()1(

!!!!!!

0

4)3()1(

,4

)3()1(4

)3()1(

⎟⎟⎟⎟⎟

⎜⎜⎜⎜⎜

−++−

−++−

=⎟⎟⎠

⎞⎜⎜⎝

×=∴

⇒==

−++=

−+++

−++=

n

n

vnv

nn

hp

vhvphp

vvn

vnv

n

vv

hp

v

vvvvvhvphp

ghhppE

ghhpp

E

ggg

AEAE

hphphp

ggg

hp

ghhppA

ghhpp

ghhpp

A

π

ππππ

ππππ

ππ

ππ

π

ππππππ

ωω

Q

where hv = pv = nv= 0. Then we have, 1

1

2

4)3()1(

4)3()1( −

⎟⎟⎟⎟⎟

⎜⎜⎜⎜⎜

−++−

−++−

=

n

n

n

ghhppE

ghhpp

E

gg π

πππππ

π

ωω

1

1

)3()1(4/

)3()1(4

4)3()1(4

4)3()1(4

⎟⎟⎟⎟⎟

⎜⎜⎜⎜⎜

−−+−

−−+−

=

⎟⎟⎟⎟⎟

⎜⎜⎜⎜⎜

−−+−

−−+−

=

n

nn

nn

n

n

n

ghhppgE

AgZhhppEg

gAgZ

ghhppgE

ghhppEg

gg

πππππ

π

πππππ

ππ

3-27

1

))3()1(4()3()1(4 −

⎟⎟⎠

⎞⎜⎜⎝

⎛−−+−

−−+−=

n

nn

nn

hhppgEhhppEg

ZA

gAgZ πππππ

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Putting:

4

4

1

2

10410/4

))32(2)13(34()32(2)13(3/4,2,3

⎟⎟⎠

⎞⎜⎜⎝

⎛−

−=

⎟⎟⎠

⎞⎜⎜⎝

⎛−−+−

−−+−=⇒====

gEAZgE

AZ

gEAZgE

AZhhpp

ωω

ππ

and if we used: A=54, Z=26, E=100, g=A/15, we’ll have,

( ) 2

1

2 1020521418.05426 −×≈=

ωω

.

which explains the point.

A comparison of this case for different exciton configurations is shown

below in Fig.(6). The same behavior seen before in Fig.(4) is repeated here,

for the same reasons.

Fig.(6). A comparison of the level density for two-component Fermi gas system based on Williams’ formula with Pauli correction for energy. Different configurations are considered. The exciton number is n=5, and the case of n=3 is also added for comparison.

3-28

n=3

n=5

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VII.C. Level density calculations with corrections due to Pauli principle and the nuclear potential well with finite depth

The results of this case are shown in Fig.(7), and they are based on,

respectively for one- and two-component, eq.(31) and eq.(39), using the

accompanied set of equations.(32) and (33) for one-component and the

eqs.(40) and (41) for two-component systems. A plot with linear y-axis of

the same figure one will get the Fig.(8). Also a comparison is made in this

case but not for different exciton configurations as before, but for different

values of the system’s Fermi energy, F, and the nucleons’ binding energy, B.

The results are shown in Fig.(9) for different values of F and in Fig.(10) for

different values of B.

Fig.(7). The results of the level density for one- and two-component Fermi

gas systems based on Williams’ formula, with both of Pauli and the finite well depth corrections added. The two-component configuration is (3,2,0,0). Values for Fermi energy and binding energy for each case are taken from the Table(1).

3-29

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Fig.(8). Same as Fig.(7) with linear y-axis.

3-30

Fig.(9). A comparison of the level density for one-component Fermi gas system based on Williams’ formula with Pauli and finite depth corrections. Different Fermi energies, F, are considered.

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Fig.(10). A comparison of the level density for one-component Fermi gas

system based on Williams’ formula with Pauli and finite depth corrections. Different Binding energies, B are considered.

An interesting behavior of the system seen from Fig.(7) is that at

energy E~90 MeV, the two-component level density results are higher than

the one-component level density results. From Fig.(8), one sees the perfect

behavior of the two-component system which continuously increases with

the excitation energy, E. One-component reduction as the energy increases

strongly suggests that if one wishes to correct the nuclear level density to the

finite depth of the nuclear well potential, two-component system should be

used. However, we used one-component system for further comparison of

the system’s Fermi energy, F, and nucleon’s binding energy, B, because

from the one-component system one can see exactly how the result would be

when changing F or B for one time. These results are shown in Fig.(9) and

Fig.(10).

3-31

From changing the Fermi energy of the system -Fig.(9)- one can notice

that as the value of F increases the level density of the system increases for

the same excitation energy E and for the same binding energy, B. This is a

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very interesting because if we remember the definition of the Fermi energy,

it is the energy value that lays half the way between the last filled and first

unfilled energy level. Fermi energy is, therefore, considered as a proper

indication for the shape of the nuclear potential. We also have:

1- if one looks at eq.(31), we see there is the term (E-iF-jB)n-1.

Lets consider(E-iF-jB) as the effective excitation energy.

When E=iF+jB, we’ll have the above term equals to zero!

This means that the effective excitation energy is zero, leading

thus to no level density value.

2- if F or B increases, we have (E-iF-jB), and not (E-F-B). The

summation indices i and j, have values from zero to p and h,

respectively -see eq.(31)-. So the effective excitation energy

can has a negative value, but this is given to the power (n-1),

since n in the exciton model reads an odd value (usually

always), we have (n-1) = even, so (-ve)n-1=+ve ..always!

From the above, when the value of Fermi energy F increases one expects

that the term (effective energy)n-1 will increase. Let’s consider a numerical

example to explain this point clearly:

Let p=3, h=2, E=10 MeV, F=38 MeV, B=10 MeV.

We have n=5, and the effective excitation energy in this case is

Eeff=[10-i (38) - j (10) ] for i =0 to 3 and j=0 to 2. The minimum effective

excitation energy is at i=j=0, leading to Eeff=10 MeV, so

[Eeff]5-1=[10]4 =104.

3-32

The maximum of Eeff is at p=3 and h=2, then Eeff =10 - 3x38 - 2x10 = 10-

114-20=-124. Then

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[Eeff]4=[-124]4= + 236421376= 2.3 x 108..!

now let’s do the same calculations with F=50 MeV, one will get minimum of the Eeff=10 MeV and maximum Eeff=-160 MeV thus, we will have the following value

[Eeff]4=655360000=6.5x108.

The same considerations apply completely for the binding energy, B, as

seen from Fig.(10), where as the binding energy increases the value of the

level density also increases.

Fig.(11) shows the comparison of this correction (Williams’ with Pauli

and finite depth) for two-component system with different exciton

configurations. The values of F and B are those taken from Table(1). The

configuration (1,0,2,2) represents an anomaly.

Fig.(11). A comparison of the level density for two-component Fermi gas

system based on Williams’ formula with Pauli and finite depth corrections. Different exciton configurations are considered.

3-33

Log

ω2(n

,E)

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VII.D. A final comparison

Finally we compare the three cases for one- and two-component

systems.

Fig.(12). A comparison of the level density for one-component Fermi gas

system based on Ericson’s, Williams’ formula with Pauli and with Pauli and finite depth corrections.

3-34

Fig.(12) shows this comparison for one-component. The curves for

Williams’ with Pauli correction only interferes with the other curves so we

plot the same figure as log-log plot shown in Fig.(13). From Fig.(13) one

can see that Williams’ with Pauli correction starts near Williams’ with Pauli

and finite depth corrections and terminates near Ericson’s results. Also one

can see that as we add more corrections the level density values decrease

which is expected since these corrections will minimize the effective

excitation energy. The last figure, Fig.(14) shows the same comparison but

for two-component system. The same behavior is seen from these results.

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Fig.(13). Same as Fig.(12) with both axes as logarithmic.

Fig.(14). Same as Fig.(12) for two-component system, and with both axes as

logarithmic.

This concludes the present calculations.

3-35

Log

Log

ω2(n

,E)

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VIII. Suggestions

The present treatment needs to be improved for other corrections. The

improvement due to other corrections, such as pairing, shell structure,

angular and linear momentum…etc, shall be considered in coming reports.

Also it is important to perform these calculations with non-ESM approach.

IX. The Program

IX.A. Description

The program used here is called “PEESM1”, written in MALAB

language. The name “PEESM” stands for “Pre-Equilibrium with Equidistant

Spacing Model”.

The program PEESM1 is the main (calling) routine. It calls eight

subroutines that are classified as below:

3-36

1- strt.m subroutine: which starts (initializes) the variables

required for the entire program. This routine actually reads an

external input file named peesm.inp where all the input

parameters required are fed into the code. The shape of

peesm.inp is given as blow. Currently this is being read by

strt.m as a matrix of 5x3, in the future this will be modified to

be read line by line in order to include detailed (text)

description for each case. The letters in this input program

refer to:

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p(pi)=pp, h(pi)=hp, p(nu)=pn, h(nu)=hn, Emax=maximum excitation energy, Ef(pi)=Fermi energy for protons, Ef(nu)=Fermi energy for neurons, B(pi)=binding energy for protons, B(nu)=binding energy for neutrons, A=mass number of the specified nucleus, Z=its atomic number, d=spacing of the ESM (d=13 or 15 used in g=A/d)

When dealing with one-component of any case, then the values of

p(pi)=p, h(pi)=h, and p(nu) and h(nu) are ignored, Ef(pi)=Fermi energy

for particles, Ef(nu)=binding energy, B(pi) and B(nu) are ignored, and Z

is ignored. At least one space is required between adjacent columns.

The last two zeros can be ignored because they are not read in the code.

n p(pi) h(pi) p(nu) h(nu) Emax Ef(pi) Ef(nu) B(pi) B(nu) A Z d 0 0

(the shape of peesm.inp input file to PEESM1.m program)

2- Ericson1.m subroutine: this calculates the one-component

Ericson’s formula.

3- Ericson2.m subroutine: this calculates the two-component

Ericson’s formula.

4- Williams1.m subroutine: this calculates the one-component

Williams’ formula (with Pauli correction only).

5- Williams2.m subroutine: this calculates the two-component

Williams’ formula(with Pauli correction only).

6- WilliamsF1.m subroutine: this calculates the one-component

improved Williams’ formula (with Pauli and finite well depth

corrections).

7- WilliamsF2.m subroutine: this calculates the two-component

improved Williams’ formula (with Pauli and finite well depth

corrections).

3-37

8- DP4PEESM.m subroutine: it is a plotting subroutine.

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IX.B. Testing the Program

To program for scientific purpose is to write a sequence of logical steps

that follow a given equation. We first learned that: “One can write anything

in any programming language and name it -a program-, and it might work!..

But.. who says it is correct?” So in order to check that the present code

“works and correct,” some check is needed for proving is consistency. I refer

to Table(1) of ref.[1] where some numerical values for two specified

examples are given, calculated by Ericson’s formula for one-component -

eq.(5)-. In there, the first example is by setting:

n=3 (p=2, h=1), A=50, Emax=15 MeV and d=13 MeV-1. The result of [1]

for ω(n,E) was 3200. If we make these values as input to PEESM1.m, we

find that our value is ω(n,E) =3200.4, with percentage error ~ 0.0125%.

n=9 (p=5, h=4), A=50, Emax=15, d=13, the results of [1] is 4.1x106, and our

result is 4.065x106 with percentage error 0.85%.

The second example in [1] is:

n=3 (p=2, h=1), A=200, Emax=100 MeV and d=13 MeV-1. The result of [1]

for ω(n,E) was 9.1x106. If we make these values as input to PEESM1.m, we

find that our value is ω(n,E) =9.103x106, with percentage error ~ 0.003%.

n=43 (p=22, h=21), A=200, Emax=100 MeV and d=13 MeV-1. The result of

[1] was 1.4x1043, and our result is 1.373x1043, the percentage error is 1.8%.

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I also refer to Table(2) of reference [1], where Williams formula for

one-component with Pauli correction is given. The values given there were

also checked with PEESM1.m results and the percentage errors were also

about ~ 1-2 %. So our program seems to be “works and correct”! A. A. Selman.

Page 40: State Density Calculations for the Exciton Levels · 2012. 12. 2. · particle state density per each MeV by g, then one can write the energy difference between any two successive

REFERENCES

[1] E. Bĕták and P. E. Hodgson, “ Particle-Hole State Density in Pre-equilibrium Nuclear Reactions”, University of Oxford, available from CERN Libraries, Geneva, report ref. OUNP-98-02 (1998).

[2] P. E. Hodgson, “Nuclear Reactions and Nuclear Structure”, Clarendon Press, Oxford, (1971).

[3] M. Avrigeanu and V. Avrigeanu, “Partial Level Density for Nuclear Data Calculations”, Comp. Phys. Comm. 112(1998)191. also available from: Cornell University online publications, ref. arXiv:physics/9805002.

[4] J. J. Griffin, “Statistical Model of Intermediate Structure”, Phys. Rev. Lett.,17(1966)478.

[5] Ye. A. Bogila, V. M. Kolomietz, A. I. Sanzhur, and S. Shlomo, “Preequilibrium Decay in the Exciton Model for Nuclear Potential with a Finite Depth”, Phys. Rev. C53(1996)855.

[6] M. Blann, “Importance of Nuclear Density Distribution on Pre-Equilibrium

Decay”, Phys. Rev. Lett., 28(1972)757. [7] M. Blann, “Preequilibrium Decay”, Ann. Rev. Nucl. Sci. 25(1975)123.

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